A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
A. S TOIMENOW
The Jones polynomial, genus and weak genus of a knot
Annales de la faculté des sciences de Toulouse 6
esérie, tome 8, n
o4 (1999), p. 677-693
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- 677 -
The Jones Polynomial,
Genus and Weak Genus of
aKnot (*)
A. STOIMENOW (1)
E-mail: alex@mpim-bonn.mpg.de,
www:http://www.informatik.hu-berlin.de/~stoimeno
Annales de la Faculte des Sciences de Toulouse Vol. VIII, n° 4, 1999
pp. 677-693
Le genre faible (ou genre canonnique), c.a.d., Ie genre mini- mal de toutes les surfaces de Seifert obtenues par l’algorithme de Seifert
a partir d’un diagramme du noeud quelconque, est etudie dans le travail de Morton
[MPCPS
99 (86),107-109].
Il montre (en utilisant le polynomede HOMFLY-PT) que ce genre est parfois strictement superieur au genre de Seifert classique.
Dans cet article on montre que les doubles des sommes connexes iterees d’un noeud K ont un genre faible qui croit infiniment, si le polynome de
Jones du double de K vérifie une certaine condition. (Le genre de ces doubles des sommes connexes itérées est pourtant toujours egal a 1.) On
donne des exemples.
ABSTRACT. - The weak (or canonical) genus, i.e., the minimal genus of all Seifert surfaces obtained by the Seifert algorithm applied on any dia-
gram of the knot, appears implicitly in the work of Morton
[MPCPS
99 (86),101-104],
where he shows (using the HOMFLY-PT polynomial) thatthis genus is sometimes strictly greater than the classical Seifert genus.
In this paper, it is shown that for any knot K, fow which the Jones polyno-
mial of a double satisfies a certain condition (almost to be the polynomial
of a twist knot), the weak genus of the (genus one) doubles of the iterated connected sums of K grows unboundedly. Examples are given.
( * > Recu le 1 er juin 1999, accepte le 6 decembre 1999
~) > Support by a DFG postdoc grant is gratefully acknowledged.
Max-Planck-Institut fur Mathematik, Vivatsgasse 7, D-53111 Bonn, Germany, Postal
Address: P.O. Box: 7280, D-53072 Bonn.
1. Introduction
In his book
[Ad,
p. 105bottom],
C. Adams mentions a result of Morton that there existknots,
whose genus g isstrictly
less than their weak genusg,
the minimal genus of
(the
surface of Seifert’salgorithm applied on)
all theirdiagrams.
This observation appearsjust
as a remark in[Mo],
but was verystriking
to the author. Motivatedby
Morton’sexample,
the author started in a series of papers[St2, St, St3]
thestudy
of the invariantg.
Akey
role inwhat we can say so far about
9 plays [St2,
theorem3.1], saying
that knotsof
given 9 decompose
intofinitely
many sequences of the kind introduced in[St4],
and called there"braiding sequences" ,
thatis,
can be obtained fromfinitely
manydiagrams by
successiveapplications
ofantiparallel
twists at acrossing
This theorem has several direct consequences, inter
alia,
to the enumeration of such knots or theproperties
of their knotpolynomials.
In this paper, we extend the series of boundedness and
stability
crite-ria for the Jones
polynomial
V[J], presented
in[St]
forpositive knots,
toalternating
knots. We make moreprecise
our observation of[St3],
that anycoefficient of V of an
alternating
knot has an upperbound,
which ispoly-
nomial in the
crossing
number for fixed genus,by writing
down anexplicite
estimate.
Furthermore,
we show that the value range of any sequence of fixedlength
ofleading
ortrailing
coefficients of V of analternating
knot ofgiven
genus stabilizes as itscrossing
number goes toinfinity.
Both
properties
aregeneralized
inslightly
weaker forms tonon-alternating
knots.
Finally,
we use these extensions togeneralize
Morton’sexample
toa series of knots with fixed genus, but
arbitrarily high
weak genus.Thus, unfortunately,
no control from below can beexpected
on g fromg.
It is to be
expected
that aproof
forspecific
series ofexamples
ispossible by
skein module calculations alsousing
Morton’sinequality [Mo]
max
degv P/2 g involving
the maximaldegree
of the v variable in the HOMFLYpolynomial
P[H].
We decidehere, however,
to present a crite-rion
using
the Jonespolynomial (and
moreexactly
the Kauffmanbracket),
whose derivation is more
analytical.
2. Preliminaries
The Jones
polynomial [J]
is a Laurentpolynomial
in one variable t(more
precisely
in its squareroot)
associated to an oriented knot or link inS3
andcan be defined
by being
1 on the unknot and the(skein)
relationwith
V+, V_ , V)( denoting diagrams equal
except near onecrossing,
which isresp.
positive, negative
and smoothed out.Briefly
after Jones’sdiscovery,
Kauffman[Ka]
found another definition of this invariant called "Kauffman’s state model" or "Kauffman bracket"(see
also[Ad, §6.2]).
Recall,
that the Kuaffman bracket(D)
of adiagram
D is a Laurentpolynomial
in a variableA,
obtainedby summing
over all states the termswhere a state is a choice of
splittings
oftype
A or B for anysingle crossing (see figure 1), #A
and#B
denote the number oftype
A(resp. type B) splittings and ISI
the number of(disjoint)
circles obtained after allsplittings
in a state.
Fig. 1 The A- and B-corners of a crossing, and its both splittings. The corner A (resp. B) is the one passed by the overcrossing strand when rotated counterclockwise
(resp. clockwise) towards the undercrossing strand. A type A (resp. B) splitting is
obtained by connecting the A (resp. B) corners of the crossing.
The Jones
polynomial
of a link L is related to the Kauffman bracket ofsome
diagram
of it Dby
The Kauffman bracket skein module of a room
(a
disc with a distin-guished
number ofpoints
on itsboundary)
is themodule,
say, overZ,
gen-erated
by isotopy
classes of inhabitants of this room(tangle diagrams
in thisdisc, intersecting
itsboundary exactly
in thedistinguished points),
and withrelations
corresponding
toresolving
thecrossings according
to the Kauffman bracket relation.See,
e. g.,[BFK].
The concept of a
braiding
sequence was introduced in[St4]
in the contextof Vassiliev
invariants,
butsubsequently
turned out to be more useful in aspecial
case whenconsidering
knotdiagrams,
on which the Seifertalgorithm [Ad, §4.3~ gives
a surface ofgiven
genus.(We subsequently
call this genus the genus of thediagram.)
DEFINITION 2.1. - A
t2-move
is the move in adiagram
D is areplace-
ment
of (a neighborhood of)
somedistinguished crossing
in Dby
thetangle of
3antiparallely
twistedcrossings,
as shown in(1).
.A
braiding
sequence associated to adiagram
is afamily of diagrams;
parametrized by c(D)
odd numbers xl, ...(where c(D) henceforth
de-notes the number
of crossings of D),
each oneindicating
the numberof t2
moves
performed
at eachcrossing.
Weadopt
the convention thatfor
xi 0we switch the
crossing
numberedby
i andapply (-xi - 1) t2
moves on theswitched
crossing.
We consider
crossings
asequivalent, if they form
a revsereclusp,
so thatt2
on eitherof
them have the sameeffect
on thediagram.
The maximal numberof (such equivalence
classesof) crossings
overdiagrams of
genus gwe call
dg .
THEOREM 2.1
(theorem
3.1of
Knotdiagrams of given
genusdecompose
intofinitely
manyequivalence
classes modulot2
moves and theirinverses. That
is, they
all can be obtainedfrom finitely
many(called "gen- erating") diagrams by repeated t2
moves.3. The Jones
polynomial
ofalternating
knots ofgiven
genusDirectly
from[St2,
theorem3.1~,
in theproof
of theorem 9.3 of[St]
wementioned a way how to compute V on a whole
braiding
sequence from the Jonespolynomials
of thegenerating diagram (as
defined in[St2])
and allits
crossing-changed
versions. From thisprinciple,
thefollowing
observation isrelatively straightforward,
but in view of the results of[St3, §6~ maybe
should be recorded in its own
right.
THEOREM 3.1. - There exists a constant
C,
such thatfor
any alter-nating
knot K and any k E Z it holdswhere
c(K)
denotes thecrossing
numberof
K andg(K)
its genus,(V~tk
isthe
coefficient of t~
inV,
anddg~K~
can bedefined by
Remark 3.1. - For fixed
c(K)
the maximal value on theright
of(3.5)
isattained at k =
c(K)/e,
which isexponential
inc(K). Therefore,
the essenceof this theorem is the claim that the coefficients of V for K
alternating
growpolynomially
inc(K)
for fixedg(K).
This wasalready
noted in~St3~,
buthere we
give
this moreexplicite
estimate.Proof.
- This isbasically
arepetition
of theproof
of theorem 9.3 in[St].
If
Vn
denote the Jonespolynomials
ofLn ,
whereLn
are links withdiagrams Dn equal
except in one room, where nantiparallel
half-twistcrossings
areinserted,
then from the skein relation for the Jonespolynomial
we havewith
Voo denoting
the Jonespolynomial
ofLoo ,
which is the link obtainedby smoothing
outa(ny) crossing
in the room.We consider now a
diagram
D in abraiding
sequence ofdiagrams
ofgenus
g(D) = 9
and some number of parameters ddg,
wheredg
can bedefined
by (3.6).
We haved > 2g
+ 1 because of the(2, 2g
+1)-torus
knotdiagram.
Then
expand
the relation(3.8)
with respect to any of the dcrossings,
at which
t2
moves can beapplied, obtaining 2d
terms to theright.
So theirnumber in
exponentially
boundedin g,
and hence it suffices to prove theinequality
for each termseparately.
Each term is of the form
with k
d, k’
E Zand 03A3ai
=O(c(D)),
wherec(D)
denotes thecrossing
number of
D,
and Lbeing
a link obtainedby smoothing
out(according
tothe usual skein
rule)
some set ofcrossings
in thegenerating diagram.
Butthe
crossing
number of L islinearly
bounded ind,
hence all its coefficientsare
exponentially
bounded in d.Then,
the coefficient sum of theproduct
term is at most
_
From this the theorem
follows,
asby [Ka2, Mu, Th]
for analternating diagram
D of analternating
knotK,
we havec(D)
=c(K),
andby ~Ga~, g(D)
=g(K).
. 0Remark 3.2. C can be in
principle
written downexplicitly. However,
the
resulting
number so far has an unattractivemagnitude. By [St], d9
97 .
8-2 - 6 7 for
> 2 but here it is possibly as well fertile to think aboutsharper
bounds.Another
straightforward
consequence wasalready
noted in[St]
and isrepeated here,
because it will be related to the extension of Morton’s exam-ple.
PROPOSITION 3.1. - Let t E
sl :_ ~ z
E C :’z)
=1 ~.
. Then~ VK(t)
:g(K)
=g ~
C C is boundedfor
anyProof. Repeat
theprevious formulas, noting
that thepartial
sums ofthe Neumann series of
t2
andt-2
are both boundedif t ~
= 1. DFinally,
we come to the announcedstability
result for the"edges"
of theJones
polynomial.
DEFINITION 3.1. For some
polynomial
V E7L~t, t-1~ define
the min-imal and maximal
degree
and the span(elsewhere
called"breadth",
not tothe author’s
taste) of
Vby
min deg V: = min{a ~ Z
:[V]ta ~ 0}
,max deg V
:=
max~
a E Z : :[V]ta ~ 0 ~
, and span V : :=max deg
V -min deg
V .Then the list
03BBlV of
V ’sleading coefficients of length
l is thel-tuple ([V,tmindeg V+-k ~~ O
EAnalogously define
the listTl V of
thetrailing coef- ficients of
Vof length
l.THEOREM 3.2. - Fix g, l and n mod 2. Then the sets := : K E and
Tl,g
:=~ TIVK
: K E(with An,g
as in(3. 7))
stabilizeas n -~ oo, that
is,
are all the same when n > nofor
some no . .Pmof.
- Theproof
of thisproperty
isclosely
related to itsanaloga
forpositive
knots from[St3, §6].
We show itjust
forAI V (because 03BBlVK
=lV!K
,so in fact =
T~).
By recalling carefully
theproof
of theorem 6.2 of[St3]
for the case t =0,
we see that if for i mod 2 fixed are links as in
(3.8) (that is,
a one-parameter antiparallel
twistsequence),
then and moregenerally
the +
1 )-tuple
any ~Z,
stabilize as z ~ oo,with the
property,
that a(not necessarily minimal) point
of stabilization mo, thatis,
anumber,
such that = resp.for all mo , is
dependent
on k resp.ll,2,
but(very crucially) indepen-
dent on the link
diagram
outside of the twistbox, assuming
mindegV
isuniformly
bounded from below(see
remark 3.3below).
We now have the
following
LEMMA 3.1. - Let D be an
alternating diagmm
and D’ be obtainedfrom
Dby applying
a(antiparallel)
twist at anyof
itspositive
resp. nega- tivecrossings.
ThenmindegV(D)
=min deg V (D’)
resp.maxdegV(D)
=max deg V ( D’ ) .
.Proof.
- Firstforget
about D’s orientation and consider its unoriented version. It can be seen from theexpression
ofmin deg V
andmax deg V
interms of the checkerboard
shading (see [Ad,
pp.160-162]
or[Ka3])
thatunder a twist
(in
the unorientedversion) min deg V changes only locally,
i. e.,
by something independent
on the rest of thediagram.
Now, considering again
D withorientation, min deg V
has a lower[St3,
lemma
6.1]
and upper[St6,
theorem4.2]
bounds in terms of thediagram
genus
(which
is fixedby
anantiparallel twist)
and the number ofnegative crossings (which
ispreserved
aswell,
if the twist is at apositive crossing),
hence min
deg V (D)
ranges within some finite interval underantiparallel positive
twists. But if the localchange
ofmin deg V
were non-zero,by
ap-plying
successive furthertwists,
we would be able topush mindegV(D) arbitrarily high
orlow, contradicting
one of the bounds.Applying
the argument on the mirrorimages,
we get the statement formax
deg
V andnegative
twists. DRemark 3.3. -
Therefore, twisting
atpositive crossings,
mindeg
V staysalways
the same. But then we see, that thedependence
of mo on k resp.ll,2
is in factjust
adependence
on k -min deg V
resp.ll,2
-min deg V,
because of the freedom to rescale V
by
a power of t(this
is not very clear from thegenerating
seriesrepresentation
of[St3, §6]).
This is the secondcrucial
point.
Prepared
with lemma 3.1 and thisobservation,
fix g, and consider sep-arately
any of thefinitely
manybraiding
sequences ofalternating (knot) diagrams
of genus g, and also consider therein all the twist boxesseparately.
First consider the twist boxes with
positive crossings.
From lemma 3.1 and remark we see that
al V
stabilizes after mo twists for some mo at anypositive crossing (under
further twists at thatcrossing), independently
on how many twists have been done at thenegative crossings.
Therefore,
to capture all contributions of knots in thisbraiding
sequence toal V it
suffices to considerseparately
thefinitely
many cases, where at eachpositive crossing
at most mo twists areperformed. Therefore,
we fix for the rest of theproof
the number of twists at eachpositive crossing.
We now show that the same argument can be made to
apply
for(twists at)
thenegative crossings.
Recall that
(3.8)
is theexplicit
form of the recursive relationwith the
subscripts
of Vdenoting
the number ofpositive (half )twists.
Nowconsider for a
diagram
D in the sequencewith
c(D) being
thecrossing
number of D. Then because of = +2m,
V’again
satisfies(3.10),
but this time withsubscripts
of Vdenoting
the number ofnegative
twists. As D isalternating, by [Ka2, Mu, Th], min deg V’ ( D ) = - mindegV(!D), where
! D is the mirrorimage
ofD,
and
applying negative
twists at D is the same asapplying positive
at!D,
which
by
lemma 3.1 fixesmindegV( !D), hence
alsomindegV~(D).
.Therefore, having
fixed the number of twists at thepositive crossings
in
D,
we are interested in theleading l
coefficients(that
now have fixedpositions)
of thepolynomials
V’ of thediagrams D,
whichagain satisfy (3.10)
in every twistbox,
thesubscripts counting
the number ofnegative
twists. But because of
(3.10),
and its iterated version(3.8),
these coefficients stabilizeby
thepositive
twist case argument. DRemark 3.4. - Note that the use of
[Ka2, Mu, Th]
is crucial - we needupper control on
min deg V’(D),
hence a lower control on the span ofV (D)
from
c(D).
Theonly (in fact, larger)
class ofknots,
for which such con-trol exists are the
adequate
knots of Lickorish and Thistlethwaite[LT] .
Itwould be
interesting,
whether any of the resultsgeneralize
to these knots.However,
much trouble isexpected
because of the need of existence of anadequate diagram
of minimal weak genus. On the otherhand,
from(3.8)
itcan be
hoped,
that a more carefulanalysis
can prove the theorem 3.2 in fullgenerality.
We conclude
by
another property of the Jonespolynomials
which is notexpected
to holdalways,
but at least"generically"
withgrowing crossing
number - the
2-periodicity
almosteverywhere
of their coefficients. Wejust
draw attention to the
problem, leaving
it open.DEFINITION 3.2.2014 Call
[m, n]
C~min deg V, max deg V] for
some V Et-1 ~
and m, n E Z with n > m + 2 a2-periodic
intervalof V if
=[V]tk+2 for
each k E[m,
n -2~.
Denote thisby [m, n]
E2p(V).
CONJECTURE 3.1
for
anyfixed
g.4.
Inequalities
fornon-alternating
knotsWe show now a version of theorem 3.1 for
non-alternating
knots. Ananalogon
to theorem 3.2 is a consequence of it.THEOREM 4.1. - There is some constant C > 0 such that
for
any knot K and any k E Z it holdsProof.
- If K has adiagram
D ina d-parameter antiparallel braiding
sequence of
diagrams
of genusg(K) (so d ~
asbefore,
from(3.8)
you have that
VK
is the sum of2d
terms of the form(3.9),
with k’ EZ,
k ~ d andc(L) ~
2d.Therefore, VK(t) . (t
+ is the sum of terms as in(3.9),
but this time with theproduct
of 1 - and so the coefficients ofare bounded
independently
onc(D) by something exponential
in d.
Now, w.l.o.g., multiply VK(t)
:=VK(t) . (t
+1)d by
a power of t, so that it to have minimaldegree
0(i.
e., to be an honestpolynomial
it t withabsolute
term).
TheTaylor expansion
of around t = 0 has an n-thcoefficient,
which is in n, withO( . ) independent
on d.Therefore,
~
(t +
in k withO( . ) depending exponentially
in d.But
clearly [VK(t) .
-~t +
= 0 for k > spanU~,
so the first assertionfollows. The second
inequality
follows from[Ka2, Mu, Th].
DCOROLLARY 4.1. -
{~l VK
:g(K) = g ~ is finite for any I
and g.Proof.
- Use thebijection
between~i VK
and~~ VK,
and prove the as-sertion for
Àl if K .
. DA more detailed
study
may also show astabiliy
property of somekind,
for
example,
when spanVK
--> oo.COROLLARY 4.2
for
some constant Cindependent
onk,
K and g, thatis, VK (t) .
hasbounded
coefficients
over all K withg(K)
= g, and moreover the numberof
non-zero
coefficients of VK(t) . (t
+ is also boundedfor fixed
g. D COROLLARY 4.3. - For Kpositive
we havefor
some constant Cdepending
ong(K).
. Inparticular,
the areonly finitely
many
positive
knots with Jonespolynomial of given
minimal andmaximal,
or
just maximal, degree.
Proof.
Use theinequality [St7,
theorem6.1~
for v2= -1/6V"(1).
. 0Remark 4.1. In
(4.11),
spanVK
-I-1 may stronger bereplaced by
thenumber of non-zero coefficients of
VK,
andc(K) by
the maximalcrossing
number of a
positive
reduceddiagram
of K.COROLLARY 4.4
(see conjecture
9.1of
-Among
the Jonespoly-
nomials
of
knotsof given g, only finitely
manypolynomials of given
spanoccur.
Proof. By
theorem4.1,
Jonespolynomials
of knots ofgiven g
withgiven
span haveonly finitely
many coefficient lists between minimal and maximaldegree.
But(for knots,
unlike forlinks)
the coefficient list recoversthe minimal
degree (amd
hence thepolynomial),
becauseV(I)
= 1 andV’(1)
= 0. D5. Genus and weak genus
DEFINITION 5.1. - The untwisted double
tangle of
a knot is obtainedby cutting
the knotdiagram
replacing
each strandby
twoand
adding
a numberof half-twists,
which aredoubly
as many as the writheof
the knotdiagmm (5.13),
and arepositive
whenorienting
the strandsantipamllelly
(with
the usual convention that -1half-twist
is ahalf-twist
with thecrossing changed).
Atangle
obtainedby
any other numberof half-twists
is calledtwisted double
tangle of
the knot. Thedifference of
the numberof
itshalf-
twists and the number
of half-twists of
the untwisted doubletangle
is calledthe twist
of
the twisted doubletangle.
Let wt be the
tangles ::IT. and ~~.
DEFINITION 5.2. - The sum
of
twotangles Tl
andT2
isdefined by
The closure
T of
atangle
T isdefined by
THEOREM 5.1. -
If T
is a doubletangle
and someof
the knotshas a Jones
polynomial,
in which there are(at least)
twocoefficients
withabsolute value 3 or
(at least)
onecoefficient
with absolute value at least4,
or(at least)
sixcoefficients
with absolute value1,
then ~ o0n-o
(while clearly
all are doubled knots and hence have genusone).
Proof.
Assume thatKn
:= have boundedg. By
theorem4.1,
our strategy will be to find somekn
EZ,
for which(t)]tkn
grows
exponentially
in n, unless the assertion is satisfied.First,
we use theKauffman
[Ka]
definition for V andreplace
Vby
the Kauffman bracket( . ) (as
all the normalization does not affect the norm of an evaluation on anypoint
onS1
andchanges
the coefficientsjust by
asign).
Then consider T in the Kauffman bracket skein module of
We have therein
for some
P{,2 E
Thenby straightforward
calculationand hence
Therefore, using
+A8)
for some k E Z and(0)
=1,
we
get, normalizing Bn by
a power ofA,
with
P1
:=Pi
andP2
=P2(-A2
-A-2)
+Pi.
The
shape
ofBn
isexponential,
and we attack itusing
thefollowing elementary
function theoretic lemmas.LEMMA 5.1. - Let
f
EA-1 ~
.If f
,regarded
as afunction f
:C
B ~0~
-~C,
has theproperty max I
1 andf ~ 0,
thenf
=for
si some k E 7~.
Proof.
Use the relationLEMMA 5.2. - Let
f
: ~ be aholomorphic function for
somefinite
set S ~0,
withf(x)
=f(x) (where
bar denotesconjugation). If
thenf
maps someinfinite
subsetof Sl
c ~ toSl,
thenf (x) f (1/x)
= 1 whereverdefined.
Proof.
- Use thatf (x) f (1/x)
is aholomorphic
function wherever de- fined and isequal
to 1 on a set with a convergencepoint.
OThe rest is
basically applying appropriately
these lemmas.LEMMA 5.3. - For any two
polynomials Pl
andP2
inZ[A,
withor
P2 ~ tAk2 for
anyk1,2
EZ,
there areinfinitely
many A ESl
with ~ 1+A" i~i
and > 1.Proof.
Assume that or thatP~ 7~ i!=~L~~.
As the assertionis
symmetric
w.r.t.Pi
andP2,
assumew.l.o.g.,
that~A~1.
Thenby
lemma
5.1,
there is some x E?~
and e > 0 such thatwith
B(x, e) being
the ball around x with radius e. SetXl(A)
:=Ak
and
X2(A)
:= 1+ A4 - A~‘ - A~+8.
If now, forinfinitely
many AE Sl
wehave
IXI(A)I =
thenapplying
lemma 5.2 onX1/X2
outside of thezeros of
X2
and 1 +A4,
we see thatXl(A)Xl(1/A)
=X2(A)X2(1/A),
inparticular
every zero 0 ofXi
must be either a zero ofX2
or the inverseof such.
However, e~’~i~8
are zeros ofXi ,
but not ofX2.
Therefore,
all butfinitely
many A ESl satisfy
inparticular
almost all A inSl
nB(x, e).
DBut now,
continuing
theproof
of theorem5.1,
if~PZ(A)~)
>1 and
I for
some A not zero ofX1,2
then for
with
exponential growth.
But from(5.14), comparing
the orders of zeros orpoles
ofBn
as A -~ 0 and A - oo(or
from[Ka2, Mu, Th] using
the evidentfact that =
O(n)),
we see thatspan Bn
islinearly
bounded inn, which means that some coefficients of
Bn
growexponentially
in n, andwe would be done
by
contradiction to theorem 4.1.Therefore, Pi and P2
are monomials with coefficients(as happens
when T is an unknot
double,
i. e., are twistknots).
But then theonly possibility
forthem,
so asBn
EZ[A, ~
for any n, is to differby
apower of
A4,
so thatfor some
Z,
from which the claim is evident. DWe chose to use the new
property
of§4
in a part of ourproof, although
it can also be done in alternative ways. We invite the reader to think about them.
EXERCISE 5.1. Use
(5.14)
to show thatif Pl,2 ~ ±Ak1,2
, then03BBlBn
or
TiBn
areinfinitely
manyfor
some valueof l,
withoutusing
thelemmas,
so that the conclusion
P1,2
= is alsopossible using corollary .~.1.
Ina much easier
(and
lessinteresting)
way, deduce the same conclusion alsofrom proposition
~.1.We
give
some hints to thereader, giving
arough
sketch of theargument.
As
al
ismapped bijectively
undermultiplication by
a fixedpolynomial,
eliminate the denominators in
{5.14),
and considerLEMMA 5.4. - Let the minimal order
of
V bedefined by
min ord V :=min~ m >
0 : :~ 0 ~,
is not a monomial. ThenAn
analogous
definition and statement hold for the maximal order max ord V of V.From
(5.14) clearly
not bothPi and P2
are zero, and ifjust
one is zero, the other cannot be asingle monomial,
so we would be doneby
the abovelemma.
Therefore,
assume that bothPI and P2
are non-zero.Now,
ifmin deg P2 mindegPi
andP2 7~
, then for any l forsufficiently large n
we have03BBlPn
=03BBl (X2 P2 )
, whichby
the lemma for lsufficiently large
has anunboundedly growing
coefficient. Ananalogous argument
withPi
and the maximaldegree
shows that we are done unless mindeg P1 =
mindeg P2
and maxdeg P1 =
maxdeg P2.
Then the lemma shows thatmin ord PI = min ord P2
andmax ord PI = maxord P2 by
asimilar argument. For
example,
ifmin ord Pl min ord P2,
consider the coefficient of for lsufficiently large,
and compare in(5.15)
thegrowth
rates of this coefficient as n - oo forX 1 P1
andXZPZ
.But now a contradiction
follows, considering
the above mentioned coefficient for l = 1, because at least one of mindeg X 1 ~
mindeg X 2
or maxdeg X 1 ~ max deg X2 holds,
no matter what k is.Therefore, Pi,2
must bemonomials,
and then
clearly they
must have coefficient :1::1.Example
5.1. - The two 14crossing (twisted)
doubles of the left-hand trefoil withpositive
andnegative clusp,
in Thistlethwaite’s tables(see [HTW])
included as
1435575
and1441716,
have the Jonespolynomials (in
the notationof
[St5])
and hence theorem 5.1 can be
applied
to thetangle
in(5.13)
with both w+and w_ . .
6. Problems
In
fact,
the motivation for this note was todevelop
the results of§3
sofar as to do the construction of
§5
without use ofproposition
3.1.Using
thisproposition,
theproof
is somewhatsimpler,
but itappeared
nicer to linkboth
parts
of the paper in the chosen way.Nevertheless,
Iprefer
to concludestressing again
someproblems
thatsuggest
to be of somesignificance
within the framework of this note.Problem 6.1. - Is there an upper bound
for
for Kalternating
in terms of
g(K)
andpossibly k,
but notc(K) (as
there is forpositive K)?
Is there a similar
inequality
also fornon-alternating
knots?Problem 6.2. Can one
generalize
theorem 3.2 to astability
propertyfor
arbitrary
knots(and
weakgenus) by
more refinedstudy
of(3.8)?
Problem 6.3. Are the
only finitely
manypositive
knots with Jonespolynomial
ofgiven span?
If we had an infinite series of suchknots,
thenby corollary
4.3 we know that their genera must growunboundedly,
but yetwe cannot exclude such a case.
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