R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
H OWARD S MITH
J AMES W IEGOLD
On a question of Deaconescu about automorphisms. - II
Rendiconti del Seminario Matematico della Università di Padova, tome 91 (1994), p. 61-64
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About Automorphisms. - II.
HOWARD SMITH - JAMES
WIEGOLD (*)
This note is concerned with groups G
satisfying
theproperty
thatAut H =
NG (H)/CG (H)
for allsubgroups H
of G. Such groups were re- ferred to in[3]
asMD-groups.
It was shown there that theonly
non-trivial finite
MD-groups
areZ2
andS3 ,
and Theorem 2.1 of the same pa- per gave acomplete
classification ofinfinite,
metabelianMD-groups.
Our first result here shows that all
(infinite)
solubleMD-groups
are infact metabelian.
Indeed,
rather more than this isproved.
Recall that agroup G is a radical group if the iterated series of Hirsch-Plotkin radi- cals reaches G.
(Thus,
forinstance, locally nilpotent
groups andhyper-
abelian groups are
radical.)
The class of radical groups iscertainly
closed under
forming
sections-inparticular,
every finite section of such a group is soluble.We shall prove the
following:
THEOREM 1. Let G be an
infinite,
radicalMD-group.
Then G ismetabelian and is thus an extension
of
atorsion-free, locally cyclic subgroup
Ahaving finite type
at everyprime p by
acyclic
group(x) of order 2,
such that a x =a -1 for
all a E A.As a consequence, we have:
COROLLARY. Let G be an infinite
locally
solubleMD-group.
Then Gis metabelian.
(*) Indirizzo
degli
AA.: H. SMITH:Department
of Mathematics, BucknellUniversity, Lewisburg,
PA 17837,U.S.A.;
J. WIEGOLD: School of Mathematics,University
of WalesCollege
of Cardiff,Senghenydd
Road, Cardiff, CF2 4AG, Wales.62
Our other result concerns
periodic MD-groups,
and shows thatZ2
and
S3
are theonly
such groups which are nontrivial.THEOREM. 2. Let G be a
periodic MD-group.
Then G isfinite.
PROOF OF THEOREM 1. In view of Theorem 2.1
of [3] (which
also shows that a group Ghaving
the structure described is anMD-group)
all we need do is show that an infinite radical
MD-group
is metabelian.Let G be a such a group. The
automorphism
group of each of the follow-ing
has a finite insoluble section: Z xZ, Zp
xZp
for p >3, Z2
xZ2
x~2 , 2g
xZg
x It follows that every abeliansubgroup
of G has finite rank andhence, by
a theorem of Baer and Heineken(see
p. 89 of[5]),
that Ghas finite rank. Since
Aut Cp co
isuncountable,
we see that everyperi-
odic abelian
subgroup
of G is reduced.Now let H be the Hirsch-Plotkin radical of G and let P be a
Sylow
p-subgroup
ofH,
for someprime
p. Then H ishypercentral
and P is re-duced and hence finite.
(For
the relevant facts aboutlocally nilpotent
groups of finite
rank,
see Section 6.3 of[5].) If p > 3, then, by
what wassaid in the
previous paragraph,
the centre of P iscyclic and,
if nontriv-ial,
contains a G-invariantcycle (z)
of order p. Since Aut2p
iscyclic
and of order
p - 1,
whileG / G’
hasexponent (at most) 2, by
1.3of [3],
we have a contradiction. Thus P =
1,
and the torsionsubgroup
of H is afinite
(2, 3)-group.
It followseasily (see [5])
that H isnilpotent.
If H isfinite then so is
G, contrary
tohypothesis.
Thus the centre Z of H con-tains an element a of infinite order. Since the torsion
subgroup
T of Z isfinite,
we may assume that(a)
G.Suppose
next that b is some nontrivial element of T. Then the mapa ~ ab, t ~ t,
for all t ET,
determines anautomorphism
« of(a)
x T =B,
say. Now Aut B is finite and so,by
theMD-property,
thenatural
embedding
ofG/CG (B)
in Aut B is anisomorphism.
So « is in-duced
by conjugation by
some element g ofG, contradicting
the factthat
(a)
a G. Thus Z and hence H is torsion-free.Further,
becauseZ x Z does not embed in G we see that H is
locally cyclic.
It followsthat
[H, G’]
= 1 since Aut H is abelian.But,
in a radical group, the cen-traliser of the Hirsch-Plotkin radical H is contained in H
(see [4,
Lem-ma
2.32]).
The result follows.PROOF OF THE COROLLARY.
Suppose
that theMD-group
G islocally
soluble. We notice from the
proof
of Theorem 1 that every abelian sub- group of G has bounded rank(at
most3)
andhence, by
a result of Mer-zlyakov (see
p. 89 of[5]),
G has finite rank. But alocally
soluble group with finite rank ishyperabelian ([5,
Lemma10.39])
and the result fol- lows from Theorem 1.PROOF OF THEOREM 2. Let G be a
periodic MD-group
andlet p
beany
prime
such that G contains an element of order p.Every
infinite el-ementary
abelian p-group has anautomorphism
of infinite order. Thesame is true of
CpCX1
and so every abelianp-subgroup
of G is finite. It fol- lows that everylocally
finitep-subgroup
isfinite,
and thus we may choose a maximal finitep-subgroup
P of G. LetN,
Crespectively
de-note the normaliser and centraliser of P in G and assume that P does not have
prime
order. Then Out P contains an element oforder p [1]
and
thus,
ifX / C
is anySylow p-subgroup
ofN/ C,
thenIX/CI I
>I PIZ(P) I Choosing
X so that P ~X,
we see that there existsx E X such that x P E PC
but r g
PC. Since G isperiodic,
we may assume that x is ap-element.
But then~x, P)
is ap-subgroup properly
contain-ing P,
a contradiction. Thus all(locally)
finitep-subgroups
haveprime
order.
Next,
suppose that G has a sectionK/L
of order 4.Certainly K/L
isnot
cyclic,
since G has no elements of order4,
and so 1~ _(L,
a,b),
where each of a and b has order 2. Now
(a, b)
is aperiodic image
of theinfinite dihedral group and therefore it is finite and contains a 2-sub- group of order at least
4,
a contradiction. We deduce that G has no sub-groups H
such that Aut H contains asubgroup
of order 4. Inparticular
G contains no
subgroups
oftype Zp
xZq where p and q
are oddprimes.
Since G itself contains no
subgroups
of order4,
it also cannot contain asubgroup
oftype Zp
xZ2.
It follows that every abeliansubgroup
of Gis of
prime
order. We now claim that G contains no elements of order p for anyprime
p > 3.Suppose (for
acontradiction)
that G has a sub- group(a)
of order p, where p is the least suchprime greater
than 3.Then
CG (a) = (a)
and so the normaliser N of(a)
has orderp(p - 1). By
the
minimality of p,
we seethat p -
1 =2k 3l
for somek, 1 and,
since theSylow subgroups
of N are ofprime order,
we have k = 1 = 1and p
= 7.But Aut
Z7
= and G has no elements of order 6. This contradiction establishes our claim. We now see that every finitesubgroup
of G hasorder at most 6 and
(of course)
that G hasexponent dividing
6.By
M.Hall’s solution of the Burnside
problem
forexponent
six[2],
G islocally
finite and therefore finite. The result follows.
REFERENCES
[1] W.
GASCHÜTZ,
Nichtabelschep-Gruppen
besitzen äusserep-Automorphis-
men, J.
Algebra,
4 (1966), pp. 1-2.[2] M. HALL Jr., Solution
of
the Burnsideproblem for
exponent six, Illinois J.Math., 2 (1958), pp. 764-786.
64
[3] J. C. LENNOX - J. WIEGOLD, On a
question of
Deaconescu about aut-morphisms,
Rend. Sem. Mat. Padova, 89 (1993), pp. 83-86.[4] D. J. S. ROBINSON, Finiteness Conditions and Generalized Soluble
Groups,
Vol. I,
Springer-Verlag,
Berlin (1972).[5] D. J. S. ROBINSON, Finiteness Conditions and Generalized Soluble
Groups,
Vol. II,
Springer-Verlag,
Berlin (1972).Manoscritto pervenuto in redazione il 3