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Uniqueness for unbounded solutions to stationary viscous Hamilton-Jacobi equations

GUYBARLES ANDALESSIOPORRETTA

Abstract. We consider a class of stationary viscous Hamilton-Jacobi equations

as

λudiv(A(x)∇u)=H(x,u) in,

u=0 on

whereλ 0, A(x)is a bounded and uniformly elliptic matrix and H(x, ξ)is convex inξ and grows at most like|ξ|q + f(x), with 1 < q < 2 and f LN/q(). Under such growth conditions solutions are in general unbounded, and there is not uniqueness of usual weak solutions. We prove that uniqueness holds in the restricted class of solutions satisfying a suitable energy-type estimate, i.e.(1+ |u|)q¯1u H01(), for a certain (optimal) exponentq. This completes¯ the recent results in [15], where the existence of at least one solution in this class has been proved.

Mathematics Subject Classification (2000):35J60 (primary); 35R05, 35Dxx (secondary).

1.

Introduction

In this paper we consider a class of elliptic equations in a bounded domain

R

N, N >2

λu−div(A(x)∇u)= H(x,u) in,

u=0 on (1.1)

where the functionH(x, ξ)is convex and superlinear with respect toξ.

Equations of this type are sometimes referred to as stationary viscous Hamilton- Jacobi equations and appear in connection to stochastic optimal control problems.

In that context, the convexity of H is a natural assumption. The model example which we are going to treat is the following

λu−div(A(x)∇u)=γ|∇u|q+ f(x) in,

u=0 on (1.2)

Received May 19, 2005; accepted in revised form March 13, 2006.

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whereq >1,λ≥0 and A(x)= (ai,j(x))is a matrix ofL()functionsai,j(x) satisfying uniform ellipticity and boundedness conditions

α|ξ|2A(x)ξ·ξβ|ξ|2 ∀ξ ∈RN, a.e. x . (1.3) Without loss of generality, we can takeγ >0. We draw our attention to the “sub- critical” case, namelyq <2, and, more precisely, to the question of uniqueness of unbounded solutions.

Let us first recall that some regularity condition is needed on f in order that problem (1.2) admits a solution. In the class of Lebesgue spaces, this condition amounts to ask that

fL

N

q(), (1.4)

whereqis the conjugate exponent ofq,i.e. q= q

q−1. Whenq<2, (1.4) implies that fLm() withm < N2, hence solutions are expected to be unbounded.

Moreover since, by Sobolev embedding theorem, one has L

N

q()H1() ⇐⇒ q ≥1+ 2

N , (1.5)

the valueq =1+ N2 is a critical one. Indeed, the solutions belong toH01()only if q ≥1+ N2, whenqis below this value solutions are not only unbounded but have not even finite energy and should be defined in a suitable generalized sense.

The fact that (1.4) is a necessary condition for having solutions can be easily justified by a heuristic argument: if A(x)= I,i.e. in case of the Laplace operator, the Calderon-Zygmund regularity implies that

uLm()uW2,m()⇒ |∇u| ∈Lm() ,

where m is associated tom through the Sobolev embedding, i.e., for N > m, m= N m

Nm. In order to be consistent with (1.2), this means that fLm()and

|∇u| ∈ Lqm()so that it should beqm = m,i.e. m = qN. We refer the reader to [1, 16] for rigorous and sharper necessary conditions on f in order to have weak solutions. It is important to recall that ifλ=0 the data f,γ,αmust also satisfy a size condition in order that a solution exists.

Pioneering results for such kind of equations were given by P.L. Lions ([17, 18]), mainly in case of Lipschitz solutions and includingq > 2. Existence results for the caseq =2 can be found in several works, among which we recall the series of papers by L. Boccardo, F. Murat, J.P. Puel (see e.g. [8, 9]) and more recently, assuming f inLN2(), in [13, 10].

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Under assumption (1.4) with 1<q <2, the existence of a solution for prob- lems as (1.2) has been recently proved in [15] (see also [14]) if either λ > 0 or λ=0 and a size condition is satisfied:

γq−11 f

L N

q() < αqC, (1.6) whereConly depends onqandN.

In this paper we deal with the problem of uniqueness of solutions. Up to now, uniqueness results for problems like (1.2) have been proved in the Lipschitz case ([17]) and in [2, 3] if either solutions are bounded orq = 2. Note that these two cases share a common feature, which is that f is required to be inLm(),mN2: for less summable f as we consider, the approach of these previous papers seems not to work. Some results whenq≤1+ N2 can be found in [4, 5].

When dealing with the question of uniqueness, one has to consider the follow- ing well-known counterexample (see also [17, 1]) forq > NN1

u(x)=Cα(|x|α−1)

α= −2−q

q−1,Cα= (N +α−2)q−11

|α|

 solves −u= |∇u|q in

D

(B1(0)),

uW01,q(B1(0)) . (1.7)

This shows that uniqueness does not hold in the class of weak solutions u in W01,q(), and, ifq >1+ N2, not even in H01()(one can check thatuH01() in this case). It is then natural to look for a suitable class of solutions in which problem (1.2) is well-posed. A linearization argument would suggest that there is uniqueness in the class

usol. of (1.2):|∇u| ∈LN(q1)(). (1.8) On the other hand, ifq >1+N2 (which givesN(q−1) >2), the existence of such kind of solutions can not be obtained unless the Calderon-Zygmund regularity the- orem applies; thus, in order to deal with general (bounded measurable) coefficients ai,j, this approach is not reasonable.

Our main purpose here is to prove the uniqueness of solutions of (1.2) in a regularity class which is consistent with the existence results available from [15].

In this latter paper it has been proved that a natural class of solutions for which both a priori estimates and existence hold is given through the extra energy condition

usol. of (1.2):(1+ |u|)q¯1uH01(), withq¯ = (N2(22)(qq)1). (1.9) We are going to prove that this regularity is precisely what is needed to select a unique solution, so that problem (1.2) is actually well-posed in this class.

Our main result concerns the caseq ≥ 1+ N2, which corresponds to H01() solutions (see (1.5)).

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Theorem 1.1. Let1+ N2q<2. Assume(1.3),(1.4)and that (i) eitherλ >0

(ii) orλ=0and(1.6)is satisfied.

Then problem (1.2) has at most one (distributional) solution u such that (1+

|u|)q¯1uH01(), withq¯ = (N2(22)(qq)1).

Note that the functionuin the counterexample (1.7) satisfies(1+ |u|)r1uH01()for anyr <q¯ but not forr = ¯q, which proves the optimality of our result.

Observe also thatq¯ tends to infinity asq → 2, which is consistent with the case fLN2(), for which existence and uniqueness have been proved (see [13, 3]

respectively) in the class of solutions u such that exp(µu)−1 ∈ H01() for a suitable constantµ.

We leave to Section 2 the proof of Theorem 1.1, actually in a generalized ver- sion which includes problem (1.1) where H is convex and satisfies similar growth conditions. Some extensions to Neumann boundary conditions as well as to the case of unbounded domains is also discussed.

In Section 3 we deal with the case NN1 < q < 1+ N2, which corresponds to fLm()with 1 < m < N2N+2. A similar result as Theorem 1.1 is proved, but since, in this case, solutions do not belong toH01(), we use a slightly stronger formulation than the distributional one, namely uniqueness is proved for so-called renormalized solutions (still in the class (1.9)). This notion (see Definition 3.1), first introduced in [12] for transport equations, is now currently used in several different contexts when dealing with solutions of infinite energy.

Still in Section 3, we prove in fact a more general uniqueness result whenq is below the critical value 1+ N2. Indeed, we will see that ifq ≤1+ N2 then the regularity (1.9) implies (1.8). This fact allows to prove uniqueness through a sim- pler linearization principle, which does not need any convexity argument and which can be applied to more general situations like, for instance, nonlinear operators (see Theorem 3.4). Note that the limiting valueq =1+ N2 is also admitted here; actu- ally, (1.9) and (1.8) coincide in that case withuH01(). On the other hand, as mentioned before, this argument was not possible forq >1+N2 since (1.8) will no more be true in general.

Finally, some further remarks will be discussed at the end of Section 3, includ- ing the caseq < NN1, where uniqueness holds simply inW01,q().

2.

The case

q1+ N2

: finite energy solutions

We consider a natural generalization of (1.2), namely the following equation λu−div(A(x)∇u)=H(x,u) in ,

u=0 on ∂ . (2.1)

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We still assume that λ ≥ 0, that A(x) satisfies (1.3) and that H(x, ξ) is a Carath´eodory function satisfying, for a.e. xand for everyξ

R

N,

ξH(x, ξ) is convex, for a.e.x, (2.2) and the growth condition

q

N N1,2

: |H(x, ξ)| ≤γ|ξ|q+ f(x) , γ >0, f(x)L

N

q(). (2.3) Note that this assumptions include the possibility that the equation contains trans- port terms; indeed, a possible choice for H is

H(x,u)=b(x)· ∇u+γ (x)|∇u|p+ f(x) wherebLN()N

,γLr()and fLN r(p−1)pr−N (), withr(N,+∞] and

N(r1)

r(N1) < p<2− Nr.

In virtue of (2.3) and (1.5), assumingq≥1+N2 corresponds to having data in H1(), so that we can reasonably talk ofH01()weak solutions.

Definition 2.1. We say thatuH01()is a weak subsolution of (2.1) ifH(x,u)L1()and

λ

uξd x +

A(x)∇u∇ξd x

H(x,u)ξd x

∀ξ ∈ H01()L() , ξ ≥0.

(2.4) A supersolution of (2.1) is defined if the opposite inequality holds. A function u being both a subsolution and a supersolution is said to be a weak solution of (2.1).

Our proof of the comparison principle for sub and supersolutions of (2.1) relies on two basic ideas: the first one is that if

−div(A(x)∇w)C|∇w|q

(w+)q¯H01() , (2.5)

thenw≤0; in other words, the homogeneous problem has only the trivial solution in this regularity class. Secondly, we aim at applying inequality (2.5) to (a small perturbation of) the difference of two solutionsuv. In order to do that, we use a convexity argument, which gives account of assumption (2.2).

A further technical tool will be required in order to justify some regularity claimed onuv: here we apply a truncation argument. To this purpose, we introduce the following truncation function

Tn(s)= s

0

θn(ξ)dξ , θn(ξ)=







1 if |ξ|<n 2n− |ξ|

n if n<|ξ|<2n 0 if |ξ|>2n

(2.6)

and we start by giving a sort ofrenormalization principlefor the “truncated” equa- tion.

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Lemma 2.2. Let uH01()be a weak subsolution of(2.1). Then u satisfies, for any nonnegativeξH01()L()and for every n

λ

Tn(u)ξd x+

A(x)∇Tn(u)∇ξd x

H(x,Tn(u))ξd x+ Inu, ξ, (2.7) where InuL1()and is defined as follows:

Inu, ξ = 1 n

{n<u<2n}

A(x)∇uuξd x− 1 n

{−2n<u<−n}

A(x)∇uuξd x

+λ

(Tn(u)n(u))ξd x (2.8) +

(H(x,u)θn(u)H(x,Tn(u)))ξd x. If moreover|u|q¯1uH01(), whereq¯ = (N2(22)(qq)1), we have

n→+∞lim n2q¯1InuL1() =0. (2.9)

Proof. LetξH01()L(),ξ ≥0, and letn>0. Choosing in (2.4) the test functionθn(u)ξwe obtain

λ

n(u)ξd x+

A(x)∇uξθn(u)d x

H(x,u)θn(u)ξd x +1

n

{n<u<2n}

A(x)∇uuξd x− 1 n

{−2n<u<−n}

A(x)∇uuξd x. (2.10)

Recalling thatθn(u) = Tn(u)and defining Inu as in (2.8) we have obtained (2.7).

Now let u be such that|u|q¯1uH01(), whereq¯ = (N2(22)(qq)1). We have, by definition of Inu

n2q¯1InuL1()

n2q¯1

1 n

{n<u<2n}

A(x)∇uu d x+ 1 n

{−2n<u<−n}

A(x)∇uu d x

 (2.11)

n2q¯1

|Tn(u)−uθn(u)|d x+n2q¯1

|H(x,u)θn(u)−H(x,Tn(u))|d x

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Observe that n2q¯11

n

{n<u<2n}

A(x)∇uu d x

{n<u<2n}

A(x)∇uu|u|2q¯2d x

β

¯ q2

{n<u<2n}

|∇|u|q¯|2d xn→+∞→ 0,

(2.12)

and similarly

n2q¯2

{−2n<u<−n}

A(x)∇uu d xn→+∞→ 0. (2.13)

We also have, using Young’s inequality, and by definition ofq,¯

|∇u|q|u|2q¯1q

2|∇u|2|u|2(q¯1)+ 2−q

2 |u|2q¯+2(q−1)2−q

= q

2q¯2|∇(|u|q¯1u)|2+2−q

2 (|u|q¯)2. Since|u|q¯1uH01(), using Sobolev embedding, we conclude that

|∇u|q|u|2q¯1L1() . (2.14) Similarly, since (2q¯ −1)(Nq) = 2q¯ we have that |u|2q¯1L(

N

q)(); since fL

N

q()we deduce that

f |u|2q¯1L1() . (2.15) Now we have, by definition ofθnandTn,

|H(x,u)θn(u)H(x,Tn(u))| ≤[|H(x,u)| + |H(x,Tn(u))|]χ{|u|>n}, hence, using the growth assumption (2.3),

n2q¯1|H(x,u)θn(u)H(x,Tn(u))| ≤2|∇u|q+ f(x))|u|2q¯1χ{|u|>n}. Thanks to (2.14)-(2.15) we conclude

n2q¯1

|H(x,u)θn(u)H(x,Tn(u))|d xn→+∞−→ 0. (2.16) Finally, sinceuL2q¯(),

n2q¯1

|Tn(u)n(u)|d x ≤2

|u|2q¯χ{|u|>n}d xn→+∞−→ 0. (2.17) From (2.11), (2.12), (2.13), (2.16), (2.17) we get (2.9).

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Remark 2.3. IfuH01()is a supersolution of (2.1) then (2.7) holds with the opposite sign, and (2.9) still holds true. In particular, if u is a weak solution of (2.1), then

λ

Tn(u) ξd x+

A(x)∇Tn(u)∇ξd x =

H(x,Tn(u))ξd x + Inu, ξ, withn2q¯1InuL1()→0 provided|u|q¯1uH01().

We come to the main comparison result.

Theorem 2.4. Assume(1.3), (2.2), (2.3)with q≥1+N2. Letλ >0. If u andvare respectively a subsolution and a supersolution of (2.1)such that(1+ |u|)q¯1u

H01()and(1+ |v|)q¯1vH01(), then we have uvin.

In particular, problem (2.1)has at most one weak solution u such that(1+

|u|)q¯1uH01().

Proof. From Lemma 2.2 we obtain that λ

Tn(u) ξd x +

A(x)Tn(u)∇ξd x

H(x,Tn(u))ξd x+ Inu, ξ, (2.18) and

λ

Tn(v) ξd x+

A(x)∇Tn(v)∇ξd x

H(x,Tn(v))ξd x + Inv, ξ, (2.19) for everyξH01()L(),ξ≥0.

Let nowε(0,1)be fixed. Subtracting (2.18) and (2.19), we obtain λ

[Tn(u)(1−ε)Tn(v)]ξd x+

A(x)∇(Tn(u)(1−ε)Tn(v))∇ξd x

[H(x,Tn(u))(1−ε)H(x,Tn(v))]ξd x+ Inu, ξ(1−ε)Inv, ξ. Now we use the convexity assumption onH, which gives

H(x,p)(1−ε)H(x, η)+εH

x, p(1−ε)η ε

,p, ηRN. With p= ∇Tn(u),η= ∇Tn(v)we obtain

H(x,Tn(u))(1−ε)H(x,Tn(v))εH

x,Tn(u)(1−ε)∇Tn(v) ε

, hence we have

λ

[Tn(u)(1−ε)Tn(v)]ξd x+

A(x)∇[Tn(u)(1−ε)Tn(v)]∇ξd x

ε

H

x,∇[Tn(u)(1−ε)Tn(v)] ε

ξd x+ Inu, ξ(1−ε)Inv, ξ.

(2.20)

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We define now

wn =Tn(u)(1−ε)Tn(v)εϕ , (2.21) whereϕis a positive function that belongs toH01()and will be chosen later. From (2.20) we obtain

λ

wnξd x +

A(x)∇wn∇ξd xε

H

x,wn

ε + ∇ϕ

ξd x

−ε

λϕ ξ +A(x)∇ϕ∇ξd x

+ Inu, ξ(1−ε)Inv, ξ.

(2.22)

Using assumption (2.3) we have H

x,wn

ε + ∇ϕ

γ ∇wn

ε + ∇ϕ

q+ f(x)

+δ)|∇ϕ|q +Cδ ∇wn

ε

q+ f(x) ,

(2.23)

whereδis any positive constant.

Using (2.23) in (2.22) we obtain λ

wnξd x +

A(x)∇wn∇ξd xCδ εq1

|∇wn|q ξd x

−ε

λϕ ξ +A(x)∇ϕ∇ξ+δ)|∇ϕ|qξf(x)ξ d x

(2.24)

+Inu, ξ(1−ε)Inv, ξ. We choose nowϕas a solution of

λ ϕ−div(A(x)∇ϕ)=+δ)|∇ϕ|q+ f(x) in ,

(1+ |ϕ|)q¯1ϕH01(). (2.25) The existence of such a functionϕis proved in [14]. Moreover, we have thatϕ≥0 (since f ≥0 from (2.3)). Thanks to (2.25) we obtain from (2.24)

λ

wnξd x+

A(x)∇wn∇ξd xCδ εq1

|∇wn|q ξd x

+Inu, ξ(1−ε)Inv, ξ. (2.26) Forl>0, we choose in (2.26)ξ =ξn defined as

ξn =[(wnl)+]2q¯1.

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Note thatξn is a positive function, and it belongs to H01()L(). Moreover, by the definition ofwnin (2.21), we have

ξnL()(2n)2q¯1, so that we can apply Lemma 2.2 foruandvand get

|Inu, ξn| ≤(2n)2q¯1InuL1()n→+∞−→ 0

|Inv, ξn| ≤(2n)2q¯1InvL1()n→+∞−→ 0. Thus (2.26) implies

λ

wn[(wnl)+]2q¯1d x +(2q¯−1)

A(x)∇wn∇wn[(wnl)+]2q¯2d x

Cδ εq1

|∇wn|q [(wnl)+]2q¯1d x+o(1)n,

whereo(1)ngoes to zero asntends to infinity. Neglecting the zero order term which is positive, and using that A(x)αI, we have

α(2q¯−1)

|∇wn|2[(wnl)+]2q¯2d x

Cδ εq1

|∇wn|q [(wnl)+]2q¯1d x+o(1)n.

(2.27)

Young’s inequality implies Cδ

εq1

|∇wn|q [(wnl)+]2q¯1d xα

2(2q¯−1)

|∇wn|2[(wnl)+]2q¯2d x +Cε,δ

[(wnl)+]2q¯+2(q−1)2−q d x, hence, using that 2q¯+ 2(2qq1) = ¯q2we get

α

2(2q¯−1)

|∇wn|2[(wnl)+]2q¯2d xCε,δ

[(wnl)+]q¯2d x+o(1)n. Using Sobolev inequality in the left hand side we obtain

C

[(wnl)+]q2¯ d x 12

NCε,δ

[(wnl)+]q2¯ d x +o(1)n. We let nowntend to infinity; sinceu,vandϕall belong toLq2¯ (), we have that

wnw := u(1−ε)vεϕ strongly inLq2¯ ()asntends to infinity,

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hence we get C

[(wl)+]q2¯ d x 12

NCε,δ

[(wl)+]q2¯ d x.

Since 1− N2 < 1, last inequality implies thatw≤ 0; indeed, if supw > 0 (even possibly infinite), one gets a contradiction by lettinglconverge to supwand using that [(wl)+]q2¯ would tend to zero inL1().

The conclusion is thatw≤0,i.e.

u(1−ε)v+εϕ , and, lettingε→0,uvin.

Let us now deal with the case λ = 0. Then, the same proof can be applied provided there exists a solution of

−div(A(x)∇ϕ)=+δ)|∇ϕ|q+ f(x) in ,

ϕ=0 on ∂, (2.28)

for someδ >0. This requires a further assumption, which is a sort of size condition on the data.

Indeed, it is known from [14] that there exists a constantC, only depending onqandN, such that if

bq−11 f

L N

q() < αqC (2.29) then the problem

−div(A(x)∇z)=b|∇z|q+ f(x) in ,

z=0 on (2.30)

admits a solutionzsuch that(1+ |z|)q¯1zH01(). In particular, if we fixα(the coercivity constant ofA(x)) and f, the set

B

f :=

b>0 : problem (2.30) has a solutionz:(1+ |z|)q¯1zH01() is non empty. Indeed, it is not difficult to see that

B

f is even an interval. In order to assure that (2.28) has a solution for a certainδ >0, we are then led to assume that (2.3) holds withγ <sup

B

f.

Theorem 2.5. Let λ = 0. Assume (1.3), (2.2) and(2.3) with q ≥ 1+ N2 and γ <sup

B

f, which is defined above. If u andvare respectively a subsolution and a supersolution of(2.1)such that(1+|u|)q¯1uH01()and(1+|v|)q¯1vH01(), then we have uvin.

In particular problem(2.1)has at most one solution u such that(1+|u|)q¯1uH01().

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The result of Theorem 2.5 may also be rephrased more explicitly in terms of a size condition on the norm of f. Indeed, letCbe the maximal possible choice in (2.29),i.e.

C= sup{C >0 : ifαqbq−11 f

L N

q() <C then problem (2.30) has a solutionz: (1+ |z|)q¯1zH01()}.

Then we have:

Corollary 2.6. Letλ=0. Assume(1.3), (2.2)and(2.3)with q≥1+ N2 and αqγq−11 f

L N

q()<C . (2.31)

Then problem(2.1)has at most one solution u such that(1+ |u|)q¯1uH01(). Remark 2.7. Applying Theorem 2.4 and Corollary 2.6 to the model problem

λu−div(A(x)∇u)=γ|∇u|q+ f(x) in,

u=0 on (2.32)

we obtain the results stated in Theorem 1.1. Observe that ifγ >0 and fLqN(), one can easily prove thatanyweak solution satisfies(u)q¯H01(); in particular, in that case uniqueness holds in the class of solutionsuH01()such that(u+)q¯H01(). Clearly, when γ is negative we should apply the result to the equation satisfied by−u.

Remark 2.8. When considering the caseλ= 0, a more careful look at the proof of Theorem 2.4 shows that in the inequality (2.23) one could replace f with f˜ = sup

ξ (H(x, ξ)−γ|ξ|q)+. The size condition of Theorem 2.5 and Corollary 2.6 would then concern f˜instead of f. If one looks at the model problem (2.32), this simply means that ifλ=0 andγ >0, the required size condition only concerns f+, as it is expected.

Remark 2.9. Whenq → 2, the exponentq¯ → +∞. In fact, ifq = 2 uniqueness for problems like (2.32) holds in the class of solutionsuH01()such thateµu− 1 ∈ H01() for some suitableµ > 0. This result is proved (in a more general framework) in [3]: the idea is to use the change of unknown functionv=eγu−1, so that the standard choice is to takeµ = γ and to prove uniqueness whenvH01(). Otherwise one could takeµ= for somen>1; in that case one proves uniqueness for solutions such that|v|n1vH01(). However, we point out that this latter choice requires to apply to the equation ofva similar truncation argument as in Lemma 2.2.

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2.1. Comments and extensions 1. Data inW1,r

The results of this section still hold if the right hand side in (2.1) is replaced by H(x,u)+div(g(x))withg(x)LN(q1)().

2. Neumann boundary conditions

Our method easily extends to prove a comparison principle for the homogeneous Neumann problem which can be written in a strong form as

λu−div(A(x)∇u)= H(x,u) in ,

A(x)∇u·ν(x)=0 on ∂, (2.33)

where ν(x)is the outward, unit normal vector toat x. Of course, we use the classical weak formulation which says thatuH1()is a weak solution of (2.33) if

λ

uϕd x+

A(x)∇u∇ϕd x =

H(x,u)ϕd x ∀ϕ∈ H1()L().

Then one has:

Theorem 2.10. Assume(1.3), (2.2), (2.3)and thatλ > 0. Let q ≥1+ N2. If u andvare respectively a subsolution and a supersolution of(2.33) such that (1+ |u|)q¯1uH1()and(1+ |v|)q¯1vH1(), then we have uvin. In particular, problem (2.33)has at most one weak solution u such that (1+

|u|)q¯1uH1().

Proof. The proof follows the same steps as for Theorem 2.4. Note that Lemma 2.2 is still true without any modification. Then one definesϕas a solution of

λ ϕ−div(A(x)∇ϕ)= +δ)|∇ϕ|q+ f(x) in ,

A(x)∇ϕ·ν(x)=0 on ∂,

and, settingwn =Tn(u)(1−ε)Tn(v)εϕ, one obtains λ

wn[(wnl)+]2q¯1d x +α

2(2q¯−1)

|∇wn|2[(wnl)+]2q¯2d x

Cε,δ

[(wnl)+]q2¯ d x +o(1)n. Sinceλ >0 one deduces

[(wnl)+]q¯H1()≤ ˜Cε,δ

[(wnl)+]q2¯ d x+o(1)n.

Using now Sobolev inequality one concludes as in the Dirichlet case. We only need to require here thathas enough regularity so that the Sobolev inequality holds.

(14)

3. Unbounded domains

A slight refinement of our proof gives a similar result in case of unbounded do- mains. To be more precise, letbe a general domain, not necessarily bounded.

Let stillq ≥1+ N2 and setq¯ = (N2(22)(qq)1). We denote by D01,2()the space obtained by completion of functions ϕCc() with respect to the norm

∇ϕL2(). It is well known that D01,2() is a Banach space which, due to Sobolev inequality, is continuously embedded intoL2(), namely

vL2()SN∇vL2()=SNvD1,2

0 () ∀v∈D10,2() , where SN, the Sobolev constant, does not depend on, but only on the dimen- sionN.

By a solution of (2.1) we mean a functionusuch that

H01() ∀ψ ∈Cc(RN) , |u|q¯1uD01,2() (2.34) and

λ

uξd x+

A(x)∇u∇ξd x =

H(x,u)ξd x ∀ξ∈Cc() . (2.35) Note that condition (2.34) gives a meaning to the Dirichlet condition on; roughly speaking, one has (in a weak sense)u=0 onBRfor any ballBR. Under assumptions (1.3), (2.2)-(2.3), the existence of a solution of (2.1) in the sense of (2.34)-(2.35) has been proved in [15]. It was also pointed out that, due to the regularity of |u|q¯1u, one can use in (2.35) any test function ξ of the formS(u), whereS(0)=0 and|S(t)| ≤ |t|2q¯2. This is achieved by choosing ξ = S(u) ζ(|xn|), whereζCc(B2),ζ ≡1 onB1, and lettingngo to infinity, which is allowed thanks to (2.34) and (2.2)-(2.3).

Theorem 2.11. Assume(1.3), (2.2), (2.3)with q≥1+ N2, and that (i)eitherλ >0

(ii)orλ=0and(2.31)holds true.

Then there exists at most one solution u of(2.1)in the sense of(2.34)-(2.35).

Proof. Note that Lemma 2.2 still holds true,i.e.(2.7) holds for anyξCc(RN), and estimate (2.9) is still valid, since it only depends on the fact that|u|q¯1uD10,2(). We proceed then as in Theorem 2.4: letϕbe a solution (whose exis- tence is proved in [15]) of the auxiliary problem

λ ϕ−div(A(x)∇ϕ)=+δ)|∇ϕ|q+ f(x) in ,

|ϕ|q¯1ϕD10,2() , ϕψH01()for anyψCc(RN). Definingwn=Tn(u)(1−ε)Tn(v)εϕwe obtain

λ

wnξd x+

A(x)∇wn∇ξd xCδ εq1

|∇wn|q ξd x + Inu, ξ(1−ε)Inv, ξ,

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