C OMPOSITIO M ATHEMATICA
L INDA N ESS
Curvature on holomorphic plane curves. II
Compositio Mathematica, tome 35, n
o2 (1977), p. 129-137
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129
CURVATURE ON HOLOMORPHIC PLANE CURVES II
Linda Ness
Introduction
Let C :
f (y, z)
= 0 be aholomorphic
curve with anordinary
doublepoint
at Pand letCt : f + t
= 0. Let B be an open ball centered at P which is so small that B n C= C1
UC2
whereCl
andC2
are non-singular
connectedholomorphic
curves andC1 ~ C2 = {P}.
Forsufficiently small t, Ct
~ B isnonsingular.
As in Part 1
[3]
we will assume that allholomorphic
curves areendowed with the metric induced
by
theFubini-Study
metricon C 2.
The
Fubini-Study
metricon C2
isgiven by
where y and z denote the usual coordinates
on C2.
Here
CI
andC2
are Riemannian surfaces as well as Riemann surfaces. In Part 1 we obtained a formula for the Gaussian curvature and studied the Gaussian curvature onCt
fl B in the moregeneral
case that C had an
ordinary singularity
at P. In Part II we willstudy
the closed
geodesics
onCt
f1 B and the lines of constant Gaussiancurvature on
Ct
flB,
when C has anordinary
doublepoint
at P.From Part 1
[3]
we recallTHEOREM 1: Let
C C e2 be a holomorphic
curvedefined by f (y, z)
= 0. The Gaussian curvature at anonsingular point of C
isgiven by
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130
where
(H(f)
is theaffine
hessianof f.)
We now state the first main result in Part II. For convenience in
referral,
we number the theoremsconsecutively throughout
Parts 1and II.
THEOREM 3: Let D be a small solid cone with vertex at P and with the line
tangent
toCl
at P as its axis. LetD2
be theimage of Dl
underthe
unitary transformation of C2
thatfixes
P andinterchanges
the tangents toCI
andC2.
Letû,
=Ct
fl B -Dl - D2.
Given M > 0 there exists E > 0 such thatif - E
t E(i)
K onÛ,
-M 0.(ii) êt
ishomeomorphic
to acylinder.
(iii) ét
isgeodesically
convex.(iv)
Inét
there is a smooth closedgeodesic
rand every other smooth closedgeodesic
inCt
consists ingoing
around r morethan once.
The second main result in Part II is a
picture
of the curves ofconstant curvature on B fl
Ct
in the case that neither branch ofCo
hasa flex at P.
1. Proof of Theorem 3
After a
unitary
transformation we may assume that P =(0, 0)
andz = 0 is
tangent
to C at P. Wegive
theproof
for the case that theother tangent at P is y = 0. The
proof
of the moregeneral
case is astraightforward generalization
of thefollowing
argument. Hence we areassuming
that(3) f(y, z)
= yz +ay3
+by2z
+cyz2 + dz3
+higher
order termsand that in
B, f
may be f actored asf
=f1 12
whereHere
RI
andR2
have terms of order 2 or more;R1
contains noy2
termand
R2
contains noZ2
term. LetCt : f
= 0 fl B. In this case the conesare defined
by
for some small
positive
number a.Part
(i)
followsimmediately
fromCorollary
2 of Theorem 2.PROOF oF ii: In the
equation defining
C, substitute z= 03B2y.
This isan
analytic change
of coordinates onC,.
Then+ terms of order at least 4 in y.
where h is
analytic
and bounded away from 0. ThusC,
istopologi- cally equivalent
to the annulusPROOF oF iii: The
following
is well-known[4] :
LEMMA 1:
Suppose
M is a compact Riemanniansurface
and D CM is open and connected. D is
geodesically
convexif
ageodesic
existsthrough
everyboundary point of
D such that all thepoints of
D in aneighborhood of
theboundary point
lie on one sideof
thegeodesic.
Hence it suffices to prove that the
geodesic
curvature on the boun-daries of
ét
has the correct constantsign.
LEMMA 2: Let
Et
denote theboundary
curveof êt defined by
For t
sufficiently
small thesign of
thegeodesic
curvaturekg
onEt
isconstant and is
given by
thesign of (a2/1 + a2) - t
PROOF: We may take y to be a local coordinate in a
neighborhood
132
of
Et.
Then we mayview Et
as theimage
of a realanalytic
functionLet
h (y )dydy give
the induced metric. Then withrespect
to the arclength parameter s
This follows
by rewriting
the classical formula[5] for kg
in terms ofcomplex
coordinates. Withrespect
to theparameter
We will show the
sign
of#h ·|y’|kg
isgiven by
thesign
of03B12/1
+a 2 -
1/2
for tsufficiently
smallby showing
We may assume that in a
neighborhood
of theboundary
curve,C,
isthe
graph
of aholomorphic
functionz,(y).
Then one can calculateusing
z =aeiBy
onEt
andwriting zt(y)
=z(y)
Now as
t ~ 0, zy - 03B1e i03B8 on Et so y -~ i/2.
y’Also as
t ~ 0,
YZyy -2ae’o hence y,/y’’ ~ i/2.
To evaluate
(8)
recall thatHence
h ( y, 03B1ei03B8y ) ~ 1 + |03B1|2
as t - 0.By calculating hy
one can showhyy’~ - i03B12 as
t ~ 0.Q.E.D.
Finally
we must check themeaning
of thesign of kg
onEt. Project Et
onto thecomplex
linez = 0;
thetangent
andgeodesic
curvaturevectors of the
projected
curve7T(Et)
arejust
theprojections
of thetangent
and curvature vectors ofEt.
For tsufficiently
small we mayassume
Hence
03C0(Et)
isswept
out in the clockwise direction.By
thelemma kg
is
negative
onEt.
Thus the curvature vectorpoints
toward theorigin.
The other
bounding
curve is theimage
ofEt
under aunitary
transformation which preserves
geodesic
curvature. Thus thesigns
are
compatible.
PROOF oF iv: We will prove the
following
moregeneral
PROPOSITION: Consider a
geodesically
convex subdomain Mof
aRiemannian
surface
such that1TI(M) == Z
and the Gaussian curvature is bounded awayfrom
zeroby
anegative
constant. Then there exists aunique
smooth closedsimple geodesic
F and every other smooth closedgeodesic
in M consists ingoing
around r more than once.PROOF: It is known that if N is a
compact
Riemannianmanifold,
then every free
homotopy
class ofloops
has aminimal length
memberwhich is a smooth closed
geodesic.
Theproof
of this result asgiven
in[1]
is valid when thehypothesis
ofcompactness
isreplaced by geodesic convexity.
To proveuniqueness,
suppose there were twodistinct smooth closed
geodesics 11
and12.
Ifli
and12 intersect,
when lifted to thesimply
connectedcovering
spacethey
bound a lune L withf
KdA 0 which contradicts Gauss-Bonnet.If li and l2
do notintersect,
there exists ageodesic
y C M which realizes the minimum distance betweenli
and12.
Whenli, 12,
and y are lifted to thesimply
connected
covering
space, we obtain ageodesic rectangle R
wheref R
KdA 0 whichagain
contradicts Gauss-Bonnet.REMARK: For
t ~ 0, H1(Ct,Z)=Z
and any element ofH1( ét, Z),
t ~ 0 is called a
vanishing cycle [2].
Theorem 3 shows that there existunique
smoothgeodesic representatives
of thevanishing cycles.
134
1 claim that one can draw the
following picture
of the curves ofconstant curvature on B fl
Ct,
forsufficiently small t,
in the case that neither branch ofCo
has a flex at thesingular point.
In this case for
sufficiently small t, Ct
~ B flCi
andc,
fl B f1C2
each containexactly
three flexes. The dots denote the six flexes. Thenipples
denote the areas of
positive
curvature.The other
assumptions
made ondrawing
thispicture are 3 co depending
on t and the coeflicients of the thirddegree
terms of thedefining equation
such that:(1)
for c0 c 2 the setK-1(C)
has sixcomponents each of which is a
simple
closed curve.(2)
If M denotes min K and thenK-1(M)
is asimple
closed curve in B flCt
and(3)
ifM c co,
K-1(c)
consists of twodisjoint simple
closed curves, oneon each side of k --- M.
We outline the
analytic proof
of thepicture
in the case that thesingular point
P =(0, 0)
and thetangent
lines are the axes. Hence weare
assuming
as in Section 1 thatWe will denote
by Q(r~B)
thepolycylinder
Fix q so small that
Q(~)
C B and henceCo
flQ(~B)
is the union of twoanalytic
branches definedby (4)
and(5).
We consider thefollowing
subregions
ofQ( ’YI )
Hence we have the
following diagram
of theprojection
ofQ(~)
intothe
1 y 1, 1 z plane.
We now introduce a
change
of coordinate onR1
andR3.
Let t= T3.
R,
andR3
are each invariant under these coordinatechanges
whichjust expand
theregions along
theparabolas
y =’Yz2
and z =yy2 respectively, |~| 1/,q.
LEMMA: With
respect
to the(y’, z’)
coordinate system inRI
as t - 0(i) (Ct
nR,)
the curve 0 = 1 +z’y’ + d(z’)3
(ii) K ~ 2 - 4|y’/z’2|2
onCt n R1
(iii) If
d~ 0 the threeflexes
onCt
flRI approach
136
(iv)
The outerboundary of Ct
flRI given by
The convergence in
(i)
and(ii)
isuniform
on compact subsets in the(y’, z’)
space. Theanalogous
results holdfor Ct
nR3.
PROOF:
Straightforward computation.
By
theprevious lemma, then,
we can obtain apicture
of the curvesof constant curvature
on
ct
rlRI
for t very smallby considering
the curveand the subsets
Py
C C whereNote that if t is small
enough
theimage
ofCt
in theIyl, Izl plane
liesin an
arbitrarily
smallneighborhood
of theimage
ofCo,
whichif q
issmall
enough
lies in anarbitrarily
smallneighborhood
of(|y| =
LEMMA: On
R2
flCt, for
tsufficiently
smallwhere
0 03B4(t) 1/~2
and03B4(t) ~ 0
as t - 0.PROOF:
Straightforward computation.
LEMMA:
On Ct
nR
1(i)
For y> |d|, Py is a simple
closed curve.If d ~ 0
(ii)
When y =Id 1, Py is a simple
closed curve minus onepoint
at 00.(iii)
Fory |d|, Py
consistsof
threedisjoint simple
closed curves(iv) limy~0, Py
=(0, #1ld)
which are theflexes.
PROOF: Obvious.
An
analogous
lemma holds onc,
nR3.
REFERENCES
[1] R. L. BISHOP and R. J. CIRTTENDON: Geometry of Manifolds, Academic Press, 1964.
[2] M. DEMAZURE: Classification des Germes à Point Critique Isolé et à Nombres de Modules 0 ou 1. Seminaire Bourbaki, 1973-74, No. 443, pp. 1-19.
[3] L. NESS: Curvature on Algebraic Plane Curves I. Comp. Math. 35 (1977) 57-63.
[4] J. J. STOKER: Differential Geometry, Wiley-Interscience, 1969.
[5] D. J. STRUIK: Lectures on Classical Differential Geometry, Addison-Wesley, 1950.
(Oblatum 1-XII-1975 & 6-IX-1976) Department of Mathematics University of Washington Seattle, Wash. 98195.
U.S.A.