• Aucun résultat trouvé

Suppose that for each x ∈ ∂U there exists a barrier h ∈ C(K) atx such that Φ(h

N/A
N/A
Protected

Academic year: 2022

Partager "Suppose that for each x ∈ ∂U there exists a barrier h ∈ C(K) atx such that Φ(h"

Copied!
7
0
0

Texte intégral

(1)

OF MARKOV SEMIGROUPS

BEBE PRUNARU

Let U K be an open and dense subset of a compact metric space such that

∂U 6=∅. Let Φ be a Markov operator with the strong Feller property acting on the space of bounded Borel measurable functions onU. Suppose that for each x ∂U there exists a barrier h C(K) atx such that Φ(h) h. Suppose moreover that every real-valuedgC(K) with Φ(g)gand which attains its global maximum at a point insideU is constant. Then for eachfC(K) there exists the uniform limitF= lim

n→∞Φn(f). MoreoverF C(K) agrees withfon

∂U and Φ(F) =F.

AMS 2010 Subject Classification: Primary: 47D07, Secondary: 60J05, 60J25, 37A30, 47A35.

Key words: Markov semigroup, boundary value problem, asymptotic stability.

1. INTRODUCTION

Let E be a locally compact Hausdorff space and let Mb(E) be the space of all complex-valued, bounded and Borel measurable functions onE. Let also Cb(E) be the set of all continuous functions in Mb(E). A linear map

Φ :Mb(E)→Mb(E)

is called a Markov operator if for each x ∈E there exists a probability Borel measure µx on E such that

Φ(f)(x) = Z

fdµx ∀f ∈Mb(E).

A Markov operator Φ is positive, in the sense that Φ(f) ≥ 0 for every f ∈ Mb(E) withf ≥0 onE. A Markov operator Φ is said to have the strong Feller property if Φ(f)∈Cb(E) for everyf ∈Mb(E).

In [1] J. Arazy and M. Engli˘s studied the iterates of Markov operators acting onMb(U) whereU is a bounded domain inCd. One of their main results is the following (see Theorem 1.4 in [1]):

Theorem 1.1. Let U ⊂Cd be a bounded domain and let H(U) be the algebra of all bounded analytic function on U. Let ∂p(U) ⊂∂U be the set of all peak points for H(U)∩C(U). Let

MATH. REPORTS15(65), 4 (2013), 489–495

(2)

Φ :Mb(U)→Mb(U)

be a Markov operator with the strong Feller property such that Φ(h) = h for every h∈H(U),

Then for every continuous function F on the closure U¯ the sequence {Φn(F)} converges uniformly on every subset of U whose closure is contained in U ∪∂p(U) to a function G∈Cb(U). Moreover, Φ(G) =G and

y→xlimG(y) =F(x) for every x∈∂p(U).

The authors provide a large class of such operators, including Berezin transforms on strictly pseudoconvex domains and convolution operators on bounded symmetric domains.

In this paper we prove a result concerning the iterates of a class of Markov operators with the strong Feller property associated with dense open subsets of compact metric spaces. Under suitable boundary conditions and assuming a maximum principle for the interior points, we obtain a uniform convergence similar to that of Theorem 1.1. Theorem 2.1 below can be used to give an alternate proof for the main result in [5]. Indeed, it may be easily seen that the Berezin-type transform defined there satisfies all the conditions appearing in Theorem 2.1. The methods used in [1] strongly motivated and inspired this research.

2. THE MAIN RESULT

The main result of this paper is the following:

Theorem2.1. LetKbe a compact metric space and letU ⊂Kbe a dense open subset such that∂U 6=∅. LetC(K)be the space of all continuous complex- valued functions on K and let C(∂U) be the corresponding space for ∂U.

Let Φ : Mb(U) → Mb(U) be a Markov operator with the strong Feller property. Suppose that Φsatisfies the following conditions:

(A) For each pointx∈∂U there existsh∈C(K)such thath(x) = 0,h(y)<0 for all y∈K\{x} and Φ(hU)≥hU onU, where hU is the restriction of h to U;

(B) If g∈C(K) is a real valued function withΦ(gU)≥gU and if there exists z∈U such that g(z) = max{g(x) :x∈K} then g is constant on K.

Then, for each f ∈C(∂U) there exists a unique functionG∈C(K) such that Φ(GU) = GU and G(x) =f(x) for all x ∈ ∂U. Moreover, if F ∈C(K) is an arbitrary continuous extension of f to K then the sequence {Φn(FU)}n converges uniformly on U to GU.

(3)

Proof. Let us assume that∂U contains at least two points.

(1) First of all, it can be proved, exactly as in Proposition 1.3 from [1], that the boundary condition (A) implies the following. For each f ∈ C(K) and for each x∈∂U

y→xlimsup

n≥1

|(Φn(fU))(y)−f(x)|= 0.

The idea is to use a barrier at xin order to show that, for any neighbor- hood W of x,

y→xlimΦnW)(y) = 1

uniformly for alln≥1, whereχW is the characteristic function ofW. We refer to [1] for details.

In particular, this shows that for each f ∈ C(K) the function Φ(fU) extends continuously up to ∂U and this extension agrees with f on ∂U. By abuse of notation, we shall continue to denote this extension by Φ(f).

(2) We show that iff ∈C(K) is a real-valued function such that Φ(f)≥f then the sequence{Φn(f)}converges uniformly on K.Indeed, this sequence is monotone increasing and if g is its pointwise limit then g is Borel measurable and Φ(gU) = gU. Since Φ has the strong Feller property, it follows that g is continuous on U. Moreover (1) implies that

y→xlimg(y) =f(x)

for every x ∈ ∂U. Since g agrees with f on ∂U and f ∈ C(K) we see that g∈C(K) and Dini’s theorem shows that the convergence is uniform onK.

(3) Let

T(Φ) ={h∈C(K) : Φ(h) =h}

and letC(T(Φ)) be the norm closed subalgebra ofC(K) generated by T(Φ).

Since T(Φ) is a selfadjoint subspace of C(K) it follows that C(T(Φ)) is a commutative C-algebra.

Let C(Φ) be the set of all f ∈C(K) for which the sequence {Φn(f)} is uniformly convergent on K and denote π(f) its limit. It is clear that π(f) ∈ T(Φ) for everyf ∈C(Φ). Let also

C(Φ)0={f ∈C(Φ) :π(f) = 0}.

We will show that C(T(Φ)) ⊂ C(Φ). It suffices to prove that for any finite set ofk functions fromT(Φ) their product belongs toC(Φ).

Let k= 2. Let h ∈ T(Φ). Since Φ(|f|2) ≥ |Φ(f)|2 for every f ∈C(K) we see that Φ(|h|2) ≥ |h|2. In this case (2) shows that |h|2 ∈C(Φ) therefore g = π(|h|2)− |h|2 ∈ C(Φ)0. Since g ≥ 0 we see that gf ∈ C(Φ)0 for every

(4)

f ∈ C(K). Indeed, it is easy to see that if F ∈ C(Φ)0 is non-negative on K thenF f ∈C(Φ)0 for everyf ∈C(K).

If h1, h2 ∈ T(Φ) then

h1h2 = (1/4)

3

X

m=0

im|gm|2 where i=√

−1 andgm = (h1+im2). Since gm ∈ T(Φ) we see that h1h2 ∈ C(Φ).

Letk≥3 and assume that every product of at mostk−1 elements from T(Φ) belongs to C(Φ). Leth1, . . . , hk inT(Φ) and let g=h1· · · · ·hk. Then

g= (h1h2−π(h1h2))·h3· · · · ·hk+π(h1h2)·h3· · · · ·hk.

By what we have already proved the first summand belongs to C(Φ)0 and the second belongs, by the induction hypothesis, to C(Φ). This shows that C(T(Φ))⊂C(Φ).

(4) Consider the map

ρ:C(T(Φ))→C(∂U)

that takes any f ∈C(T(Φ)) into its restriction to ∂U. It turns out that ρ is onto. To see this, we first observe that the boundary condition (A) together with (2) implies that for eachx∈∂U there existsg∈ T(Φ) such thatg(x) = 0 and g(y)<0 for every y∈∂U\{x}. This shows that the range ofρ separates the points of ∂U and the Stone-Weierstrass theorem shows that this image is norm-dense inC(∂U). On the other hand, it is well-known (see Theorem I.5.7 in [6]) that the image of a *-homomorphism between twoC-algebras is norm- closed. The conclusion is that ρ is onto. Since C(T(Φ)) ⊂C(Φ), and since for each f ∈C(Φ) the function π(f) ∈ T(Φ) and agrees withf on ∂U we see that for each f ∈ C(∂U) there exists a unique function θ(f) ∈ T(Φ) which agrees with f on ∂U. Uniqueness follows easily from (B). The map f 7→ θ(f) is obviously linear and unit preserving.

(5) Let L={g ∈C(K) :g=π(|h|2)− |h|2 for someh∈ T(Φ)}.We will show that L6={0}.Assume, on the contrary, thatL={0} which means that π(|h|2) =|h|2 for every h ∈ T(Φ). In this case, ifh1 and h2 are functions in T(Φ) then π(h1h2)−h1h2 can be written as a linear combination of elements fromL(see step (3)). It then follows thatπ(h1h2) =h1h2.It follows thatT(Φ) is closed under multiplication hence it equals C(T(Φ)). This shows that the map θ:C(∂U) → C(K) defined in (4) is multiplicative on C(∂U). It follows that there exists a continuous map γ:K→∂U such that

θ(f) =f◦γ ∀f ∈C(∂U).

(5)

Letz∈U and letx=γ(z). Leth∈C(∂U) be a nonconstant real-valued function such that

h(x) =sup{h(y);y∈∂U}.

Then

h(x) = (h◦γ)(z) = (θ(h))(z).

However, since θ(h) ∈ T(Φ) and is nonconstant, it attains its global maximum only on∂U. We get a contradiction. The conclusion is thatL6={0}.

(6) Leth∈ T(Φ) such that the functiong=π(|h|2)−|h|2is not identically zero on U. As pointed out in (3), g ≥0 on K and g ∈C(Φ)0. Moreover, one can see that Φ(g) ≤ g. We will show that g > 0 on U. Suppose, on the contrary, that there existsz∈U such thatg(z) = 0. Since Φ(g)≤g and since g ≥ 0 It follows from (B) that g = 0 on K. This contradiction shows that g >0 on U. Sinceg= 0 on∂U this shows that the closed idealI(g) ofC(K) generated byg equals

Z(∂U) ={f ∈C(K) :f = 0 on ∂U}.

Since, as we pointed out in (3),I(g)⊂C(Φ)0 this shows thatf−θ(f∂U)∈ C(Φ)0 for every f ∈ C(K), where f∂U is the restriction of f to ∂U. This means that the sequence {Φn(f)} converges uniformly on K to θ(f∂U) for every f ∈ C(K). This completes the proof for the case when ∂U contains at least two points.

(7) Suppose now that ∂U reduces to a singleton{x0}. The first two steps hold true in this case as well. Moreover, the boundary condition (A) shows that there existsg∈C(K) such thatg(x0) = 0,g(y)<0 onUand Φ(g)≥g. It then follows from (2) that g∈ C(Φ) and, since g = 0 on ∂U, we see that π(g) = 0 hence g ∈C(Φ)0. It then follows, exactly as in (6), that I(g) = Z(∂U). This shows that f−f(x0)∈C(Φ)0 for every f ∈C(K) therefore

n→∞lim Φn(f) =f(x0)

uniformly on K, for all f ∈ C(K). This completes the proof of this theo-

rem.

Condition (B) (the maximum principle) holds true, for instance, in the case when every pointy∈U is accessible for Φ. This means that for eachx∈U and each open neighborhoodωofythere existsk≥1 such that Φkω)(x)>0, whereχω= 1 on ω and 0 elsewhere.

3. CONNECTIONS WITH THE CLASSICAL DIRICHLET PROBLEM

Let Ω⊂Rd be a bounded domain (open connected set). Letδ: Ω→R+

be a strictly positive, continuous function on Ω such that δ(x) ≤ dist(x, ∂Ω)

(6)

for all x ∈ Ω. For each x ∈ Ω let B(x) denote the open ball of radius δ(x) centered atx. Letλbe the Lebesgue measure onRd.

For each x∈Ω define a probability measure µx on Ω as follows:

µx(ω) = (λ(B(x)))−1λ(ω∩B(x))

for every Borel subset ω ⊂ Ω. It is easy to see that the map x 7→ µx(ω) is continuous on Ω for any fixed Borel subsetω ⊂Ω. It then follows that for any f ∈Mb(Ω) the function

Φ(f)(x) = Z

f(y)dµx(y) x∈Ω

is continuous on Ω therefore we obtain in this way a Markov operator Φ :Mb(Ω)→Mb(Ω)

with the strong Feller property. This operator can be expressed as follows:

Φ(f)(x) = (λ(B(x)))−1 Z

B(x)

f(y)dλ(y) x∈Ω

for all f ∈Mb(Ω). Due to the connectedness of Ω, Φ satisfies the maximum principle from Theorem 2.1. Such operators are usually called averaging oper- ators.

If h is a real valued bounded, subharmonic function on Ω then Φ(h)≥h on Ω. In particular, every bounded harmonic function on Ω is a fixed point for Φ. The converse is also true but much more difficult to prove (see [4] and [2]).

Assume now that every point x∈∂Ω is regular for the classical Dirichlet problem on Ω (see [3] for basics of potential theory). In this case, the Markov operator Φ defined above satisfies all the assumptions of Theorem 2.1. It then follows that for each function F ∈ C(Ω) the sequence {Φn(F)}n converges uniformly on Ω and its limitGis the solution of the classical Dirichlet problem with boundary value f = F|∂Ω. The harmonicity of G follows directly from the maximum principle, therefore there is no need to make appeal to the deep results mentioned above.

It might be interesting to find other examples of elliptic operators to which Theorem 2.1 could be applied in a similar manner. The results of this paper may be linked to the field of discrete potential theory and one of the best references here remains the classical monograph of J.L. Doob. [3].

Acknowledgments. This work was supported by a grant of the Romanian National Authority for Scientific Research, CNCS-UEFISCDI, project number PN-II-ID-PCE- 2011-3-0119.

(7)

REFERENCES

[1] J. Arazy and M. Engli˘s, Iterates and the boundary behavior of the Berezin transform.

Ann. Inst. Fourier (Grenoble)51(2001) 1101–1133.

[2] A. Cornea and J. Vesely, Martin compactification for discrete potential theory and the mean value property. Potential Analysis4(1995), 547–569.

[3] J.L. Doob, Classical potential theory and its probabilistic counterpart. Grundlehren der Mathematischen Wissenschaften [Fundamental Principles of Mathematical Sciences], 262, Springer-Verlag, New York, 1984.

[4] W. Hansen and N. Nadirashvili, A converse to the mean value theorem for harmonic functions. Acta Math. 171(1993), 139–163.

[5] C. Liu,Iterates of a Berezin-type transform. J. Math. Anal. Appl. 329(2007) 822–829.

[6] G.K. Pedersen, C-Algebras and Their Automorphism Groups. Academic Press, New York (1979).

Received 11 February 2013 “Simion Stoilow” Institute of Mathematics of the Romanian Academy, P.O. Box 1-764, RO-014700 Bucharest,

Romania Bebe.Prunaru@imar.ro

Références

Documents relatifs

More exactly, we show that inclusion (1.1) is h-locally controlable around the mild solution z(.) if a certain linearized inclusion is λ-locally controlable around the null solution

2 This naive algorithm can be improved and it is possible to obtain a word complexity in O(n) (A. Weilert 2000) using a divide and conquer approach... Show how the LLL algorithm gives

functions reuches the extreme bound of 9 possible simplification.. function belongs to

We prove that the strong detonation travelling waves for a viscous combustion model are nonlinearly stable, that is, for a given perturbation of a travelling wave, the

In [40], Petrunin developed an argument based on the second variation formula of arc-length and Hamitlon–Jacobi shift, and sketched a proof to the Lipschitz continuity of

Then U is factorial by Theorem 1, be- cause it is factorial if the points of Sing(R) impose independent linear conditions on homogeneous forms of degree 3r + d − 5 (see [8])...

Delano¨e [4] proved that the second boundary value problem for the Monge-Amp`ere equation has a unique smooth solution, provided that both domains are uniformly convex.. This result

Motivated b y the reasoning leading to Theorem 5 and for later convenience we adopt the following terminology.. Suppose that sEC ~ is