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www.imstat.org/aihp 2008, Vol. 44, No. 4, 593–611

DOI: 10.1214/07-AIHP108

© Association des Publications de l’Institut Henri Poincaré, 2008

Skew-product representations of multidimensional Dunkl Markov processes

Oleksandr Chybiryakov

Laboratoire de Probabilités et Modèles Aléatoires, Université Pierre et Marie Curie, 175 rue du Chevaleret, F-75013 Paris.

E-mail: oleksandr.chybiryakov@m4x.org

Received 14 September 2005; revised 6 April 2006; accepted 17 October 2006

Abstract. In this paper we obtain skew-product representations of the multidimensional Dunkl processes which generalize the skew-product decomposition in dimension 1 obtained in L. Gallardo and M. Yor. Some remarkable properties of the Dunkl martin- gales.Séminaire de Probabilités XXXIX, 2006. We also study the radial part of the Dunkl process, i.e. the projection of the Dunkl process on a Weyl chamber.

Résumé. Dans cet article nous obtenons des produits semi-directs des processus de Dunkl multidimensionnels qui généralisent ceux obtenus en dimension 1 dans L. Gallardo and M. Yor. Some remarkable properties of the Dunkl martingales. InSéminaire de Probabilités XXXIX, 2006. Nous étudions les processus de Dunkl radiaux qui sont les projections des processus de Dunkl sur une chambre de Weyl.

MSC:60J75; 60J25

Keywords:Dunkl processes; Feller processes; Skew-product; Weyl group

1. Introduction

The study of the multidimensional Dunkl processes was originated in [18] and [20]. They were studied further in [7–

10]. These processes share some important properties with Brownian motion: for example, they are martingales and enjoy the chaotic representation property as well as the time-inversion property. To a Dunkl process we can associate two processes: its Euclidean norm and its radial part. The Euclidean norm of the Dunkl process is in fact a Bessel process and its radial part is a continuous Markov process taking values in a Weyl chamberC. Note that a particular case of the radial part process – Brownian motion in a Weyl chamber – is studied in [2].

It is well known that Brownian motion (and more generally any rotational invariant diffusion) can be decomposed as the skew-product of a certain radial process and a time-changed spherical Brownian motion (see [6,17]). In general, the following question can be raised: suppose given a groupGacting (not necessarily transitively) onRnand a Markov process onRn, “invariant” by the action ofG. Does this lead to a certain skew-product decomposition of the Markov process? In this paper we answer this question in the case of the Dunkl processes and the groupW – the group of symmetries ofRn. We also studyXW – the radial part of the Dunkl process noting some analogies betweenXW and Bessel processes.

The paper is organized as follows. In Section 2 we introduce some notations about martingale problems and ex- tended infinitesimal generators for Markov processes. In Section 3 we give the definition of the Dunkl process and its radial part. We also present the invariance property of the Dunkl process under the action of the groupO(Rn).

Section 4 contains the study of the radial part of the Dunkl process. We give the condition on the parameters ofXW which guarantees that it does not hit the walls of a Weyl chamberC. This is done by applying a famous argument due

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to McKean (see Problem 7, p. 47 in [16]). As a part of the proof we find harmonic functions forXWwhich are analogs of harmonic functions for Bessel processes, i.e. the adequate power or logarithm function. Under the condition that XWdoes not hit the walls ofCit can be characterized as the unique solution of a stochastic integral equation or as the unique solution of the corresponding martingale problem (ifXW hits the walls ofC it can still be characterized as a unique solution of the stochastic integral equation up toT0– the first time it hits the walls ofC).

In Section 5 we generalize the skew-product decomposition given in [10] to multidimensional Dunkl processes.

From [9] it is known that the Dunkl process can jump only in the directions given by the roots of an associated root system. In Theorem 19 we construct the Dunkl process from its radial part by adding the jumps in these directions one by one. In order to add the jumps we do the time-change then add jumps in the fixed direction and then do the inverse time-change. In order to add the jumps in a fixed direction we use the perturbation of generators technique from [5].

We also see that under a certain invariance condition for the extended infinitesimal generator this perturbation is given by a skew-product with a Poisson process. From Lemma 18 and Theorem 19 we obtain that the Dunkl process can be characterized as the unique solution of a martingale problem. Note a similar result from [20], which is recalled in Theorem 4. Our result holds for a more general class of processes – the two-parameter Dunkl processes (see [10] in dimension 1, [7] and [15]), but we need to impose the condition which guarantees that the radial part of the Dunkl process does not hit the wall ofC.

2. Notations

We will constantly use martingale problems. Therefore, we need to recall here some definitions from [5] which will be used later.

Let(S, d)be a metric space andDS[0,∞)(CS[0,∞)) the space of right continuous (continuous) functions from [0,∞)into (S, d)having left limits.P(S)denotes the set of Borel probability measures on S. For any xS, δx denotes the element ofP(S)with unit mass atx. LetLbe the space of all measurable functions onS.Ais a linear mapping whose domainD(A)is a subspace ofLand whose rangeR(A)lies inL. TypicallyD(A)will beCK(S)– the space of infinitely differentiable functions onSwith compact support.

LetX be a measurable stochastic process with values inS defined on some probability space(Ω,F, P ). For νP(S)we say thatXis asolution of theDS[0,∞)martingale problem(A, ν)ifXis a process with sample paths inDS[0,∞),P(X0∈ ·)=ν(·), and for anyuD(A)

u(Xt)u(X0)t

0

Au(Xs)ds

is an(FtX)-martingale, whereFtX:=F{Xs, st}, where in this paperF{Xs, st}indicates the sigma-field gener- ated by variablesXs,st. LetUbe an open set ofSandXbe a process with sample paths inDS[0,∞). Define the (FtX)-stopping time

τ:=inf{t≥0|Xt/UorXt/U}.

ThenXis asolution of the stoppedDS[0,∞)martingale problem(A, ν, U )ifP (X0∈ ·)=ν(·),X·=X·∧τ a.s., and for anyuD(A)

u(Xt)u(X0)tτ

0

Au(Xs)ds

is an (FtX)-martingale. If there exists a unique solution of a (stopped) martingale problem we will say that the (stopped) martingale problem is well-posed.

In what follows it will be convenient to work with the extended infinitesimal generator (see [14,21], VII). We recall here the definition from ([21], VII).

IfXis a Markov process with respect to(Ft), a Borel functionfis said to belong to the domainDAof theextended infinitesimal generator(orextended generator) if there exists a Borel functiongsuch that, a.s.,t

0|g(Xs)|ds <+∞

for everyt, and

f (Xt)f (X0)t

0

g(Xs)ds

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is a(Ft, Px)-right-continuous martingale for everyx.

3. Preliminaries

Letx·ydenote the usual scalar product forxandyonRn. For anyα∈Rn\{0},σαdenotes the reflection with respect to the hyperplaneHα⊂Rnorthogonal toα. For anyx∈Rn, it is given by

σα(x)=x−2α·x α·αα.

For our purposes we need the following definition (see, for example, [19]):

Definition 1. LetR⊂Rn\{0}be a finite set.ThenRis called a(restricted)root system,if 1. R∩Rα= {±α}for allαR;

2. σα(R)=Rfor allαR.

The subgroupWO(Rn)which is generated by the reflections{σα |αR}is called the Weyl reflection group associated withR.

One can prove that for any root systemRinRn, the reflection groupWis finite and the set of reflections contained inWis exactly{σα, αR}(see [19]).

Example 2 (Root system of typeAn1). Lete1, . . . , enbe the standard basis vectors ofRn,then R=

±(eiej),1≤i < jn is a root system inRn.

Example 3 (Root system of typeBn). R= {±ei,1≤in,±(ei±ej),1i < jn}is a root system onRn. Without loss of generality we will suppose that ifR is a root system inRnthen for anyαR,α·α=2, so that for anyx∈Rn

σα(x)=x·x)α. (1)

For any given root systemRtakeβ∈Rn\

αRHα, thenR+= {αR|α·β >0}is its positive subsystem. For any αReitherαR+or−αR+. Of course the choice ofR+is not unique.

From [8,20] theDunkl processesX(k)are a family of càdlàg Markov processes with extended generatorsLkwhere, for anyuC2K(Rn),Lkuis given by

Lku(x)=1

2 u(x)+

αR+

k(α)

u(x)·α

x·αu(x)u(σαx)

(x·α)2 , (2)

wherekis a nonnegative multiplicity function invariant by the finite reflection groupWassociated withR, i.e.k:R→ [0,+∞)andkwk, for anywW. It is simple to see thatLk does not depend on the choice ofR+. In what follows suppose thatX0∈Rn\

αRHα a.s.

The semi-group densities of the Dunkl process with the generator(2)are given by pt(k)(x, y)= 1

cktγ+n/2exp

−|x|2+ |y|2 2t

Dk

x

t, y

t

ωk(y), x, y∈Rn, (3)

whereDk(u, v) >0 is the Dunkl kernel (for the properties of the Dunkl kernel see [19]),γ:=

αR+k(α),ωk(y)=

αR+|α·y|2k(α)andck=

Rne−|x|2/2ωk(x)dx(see [18]).

We will need the following result from [20].

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Theorem 4. Let(Pt)t0be the semigroup of the Dunkl process given by its density(3)and letLk be given by(2).Let (Xt)t0be a càdlàg process onRnsuch that its Euclidean norm process(Xt)t0on[0,+∞[is continuous.Then the following statements are equivalent.

1. (Xt)t0is the Dunkl process associated with the semigroup(Pt)t0. 2. For anyfC2(Rn)

Mtf

t0:=

f (Xt)f (X0)t

0 Lkf (Xs)ds

t0

is a local martingale.

3. For anyfC2K(Rn),(Mtf)t0is a martingale.

Consider now a fixed Weyl chamberC of the root-systemR which is a connected component ofRn\

αRHα. The spaceRn/WofW-orbits inRncan be identified toC, i.e. there exists a homeomorphism φ:Rn/WC. Denote XtW:=π(Xt(k))– aradial part of the Dunkl process(or aradial Dunkl process), where

π:=φπ1 (4)

andπ1:Rn→Rn/W denotes the canonical projection. From [8],XW is a Markov process with extended generator LWk u(x)=1

2 u(x)+

α∈R+

k(α)u(x)·α

x·α , (5)

for anyuC20(C), such that ∇u(x)·α=0 forxHα,αR+. The semigroup densities ofXW are of the form pWt (x, y)= 1

cktγ+n/2exp

−|x|2+ |y|2 2t

DkW

x

t, y

t

ωk(y), x, yC, (6)

where

DWk (u, v)=

wW

Dk(u, wv). (7)

From [20] the Dunkl process(Xt)t≥0is a Feller process and its Euclidean norm(Xt)t≥0is a Bessel process of indexγ+n/2−1. It is easy to see that(XtW)t0defined above is also a Feller process.

In order to state the next result, we denote the trajectory of the Dunkl process starting at x by (X(k,R,x)t )t0. The following proposition is an analog for the Dunkl–Markov processes of the rotational invariance property of the Brownian motion inRn.

Proposition 5. Let(Xt(k,R,x))t0,x∈Rn be the Dunkl process,O(Rn)– the orthogonal group ofRn.Then for any θO(Rn)

θ Xt(k,R,x)

t0,x∈Rn (d)=

X(kt θ,θ R,θ x)

t0,x∈Rn,

wherekθ:θ Rαk(tθ α),tθis the transpose ofθ,θ R= {θ α, αR}.

Proof. It will be convenient to denoteLRk the extended generator of(X(k,R,x)t )t0,x∈Rn given by (2). By Theorem 4 it is enough to prove that for anyuC2(Rn)andx∈Rn

Lθ Rkθ u(θ x)=LRk(uθ )(x).

From (1) one has (uθ )

σα(x)

=u

θ x·x)θ α

=u

θ x(θ α·θ x)θ α

=u

σθ α(θ x)

(5)

and

(uθ )(x)·α=t

θu(θ x)

·α= ∇u(θ x)·θ α.

Then

LRk(uθ )(x)= 1

2 u(θ x)+

θ αθ R+

k(α)

u(θ x)·θ α

θ x·θ αu(θ x)u(σθ α(θ x)) (θ x·θ α)2

=Lθ Rkθ u(θ x).

4. Study of the Markov processXW

Consider the Weyl chamberC= {x∈Rn|x·α >0, α∈R+}. We now study the radial part of the Dunkl process, i.e.

the Markov process(XtW)t0with extended generator given by (5).(XWt )t0is a continuous Feller process with its values inC.

Denote

¯

ωk(x)=

αR+

·x)k(α), (8)

then for anyuC20(C), such thatu(x)·α=0 forxHα,αR+, andxC LWk u(x)=1

2 u(x)+

αR+

k(α)u(x)·α x·α

=1

2 u(x)+ ∇u(x)· ∇logω¯k(x).

The following proposition gives a condition on the functionk:R→R+in the definition of the extended genera- tor (5), which ensures that the processXW, such thatX0WCa.s., never touches∂C.

Proposition 6. LetXW be the radial Dunkl process,X0WCa.s.,with extended generator given by(5).Suppose that for anyαR,k(α)12.Define

T0:=inf

t >0|XWt∂C

, (9)

then

T0= +∞ a.s.

Remark 7. Suppose that for anyαR, k(α)12. From Proposition6 Px(T0= +∞)=1, wherePx denotes the law ofXW started atxC.Lety∂C.For anyε >0,using(6),one obtains that Py(XεWHαC)=0.Since

∂C(

αRHα)C Py

XεWC

=1.

Hence,by the same argument as in([13],p. 162), Py

XtWC,ε < t <+∞

=Ey PXW

ε

XWtC,∀0< t <+∞

=1, where expectationEyis computed under the lawPy.Lettingε→0one obtains

Py(T0= +∞)=1.

Hence Proposition6is true ifX0W∂C.

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In order to prove this proposition we need the following two lemmas.

Lemma 8. ForxCdefine δ(x):=

αR+

·x)12k(α), (10)

thenδis harmonic inC forLWk given by(5),i.e.LWk δ(x)=0for anyxC.

Remark 9. It is important in the following proof that the functionkin the definition ofLWk is constant on the orbits ofRunder the action of the associated Weyl group.

Proof of Lemma 8. Fori=1, . . . , mlet Ri be the orbits ofR under the action of the associated Weyl groupW. DenoteR+i =RiR+. Then for any{i1, . . . , il} ⊂ {1, . . . , m}

Rˆ+=R+i1∪ · · · ∪Ri+l

is also a positive subsystem of the root systemRˆ=Ri1∪ · · · ∪Ril inRn (the two conditions in Definition 1 forRˆ are easily verified). Without loss of generality it is enough to consider the irreducible case and in that case there are at most two orbits. Hence, it is enough to prove the lemma form=2. Denote

πi(x)=

αRi+

·x).

Sincek:R→R+is constant onR+i define ki:=k(α), αR+i ,

then

¯

ωk(x)=π1k1(x)π2k2(x) and

δ(x)=π112k1(x)π212k2(x).

We want to prove thatLWk δ(x)=0 for anyxC. From Theorem 4.2.6 in ([4], p. 140), for any root systemR, if π(x)=

αR+·x), then π(x)=0.

Note that

π12k+2

π12k· ∇logπk

=0. (11)

Indeed

π12k= ∇ · ∇π12k= ∇ ·

(1−2k)π2k∇π

=(1−2k)

−2kπ2k1(π· ∇π )+π2k π

= −2k(1−2k)π2k1(π· ∇π ).

On the other hand 2

π12k· ∇logπk

=2k(1−2k)π2k1(π· ∇π )

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and the result(11)follows.

Denote

¯

π:=π112k1 and

ˆ π:=π1k1. We need to check that

A=

π112k1π212k2 +2

π112k1π212k2

· ∇log

π1k1π2k2

=0 or

π π¯ 212k2 +2

¯ π π212k2

· ∇log ˆ π π2k2

=0.

One has

π π¯ 212k2

=π212k2 π¯ + ¯π π212k2

+2

∇ ¯π· ∇π212k2 and

¯

π π212k2

· ∇log ˆ π π2k2

=

¯

ππ212k2+π212k2∇ ¯π

·

∇logπ2k2+ ∇logπˆ

=

¯

ππ212k2· ∇logπ2k2 +

¯

ππ212k2· ∇logπˆ +

π212k2∇ ¯π

· ∇logπ2k2 +

π212k2∇ ¯π

· ∇logπˆ , then

A=π212k2 π¯+2π212k2(∇ ¯π· ∇logπ )ˆ + ¯π π212k2

+2π¯

π212k2· ∇logπ2k2 +2

∇ ¯π· ∇π212k2 +2

¯

ππ212k2

· ∇logπˆ +2

π212k2∇ ¯π

· ∇logπ2k2 . But

¯

π+2(∇ ¯π· ∇logπ )ˆ =0 and

π212k2 +2

π212k2· ∇logπ2k2

=0, hence

A=2

∇ ¯π· ∇π212k2 +2

¯

ππ212k2

· ∇logπˆ +2

π212k2∇ ¯π

· ∇logπ2k2

=2π π¯ 212k2

∇logπ¯ · ∇logπ212k2 +

∇logπ212k2· ∇logπˆ +

∇logπ¯ · ∇logπ2k2 . But one has

∇logπ¯· ∇logπ212k2

=

∇logπ112k1· ∇logπ212k2

=(1−2k1)(1−2k2)(∇logπ1· ∇logπ2), ∇logπ212k2· ∇logπˆ

=k1(1−2k2)(∇logπ1· ∇logπ2), ∇logπ¯· ∇logπ2k2

=k2(1−2k1)(∇logπ1· ∇logπ2)

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and

(∇logπ1· ∇logπ2)= 1 π1π2

(π1· ∇π2)

= 1 2π1π2

1π2)π1 π2π2 π1

=0.

HenceA=0 and the lemma is proven.

In the same way one can prove the following lemma.

Lemma 10. ForxCdefine δ(x)¯ :=

αR+,k(α)=1/2

·x)12k(α)log

αR+,k(α)=1/2

·x), (12)

thenδ¯is harmonic inC forLWk given by(5).

Proof. Suppose thatk(α)=12 for anyαRthen for anyuC2(C),xC LW1/2u(x)=1

2

u(x)+

u(x)· ∇logπ(x) , whereπ(x)=

αR+·x). Then logπ(x)= − 1

π2(x)

π(x)· ∇π(x) + 1

π(x) π(x)= − 1 π2(x)

π(x)· ∇π(x)

and

logπ(x)+

∇logπ(x)· ∇logπ(x)

=0.

Denote

¯

π1:=

αR+,k(α)=1/2

·x)12k(α)=

1im,ki=1/2

πi12ki, ˆ

π1:=

αR+,k(α)=1/2

·x)k(α)=

1im,ki=1/2

πiki,

¯

π2:=log

αR+,k(α)=1/2

·x), ˆ

π2:=

αR+,k(α)=1/2

·x)1/2,

thenω¯k= ˆπ1πˆ2andδ¯= ¯π1π¯2. In order to prove Lemma 10 one needs to check that ¯1π¯2)+2

¯1π¯2)· ∇log(πˆ1πˆ2)

=0, but it is equal to

¯ π2

π¯1+2

∇ ¯π1· ∇log(πˆ1) + ¯π1

π¯2+2

∇ ¯π2· ∇log(πˆ2) +2(∇ ¯π1· ∇ ¯π2)+2π¯2(∇ ¯π1· ∇logπˆ2)+2π¯1(∇ ¯π2· ∇logπˆ1)

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and in the same way as in the proof of Lemma 8 one can see that it is equal to zero.

Using Lemmas 8 and 10 one obtains the following result, which will lead to a presentation ofXW (see Corollaries 13 and 14).

Lemma 11. Letω¯kbe defined by(8)andk(α)12for anyαR.Suppose thatX0Ca.s.,then there exists a unique solutionXof the stochastic integral equation

Xt=X0+βt+ t

0

∇logω¯k(Xs)ds, (13)

where(βt)t0is a Brownian motion onRn.FurthermoreP(t >0, XtC)=1.

Proof. We will follow the proof of the similar argument given in ([1] Lemma 3.2). Since the function∇logω¯kC(C)Eq. (13) has a unique (strong) maximal solution inC, defined up to timeζ, whereζ is an explosion time or the exit time fromC.

Case 1(k(α)=12 for anyαR). From Lemma 8 the functionδdefined by (10) is harmonic and positive onC.

By Ito’s formula one deduces that{δ(Xt), t < ζ}is a positive local martingale, thus it converges a.s. whentζ. But δ= +∞on∂C, thereforeXt → +∞whentζ. On the other hand by Ito’s formula fort < ζ

Xt2= X02+2 t

0

(Xs·dβs)+2 t

0

γds+t n

= X02+2 t

0

Xsdβ˜s+t (n+2γ ), whereγ=

αR+k(α)andβ˜t =t

0Xs1(Xs·dβs),t < ζ is a real-valued Brownian motion up to timeζ. This shows thatXt2is the square of a(n+2γ )-dimensional Bessel process up to timeζ (started atX02>0 a.s.).

SinceXt2→ +∞, by standard results (see [21], XI.1)ζ = +∞a.s. This implies thatT0= +∞a.s., whereT0is defined by (9).

Case 2(There existsαRsuch thatk(α)=12). From Lemma 10 and Ito’s formula,{¯δ(Xt), t < ζ}is a continuous local martingale. Let At := ¯δ(X),δ(X)¯ t for t < ζ andτt :=inf{s≥0|As =t}, then by Theorem 1.7 in ([21], Chapter V)Bt= ¯δ(Xτt)− ¯δ(X0)will be a real-valued Brownian motion up to timeAζ. Ifζ <+∞we have already seen thatXtcannot tend to+∞. Hence, iftζ, eitherδ(X¯ t)tends to+∞or to−∞. Therefore, eitherBt tends to+∞or to−∞, whentAζ, but that is impossible for Brownian motion, either becauseAζ <+∞, or because

Aζ= +∞andBt≥0(Bt≤0)infinitely often whent→ +∞.

Proof of Proposition 6. Let Cm:=

xCx·α > 1

m, αR,x< m

. (14)

TakegmC(Rn)such thatgm≡logω¯k onCm+1andgm≡0 onRn\Cm+2. For anyuCK(Rn), defineLmby Lmu(x)=1

2 u(x)+

u(x)· ∇gm(x) .

Let(XtW)t0be the radial part of the Dunkl process andτˆm:=inf{s >0|XWs/Cm}. For anyfCK(Rn)there existsf˜∈CK(C)such thatf˜≡f onCm+1. Then from(5)

f˜ XtW∧ ˆτ

m

− ˜f X0W

t∧ ˆτm

0

LWk f˜ XsW

ds=f XWt∧ ˆτ

m

f XW0

t∧ ˆτm

0

Lmf (XWs )ds (15) is a martingale.

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LetXbe the solution of(13)such that P(X0∈ ·)=P

XW0 ∈ ·

= ¯ν(·) (16)

forν¯∈P(C). Letτ¯m:=inf{s >0|Xs/Cm}. Then from Lemma 11 one deduces that

¯

τm→ +∞ a.s. (17)

Furthermore from(13)and Ito’s formula one deduces that f (Xt∧ ¯τm)f (X0)

t∧ ¯τm

0 Lmf (Xs)ds (18)

is a martingale forfCK(Rn).

By Theorem 3.3 in ([5], p. 379) for anyνP(Rn)the DRn[0,∞)martingale problem(Lm, ν)is well posed.

Then by Theorem 6.1 in ([5], p. 216) for eachνP(Rn)the stoppedDRn[0,∞)martingale problem(Lm, ν, Cm)is well-posed. But from (15), (18) and (16)X·∧ ˆWτ

m andX·∧ ¯τmare solutions of(Lm,ν, C¯ m). Hence XWt∧ ˆτ

m

t≥0 (d)=

Xt∧ ¯τm

t≥0 (19)

andPˆm< t )=P¯m< t ), for anyt >0. Hence from (17) ˆ

τm→ +∞ a.s.

and passing to the limit asm→ ∞in(19)one obtains that XWt

t0

(d)=(Xt)t0

and

T0= +∞ a.s.,

whereT0is defined by (9).

SinceXtW=π(Xt), whereXt is the Dunkl process one obtains Corollary 12. Let(Xt)t0be the Dunkl process,such thatX0∈Rn\

αR+Hα a.s.,with extended generator given by(2).Suppose that,for anyαR,k(α)12.Define

T0:=inf

t >0Xt

αR+

Hα

,

then

T0= +∞ a.s.

The proof of Proposition 6 leads to

Corollary 13. Let(XWt )t0be the radial Dunkl process,such thatX0Ca.s.,with extended generator given by(5).

Suppose that for anyαR k(α)12.ThenXW is the unique solution to the stochastic integral equation Xt=X0+βt+

t

0 ∇logω¯k(Xs)ds,

(11)

where(βt)t0is a Brownian motion inRnandω¯kis given by(8).This solution is strong in the sense of([12],IV).

Denoteν(·):=P(X0W∈ ·),thenXWis a unique solution to theCC[0,∞)martingale problem(LˆWk , ν),whereLˆWk is the restriction ofLWk onCK(C).

Suppose now that there existsαR such thatk(α) < 12 and consider the radial Dunkl process. The preceding results extend to this case if one works tillT0– the first time the process hits the walls of the Weyl chamber. Loosely speaking, here,T0is considered as if it were an “explosion time.” One gets the following corollary.

Corollary 14. Let(XWt )t0be the radial Dunkl process,such thatX0Ca.s.,with extended generator given by(5).

Suppose that there existsαRsuch thatk(α) <12.LetT0be defined by(9).Then(XWt , t < T0)is the unique solution to the stochastic integral equation

Xt=X0+βt+ t

0 ∇logω¯k(Xs)ds, t < T0,

where(βt)t≥0is a Brownian motion inRnandω¯kis given by(8).This solution is strong in the sense of([12],IV).

Proof. Is analogous to the proof of Lemma 11 and Proposition 6.

Remark 15. One can show that the result of Corollary14is true fort≥0andXW“reflects instantly” when it reaches

∂C(see[3]).

5. Skew-product decomposition of jumps

LetXbe a Dunkl process,π:RnCbe given by(4). SinceXis càdlàg andπ(X)is continuous it will be useful to introduce the spaceDπRn[0,∞)defined by

DπRn[0,∞):=

ωDRn[0,∞)|πωCC[0,∞)

. (20)

LetE:=Rn\

αRHα. Denote DπE[0,∞):=

ωDE[0,∞)|πωCC[0,∞) .

We will say thatXis asolution of theDπE[0,∞)(DπRn[0,∞))martingale problem(A, ν)ifXis a process with sample paths inDπE[0,∞)(DπRn[0,∞)) andXis a solution of theDE[0,∞)(DRn[0,∞)) martingale problem(A, ν).

Letλ >0 andαR+. LetD(A)CK(E)andR(A)CK(E). Suppose that for anyνP(Rn)there exists X – a solution of theDπRn[0,∞)martingale problem for(A, ν). We will need the following construction from ([5], p. 256). LetΩ=

k=1(DRn[0,∞)× [0,∞)) and(Xk, Δk)denote the coordinate random variables. DefineGk= F(Xl, Δl: lk)andGk=F(Xl, Δl: lk). Then there is a probability distribution onΩ such that for eachk Xk is a solution of theDπRn[0,∞)martingale problem forA,Δk is independent ofF(X1, . . . , Xk, Δ1, . . . , Δk1)and exponentially distributed with parameterλ, and forA1GkandA2Gk+1,

P(A1A2)=E IA1P

A2|Xk+1(0)=σα

Xkk)

(21) andP(X1(0)∈ ·)=ν(·). Defineτ0=0,τk=k

i=1Δi, andNt=kforτkt < τk+1. Note thatNis a Poisson process with parameterλ. Define

Y (t )=Xk+1(tτk), τkt < τk+1, (22)

andFt :=FtYFtN.

Notation 16. We will denoteY in(22)byXαN.

(12)

Lemma 17. LetD(A)CK(E)andR(A)CK(E).Suppose that for anyνP(E)there exists a solutionXof theDπE[0,∞)martingale problem(A, ν).Then for anyνP(E)there exists a Poisson processN with parameter λsuch thatY =XαN,whereα is defined by(22),is a solution of theDπE[0,∞)martingale problem(Aλ,α, ν), where for anyuD(A)andxE

Aλ,αu(x)=Au(x)+λ

u(σαx)u(x) . Furthermore if for anyuD(A)andxE

A(uσα)(x)=Au σα(x)

, (23)

then there exists a solution of(Aλ,α, ν)given by (Yt)t0:=

σαNtXt

t0,

whereNis a Poisson process with parameterλindependent ofX.

Proof. We follow the proof of Proposition 10.2 in ([5], p. 256). Since E is not complete one shall consider the DπRn[0,∞)martingale problem (A,ν). For any˜ ν˜∈P(Rn)letX˜0 be such thatP(X˜0∈ ·)= ˜ν(·). If ν(E)˜ =0, then X˜t:= ˜X0, for anyt≥0, is a solution of theDπRn[0,∞)martingale problem(A,ν). If˜ ν(E) >˜ 0 and(Xt)t0is a solu- tion of theDπE[0,∞)martingale problem(A,ν)¯ withν(¯ ·)= ˜ν(·)/ν(E),˜ ν¯∈P(E), thenX˜t:=XtI{ ˜X0E}+ ˜X0I{ ˜X0/E} is a solution of theDπRn[0,∞) martingale problem (A,ν). Taking˜ μ(x,·)=δσα(x)(·) and using Proposition 10.2 in ([5], p. 256) one obtains that Y = ˜XαN is a solution of the DRn[0,∞) martingale problem(Aλ,α,ν). Let˜

˜

ν=νP(E), thenX˜ ≡Xis a solution of theDπE[0,∞)martingale problem(A, ν). Furthermore, from (21) P

k≥1

Xk+1(0)=σα

Xkk)

=1

and P

k1

Y (τk)=σα

Y (τk)

=1.

Hence P

k1

π Y (τk)

=π

Y (τk)

=1.

Since Xk has paths in DπE[0,∞) for any k≥1 π(Y )is a.s. continuous and Y is a process with sample paths in DE[0,∞). HenceY is a solution of theDπE[0,∞)martingale problem(Aλ,α, ν).

Suppose now that(23)is true. LetN be a Poisson process independent ofX andτk :=inf{s≥0|Ns=k}. Let Yt=σαNtXt. Note that for anyuCK(E)

Mtu:=u(Xt)u(X0)t

0

Au(Xs)ds is a(FtX)-martingale.

Sincei)i0are independent fromMu, for anyk≥0 u

X

(tτ2k)τ2k+1

u X(τ2k)

(tτ2k)τ2k+1

τ2k

Au(Xs)ds (24)

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