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Sciences &

Technologie

A

N°40, Décembre 2014, 27-30

© Université Constantine 1, Algérie, 2014 Résumé

SOME ASPECTS OF QUANTUM TUNNELING EFFECT IN DE SITTER-SCHWARCHILD SPACE-TIME

B. CHOUDER

Laboratoire de Physique Mathematique et Subatomique, Physics Department, Faculty of Exact Sciences, Frères Mentouri University, Constantine, Algeria.

Reçu le 12/01/2014 – Accepté le 14/07/2014 Abstract

Using the tunneling effect method near the black hole horizon and the WKB approximation for both fermionic and bosonic particles, some aspects are shown and discussed in a de Sitter-Schwarchild space-time type.

Keywords: quantum tunneling, cosmology.

Enutilisant la méthode de l’effet tunnel au voisinage de l’horizon d’un trou noir et l’approximation WKB pour des particules fermioniques et bosoniques, Quelques aspects ont été montres et discutes dans un espace-temps du type de Sitter-Schwarchild.

Mots clés : effet tunnel quantique, cosmologie

صخلم

بيرقت و دوسأ بقث قفأ نم برقلاب قفنلا لوعفم ةقيرط لامعتساب WKB

دق ةيئايزيفلا رهاظملا ضعب . ةينوزوب و ةينويمرف تاميسجل ةبسنلاب

يناكمز ءاضف يف تشقون و تحضو رتيس ود عون نم

- .دلزراوش

تاملكلا ةيحاتفملا : .ايجولومسكلا ، يتناوكلا قفنلا لوعفم

(2)

B. CHOUDER

28 I. INTRODUCTION

In this paper we study the tunneling behavior of spin -1/2 fermions across the event horizon of the Schwarzschild-de Sitter black hole where effects of quantum gravity are taken into account , and using the Hamilton-Jacobi method [1,2].

However, for the case of the bosons we try to find an exact formula for

𝜕

𝑟

𝐼 (r)

for an arbitrary non-Abelian Yang-Mills theory [3,4].

II. HAWKING RADIATION OF SCHWARCHILD-DE SITTER BLACK HOLE

The metric of any spherically symmetric solution in a Schwarzschild form is:

𝑑𝑠

2

= −𝑓(𝑟)𝑑𝑡

2

+ 𝑑𝑟

2

𝑓(𝑟) + 𝑟

2

(𝑑𝜃

2

+ 𝑠𝑖𝑛

2

𝜃 𝑑𝜑

2

The vacuum Einstein equations give a linear equation for ƒ(r), which has as solutions:

𝑓(𝑟) = 1 − 2𝑎/𝑟

and

𝑓(𝑟) = 1 − 𝑏𝑟

2

The first is a zero stress energy solution describing a black hole in empty space time, the second (with b positive) describes de Sitter space with a stress-energy of a positive cosmological constant of magnitude 3b. Superposing the two solutions gives the de Sitter– Schwarzschild solution:

𝑓(𝑟) = 1 − 2𝑎/𝑟 − 𝑏𝑟

2

We remind that the two parameters a and b give the black hole mass and the cosmological constant respectively.

III. FERMIONS

The fermion’s motion is determined by the generalized Dirac equation ref.[1]

[

𝑖𝛾

0

𝜕

0

+ 𝑖𝛾

𝑖

𝜕

𝑖

(1 − 𝛽𝑚

2

) + 𝑖𝛾

𝑖

𝛽ℏ

2

(𝜕

𝑗

𝜕

𝑗

)𝜕

𝑖

+

𝑚

(1 + 𝛽ℏ

2

𝜕

𝑗

𝜕

𝑗

− 𝛽𝑚

2

) +𝑖𝛾

𝜇

𝜇

(1 + 𝛽ℏ

2

𝜕

𝑗

𝜕

𝑗

− 𝛽𝑚

2

)

] 𝜓 = 0

(1)

Where:

𝜇

≡ 𝑖

2 𝜔

𝜇𝑎𝑏

𝛴

𝑎𝑏

𝛴

𝑎𝑏

=

𝑖

4

[𝛾

𝑎

, 𝛾

𝑏

]

,

{𝛾

𝑎

, 𝛾

𝑏

} = 2𝜂

𝑎𝑏 ,

𝜔

𝜇𝑎

𝑏

= 𝑒

𝜈𝑎

𝑒

𝜆𝑏

𝛤

𝜇𝜆𝜈

− 𝑒

𝜆𝑏

𝜕

𝜇

𝑒

𝜆𝑎

We assume that the wave function of the spin up state has the form:

𝜓 = ( 𝐴 0 𝐵 0

) 𝑒𝑥𝑝 (

𝑖

𝐼(𝑡, 𝑟, 𝜃, ∅))

(2)

and

𝑒

𝜇𝑎

= 𝑑𝑖𝑎𝑔(√𝑓, 1 √𝑓 ⁄ , 𝑟, 𝑟 sin 𝜃),

:𝛾

𝑡

=

1

√𝑓(𝑟)

( 𝑖 0 0 −𝑖 ), 𝛾

𝜃

= √𝑔

𝜃𝜃

( 0 𝜎

1

𝜎

1

0 ), 𝛾

𝑟

= √𝑓(𝑟) ( 0 𝜎

3

𝜎

3

0 ),

𝛾

= √𝑔

∅∅

( 0 𝜎

2

𝜎

2

0 )

(3) With

√𝑔

𝜃𝜃

=

1

𝑟,

√𝑔

∅∅

=

1

𝑟 sin 𝜃,

𝜎

𝑖 are the Pauli matrices. Our purpose is to find the solutions of eqn (1). First substituting the wave function eqn (2) and the matrices eqn (3) into the generalized Dirac equation eqn (1).

Since we are working With the WKB approximation we obtain 4 Hamilton-Jacobi equations:

−𝑖𝐴 1

√𝑓𝜕𝑡𝐼 − 𝐵(1 − 𝛽𝑚2)√𝑓𝜕𝑟𝐼

−𝐴𝑚𝛽[𝑔𝑟𝑟(𝜕𝑟𝐼)2+ 𝑔𝜃𝜃(𝜕𝜃𝐼)2+ 𝑔∅∅(𝜕𝐼)2] +𝐵𝛽√𝑓𝜕𝑟𝐼[𝑔𝑟𝑟(𝜕𝑟𝐼)2+ 𝑔𝜃𝜃(𝜕𝜃𝐼)2+ 𝑔∅∅(𝜕𝐼)2]

+𝐴𝑚(1 − 𝛽𝑚2) = 0 (4) 𝑖𝐵 1

√𝑓𝜕𝑡𝐼 − 𝐴(1 − 𝛽𝑚2)√𝑓𝜕𝑟𝐼

−𝐵𝑚𝛽[𝑔𝑟𝑟(𝜕𝑟𝐼)2+ 𝑔𝜃𝜃(𝜕𝜃𝐼)2+ 𝑔∅∅(𝜕𝐼)2] +𝐴𝛽√𝑓𝜕𝑟𝐼[𝑔𝑟𝑟(𝜕𝑟𝐼)2+ 𝑔𝜃𝜃(𝜕𝜃𝐼)2+ 𝑔∅∅(𝜕𝐼)2] +𝐵𝑚(1 − 𝛽𝑚2) = 0 (5)

𝐴 {

−(1 − 𝛽𝑚2)√𝑔𝜃𝜃𝜕𝜃𝐼

+𝛽√𝑔𝜃𝜃𝜕𝜃𝐼[𝑔𝑟𝑟(𝜕𝑟𝐼)2+ 𝑔𝜃𝜃(𝜕𝜃𝐼)2+ 𝑔∅∅(𝜕𝐼)2]

−𝑖(1 − 𝛽𝑚2)√𝑔∅∅𝜕𝐼

+𝑖𝛽√𝑔∅∅𝜕𝐼[𝑔𝑟𝑟(𝜕𝑟𝐼)2+ 𝑔𝜃𝜃(𝜕𝜃𝐼)2+ 𝑔∅∅(𝜕𝐼)2]}

=

0(6)

(3)

SOME ASPECTS OF QUANTUM TUNNELING EFFECT IN DE SITTER-SCHWARCHILD SPACE-TIME

29 𝐵

{

−(1 − 𝛽𝑚2)√𝑔𝜃𝜃𝜕𝜃𝐼

+𝛽√𝑔𝜃𝜃𝜕𝜃𝐼[𝑔𝑟𝑟(𝜕𝑟𝐼)2+ 𝑔𝜃𝜃(𝜕𝜃𝐼)2+ 𝑔∅∅(𝜕𝐼)2]

−𝑖(1 − 𝛽𝑚2)√𝑔∅∅𝜕𝐼

+𝑖𝛽√𝑔∅∅𝜕𝐼[𝑔𝑟𝑟(𝜕𝑟𝐼)2+ 𝑔𝜃𝜃(𝜕𝜃𝐼)2+ 𝑔∅∅(𝜕𝐼)2]}

= 0

(7) To find the relevant solution we perform the separation of variables as follows:

𝐼 = −𝜔𝑡 + 𝑊(𝑟) + Ө(𝜃, ∅)

eqn (6)and eqn (7)They are identical after divided respectively by A and B

(√𝑔

𝜃𝜃

𝜕

𝜃

Ө + 𝑖√𝑔

∅∅

𝜕

Ө)

[𝛽𝑔

𝑟𝑟

(𝜕

𝑟

𝑊)

2

+ 𝛽𝑔

𝜃𝜃

(𝜕

𝜃

Ө)

2

+ 𝛽𝑔

∅∅

(𝜕

Ө)

2

− (1 − 𝛽𝑚

2

)] = 0

(√𝑔

𝜃𝜃

𝜕

𝜃

Ө + 𝑖√𝑔

∅∅

𝜕

Ө) = 0

eqn (4)and eqn (5) They are identical after cancelling A and B and give

𝐴

6

(𝜕

𝑟

𝑊)

6

+ 𝐴

4

(𝜕

𝑟

𝑊)

4

+ 𝐴

2

(𝜕

𝑟

𝑊)

2

+ 𝐴

0

= 0

With

𝐴

6

= 𝛽

2

𝑓

4

𝐴

4

= 𝛽𝑓

3

(𝑚

2

𝛽 + 2𝛽𝑄 − 2)

𝐴

2

= 𝑓

2

[(1 − 𝛽𝑚

2

)

2

+ 𝛽(2𝑚

2

− 2𝑚

4

𝛽 − 2𝑄 + 𝛽𝑄)]

𝐴

0

= −𝑚

2

(1 − 𝛽𝑚

2

− 𝛽𝑄)

2

𝑓 − 𝜔

2

𝑄 = 𝑔

𝜃𝜃

(𝜕

𝜃

Ө)

2

+ 𝑔

∅∅

(𝜕

Ө)

2

= 0

Neglecting the higher orders of

𝛽

and solving the above equations at the event horizon yields

𝑊(𝑟) = ± ∫( Γ. Λ) 𝑑𝑟

where

Γ = 1

𝑓 √𝑚

2

(1 − 2𝛽𝑚

2

)𝑓 + 𝜔

2

and

Λ = (1 + 𝛽 ((𝑚

2

+ 𝜔

2

𝑓 ))

With :

𝑓(𝑟) = 1 −

2𝑎

𝑟

− 𝑏𝑟

2

The tunneling rate[5] of the spin -1/2 fermion crossing the horizon is

𝛤 = 𝑃

(𝑒𝑚𝑖𝑠𝑠𝑖𝑜𝑛)

𝑃

(𝑎𝑏𝑠𝑜𝑟𝑝𝑡𝑖𝑜𝑛)

= exp(−2Im𝐼

+

) exp(−2Im𝐼

)

= exp (−2Im𝑊

+

− 2ImӨ) exp (−2Im𝑊

− 2ImӨ)

the Hawking temperature

𝑇 = ℏ

4 (𝐼𝑚𝑊(𝑟))

−1

IV. FERMIONS

The equation of motion give by

0 = ∇

𝜗

𝐹

𝜇𝜗𝑎

= 𝑔

𝜗𝛼

[𝜕

𝛼

𝐹

𝜇𝜗𝑎

− 𝛤

𝛼𝜇𝜆

𝐹

𝜆𝜗𝑎

− 𝛤

𝛼𝜗𝜆

𝐹

𝜇𝜆𝑎

+ 𝑔𝑓

𝑎𝑏𝑐

𝐴

𝜗𝑏

𝐹

𝛼𝜇𝑐

]

Where we defined

𝐹

𝜇𝜗𝑎

= 𝜕

𝜇

𝐴

𝜗𝑎

− 𝜕

𝜗

𝐴

𝜇𝑎

+ 𝑔𝑓

𝑎𝑏𝑐

𝐴

𝜇𝑏

𝐴

𝜗𝑐

We assume the vector field

𝐴

𝜇𝑎

= 𝑎

𝜇𝑎

𝑒

−𝑖𝐼

Before simplifying slightly, We obtained finally

0 = 𝑔

𝑡𝑡

[ 1

2

𝑎

𝑡𝑎

(𝜕

𝑡

𝐼)

2

] +𝑔

𝑟𝑟

[ 1

2

𝑎

𝑡𝑎

𝜕

𝑟

𝐼𝜕

𝑟

𝐼 + 𝛤

𝑟𝑡𝑡

𝜕

𝑟

𝑎

𝑡𝑎

− 𝛤

𝑟𝑡𝑡

𝑔𝑓

𝑎𝑏𝑐

𝐴

𝑡𝑏

𝐴

𝑟𝑐

− 𝑔 𝑖

ℏ 𝑓

𝑎𝑏𝑐

𝐴

𝑟𝑏

𝑎

𝑡𝑐

𝜕

𝑟

𝐼]

Taking the semi classical limit we obtain

(𝜕

𝑡

𝐼)

2

= 𝑓

2

(𝜕

𝑟

𝐼)

2

⇒ 𝜕

𝑡

𝐼 = ±𝑓 𝜕

𝑟

𝐼

We perform the separation of variables as follows:

𝐼(𝑟, 𝑡, 𝜃, 𝜑) = Ω𝑡 + 𝑊(𝑟) + 𝐼

(𝜃, 𝜑)

we obtain

= ±𝑓 𝜕𝑊(𝑟)

𝜕𝑟 𝑊(𝑟) = ±Ω ∫ 𝑑𝑟

𝑓

The tunneling rate is given by

(4)

B. CHOUDER

30

𝛤 = 𝑃

(𝑒𝑚𝑖𝑠𝑠𝑖𝑜𝑛)

𝑃

(𝑎𝑏𝑠𝑜𝑟𝑝𝑡𝑖𝑜𝑛)

= exp(−2Im𝐼

+

) exp(−2Im𝐼

)

= exp (−2Im𝑊

+

) exp (−2Im𝑊

)

And therefore, the Hawking temperature reads:

𝑇 = ℏ

4 (𝐼𝑚 ∫ 𝑑𝑟 𝑓

𝑟 0

)

−1

It is worth to mention that we have used Matlab[6] to solve this problem , the equation 𝑟 − 2𝑎 − 𝑏𝑟3= 0 gives 3horizons 𝑟1, 𝑟2, 𝑟2 for each we calculate the temperature of Hawking near 𝑟1, 𝑟2, 𝑟2 . After we draw the corresponding curves

𝑇

1,2,3

= 𝑓(𝑎, 𝑏)

we get

The temperature near 𝑟1

CONCLUSION

We have calculated the Hawking radiation temperature of spin 1/2 particles in the 4-dimensional Schwarzschild-de Sitter spacetime with Hamilton-Jacob method. As it is the case of the spin 1 particles.The tunneling rate and Hawking temperature were represented.

ACKNOWLEDGMENT

We are very grateful to the Algerian Ministry of education and research as well as the DGRSDT for the financial support.

REFERENCES

[1] Deyou Chen ,Houwen Wu and Haitang Yang, Fermion’s tunneling with effects of quantum gravity, (2013) [arXiv:

1305.7104v2 [gr-qc]]

[2] K. Nozari and M. Karami, Minimal length and generalized Dirac equation, Mod. Phys. Lett. A 20 (2005) 3095 [arXiv:0507028[hep-th]].

[3] B R Majhi,,S Samanta Ann. Phys.325:2410-2424 (2010) [arXiv:0901.2258]

[4] Alexandre Yale . Exact Hawking Radiation of Scalars, Fermions, and Bosons Using the Tunneling Method Without Back-Reaction ,(2011) [arXiv: 1012.3165v3 [gr-qc]]

[5] P. Mitra, Hawking temperature from tunnelling formalism, Phys. Lett. B 648 (2007) 240[arXiv:0611265[hep- th]].

The Hawking temperature near 𝑟2

The Hawking temperature near 𝑟3

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