R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
F. L OONSTRA
Special cases of subproducts
Rendiconti del Seminario Matematico della Università di Padova, tome 64 (1981), p. 175-185
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Special
F. LOONSTRA
(*)
1. Introduction.
In
spite
of theimportance
of subdirectproducts
of modules wedo not know much of their structure in
general.
Anexception
is asubdirect
product
M = M1 XM2
of two modulesX,,
yM2 .
In thatcase there is a module F and
epimorphisms
such that if = For
general
subdirectproducts
such a common factor module .h does not exist. If however if = X
if,
S
is a subdirect
product
of theif, (i E I),
and .1~ a module withepi- morphisms
ce, :Mi -+ F(i
t EI),
such that M =f(mi)i..[ c fl
i E.1Milximi
=I then if is called a
special
subdirectproduct,
de-noted
F).
itl k
If is a submodule of the finite direct sum M* =
@ then
ifi~i
can be characterized in the
following
efficient way (1): Define F = and 0153i:by oti(mi) = mi + M;
then an elementm2, ... ,
mk)
E M*belongs
to hlexactly
if a1m1 -’- ... -f- «kmk = 0.In other words: a submodule 3f of the finite direct sum if* can be characterized
by
means ofhomomorphisms
0153i: and equa-tions of the
form a1x1
+ ... + akxk = 0.(*) Indirizzo dell’A.: Technische
Hogeschool
Delft,Afdeling
der Algemene Westenschappen, Julianalaan 132, 2600 AT Delft, Olanda.(1) See: L. FucHS - F. LOONSTRA, On a class of submodules in di1’cct pro- ducts, Rend. Accad. Naz. dei Lincei, Serie VIII, 60 (1976), pp. 743-748.
In the
following
wegeneralize
thisprocedure
for a setof modules and
epimorphisms
ai : onto an R-module F in case R is commutative.Let I-~ be a commutative
ring (1 E .R),
and F anonempty
set of non-zero
unitary
leftR-modules,
and ai : a setof
R-epimorphisms.
Let if*== 11
and M the submodule of M*defined as follows: zEr
where I and J are index sets. We suppose that for
each j
E J almostall r~i are zero. The R-module
M,
defineby (1)
is called asubproduct
of the
Mi,
denotedby
The relations
correspond
with ahomogeneous system
ofequations
over F:We denote
by
The solutions
(... , f i ,
of(3)
form an R-module S andthey
cor-respond
in a one to one way with the elements of the R-moduleIndeed,
if satisfies(3),
then there is ahomomorphism
92:defined
by
The relations
(3)
assurethat q
is well-defined.Conversely,
if1p E
HomR (XI Y, .~’),
thendetermines a solution of
(3).
We haveThe elements m =
(mi)zEI E
3f are determinedby
the relationsoci(mi)
=ti
i(i E I),
if is a solution of(3).
The R-module ~S’ of all solutions of(3)
can berepresented
aswhere
~B
is the submodule ofconsisting
of thei-components
of allsolutions of
(3).
IfNi
thenThe
subproduct M,
definedby (1)
can be considered as the inter- section of the one-relationsubproducts
whereand
Let ~1 be the
subproduct (1)
withcorresponding system (3)
of equa- tions over.F; using
the samesystem
ai: we mayconsider another
system
of with themi
corresponding system
ofequations
over FBoth
systems
of relations lead to the samesubproduct
lVl if any solu- tion of(3)
is a solution of(9)
andconversely.
It is clear thata necessary and sufficient condition therefore
is,
that there existsan
B-isomorphism.
where
Y’ = ..., hj’, ...>, hj’ = Ei rij’ixi,
such thatcorresponding
ele-i
ments cp
andv(q)
=~~
have theproperty gg(xi + Y)
=(p’(x, + Y’),
Vi E I.
2. Relation between
subproduct
and subdirectproduct.
We formulate a relation between the modules
and where The elements
99(i) c-
F) correspond
in a one to one way with the solutionsof the
equation g,
= 0. If we take an element of each moduleHomR(X/Yj, F),
where9)(i) corresponds
with a solution of the equa-tion g,
=0,
then the
system
defines an element of the
subproduct
.lVl if andonly
if for any twoindices j, k
E J we havewhere
For in that case the
corresponding system ( ... , f i , ... )
satisfies allequations (3).
If we define the mapby
where
(f~i))
is thecorresponding
solutionof gj
=0,
then(... , ...).,ej
defines a solution of
(3)
if andonly
ifDenoting by
.H =HomR (X/Y, F), Hi
=HomR (XI Yi, .F’), j
EJ,
thenwe find
2.1.
special
-subdirectproduct
H =means
of
theIII /
B(j), j E J.
To determine conditions therefore that M is a subdirect
product
X
Mi,
we consider theequations (3), § 1;
the solutions(fi)¡eI
haveic-i
to form a subdirect
product,
i.e. thatTherefore,
for anyf i E
F there must be ahomomorphism
q EE
gomR (XI Y, F)
such that +H)
=f i .
If cp : xi + H «f i ,
thenthis map must induce a
homomorphism
q;: - F. We now for- mulate2.2. Let the R-module M be
defined by (2), § 1;
then M is adirect
product
M= X lVl
iif
thefollowing
conditions aresatisfied:
2EI
PR.:
Mapping xi
= xi+
Y onto an elementf
e F there exists anR-homomorph18m (by (a)), and cp
has an extensioninducing
99. The two conditions(a)
and(b )
are there- fore sufficient therefore that is a subdirectproduct.
If the condi- tions( a )
and( b )
are satisfied we see moreover thatHom, (XI Y, .F’) ~
0.2.3.
Necessary
conditionstherefore
that anysubproduct
de f ines
a subdirectproduct
M = XMi,
arei C-1
(b’)
F is divisible . PR.: Since theequations (3), § 1
must have a solution with xi =f i, where f
is anyprescribed
element of.F’,
the mapf
i defines ahomomorphism 99: - F,
and thatimplies (a’). Choosing in
par- ticular-asubproduct
the
corresponding equation (over .h)
rlXI+
X2 = 0 must be solvable for any X2 =f 2
E.F’,
i.e. ~’ must be divisible.Summarizing
the last two results we find2.4.
Necessary
andsufficient
conditionstherefore
that any sub-product M, de f ined by
meansof
asystem (2), §
1 is a subdirectproduct,
are(a) O(Xi)
CÂnnR F (Vi
EI ) , (b)
F isinjective .
We continue this
§
with thefollowing question:
suppose that thesubproduct M,
definedby (2), § 1,
is a subdirectproduct
M= X M, .
iEl
Sincem
= n ~Vl~~>,
where M(j) is a one-relationsubproduct,
defined;eJ
by
thej-th equation
it is easy to prove that every is a subdirect
product
of the ·Using
the notations of 2.1.: H = XHj ~8~~~, fl F) ,
where(3(j)cp(j)
=i-i jij
==(’"?/~?’")t~jr ~
a solution of thej-th
Now99 c H
can berepresented
aswith = for all
pairs j,
k E J. If cp ~(..., f i, ... )iEI,
I thenby
definition offlue,
all thecomponents
of(... , f i’~, ...)
must be-foreach i E I-the same as those of
(..., f i,
But then all the M(j)are subdirect
products.
We have therefore2.5.
If
the8ubproduct M
x(j) is a subdirectproduct,
then alli
the one-relation
subproducts
X(j) are subdirectproducts of
theMi (i
EI).
We prove the converse : suppose M = defines a
subproduct,
iEJ
and that each is a subdirect
product
We prove that If is also a subdirect
product
of the.Mi (i E ~) .
If iscompletely
determinedby
the R-moduleHomn (XjY, ~’),
since cp E determines a solution of theequations (3), § 1:
(...y/~ by
means ofw(3ii)
=99 (xi + Y) = f
i(i E I).
° The modules Homn(XI Yj, I’) correspond (for each j
EJ)
with a subdirectproduct
Any corresponds
in a one to one way withwhere =
(Vj, k E J).
Since every E
.H~
can occur asj-th component
of an element99 E
H~,
and sinceg~ corresponds
with a subdirectproduct
anyprescribed f
=f2’’
of .F’ can occur asj-th component (corresponding
to
99(i)).
But then the samef i corresponds
to every99(k)
in(10).
Thatimplies
that M is a subdirectproduct
of the(i E 1).
The result is:2.6. The
subproduct M
=n
is a subdirectproduct
lJtI = XMi
i ic-I
i f
andonly if
all the one-relationsubproducts
M(n(j
EJ)
are subdirectproducts.
EXAMPLE. An
interesting example
of a subdirectproduct
is thefollowing
one-relationsubproduct
of the two R-modulesM1
and~V12 :
where (Xl and (X2 are
epimorphisms.
The last conditionimplies
that Mis a subdirect
product
of1~1
andM2.
Definethen
ocIN1
=F1, 0!2N2 == F2.
Now it is easy to prove theisomorphism
~ : M2/N2,
definedby Ø(m1
-~--N1 )
= m2-~- N2
if andonly
if(ml, m2)
E M. Moreover3. Essential
subproducts.
We suppose that M is a
subproduct (§ 1, (2))
of afinite
numberof R-modules =
1, 2,
... ,1~,
while theepimorphisms
oci:Mi
-* Fhave kernels
Ker (ai)
which are closed ini.e.
Ker (oci)
has no proper essential extension inMi .
We want tostudy
the conditions for if to be an essentialsubproduct
of theMi ( i
=1, ... , 1~ ) .
We know that(2) F. LOONSTRA, Essential submodules and essential subdirect products, Symposia Math., 23 (1979), pp. 85-105.
M n
Mi
is characterizedby
the fact that 0( Z ~ i )
andthis last condition is
equivalent
withDefining
for each i =1, ... , 1~
the idealLi
of 1’~by
and the submodule
by
we have
is characterized
by
Since Ker
(oci) C, CIMi (i
=1,
...,k),
it follows thatsince M n
Mi ç eMi (i
=1, ... , k).
If therefore the
subproduct
M is definedby epimorphisms
oci withclosed
kernels,
thenSince the converse of
(12)
isalways true,
we findSummarizing
we have thefollowing
result:subproduct of
the ... , Mk withepimorphisms
Lxi:F,
such thatthe kernels Ker
(ai)
are closed in(b’i), Li
the idalof
Rgenerated by
the rli, r, , ,ri 17 ...(i
=1,
...,k),
andFi
the submoduleof F,
de-fined by Fi = If
Ef
=017
i =1,
... ,k ;
then M is an essential sub-product of
theMl’.’" Mk, if
andonly if Pi ç eP (i
=1,
... ,k).
REMARK 1. Since Ker
(mi) ç clMi
and M r1.lVl
we see thatF
i cannot be the zero submodule of F.Suppose
that17
... ,k ;
L-ti:~ F~
is a finitesystem
ofR-modules and
(i
=1, ... , k)l
asystem
ofepimorphisms,
and les=
1,
... ,k}
be asystem
of k essential submodules of .F. Thitsystem
ai ,F,
determinesuniquely
an essentialsubproduct
M(of
the111i)
such that Mcorresponds
in the above sense with the pre- scribed submodules(i =1,
... ,k) . Indeed,
for each of the submodulesç eF
we define the idealLi ç
Rby
That
implies
that-foreach j
E J-we have a finitesystem
ofelements of .R
We define a
subproduct
M as followsSince
Fi ç eF (i =1, ... , ~)
it is now easy to see that the con-structed
subproduct
if is an essentialsubproduct,
forFi ç eF
andlXi(M
r1lVli)
=.F’i implies
M r1Mi ç eMi (i
=1,
...,k).
The
corresponding
one-relationsubproducts
are determinedby the j-equation
REMARK 2. is a
principal
idealring,
thenLi
=~ra~,
and thatmeans that .DI can be described
by
means of oneequation
product of
the ... ,Mk;
then(i)
The one-relationsubproducts M(j), j
E J are essential sub-products if
M is an essentialsubproduct.
(ii) If
theM(j), j
EJ,
are essentialsubproducts,
and J is af inite set,
then M is an essentialsubproduct.
PROOF :
(i)
This follows from the fact that(i =1, ... , k)
and the fact that M r1
Mi C
nlVli
C(i =1,
...,k)
forall j
E J.(ii)
Ifç eMi (i
=1,
... ,k)
forall j
E J(where
J is fi-nite ! ),
then we have for the intersectionManoscritto pervenuto in redazione il 23 maggio 1980.