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Some examples of composition operators and their approximation numbers on the Hardy space of the
bi-disk
Daniel Li, Hervé Queffélec, Luis Rodríguez-Piazza
To cite this version:
Daniel Li, Hervé Queffélec, Luis Rodríguez-Piazza. Some examples of composition operators and their
approximation numbers on the Hardy space of the bi-disk. 2018. �hal-01536919v2�
Some examples of composition operators and their approximation numbers on the
Hardy space of the bi-disk
Daniel Li, Hervé Queffélec, L. Rodríguez-Piazza
March 1, 2018
Abstract. We give examples of composition operators C
Φon H
2( D
2) showing that the condition k Φ k
∞= 1 is not sufficient for their approximation numbers a
n(C
Φ) to satisfy lim
n→∞[a
n(C
Φ)]
1/√n= 1, contrary to the 1-dimensional case.
We also give a situation where this implication holds. We make a link with the Monge-Ampère capacity of the image of Φ.
Key-words: approximation numbers; Bergman space; bidisk; composition oper- ator; Green capacity; Hardy space; Monge-Ampère capacity; weighted compo- sition operator.
MSC 2010 numbers – Primary : 47B33 – Secondary : 30H10 – 30H20 – 31B15 – 32A35 – 32U20 – 41A35 – 46B28
1 Introduction and notation
1.1 Introduction
The purpose of this paper is to continue the study of composition operators on the polydisk initiated in [2], and in particular to examine to what extent one of the main results of [21] still holds.
Let H be a Hilbert space and T : H → H a bounded operator. Recall that the approximation numbers of T are defined as:
a
n(T ) = inf
rankR<n
k T − R k , n ≥ 1 , and we have:
k T k = a
1(T ) ≥ a
2(T ) ≥ · · · ≥ a
n(T ) ≥ · · ·
The operator T is compact if and only if a
n(T )
n−→
→∞0.
For d ≥ 1, we define:
( β
d−(T ) = lim inf
n→∞
a
nd(T )
1/nβ
d+(T ) = lim sup
n→∞
a
nd(T )
1/nWe have:
0 ≤ β
d−(T ) ≤ β
+d(T ) ≤ 1 , and we simply write β
d(T ) in case of equality.
It may well happen in general (consider diagonal operators) that β
−d(T ) = 0 and β
d+(T ) = 1.
When H = H
2( D ) is the Hardy space on the open unit disk D of C , and T = C
Φis a composition operator, with Φ : D → D a non-constant analytic function, we always have ([19]):
β
1−(C
Φ) > 0 , and one of the main results of [19] is the equivalence:
(1.1) β
+1(C
Φ) < 1 ⇐⇒ k Φ k
∞< 1 .
An alternative proof was given in [21], as a consequence of a so-called “spectral radius formula”, which moreover shows that:
β
1−(C
Φ) = β
+1(C
Φ) .
In [2], for d ≥ 2, it is proved that, for a bounded symmetric domain Ω ⊆ C
d, if Φ : Ω → Ω is analytic, such that Φ(Ω) has a non-void interior, and the composition operator C
Φ: H
2(Ω) → H
2(Ω) is compact, then:
β
d−(C
Φ) > 0 . On the other hand, if Ω is a product of balls, then:
k Φ k
∞< 1 = ⇒ β
+d(C
Φ) < 1 .
We do not know whether the converse holds and the purpose of this paper is to study some examples towards an answer.
The paper is organized as follows. Section 1 is this short introduction, as well as some notations and definitions on singular numbers of operators and Hardy spaces of the polydisk to follow. Section 2 contains preliminary results on weighted composition operators in one variable, which surprisingly play an important role in the study of non-weighted composition operators in two vari- ables. Section 3 studies the case of symbols with “separated” variables. Our main one variable result extends in this case. Section 4 studies the “glued case”
Φ(z
1, z
2) = φ(z
1), φ(z
1)
for which even boundedness is an issue. Here, the
Bergman space B
2( D ) enters the picture. Section 5 studies the case of “triangu- larly separated” variables. This section lets direct Hilbertian sums of weighted composition operators in one variable appear, and it contains our main result:
an example of a symbol Φ satisfying k Φ k
∞= 1 and yet β
2+(C
Φ) < 1. The final Section 6 discusses the role of the Monge-Ampère pluricapacity, which is a multivariate extension of the Green capacity in the disk. Even though, as evidenced by our counterexample of Section 5, this capacity will not capture all the behavior of the parameter β
m(C
Φ), some partial results are obtained, relying on theorems of S. Nivoche and V. Zakharyuta.
1.2 Notation
We denote by D the open unit disk of the complex plane and by T its boundary, the 1-dimensional torus.
The Hardy space H
2( D
d) is the space of holomorphic functions f : D
d→ C whose boundary values f
∗on T
dare square-integrable with respect to the Haar measure m
dof T
d, and normed with:
k f k
22= k f k
2H2(Dd)= Z
Td
| f
∗(ξ
1, . . . , ξ
d) |
2dm
d(ξ
1, . . . , ξ
d) . If f (z
1, . . . , z
d) = P
α1,...,αd≥0
a
α1,...,αdz
1α1· · · z
αdd, then:
k f k
22= X
α1,...,αd≥0
| a
α1,...,αd|
2.
We say that an analytic map Φ : D
d→ D
dis a symbol if its associated composition operator C
Φ: H
2( D
d) → H
2( D
d), defined by C
Φ(f ) = f ◦ Φ, is bounded.
We say that Φ is truly d-dimensional if Φ( D
d) has a non-void interior.
We will make use of two kinds of symbols defined on D . The lens map λ
θ: D → D is defined, for θ ∈ (0, 1), by:
(1.2) λ
θ(z) = (1 + z)
θ− (1 − z)
θ(1 + z)
θ+ (1 − z)
θ(see [26], p. 27, or [16], for more information), and corresponds to u 7→ u
θin the right half-plane.
The cusp map χ : D → D was first defined in [15] and in a slightly different form in [20]; we actually use here the modified form introduced in [17], and then used in [18]. We first define:
χ
0(z) =
z − i iz − 1
1/2− i
− i z − i iz − 1
1/2+ 1
;
we note that χ
0(1) = 0, χ
0( − 1) = 1, χ
0(i) = − i, χ
0( − i) = i, and χ
0(0) = √ 2 − 1.
Then we set:
χ
1(z) = log χ
0(z), χ
2(z) = − 2
π χ
1(z) + 1, χ
3(z) = a χ
2(z) , and finally:
χ(z) = 1 − χ
3(z) , where:
(1.3) a = 1 − 2
π log( √
2 − 1) ∈ (1, 2)
is chosen in order that χ(0) = 0. The image Ω of the (univalent) cusp map is formed by the intersection of the inside of the disk D 1 −
a2,
a2and the outside of the two disks D 1 +
ia2,
a2and D 1 −
ia2,
a2·
Besides the approximation numbers, we need other singular numbers for an operator S : X → Y between Banach spaces X and Y .
The Bernstein numbers b
n(S), n ≥ 1, which are defined by:
(1.4) b
n(S) = sup
E
x
min
∈SEk Sx k ,
where the supremum is taken over all n-dimensional subspaces of X and S
Eis the unit sphere of E.
The Gelfand numbers c
n(S), n ≥ 1, which are defined by:
(1.5) c
n(S) = inf {k S
|Mk ; codim M < n } . The Kolmogorov numbers d
n(S), n ≥ 1, which are defined by:
(1.6) d
n(S) = inf
dimE<n
sup
x∈BX
dist (Sx, E)
.
Pietsch showed that all s-numbers on Hilbert spaces are equal (see [24], § 2, Corollary, or [25], Theorem 11.3.4); hence:
(1.7) a
n(S) = b
n(S) = c
n(S ) = d
n(S) .
We denote m the normalized Lebesgue measure on T = ∂ D . If ϕ: D → D , m
ϕis the pull-back measure on D defined by m
ϕ(E) = m[ϕ
∗−1(E)], where ϕ
∗stands for the non-tangential boundary values of ϕ.
The notation A . B means that A ≤ C B for some positive constant C and
we write A ≈ B if we have both A . B and B . A.
2 Preliminary results on weighted composition operators on H 2 ( D )
We see in this section that the presence of a “rapidly decaying” weight allows simpler estimates for the approximation numbers of a corresponding weighted composition operator. Such a study, but a bit different, is made in [14].
Let ϕ: D → D a non-constant analytic self-map in the disk algebra A( D ) such that, for some constant C > 1 and for all z ∈ D :
(2.1) ϕ(1) = 1 , | 1 − ϕ(z) | ≤ 1 , | 1 − ϕ(z) | ≤ C (1 − | ϕ(z) | )
as well as ϕ(z) 6 = 1 for z 6 = 1. We can take for example ϕ =
1+λ2θwhere λ
θis the lens map with parameter θ.
Let w ∈ H
∞and let T be the weighted composition operator T = M
w◦ϕC
ϕ: H
2→ H
2.
Note that M
w◦ϕC
ϕ= C
ϕM
w. We first show that:
Theorem 2.1. Let T = M
w◦ϕC
ϕ: H
2→ H
2be as above and let B be a Blaschke product with length < N . Then, with the implied constant depending only on the number C in (2.1) (and of ϕ):
a
N(T ) . sup
|z−1|≤1, z∈ϕ(D)
| B(z) | | w(z) | .
Proof. The following preliminary observation (see also [16], p. 809), in which we denote by S(ξ, h) = { z ∈ D ; | z − ξ | ≤ h } the Carleson window with center ξ ∈ T and size h, and by K
ϕthe support of the pull-back measure m
ϕ, will be useful.
(2.2) u ∈ S(ξ, h) ∩ K
ϕ= ⇒ u ∈ S(1, Ch) ∩ K
ϕ. Indeed, if | u − ξ | ≤ h and u ∈ K
ϕ, (2.1) implies:
1 − | u | ≤ | u − ξ | ≤ h and | u − 1 | ≤ C(1 − | u | ) ≤ Ch .
Set E = BH
2. This is a subspace of codimension < N. If f = Bg ∈ E, with k g k = k f k (isometric division by B in BH
2), we have T f = (wBg) ◦ ϕ, whence:
k T (f ) k
2= Z
D
| B |
2| w |
2| g |
2dm
ϕ,
implying k T (f ) k
2≤ k f k
2k J k
2where J : H
2→ L
2(σ) is the natural embedding and where
σ = | B |
2| w |
2dm
ϕ.
Now, Carleson’s embedding theorem for the measure σ and (2.2) show that (the implied constants being absolute):
k J k
2. sup
ξ∈T,0<h<1
1 h
Z
S(ξ,h)∩Kϕ
| B |
2| w |
2dm
ϕ. sup
0<h<1
1 h
Z
S(1,Ch)∩Kϕ
| B |
2| w |
2dm
ϕ.
sup
|z−1|≤1, z∈ϕ(D)
| B(z) |
2| w(z) |
2sup
0<h<1
1 h
Z
S(1,Ch)∩Kϕ
dm
ϕ. sup
|z−1|≤1, z∈ϕ(D)
| B(z) |
2| w(z) |
2,
since m
ϕis a Carleson measure for H
2and where we used that, according to (2.1):
K
ϕ⊆ ϕ( D ) ⊆ { z ∈ D ; | z − 1 | ≤ 1 } .
This ends the proof of Theorem 2.1 with help of the equality of a
N(T ) with the Gelfand number c
N(T ) recalled in (1.7).
In order to specialize efficiently the general Theorem 2.1, we recall the fol- lowing simple Lemma 2.3 of [16], where:
(2.3) ρ(a, b) =
a − b 1 − ¯ ab
, a, b ∈ D ,
is the pseudo-hyperbolic distance:
Lemma 2.2 ([16]). Let a, b ∈ D such that | a − b | ≤ L min(1 − | a | , 1 − | b | ). Then:
ρ(a, b) ≤ L
√ L
2+ 1 =: κ < 1 . We can now state:
Theorem 2.3. Assume that ϕ is as in (2.1) and that the weight w satisfies, for some parameters 0 < θ ≤ 1 and R > 0:
| w(z) | ≤ exp
− R
| 1 − z |
θ, ∀ z ∈ D with R e z ≥ 0 .
Then, the approximation numbers of T = M
w◦ϕC
ϕsatisfy:
a
nm+1(T ) . max
exp( − an), exp( − R 2
mθ) , for all integers n, m ≥ 1, where a = log[ √
16C
2+ 1/(4C)] > 0 and C is as in
(2.1).
Proof. Let p
l= 1 − 2
−l, 0 ≤ l < m and let B be the Blaschke product:
B(z) = Y
0≤l<m
z − p
l1 − p
lz
n.
Let z ∈ K
ϕ∩ D so that 0 < | z − 1 | ≤ 1. Let l be the non-negative integer such that 2
−l−1< | z − 1 | ≤ 2
−l. We separate two cases:
Case 1: l ≥ m. Then, the weight does the job. Indeed, majorizing | B(z) | by 1 and using the assumption on w, we get:
| B(z) |
2| w(z) |
2≤ | w(z) |
2≤ exp
− 2R
| 1 − z |
θ≤ exp( − 2R 2
lθ) ≤ exp( − 2R 2
mθ) .
Case 2: l < m. Then, the Blaschke product does the job. Indeed, majorize | w(z) | by 1 and estimate | B(z)) | more accurately with help of Lemma 2.2; we observe that
| z − p
l| ≤ | z − 1 | + 1 − p
l≤ 2 × 2
−l= 2(1 − p
l) ≤ 4C(1 − p
l) and then, since z ∈ K
ϕ, we can write with C ≥ 1 as in (2.1):
1 − | z | ≥ 1
C | 1 − z | ≥ 1
2C 2
−l≥ 1
4C | z − p
l| ,
so that the assumptions of Lemma 2.2 are verified with L = 4C, giving:
ρ(z, p
l) ≤ 4C
√ 16C
2+ 1 = exp( − a) < 1 .
Hence, by definition, since l < m:
| B(z) | ≤ [ρ(z, p
l)]
n≤ exp( − an) .
Putting both cases together, and observing that our Blaschke product has length nm < nm + 1, we get the result by applying Theorem 2.1 with N = nm + 1.
2.1 Some remarks
1. Twisting a composition operator by a weight may improve the compact- ness of this composition operator, or even may make this weighted composition operator compact though the non-weighted was not (see [8] or [14]). However, this is not possible for all symbols, as seen in the following proposition.
Proposition 2.4. Let w ∈ H
∞. If ϕ is inner, or more generally if | ϕ | = 1 on
a subset of T of positive measure, then M
wC
ϕis never compact (unless w ≡ 0).
Proof. Indeed, suppose T = M
wC
ϕcompact. Since (z
n)
nconverges weakly to 0 in H
2and since T (z
n) = w ϕ
n, we should have, since | ϕ | = 1 on E, with m(E) > 0:
Z
E
| w |
2dm = Z
E
| w |
2| ϕ |
2ndm ≤ Z
T
| w |
2| ϕ |
2ndm = k T (z
n) k
2n−→
→∞
0 , but this would imply that w is null a.e. on E and hence w ≡ 0 (see [7], Theorem 2.2), which was excluded.
Note that É. Amar and A. Lederer proved in [1] that | ϕ | = 1 on a set of positive measure if and only if ϕ is an exposed point of of the unit ball of H
∞; hence the following proposition can be viewed as the (almost) opposite case.
Proposition 2.5. Let ϕ: D → D such that k ϕ k
∞= 1. Assume that:
Z
T
log(1 − | ϕ | ) dm > −∞
(meaning that ϕ is not an extreme point of the unit ball of H
∞: see [7], Theo- rem 7.9). Then, if w is an outer function such that | w | = 1 − | ϕ | , the weighted composition operator T = M
wC
ϕis Hilbert-Schmidt.
Proof. We have:
∞
X
n=0
k T (z
n) k
2=
∞
X
n=0
Z
T
(1 − | ϕ | )
2| ϕ |
2ndm = Z
T
1 − | ϕ |
1 + | ϕ | dm < + ∞ ,
and T is Hilbert-Schmidt, as claimed.
2. In [14], Theorem 2.5, it is proved that we always have, for some constants δ, ρ > 0:
(2.4) a
n(M
wC
ϕ) ≥ δ ρ
n, n = 1, 2, . . .
(if w 6≡ 0). We give here an alternative proof, based on a result of Gunatillake ([9]), this result holding in a wider context.
Theorem 2.6 (Gunatillake). Let T = M
wC
ϕbe a compact weighted compo- sition operator on H
2and assume that ϕ has a fixed point a ∈ D . Then the spectrum of T is the set:
σ(T ) = { 0, w(a), w(a) ϕ
′(a), w(a) [ϕ
′(a)]
2, . . . , w(a) [ϕ
′(a)]
n, . . . }
Proof of (2.4). First observe that, in view of Proposition 2.4, ϕ cannot be an
automorphism of D so that the point a is the Denjoy-Wolff point of ϕ and is
attractive. Theorem 2.6 is interesting only when w(a) ϕ
′(a) 6 = 0.
Now, we can give a new proof Theorem 2.5 of [14] as follows. Let a ∈ D be such that w(a) ϕ
′(a) 6 = 0 (H( D ) is a division ring and ϕ
′6≡ 0, w 6≡ 0). Let b = ϕ(a) and τ ∈ Aut D with τ(b) = a. We set:
ψ = τ ◦ ϕ and S = M
wC
ψ= T C
τ. This operator S is compact because T is.
Since ψ(a) = a and ψ
′(a) = τ
′(b)ϕ
′(a) 6 = 0, Theorem 2.6 says that the non-zero eigenvalues of S , arranged in non-increasing order, are the numbers λ
n= w(a) [ψ
′(a)]
n−1, n ≥ 1. As a consequence of Weyl’s inequalities, we know that:
a
1(S) a
n(S) ≥ | λ
2n|
2≥ δ ρ
n, with:
δ = | w(a) |
2> 0 and ρ = | ψ
′(a) |
4> 0 .
To finish, it is enough to observe that a
n(S) ≤ a
n(T ) k C
τk by the ideal property of approximation numbers.
3 The splitted case
Theorem 3.1. Let Φ = (φ, ψ) : D
d→ D
dbe a truly d-dimensional symbol with φ: D → D depending only on z
1and ψ : D
d−1→ D
d−1only on z
2, . . . , z
d, i.e.
Φ(z
1, z
2, . . . , z
d) = φ(z
1), ψ(z
2, . . . , z
d)
. Then, whatever ψ behaves:
k φ k
∞= 1 = ⇒ β
d(C
Φ) = 1 .
Proof. The proof is based on the following simple lemma, certainly well-known.
Lemma 3.2. Let S : H
1→ H
1and T : H
2→ H
2be two compact linear oper- ators, where H
1and H
2are Hilbert spaces. Let S ⊗ T be their tensor product, acting on the tensor product H
1⊗ H
2. Then:
a
mn(S ⊗ T ) ≥ a
m(S) a
n(T ) for all positive integers m, n.
We postpone the proof of the lemma and show how to conclude.
We can assume C
Φto be compact, so that C
φis compact as well. Since k φ k
∞= 1, we have, thanks to (1.1) :
a
m(C
φ) ≥ e
−m εmwith ε
mm−→
→∞
0 .
Replacing ε
mby δ
m:= sup
p≥mε
p, we can assume that (ε
m)
mis non-increasing.
Moreover,
m ε
m→ ∞
since C
φis compact and hence a
m(C
φ)
m−→
→∞0. We next observe that, due to the separation of variables in the definition of φ and ψ, we can write:
(3.1) C
Φ= C
φ⊗ C
ψ.
Indeed, write z = (z
1, w) with z
1∈ D and w ∈ D
d−1. If f ∈ H
2( D ) and g ∈ H
2( D
d−1), we see that:
C
Φ(f ⊗ g)(z) = (f ⊗ g) φ(z
1), ψ(w)
= f φ(z
1)
g ψ(w)
= [C
φf (z
1)] [C
ψg(w)] = (C
φf ⊗ C
ψg)(z) .
Since tensor products f ⊗ g generate H
2( D
d) = H
2( D ) ⊗ H
2(D
d−1), this proves (3.1).
Let now m be a large positive integer. Set ([ . ] stands for the integer part):
(3.2) n
m= [mε
m]
d−1and N
m= m n
m.
From what we know in dimension d − 1 (see [2], Theorem 3.1) and from the preceding, we can write (observe that ψ has to be truly (d − 1)-dimensional since Φ is truly d-dimensional):
a
m(C
φ) ≥ exp( − m ε
m) and a
n(C
ψ) ≥ a exp( − C n
1/(d−1)) ,
for some positive constant C, which will be allowed to vary from one formula to another. Lemma 3.2 implies:
a
Nm(C
Φ) ≥ a exp[ − C (m ε
m+ n
m1/(d−1))] . Since n
m. (mε
m)
d−1, we get:
a
Nm(C
Φ) ≥ a exp( − C m ε
m) . Observe that N
m= m n
m∼ m
dε
md−1and so N
m1/d∼ m ε
m1−1/d. As a consequence:
a
Nm(C
Φ) ≥ a exp( − C m ε
m) = a exp
− (C ε
m1/d) (m ε
m1−1/d)
≥ a exp( − η
mN
m1/d) with η
m:= C ε
m1/d.
Now, for N > N
1, let m be the smallest integer satisfying N
m≥ N (so that N
m−1< N ≤ N
m), and set δ
N= η
m. We have lim
N→∞δ
N= 0. Next, we note that lim
m→∞N
m/N
m−1= 1, because N
m≥ N
m−1and:
N
mN
m−1≤ m m − 1
m ε
m+ 1 (m − 1) ε
m−1 d−1∼ ε
mε
m−1 d−1≤ 1 . Finally, if N is an arbitrary integer and N
m−1< N ≤ N
m, we obtain:
a
N(C
Φ) ≥ a
Nm(C
Φ) ≥ a exp( − η
mN
m1/d) ≥ a exp( − C δ
NN
1/d) , since we observed that lim
m→∞N
m/N
m−1= 1.
This amounts to say that β
d(C
Φ) = 1.
Proof of Lemma 3.2. It is rather formal. Start from the Schmidt decomposi- tions of S and T respectively (recall that Hilbert spaces, the approximation numbers are equal to the singular ones):
S =
∞
X
m=1
a
m(S) u
m⊙ v
m, T =
∞
X
n=1
a
n(T ) u
′n⊙ v
n′,
where (u
m), (v
m) are two orthonormal sequences of H
1, (u
′n), (v
n′) two orthonor- mal sequences of H
2, and u
m⊙ v
mand u
′n⊙ v
′ndenote the rank one operators defined by (u
m⊙ v
m)(x) = h x, v
mi u
m, x ∈ H
1, and (u
′n⊙ v
n′)(x) = h x, v
′ni u
′n, x ∈ H
2.
We clearly have:
(u
m⊙ v
m) ⊗ (u
′n⊙ v
n′) = (u
m⊗ u
′n) ⊙ (v
m⊗ v
′n) ,
so that the Schmidt decomposition of S ⊗ T is (with SOT-convergence):
S ⊗ T = X
m,n≥1
a
m(S) a
n(T ) (u
m⊗ u
′n) ⊙ (v
m⊗ v
′n) ,
since the two sequences (u
m⊗ u
′n)
m,nand (v
m⊗ v
′n)
m,nare orthonormal: for instance, we have by definition:
h u
m1⊗ u
′n1, u
m2⊗ u
′n2i = h u
m1, u
m2, i h u
′n1, u
′n2i .
This shows that the singular values of S ⊗ T are the non-increasing rear- rangement of the positive numbers a
m(S) a
n(T ) and ends the proof of the lemma: the mn numbers a
k(S) a
l(T ), for 1 ≤ k ≤ m, 1 ≤ l ≤ n all satisfy a
k(S) a
l(T ) ≥ a
m(S) a
n(T ), so that a
mn(S ⊗ T ) ≥ a
m(S) a
n(T ).
4 The glued case
Here we consider symbols of the form:
(4.1) Φ(z
1, z
2) = φ(z
1), φ(z
1) , where φ: D → D is a non-constant analytic map.
Note that such maps Φ are not truly 2-dimensional.
4.1 Preliminary
We begin by remarking the following fact.
Let B
2( D ) be the Bergman space of all analytic functions f : D → C such that:
k f k
2B2:=
Z
D
| f (z) |
2dA(z) < ∞ ,
where dA is the normalized area measure on D .
Proposition 4.1. Assume that the composition operator C
φmaps boundedly B
2( D ) into H
2( D ). Then C
Φ: H
2( D
2) → H
2( D
2), defined by (4.1), is bounded.
Proof. If we write f ∈ H
2( D
2) as:
f (z
1, z
2) = X
j,k≥0
c
j,kz
j1z
k2, with X
j,k≥0
| c
j,k|
2= k f k
2H2,
we formally (or assuming that f is a polynomial) have:
[C
Φf ](z
1, z
2) = X
j,k≥0
c
j,k[φ(z
1)]
j[φ(z
1)]
k=
∞
X
n=0
X
j+k=n
c
j,k[φ(z
1)]
n. Hence, if we set g(z) = P
∞n=0
P
j+k=n
c
j,kz
n, we get:
[C
Φ(f )](z
1, z
2) = [C
φ(g)](z
1) , so that, by integrating:
k C
Φ(f ) k
H2(D2)= k C
φ(g) k
H2(D). By hypothesis, there is a positive constant M such that:
k C
φ(g) k
H2(D)≤ M k g k
B2(D). But, by the Cauchy-Schwarz inequality:
k g k
2B2(D)=
∞
X
n=0
1 n + 1
X
j+k=n
c
j,k2
≤
∞
X
n=0
X
j+k=n
| c
j,k|
2= X
j,k≥0
| c
j,k|
2= k f k
2H2(D2),
and we obtain k C
Φ(f ) k
H2(D2)≤ M k f k
H2(D2).
4.2 Lens maps
Let λ
θbe a lens map of parameter θ, 0 < θ < 1. We consider Φ
θ: D
2→ D
2defined by:
(4.2) Φ
θ(z
1, z
2) = λ
θ(z
1), λ
θ(z
1) . We have the following result.
Theorem 4.2. The composition operator C
Φθ: H
2( D
2) → H
2( D
2) is:
1) not bounded for θ > 1/2;
2) bounded, but not compact for θ = 1/2;
3) compact, and even Hilbert-Schmidt, for 0 < θ < 1/2.
Proof. The reproducing kernel of H
2( D
2) is, for (a, b) ∈ D
2: (4.3) K
a,b(z
1, z
2) = 1
1 − ¯ az
11 1 − ¯ bz
2, (z
1, z
2) ∈ D
2, and:
k K
a,bk
2= 1
(1 − | a |
2)(1 − | b |
2) ·
1) If C
Φθwere bounded, we should have, for some M < ∞ : k C
Φ∗θ(K
a,b) k
H2≤ M k K
a,bk
H2, for all a, b ∈ D . Since C
Φ∗θ(K
a,b) = K
Φθ(a,b)= K
λθ(a),λθ(a), we would get, with b = 0:
1 1 − | λ
θ(a) |
2 2≤ M
21 1 − | a |
2;
but this is not possible for θ > 1/2, since 1 − | λ
θ(a) |
2≈ 1 − | λ
θ(a) | ∼ (1 − a)
θwhen a goes to 1, with 0 < a < 1.
For 2) and 3), let us consider the pull-back measure m
θof the normalized Lebesgue measure on T = ∂ D by λ
θ. It is easy to see that:
(4.4) sup
ξ∈T
m
θ[D(ξ, h) ∩ D )] = m
θ[D(1, h) ∩ D ] ≈ h
1/θ.
In particular, for θ ≤ 1/2, m
θis a 2-Carleson measure, and hence (see [15], The- orem 2.1, for example) the canonical injection j : B
2( D ) → L
2(m
θ) is bounded, meaning that, for some positive constant M < ∞ :
Z
D
| f (z) |
2dm
θ(z) ≤ M
2k f k
2B2.
Since Z
D
| f (z) |
2dm
θ(z) = Z
T
| f [λ
θ(u)] |
2dm(u) = k C
λθ(f ) k
2H2, we get that C
λθmaps boundedly B
2( D ) into H
2( D ).
It follows from Proposition 4.1 that C
Φθ: H
2( D
2) → H
2( D
2) is bounded.
However, C
Φ1/2is not compact since C
Φ∗1/2(K
a,b)/ k K
a,bk does not converge to 0 as a, b → 1, by the calculations made in 1).
For 3), let e
j,k(z
1, z
2) = z
1jz
2k, j, k ≥ 0, be the canonical orthonormal basis of H
2( D
2); we have [C
φθ(e
j,k)](z
1, z
2) = [λ
θ(z
1)]
j+k. Hence:
X
j,k≥0
k C
φθ(e
j,k) k
2H2(D2)≤
∞
X
n=0
(2n + 1) Z
T
| λ
θ|
2ndm ≤ Z
T
2
(1 − | λ
θ|
2)
2dm .
Since, by Lemma 4.3 below, 1 − | λ
θ(e
it) |
2& | 1 − e
it|
θ≥ t
θfor | t | ≤ π/2, we get:
X
j,k≥0
k C
φθ(e
j,k) k
2H2(D2). Z
π/20
dt
t
2θ< ∞ ,
since θ < 1/2. Therefore C
φθis Hilbert-Schmidt for θ < 1/2.
For sake of completeness, we recall the following elementary fact (see [26], p. 28, or also [16], Lemma 2.5)).
Lemma 4.3. With δ = cos(θπ/2), we have, for | z | ≤ 1 and R e z ≥ 0:
1 − | λ
θ(z) |
2≥ δ
2 | 1 − z |
θ. Proof. We can write:
λ
θ(z) = 1 − w
1 + w with w = 1 − z
1 + z
θand | w | ≤ 1 . Then:
R e w ≥ δ | w | ≥ δ
2 | 1 − z |
θ. Hence:
1 − | λ
θ(z) |
2= 4 R e w
| 1 + w |
2≥ δ | w | ≥ δ
2 | 1 − z |
θ, as announced
We now improve the result 3) of Theorem 4.2 by estimating the approxima- tion numbers of C
Φθand get that C
Φθis in all Schatten classes of H
2( D
2) when θ < 1/2.
Theorem 4.4. For 0 < θ < 1/2, there exists b = b
θ> 0 such that:
(4.5) a
n(C
Φθ) . e
−b√n.
In particular β
2+(C
Φθ) ≤ e
−b< 1, though k Φ
θk
∞= 1, and even Φ
θ( T
2) ∩ T
26 = ∅ . Proof. Proposition 4.1 (and its proof) can be rephrased in the following way: if C
φmaps boundedly B
2( D ) into H
2( D ), then, we have the following factoriza- tion:
(4.6) C
Φ: H
2( D
2) −→
JB
2( D ) −−→
CφH
2( D ) −→
IH
2( D
2) ,
where I : H
2( D ) → H
2( D
2) is the canonical injection given by (If )(z
1, z
2) = f (z
1) for f ∈ H
2( D ), and J : H
2( D
2) → B
2( D ) is the contractive map defined by:
(Jf )(z) =
∞
X
n=0
X
j+k=n
c
j,kz
n, for f ∈ H
2( D
2) with f (z
1, z
2) = P
j,k≥0
c
j,kz
1jz
2k.
In the proof of Theorem 4.2, we have seen that, for 0 < θ ≤ 1/2, the composition operator C
λθis bounded from B
2( D ) into H
2( D ); we get hence the factorization:
C
Φθ: H
2( D
2) −→
JB
2( D ) −−−→
CλθH
2( D ) −→
IH
2( D
2) ,
Now, the lens maps have a semi-group property:
(4.7) λ
θ1θ2= λ
θ1λ
θ2, giving C
λθ1θ2= C
λθ1◦ C
λθ2.
For 0 < θ < 1/2, we therefore can write C
λθ= C
λ2θ◦ C
λ1/2(note that 2θ < 1, so C
λ2θ: H
2( D ) → H
2( D ) is bounded), and we get:
C
Φθ= I C
λ2θC
λ1/2J . Consequently:
a
n(C
Φθ) ≤ k I k k J k k C
λ1/2k
B2→H2a
n(C
λ2θ) .
Now, we know ([16], Theorem 2.1) that a
n(C
λ2θ) . e
−b√n, so we get that a
n(C
Φθ) . e
−b√n.
Remark. In [2], we saw that for a truly 2-dimensional symbol Φ, we have β
2−(C
φ) > 0. Here the symbol Φ
θis not truly 2-dimensional, but we never- theless have β
2(C
Φθ) > 0. In fact, let E = { f ∈ H
2( D
2) ;
∂z∂f2≡ 0 } ; E is isometrically isomorphic to H
2( D ) and the restriction of C
Φθto E behaves as the 1-dimensional composition operator C
λθ: H
2( D ) → H
2( D ); hence ([19], Proposition 6.3):
e
−b0√n. a
n(C
λθ) = a
n(C
Φθ|E) ≤ a
n(C
Φθ) ,
and β
2−(C
Φθ) ≥ e
−b0> 0.
5 Triangularly separated variables
In this section, we consider symbols of the form:
(5.1) Φ(z
1, z
2) = φ(z
1), ψ(z
1) z
2, where φ, ψ : D → D are non-constant analytic maps.
Such maps Φ are truly 2-dimensional.
More generally, if h ∈ H
∞, with h(0) = 0 and k h k
∞≤ 1, has its powers h
k, k ≥ 0, orthogonal in H
2(for convenience, we shall say that h is a Rudin function), we can consider:
(5.2) Φ(z
1, z
2) = φ(z
1), ψ(z
1) h(z
2)
For such h we can take for example an inner function vanishing at the origin,
but there are other such functions, as shown by C. Bishop:
Theorem (Bishop [4]). The function h is a Rudin function if and only if the pull-back measure µ = µ
his radial and Jensen, i.e for every Borel set E:
µ(e
iθE) = µ(E) and Z
D
log(1/ | z | ) dµ(z) < ∞ .
Conversely, for every probability measure µ supported by D , which is radial and Jensen, there exists h in the unit ball of H
∞, with h(0) = 0, such that µ = µ
h.
If we take for µ the Lebesgue measure of T , we get an inner function. But, as remarked in [4], we can take for µ the Lebesgue measure on the union T ∪ (1/2) T , normalized in order that µ(T ) = µ (1/2) T
= 1/2. Then the corresponding h is not inner since | h | = 1/2 on a subset of T of positive measure. He also showed that h(z)/z may be a non-constant outer function. Also, P. Bourdon ([6]) showed that the powers of h are orthogonal if and only if its Nevanlinna counting function is almost everywhere constant on each circle centered on the origin.
5.1 General facts
We first observe that if f ∈ H
2( D
2) and:
f (z
1, z
2) = X
j,k≥0
c
j,kz
j1z
k2,
then we can write:
f (z
1, z
2) = X
k≥0
f
k(z
1)
z
2kwith:
f
k(z
1) = X
j≥0
c
j,kz
j1, and:
k f k
2H2(D2)= X
j,k≥0
| c
j,k|
2= X
k≥0
k f
kk
2H2(D).
That means that we have an isometric isomorphism:
J : H
2( D
2) −→
∞
M
k=0
H
2( D ) , defined by Jf = (f
k)
k≥0.
Now, for symbols Φ as in (5.1), we have:
(C
Φf )(z
1, z
2) = X
j,k≥0
c
j,k[φ(z
1)]
j[ψ(z
1)]
kz
2k,
so that J C
ΦJ
−1appears as the operator L
k
M
ψkC
φon L
k
H
2( D ), where M
ψkis the multiplication operator by ψ
k:
[(M
ψkC
φ)f
k](z
1) = [ψ(z
1)]
k[(f
k◦ φ)(z
1)] . When Φ is as in (5.2), we have:
(C
Φf )(z
1, z
2) = X
j,k≥0
c
j,k[φ(z
1)]
j[ψ(z
1)]
k[h(z
2)]
k,
with:
k C
Φf k
2≤
∞
X
k=0
k T
kf
kk
2and:
T
k= M
ψkC
φ;
hence J C
ΦJ
−1appears as pointwise dominated by the operator T = ⊕
kT
kon L
k
H
2( D ). This implies a factorization C
Φ= AT with k A k ≤ 1, so that a
n(C
Φ) ≤ a
n(T ) for all n ≥ 1.
We recall the following elementary fact.
Lemma 5.1. Let (H
k)
k≥0be a sequence of Hilbert spaces and T
k: H
k→ H
kbe bounded operators. Let H = L
∞k=0
H
kand T : H → H defined by T x = (T
kx
k)
k. Then:
1) T is bounded on H if and only if sup
kk T
kk < ∞ ;
2) T is compact on H if and only if each T
kis compact and k T
kk −→
k→∞
0.
Going back to the symbols of the form (5.1), we have k M
ψkk ≤ k ψ
kk
∞≤ 1, since k ψ k
∞≤ 1; hence k M
ψkC
φk ≤ k C
φk and the operator (M
ψkC
φ)
kis bounded on L
k
H
2( D ). Therefore C
Φis bounded on H
2( D
2).
For approximation numbers, we have the following two facts.
Lemma 5.2. Let T
k: H
k→ H
kbe bounded linear operators between Hilbert spaces H
k, k ≥ 0. Let H = L
k
H
kand T = (T
k)
k: H → H , assumed to be compact. Then, for every n
1, . . . , n
K≥ 1, and 0 ≤ m
1< · · · < m
K, K ≥ 1, we have:
(5.3) a
N(T ) ≥ inf
1≤k≤K
a
nk(T
mk) , where N = n
1+ · · · + n
K.
Proof. We use the Bernstein numbers b
n(see (1.4)), which are equal to the approximation numbers (see (1.7)).
For k = 1, . . . , K, there is an n
k-dimensional subspace E
kof H
mksuch that:
b
nk(T
mk) ≤ k T
mkx k , for all x ∈ S
Ek.
Then E = L
Kk=1
E
kis an N-dimensional subspace of H and for every x = (x
1, x
2, . . .) ∈ E, we have:
k T x k
2= X
k≤K
k T
mkx
mkk
2≥ X
k≤K
[b
nk(T
mk)]
2k x
mkk
2≥ inf
k≤K
[b
nk(T
mk)]
2X
k≤K
k x
mkk
2= inf
k≤K
[b
nk(T
mk)]
2k x k
2; hence b
N(T ) ≥ inf
k≤Kb
nk(T
mk), and we get the announced result.
Lemma 5.3. Let T = L
∞k=0
T
kacting on a Hilbertian sum H = L
∞k=0
H
k. Let n
0, . . . , n
Kbe positive integers and N = n
0+ · · · + n
K− K. Then, the approximation numbers of T satisfy:
(5.4) a
N(T ) ≤ max
0≤
max
k≤Ka
nk(T
k), sup
k>K
k T
kk .
Proof. Denote by S the right-hand side of (5.4). Let R
k, 0 ≤ k ≤ K be operators on H
kof respective rank < n
ksuch that k T
k− R
kk = a
nk(T
k) and let R = L
Kk=0
R
k. Then R is an operator of rank ≤ n
0+ · · · + n
K− K − 1 < N . If f = P
∞k=0
f
k∈ H , we see that:
k T f − Rf k
2=
K
X
k=0
k T
kf
k− R
kf
kk
2+ X
k>K
k T
kf
kk
2≤
K
X
k=0
a
nk(T
k)
2k f
kk
2+ X
k>K
k T
kf
kk
2≤ S
2∞
X
k=0
k f
kk
2= S
2k f k
2, hence the result.
We give now two corollaries of Lemma 5.3.
Example 1. We first use lens maps. We get:
Theorem 5.4. Let λ
θthe lens map of parameter θ and let ψ : D → D such that k ψ k
∞:= c < 1 and h a Rudin function. We consider:
Φ(z
1, z
2) = λ
θ(z
1), ψ(z
1) h(z
2) . Then, for some positive constant β, we have, for all N ≥ 1:
(5.5) a
N(C
Φ) . e
−β N1/3.
Proof. Let T
k= M
ψkC
λθ. We have k T
kk ≤ c
k, so sup
k>Kk T
kk ≤ c
K. On the other hand, we have a
n(T
k) ≤ c
ka
n(C
λθ) ≤ a
n(C
λθ) . e
−βθ√n([16], Theo- rem 2.1). Taking n
0= n
1= · · · = n
K= K
2in Lemma 5.3, we get:
0≤
max
k≤Ka
nk(T
k) . e
−βθK.
Since n
0+ · · · + n
K− K ≈ K
3, we obtain a
K3. e
−βK, which gives the claimed result, by taking β = max β
θ, log(1/c)
.
Example 2. We consider the cusp map χ. We have:
Theorem 5.5. Let χ be the cusp map, h a Rudin function, and ψ in the unit ball of H
∞, with k ψ k
∞:= c < 1. Let:
Φ(z
1, z
2) = χ(z
1), ψ(z
1) h(z
2) . Then, for positive constant β , we have, for all N ≥ 1:
a
N(C
Φ) . e
−β√N /√logN.
Proof. Let T
k= M
ψkC
χ. As above, we have sup
k>Kk T
kk ≤ c
K. For the cusp map, we have a
n(C
χ) . e
−αn/logn([20], Theorem 4.3); hence a
n(T
k) . e
−αn/logn. We take n
0= n
1= · · · = n
K= K [log K] (where [log K] is the integer part of log K). Since n
0+ · · · + n
K≈ K
2[log K], we get, for another α > 0:
a
K2[logK](C
Φ) . e
−αK, which reads: a
N(C
Φ) . e
−β√
N/logN
, as claimed.
5.2 Lower bounds
In this subsection, we give lower bounds for approximation numbers of com- position operators on H
2of the bidisk, attached to a symbol Φ of the previous form Φ(z
1, z
2) = φ(z
1), ψ(z
1) h(z
2) where h is a Rudin function. The sharp- ness of those estimates will be discussed in the next subsection. We first need some lemmas in dimension one.
Lemma 5.6. Let u, v : D → D be two non-constant analytic self-maps and T = M
vC
u: H
2( D ) → H
2( D ) be the associated weighted composition operator.
For 0 < r < 1, we set A = u(r D ) and Γ = exp − 1/Cap (A)
. Then, for 0 < δ ≤ inf
|z|=r| v(z) | , we have:
(5.6) a
n(T ) & √
1 − r δ Γ
n.
In this lemma, Cap (A) denotes the Green capacity of the compact subset A ⊆ D (see [21], § 2.3 for the definition).
For the proof, we need the following result ([27], Theorem 7, p. 353).
Theorem 5.7 (Widom) . Let A be a compact subset of D and C (A) be the space of continuous functions on A with its natural norm. Set:
d ˜
n(A) = inf
E
sup
f∈BH∞
dist (f, E)
,
where E runs over all (n − 1)-dimensional subspaces of C (A) and dist (f, E) = inf
h∈Ek f − h k
C(A). Then
(5.7) d ˜
n(A) ≥ α e
−n/Cap (A)for some positive constant α.
Proof of Lemma 5.6. We apply Theorem 5.7 to the compact set A = u(r D ).
Let E be an (n − 1)-dimensional subspace of H
2= H
2( D ); it can be viewed as a subspace of C (A), so, by Theorem 5.7, there exists f ∈ H
∞⊆ H
2with k f k
2≤ k f k
∞≤ 1 such that:
k f − h k
C(A)≥ α Γ
n, ∀ h ∈ E . Then:
k v (f ◦ u − h ◦ u) k
C(rT)≥ δ k (f − h) ◦ u k
C(rT)= δ k f − h k
C(A)≥ α δ Γ
n. But:
k v (f ◦ u − h ◦ u) k
C(rT)≤ 1
√ 1 − r
2k v (f ◦ u − h ◦ u) k
H2; Hence:
k T f − T h k
H2≥ α p
1 − r
2δ Γ
n≥ α √
1 − r δ Γ
n.
Since h is an arbitrary function of E, we get (B
H2being the unit ball of H
2):
dim
inf
E<nsup
f∈BH2
dist T f, T (E)
≥ α √
1 − r δ Γ
n.
But the left-hand side is equal to the Kolmogorov number d
n(T ) of T (see [21], Lemma 3.12), and, as recalled in (1.7), in Hilbert spaces, the Kolmogorov numbers are equal to the approximation numbers; hence we obtain:
(5.8) a
n(T ) ≥ α √
1 − r δ Γ
n, n = 1, 2, . . . , as announced.
The next lemma shows that some Blaschke products are far away from 0 on some circles centered at 0.
We consider a strongly interpolating sequence (z
j)
j≥1of D in the sense that, if ε
j:= 1 − | z
j| , then:
(5.9) ε
j+1≤ σ ε
jand so ε
j≤ σ
j−1ε
1, where 0 < σ < 1 is fixed. Equivalently, the sequence ( | z
j| )
j≥1is interpolating. We consider the corresponding interpolating Blaschke product:
(5.10) B(z) =
∞
Y
j=1
| z
j| z
jz
j− z 1 − z
jz ·
The following lemma is probably well-known, but we could find no satisfac-
tory reference (see yet [10] for related estimates) and provide a simple proof.
Lemma 5.8. Let (z
j)
j≥1be a strongly interpolating sequence as in (5.9) and B the associated Blaschke product (5.10).
Then there exists a sequence r
l:= 1 − ρ
lsuch that:
(5.11) C
1σ
l≤ ρ
l≤ C
2σ
l, where C
1, C
2are positive constants, and for which:
(5.12) | z | = r
l= ⇒ | B(z) | ≥ δ , where δ > 0 does not depend on l.
Proof. Let us denote by p
l, 1 ≤ p
l≤ l, the biggest integer such that ε
pl≥ σ
l−1ε
1. We separate two cases.
Case 1: ε
pl≥ 2 σ
l−1ε
1.
Then, we choose ρ
l= α σ
l−1ε
1with α fixed, 1 < α < 2. Since ρ(ξ, ζ) ≥ ρ( | ξ | , | ζ | ) for all ξ, ζ ∈ D (recall that ρ is the pseudo-hyperbolic distance on D ), we have the following lower bound for | z | = r
l:
| B(z) | =
∞
Y
j=1
ρ(z, z
j) ≥
∞
Y
j=1
ρ(r
l, | z
j| ) = Y
j≤pl
ρ(r
l, | z
j| ) × Y
j>pl
ρ(r
l, | z
j| ) := P
1× P
2,
and we estimate P
1and P
2separately.
We first observe that ρ
lε
pl≤ α σ
l−1ε
12 σ
l−1ε
1≤ α
2 , and then:
ρ
lε
j= ρ
lε
plε
plε
j≤ α 2 σ
pl−j.
The inequality ρ(1 − u, 1 − v) ≥
(u+v)|u−v|for 0 < u, v ≤ 1 now gives us:
(5.13) ρ(r
l, | z
j| ) ≥ ε
j− ρ
lε
j+ ρ
l= 1 − ρ
l/ε
j1 + ρ
l/ε
j≥ 1 − (α/2) σ
pl−j1 + (α/2) σ
pl−j, for j ≤ p
l, and:
(5.14) P
1≥
Y
∞k=0
1 − (α/2) σ
k1 + (α/2) σ
k· Similarly:
ε
pl+1ρ
l≤ σ
l−1ε
1α σ
l−1ε
1≤ 1 α
and: ε
jρ
l≤ 1
α σ
j−pl−1for j > p
l; so that:
(5.15) ρ(r
l, | z
j| ) ≥ ρ
l− ε
jρ
l+ ε
j= 1 − ε
j/ρ
l1 + ε
j/ρ
l≥ 1 − α
−1σ
j−pl−11 + α
−1σ
j−pl−1, for j > p
l,
and
(5.16) P
2≥
∞
Y
k=0
1 − α
−1σ
k1 + α
−1σ
k·
Finally, the condition of lower and upper bound for ρ
lis fulfilled by construction.
Case 2: ε
pl≤ 2 σ
l−1ε
1.
Then, we choose ρ
l= a ε
plwith σ < a < 1 fixed. Computations exactly similar to those of Case 1 give us:
(5.17) | B(z) | ≥
∞
Y
k=0
1 − a σ
k1 + a σ
k×
∞
Y
k=0
1 − a
−1σ
k1 + a
−1σ
k=: δ > 0 , for | z | = r
l. Moreover, in this case:
a σ
l−1ε
1≤ ρ
l≤ 2 a σ
l−1ε
1, and the proof is ended.
Now, we have the following estimation.
Theorem 5.9. Let φ, ψ : D → D be two non-constant analytic self-maps and Φ(z
1, z
2) = φ(z
1), ψ(z
1) h(z
2)
, where h is inner.
Let (r
l)
l≥1be an increasing sequence of positive numbers with limit 1 such that:
|z
inf
|=rl| ψ(z) | ≥ δ
l> 0 , with δ
l≤ e
−1/Cap (Al), where A
l= φ r
lD
.
Then the approximation numbers a
N(C
Φ), N ≥ 1, of the composition oper- ator C
Φ: H
2( D
2) → H
2( D
2) satisfy:
(5.18) a
N(C
Φ) & sup
l≥1
h √
1 − r
lexp − 8 √ N p
log(1/δ
l) p
log(1/Γ
li ,
where:
(5.19) Γ
l= e
−1/Cap (Al).
Proof. Since h is inner, the sequence (h
k)
k≥0is orthonormal in H
2and hence a
n(C
Φ) = a
n(T ) for all n ≥ 1, where T = L
∞k=0
T
kand T
k= M
ψkC
φ. Then Lemma 5.6 gives:
(5.20) a
n(T
k) & √
1 − r
lδ
klΓ
nlfor all n ≥ 1 and all k ≥ 0.
Let now:
(5.21) p
l=
log(1/δ
l) log(1/Γ
l)
,
where [ . ] stands for the integer part, and:
(5.22) n
k= p
lk , for k = 1, . . . , K .
By Lemma 5.2, applied with m
k= k (i.e. to H
1, . . . , H
K), we have, if N = n
1+ · · · + n
K:
a
N(T ) ≥ inf
1≤k≤K