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TR/04/85 February 1985 The Complex Grothendieck for 2x2 matrices by Andrew Tonge Summary. for 2x2 We show that the complex Grothendieck constant matrices is 1

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TR/04/85 February 1985

The Complex Grothendieck for 2x2 matrices

Andrew Tonge by

Summary.

for 2x2 We show that the complex Grothendieck constant matrices is 1

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-1-

Grothendieck's inequality asserts that if (ai j) is an n×n matrix and if x 1 . . . ,xn ,y1 , . .. ,yn are elements of the unit ball of a Hilbert space, then there is an absolute constant K such that n aij xi ,yj k|| a || ,1 .

1 j

i,

|

|

< >

=

We have written ||a||∞ , 1 for the norm of the matrix (ai j) considered as a linear operator from ℓn to ℓ1n. Thus

⎪⎭

⎪⎬

⎪⎩

⎪⎨

⎧ ∑ ≤ ≤ ≤ ≤

= =

∞ n :|si| 1 |,tj | 1,1 i,j n

1 j

i, aij si tj ,1 sup

||

a

||

When we say that K is an absolute constant, we mean that K is independent of n , of the matrix (ai j) and of the vectors

x1,...,xn ,y1,...,yn . The reader may consult [2] for a proof of Grothendieck's inequality and for supplementary information.

The best value of K is unknown, and there are differences between the real and complex cases. However, in both cases it is known that K > 1 · More precise regults may be found in [1] and [3].

Allan Sinclair (Edinburgh) has suggested that it would be of interest to determine the best universal constants Km ,n such that if (a i j ) is an n×n matrix and if x1 ,...,xn ,y1,...,yn are elements of the unit ball of a Hilbert space, then

n aij xi ,yj km,n || a || ,1

1 j

i,

|

|

= < >

For example, this would be a way to obtain information about the best value of K ·

Sinclair has obtained various estimates for Km ,n (private communication) and has conjectured that in the complex case

K2 ,2 = 1. (Results from [l] show that in the real case K2 ,n = √2 for every n > 1.) We prove this conjecture and show, more

generally, that in the complex case K m ,2 = 1 for every m .

THEOREM. Let (ai j) be a complex 2×2 matrix and let x 1 , x2, y1 and y2 be elements of the unit ball of a complex Hilbert space. Then

2 aij xi,yj ||a || ,1

1 j

i,

|

|

< >

=

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- 2 -

Proof. Simple manipulations reduce the problem to that of proving

sup

{

|a11 s1 a21 s2 | |a12 s1 a22 s2|:| s1| | s2 | 1

}

.

} 1 2 ||

x

| 1||

x

||

: 2||

22 x 1 a

12 x a

||

2 ||

21 x 1 a

11 x a

||

{ sup

=

= +

+ +

=

= +

+ +

Writing norms (and absolute values) in terms of inner products, this inequality becomes

{ }

{

u Re vz p Re qz : | z| 1

}

.

sup

1

| z

| : qz Re p vz

Re u sup

that show can

we if follow therefore

will result The

22 . 12 a 2a q

2 and 22 | a 2 | 12 | a

| p 21 , 11 a 2a v 2 , 21 | a 2 | 11 | a

| u where

, 1 2 | s

| 1| s

| 2 : s 1, s q Re 2 p

s 1, s v Re u sup

1 2 ||

x

||

1||

x

||

2 : x 1, x q Re 2 p

x 1, x v Re u sup

= +

+ +

=

≤ +

+ +

=

+

=

= +

=

=

=

>

+ +

>

<

+

=

=

>

<

+ +

>

<

+

⎭⎬

⎩⎨

Now write v , q and z in terms of their real and imaginary parts, so that v = α + iβ , q=λ +iμ and z = x + iy . Then if we set

f(x,y) = u + αx −βy + p + λx − μy we have to prove that

sup

{

f(x,y):x2 + y2 1

}

= sup

{

f(x,y):x2 + y2 = 1

}

.

[Note that when x2 + y2 ≤ 1, f(x,y) is well-defined as a real number, since u > |v| and p > |q| .]

This identity will certainly follow if we can show that f has no local maximum in the open disc x 2 + y2 < 1 . In this disc f is continuously differentiable, provided that u ≥ |v| > 0 and P ≥ |q| > 0 . The partial derivatives are

2 . 1 ) uy λx (p 2u 2 1 1 ) βy αx (u 2β y 1

/ f

2 and 1 ) uy λx (p 2λ 2 1 1 ) βy αx (u 2 α x 1 / f

+

+

=

+

+

+

=

A local maximum can only occur if ∂f/∂x = ∂f/∂y = 0 , and this is impossible when the following conditions are satisfied.

(i) α , β , λ and μ are all non-zero, and (ii) αu ≠ βλ .

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- 3 -

However, if these conditions are not satisfied , then for any given ε > 0 we can select a matrix 'j) such that

(ai , i (1 ε/8

| ' j a i

aij − ≤ ≤ ≤

| j 2)

and such that the numbers α' , β ' , λ ' and μ ' associated with ( 'j ) are all non-zero and do satisfy α' μ' ≠ β' λ' . But then

ai

⎪⎭

⎪⎬

⎪⎩

⎪⎨

⎧ ∑ < > ≤ ≤ ≤ ≤

= aij xi,y j : || xi || 1, || y j || 1, 1 i, j 2 2

1 j sup i,

⎪⎭

⎪⎬

⎪⎩

⎪⎨

⎧ ∑ < > ≤ ≤ ≤ ≤

+ =

≤ ' xi,yj : || xi || 1, || yj || 1, 1 i, j 2

aij 2

1 j sup i, 2 ε

1

≤ 2

1 ε + || a' || ∞ ,1

≤ ε + ||a ||∞,1

Let ε → 0 to get the result we want.

References.

[1] J.L .Krivine. Constantes de Grothendieck et fonctions de type positif sur les spheres. Adv. in Math, 31 (1979) 16-30.

[2] J. Lindenstrauss and L.Tzafriri. Classical Banach spaces I.

Springer (1977).

[3] G.Pisier. Grothendieck' s theorem for non-cotntnutative C*-algebras with an appendix on Grothendieck's constants. J. Funct. Anal.

29 (1978) 397-415.

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