R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
R ADOSLAV D IMITRI ´ C On subfunctors of the identity
Rendiconti del Seminario Matematico della Università di Padova, tome 76 (1986), p. 89-98
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On Subfunctors of the Identity.
RADOSLAV DIMITRI0107
(*)
1. Introduction.
This note is concerned with the
study
ofmultiplicative
and he-reditary
functors i.e. those subfunctors 1" of theidentity satisfying,
forevery
B A, (B +
and FB = B n FArespectively.
It also discusses some
concepts
of.F’-purity,
connected with Fuchs’Problem 15
(in [2 ] )
and the note is to be considered as an introduc- tion to a morethorough
treatment of this Problem. Some of the ideas here have beenanticipated
in[1].
Throughout
we deal with acategory
of(unital)
R-modules were Bis a commutative
ring
with unit. F will denote a subfunctor of theidentity
in thatcategory
i.e.(an additive)
functor suchthat,
for everyhomomorphism f : B --3- A, Ff
=flFB (thus
andThis
implies
inparticular that,
for everyB A, (B + FA) IB F(A IB)
and that I~’ commutes with direct sums.
By purity
we meanRD-purity
denotedby B
c ,~A, meaning
thatevery
equation rx
= b E B(r
ER) having
solution x E A also has asolution in B.
2.
Multiplicative
functors.DEFINITION 1. A subfunctor of the
identity
is calledpticative if,
for every submodule B of an R-moduleA,
- ( B +
(*)
Indirizzo dell’A.: ul. 29. Novembra, 108, 11000Beograd, Jugoslavija.
The
following proposition
describes allmultiplicative
functors inthe
category
of modules over PID’S.PROPOSITION 2. If .R is
PID,
then a subfunctor F of theidentity
is
multiplicative
if andonly
if it is amultiplication by
an r E .R.PROOF. One way is trivial. Assume now that F is
multiplicative.
Every
.R-module A is aquotient
of a free module: A ==(0
This
gives
FA =(B + (B +
=rA,
forA characterization of
multiplicative
functors isgiven
inTHEOREM 3. The
following
areequivalent:
( 1 )
.~’ ismultiplicative;
(2)
F isepi-exact
i.e. if is an exact se-quence, then so is FA S FC -j-
0;
( 3 )
~’ is a radical i.e.F(AIFA)
=0,
for every .A and==
~A :
FA =01
is closed underquotients
and submodules.PROOF.
(1) « (2 ) :
The relationsqFA
=(B +
prove thispart immediately.
(1)
~(3) : F(AIFA) - (FA +
= 0.Now,
if A. eX,
then
F(AjB) == (B + 0,
thus JV is closed under quo- tients.(3)
~( 1 ) :
SinceAIFA
thehypothesis
that J~ is closed un-der
quotients, gives +
== 0 =F(Aj(B + I’A)) -
==
.F’(A JB/(B +
so thatThis
implies -f- FA)/B,
thusproving
that F is indeedmultiplicative.
The theorem that follows enables us to work with classes of modules closed under
submodules, quotients
and directproducts
as well aswith filter like families of ideals of .R closed under
arbitrary
intersec-tions,
instead ofworking
withmultiplicative
functors. Wegive
itsdetailed
proof.
THEOREM 4. There is a
bijective correspondence
between:(1) Multiplicative
functors.91
(2)
Classes of modules closed undersubmodules, quotients
anddirect
products.
(3)
Families F =R) satisfying
PROOF.
(1)
-+(2):
Forgiven multiplicative
functor .I’ define= FA
=0}. C,
isclearly
closed under submodules andquotients (Theorem 3).
IfA 2 E CF (i E I ) ,
then forevery j E I,
0 = _Therefore,
for every, is also closed under
arbitrary products.
(2)
-(1 ) :
Forgiven
class C of modules closed under submodu-les, quotients
and directproducts,
y defineFe by FeA
= the smallest submodule B of A such that E C. We show thatFe
satisfies(3)
in Theorem 3:
By
the way we definedFe,
= 0. IfFeA == 0
i.e. A E e itgives
andB e C,
for everyBA.
Hence =
Fe(AIB)
=0,
and this proves that X is closed under submodules andquotients.
The
correspondence ( 1 ) H ( 2 )
isbijective:
.F -¿. E
eF
orequivalently F(AjFcFA)
=0
1 hence(FCFA +
= 0 i.e. FABy
Theorem3, F(A IFA) = 0, thus, by
the definition of weget
F =b ) If,
for weget
and, by
the known fact we obtain(3)~(2): .~ --~ ~~- _ ~A ~ I
for everyx E A,
It isclear that
Cy
is closed under submodules. That it is closed underquotients
we see from the fact that if x EA IB
then ann e Yand
a ) applies.
IfCy ( i E I ) , then,
for every ,~ . Forarbitrary
The
correspondence ( 2 ) H ( 3 )
isbijective:
for every x in
A,
ann x E « fourevery x in
A, B/ann x
c- C « for every x inA., .
This
implies
that A e C since A is thequotient
of(the
lastequivalence
is valid since .R isassumed to be
having
aunit) .
The
correspondence (1 ) H (3 )
is realizedby
= the smallest submodule B of A such that for every
~ E
AIB,
ann x E Y.Notice that if Y
# #
in Theorem4,
then E Y.Also 0 e Y « F is zero functor => e = the
category
of R-modules.If .R is
PID,
thenby Proposition 2,
theonly multiplicative
functorsare
multiplications by r
EB,
thus C consists of all R-modules boundedby
a fixedr E R,
while Y == for an3.
Hereditary
functors.A very
important
class off unctors,
in a sense dual tomultiplicative functors,
is introduced inDEFINITION 5. Call a subfunctor 1~ of the
identity hereditary if
for every submodule of an R-module
A,
FB = B r1 FA.As a
corollary
to thisdefinition,
we derive that for ahereditary
functor F and
arbitrary
R-modulesC, D,
FC =F(C
r1D) . Combining Proposition
1.4 and Exercise 1.1 in[4]
we stateTHEOREM 6. The
following
areequivalent:
( l )
1~’ ishereditary;
93
(2)
F is left exact i.e. if 0 --~-B ~
~A~. --~ C is an exact sequence, then so is0 - FB * FC;
(3)
F2 = F and ={A:
=A~
is closed under submodules.PROOF.
(1)
=>(2):
Exactness at FB isstraightforward
since F is asubfunctor of the
identity.
The exactness at T’A is established from the chain ofequalities:
(2)
z4-(3):
The exact sequence 0 induces another exact sequence 0 thatgives
F2 = F.If FA = A and
B A,
then exactness inducesexactness of 0 - FB - A - thus FB =
B ;
this shows that is closed undersubmodules;
(3) => (1):
Let FA e G so B n FA e G orequivalently FB B
n FA =F ( B
nFA) ~ FB
therefore F ishereditary.
One of several
important
characteristics ofhereditary
functors is to be found inPROPOSITION 7. A subfunctor of the
identity
commutes withinverse limits if and
only
if it ishereditary
and commutes with directproducts.
PROOF.
By
a knownfact,
.F commutes with inverse limits if andonly if
it commutes with directproducts
andequalizers.
The lastcondition is
equivalent
toheredity
of F.Here,
for the sake ofcompleteness
andusefulness,
y we state Pro-position
3.3 from[4].
THEOREM 8. There is a
bijective correspondence
betw een :(1) Hereditary
functors.(2)
Classes C of modules closed undersubmodules, quotients
and direct sums.
(3)
Families ideals of 1~(called pretopologies
onR) satisfying
PROOF. The
correspondences
are as follows:At the end of this section we examine subfunctors of the
identity
that are at the same time
hereditary
andmultiplicative.
PROPOSITION 9. For a subfunctor F of the
identity,
thefollowing
are
equivalent:
( 1 )
F commutes with directlimits;
(2)
for everyhomomorphism f : B - A,
can-onically ;
(3)
for everysubgroup
there is a canonicalisomorphism
7
(4)
.F ishereditary
andmultiplicative;
(5)
I’ is exact.PROOF.
(1)
~(2): By
the ’knownfact, .F (being
a subfunctorof the
identity)
commutes with direct limits if andonly
if it commuteswith
coequalizers
or,equivalently,
withcoqernels.
This isexactly (2);
(2)
=>(3)
isobvious;
(3)
«(4)
~(5):
If 0 --~ B -j- A ---~ C -~ 0 isexact,
thenby
Theorems 3 and
6,
0 -+ FB -+ FA -+ FC - 0 is exact if andonly
if Fis
multiplicative
andhereditary.
The latter sequence is exact if andonly
ifFAIFB F(AfB) canonically;
(3), (4) ~ (1) :
If is a directspectar,
then where B =
i j} + Ai.
F-in-duced spectar
is95
thus F commutes with direct limits.
PROPOSITION 10. If F is a subfunctor of the
identity
in the cate-gory of modules over a
PID,
then F ismultiplicative
andhereditary
if and
only
if I’ is the Zero-functor or theidentity
itself.PROOF.
By Proposition 2,
F ismultiplication by
an r E .R. Since F ishereditary,
we have rl~ == .1~n rQ (Q-the quotient
field of.R) ;
thisis
possible only
if r is invertible so theonly
choices are either r = 1or r = 0.
4.
Following
Fuchs(we only change
the name alittle;
see[2],
Prob-lem
15)
we haveDEFINITION 11. For a subfunctor F of the
identity,
call the exactsequence
F-exact if the induced sequence
There are several
concepts
ofF-purity
introduced in the literature.For
instance,
Nunke in[3]
calls the exact sequenceE, F-pure
if itis an element Ext
(AIB, B).
If n =
k.m,
the exact sequence 0 - -+Z(n) - Z(m)
-~ 0gives
anexample
of n-exact sequence in thecategory
of Abelian groups; this sequence is not n-pure in Nunke’s sense.Conversely
Nunke
D-pure
but is not D-exactsequence
(D being
the divisiblepart
of agroup).
THEOREM 12. If .F’ is a subfunctor of the
identity
and E agiven
exact sequence, then the
following
areequivalent:
(1) .E
isF-exact;
( 2 )
.F’B = B n FA andF(AfB)
=(B + (3) F(AfB) canonically.
PROOF. The same
reasoning applies
as inproofs
of Theorems 3 and 6.EXAMPLES. 1.
By
Theorem 29.1 in[2],
.E is pure exact if andonly
if it isr-exact,
for every r E I~.2. If E is pure
exact,
then it is S-exact(here S
denotes the soclesubfunctor). By
Theorem 12 we need to showonly
that==
(B +
The last follows from the known fact(see
e.g. The-orem 28.1 in
[2])
that B is pure submodule of A if andonly
if forevery C
E there is an a e c of the same order as c.3. If E is
splitting,
then it is F-exact for every subfunctor F of theidentity.
Indeed if A = B0 C,
then B n FA = B n(FB 0
@FC) ==
FB andF(AIB)
== FC =(B EBFA)/B,
thus .F’ satisfies both conditions in Theorem 12(2).
PROPOSITION 13. Assume that E is an exact sequence, where A =
Åo EB At,
withAo
torsion free andA1
torsion. Then .E is T-exact(T-the
torsionfunctor)
if andonly
ifT ( (.Ao -~- B)IB)
= 0 or,equiva-
lently,
BPROOF.
By
Theorem12, .E
isT-pure
if andonly
ifT((Ao + .A.1)/B)
==- ( B +
which isequivalent
toT( (Ao + B ) /B )
= 0 orB)
being
torsion free. This is same asAo n B ~ * Ao .
We also introduce
DEFINITION 14. For a subfunctor F of the
identity,
call the exactsequence
if the induced sequence
is pure exact.
97
PROOF. =>: The
proof
thatT(AIB)
==(B +
isby
the sameargument
as inExample
2. ThatTB ~ *
TA followsstraightforwardly
from
B ~ * A.
: We need to prove
that B *
A. Let ra= b, a
EA,
b EB,
r E B. Then rqa = qra =
qb =
0 so qa E TC.By
T-exactness there is an withqa’ =
qa i.e. a - B andqra’ =
0 thus there is asuch that ra’ = b’ . Since
TB ~ * TA,
there is a TB withra’ - rb" - b’ therefore
r ( a’ - b" )
= 0 hencer(a - ( a’ - b" ) )
== rac = b.One can show in a similar fashion that E is pure exact if and
only
if it is
pure-r-exact
for every r c R(see Example
I in[1 ]
and Exer-cise
1, §
29 in[2]).
Following
Stenstr6m(see [4],
Exercise1, § 6)
call the exact se-quence E
(Y
is apretopology
on.R)
if for every x E C withann x there
exists YEA mapped
upon x, such that ann y = ann x . THEOREM 16. behereditary
functor and Y thepretopology corresponding
to it in thecorrespondence given by
Theorem 8. Thenthe exact sequence E is
pure-F-exact
if andonly
if it isY-pure.
PROOF. ~: Assume that B is
pure-F-exact
sequence. We prove that it is To thisend,
let x E C with ann x c 5-.By
Theo-rem
8,
this means that x EFC,
therefore there is a y E FA(i.e.
ann y EY) }
such that qy = x. We find a such that qyo= x and ann x ann ya : if rx= o, then ry
E FB * FA so there is a y1 E such thatr ( y -
-
= 0 ;
it isenough
now to take yo = y - y, .: We assume that E is
-pure
and prove that ~E is pure exact. If x E .F’C i.e. ann xe Y,
then there is a y E Awith qy
= xand ann y = ann x so that
y E FA.
This shows that .E is F-exact.It is also pure exact: if ry = b E
FB, y
E.F’’A, by 5;--purity
there exists yi e A such that qyl := qy i.e. y - FB and ann ann q y. Since rqy == 0 we have 0 thusgiving r(y -
= ry = b.REFERENCES
[1] R. DIMITRI0107,
Relativity in
AbelianGroups,
1980(Serbocroatian),
MS Thesis,University
ofBeograd.
[2] L. FUCHS,
Infinite
AbelianGroups,
Vol. I, Academic Press, New York andLondon,
1970.[3]
R. NUNKE,Purity
andsubfunctors of
theidentity, Topics
in AbelianGroups, Chicago (1963),
pp. 121-171.[4]
B. STENSTRÖM,Rings
and Modulesof Quotients, Springer-Verlag,
Berlin -Heidelberg - New
York, 1971; LNM 237.Manoscritto pervenuto in redazione il 9 febbraio 1985.