R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
D IETER H ELD
The situation of Sp
4(4) · 2 in the sporadic simple group He
Rendiconti del Seminario Matematico della Università di Padova, tome 80 (1988), p. 117-125
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in the Sporadic Simple Group He
DIETER HELD
(*)
0. Introduction.
The
objective
of this paper is to prove thefollowing
result:THEOREM. The
simple
group He contains an extension of~’p4(4) by
the fieldautomorphism
as a maximalsubgroup.
REMAKK.
Recently,
researchers have shownincreasing
interestin the
study
ofgeometries
for thesporadic simple
groups; see for instance[4].
For suchstudies,
a solid information about the maximalsubgroups
of the group inquestion
ismandatory.
Also for the purpose of existenceproofs by
coset enumeration methodes one needs detailedknowledge
of the situation of thesesubgroups. Although,
the assertionof the theorem is contained in an
unpublished
articleby
W. Gemmer[3],
the
proof, there,
is notcompletely
without flaws.Therefore,
and be-cause the content of the theorem has been used
by
variousauthors,
it seems worthwhile to
present
adirect,
short andconceptional
ar-gument
for it.In what
follows,
we shall denote Heby G,
and shall make use of the information about the local structure of G contained in[6]. By
~Sp4(4)
we denote theprojective symplectic
4-dimensional groupover
GF(4).
(*) Indirizzo dell’A.: Fachbereich Mathematik der Universitat, D-6500 Mainz,
Rep.
Fed. Tedesca.118
1. A
(B, N)-pair
oftype Sp,(4).
The
Sylow 2-subgroup
T of G containsprecisely
twoelementary
abelian
subgroups .R1
and of order 26. These twosubgroups
arenot
conjugate
in G. We have thatN(Ri) splits
overRi,
and that acomplement Mi
ofR, in
has thefollowing properties:
=3,
A6, £6’
and= Put
h~~
=O(M;). Then, hi
actsfixed-point-free
on.Ri .
Itis known that
Thus,
is a group of order 28.32. Since[hl, h2]
ERl n R2,
we mayconjugate h2
and.~12 by
anelement of
Rl
n.R2 to get
that H =h2~
is anelementary
abeliangroup of order 9.
Clearly,
is 2-closed andCR1Rs(H)
=1>,
since
hi
actsfixed-point-free
on.Ri
f or i =1, 2;
note that an involutionof
R1R2
liesin Ri
U.R2.
Put
.R2 = zl,
I Z31n,ft7:).
In Z there areprecisely
twofour-subgroups consisting
of non-central involutions. These areZ1
==
and Z2 =
Note that Z possessesprecisely
9 central involutions of G.
Clearly,
H normalizesnon-trivially Z,
and
Z2 .
Sincehi, hi , h2 , h2
actfixed-point-free
on Z and are all 3-central,
weget
that all elements of He are 3-central inG ;
note that anelement of order 3 of G does not centralize an
elementary
abeliansubgroup
of order 8 in G. It isimportant
to observe thatZl and Z2
are
conjugate by
theinvolution z2 E T
and thatSince H normalizes
R1
and there is an H-invariantcomplement yY2
of Z inI~1
and an g-invariantcomplement yP1
of Z in.R2 by
Maschke’stheorem.
Compute [h2 , W2]
CR2 ç; .Rl n W2
=1)
andc
WI
nRl
CR1
n.I~2
nWi
=1 >.
Weget
Since hi
actsfixed-point-free
on we see that andare both
isomorphic
to.Å4.
Now, (hi, h2~
acts onZi
as anautomorphism
group of order 3.Hence,
7hI h2
orh 1 h’ 2
centralizesZ,,. Interchanging h2
andh22 if
neces-sary, y we may and shall assume that
[hlh2, Zl]
=1>.
It follows thatZ,]
=1>. Hence,
and are bothisomorphic
to
A,.
We have obtainedCl earl y,
Remember that
Zf2 = Z2.
Weapply
now[6;
Lemma(3.4)]
andget
that r1 is a
splitting
extension ofBj by
a groupisomorphic
to
As.
Weput
Thus,
Consider the
subgroup Pi
=Bihi>. Clearly, lpil
=28 32 5,
andby
a result of W.Gaschiitz,
weget
thatPi
= where= 3 and for i =
1,
2. From earlierinformation, he
acts
fixed-point-free
onl~i
and = The groupgenerated by
all 2-elements and all 5-elements ofPi
isequal
toIt follows
.RiLa= Bi.
Weconjugate
onto(hi) by
an elementso that
hi
centralizesi5§’ = L,. Then,
We know that
h,
centralizes and thatN(Ri)
n(1
Clearly,
c rlBl
=L1. Analogously,
Remember that
Li -v A5.
There is aninvolution ri
inLi
such thatBy choice,
we have[~i~i]==[~2~2]==l’
Weget
that120
Let us describe the action of
rl, r2)
on H:Thus,
It follows
Put N =
r2>.
Since r2r,:h,
-hlh2’-
we see thatr2~
inducesa non-abelian
automorphism
group of H and(rx r2)4 E C(H). By
a resultof
[2],
we haveC(H)
= H X~y where
is afour-group having only
non-central involutions and
~~s(4).
Since elements of order 8 in G are roots of central involutions ofG,
we see that rl r2 cannot have order 8. The caseo(rlr2)= 233
cannot occur, since in G thereare no elements of order 24. It follows that
(r1 r2)4
E .g. Thisimplies
that
Dg
andC,(H)
= H. In what follows weput NfH
=W ;
note that yY is the
Weyl-group
and .H is aCartan-subgroup
of~(4).
Compute:
We
get
further:It follows
since and
Rl n R2
· From the structures of the centralizers of elements of order 3 in G weget
If r, would lie in
~T(.1-~2),
then r, would normalize and alson R2
= Z which isagainst Z
r1Z21
= Z =1>. Thus, r, 0
Analogously,
weget T2 f! N(Ri)
and Z nZ[2
= Z r’1W1
=(1) .
Oneobtaines
Amongst
otherfacts,
we haveproved
thefollowing
result:Put B = We shall show that the
following
conditionsof
[8]
are satisfied:(i’)
B uBriB
is asubgroup
of G for i =1, 2;
(iv)
If for some WE W in thegenerators
r., r2 thenWe have Bri n B = note that H acts
transitively
onand
that r1 E N(B)
asr,, 0 N(R1R2)
and =Similarly,
onegets
n B=1~2g. Therefore,
the number of left cosets of B inBri B
isequal
to[B :
B r1 = 28 32: 26 32 = 4. It follows that B U =Pi
=Ri«hi) X L~)
for i =1,
2. We have shown that(i’)
holds.
Note that if i =
1,
and that- - -I
Case 1.
Here,
i = 1 and w = r2 .Compute:
It follows
Case 2.
Here, i
= 1 and w =Compute :
It follow ~’
Compute:
122
It follows
Case 4.
Here,
i = 2 andCompute:
It follows Br, C
Case 5.
Here,
i = 2 andCompute :
Ca8e 6.
Here,
i = 2 and w == r1r2r1:Compute:
It follows C BrZrlrarl B.
Application
of[8] yields
that U = BNB is asubgroup
of (~. Note that B r1 N= .H,
since = H and B is 2-elosed. A further ap-plication
of[8] yields
that w = w’ is forcedby
BwB = Bw’ B for w, w’ E W. It followswhere w runs
through
all elements of W.Note that and so, we have to
compute [B :
Bw nB]
forthe
eight
elements of W.Obviously, [B :
B1 nB]
= 1. Since r1n
RIR2
=1),
weget
that an H-invariantsubgroup
of hasorder
2i,
where i is even; see[5; V.3.15].
We knowalready
that[B :
nB]
= 22. It is clear that Bw r1 B is normalizedby .H,
since_ .H for each WE W.
Thus, [B :
Bw nB]
= 2’ i with i even. Forthe order of ZJ we
get
thefollowing equation:
where as
IRIR21
= 28.By
our aboveremark,
we have thatij
is even.We had
proved
earlierN(B)
for i =1,
2. It followstogether
with[8]
that the conditions of definition(3.24)
of[7]
aresatisfied. In
particular,
theorem(3.28)
of[7]
holds. Thisimplies
thatNu(P)
= P for anysubgroup
P with B.Hence,
=B,
and so Bw n B c B for ~W~. It follows
2ii >
4for j
E~4, ... , 8~ ;
remember
that ij
is even.Put~=(l+4+4+2~+...+2’"). Then, jt7)= 2~3~.~.
Weknow that 5 divides n. Since divides we
get
that n divides 3.527317 = 437 325. A littlecomputer
programgives
the solution:Thus
We want to show that U ~
Sp4(4). By
the result of[1]
it isenough
to prove that U is a
simple
group all of whose involution centralizersare 2-constrained. Since in G there is no odd order
subgroup
normalizedby
weget
thatO(U) = 1~.
Since an element of order 17 does not centralize an involution ofG,
weget
that02( U) _ 1~.
Denote
by
g a minimal normalsubgroup
of U.Then,
17 dividesJEJ,
since otherwise we would
get
a contradiction to the fact that aSylow 17-subgroup
isselfcentralizing;
note that g cannot be solvable. Since 172 does not divide weget
that K is asimple
group.Denote
by S
aSylow 17-subgroup
of IT.Then, by
Frattini’s ar-gument,
we have U =K. Nu(S).
Since .g issimple
andnon-abelian,
we must have
by
a transfer lemma due to Burnside.Hence, [U: K]
divides4,
sinceING(S)/SI
= 8. ButRIR2
has no elements oforder 8. This forces
[ U: K]
E{1, 2}.
Assume that[ U: K]
= 2.Then,
we have
[K[
= 27 32 52 17. Let .R be aSylow 2-subgroup
of .~ which lies inRlR2. Evidently, IRI
( =27,
and so, .1~ is nor- malizedby
.g which-however-isagainst C(H)
r1R1R2 = I).
Itfollows
[U: K]
=1,
and thisimplies
that U is asimple
group.We have still to show that the centralizer of every involution of U is 2-constrained
using easily
accessible information from[6].
From the structure of we
get == R1R2; obviously
ist 2-constrained. In
G,
the involutions z,,n and z1z3n areconjugate
via z2 . We know that and that
also
~~=2~3-5.
From the order of U and the structure of weget
that =B1
and =B2 . Clearly, Ba
is 2-constrained fori = 1, 2.
If r1Nu(R1)I I =
=
28 3 ~ 5,
then we wouldget Bl = ~
sinceB2
would be theunique
normal
subgroup
of index 3 in But this is notpossible,
as 5124
does not divide
Thus,
r1=
2s.3. It followsthat there are
precisely
three U-classes of involutionspassing through Ri. Representatives
for these classes are zl, z,,7r, and Thesame result holds for the U-classes of involutions
passing through 1~2.
Since every involution of U is
conjugate
in U to an involution ofRi
we have obtained that the centralizer in U of every involution of U is 2-constrained.Moreover,
one observes that U hasprecisely
three classes of involutions. We have
proved
thatU 1".1 Sp4(4) ,
2. The
maximal subgroup isomorphic
to,~p4 ( 4 )
extendedby
the field.automorphism.
In the last section we have
proved
the existence of asubgroup
Uof G such that U 1".1
Sp,(4)
We know that U isgenerated by
the sub-groups
Pl
andP2
ofU,
as ri EPi
for i =1, 2,
and also B CP2.
Consider the element
z2 z~’. Clearly, z2 z’
normalizes but is not contained in We know also that andZ~z~ z~’~
are bothisomorphic
toThus, Bl, Z27:’)
isequal
to r1 and~B2, z2 ~’~
isequal
to r1Application
of[6;
Lemma(3.2)] yields
thatBi, z2 z~’~
is asplitting
extension of.Ri by ~s;
inparticular,
weget
thatZ27:’
normalizesBi
for i =1,
2.Clearly, [h,7 Z27:’]
E and[h2, Z27:’]
E.1~2~h2~.
It follows that bothP,
andP2
are normalized
by Z2 7:’. Therefore, 7:’)
is asubgroup
of G whichobviously
is an extension ofSp4(4) by
thefield-automorphism.
Put
Go
=7:’).
We showfinally
thatGo
is a maximalsubgroup
of G.
Sylow’s
theoremgives
thatINGo(S)I
=2317,
where S is aSylow
17-subgroup
of U. Note thatNao(S)
is the full normalizer of S in G.Let .~ be a
subgroup
of G such thatThen, [M: Go]
isequal
to a divisor t of 2.3.73 such that t _--_ 1 mod 17. Theonly possibility
is t = 2058.Thus,
M = G andGo
is a maximalsubgroup
of G. The theorem is
proved.
REFERENCES
[1] B. BEISIEGEL, Über
einfache
endlicheGruppen
mitSylow 2-Gruppen
derOrdnung
höchstens 210, Commun.Algebra,
5(1977),
pp. 113-170.[2] G. BUTLER, The maximal
subgroups of
thesporadic simple
groupof
Held,J.
Alg.,
69 (1980), pp. 67-81.[3] W. GEMMER, Eine
Kennzeichnung der einfachen Gruppe
von Held,Diplom-
arbeit, Universität Mainz, 1974.[4] E. GERNER, Ein
Apartment für
eine Geometrie dersporadischen einfachen Gruppe
He, J.Algebra,
to appear.[5] D. GORENSTEIN, Finite groups,
Harper
and Row, New York, 1968.[6] D. HELD, The
simple
groups related toM24,
J.Alg.,13
(1969), pp. 253-296.[7] M. SUZUKI,
Group theory
I,Springer-Verlag,
Berlin, 1982.[8] J. TITS, Théorème de Bruhat et sous-groupes
paraboliques,
C. R. Acad. Sci.Paris, 254
(1962),
pp. 2910-2912.Manoscritto pervenuto in redazione il 21