A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
L EV A IZENBERG
L AWRENCE Z ALCMAN
Instability phenomena for the moment problem
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 22, n
o1 (1995), p. 95-107
<http://www.numdam.org/item?id=ASNSP_1995_4_22_1_95_0>
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LEV AIZENBERG - LAWRENCE ZALCMAN
Suppose K
is a compact set in C" orR",
andlet u
be a finitecomplex
Borel measure on K. In this paper we
show,
underappropriate
conditions onK,
that if theanalytic
or harmonic moments decreasesufficiently rapidly (or
growsufficiently slowly)
in a certainprecise
sensedependent
onK,
thenthese moments vanish
identically.
In the most favorable cases, it is thenpossible
to conclude
that o
= 0. Thisphenomenon
does not seem to have been noticedpreviously,
even in the classical case of the power momentproblem
for a finiteinterval in R.
In the
sequel
all measures are Borel.1. -
Holomorphic moments, n
= 1We
begin
with a discussion of the situation for n = 1.THEOREM 1. Let K be a compact set in the
plane
which does not contain theorigin,
andlet a be a finite complex
measure on K with momentsIf
and K does not separate 0
from
oo(i. e.,
0belongs
to the unbounded component thenIf
K does separate 0from
oo, thenfor
each sequencesatisfying (2)
there is a measure ~u on K
having
as its moment sequence,i. e.,
such that(1)
holds.Pervenuto alla Redazione il 23
Giugno
1994.PROOF.
Suppose
that K does not separate 0 and oo. LetClearly,
F isanalytic
off K.Expanding
F in a power series about 0, we findwhere the aj are
given by (1).
If(2) holds,
this series convergesuniformly
on an open disc
containing
K.Thus,
the restriction of F to the unbounded component extends to beanalytic
on the entirecomplex plane.
SinceF(oo)
= 0, F vanishesidentically,
so aj = 0for j
=0, 1,2, ....
Now
suppose
that K separates 0 from oo. Denoteby
U the unboundedcomponent
of C BK
and consider the space A of all continuous functions on K U U which areanalytic
on U.By
the maximum modulusprinciple,
max I
defines a norm on A under which it is identified with a Kclosed
subspace
ofC(K).
Let be a sequence which satisfies(2),
so that00
Then the function
Sp(z) = L CLnzn
isanalytic
onIzl R},
and we mayn=o
choose p
so thatmax
KIzl
p R. Now setwhere r is the
positively
oriented circle of radius p about theorigin. Clearly,
Thus L defines a continuous linear functional on
A,
which(by
the Hahn-BanachTheorem)
extends to all ofC(K).
Thus there exists a finitecomplex
measureit on K such that
On the other
hand,
we haveSince the functions =
z-~+1>, j - 0,1,2,...,
allbelong
toA, (3) yields L( f j )
= aj. It then follows from(4)
that the measure it has moment sequencei.e.,
that(1)
holds. DNote,
inparticular,
that one may choose such that(2)
holds butaj f0
for
all j.
An
analogous reasoning,
based onexpanding
the functionF(z)
in a Laurent series about thepoint
z = oo,yields:
THEOREM 1’. Let K be a compact set in the
plane
which does not contain theorigin,
andlet it
be afinite complex
measure on K with momentsIf
and K does not separate 0
from
oo, thenb1’
= 0for all j
=0, 1,2, ....
If
K does separate 0from
oo, thenfor
each sequencesatisfying (2’)
there is a measure it on K
having
as its moment sequence, i.e., such that(1’)
holds.COROLLARY 1.
Suppose
K has empty interior,CBK
isconnected,
andK. Then
(2)
and(2’)
eachimply
that it = 0.PROOF.
Suppose
that(2’)
holds.Then, by
Theorem1’,
allanalytic
moments( 1’)
vanish.Taking
linear combinations showsthat it
isorthogonal
to allanalytic polynomials. By Mergelyan’s Theorem,
any function inC(K)
can beuniformly approximated
on Kby
suchpolynomials.
annihilates all elements ofC(K)
and hence vanishesidentically.
If(2) holds,
theproof
of Theorem 1 shows thatF(z)
vanishesidentically.
Thus the coefficients of its Laurentexpansion
about oo
(given by ( 1’))
areidentically
zero, soagain ti
= 0. DWhen K is an interval that does not contain the
origin,
it ispossible
tostrengthen Corollary
1 under theassumption
that it does notplace
any mass at the(relevant) endpoint
of[a, b]. Specifically,
we haveCOROLLARY 2. be a
finite complex
measure on[a, b]
C R, where0 a b.
If
either = 0 andor
~,({a})
= 0 andthen it = 0.
PROOF.
Suppose
Let
so that
F(z)
isanalytic
on(CB{b}.
For y > 0 we havewhere
Py
is the Poisson kernel for the upper halfplane.
Since(Py
*converges weak* to it as y - 0, we have
for any function
f
ECo(R).
Now fix c E
(a, b)
andlet p
E besupported
in[0, c].
We havesince F is
analytic
on[0,c]. Taking
the sup over allsuch p satisfying
1,we = 0. It follows
that
=0; and,
since1A(i b})
=0,
0 This result
applies
inparticular
toabsolutely
continuous measures,i.e.,
functions in
L 1 ( [a, b] ).
REMARK. The first
part
of Theorems 1 and 1’ hold notonly
for measuresbut for distributions of
compact support
and foranalytic
functionals aswell;
the
proofs
remain the same. As a consequence ofthis,
we have:COROLLARY 3. Let
f
be an entirefunction
such thatSuppose
thatfor
some p > 0 one hasThen
f -
0.I f,
inaddition, f
EL2(R) (i. e., f
is in the Wiener class[A 1,
p.166]),
wemay relax the
inequality
in(6)
to allowequality.
PROOF. If
(5) holds,
thenf(z) = u(e-ixz),
where u is a distributionsupported
on[-r, r],
cf.[Ru,
p.183].
Nowwhere ul is a distribution whose
support
lies in[p, p + 2r].
It follows thatBy Corollary
1(and
theprevious Remark),
it follows that Ul 1 = 0 and hencef m
0. Whenf
e the distribution Ul 1 is a function inL2 ( [ p, p + 2r ] ),
sothe result follows from
Corollary
2. D2. -
Holomorphic moments,
n > 1We shall follow the conventional notations for multi-indices.
Thus,
fora =
(al,
a2,...,an)
ann-tuple
ofnon-negative integers
and z =(zi ,
z2, ... ,zn)
E Cn we shallwrite
at + a2 + ... + an For K a_
n
compact
set inC",
setda(K)
= maxand K
=U {w : rZj
nK ~ ~},
whereK
.. ~=~{w
E Cn : W1’ =zj }.
Putlj" x lj
x...xê (n times).
THEOREM 2. Let K be a compact set in en such =
1, ... ,
n, K and thepoints
0 and(oo, ... , oo) belong to the
same connectedcomponent be
a finite complex
measure on K with momentswhere I =
( 1, ... , 1 ).
If
then aa = 0
for
all a E(Z +)n.
PROOF. Let
Clearly,
F isanalytic
onênBK. Expanding
F in a power series about 0, we findwhere the aa are
given by (7).
Since(8) holds,
the series convergesuniformly
on a
complete
Reinhardt domain Dcontaining K ([AM]
cf.[F,
pp.49-51]).
Denote
by
U thecomponent
ofênBK containing
0 and(oo,..., oo). Clearly,
Fis
analytic
on D U U. Inparticular,
it isanalytic
on the union of npolydiscs
about the
origin, the j-th
of whichhas j-radius equal
oo. Since theenvelope
of
holomorphy
of this union isclearly
all of the series for F convergeseverywhere
and thus defines an entire function. ButThus F vanishes
identically,
so = 0 for all of such that aj >0, j
=1, 2, ... ,
n.0 COROLLARY 4. Let K be as in Theorem 2.
If
everyfunction in C(K) is unifor7nly approximable
on Kby polynomials in
then(8)
= 0.PROOF.
According
to Theorem2,
all aa = 0.Consequently,
for everypolynomial
P one hasThus,
for every p EC(K),
0 When K is a subset of the real
subspace
R" of en which does not intersect the coordinateplanes,
theapproximation
condition ofCorollary
4 holds(by
theStone Weierstrass
Theorem).
Thus we have:COROLLARY 5. Let K be a compact set in c en which does not intersect the coordinate
planes. If (8) holds, then it
= 0.PROOF. In this case, the
projection
of K onto eachcomplex
coordinateplane
does not separate 0 and oo there.Thus,
thepoints
0 and(00, ... oo) belong
to the same connected component of so the
hypotheses
of Theorem 2and
Corollary
4hold,
and hence ~c = 0. 0In
analogy
withCorollary 3,
we have also:COROLLARY 6. Let
f
be an entirefunction
in en such thatSuppose
thatfor
some p > 0 we havewhere
and a ! =
a 1 ! ...
an !. Thenf -
0.If, in addition, f
E we may relax theinequality
in(9)
to allowequality.
Denote
by
J the collection of 2n vectors of the form p =(pl, p2, ... , pn)
where
py = ±1
foreach j.
A vector p E Joperates
on apoint z
=(zl , ... , zn)
with nonzero coordinates viap(z) = z2P2,...
LetpK
be theimage
ofK under this
mapping
and setThe
following
extension of Theorem 2 obtains.THEOREM 3. Let K
and it
be as in Theorem 2 withcnBK
connected.If
holds in
place of (8),
then all the momentsaP
= 0(so
that a,3 = 0for
all03B2 e Z
COROLLARY 7.
If, in addition,
everyfunction
inC(K)
isuniformly approximable
on Kby polynomials
in Z¡,..., Zn and1/ Zl , ... , 1/ Zn,
then( 10) implies
p, = 0.Denoting by R(K)
the uniform closure on K of the rational functions which areholomorphic
on K, we see that when K satisfies the conditions ofCorollary 7,
one hasC(K)
=R(K).
It does not seem easy to findgeneral
conditions which insure this. For
instance,
one may haveR(K)fC(K)
evenwhen K is
polynomially
convex and contains noordinary analytic
structure.EXAMPLE. Let X be a Swiss Cheese
[ZI,
pp.69-70], i.e.,
acompact
set in C without interior such that It is well-known that there exists p ER(X)
such that zand p generate R(X), i.e., polynomials
in zand p
areuniformly
dense inR(X). (This
is theBishop-Hoffman Theorem;
for theproof,
cf.
[Ro,
Theorem3.6].)
We mayclearly
choose Xand p
so that 0belongs
tothe unbounded
component
of X andp(z) f0
on X. Now set4D(z) = (z,
andput K
=(D(X). Evidently,
K contains noanalytic
discs. LetP(K)
be theuniform
algebra
of functionsuniformly approximable
on Kby polynomials.
Now = F defines an
algebra isomorphism
ofC(K)
ontoC(X)
whichmaps
P(K)
ontoR(X).
SinceR(X) fC(X)
we have On the otherhand,
since thespectrum
of the Banachalgebra R(X)
is X, thespectrum
ofP(K)
is K,i.e.,
K ispolynomially
convex.Hence, by
the Oka-WeilTheorem, R(K)
=P(K),
so that3. - Harmonic moments
In
discussing
harmonic moments, it will be convenient to consider thecases n = 2 and n > 3
separately.
Webegin
with n > 3. Denoteby Bl
theopen unit ball in Rn and
by aBi
itsboundary,
the unitsphere.
Let be anorthonormal basis of
homogeneous
harmonicpolynomials
inL2(aB,), where j
is the
degree
ofPj,s
and s =1, ... , ~ (j, n).
THEOREM 4. Let K be a compact set in Rn
(n
>3)
which does not contain theorigin,
andlet a
be afinite complex
measure on K with momentsIf
and K does not separate 0
from
oo, then a1’,s = 0for
allj,
s.If
K does separate 0from
oo, thenfor
each collectionof
numberssatis, fying (12)
there is a measure on K such that( 11 )
holds.PROOF. Consider the Newtonian
potential
Clearly,
F is harmonic on For the fundamental solution of theLaplace equation
in(n > 3),
one has theexpansion ([D],
cf.[Al,
Lemmas 36.3 and38.5])
where
S2n
is the area of the unitsphere 8B1,
and the series on theright-hand
sideof
(13)
convergesuniformly together
with all derivatives oncompact
subsets of the cone{(x, y)
EI y Expanding
F in a series ofhomogeneous polynomials
in aneighborhood
of 0, we findwhere the are
given by (11).
If(12) holds,
then the series convergesuniformly
on some ballBR
with radius R >max I x 1.
Then the restriction ofK
F to the
unbounded ·component
of extends to be harmonic on all of Rn.Since
F(oo)
= 0, it follows that F - 0, so a 1’,s = 0 for allj,
s.Now suppose that K
separates
0 from oo. Denoteby
U the unboundedcomponent
of(R~
U{oo})BK
and consider thespace H
of all continuousfunctions on K U U which are harmonic on U.
By
the maximumprinciple, [[ f[[H
=max I
defines a norm on H under which H is(identified with)
aK
closed
subspace
ofC(K).
Now suppose that the a1’,ssatisfy (12),
so thatChoose p such that max
I x
p R and setK
This series converges
uniformly
on each ballBr,
rR,
and defines a harmonicfunction on
BR.
PutClearly,
Thus L defines a continuous linear functional on
H,
which(by
the Hahn-BanachTheorem)
extends to all ofC(K).
Thus there exists a finitecomplex
measureJJ on K such that
Now the functions
obtained
by applying
the Kelvin transformation withrespect
toaBl
to allbelong
to H. Thusby (14)
and(15)
we haveby
theorthonormality
ofIPj,,)
onaBle
It now follows from(16) that it
hasthe a1’,s as its harmonic moments,
i.e.,
that(11)
holds. DIn
analogy
with Theorem 1’ we have thefollowing analogue
of Theorem4.
THEOREM 4’. Let K be a compact set in
(n
>3)
which does not contain theorigin
and be afinite complex
measure on K with momentsIf
and K does not separate 0
from
oo, then all the moments a1’,s = 0.If
K does separate 0from
oo, thenfor
each collectionof
numberssatisfying (12’)
there is a measure on K such that( 11’)
holds.The two-dimensional
analogues
of Theorems 4 and 4’ are also valid. Hereone
has (J (j, 2)
= 2 forall j
> 1. One may takeP1’,l (Xl, X2)
=Re(x
1 +iX2Y
andP1’,2(Xl, X2)
=Im(x
+ up to anormalizing
constant.Writing
Xl +iX2
= z, oneconsiders,
inplace
of the Newtonianpotential,
thelogarithmic potential
which is
again
harmonic on If(12)
or( 12’) holds,
the restriction of F to the unbounded component ofJR2BK
extends to be harmonic on all ofJR2. Evidently, IF(z)1 Clog Izl
forlarge Izl.
It follows from a version of Liouville’s Theorem[Bu, Corollary 6.33]
that F is constant. To see that F = 0, observe thatsince
log 1 - - I
tendsuniformly
to 0 on K as z -~ oo. But the left hand side isfinite,
sowezmust
haveJj(K)
= 0. ThusF(oo)
= 0 and F vanishesidentically.
Denote
by h(K)
the hull of K,i.e.,
the union of K with all the boundedcomponents
of itscomplement.
Recall([L,
p.307])
that a set E is thin atxo E R~ if either E does not have xo as a limit
point
or there exists a functionv
superharmonic
on R" such thatCOROLLARY 8.
Suppose
that int K = 0 andRnBh(K)
is not thin at anypoint of
K. Thenif 0 ~
K and K does not separate 0from
oo,(12)
and( 12’)
each
imply
- 0.This follows from Theorem 4 and 4’
together
with the fact([Br],
cf.[D])
that in this case every function in
C(K)
is the uniform limit on K of harmonicpolynomials.
As an immediate consequence we have:
COROLLARY 9.
Suppose
that K has zeroLebesgue
measure in Rn, isconnected,
and0 ~
K. Then(12)
and(12’)
eachimply
0.Indeed,
sinceRnBK
isconnected, h(K)
= K. ButRNBK
is nowhere thin if K hasLebesgue
measure 0, since otherwise(17)
would be inconsistent with thesuper-mean-value property
ofsuperharmonic
functions for balls around xo.4. - Final comments
This work is in
large
measure a continuation of[A2],
whereproblems
ofMorera
type
were considered for non-closed curves andpieces
ofhypersurfaces.
For further information on such
problems
see[Z2], [Z3],
and[BCPZ].
Additionalmotivation for the
questions
considered here is in[AR]
and the papers listed there.We are
grateful
to Paul Gauthier forenlightening
discussions on harmonicapproximation
and to T.W. Gamelin forproviding
the reference[Ro].
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[A2] L. AIZENBERG, Variations on the theorem of Morera and the problem of Pompeiu.
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[AM] L.A. AIZENBERG - B.C. MITYAGIN, The spaces of functions analytic in multicircular domains. Sibirsk. Mat. Zh. 1 (1960), 153-170, (Russian).
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[Br] M. BRELOT, Sur
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[D] J. DENY, Systèmes totaux de fonctions harmoniques. Ann. Inst. Fourier 1 (1949),
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[F] B.A. FUKS, Introduction to the Theory of Analytic Functions of Several Complex
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[L] N.S. LANDKOF, Foundations of Potential Theory. Springer-Verlag, Berlin, 1972.
[Ro] H. ROSSI, Holomorphically convex sets in several complex variables. Ann. Math.
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[Z1] L. ZALCMAN, Analytic Capacity and Rational Approximation.
Springer-Verlag,
Berlin, 1968.[Z2] L. ZALCMAN, Offbeat integral geometry. Amer. Math. Monthly 87 (1980), 161-175.
[Z3] L. ZALCMAN, A bibliographic survey of the Pompeiu problem. In:
"Approximation
by Solutions of Partial Differential Equations" (B. Fuglede et al, eds.), Kluwer Acad. Publ., Dordrecht, 1992, pp. 185-194.Department of Mathematics & Computer Science
The Gelbart Research Institute for Mathematical Sciences Bar-Ilan University
Ramat-Gan, Israel