C OMPOSITIO M ATHEMATICA
B ERT V AN G EEMEN J AAP T OP
Selfdual and non-selfdual 3-dimensional Galois representations
Compositio Mathematica, tome 97, n
o1-2 (1995), p. 51-70
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Selfdual and non-selfdual 3-dimensional Galois
representations
Dedicated
to FransOort
onthe
occasionof his 60th birthday
BERT VAN
GEEMEN1
and JAAPTOP2
0 1995 Kluwer Academic Publishers. Printed in the Netherlands.
1 Dipartimento
di Matematica, Università di Torino, Via Carlo Alberto 10, 10123 Torino, Italia.e-mail:
geemen@dm.unito.it
2Vakgroep
Wiskunde, Rijksuniversiteit Groningen, P.O. Box 800, 9700 AV Groningen,The Netherlands. e-mail:
top@math.rug.nl
Received 21 December 1994; accepted in final form 12 April 1995
1. Introduction
In
[vG-T],
anexample
of a(compatible system
ofA-adic)
3-dimensionalGo. = Gal(Q/Q)-representation(s)
was constructed. Thisrepresentation
p is non-selfdual.By definition,
this means that thecontragredient p*
is notisomorphic
top(2).
The(2)
here denotes a Tatetwist;
it is needed because the absolute values ofeigenvalues
of the
image
of a Frobenius element at p under p have absolute value p. Hence forp*
one finds absolute values1 /p,
socomparing
p andp*
is of interestonly
afterthe Tate twist
above,
which results in ap(2) yielding
absolute values 1/p
as well.We note here in
passing
that in concrete cases, it isnormally
rather easy toverify
that a
given representation
is non-selfdual.Namely,
one may compare traces of p andp* (-2).
The latter trace is forrepresentations
such as oursjust
thecomplex conjugate
of the former. Hence if some trace of p is notreal,
then therepresentation
is non-selfdual.
Moreover,
if some trace dividedby
itscomplex conjugate
is not aroot
of unity,
thenp is
non-selfdual in thestronger
sense that even whenmultiplied by
a Dirichletcharacter,
it still is notisomorphic
to03C1*(-2).
This is usedexplicitly
in 5.11.
Our interest in such 3-dimensional
Go.-representations
was motivatedby
aquestion
of Clozel. Thequestion
was if one couldexplicitly
construct such aGalois
representation
and a modular form onGL(3)
such that their local L-factorsare the same for all
primes.
In theGL(2)-case,
aprocedure
forassociating
Galoisrepresentations
to cusp forms is well known. ForGL(3)
and non-selfdual Galoisrepresentations however,
such a relation remainscompletely conjectural.
Our paper[vG-T]
may beregarded
as somepartial
affirmative evidence for Clozel’squestion;
an
example
is exhibited where the L-factors coincided at least for all oddprimes
less then 71. The Galois
representation
constructed tumed out to beirreducible,
non-selfdual,
and ramifiedonly
at theprime
2([vG-T,
Sect.3,
Remark2]).
Twomore
examples
of Galois- andautomorphic representations
of this kind for which several L-factors coincide aregiven
in[GKTV].
While there exists an
algorithm
tocompute
the modular forms onGL(3) (see
[AGG]),
there is nostraightforward
way to find three dimensional Galois rep- resentations. Of course one can consider theSym2
of two dimensional Galoisrepresentations,
but suchrepresentations
are selfdual(their image
lies in the group of similitudes of aquadratic form).
Asexplained
in[vG-T],
oneplace
to look fornon-sèlfdual
Galoisrepresentations
is in theH2 (etale cohomology)
of a surfaceS with dim
H2,0
= 2 which has anautomorphism cr
of order4,
defined overQ.
In case the Néron-Severi group NS of S’ has anorthogonal complement
Wof rank 6 which is
GQ-stable
and if u acts with threeeigenvalues
i onW,
thenthe
eigenspaces V~, V’~
of cr on W Q9Qi
arelikely
candidates for a non-selfdual 3-dimensionalGQ-representation.
(The
twoeigenspaces
of Q are now eachisotropic
for the intersection form onH2,
so there is no obvious reasonwhy
the associatedrepresentations
should beselfdual.)
In
[vG-T]
we used a oneparameter family
of such surfaces(constructed by
Ash and
Grayson)
to find theexample
cited above. The two newexamples
alsoarise in this
family.
Thepresent
paper is concemed with a different construction of 3-dimensional Galoisrepresentations.
Asbefore,
these are found in theH2
of .surfaces. The surfaces S under consideration will bedegree
4cyclic
basechanges of elliptic
surfaces C with baseP1. By taking
theorthogonal complement
to alarge algebraic part
inH2 together
with allcohomology coming
from the intermediatedegree
2 basechange,
one obtains(see
2.4below)
arepresentation
space forGQ.
This comes
equipped
with the action of theautomorphism
of order 4defining
the
cyclic
basechange. Taking
aneigenspace
of this actionfinally yields
therepresentation
we wish tostudy.
Our main technical result is a formula for the traces of Frobenius elements on this space in terms of the number of
points
on S and S over a finite field(Theorem 3.5).
This formula allows us to
compute
the characteristicpolynomial
of Frobenius in many cases.Using
it we succeed inproving
that certainexamples
obtainedyield
selfdual
representations,
while others do not. For some of the selfdual cases we canactually
exhibit 2-dimensional Galoisrepresentations
whosesymmetric
squareseems to coincide with the 3-dimensional Galois
representation (see (5.5)
and(5.6)).
We also find many non-selfdual
representations;
someexamples
aregiven
inSection 5.11. Thus
far,
these have not been related to modular forms onGL(3 ) prob- ably
because the conductor of these Galoisrepresentations
seems ratherlarge.
It is a
pleasure
to thank Jean-Pierre Serre forshowing
interest in this work andfor
suggesting
a number of corrections to an earlier version of this paper. We alsothank the referee for
pointing
out the very useful reference to the table of Persson to us. The second author would like to express hisgratitude
toLynne Walling,
JasbirChahal and
Andy Pollington
who made hisstay
in Colorado and Utahduring
thesummer of 1994 an
inspiring
and veryenjoyable
one. Most of the work on this paperby
the second author was done while he visitedBrigham Young University
inProvo. All
computer calculations
wereperformed
on thesystem
of the MathematicsDepartment
of theUniversity
of Colorado in Boulder.2. The construction
2.1. In this
section,
ageneral
method forconstructing representation
spaces for Galois groups isexplained.
This is doneby
firstconsidering cyclic quotients of P1,
then base
changing
surfaces defined over thequotient,
andfinally taking pieces
inthe
cohomology
of the basechanged
surface. We will now describe all thesesteps
of the construction in detail.
2.2. On
P1,
define theautomorphism u by 03C3(z) = (z
+1)/(-z
+1).
One checksthat
a2
isgiven by z ~ -1/z. Moreover,
the function u =(z2 - 1)/z
isa2-
invariant and transforms under a as Q*u =
-4/u.
Hence thequotient P1/~03C3~
isdescribed as
in which j: z ~ u = (z2 - 1)/z and h: u ~ t = (u2 - 4)/u and h o j: z ~ t = (z4 - 6z2
+1)/z(z2 - 1)).
Thequotient
map istotally
ramified over t = ±4i andthis is all the ramification.
To have this ramification over
points
i ± si(with s ~ 0)
use the additionalautomorphism 9r,s: t
H r +st/4.
Thecomposition
now defines the
cyclic degree
4 cover ofP1 that
we will consider. It istotally
ramified above r ± si and unramified elsewhere.
2.3. Let 03B5 ~
Pl t
denote astable,
minimalelliptic
surface with baseP1. By pull back,
two otherelliptic
surfaces are derived from 9 asLet
X,
S denote the(again stable)
minimal models ofXo, So
overPI, Pl
respec-tively. Explicitly,
if Ecorresponds
to a Weierstrassequation
then X and S are obtained from
and
respectively.
The modelgiven by
such an affine Weierstrass minimal model(includ- ing
the fiber overinfinity)
will be denotedby Eaff , Xaff, Saff.
If the
morphisms
onP1 under
consideration map zo ~ u0 ~to,
and if moreover xr,s is unramified overto (which
meansto =f r ::1: si),
then the fibre of S over zo is the same as the fiber of X over uo and the fiber of E overto.
In case there is ramification overto,
we haveby
theassumption
that E is stable that the fibre overto
is oftype Iv
with0
v. Then the fibre of X over uo is oftype I2v
and that of Sover zo is of
type I4v.
Note
finally
thatby construction,
one has anautomorphism 03C3 :
S ~ S which ison the model
given by
the(x,
y,z)-coordinates given by
The order of 03C3
equals
4.2.4. Let Il be any
perfect
field. We will construct ~-adicrepresentations
ofGK = Gal(K/K)
associated to the situation above. To thisend,
werequire
that 03C0 =7r,,,: IP’ 1 ~ P1 and 03B5 ~ Pl are
defined over K. Then the constructed S and X areelliptic
surfaces defined over J( as well.Moreover,
theautomorphism o,
on S isdefined over K. Consider the
cohomology
groupH2(SK, Q~).
By pullback
we mayregard H2(XK, Qi)
as aGK-invariant subspace
ofH2(SK, Q~).
Infact,
because X =S/a2
one knowsH2(XK, Q~)
=H2(SK, Qi)U2=I.
So thissubspace
is a-invariant aswell,
and moreover it is gen- eratedby the ± 1-eigenspaces
of u inH2(SK, Q~).
A secondsubspace
to be con-sidered is
A~(S),
theQ~-subspace
inH2 spanned by
allcomponents
of bad fibers of S -JI»1.
ThisA~(S)
is also both u- andGK-invariant.
Define
The space
W~
comesequipped
with a cr- and aGK -action.
Since theautomorphism
u on S is defined over
K,
the two actions commute. Fix a 4thprimitive
root ofunity
i EQ~. By
what is saidabove,
theonly eigenvalues
of 0, onWi
are +1. Afterextending
scalars fromQ~
toQ~(i),
theGK-representation Wi splits according
tothe
eigenvalues
+1 of 03C3. PutOur
goal
will be tostudy
for the caseK = Q
theGQ-representation
onVe.
In
particular,
we will answer thequestion
how tocompute
traces of Frobenius elements inGo
for such arepresentation.
3. The trace formula
We will use the notations and the construction from Section 2 above. Without loss of
generality
we will assume that theoriginal
surface S -P1
is obtained from an affine Weierstrass minimal model.Any
fiberEt
of this model is either an affine smoothelliptic
curvegiven by
a Weierstrassequation,
or it is an affine cubicequation
with a doublepoint.
ThisEt
hence differs from the fiber of E over t in at most two ways:firstly,
onEt
we haveignored
thepoint
atinfinity. Secondly,
in case the fiber of E ~
IP1
1 over t is an n-gonwith n 2,
then it has morecomponents
thanEt.
Recall the notation£aff, Xaff, Saff
for the union of these affine fibers(including
the fiber overinfinity).
In order tocompute
traces, we will fora moment
require
that the abovesetup
with03B5, X, S, Et
etc. is all defined over afinite field
IFp
with p an oddprime.
Put q =pn
and writeFq
for theqth
power map inGTFq.
If a EF*q,
then write(1)
= 1 in case a is a squarein F*q,
and(a)
= - 1otherwise.
PROPOSITION 3.1. Let S ~
P1
be anelliptic surface
constructedby pull
backfrom £ --+ ]Pl as in
Section 2. For the associatedrepresentation
spaceWl
one hasthe formula
in which ut denotes a root in
Fg of X2 - tX - 4 = 0 and Et
isthe fiber
over tof 03B5 ~ P1.
REMARK 3.2. Note that the above formula makes sense: a ut as
required
existswhenever the factor
( q
+ 1 is non-zero.Moreover,
in that case thesymbol
(u2t+4 q)
isindependent
of the choice of ut.The
explicit
formula for the trace here shows that it isexpressed completely
interms of the number of
points
in the fibres of theoriginal
surface 03B5 ~P1.
In what
follows,
and inparticular
in theproof
ofProposition 3.1,
thefollowing
general lemma
will be useful.LEMMA 3.3.
Suppose
Y -P1
is aminimal,
stableelliptic surface defined
over
1Fq, corresponding
to a minimalaffine
Weierstrass modelYaff,
with stablefibers
over eachpoint
inP1.
Put
AI(Y)
CH2(Yjr , Qi)
to be thesubspace spanned by
afiber,
the zerosection,
and allcomponents of singular fibers
notmeeting
the zero section. LetH2tr(Y)
be theorthogonal complement of A~(Y)
inH2(Yjr , Q~).
Then
Proof. By
the Lefschetz trace formula one knowsThe lemma will follow once we have shown that moreover
This will be done
by describing
the contributions to each of these termscoming
from the various
(components of)
fibers and the zero section.Firstly,
there is a contribution q + q =2q
from the fiber and the zero sectionto
trace(Fq|A~(Y)). Also,
all smooth fibers contribute to each of#Yaff(Fq)
and#Y(Fq)
the same number of affinepoints, plus
onepoint
atinfinity
inY(IFq).
What remains are the
singular
fibers. If Y has such a fiber over apoint t,
thenby assumption
it is an n-gon for n 2. If t is notFq-rational,
then because Y is defined overFq,
the Frobenius mapFq interchanges
the fiber at t withpossibly
several others in a
cyclic
way, and one concludes from this that the total contribution obtained from this to any oftrace(Fq|A~(Y)), #Yaff(Fq)
and#Y(Fq)
is 0.On the other
hand,
suppose we have asingular
fiber over a rationalpoint.
InYaff,
this fiber is
represented by
a cubic curve witha node, given by
an affine Weierstrassequation.
Wedistinguish
the twopossibilities
where thetangent
lines at the nodeare
Fq
-rational(split multiplicative)
ornon-IFq
-rational(non-split).
In case of asplit multiplicative fiber,
allcomponents
of the n-gon we consider in Y are defined overIFq.
Hence this contributes(n - 1)q
totrace(Fq|A~(Y)),
andn(q
+1) - n
= nqrational
points
to#Y(Fq),
and q - 1 to#Yaff(Fq).
In case of a
non-split multiplicative
fiber onefinds q
+ 1points
inYaff(Fq).
To
compute
the contributions to#Y(Fq)
and totrace(Fq|A~(Y)),
we treat thecases n odd and n even
separately.
Thepoints
on thezero-component
where othercomponents
of the n-gon intersectit,
areinterchanged by Fq
in case of anon-split
fiber. From this one concludes that if n is
odd,
then thezero-component
is theonly component
defined overFq.
The intersectionpoint
of the twocomponents
’farthestaway’
from thezero-component
isIFq-rational
aswell,
hence the contribution to#Y(Fq) equals q
+ 2 and that totrace(Fq|A~(Y))
is 0 for odd n. For n even, thecomponent ’opposite’
the zero-one is defined overlFQ
aswell,
and thisyields
acontribution
2(q
+1)
to#Y(Fq) and q
totrace(Fq|A~(Y)).
Combining
all thesepossible
contributions nowgives
the relation between#Y(Fq), #Yaff(Fq)
andtrace(Fq|A~(Y))
stated above. This proves the lemma. 0Proof of Proposition
3.1. The secondequality
is astraightforward application
ofthe definitions
given
in Section 2. We will prove the firstequality using
Lemma 3.3.With notations as in the
lemma,
we haveBy pull back,
we mayregard H2tr(X)
as asubspace
ofH2tr(S)
which isFq-invariant.
Hence what remains to be proven is that
as
Q~[Fq]-modules. Using
thefollowing
commutativediagram
with exact rows andcolumns
this is immediate. o
3.4. Fix from now on i E
Qi with i2
+ 1 = 0.Proposition
3.1 allows us tocompute
traces of Frobenius on the spaceW~. However,
what we areactually
interested
in,
is thesubspace V£
CW~ ~Q~ Qi
defined as thei-eigenspace
of theautomorphism 03C3 acting
onW~.
Recall that theonly eigenvalues
of (7 onW~ are ±i,
hence
Vt
=(I - iU)Wi’ Moreover,
I - iu = 21 onVi.
Now reason as in[vG-T,
Sect.
3.8];
it follows thatthe latter trace is
precisely
the trace ofFq acting
on aquartic
twist~
ofWi.
Define
geometrically
this is the same surface asS,
but theFq-action
is différent. Now~
is
by
definition thesubspace
ofH2(Fq, Q~)
thatcorresponds geometrically
withW~.
Since S = S
geometrically,
we can inprinciple
calculatetrace(Fq03C3|W~) =
trace(Fq|~) using Proposition
3.1. Inpractice,
we need to understandaff(Fq)
and
analogously aff(Fq). By
the definition ofS,
these are thepoints
P inSaff(Fq4)
which
satisfy 03C3-1 (P)
=Fq(P).
Note that under the mapsuch
points
map toFq-rational points
ineaff.
Thus to find thepoints
in5’aff(Fg),
we need to know the
points
in03B5aff(Fq),
and the Galois action on thepoints
abovethem in the
covering Saff
~eaff.
Thiscovering
iscompletely
determinedby
thecovering
on the bases 03C0r,s :P1z
~P1t.
Similarly,
the intermediate surface X =S / (j2
is thequadratic
twist overFq2 /Fq
of
X, using
theautomorphism
of order 2 on X inducedby
u. From thisdescription
one deduces that
Fq -rational points
inXaff(1Fq) correspond precisely
topoints
inXaff (Fq2 )
which are notFq-rational,
but which map topoints
ineaff(1Fq). Again,
thisis
completely given
in terms of fibers ineaff
over rationalpoints, together
with thecovering Pl
~IP’.
Theexplicit
trace formula obtained in this way is as follows:THEOREM 3.5. With notatz’ons as
above,
Proof.
Thefirst equality
follows from the discussion above. To prove thesecond,
we consider the fibers of
£aff
over all rationalpoints
r +st/4
inP1.
Recall that the maps on the bases we consider aregiven by
The fiber over
infinity
ineaff
occurs twice inXaff (over
u =0, oo)
and 4 times inSaff (over z
=iLl,0, oo).
Since these fibers are all over rationalpoints,
this doesnot contribute to the
imaginary part of trace(Fq|V~),
and one obtains(4 - 2)/2
= 1times
#E~(Fq)
as contribution to the realpart. Next,
contributions from fibers overt
with t2
+ 16 = 0 are0,
because these t areprecisely
the ramificationpoints
of themap described
above,
sothey give
the same contribution to any ofSaff, Xaff.
Is t E
Fq
not a ramificationpoint,
then thepoints
ut inP§ mapped
to tsatisfy
(u2t - 4)/ut
= t. Thesepoints
are1FQ-rational precisely when t2
+ 16 EIF; 2.
Inthat case, the fiber of
Xaff
over each of the two ut is identical to thefiber £t
of Eover t.
Moreover,
we obtain this fiber not inSag(Fq )
in case there is no rational zwith
(z2 - 1)/z = ut (which
isequivalent
to(u2t+4 q) = -1).
The otherpossibility
is that
(u¡+4)
=1,
which meansprecisely
that all 4 values of z over theut’s
arerational
(and
over eachof them,
the same fiber£t
isobtained). If,
on the otherhand,
q 1
then we obtain 4copies of Et
inaff(Fq) precisely
in the case thatFq(z) = 03C3-1(z), or equivalently zq
=(z-1)/(z+1), for(any of the)
zsatisfying
z
~ ut ~ t.
Written out, this means that the rootsof X4-tX3-6X2+tX+1
= 0in
IFq
arerequired
tosatisfy Xq+1 + Xq - X + 1
= 0. This proves Theorem 3.5. ~ In Section 5.1below,
thefollowing corollary
will beimportant.
COROLLARY 3.6. With notations as in Theorem
3.5,
supposethat for
each t EIFq
the two
fibers Er±st/4
areisomorphic
overFq.
Then
trace(Fq|V~)
E Z.Proof.
We have to show that theimaginary part
oftrace(Fq|V~)
is 0.By
Theorem 3.5 this
imaginary part
is a sum over t EIFq t2
+ 16 EF*qB F*2q.
We will show that in this sum, the contributions from ft cancel.
By
assump-tion
#Er+st/4(Fq) = #Er-st/4(Fq).
Hence what remains to be proven is thatf(t) == -f( -t)
for t as above.Take any such t. The 4 values of z which are
mapped
to t can be written as{z, 03C3(z), a2( z), 03C33(z)}.
Sincet2 + 16
EF*qBF*2q,
none of these areequal,
hencewe have either zq =
0,(z)
or Zq =03C3-1(z). By definition, ~(t) = -1
in the formercase and
E(t)
= 1 in the latter.Furthermore,
note that if z ismapped
tot,
then - z ismapped
to -t, and03C3(z) = -03C3-1(-z).
This shows that zq =Q(z) precisely
when
(-z)q
=03C3-1(-z).
In otherwords, ~(t) = -~(-t),
as claimed. D4. 3-dimensional
examples
4.1.
Throughout,
the notations introduced in Section 2 will be used. We will now indicate ageneral
construction ofexamples
where the desiredrepresentation Vi
has dimension 3. Two
explicit
families of suchexamples
will begiven.
To this
end,
we will assume that the surface 03B5 ~P1
is of thesimplest possible
kind: a rational
elliptic
surface. For suchsurfaces,
it is known thath2(03B5)
= 10 = therank of the Néron-Severi group; cf.
[S,
Proof of Lemma10.1].
We willinvestigate
under what conditions the
degree
4cyclic
basechange
under 7r,,,:P1
~P1
willyield
a 3-dimensionalV~,
orequivalently,
a 6-dimensionalWi.
PROPOSITION 4.2.
Suppose
therepresentation
spaceVi
in Section 2 is con-structed with as
starting point
astable,
rationalelliptic surface
03B5 ~P1.
Letrank(E)
denote the rankof
the groupof sections of E --+
JID1.
Then one hasdim Vi
= 4 + rank £in case E has smooth
fibres
over theramification points of
thecyclic
map 03C0r,s, anddim Ye = 2 + rank 03B5
in case the
fibres
over theseramification points
are bothsingular of
the sametype.
Proof.
Recall that the basechanged
surface is denotedS,
and the intermediate surface under thedegree
2 basechange
is called X.By
definition ofW~ (cf. 2.4)
one has:
dim Wi
=h2(S) - h2(X) - (dim A~(S) - dim A~(X))
with
Ai
thesubspace
ofH2 spanned by
allcomponents
of bad fibers.Since E is rational and stable and 03C0r,s is
composed
of twomorphisms
ofdegree 2,
one cancompute
the dimensionsh2(X)
andh2(S) using general theory
of(elliptic)
surfaces. Infact,
note thatby [K,
Sect.12]
our surfaces haveci =
0 andC2 =
1 2x( O)
= 12 for E and = 24 for X and = 48 for S. Hencereasoning
as in[vG-T, (3.1)]
it follows thath2(X )
= 22 andh2(S)
= 46. Infact,
the well knownargument
from loc. cit. shows that anyelliptic
surface with baseP1
hashl
=0,
henceh0,2
=~(O) -
1. Thisimplies h0,2(X)
= 1(and
X is a K3surface)
andh0,2(S) =
3. So one concludes that theHodge
structurecorresponding
toVe
hasHodge
numbersh0,2 = h2,0 =
1 andhl dim Ve -
1.The space
A~(03B5)
has dimension1+n = 10-1-rank(03B5),
with n = the numberof
components
of bad fibers which do not meet the zero section. We willdistinguish
two cases now,
depending
on the fibers of E over the ramificationpoints
r f si of.
In case 03B5 ~
P1
has smooth fibers over r ±si,
each of the bad fibersof 03B5 ~ P1
occurs twice in the double cover X and 4 times in the
degree
4 cover S. Thisgives
all the bad fibers of X and
S,
hencedim
A~(X) = 1 + 2n
and dimA~(S)
= 1 + 4n.The conclusion in this case is that
dim We
=46-22-2n= 24 - 16 +
2 rank(£)
= 8 + 2rank(03B5).
The second case to consider is that the fibers of E over r i si are of
type I,
for some v 1. Then dimAQ(E)
= 1 +2(v - 1) + m = 9 - rank(03B5),
where m = thenumber of
components
of bad fibers different from the ones over r + si which do not meet the zero section. In X we obtain instead of the twoI, -fibers
twoI2v -ones,
and
similarly
in S twoI4"-fibers.
It follows thatdim
A~(X)
= 1 +2(2v - 1)
+ 2m and dimAQ(S)
= 1 +2(4v - 1)
+4m,
hence
This proves
Proposition
4.2. 04.3. The conclusion from the
proposition
aboveis,
that to obtainrepresentations Vi
which are
3-dimensional,
one may consider rank 1stable,
rationalelliptic
surfaceshaving
two bad fibers of the sametype,
and then basechange
them via a 7r whichis ramified over the
points corresponding
to these fibers. In order to find rationalstable
elliptic
surfaces of rank1,
the table in[O-S]
is useful. It lists thepossible configurations
of badfibers, although
there is noguarantee
that any surface witha
given configuration really
exists.By restricting
ourselves to the cases where thesurfaces have a non-trivial group of torsion sections as well
(which
makes it easierto write down Weierstrass
equations),
thefollowing
twoexamples
were found.As the referee of this paper
pointed
out to us, we could have saved ourselvessome work here: Persson’s list
[P]
notonly gives
allpossible configurations
of badfibers of rational
elliptic surfaces,
but alsoprovides
realizations of the surfaces.The ones we describe below in
Examples
4.4 and 4.7 are denotedLE2(8 ; 0,0,0)
and
Q (2; 0, 0, 0)
in loc. cit. It may beinteresting
tostudy
the otherexamples
fromPersson’s list of rank 1 rational stable
elliptic
surfaces with twosingular
fibers ofthe same
type
as well.EXAMPLE 4.4. Consider
03B5, corresponding
to the Weierstrassequation
This defines a rational
elliptic surface,
as follows e.g. from[S, (10.14)].
Note thatalthough
threeparameters
appearhere, geometrically
thisfamily depends
ononly
one:
using
affine transformations t = Àt+ J-l
andrescaling
x, y one can, forc ~ 0,
transform the
equation
intoy2
=X(X2
+d(t2 + 1)X + 1).
The fiber overinfinity
of E can be determined
by changing
coordinates to u =1/t, ~
=Y /t3, ç
=x/t2.
This
yields
the newequation
To obtain a
multiplicative
fiber over t = ooi.e.,
over u =0,
one needs to assumeIn that case, the fiber over t = oo is
of type 18.
The other bad fibers occur overpoints
where two zeroes of the cubic
polynomial
in x coincide. Thishappens
whenThe
type
of bad fiberdepends
on themultiplicity
of the roots of thisequation.
Sincewe want to obtain a stable
elliptic
surface of rank1,
we need that all bad fibersover finite t are of
type h .
This means that all 4 roots of the aboveequation
mustbe
simple,
i.e.Under the above
conditions,
we indeed find a surface asrequired.
A section ofinfinite order is
given by
in which a satisfies
03B12 +
2aa + 1 =b2 2c03B1.
If one takes
one obtains a surface which will be denoted
03B5a,r,s
which has theproperty
that two of theI1-fibers
are over r ± si.REMARK 4.5. The above
example
is in factunique
in thefollowing
sense.Any stable,
rationalelliptic
surface with a section of order 2 and with rank 1 hasaccording
to[O-S]
one18
and fourIl
fibers. If the surface isgiven by
a Weierstrassequation,
one may assume without loss ofgenerality
that the section of order 2corresponds
to x =0, y
= 0 and that the18
fiber is located over t = 00. Henceafter
rescaling x, y
theexample
above is obtained.4.6. We will now
give
a moregeometric approach
to the currentexample
whichhowever will not be used in the remainder of the paper. Recall from 4.4 that E may be defined
by:
e
=Cd: t2 = z(z2
+d(y2
+1)z
+1),
where our t is the old
Y,
y is the old t and z is the old X. We now substitute y :=y/Ho
Each £d
can be viewed as a double cover ofIp2 (with
coordinates(x :
y :z))
branched over the
quartic
curve(note
thedegree
of the branch curve must beeven)
defined
by
F:The curve F = 0 thus consists of an
elliptic
curve E(with
affineequation y2
=x(x2
+ dx +1))
and the line atinfinity z
= 0. Thepencil
ofelliptic
curves isgiven by
the inverseimages
of thelines y
= 03BBx. It hasIl
fibers over the 4 linestangent
to E
(and
thus the fiber over the line x = 0 must be an7g fiber),
thepoints
oftangency
are thuspoints
of order 4 on E.The section of the
family £
over the t-line isgiven by putting
x = a for asuitable number a. This
corresponds
to the section(Note
that the lines x =j3
intersect the curve F = 0 in twopoints,
each withmultiplicity 2,
thus the inverseimage
of such a line is reducible.Moreover, x = j3
intersects y = Ax in one
point,
and thus eachcomponent
of the inverseimage
ofx =
j3
is(the image of)
asection.)
Let £
1 =BJF2
be theblow-up
ofp2
in the basepoint (0 :
0 :1)
of thepencil,
it has a
morphism BJF2 --+ P1 whose
fibers are the lines in thepencil.
We have a2:1
map É - BJF2
of fibrations overP1.
The 4:1cyclic
cover S of E branchedalong
two of theh
fibers is a double cover of the ruled surfaceS4,
obtained asthe
pull-back of 03A31 ~ P1 along
thecyclic
4:1 mapP1 ~ P1. (We write £n
forthe Hirzebruch surface
of degree n ([BPV], V.5).) Similarly,
the 2 : 1 intermediatecover X
(a
K3surface)
is a double cover of03A32.
We consider the branch-loci of the ’vertical’ 2:1 maps
(the
surfacesSi actually
have to be
blown-up
in thesingular points
of the branch loci to obtain the minimal models of thecoverings).
The branch locus of É -BP2
is the union of three divisors: the strict transform of theelliptic
curve E(again
denotedby E),
theinverse
image
of1,,.
Cp2
and theexceptional
divisorC1 C BP1.
A fiber ofBP2 ~ pi 1 meets
this branch locus in 4points,
2 are onE,
and the other two are onl~
andC1.
The branch locus of X ~
E2
is the union of the inverseimage E’
of E(E’ has
two nodes and its normalization
É’
is anelliptic
curve,2-isogenous
toE)
and tworational curves
(one lying
overl~
and the other isC2
CE2 lying
overCi C BP2).
The inverse
image
of E’ inE4
is a curve C with arithmetic genus 7 andgeometric
genus 3. Its normalization is a double cover of
É’ branching
over the 4points
ofÉ’
over 2
points
of order 4 on Ein thé
branch locus of03A32 ~ BP2.
The branch locus S -S4
is the union of C -and two rational curves, onelying
4:1 overl~ ~ BP2,
the other is
C4
CE4 lying
overC2
C03A32.
Equations
for the curvesE’
and C may be obtained as follows. We can choose thepair
oftangent
lines to E asbeing
definedby y2
=a2x
withA2
= d +2. Then
(the
function fieldof) E’
is definedby u2
=(y - 03BBx)/(y
+Àx) (so
y =
ax(1
+u2)/(1 - u2))
and C is definedby v4
=(y - ÀX)/(y
-t-Àx) (so
y =
Ax(l
+v4)/(1 - v4)).
EXAMPLE 4.7. Other
examples
of suchelliptic
surfaces are obtained as follows.Consider the minimal smooth surface
corresponding
toThis
only
works of coursewhen a ~
0. In that case, the fiber overinfinity
isgiven
by y2 = x3
+ a. The minimal surface has anI6-fiber
at t =0,
anI3
at t = 1 andthree
Il-fibers
over the zeroes of27t3 - 27t2 -
4a. Note that thispolynomial only
has three different zeroes when we demand
a(a + 1) ~ 0,
which we do from nowon. A section of infinite order is then
provided by
To obtain two of the
Il-fibers
over r fsi,
one may start with a(new) parameter
q and take
(These
formulas are foundby
firstwriting
thequotient r/s
as q, and thendemanding
that the monic
polynomial
in thaving
r :f: si =s(q
fi)
as zeroes, is a divisor of27t3 - 27t2 - 4a.)
Theresulting
surface will be denoted£q.
4.8. We also
give
ageometrical approach
to theelliptic
surfaces definedby
theequation y2 = x3
+a(x
+t2(t - 1))2.
Thisequation
exhibits the surface as a2:1 cover of the x-t
plane
branched over a sextic curve which issingular
in(0, 0).
Blowing
up(x
:=tx), taking
the strict transform andhomogenizing gives
aquartic
curve in
p2 (coordinates (x : t : z))
definedby
Let P =
(0 :
0 :1), Q
=(0 :
1 :1),
thenSing(F
=0)
=f P, Q}.
Theelliptic
surface is defined
by
the(affine) equation:
The
elliptic pencil
isgiven by
the inverseimages
of the lines t = À. The basepoint
of thepencil
is(1 :
0 :0)
which lies on F = 0. The line t = x intersects F = 0 in P withmultiplicity
4 and thus defines two sections of E(there
are alsotwo sections over x =