Season 3 • Episode 02 • Proving Pick’s formula
0Proving Pick’s formula
Season 3
Episode 02 Time frame 2 periods
Objectives :
•
Find, step by step, a proof of Pik's formula.Materials :
•
Lesson : Proof of Pik's formula.•
Beamer : Proof of Pik's formula.•
Paper for posters.1 – Devise a plan for the proof 10 mins
A brainstorming sessionto devise a plan for the proof, moderated by the teaher.
2 – Part 1 : Prove that Pick’s formula is additive 45 mins
The aim of this rst part is to prove that if
P
andT
are two polygons with one edge in ommon, and if Pik's formula holds forP
andT
, it also holds for the polygonP T
obtained by adding
P
andT
.3 – Part 2 : Prove Pick’s formula for any polygon 55 mins
Followthe steps : unit square, retangle, right-angled triangle, any triangle, any onvex
Proof of Pick’s formula
Season 3
Episode 02 Document Lesson
Proposition 1
Pick’s formula is additive : if P and T are two polygons with one edge in common, and if Pick’s formula holds for P and T , it also holds for the polygon P T obtained by adding P and T . This is also true for more than two polygons.
Proof. First, it's obviousfrom the denitions that
A P T = A P + A T
. Then, suppose that Pik'sformulaholdsforthetwopolygons,andweusethesamenotationsasintheprevioussession. Let's all
c
the number of boundary points inommon. Then we see thatI P T = I P + I T + ( c − 2)
and also
B P T = B P + B T − 2( c − 2) − 2 .
Wean dedue that
1
2 B P T + I P T − 1 = 1
2 ( B P + B T − 2( c − 2) − 2) + I P + I T + ( c − 2) − 1
= 1
2 B P + 1
2 B T − ( c − 2) − 1 + I P + I T + ( c − 2) − 1
= 1
2 B P + I P − 1 + 1
2 B T + I T − 1
= A P + A T
= A P T
Sotheformulaalsoholds forthepolygon
P T
.It'seasytoextandthis resulttomorethantwopolygons.
Lemma 1
Pik's formula is true for the unit square and for any retangle with sidesparallel tothe axes.
Proof.Foraunitsquare
S
,we haveA S = 1
,B S = 4
andI S = 0
.As1 2 B S + I S − 1 = 1
,theformulaholds.Then,anyretangle withsidesparalleltotheaxesismadeofunitsquares,
so fromProposition 1,the formulaalsoholds for these retangles.
Lemma 2
Pik's formulaholds for any right-angledtrianglewith itsperpendiular sides parallel tothe axes.Proof. Any suhtriangle
T
isone halfof aretangeR
with sides paralleltothe axes, ut diagonally,andit'slearthat2 A T = A R
.Let'salln
andm
the numberofpointsoneah side of the retangleandd
thenumberof pointsonthe diagonal.Then, asimpleanalysis givesB R = 2( n + m − 2)
andI R = ( n − 2)( m − 2) B T = n + m − 1 + d
andI T = ( n − 2)( m − 2) − d
2
Season 3 • Episode 02 • Proving Pick’s formula
2Then we an ompute on one hand
1
2 B R + I R − 1 = n + m − 2 + ( n − 2)( m − 2) − 1
= n + m − 3 + ( n − 2)( m − 2)
and on the other hand
2( 1
2 B T + I T − 1) = B T + 2 I T − 2
= n + m − 1 + d + ( n − 2)( m − 2) − d − 2
= n + m − 3 + ( n − 2)( m − 2)
The two expressions are equal, and we also know from the previous Lemma that
A R =
1
2 B R + I R − 1
, so we dedue2 A T = A R = 1
2 B R + I R − 1 = 2( 1
2 B T + I T − 1)
whih impliesthat the formulaistrue for triangle
T
:A T = 1 2 B T + I T − 1
.Lemma 3
Pik's formula holds forany lattie triangle.Proof.Thislemmaisproved byagraphial
argument : any lattie trianglean be tur-
ned into a retangle by attahing at most
three suitable right-angled triangles and
one retangle. Sine the formula is orret
fortherighttrianglesandfortheretangle,
italsofollowsfortheoriginaltriangle.This
last step uses the fat that if the theorem
is true for the polygon PT and for the tri-
angle T, then it'salso true for P; this an
be proved in the same way as propostion
one.
b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b b
b b b b b b b
Theorem 1
Pick’s formula is true for any lattice poly- gon.
Proof. This theorem follows from lemma
3, proposition 1 and the fat that any
lattie polygon an be ut into triangles
(triangulated).