R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
J AMES C. B EIDLEMAN H OWARD S MITH
On non-supersoluble and non-polycyclic normal subgroups
Rendiconti del Seminario Matematico della Università di Padova, tome 89 (1993), p. 47-56
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On Non-Supersoluble and Non-Polycyclic
Normal Subgroups.
JAMES C. BEIDLEMAN - HOWARD SMITH
(*)
ABSTRACT - This paper presents an
investigation
of groups G with the propertythat every
non-polycyclic
normalsubgroup H
has a finite G-invariant insolu- bleimage
and continues aprevious investigation
of groups with a similarproperty in relation to
non-supersolubility.
0. Introduction.
This work is concerned
mainly
with groupshaving
a certain proper-ty
in relation to theirnon-polycyclic
normalsubgroups.
Assuch,
it rep- resents a continuation of theinvestigations
carried out inpapers [ 1 ] and [2],
whereproperties u
and(respectively)
were introduced. We recall that a group G was said to haveproperty
u(respectively ~) if, given
anynon-nilpotent (respectively non-supersoluble)
normal sub-group H
ofG,
there exists a G-invariantsubgroup K
of finite index in H such thatH/K
isnon-nilpotent (respectively non-supersoluble). By
Theorem 2
of [2],
any group with c also has u.The firts section proper
presents
some further results on groups withproperty and,
it ishoped, provides
some motivation for the in- troduction of theproperty
7r which is defined in Section 2 and which is discussedthroughout
the remainder of the paper.1.
Non-supersoluble
normalsubgroups.
If the group G has ~, then we know from
Proposition
1 and Theo-rem 1 of
[2]
that the unionH(G)
of the series of iterated Hirsch-Plotkin(*) Indirizzo
degli
AA.: J. C. BEIDLEMAN: Department of Mathematics, Uni- versity ofKentucky, Lexington,
KY 40506; H. SMITH:Department
of Mathemat- ics, BucknellUniversity, Lewisburg,
PA 17837.radicals is
polycyclic
and that theintersection Of(G)
of all maximal sub-groups of finite index in G is contained in the
Fitting
radicalFit (G) (which
isfinitely generated).
These results draw attention to normalpolycyclic subgroups,
which arealways
contained inH(G). Defining P(G)
to beproduct
of all normalpolycyclic subgroups
of the groupG,
we have the
following.
LEMMA 1. Let G be a group with
properly
J. Then~f(G) P(G),
P(G)
ispolycyclic
and =PROOF. In view of the
preceding remarks,
all that needs to be shown isthat,
in a group G with (j,(the
re-verse inclusion
being obvious). But,
from Theorem 1of [2],
we knowthat G =
G/if;¡(G)
has 7 and so,again
from ourremarks, P(G)
ispoly-
cyclic.
The result follows.Now Theorem 1
of[l]
tells us that a group G has v if andonly
if~¡( G) ~
Fit(G),
Fit(G)
isnilpotent
and Fit = FitFurther,
we have seen that all normallocally nilpotent subgroups
of agroup G with c are
polycyclic. Accordingly,
it wouldperhaps
be reason-able to
hope
that the converse of Lemma 1holds,
but it is easy to show that this is not the case, for if G is the group withpresentation
~x, y ~ y -1 xy = x 2 ~,
then G has no non-trivial normalpolycylic
sub-groups =
1,
but G does not have a sinceFit (G)
is notfinitely generated. (This
is the sameexample
as that mentioned at the end ofSection 3 of
[2]).
To find necessary and sufficient conditions for a group tosatisfy
J, conditions which are in some way similar to those for v-groups asgiven
in Theorem 1 of[1],
we alter ourperspective
a littleand notice
that,
for groups G with u,Fit(G)
coincides with the Baer radical of G(and, indeed,
with the Hirsch-Plotkinradical).
For any groupG,
let us denoteby PI (G)
thesubgroup generated by
all subnor- malpolycyclic subgroups
of G. Then thefollowing
result holds.THEOREM 1
(c.f.
Theorem 1of [1]
and Theorem 1of [2]).
A group G hasproperty a if
andonly if
(a) ~ f(G) Pl (G)
andpolycyclic.
Further, if
G has (j, thenPROOF. If A is a subnormal
polycyclic subgroup
of the group G then A is contained in the iterated Hirsch-Plotkin radical of G(since
it is contained in the iterated Baerradical).
If G has ~, then this radical is49
polycyclic. Arguing
as in theproof
of Lemma1,
we see thatproperties (a)
and(b)
hold.Conversely,
assume that(a)
holds. Then(b)
also holds.Further, Fit (G)
isfinitely generated (since
it is contained in the Baerradical).
We shall show isnilpotent
and thatIt will
follow, by
Theorem 1of [2],
that G has or.Suppose
L is a G-invariantsubgroup
of finite indexin ~ f(G).
Then=
Frat (GIL)
is mte and hencenilpotent, by
a result ofGaschiitz
(see
5.2.15(i)
of[7]). Since ~ f(G)
ispolycyclic,
it follows that all finiteimages
arenilpotent
andhence, by
a theorem of Hirsch(see
5.4.18 of[7]), ~ f(G)
isnilpotent.
Now let be a nor-mal
nilpotent subgroup
of We need to show that F isnilpotent.
By (a)
and(b),
F ispolycyclic
and so, asabove,
if F is notnilpotent
there is a G-invariant
subgroup
T of finite index in F such that F =F/T
is
non-nilpotent. T/T
isfinite,
it is contained inFrat (G/T). Also,
isnilpotent.
We can nowapply
the Frattiniargument
as in theproof
of5.2.15(i)
of[7]
to conclude thatF/T
isnilpo- tent,
a contradiction whichcompletes
theproof
of the theorem.A further radical and one which is related to those discussed
above,
is
LP(G),
the(unique)
maximal normallocally polycyclic subgroup
ofthe group G.
Clearly P(G) ~ PI (G) ~ LP(G),
and we havealready
men-tioned an
example
of a group G in whichP(G)
= 1= ~ f (G)
andPI (G) =
=
Fit (G)
is notfinitely generated.
Anexample
due to McLain and re-ferred to in Section 4 of
[2] provides
us with anon-polycyclic, locally polycyclic
group G with a inwhich ~ f(G)
= 1. ThusPI (G)
cannot be re-placed by LP(G)
in the statement of Theorem 1. Anotherexample
worth
mentioning (with regard
to therelationship
between the variousradicals)
is one due to Dark[3].
His group G is a(non-trivial)
Baergroup with no non-trivial normal abelian
subgroup.
Inparticular, Pi (G) = G
andP(G)
= 1.To illustrate further the
significance
ofpolycyclic subgroups
withregard
to 7, wepresent
thefollowing result,
which followseasily
fromTheorem
1,
and which should becompared
withCorollary
5of [1]
andTheorem 4 of
[2].
THEOREM 2. A group G has r
if
andonly if
(a)
whenever H H and ispolycyclic,
then His
polycyclic
and(b) polycyclic.
We note that condition
(b)
cannot bedispensed with,
as is shownby
theexample
mentionedfollowing
theproof
of Lemma 1(or by
any group G = 1 but not
a)).
-2.
Non-polycyclic
normalsubgroups.
A group G shall be said to have
property n if, given
anynon-poly- cyclic
normalsubgroup
H ofG,
there exists a G-invariantsubgroup
Kof finite index in H such that
H/K
isnon-polycyclic (i.e. insoluble).
Among
otherthings,
our intent is toestablish,
for theproperty
7r, re-sults similar to those obtained for u and ~. In some cases, the
proofs
arenot
substantially
different from those of thecorresponding
results for u and a and are therefore sketchedbriefly
or omittedaltogether.
We be-gin
with acouple
of ratherstraightforward
results.LEMMA 2
(c.f.
Lemma 1of [1]
and Lemma 1of [2]).
A group G has7r
if and only if,
whenever H is anon-polycyclic
normalsubgroup of G,
there is a normal
subgroup
Noffinite
index in G such thatHN/N
isinsoluble.
LEMMA 3.
If
G hasproperly
7r then G has a.We note that McLain’s
(locally finite)
group, mentionedearlier,
hasthe
property
but not theproperty
7r, since alocally
soluble group withn must be
polycyclic.
PROOF OF LEMMA 3. If G has 7r and H is a
normal, non-supersolu-
ble
subgroup
ofG,
then either H isnon-polycyclic,
in which case thereis
clearly
a G-invariantsubgroup
K of finite index in H withH/K not supersoluble,
or else H ispolycyclic,
in which case thereis, by
a theo-rem of Baer
(see [8],
p.162),
a normalsubgroup
K of finite index in H such thatH/K
isnon-supersoluble.
Since H isfinitely generated,
wemay take K to be normal in
G,
and theproof
of Lemma 3 iscomplete.
Using
theselemmas,
thefollowing
theorem may beproved
withoutdifficulty.
THEOREM 3. A group G has n
if and only polycyclic
andhas 7r.
Further, if
G has 7r, thenP(G) (indeed LP(G))
ispoly- cyclic
andP(G/~ f(G)) ~
As a consequence of Theorem
3,
we note that a group G has 7r if andonly
if G has c and and 7r.Our sufficient conditions for a group G to have 7r include the
hypoth-
51
esis that have 7r. This
is, perhaps,
a littleunsatisfactory.
Ac-cordingly,
it would beinteresting
to know of a(reasonable)
sufficient condition for a group G = 1 to have 7r.Also,
there isperhaps
a theorem withregard
to theproperty
7r which iscomparable
to Theorem 1
of[l]
and Theorem 1of [2] (or
Theorem 1above)
for u and~
respectively.
Oneconjecture might
be that a group G has 7r if andonly
if
LP(G), LP(G)
ispolycyclic
and =However,
in the final section wegive
anexample
which shows that this is not the case.(The given hypotheses
are,nonetheless,
seen toimply
that G has c and
if,
inaddition,
G islocally
finite then G has n - this follows from Theorem 8below).
3. Closure
properties
and finiteness conditions.We
begin
this section with some resultsconcerning
n which recall similar results from[1]
and[2]. (Part (iii)
of course has nocounterpart
for the
property u).
THEOREM 4.
(i)
Let G be a group withproperly
n and let H be anon-polycyclic
ascendantsubgroup. of
G. Then there is a normal sub- group Lof finite
index in G such thatHL/L
is insoluble(see
Corol-Lary
2of [1 ]).
(ii)
Let H be an ascendantsubgroup of
the group G.If
Gthen so does H
(see
Lemma 2of [1 ]
and Lemma 3of [2]).
(iii)
Let G be a group with asubgroup.
Hoffinite
index. Then G hasproperly
7rif
andonLy if
H does(see
Theorem 10of[2]).
We now
present
a theorem which indicates one way ofdistinguish- ing
the class of groups with 7r within the class of groupssatisfying
a. Todo this we
require
thefollowing
definition.A group G shall be said to
satisfy
theproperty
7r*if,
for each normalsubgroup
N whose finiteG-quotients
are allsoluble,
there is a bound(depending
ingeneral
onN)
for the derivedlengths
of thesequotients.
We are now
ready
to prove:THEOREM 5. Let G be a group with a. Then G has n
if and only if G satisfies
n*.PROOF. It is
easily
seen that ~cimplies
7r*.Suppose
then that G sat-isfies 7r*. Then is
polycyclic
and has c([2],
Theorem1).
It isstraighforward
toverify
thatG (G)
has 7r*and,
in order to showthat G has 7r, we can
(in
view of the remarkfollowing
Theorem 3above)
assume that
~f(G)
= 1. Let N be a normalsubgroup
of G all of whose fi- niteG-quotients
are soluble and hence of derivedlength
at mostd,
say.Let M be a maximal
subgroup
of finite index in G. It suffices to prove thatN ~d~ M,
for thenN ~~ 5 ~f(G)
= 1 and so N is soluble andhence, by Proposition
1of [2], polycyclic. Clearly
we may supposeN 1- M,
so that G = MN. Let T =mnN. Then
N : T ) I
is finite and theconju- gates
of T in G areprecisely
theconjugates
in N. WriteTo
=CoreG
T.Then
N: To ) I
is finite and so N~d ~ To ~ M,
asrequired.
Using
results of Mal’cev and Zassenhaus(4.2
and 3.7of [8]),
the above theorem and Theorem 7of [2],
we obtain thefollowing.
THEOREM 6. Let G be a
subgroup of GL(n, R),
where R is afinite- ly generated
domain. Then thefollowing
statements areequiva-
lent :
°
(a)
G has 7r.(b)
G has a.(c)
Theunipotent
radicalof
G isfinitely generated.
COROLLARY 1. Let G be a
subgroup
ofGL(n, Z).
Then G has 7r.Returning
now to closureproperties,
we shall establish a resultwhich
depends partly
on the abovecorollary.
THEOREM 7. Let G be a group with normal
polycyclic by-finite subgroup
S. Then Gif
andonly if GIS
has 7r.PROOF.
Suppose G/S
hasproperty n
and let N be a normal sub- group of G with all of its finiteG-quotients
soluble. ThenNS/S
ispolycyclic
and so N ispolycyclic-by-finite-by-polycyclic
and hencepolycyclic-by-finite
and thuspolycyclic.
So G has 7r.Conversely,
sup- pose that G has n and let C =CG (8).
Assume that S is finite.Then, by
Theorem
4,
both C and CS have 7r. Since C n SZ(C),
it followseasily that C/C
n S has andthus, by
Theorem 4again,
thatG/S
has n.By
induction on the Hirsch
length,
we may thus suppose that S isfinitely generated
and free abelian. ThenGIC is
Z-linear and thus has 7r,by Corollary
1.Now let N be a normal
subgroup
of G such that S N and all finiteG-quotients
ofN/S
are soluble. Since S ~C,
we haveNC/C polycyclic.
If
N1
= N f1 C is notpolycyclic
then there is a G-invariantsubgroup
Tof finite index in
N1
withN1/T
insoluble. Let D = which is normal in G and of finite index in N. Since S ~ D we haveN/D
solubleand so
N1/T
iscentre-by-soluble
and thus soluble. This contradictioncompletes
theproof
of the theorem.53
We note the
following
consequence, whoseproof requires (besides
Theorem7)
Theorem 6 and Lemma 3 above andProposition
1of [2].
COROLLARY 2. Let S be a
soluble-by-finite
normalsubgroup
of thegroup G. Then G has 7r if and
only
ifG/S
and S both have 7r.It is easy to see that any
polycyclic-by-finite
group G has n, and weknow from Theorem 6 of
[2]
that a group G with finite rank has o~ if andonly
if G ispolycyclic-by-finite.
Thus a group G of finite rank has 7r if andonly
if it has a(if
andonly
if it ispolycyclic-by-finite).
Next,
wegive
acouple
of results onlocally
finite groups.LEMMA 4. Let G be a
locally finite
groups which is alsoresidually finite,.
Then G has nif
andonly if
everylocally
soluble normal, sub-group.
of
G isfinite.
PROOF.
Suppose
G has 7r and let N be alocally soluble,
normal sub- group of G. Since every finiteimage
of N issoluble,
N ispolycyclic
andtherefore finite.
Conversely,
assume G satisfies thegiven hypothesis
on
locally
soluble normalsubgroups
and let N be a normalsubgroup
ofG all of whose finite
G-quotients
are soluble. Then N isresidually
solu-ble and hence
locally
soluble. Thisgives
N finite and thuspolycyclic.
Hence G has 7r.
THEOREM 8. A
locally finite
group G hasproperty
nif
andonly if
the
foLLo2ving
conditions hold:(a) Every locally soluble,
normalsubgroup of
G isfinite.
(b)
G has a.PROOF. If the
locally
finite group G has cor, then the finite residual R of G is finite(and nilpotent), by
Theorem 8 of[2]. Suppose
G has n andlet N be a
locally soluble,
normalsubgroup
of G. ThenG/R
has 7r andso,
by
Lemma4, NR/R
is finite.Hence, by
Lemma3,
N is finite. Nowassume G satisfies
(a)
and(b)
and letN/R
be alocally soluble,
normalsubgroup
of G. Then N islocally
soluble and therefore finite. ThusN/R
is finite and it follows from Lemma 4 that
G/R
has 7r. Let H be a normalsubgroup
of G all of whose finiteG-quotients
are soluble. ThenHR/R
is
polycyclic
and therefore H ispolycyclic.
Thus G has 7r.We conclude this section with some consequences of Theorem
8,
Theorem 6of [1]
and Theorem 4.32 of[6]
on groups with finiteness con-ditions on
conjugates.
For the second theoremhere,
we recall that agroup G is a
CC-group
ifG/CG«x)G)
is aCernikov
group, for all x in G.By
Lemma 2.1of [5],
R’ ~Z(G)
andG/R
is anFC-group,
where R de- notes the radicablepart
of G.THEOREM 9. Let G be an
FC-group.
Then G has nif
andonly if,
whenever H is a
locally soluble,
normalsubgroup of G,
then H has asubgroup K ~ Z(G)
such thatH/K is finite.
THEOREM 10. Let G be a Then
(i)
G has uif
andonly if
Fit(G) is nilpotent
and Fit(G/R) _
= (Fit (G))/R.
(ii)
G has aif
andonly if Fit (G) is finitely generated
andFit
(G/R) = (Fit (G))/R.
(iii)
G has 7rif
andonly if
G has a andG/R
has ~c.4. An
example
and analgorithm.
In this final section we
present
analgorithm
which determines whether certain normalsubgroups
of a group with n arepolycyclic,
butfirst we
give
anexample
whichdisposes
of theconjecture
mentioned atthe end of Section 2. In
fact,
wepresent
a(non-trivial) locally
solublegroup G with trivial
locally polycyclic
radical in which~f(G)
= 1. Clear-ly
this group cannotsatisfy
7r. The group iseasily
described.For each
integer
i ~0,
letHi
be an infinitecyclic
group. DefineG1
to be
Ho and, inductively, Gi + 1
=Hi wr Gi
for eachi ~ 1,
where thewreath
product
in each case is the standard one. Then let G be the as-cending
union of theGi , i
=1, 2,
....Clearly
G islocally
soluble and torsion-free.In order to establish this
claim,
werequire
twolemmas,
the first of which is almost obvious.Incidentally,
we remark that the group G is not a «wreath power» of infinitecyclic
groups in the sense of P. Hall(see
6.2 of[6]).
LEMMA 5. With G
defined
asabove,
let i be anarbitrary positive integer
and let N be the normal closure in GHi+1’ ...).
ThenG = Gi N
andGi n N = 1.
LEMMA 6.
Suppose
G= ~a~ wr H,
the standard wreathproduct
55
of
theinfinite cyclic
group.(a)
with a group Hsatisfying ~ f ( H )
= 1.Then ~ f(G)
= 1.Before
sketching
theproofs
of theselemmas,
let us see howthey
suffice to establish our claim.
Firstly,
suppose K is anon-trivial, locally polycyclic,
normal sub- group of our group G andlet g
be a non-trivial element of K. Then g EGi ,
forsome i,
and(g)H1
islocally polycyclic. Suppose Hi
=(h).
Then[h, g] ~
1and, since g
has infiniteorder, ([h, g]~~9>
is notfinitely
gener-ated. Thus
([g, h], g)
is notpolycyclic,
a contradiction.Now let x be any non-trivial element of G.
Again x
EGi ,
for some i.By
Lemma 6(and induction), ~ f(Gi)
= 1.By
Lemma5, therefore,
wecan find a maximal
subgroup
M of G which does not contain x. Thus~f(G)
= 1.PROOF OF LEMMA 5.
Clearly
we haveG = Gi N. Now,
for eachj ~ i,
let ...,Hj),
asubgroup -of
ing
thisargument (if necessary)
we obtain(eventually)
x eHGi n Gi
=- 1. The result follows.
PROOF OF LEMMA 6. The
proof
here imitates(so
far aspossible)
acouple
of theproofs
from[4].
Let G be asstated,
and suppose first that H is finite. Let x be a non-trivial element of the base group A =(a)H
and choose a
prime p
notdividing
the order of H such thatUsing
Maschke’sTheorem,
one theneasily
obtains a G-invariant sub- group D of A suchthat z g
D andA/D
is asimple
H-module. ThenHD,
a maximalsubgroup
of finite index in G. It followsthat §f(G) =
= 1. In the
general
case,again
assume x is a non-trivial element of A ==
(a)H.
As in theproof
of Lemmas 3.2 and 3.3of[4],
butusing
thestronger
condition~f(I~
=1,
we can obtain a normalsubgroup K
of fi-nite index in H such that Frat
(H/K)
= 1 and ahomomorphism
0 fromG onto
~a~ wr H/K
such that 1. This allows us to reduce to thecase where H is finite and the result follows.
Corollary
1 of each of papers[1]
and[2]
describes analgorithm
fordetecting nilpotency
orsupersolubility
of certain normalsubgroups.
We conclude with a similar
algorithm
for theproperty
7r.PROPOSITION. Let G be a
finitely presented
group with theproperty
7r. Then there is an
aLgorithm which,
when afinite
subset ...,xm ~
.
of
G istogether
with theinformation
that N =x.)
is normal in
G,
decides whether N ispolycyclic.
PROOF. As in the
proof
ofCorollary
1 of[1],
we introduce two re-cursive
procedures,
one of which mustterminate, by
Lemma 2. The re-sult will follow
immediately.
The first
procedure
is the obviousanalogue
of that described in theabove-mentioned
corollary.
Now let
(~wl,1, ..., wl, ml ~ , ~w2,1, ..., w2, ~ ~ , ..., ~wn,1, ..., wn, ~ ~)
be an
n-tuple
of subsets of words in thegenerators
xl , ..., Xm. Fur-ther,
for each i =1,
..., n, letHi
be thesubgroup (of N) generated by
the elements wl,1, 9 ..., wl, mi , ..., ..., wi, Tnï. The second
procedure attempts
to show that thesubgroups Hi
form apolycyclic
series for N.Again referring
to theproof
ofCorollary
1 of[1],
it is not difficult to seehow to
proceed.
The details are omitted here.REFERENCES
[1] J. C. BEIDLEMAN - D. J. S. ROBINSON, On the structure
of
the normal sub- groupsof
a group:nilpotency,
Forum Math., 3 (1991), pp. 581-593.[2] J. C. BEIDLEMAN - D. J. S. ROBINSON, On the structure
of
the normal sub- groupsof
a group:supersolubility,
Rend. Sem. Mat. Univ. Padova, 87 (1992), pp. 139-149.[3] R. S. DARK, A
prime
Baer group, Math. Z., 105 (1968), pp. 294-298.[4] K. W. GRUENBERG, Residual
properties of infinite
soluble groups, Proc.London Math. Soc., (3), 7 (1957), pp. 29-62.
[5] J. OTAL - J. M.
PEÑA,
Characterizationsof
theconjugacy of Sylow p-sub-
groups
of CC-groups,
Proc. Amer. Math.Soc.,
106 (1989), pp. 605-610.[6] D. J. S.
ROBINSON,
Finiteness Conditions and Generalized SolubleGroups
(2 vols.),Springer,
Berlin (1972).[7] D. J. S.
ROBINSON,
ACourse
in theTheory of Groups, Springer,
New York (1982).[8] B. A. F. WEHRFRITZ,
Infinite
LinearGroups, Springer,
Berlin (1973).Manoscritto pervenuto in redazione il 29 novembre 1991.