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Eigenvalues for a Schrodinger operator on a closed Riemannian manifold with holes
Olivier Lablée
To cite this version:
Olivier Lablée. Eigenvalues for a Schrodinger operator on a closed Riemannian manifold with holes.
2013. �hal-00782066�
Eigenvalues for a Schrödinger operator on a closed Riemannian manifold with holes
Olivier Lablée January 28, 2013
Abstract
In this article we consider a closed Riemannian manifold(M,g)andA a subset ofM. The purpose of this article is the comparison between the eigenvalues(λk(M))k≥1of a Schrödinger operatorP := −∆g+Von the manifold(M,g)and the eigenvalues(λk(M−A))k≥1ofPon the manifold (M−A,g)with Dirichlet boundary conditions.
1 Introduction
The behaviour of the spectrum of a Riemannian manifold(M,g)under topo- logical perturbation has been the subject of many research. The most famous exemple is the crushed ice problem[Kac], see also[Ann]. This problem consists to understand the behaviour of Laplacian eigenvalues with Dirichlet boundary on a domain with small holes. This subject was first studied by M. Kac[Kac]in 1974. Then, J. Rauch and M. Taylor[RT]studied the case of Euclidian Laplacian in a compact setMofRn: they showed that the spectrum of∆Rnis invariant by a topological excision of aMby a compact subsetAwith a Newtonian capac- ity zero. Later, S. Osawa, I. Chavel and E. Feldman[Ca-Fe1],[Ca-Fe2]treated the Riemmannian manifold case. They used complex probalistic techniques based on Brownian motion. In 1995, in a nice article[Cou]G . Courtois stud- ied the case of Laplace Beltrami operator on closed Riemannian manifold. He used very simple techniques of analysis. In[Be-Co]J. Bertrand and B. Colbois explained also the case of Laplace Beltrami operator on compact Riemannian manifold. In this article we focus on the the Schrödinger operator−∆g+V case on a closed Riemannian manifold.
Assumption. The manifold is closed (ie compact without boundary); the function V is bounded on M andminMV>0.
In this work we show that under “little” topological excision of a part A from the manifold, the spectrum of−∆g+VonM−Ais close of the spectrum onM. More precisely, the “good” parameter for measuring the littleness ofA is a type of electrostatic capacity defined by :
cap(A):=inf
Q(u),u∈H1(M),Z
Mu dVg=0,u−e1∈H01(M−A)
wheree1denotes the first eigenfunction of the operator−∆g+Von the mani- foldM, andQis the following quadradic form :
Q(ϕ):= Z
M|dϕ|2 dVg+ Z
MV|ϕ|2dVg
andH01(M−A)is the Sobolev space defined by :
H01(M−A):={g∈ H1(M), g=0 on a open neighborhood ofA} the closure is for the normk.kH1(M),H1(M)is the usual Sobolev space onM.
Indeed, more cap(A) is small, more the spectrum−∆g+V on M−Ais close of the spectrum onMin the following sense :
Theorem. Let(M,g)a closed Riemannian manifold. For all integer k ≥ 1, there exists a constant Ck depending on the manifold(M,g)and on the potential V such that for all subset A of M we have :
0≤λk(M−A)−λk(M)≤Ck
q cap(A).
The organization of this paper is the following : in the part 2 we start by recall some classicals results in spectral theory, we define our Sobolev space H01(M−A)and the notion of Schrödinger capacity. In particular, we explain the link between the functionnal Hilbert space H01(M−A)and Schrödinger capacity cap(A). The last part of this paper is a detailed proof of the main theorem.
2 Spectral problem background
2.1 Schrödinger operator on a Riemannian manifold
We recall here some generality on spectral geometry, for a more detailed survey see for example[Lab]. In Riemannian geometry, the Laplace Beltrami operator is the generalisation of Laplacian∆=
n
∑
j=1
∂2
∂x2j onRn. For aC2real valued func- tion f on a Riemannian manifold and for a local chartφ : U⊂ M→Rof the manifoldM, the Laplace Beltrami operator is given by the local expression :
∆gf = √1g
n
∑
j,k=1
∂
∂xj
√ggjk∂(f◦φ−1)
∂xk
whereg=det(gij)andgjk= (gjk)−1.
The spectrum of this operator is a nice geometric invariant, see Berger, Gauduchon and Mazet[BGM]and[Be-Be]. The spectrum of Laplace Beltrami operator has many applications in geometry topology, physics ,etc ...
For every Riemannian manifold(M,g)with dimensionn≥1 we have the
“natural” Hilbert space L2(M) = L2(M,dVg),Vg is the Riemannian volume form associated to the metricg. ForVa function fromMtoR, we define the Schrödinger operator on the manifold(M,g)by the linear unbounded opera- tor on the set of smooth compact supports real valued functionsCc∞(M,R)⊂ L2(M)by :−∆g+V.
2.2 Spectral problem
The spectral problem is the following : find all pairs(λ,u) withλ ∈ Rand u∈L2(M)such that :
−∆gu+Vu=λu
(withu∈L2(M)in the non-compact case).
In the case of manifold with boundary, we need boundary conditions on the functionsu, for example the Dirichlet conditions : u= 0 on the boundary ofM, or Neumann conditions : ∂u∂n = 0 on the boundary of M. In the case of closed manifolds (compact without boundary) we don’t have conditions.
For our context (the closed case) the natural space to look here is the Sobolev spaceH1(M,g)define by
H1(M,g):=C∞(M) where the closure is for the normk.kH1 :kukH1 :=
q
kuk2L2+kduk2H1. An other point of view to define the spaceH1(M,g)is the following :
H1(M,g):=nu∈ L2(M);du∈ L2(M)o where the derivation is the sense of distribution.
The spaceH1(M,g)is a Hilbert space for the inner product : hu,viH1 :=hu,viL2+hdu,dviL2.
Recall here a classical theorem of spectral theory (see for example[Re-Si]) : Theorem. For the above problems, the operator−∆g+V is self-adjoint, the spectrum of the operator−∆g+V consists of a sequence of increasing eigenvalues with finite multiplicity :
λ1(M)≤λ2(M)≤ · · · ≤λk(M)≤ · · · →+∞.
Moreover, the associate eigenfunctions (ek)k≥0 is a orthonormal basis of the space L2(M).
Definition. We define the quadradic formQwith domainD(Q):= H1(M)by :
Q(ϕ):= Z
M|dϕ|2 dVg+ Z
MV|ϕ|2dVg.
Recall also (see for example[Co-Hi]) the minimax variational characteriza- tion for eigenvalues : for allk≥1
λk(M) = min
E⊂H1(M)
dim(E)=k
maxϕ∈E
ϕ6=0
R(ϕ)
whereR(ϕ)is the Rayleigh quotient of the functionϕ:
R(ϕ):= Q(ϕ) R
Mϕ2dVg.
In our context, a consequence of the minimax principle is :
Proposition 2.1. The first eigenvalue λ1(M)and e1 the first eigenfunction of the operator−∆g+V on the manifold(M,g) satisfyλ1(M)≥minMV >0and e1>
0or e1<0in M.
Proof. It’s clear that Z
M|de1|2 dVg+ Z
MV|e1|2 dVg≥min
M Vke1k2L2(M)
and on the other hand Z
M|de1|2dVg+ Z
MV|e1|2 dVg=− Z
M
∆ge1e1dVg+ Z
MV|e1|2 dVg
= Z
M −∆g+V
e1e1dVg=λ1(M)ke1k2L2(M)
soλ1(M)≥minMV. Next, suppose the functione1changes sign intoM, since e1∈ H1(M), the function f :=|e1|belongs to H1(M)and|d f|=|de1|(see for example[GT]), henceR(f) =R(e1). So, the function f is a first eigenfunction of−∆g+Von the manifoldMwhich satisfiesf ≥0 onM,f vanish intoMand
−∆g+V
f =λ1(M)f ≥0 onM. Using the maximum principle[Pr-We], the function fcan not achieved it minimum in an interior point of the manifoldM, hence f does not vanish onM, so we obtain a contradiction.
3 Proof of the main theorem
3.1 Somes usefull spaces
We define on the spaceH1(M)the⋆-norm by : kuk2⋆:=
Z
M|du|2dVg+ Z
MV|u|2 dVg
so, without difficulty we have :
Proposition. The application k.k⋆ is a norm on the space H1(M); moreover this norm is equivalent to the Sobolev norm k.kH1(M). In particular H1(M),k.k⋆ is a Banach space.
Now, for a compact subset Aof the manifold M the usual Sobolev space H01(M−A)is defined by the closure of test functions space on M−Afor the normk.kH1(M):
H01(M−A):=D(M−A).
What happens when the set Ais not compact ? For example if Ais a dense and countable subset of points of the manifold M, the space of test functions D(M−A)is reduced to{0}. Therefore we cannot define the spaceH01(M−A). In this case, we propose a definition ofH10(M−A)for any subsetAofM.
Definition. We define the Sobolev spacesH10(M−A)andH10(M−A)by : H10(M−A):=ng∈ H1(M),g=0 on a open neighborhood ofAo
; H01(M−A):=H10(M−A)
where the closure is for the normk.kH1(M). We have the :
Proposition. If the set A is compact, the previous definition of the space H10(M−A) coincides with the usal ones.
Proof. Let f ∈ H01(M−A), then by definition : for allε ≥ 0 there exists g ∈ H10(M−A)such that kf−gkH1(M) ≤ ε. So, we will show that we can write g as a limit of sequence from the space D(M−A) and conclude. Since g ∈ H10(M−A)there exists an open setU ⊃ Asuch thatg|U = 0. Consider two open setsU1andU2of the manifoldMsuch that :
A⊂U1, M−U⊂U2,U1∩U2=∅; and consider also a functionϕ∈ D(M)such that :
ϕ|U1 =0, ϕ|U2 =1.
Of course, the function ϕ belongs to the space D(M−A). Next, since g ∈ H10(M−A) ⊂ H1(M)and as the set of smooth functionsC∞(M)is dense in H1(M): there exists a sequence(gn)ninC∞(M)such that lim
n→+∞gn=gfor the normk.kH1(M). Therefore we claim that : lim
n→+∞ϕgn =gfor the normk.kH1(M). Indeed, start by, for all integern:
kϕgn−gk2H1(M)≤ kgn−gk2H1(M−U)+kϕgn−gk2H1(U)
≤ kgn−gk2H1(M)+kϕgn−gk2H1(U). Next, we observe that, for all integern:
kϕgn−gk2H1(U)=kϕgnk2H1(U)
= Z
U|ϕgn|2 dVg+ Z
U|dϕgn+ϕdgn|2dVg
≤ Z
U|ϕgn|2 dVg+ Z
U|dϕgn|2 dVg+ Z
U|ϕdgn|2dVg+2Z
U|dϕgnϕdgn|dVg
≤ kϕk2∞kgnk2L2(U)+kdϕk2L∞(M)kgnk2L2(U)
+kϕk2∞kdgnk2L2(U)+2kdϕk∞kϕk∞ Z
U|gndgn| dVg
≤ kϕk2∞kgnk2L2(U)+kdϕk2∞kgnk2L2(U)
+kϕk2∞kdgnk2L2(U)+2kdϕk∞kϕkL∞(M)kgnkL2(U)kdgnkL2(U),
by Cauchy-Schwarz inequality.
Finally we get for all integern: kϕgn−gk2H1(U)≤ kgnk2H1(U)
2kϕk2∞+kdϕk2∞+2kdϕk∞kϕk∞
. As a consequence, we have for all integern:
kϕgn−gk2H1(M)≤ kgn−gk2H1(M−U)
+kgnk2H1(U)
2kϕk2∞+kdϕk2∞+2kdϕk∞kϕk∞
.
Now, it suffices to note that kgnk2H1(U) = kgn−gk2H1(U) ≤ kgn−gk2H1(M) (sinceg=0 on the open setU) and we have finally :
kϕgn−gk2H1(M)≤ kgn−gk2H1(M)
1+2kϕk2∞+kdϕk2∞+2kdϕk∞kϕk∞
. The sequence (ϕgn)n belong toD(M−A)N,and since lim
n→+∞gn = g for the norm k.kH1(M) the previous inequality implies lim
n→+∞ϕgn = g for the norm k.kH1(M).
So we have shown that every function f ∈ H01(M−A)is a limit (for the normk.kH1(M)) of a sequence ofD(M−A).
Let us also denote the spacesH⋆1(M)andSA(M)by : H⋆1(M):=
f ∈H1(M),Z
Mf dVg=0
; and
SA(M):=nu∈ H⋆1(M),u−e1∈ H01(M−A)o. In the definition of the spaceH⋆1(M)the conditionR
Mf dVg = 0 is analog to a boundary condition. We observe that the spaceH1⋆(M)is a Hilbert space for the norm :
kuk⋆:= Z
M|du|2 dVg+ Z
MV|u|2 dVg; andSA(M)is just an affine closed subset ofH1(M).
3.2 Schrödinger capacity
Next, we introduce the Schrödinger capacity of the setA;
Definition. Let us consider the Schrödinger capacity cap(A)of the set Ade- fined by
cap(A):=inf Z
M|du|2dVg+ Z
MV|u|2dVg,u∈SA(M)
.
Let us remark that : there exists an unique functionuA ∈SA(M)such that cap(A) =
Z
M|duA|2dVg+ Z
MV|uA|2dVg.
Indeed : here the capacity cap(A)is just the distance between the function 0 and the closed spaceSA(M). This distance is equal tokuAk⋆whereuAis the orthogonal projection of 0 onSA(M):
cap(A) =d⋆(0,SA(M)):=inf{kuk⋆,u∈SA(M)}=kuAk⋆.
In the following lemma we give the relationships between the capacity cap(A), the functionsuA,e1and the Sobolev spacesH01(M−A), H1(M).
Lemma. For all subset A of the manifold M, the following properties are equivalent : (i) cap(A) =0;
(ii) uA=0;
(iii) e1∈ H01(M−A); (iv) H01(M−A) =H1(M).
Proof. It is clear from the formula (3.1) that(i)⇔ (ii) ⇔ (iii). Next, suppose the property (iii) holds : so there exists a sequence (vn)n ∈ H10(M−A)N such that lim
n→+∞vn = e1 for the norm k.kH1(M). So, for all smooth function ϕ∈ C∞(M)we have lim
n→+∞(ϕvn)/e1 =ϕfor the normk.kH1(M), indeed for all integern:
ϕvn
e1 −ϕ
2 H1(M)
= Z
M
ϕvn
e1 −ϕ
2
dVg+ Z
M
d
ϕvn
e1
−dϕ
2
dVg. First, we have for all integern:
Z M
ϕvn
e1 −ϕ
2
dVg= Z
M
1
|e1|2|ϕ(vn−e1)|2 dVg
≤ 1 e1
2
∞kϕk2∞kvn−e1k2L2(M) so, since lim
n→+∞vn=e1for the normk.kH1(M)we have
n→lim+∞ Z
M
ϕvn
e1 −ϕ
2
dVg=0.
On the other hand, for all integern: Z
M
d
ϕvn
e1
−dϕ
2
dVg= Z
M
d(ϕvn)e1−ϕvnde1
e21 −dϕ
2
dVg
= Z
M
1 e21
!
d(ϕ)vne1+ϕd(vn)e1−ϕvnd(e1)−d(ϕ)e21
2 dVg
≤ 1 e1
2
∞
dϕvne1−dϕe21+ϕdvne1−ϕvnde1
2 L2(M)
≤ 1 e1
2
∞
dϕvne1−dϕe21L2(M)+kϕdvne1−ϕvnde1kL2(M) 2
≤ 1 e1
2
∞
hkdϕk∞ke1k∞kvn−e1kL2(M)+
kϕk∞ke1(dvn−de1) +e1de1−vnde1kL2(M)i2
≤ 1 e1
2
∞
hkdϕk∞ke1k∞kvn−e1kL2(M)+
kϕk∞ke1k∞kdvn−de1kL2(M)+kϕk∞kde1k∞ke1−vnkL2(M)i2; so, since lim
n→+∞vn =e1for the normk.kH1(M)we have
n→lim+∞ Z
M
d
ϕvn
e1
−dϕ
2
dVg=0.
Therefore, for all function ϕ ∈ C∞(M)we have lim
n→+∞ ϕvn
e1 = ϕfor the norm k.kH1(M).
Next, by density ofC∞(M)in H1(M): for all function f ∈ H1(M)we have
n→lim+∞
f vn
e1 = f . Since the sequencef v
n
e1
n∈ H10(M−A)Nwe get finally that f belongs to spaceH10(M−A). Finally, it is easy to see that(iv)⇒(iii).
An obvious consequence of this lemma is the following result :
Proposition. The spectrum of−∆g+V on the manifold(M,g)and on the manifold (M−A,g)are equal if and only if cap(A) =0.
3.3 The Poincaré inequality
Now, let introduce the Poincaré inequality :
Theorem. If λ1(M) denotes the first eigenvalue of the operator −∆g+V on the manifold(M,g), the following inequality
kuAk2L2(M)≤ cap(A) λ1(M) holds for all subset A of M.
Proof. The case cap(A) =0 is an obvious consequence of the lemma in section 3.2. Suppose here that cap(A) >0, thenkuAkL2(M)> 0. The first eigenvalue λ1(M)of the operator−∆g+Von the manifold(M,g)is given by :
λ1(M) = min
E⊂H1(M)
dim(E)=1
maxϕ∈E
ϕ6=0
R
M|dϕ|2+V|ϕ|2dVg
R
M|ϕ|2dVg
= min
ϕ∈H1(M)
ϕ6=0
R
M|dϕ|2+V|ϕ|2 dVg R
M|ϕ|2 dVg
SinceuAbelongs to the spaceH1(M)we getλ1(M)≤ kucap(A)
Ak2L2(M)
.
3.4 The main theorem
Recall our main result :
Theorem. Let(M,g)a compact Riemannian manifold. For all integer k ≥1, there exists a constant Ckdepending on the manifold of(M,g)and the potential V such that for all subset A of M we have :
0≤λk(M−A)−λk(M)≤Ck
q cap(A).
Remark. We can easily adapt the proof for a compact Riemannian manifold with boundary.
Proof. Let us denote by(ek)k≥1an orthonormal basis of the spaceL2(M)with eigenfunctions of the operator−∆g+Von the manifold(M,g). For all integer k≥1, we consider the sets
Fk:=span{e1,e2, . . . ,ek} and
Ek :=
f
1−ueA
1
, f ∈ Fk
.
First, observe thatEk ⊂ H10(M−A). For allj ∈ {1, . . . ,k}we introduce also the functionsφj :=ej
1−ueA1 ∈Ek.
•Step 1: we compute the L2-inner product φi,φj
L2(M)for all pairs(i,j) ∈ {1, . . . ,k}2:
φi,φj
L2(M)= Z
Meiej
1−ueA
1
2 dVg
=δi,j−2 Z
M
eiej
e1 uAdVg+ Z
Meiej
u2A e21 dVg. Thus, for all pair(i,j)∈ {1, . . . ,k}2we get :
φi,φj
L2(M)−δi,j
≤2
Z M
eiej e1 uA
dVg+
Z M
eieju2A e21
dVg, hence, by Cauchy-Schwarz inequality we obtain
φi,φj
L2(M)−δi,j
≤2 max
1≤i,j≤k
eiej e21
∞kuAkL2(M)+ max
1≤i,j≤k
eiej e21
∞kuAk2L2(M)
≤2 max
1≤i,j≤k
eiej
e1 ∞
qvol(M)kuAkL2(M)+ max
1≤i,j≤k
eiej
e21
∞kuAk2L2(M)
hence by Poincaré inequality we have
φi,φj
L2(M)−δi,j
≤Bk,M
qcap(A) +cap(A)
whereBk=Bk(e1,e2, ...,ek,λ1(M),M)≥0, and since the eigenfunctionse1,e2, ...,ek and the eigenvalueλ1(M)depends only on(M,g)andV, for all integerkthe constantBkdepends only on(M,g)andV, ie :Bk=Bk(M,V).
Therefore, there existsεk ∈]0, 1[(depends on the constantBk) such that for all A⊂ Mwe have :
cap(A)≤εk⇒dim(Ek) =kand∀j∈ {1, ...,k}, φj
2
L2(M)−1≤Dk
qcap(A) where (and for the same reasons as in the study ofBk) for all integerk, the con- stantDkdepends only onMandV, ieDk=Dk(M,V).
•Step 2: Let a functionφ= f
1−ueA1∈Ek, with f ∈Fk. Without loss gener- ality we can assume thatkfkL2(M)=1, indeed : we haveR(φ) =R
φ kfkL2(M)
and in our context we intererest in the Rayleigh quotient ofφ(see the end of the final step of the proof).
SetvA := ueA1, we have : Z
M|dφ|2dVg= Z
M|d f−d(f vA)|2 dVg
= Z
M|d f|2dVg+ Z
M|d f vA+f dvA|2dVg−2 Z
Md f d(f vA)dVg
= Z
M|d f|2 dVg+ Z
M|d f vA|2 dVg+ Z
M|f dvA|2dVg
+2Z
Md f dvAf vAdVg−2 Z
M|d f|2vAdVg−2 Z
Md f dvAf dVg
= Z
M|d f|2 dVg+ Z
M|d f vA|2 dVg+ Z
M|f dvA|2dVg
−2Z
M|d f|2vAdVg−2Z
Md f dvAf(1−vA) dVg. Recall we havedvA= duAe1−e2uAde1
1 , and : Z
MV|φ|2dVg= Z
MV|f|2 dVg−2 Z
MV|f|2vAdVg+ Z
MV|vAf|2dVg
hence Z
M|dφ|2dVg+ Z
MV|φ|2dVg= Z
M|d f|2 dVg+ Z
MV|f|2dVg
| {z }
:=A(f)
+ Z
M|d f vA|2 dVg
| {z }
:=B(f)
+ Z
M|f dvA|2dVg+ Z
MV|vAf|2 dVg
| {z }
:=C(f)
−2
Z
M|d f|2vAdVg+ Z
MV|f|2vAdVg
| {z }
:=D(f)
−2Z
Md f dvAf(1−vA)dVg
| {z }
:=E(f)
.
Study of A(f) := R
M|d f|2 dVg+R
MV|f|2dVg ≥ 0 : since f ∈ Fk we can write f =
k
∑
i=1
αieiwhere(αi)1≤i≤k∈ Rkand with
k
∑
i=1
α2i = 1 (sincekfkL2(M)= 1), thus we get
A(f) =
* k
∑
j=1
αjdej,
∑
ki=1
αidei +
L2(M)
+
*√ V
k
∑
j=1
αjej,√ V
k
∑
i=1
αiei +
L2(M)
=
∑
i,j
αiαj
dej,dei
L2(M)+ Z
MVejeidVg
=
∑
i,j
αiαj
−ej,∆gei
L2(M)+ Z
MVejeidVg
=
∑
i,j
αiαj
ej, −∆g+V ei
L2(M)
=
∑
i,j
αiαjλi(M)ej,ei
L2(M)=
k
∑
i=1
α2iλi(M)≤λk(M).
Hence, for all integerk, and for all function f ∈ Fksuch thatkfkL2(M)=1 we have
0≤A(f)≤λk(M). Study ofB(f):=R
M|d(f)vA|2 dVg: herevA = ueA1 anddvA = duAe1−e2uAde1
1 ,
so we getB≤ kd fk2∞kvAk2L2(M)and, with the Poincaré inequality : kvAk2L2(M)≤
1 e1
2
∞kuAk2L2(M)≤ 1 e1
2
∞
cap(A) λ1(M)
hence, for all integerk, and for all function f ∈ Fksuch thatkfkL2(M) =1 we have
0≤B(f)≤Ekcap(A)
whereEk = Ek(e1,λ1(M))> 0, moreover since the eigenfunctione1and the eigenvalueλ1(M)depends only on(M,g)andV, for all integerkthe constant Ekdepends only on(M,g)andV, ie :Ek=Ek(M,V).
Study ofC(f): hereC(f)is equal toZ
M|f dvA|2dVg
| {z } +
:=C1(f) Z
MV|vAf|2 dVg
| {z }
:=C2(f)
. Let
us observe firstC1(f):
C1(f)≤ kfk2∞kdvAk2L2(M)
and
kdvAk2L2(M)= Z
M
duAe1−uAde1 e21
2
dVg
≤ 1 e1
2
∞ Z
M|duAe1−uAde1|2 dVg
≤ 1 e1
2
∞
Z
M|duAe1|2 dVg+2Z
M|duAde1e1uA| dVg+ Z
M|de1uA|2 dVg
≤ 1 e1
2
∞
kduAk2L2(M)ke1k2∞+2kde1k∞ke1k∞kduAkL2(M)kuAkL2(M)+kde1k2∞kuAk2L2(M)
. Next we have also :
C2(f) = Z
MV|vAf|2dVg≤ kfk2∞ Z
MV|vA|2dVg
≤ kfk2∞
1 e1
2
∞ Z
MV|uA|2 dVg. Hence we get :
C(f)≤ kfk2∞
1 e1
2
∞
hkduAk2L2(M)ke1k2∞
+2kde1k∞ke1k∞kduAkL2(M)kuAkL2(M)+kde1k2∞kuAk2L2(M)
i
+kfk2∞
1 e1
2
∞ Z
MV|uA|2dVg
≤ kfk2∞
1 e1
2
∞
hkduAk2L2(M)ke1k2∞+2kde1k∞ke1k∞kduAkL2(M)kuAkL2(M)+kde1k2∞kuAk2L2(M)
+ Z
M|duA|2dVg+ Z
MV|uA|2dVg
≤ kfk2∞
1 e1
2
∞
hkduAk2L2(M)+kVk∞kuAk2L2(M)
+2kde1k∞ke1k∞kduAkL2(M)kuAkL2(M)+kde1k2∞kuAk2L2(M)
i; so, sincekduAk2L2(M)≤ cap(A)andkuAk2L2(M)≤ cap(A)λ1(M) we get for all integer k, and for all function f ∈ Fksuch thatkfkL2(M)=1 :
0≤C(f)≤Fkcap(A)
where Fk = Fk(f,e1,λ1(M)) > 0. Here, for k fixed, the constantFk depends also on f, and f depends on the functions f1,f2,· · ·,fk (which are depends only on M andV) and on the scalarsα1,α2,· · ·,αk; since
∑
ki=1
α2i = 1, all the (αi)1≤i≤kare bounded inR, so finally, for all integer kthe constant Fk can be bounded by a constant (we denotes also by Fk = Fk(M,V)) which depends only onMandV.
Study of|D(f)|: we have
|D|= Z
M|d f|2vAdVg+ Z
MV|f|2vAdVg
≤ kd fk2∞
1 e1
∞
Z M
uA
e1 dVg+
V|f|2 e1
∞
Z
M|uA| dVg
≤max kd fk2∞
1 e1 ∞,
V|f|2 e1
∞
!Z
M|uA| dVg
≤max kd fk2∞
1 e1
∞,
V|f|2 e1
∞
!q
Vol(M)kuAkL2(M)
≤max kd fk2∞
1 e1
∞,
V|f|2 e1
∞
!q Vol(M)
scap(A) λ1(M). Hence, for all integerk, and for all function f ∈Fksuch thatkfkL2(M)=1 :
|D(f)| ≤Gk
qcap(A)
where (and for the same reasons as in the study ofF, see the constantFk) for all integerk, the constantGkdepends only onMandV, ieGk=Gk(M,V). Study of|E(f)|: recall thatE(f) =R
Md f dvAf(1−vA) dVg, hence
|E(f)| ≤ Z
M|d f dvA| |f| dVg+ Z
M|d f dvA| |f vA| dVg. For the first termR
M|d f dvA| |f|dVgwe have : Z
M|d f dvA| |f| dVg≤ kfk∞kd fk∞
qVol(M)kdvAkL2(M);
we have see in the study ofC(f)that kdvAk2L2
≤ 1 e1
2
∞
kduAk2L2(M)ke1k2∞+2kde1k∞ke1k∞kduAkL2(M)kuAkL2(M)+kde1k2∞kuAk2L2(M)
so withK:=kfk∞kd fk∞
pVol(M)e11
∞we get Z
M|d f dvA| |f| dVg
≤KqkduAk2L2(M)ke1k2∞+2kde1k∞ke1k∞kduAkL2(M)kuAkL2(M)+kde1k2∞kuAk2L2(M)
≤K vu
utcap(A)ke1k2∞+2kde1k∞ke1k∞
qcap(A)
scap(A)
λ1(M) +kde1k2∞
cap(A) λ1(M)
≤Hk
qcap(A)