R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
M ARIA J OÁO F ERREIRA M ARCO R IGOLI
R ENATO T RIBUZY
Isometric immersions of Kähler manifolds
Rendiconti del Seminario Matematico della Università di Padova, tome 90 (1993), p. 25-38
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MARIA
JOÁO
FERREIRA - MARCO RIGOLI - RENATOTRIBUZY (*)
1. Introduction.
The
present
article is concerned with obstruction to the existence of(I, I)-geodesic
isometric immersions from a ICAhler manifold M.The
concept
of a(1,1)-geodesic
map is a natural extension of the no-tion of a minimal immersion from a Riemann
surface; (1,1)-geodesic
maps appear sometimes in the literature with the name of circular or
pluriharmonic
maps.It is well known
([D-R])
that the(I, I)-geodesic
isometric immer- sions from M into R n areexactly
the minimal isometric immersions. A naive remark allows us to inferthat,
moregenerally,
the minimal iso- metric immersions from a ICAhler manifold into alocally symmetric
Riemannian manifold of
non-compact type
are(1,1)-geodesic.
M.
Dacjzer
and L.Rodrigues
haveproved
in[D-R]
that ifQc
is aspace form of sectional curvature c > 0
(resp.
c0) and p:
(m = complex
dimension ofM)
is a(1,1)-geodesic (resp. minimal)
iso-metric
immersion,
then m = 1. We will show that theonly ( 1,1 )-geode-
sic isometric immersions from M into a
1/4-pinched
Riemannian mani- fold are the minimal isometric immersions from a Riemannian surface.A dual result is obtained for maps into a Riemannian manifold with
negative
sectionalcurvature, namely,
if N is a Riemannian manifold whose sectional curvaturessatisfy - 1 :-5 -1 /4,
theonly
minimal isometric immersions from a Kahler manifold into N are the minimal immersions from a Riemann surface.
In a different
context,
space forms can be considered asconformally
(*) Indirizzo
degli
AA.: M. J. FERREIRA:Departamento
de Matematica, Fa- culdade deCiencias,
Universidade de Lisboa, Rua Ernesto de Vasconcelos, Ed C2, 1700 Lisboa,Portugal;
M. RIGOLI:Dipartimento
di Matematica, Universitàdegli
Studi di Catania, Viale Andrea Doria 6, 95125Catania, Italy;
R. TRIBUZY:Departamento
de Matematica - ICE, Universidade doAmazonas,
69000 Manaus, AM, Brazil.flat Einstein manifolds. In that direction we
generalize
Theorem 1.2of [D-R]
to isometric immersions intoconformally
flat Riemannian ma-nifolds with certain bounds on their Ricci curvature.
To a certain extent
holomorphic
maps between Kahler manifolds arethe
simplest examples
of(1,1)-geodesic
maps. In[D-T],
M.Dacjzer
andThorbergson
have shown that for m > 1 theonly (1,1)-geodesic
isome-tric immersions from M into a
complex space-form
withholomorphic
sectional curvature c ~ 0 are the
holomorphic
immersions.Regarding
as the
complex
Grassmannian of one dimensionalcomplex subspa-
ces of C’ it is natural to
try
to extend their results to isometric immer- sions into acomplex
Grassmannian. We show that if N is thecomplex
Grassmannian
of p-dimensional complex subspaces
of C’ and m >(p - - 1 ) (n - p - 1) + 1,
theonly (1,1)-geodesic
isometric immersions from Mm into N are theholomorphic
immersions.Furthermore,
if N is thecorresponding
dualsymmetric
space ofnon-compact type,
for m >> ( ~ - 1 ) (n - ~ - 1 ) + 1,
there are nonon-holomorphic
minimal isome- tric immersions from M m into N.2.
(1,1)-geodesic
maps intopinched
Riemannian manifolds.Let Mm be a Kahler manifold with
complex
dimension m and N bean
arbitrary
Riemannian manifold.The
complex
structure of M mgives
rise to thesplitting
where is the
complexified tangent
bundle and the holomor-phic tangent bundle,
is theeigenbundle
of Jcorresponding
to the ei-genvalue
+ i.The second fundamental form of a smooth map p: M -> N is the cova-
riant tensor field a = E
C( 02 T * M ).
p is said to be
(1,1)-geodesic
if the(1,1)-part
of thecomplex
bilinearextension of « vanishes
identically,
orequivalently,
if forany X,
Y EE C( TM )
where J denotes the
complex
structure of M.p is said to be minimal if trace a = 0.
Clearly (1,1)-geodesic
immer-sions are minimal immersions.
PROPOSITION 1. If N is a
non-compact locally symmetric
Rieman-nian manifold and p: is an isometric immersion the
following
assertions are
equivalent:
is
( 1,1 )-geodesic, (ii) p
is minimal.PROOF. For each x E M we consider a local orthonormal frame field
... , em,
Je1,
... ,Jem )
in aneighbourhood
of x. We shall use the fol-lowing
notation:and
If
R M
andR N
denoterespectively
the Riemannian curvature ten-sors of M and
N, using
thecomplex
multilinear extension of the Gaussequation
we can writeSince M m is Kahler the left-hand side member of
(1)
vanishes identi-cally. If p
isminimal, summing
in i weget
On the other
hand,
the universalcovering
of N is a Riemanniansymmetric
spaceN
of thenon-compact type.
Let 7~:N -
Nrepresent
the
covering
map and G the connectedcomponent
of theidentity
in thegroup of isometries
of N . At
somepoint
y EN
suchthat x( y )
= welet K denote the
isotropy subgroup
of G at y. If Srepresents
the Liealgebra
of G and x thesubalgebra corresponding
toK,
we canidentify Ty N
with theorthogonal complement T
of x in 8 withrespect
the Kil-ling-Cartan
form of G. Under thisidentification,
for each m, thelifting
of2~ (resp. corresponds
to some vectorE~(resp. E _~ )
of1P~
where denotes the
complexification
of ~P. Then if R denotes the Rie- mannian curvature tensor ofN
we know thatFrom
(2)
we conclude thatE -j)
= 0 for 1 ~i, j
m, hence p is( 1,1 )-geodesic.
REMARK. If N is a real
symmetric
space of rank 1 either of thecompact
ornon-compact type and p
is a(1,1)-geodesic
isometric immer-sion,
eq.(3) holds,
and we recover Theorem 1.2of [D-R].
Indeed[E j,
= 0 for all 1 i,j m and it iseasily
seen that this canhappen only
when m = 1. We nowgeneralize
this result topinched-Rieman-
nian manifolds.
Let S be a
positive
real number. A Riemannian manifold N is said to bepositively (negatively) S-pinched
at apoint y E N
if there exists a po- sitive real number L such that LSL( - L ~ - LS )
for any 2-dimensional
subspace
of N is said to bepositively (ne- gatively) S-pinched
if it ispositively (negatively) S-pinched
at eachpoint y E N.
THEOREM 1. Let N be a
positively 1/4-pinched
Riemannian mani- fold. is a(1, I)-geodesic
isometricimmersion,
thenm = 1.
THEOREM 2. Let N be a
negatively 1/4-pinched
Riemannian mani- fold. If p: Mm --~ N is a minimal isometricimmersion,
then m = 1.To prove Theorems 1 and 2 we need the
following
lemma:LEMMA 1. Let N be a Riemannian manifold whose sectional cur-
vatures
satisfy
one of thefollowing inequalities:
Then if
X, Y, Z,
W is a local orthonormal frame field thefollowing inequality
holds:PROOF OF LEMMA 1. Assume
(i)
holds.By polarization
weget
Therefore from the left-hand side
inequality
we haveReplacing
Xby - X
in theright-hand
side ofinequality (4)
weget
(5)
and(6)
lead toNow a similar
procedure
with Zreplaced by -
Z in allinequalities gives
PROOF OF THEOREMS 1 AND 2. If necessary
normalizing
the metricwe can assume, without loss of
generality,
that L = 1.If p
is(1,1)-geodesic
in the case of Theorem1,
or if p is minimal in the case of Theorem2,
we know from(2) that,
for mwhere we have used the Bianchi
identity.
Now the
hypothesis
of Theorem 1(2) implies
thatwhich cannot
happen.
Then m must be 1.3. Minimal isometric immersions into
conformally
flat Rieman- nian manifolds.Riemannian manifolds with constant sectional curvature are very
special examples
ofconformally
flat Riemannian manifolds.A Riemannian manifold
(N, h)
is said to beconformally
flat if there exists a smooth functionf : N -~
R such that(N, e 2f h)
is flat.The main invariant under conformal
changes
of the metric is theWeyl
curvature tensor W. Thevanishing
of Wcompletely
characterizes theconformally
flat Riemannian manifolds.For each x E N we denote
by ex (n)
thesubspace
of con-sisting
of «curvature like» tensors: that means those tensorssatisfying
the Bianchi
identity.
The action of(n
=dim N )
ongives
rise to the
following decomposition
into irreduciblesubspaces
where = and
Rx ( N )
is formedby
the «Ricci traceless»tensors,
thatis,
those tensors 0 whose Ricci contractionc(6) (c(0) (x, y)
= trace0( x,
., y,.))
vanishes. Theorthogonal complement
of is called the space of
Weyl
tensors. The We-yl
tensor of a Riemannian manifold is theWeyl part
of its curvaturetensor.
It is an easy matter to
verify
that the Riemannian curvature tensor ofa
conformally
flat Riemannian manifold N with Ricci curvatureRicciN
and normalized scalar curvature
S(N ) =1 /n
traceRicciN
isgiven by
In this section we
analyse
the existence of minimal isometric im- mersions into certainconformally
flat Riemannian manifolds.As above Mm will
represent
a Kahler manifold withcomplex
dimen-sion m. We shall use the
following
notationTHEOREM 3. Let N be a
conformally
flat Riemannian manifold withpositive
scalar curvature such thatr/S
>n/2(n - 1).
If is a
(1,1)-geodesic
isometricimmersion,
thenm = 1.
THEOREM 4. Let N be a
conformally
flat Riemannian manifold withnegative
scalar curvature such thatR/s
>n/2(n - 1).
If p:
M m ~ N is a minimal isometricimmersion,
then m = 1.COROLLARY 1. Let N be a
conformally
flat Riemannian manifold such thatnA/2(n - 1)
A for somepositive
real number A.is a
(1, I)-geodesic
isometricimmersion,
thenm = 1.
COROLLARY 2. Let N be a
conformally
flat Riemannian manifold such that -A ~RicciN - (n/2(n - 2))A
for somepositive
real num-ber A.
If m > 1 there does not exist minimal isometric immersions from M m into N.
REMARK. If N has non-zero constant sectional
curvature, r/S
== 1.
PROOF OF THEOREM 3.
Assuming
that p: Mm -~ N is(1,1)-geode-
sic,
we obtain from eq.(2)
On the other
hand,
if m >1, taking i ~ j
we conclude from(7)
thatwhich is a contradiction.
PROOF OF THEOREM 4.
If p
isminimal,
eq.(2)
establishes thatBut from
(7)
which can
only happen
if m = 1.4.
Holomorphicity
of minimal isometric immersion into acomplex
Grassmannian.Dacjzer
andThorbergson
have studied in[D-R]
minimal isometric immersions into acomplex
space formCQc
with non-zero constant holo-morphic
sectional curvature c. Their result states that if m >1,
c > 0( 0)
and p: is a(1,1)-geodesic (minimal)
isometric immer-sion, then p
is ±holomorphic.
Regarding
CP’ as thecomplex
Grassmannian manifold ofcomplex
1-planes
we extend these results to isometric immersions into acomplex
Grassmannian(respectively
to its dualsymmetric
manifoldof
non-compact type).
We let denote the Grassmannian manifold of
p-dimensional complex subspaces
of cn. The action of theunitary
groupU(n)
on endows with the structure of a Hermitiansymmetric
space isometric to
U(n)/ U((p)
x(n - p)).
Inparticular, Gp(cn)
is aKahler manifold. We
represent by
its dualsymmetric
space ofnon-compact type U(p,
n - xU(n - p)),
whereU(p,
n -p)
is the
group of
matrices inGl( Cn)
which leave invariant the Hermitianform - Zl , Z1 -
...- Zp Zp
+ + ... +THEOREM 5. Let be a
(1,1)-geodesic
isometricimmersion. If
m > ( ~ - 1 ) (n - p - 1 ) + 1, then p
is ± holomor-phic.
THEOREM 6. Let 9: be a minimal isometric immer- sion. If m >
( ~ - 1 ) (n -
p -1)
+1, then p
is ±holomorphic.
REMARKS.
1)
When p = 1 weget
Theorems A and Bof [D-T].
2)
As an easy consequence of Theorems 5 and 6 we alsoget
Theo-rem 1.2 of
[D-R]
which asserts that for Riemannian manifolds with con-stant sectional curvature c > 0
( 0)
theonly (1,1)-geodesic (minimal)
isometric immersions are the minimal immersions from a Riemann sur-
face.
In
fact,
letQc
be a Riemannian manifold with constant sectional cur-vature c.
Assume,
forinstance,
that c > 0 and m > 1. Without loss ofgenerality
we can assumeQc
issimply connected,
hence isometric to S n .Therefore,
since there exists atotally geodesic
immersion from S"to a
(1,1)-geodesic
wouldoriginate
a(1,1)-geodesic immersion §:
This cannothappen, since y
would be
simultaneously holomorphic
andtotally
real. The case c 0 isanalogous.
PROOF OF THEOREM 5 AND 6. Let
represent
the Liealgebra
of
U(k),
N = and q = n - p.At some
point
y weidentify Ty N
with theorthogonal
com-plement 1P
of x in’U(n)
withrespect
to theKilling-Cartan
form of
U(n).
Let1P~
denote thecomplexification
of 1P.Under this identification we obtain from
(2)
Therefore,
we conclude that = W is an Abelian iso-tropic subspace
ofO’c.
We remark thatN is a Kahler manifold. It is
easily
seenthat,
under the above identifi-cation,
thetype decomposition
ofTy N gives
rise to thesplitting
where
and
Clearly, if p
isholomorphic (respectively -holomorphic)
W c 1P+(re- spectively
W c1P~ ).
It is also a well-known fact that 1P+ and T- are Abe- liansubspaces
ofTheorem 5 is now a direct consequence of the next lemma.
By
duali-ty
we obtain Theorem 6 in the same way.LEMMA 1. If
( ~ - 1 ) ( q - 1 )
+1,
then W cT+ or W c c 0-.PROOF. We assume that and and prove that
dimC W > (p-1)(q-1).
We shall consider two cases:
Since the
procedure
is similar weonly
consider W n 1P~ # 0.There
exists,
atleast,
one matrix 0 # X= 0]
e W whereBx
is0
A, x 0
a q x p
complex
matrix and Y =By 0
whereAy
is a non-zero p x qcomplex
matrix. ~~Y 0Now
[X, Y]
= 0implies
thatWe can assume without loss of
generality
thatp ~
q. FromBxAy
= 0we see that the rank of
Bx
isstrictly
smaller than p, otherwiseAy
wouldbe
identically
zero.Let
and take
Since the metric is invariant
by
the action ofU(p)
xU(q),
wi-thout loss of
generality
we can asume thatBX0 = f 0
where I is adiagonal non-singular
matrix. 0 0We consider the
subspaces
and
As we can see from the
equations AxBxo
=BXoAx
=0,
for eachX E we must have
Ax = [0 ~ ],
whenÃx
is a 1 x 1 matrix with~p=/c. 0 A x
Now let
and choose
If necessary
changing WI
andW2
we can assume, without loss of ge-nerality,
that thisparticular AX1
is adiagonal nonsingular
matrix.Again
theequations
= = 0 allow us to concludethat,
forLSv Ol
-each X =
W2
we must have0 0
where a(p - r)
x(q - r)
matrix. Thus 0 0
since
1 ~ r ~ ~ -
1. Theequality
-
1)
+ 1 is attained when r = 1.- Case 2. - Assume now that W n
1P+ = §
and W n P- =O.
For each1 x s
complex
matrix C = we letCl ,
... ,C,
denote the lines of C andC1, ..., CS
its columns.First notice that if there exist two
linearly independent
ele-ments
with
(Ax)l
= ... = = 0 and(Ay),
= ... =(Ay)p-2
= 0 we shallhave
B(= By =
0.Indeed,
from[X, Y]
= 0 weget
that fori, j
Ef 1,
...,ql,
so that if
Bx’ - 0,
there exists 1 si s q
such that X = Y E 1P~ which cannothappen.
Using
an inductiveargument
we conclude that we canonly
havetwo alternative situations:
A)
There exists one andonly
one elementsuch that
(Ax),
= ... =(Ax)p-l
= 0.B)
There exists p - 1 such that in W there is no elementSuppose
A holds. Then there exist at most(q - 1) linearly indepen-
dent elements
Y 0
Y=Ay
in W with(Ay)i =
... 0. InBy
0In W
fact,
for suchY1,
is a solution of theequation (Bl)T)
= 0( I
:5 k :5P).
Moreover any other Z =0 0
Az
E W is such that for any
(1 k p).
Moreover any other Z =z
0
E W is such that for anyBz 0
1 S k S
p - 1 (Az)k,(Bl)T)
= 0. Therefore there exist at mostlinearly independent
elements in W.If B holds with a similar
reasoning
weeasily
obtain that W i~(p-1)(q-1)+1
as well.REMARKS. In the same way other bounds on the dimension of
Mm ,
can be obtained
preventing
the existence ofnon-holomorphic (1, l)-geo-
desic
(respectively
minimal for thenon-compact case)
isometric immer- sion into other classical irreducible Hermitiansymmetric
manifolds.For instance if N is the
complex quadric
isometric toSO(n
+2)/(,SO(2)
xSO(n)) (respectively SO(2, n)/(SO(2)
xSO(n)))
we can prove
analogously
that if m > 2 and p: N is a(1,1)-geo-
desic
(respectively minimal)
isometricimmersion, the p
is ± holomor-phic.
The authors were informed that Ohnita and
Udagawa [0-U]
haveobtained this result
using
different methods.In a
forthcoming
paper weanalyse
the minimal isometric immer- sions from a Kahler manifold into a real Grassmannian manifold.Acknowledgnlents. -
The authors would like to thank forhospitality
at ther International Centre for Theoretical
Physics,
Trieste.REFERENCES
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