C OMPOSITIO M ATHEMATICA
T AKESHI S AITO
The discriminants of curves of genus 2
Compositio Mathematica, tome 69, n
o2 (1989), p. 229-240
<http://www.numdam.org/item?id=CM_1989__69_2_229_0>
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The discriminants of
curvesof genus 2
TAKESHI SAITO
Department of Mathematics, Faculty of Science, University of Tokyo, Hongo Tokyo 113, Japan
Received 26 January 1988; accepted 4 July 1988 e Kluwer Academic Publishers,
In our
previous
paper[SI],
we studied the relation between the discriminant and the conductor of curvesof arbitrary
genus. In the caseof genus 2,
thereis another discriminant
slightly
différent from that used there. The former is definedby using
the canonicalisomorphism
of Mumford and the latter is classical and related to theSiegel
modular formof weight
10. The purpose of this paper is tostudy
the différence between these two discriminants. Our main result asserts that it is determinedby
the base locus of the canonical divisor when the curvesdegenerate.
Let g: Y ~ T be a proper and smooth
morphism
withgeometrically
connected fibers and of relative dimension 1. Then there exists a
unique
canonical
isomorphism [D]
Here
wY/Tis
the relative canonical sheaf. In this case, it isisomorphic
to03A91Y/T.
The notation det denotes the determinant invertible sheaf
of perfect complex ([K-M] Chapter 1).
In this case detRg*WY/T (resp.
detRg*03C9~2Y/T)
issimply
isomorphic
to039B03B3g*03C9Y/T (resp.
A303B3-3g*03C9~2Y/T)
where y is the genus of Y.When the genus is
2,
there is a canonical section 0394’ Er(T, (det Rg*03C9Y/T)~10).
This is the well known
Siegel
modular form ofweight
10([M]
p.317).
It is defined
using A
asfollows.
It is well known that the canonicalmorphism
is an
isomorphism where S2
denotes the secondsymmetric
power. From thiswe have a canonical
isomorphism
Then 0’ is defined
by
Therefore to know the différence between these two discriminants A and
0394’,
it is sufficient to
study Ai.
Now let us
study
it in the situation of[S1].
Let S be thespectrum
of a discrete valuationring
withalgebraically
closed residue field. Let s(resp. ~)
be the closed
(rcsp. generic) point
of S.Let f:
X ~ c be a proper flatgeometrically
connected andregular
S-scheme with smoothgeneric
fiberand of relative dimension 1. Assume that the genus of X is 2. Then we have the canonical non-zero rational sections
A,
0’ and03941
of the invertibleOS-modules Homc,(det Rf*03C9~2X/S, (det Rf*03C9X/S)~13), (det Rf*03C9X/S)~10
andHom(Ds«det Rf*03C9X/S)~3,
detRf*03C9~2X/S) respectively.
For a non-zero rational section 1 of an invertibleOS-module L,
let ord 1 denote theunique integer
such that
(9s -
l =pn L
where p is the maximal ideal ofOS.
We called ord Athe discriminant of X over S in
[S1]
Section 1. Our purpose is to know ordAi.
We will show that ord
03941
is determinedby
the base locus of the relative canonical sheaf wxls. Let03BA: f*f*03C9X/S ~
úJx/s be the canonicalmorphism.
The
support
of the cokernelof K, i.e.,
the base locus of wxls, is inXs
sincethe canonical divisor of a smooth curve
of genus
1 is basepoint
free. LetI be the annihilater ideal of the cokernel
of K,
let D be theunique
divisor ofX such that
ID ~
I andID/I
is of finitelength
and let R be the0-cycle LXEX lengthOX,x (ID/I)x. [x].
Then thesupport
of D and R are inXS .
Our main resultis the
following.
THEOREM: Under the above
notation,
COROLLARY 1:
If Ú)x/s
is basepoint free,
thenAI defines
anisomorphism of
invertible
(9s-modules
Assume X is minimal. Then
03941 always defines
ahomomorphism of (9s-modules
and it is an
isomorphism if
andonly if
wx/s is basepoint free.
COROLLARY 2: Under the
assumption of the theorem,
where
Art(X/S)
is the Artin conductorof
X over Sdefined
in[Sl ] Section
1.Always
0’defines
a sectionof OS-module
and it is a generatorif and only if
theminimal model
of
X is smooth.First we
give
theproof
of the corollariesadmitting
the theorem.Proof of Corollary
1:First,
we remark that03941
defines ahomomorphism (resp.
anisomorphism)
ofOS-modules
if andonly
if ord03941
0(resp.
ord
Ol - 0). If wx/s
is basepoint free,
it isclearly
follows from the theorem that ordO1 -
0. Assume X is minimal. Then c,(wxls)
n D 0. On theother
hand, always
we have -D2
0 anddeg
R 0. Hence we have thefirst assertion. For the
second,
ordOl -
0 is nowequivalent
to cl(wxls) n
D =
D2 = deg
R = 0. It is easy to see that this holds if andonly
if D = 0and R = 0. This condition is
evidently equivalent
to that wx/s is basepoint
free.
Proof of Corollary
2: Theequality immediately
follows from the theoremabove,
Theorem 1 of[SI] and
theequality
ord 0394’ = ord A + ord
Ai.
To see the rest, we may assume X is minimal since ord 0’ is invariant under
blowing-up.
Now the assertion follows fromCorollary
1 above andCorollary
1 to Theorem 1of [S1].
Proof of
Theorem: We consider theperfect complex
ofOX-modules
M =
[f*f*03C9X/S ~ 03C9X/S].
Heref *f*03C9X/S (resp. 03C9X/S)
isput
ondegree
0(resp. 1).
Thiscomplex
is consideredby
Mumford([M]
Section8).
It is easy to see thatH° (M )
is an invertible(9x-module.
Thesupport of H1(M) i.e.,
thebase locus of wls is in
XS
and othercohomology
sheaves vanish. Hence the construction of the localized chern class of Bloch-MacPherson([B]
Section
1, [F]
Section18)
can benaturally applied
to this case and we obtainc2xs (M )
inCH0(Xs).
Next we consider the derived 2nd exterior power
complex
LA 2
M. Thecomplex
L A 2 M is defined to bewhere
A’f *f*ú)x/s
isput
ondegree
0.Although
thegeneral
definition of the derived exterior powercomplex
isgiven by
the method ofDold-Puppe
([I] Chapter
1 Section4),
for our purpose, it is more convenient to refer[S2]
Section 1. For the
perfect complex
K ofamplitude
in[0, 1],
we can defineL 1B q K to be
D(L 039BqDK).
Here DK = RHomOX(K, OX)
and the definitiongiven
thereapplies
to it. Moredirectly,
for thecompex K
=[E ~ L],
whereE is
put
ondegree 0,
L 1B q K is definedby
where 039BqE is
put
ondegree
0.Since L
/B 2
M isacyclic
outside the base locus of 03C9X/S, the localized chern classcX2X(L 039B2 M )
ECH0(Xs)
is also defined. We will prove thefollowing
three
equalities.
(a) deg cX2Xs (M) = 2cl (03C9X/S)
n D - D2 +deg
R.(b) deg cX2Xs(L
A 2M) = - ord Ai .
(C) cX2Xs (M ) = - cX2Xs (L 039B2 M).
The theorem follows from these
equalities
at once.The
equality (c)
and the fact thatcX1Xs (L
039B2M ) =
0 isproved
inquite
thesame way as
Proposition (2.1)
of[S2]. Or,
we maydirectly apply
it to thedual DK. We show the
equality (b). By applying Proposition (2.3)
of[S2],
we
have - deg cX2Xs(L
A 2M) = x(S, Rf*L
A 2M).
Hence we are reducedto show
First,
wecompute
ordAi.
Sincef
X ~ S iscohomologically
flat([R]
Proposition (9.5.1)),
we have detRf*03C9X/S = det f*03C9X/S.
Now it is easy tosee, and follows from Lemma 2 of
[SI] for example,
thatHere
S2 f*OJx/s
isput
ondegree -
1. Next wecompute Rf*L
/B 2 M. Weconsider the
spectral
sequenceThe
complex
ofEl-terms
isotherwise
Since the sequence
is exact,
E*,01
isquasi-isomorphic
to[S2 f*03C9X/S ~ f*03C9~2X/S],
whereS2f*03C9X/S
is
put
ondegree
1.For q - 1, by
the Serreduality R1 f*OX ~ HomOS (f*03C9X/S, OS),
is the canonical
isomorphism. Hence E,’’
1 isquasi-isomorphic
toR1f*03C9X/S[- 2].
Now it is easy to see thatHence we have
proved
theequalities (b’)
and(b).
Lastly
we prove(a).
This ismerely
acomputation
of the chern class. Let A =H0(M) =
Ker 03BA and B =H’(M) =
Coker K. We recall that A is aninvertible
OX-module.
Then we haveand
Let B’ - B
~OXOD
and B" -Ker(B ~ B’).
Here B’ - OJx/sQ9(!x ÔD
andB"" --
ID/I.
Henceand
From the exact sequence 0 ~ B" ~ B ~ B’ ~
0,
we haveBy substituting
this to(*),
we obtain theequality (a).
Thus we havecompleted
theproof
of the theorem.We
compute
ord0,
in the semi-stable case. Letf :
X - S be aregular
curve of genus 2 as above.
When X,
is a reduced normalcrossing divisor,
wesay X
is semi-stable.PROPOSITION: Assume X is minimal and semi-stable. Let P be the set
of singular points of XS
such thatXS - {p}
is disconnected. ThenProof.-
When X satisfies thefollowing condition,
wesay X
is oftype
1 and otherwise X is oftype
0.(*) By suitably choosing
thenumbering
of the irreduciblecomponents Ci
0 i x m of
XS,
thefollowing equalities
are satisfiedotherwise.
otherwise.
LEMMA 1:
If
X isof
type 0, úJX/S is basepoint free
and P =QS.
Assume X isof
type 1. Let pi be the intersectionpoint of Ci
andCi,, 1 for
0 i m. Thenand
We show Lemma 1
implies Proposition.
If X is oftype 0,
ord03941 =
Card P = 0
by
Lemma 1 andCorollary
1 of Theorem. Assume X is oftype
1. Thenby
some easycalculation,
we seeord 03941
= m follows from Lemma 1 and Theorem. On the otherhand,
it is clear that Card P = m.Proof of
Lemma 1: The assertions on P is easy to check. Tostudy
the baselocus of 03C9X/S, we use the
following
fact which is stated in[M]
Footnote 5.LEMMA 2: Let Z be a stable curve over
a. field
k. Let B be the base locusof 03C9Z/k.
Let W be the set
of singular points
pof Z
such thatZ - {p}
is disconnected and let V be the setof
the smooth and rational irreducible components Cof
Zsuch that every
singular point of
Z in C is contained in W. ThenWe will
give
aproof
of Lemma 2 later inAppendix,
because the author cannot find a proper reference of theproof.
We continue the
proof
of Lemma 1admitting
Lemma 2. Let g: Y - S bethe stable model of X
i.e.,
the contraction n : X ~ Y of the( - 2)-curves
inX. Then the base locus of Ú)x/s is the inverse
image
of wyls since03C0*03C9Y/S =
Ú)x/s and 03C0*03C9X/S = wyls. Since the formation of g*Wy/s commutes with the base
change,
the base locus of wyls has the samesupport
as that of Ú)Ys/s.Assume X is of
type
0. Then we caneasily
check that W and Vfor YS
isempty.
Henceby
Lemma2,
the base locus of Ú)Ys/s isempty.
Therefore that of Ú)Y/s and that of Ú)x/s are alsoempty.
Now we assume X is
of type
1. LetDk
be the divisor03A3ki=0 (k - i) · Ci
ofX for 1
k
m. We will show thefollowing,
later.CLAIM:
03C9X/S(Dk)|Dk ~ (9D,
for 1k
m.We continue the
proof admitting
Claim. LetEk
be the divisor k -XS.
Sincethe formation of
f*03C9X/S
commutes with the basechange,
we haveWe define an
injection
a:(9D,
~03C9X/S|Ek
as thecomposite
of thefollowing morphisms.
Theisomorphism
in the claimODk ~ 03C9X/S(Dk)|Dk,
anisomorphism 03C9X/S(Dk)|Dk ~ 03C9X/S(Dk - Ek)|Dk
definedby
an elementof OS
of orderk,
andthe canonical
injection Ú)x/s(Dk - Ek)|Dk
~Ú)X/SIEk.
Let a EH0(X, wxls)
bea section of wxls such that the reduction a- E
H0(Em, Ú)X/SIEm)
comes from1 E
H0(Dm, 0DII) by
oc.By inverting
thenumbering
of the irreducible components,similarly
we define a section bof H° (X, úJx/s).
We prove that(a, b)
is a basis of the freeC,-module H° (X, úJx/s)
of rank 2. Forthis,
it issufficient to show that
(â, b)
is a basis theK(s)-vector
spaceH0(XS, 03C9XS/S).
Since
03C9X/S(C0 - XS)|C0
~úJx/s(Cm - XS)|Cm naturally
defines the subsheaf of03C9X/S|XS,
we have aninjection
By Claim, (a, b )
is a basis of the vector space on the left hand side. Hence thisinjection
is anisomorphism
and(â, 5)
is a basis ofH0(XS, 03C9X/S|XS).
Now we calculate the base locus of cvxjs
using
the basis(a, b)
ofH°(X, 03C9X/S).
Let A be the effective divisor diva -L;=o
k -Ck.
Thenby
thedefinition
of a,
we have(Ck, A) =
0for k ~
m.By definition,
the divisor A is a linear combination ofCm
and a flat divisor. Hence A is a flat divisor.In the same way, the effective divisor B = div b -
03A3mk=0 (m - k) - Q
is aflat divisor and
(Ck, B) -
0for k ~
0.Using this,
we caneasily
check thatD and R are as in the statement of Lemma 1.
Our
remaining
task is to prove Claim.Proof of
Claim: For a divisor D ofX,
the invertibleC,-module wx/s(D)ID
isisomorphic
to the canonical sheaf WD of D over S. Let n be aprime
elementof (Ds
andD’k
be the divisor03A3k-1i=0 C,
of X. It is easy to see that there are exact sequencessuch that the
composite
03C9Dk ~ 03C9Dk-1 ~ 03C9Dk coincides with themultiplication by n.
First we prove
H0(Dk, 03C9Dk) ~ OS/pk
for 1k
m,by
inductionon k. For
simplicity,
when the base space isclear,
we omit to write it asH0(03C9Dk)
=H0(Dk, 03C9Dk)
andby
smallh,
we denote thelength
of thecohomology
H as inh0(03C9Dk)
=lengthOSH0(03C9Dk).
For theproof
of the abovefact,
it is sufficient to prove thatKer(n : H0(03C9Dk) ~ H’(o)D,» K(s) i.e., h0(03C9Dk)
= 1 and thath0(03C9Dk)
= k. First we showh0(03C9Dk)
= 1. Since(D’k, D’k) = -
1 and(Dk , c1(03C9X/S))
=1, by Riemann-Roch,
we have~(ODk) =
0. SinceD’k
is reduced andconnected, H0(ODk) ~ 03BA(s).
Hence wehave
h1(ODk)
= 1.By
the Serreduality H0(03C9Dk) ~ HomOS(H1(OD’k), 03BA(~)/03BA(s)),
we have
h0(03C9D’k)
= 1. Next we showh0(03C9Dk)
= k. For k =1,
sinceDk = D’k,
we have seen this. Since(Dk, Dk) = - k
and(Dk ,
c1(wx/s))
=k, by Riemann-Roch, Z(CD,)
= 0. SinceOS/pk
cH0(ODk),
we haveh0(ODk)
k.Hence h1(ODk) k. Also by
the Serreduality, we have h0(03C9Dk)
k. On theother
hand, by
the exact sequence(b),
we haveh0(03C9Dk) h0(03C9dk-1)
+h0(03C9Dk).
Hereh0(03C9Dk-1)
= k - 1by
theassumption
of induction andhO(WDÁ)
= 1 as we have seen before. Hence we haveh0(03C9Dk)
k. Thus wehave
proved hO(wDÁ)
= k. This argument also provesH0(ODk) ~ (Ds/pk
andthe
global
section of the exact sequence(b)
is exact.
Now we prove 03C9Dk ~
(!)Dk.
Let a = 03B1k:ODk ~
03C9Dk be themorphism
defined
by
agenerator of H0(03C9Dk) ~ OS/pk.
We prove this is anisomorphism.
The exact sequence
(a)
defines thefollowing
commutativediagram
of exactsequences
We prove
fi
and y areisomorphisms.
This proves Claim. First weprove 03B2
is an
isomorphism.
LetH0(03B2): H0(ODk-1) ~ H0(03C9Dk-1)
be themorphism
induced
by 03B2.
Thenby
the exact sequence(B), H0(03B2)
coincides withH° (a)
(DidOS/pk-1
and is anisomorphism.
Since 03C9Dk-1 ~ODk-1,
the fact thatH0(03B2)
is anisomorphism implies p
is anisomorphism. Lastly
we prove y isan
isomorphism.
It is easy to check thatdeg WDJC,
= 0 for 0 i k. Onthe other
hand,
sinceh0(03C9Dj) = j for j - k,
k -1,
we haveh0(03C9Dk|D’k)
1.Since
D’k
is reduced andconnected,
these facts show that03C9Dk|D’k, ~ OD’k
andthe
global
section of the exact sequence(a)
is exact. From
this,
it follows thatH0(03B3)
is anisomorphism
and y is anisomorphism.
Thus we havecompleted
theproof
of Claim. Hence we haveproved Proposition.
We consider a moduli theoretic
meaning
of ord03941,
whichexplains
thisnotation. Let
M2 (resp. M2 )
be the fine moduli stack of smooth(resp. stable)
curves
of genus
2. Let A be the normalcrossing
divisorM2 - M2.
Then Ahas two irreducible
components Ao
andAi.
Anelliptic
curve with a nodecorresponds
toAo
and twoelliptic
curvestransversally meeting
at onepoint corresponds
toAi.
Letf:
X ~ S be as inProposition
so that X defines amorphism
S ~M2.
Then themeaning
ofProposition
is that thedegree
ofthe inverse
image
of the divisorby
thismorphism
isequal
to ordAi (cf. [D-M] Proposition 1.5).
In otherwords,
ordAi
is the intersection number of Swith Ai.
Thus even for not semi-stable curves, wemight
consider ord
Ai
as if it was the intersection number of S withAi.
Lastly,
we mention the relation with a work on ord 0’ of K. Ueno[U].
First we
briefly
review it.THEOREM
(Ueno [U]):
Letf
X ~ S be as in Theorem above. Assume that char03BA(s) ~ 2, 3,
5 and that X is minimal. Thenord 0394’ = - Art(X/S)
+(correcting term).
The
correcting
term is determinedby
theconfiguration of
theclosed fiber
andgiven explicitly by
a table.We consider the relation between this and ours.
By Corollary
2of Theorem,
this
correcting
term should becomputed by
ourdescription
of ordAi.
However,
it isdirectly
checkedonly
for the semi-stable case inProposition.
It remains open to check it
generally.
Appendix.
Proof of Lemma 2We prove Lemma 2. Let Z be a stable curve over a field k. Let C be a
component
of Z. First we showthat,
unless C is smooth andrational,
theinvertible
(9c-module
oec is basepoint
free. When C issmooth,
this fact is well known. Assume C issingular.
Let n :C ~
C be the normalization of C andEc
be the set ofsingular points
of C. Then we have an exact sequenceSince
Hl (C, 03C9C) ~ H1(C, oec) zi k,
theglobal
section of(a)
is exact. When C is not
rational,
this fact shows that 03C9C is basepoint
free.Assume C is rational and not smooth.
Similarly
asabove,
we have an exactsequence
Here
03C0*03C9C ~ (D( - 2
+ 7r(03A3C)).
ForpELe,
there is asection 07P
E H°(C, 03C0*03C9C)
suchthat 03C3p(q1)
= - 03C3p(q2)
=1= 0 in03C9C(p)
for{q1, q2}
= 7r -,(p)
and
03C3p(q) =
0 forq ~ 03C0-1(03A3C - {p}). By (B),
03C3p defines a sectionc-HO(C, 03C9C)
and does not vanish on(C - 03A3C) ~ {p}.
Therefore Wc is basepoint
free.Let
Zc
be the closure of thecomplement
Z - C andQc
be the set ofintersection
points
of C andZC.
Then we have an exact sequenceThis sequence and the above fact show
that,
unless C is smooth andrational, (C - Oc)
n B =0.
It also shows thatis exact. Here
H’ (C, 03C9C) ~ H’ (Z, 03C9Z) ~ k
andH’ (Zc, 03C9ZC) ~ knc,
where
03A0C
is the set of connected componentof Zc.
Let ac : kQC ~ kfIc be themorphism
definedby ep
H eA where A is the connectedcomponent
ofZc containing
p. Then p EQc
is contained in the base locus of Wz if andonly
if the
projection
from Ker ac to thep-component
is the0-map.
Thiscondition is satisfied if and
only
if the connectedcomponent
ofZc containing
p does not contain other
points
ofQc,
which meansZ - {p}
is disconnected.This shows that for a
singular point
p ofZ,
p is contained in B if andonly if p
is in W.Now what remains to
study
is the smooth and rational components of Z.Let C be such a
component.
From the exact sequence 0 ~ 03C9ZC ~ oez -03C9Z|C ~ 0,
we have the exact sequenceH0(Z, 03C9Z) ~ H0(C, ù)zlc) ~ H1(ZC, 03C9ZC).
Here b is thecomposite H0(C, 03C9Z|C)
~~p~QC 03C9Z(p) 1 Hl (Zc, 03C9ZC).
AssumeQc
c W i.e. to Ker eHO (C, 03C9C) =
0. Thismeans C c B.
Contrary,
assumeQç r
W i.e.C ~
V. Thenby
the similarargument
as that on the rational and non-smooth component, we see that(C - W ~ QC) ~ B = ~.
Thus we havecompleted
theproof
ofLemma 2.
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[D-M] P. Deligne and D. Mumford: The irreducibility of the space of curves of given genus, Publ. Math. IHES, 36 (1969) 75-109.
[F] W. Fulton; Intersection Theory, Springer-Verlag, Berlin (1984).
[I] L. Illusie: Complexe cotangent et déformation I, Springer LNM 239 Berlin/Heidelberg/
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[K-M] F. Knudsen and D. Mumford: The projectivity of the moduli space of stable
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[S1] T. Saito: Conductor, discriminant and the Noether formula of arithmetic surfaces, Duke Math. J. 57 (1988) 151-173.
[S2] T. Saito: Self-intersection 0-cycles and coherent sheaves on arithmetic schemes, to appear in Duke Math. J.
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