R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
M ARCO B IROLI
An estimate on convergence for an homogeneisation problem for variational inequalities
Rendiconti del Seminario Matematico della Università di Padova, tome 58 (1977), p. 9-24
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convergence for homogeneisation problem for variational inequalities.
MARCO BIROLI
(*)
1. - Intro duction
an d results.Let be Q c I~n an open bounded set with smooth
boundary 1’,
Y =
~n [o, ail (y)
E Loo( Y) i, j
-1, ... ,
~, such thati=l
(where
, > is theduality
betweenHà (Q)
and H-1(Q)
andaij (Y)
are
prolonged
toby periodicity)
andwhere qil
are constants defined as in[3], [9], [10].
(*)
Indirizzo dell’A : Istituto di Matematica del Politecnico di Mi- lano - Via Bonardi, 9 Milano.Lavoro
eseguito
nell’ambito del gruppo G.N.A.F.A. del CNR.Let be
f
E(Q),
we have :Th. 1 - We consider the
problems
let be Us and u the solution
of (1, Ie)
and(1, 1),
we haveMoreover it
we haveThe first
part
of Th. 1 is shown in[7]
for thesymmetric
caseand in
[8], [12]
in thegeneral
caseby
«local energy >>method,
thesecond
part
of Th. 1 is shownby « multiple
scales » method in[8]
[9] (*).
We consider now theproblems
where 1p
is a measurablefunction,
suchthat I v
EHÓ (S~), v y~ ~ ~ ~.
Th. 2 Let be Us and u solution
of (1,3~)
and(1,3)
we have(*) Cf. also [1], [2].
The first
part
of Th. 2 is shown in[11] by
the method of « local energy »(cfr.
also[5]
and[6]),
the secondpart
of Th. 2 is shown in[4] by penalisation
method and H61der-estimates. The aim of this work is show an estimateanalogous
to(1, 2)
in the case of varia-tional
inequalities.
Th. 3.
Let be aij (y) 8
C’-(.Rn) , f e
Lx(Q) , Us (u)
the solutionThe Th. 2 is shown
by penalisation
and«multiple
scales » method.In §
2 we show somepreliminary results, in §
3 westudy
the conver-gence for the
penalised equations
andin §
4 wegive
theproof
ofTh. 3.
Rem. 1
(a)
Thehypothesis
of thepart (I)
are verifiedif y
= 0 :/
x(b)
The result of Th. 3 can begeneralized
to the caset E8
(c)
We don’t know if the estimates in Th. 3 areoptimal ;
2. -
Some preliminary
results.We consider the
penalised problem
LEMMA 1. The
problem (2.1)
has aunique
solutionu-1;
ELoo
(Q)
we haveFrom
(2,1)
we havethen
From
(2,5)
we have uA e C(Q).
We show now
(2,2)
ab absurdum)).We write
Let be
Q’ and
S~~
are open set and,~~
c,~~
c S2’.Let be an open set with smooth
boundary
such that,~;~
cc c
Q"
c ’0’.We have
then from the maximum
principle, [13],
From
(2,8)
we havethen from
(2,7) (2,9)
we have a contradiction.From
(2,1) (2,2)
we have also(2,3).
LEMMA 2.
If .
we haveMoreover
if A
1p E Loo(0)
we haveWe show at first
(2.11).
We observe that if
A y
E L°(S~)
from the lemma 1 we haveIIA
I andrepeating
the calculation of[6]
pg. 76-88 or
[13]
177-197 we havewhere C
depend only
onC.
From
(1,66) (2,1)
we havethen
From
(2,12)
we haveWe
prolongate ul
and uby
0 and we denoteagain
andu these new functions.
From
(2,13)
we havethen
then there
is x
E B(x, e)
such thatFrom
(2,14)
we haveWe choose then
We show now
(2,10).
From the lemma 2.1 of
[7] (the hypothesis
ofsymmetry
is unne-cessary for this
lemma) if y
E(,S2), n
p _ + oo , y there isa sequence such that
where
C3
is a constantdependent only
onI/1J’/lwl,P.
Let
(ur¡)
the solution of theproblem
From
[12]
pg.22, part III,
we fraveFrom
(2,16) (2,21) (2,22)
we haveWe choose
Rem. 1 - We observe that the constants in the lemma 2
depend
only
on norm of the coefficients of A.Lemma 3. We consider the
problems
we have
We consider 0
== 2013Zt-i/ ,
0 E W2,p(Q). Vp,
for the lemma 2.1 of[7]
there is a sequence0~
such thatLet
be us (un)
the solution of theproblem
We have
We
choose q
- 8 and we have the result.3. - The
penalised equation.
We suppose for the moment
f
= 0.We consider the
penalised problems
Lemma 4. We have
We use for the
proof
the« multiple
scales » method.x
Let
be y -
wehave, [8] [9],
E
where
Let be
we have
Let be
where X2 (x ; y)
is notgiven
for the moment.We consider w
= ~c8 - v~ ,
We
choose x2 (x ; y)
such thatX2
(0153 ; y) Y-periodic
in y.We observe that we have
then the
problem (3,4)
has a solution.We observe that
From
(3,5)
we havethen
From
(3,4) (3,5) (3,7)
we haveand, by multiplication
for we caneasily
showWe observe now that
From
(3,6) (3,7) (3,8) (3,9) (3,10)
we havewhere
By
the same method used in[10], [13]
for theproof
of- estimate in
elliptic problems
we havethen from
(3,12)
We consider now the case Let be
we have
We observe that the
problems
are
equivalent
to theproblems
where
We consider now the
problem
From
[12]
pg 22.part
III we haveand from
(3,12)
we havethen
We consider the
problem
and the
corresponding penalised problems
We suppose for the moment
We have
then
We choose then
Let be now 1p e
(Q),
p > n ; there isy~~ , 1pfJ (~
>0).
such
that, [7],
We consider the
problems
From the abowe we have
then
We choose then
.Rem. 1 - We observe that the
dependence
on n of the estimateof th. 3 derive from the
dependence
on n of the estimate in the lemma2 ;
then from(2,13) repeating
our calculations we haveREFERENCES
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andsingularities,
Int. Fluid
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Manoscritto