R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
P IER C ARLO C RAIGHERO
A remark on Abhyankar’s space lines
Rendiconti del Seminario Matematico della Università di Padova, tome 80 (1988), p. 87-93
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Abhyankar’s Space
PIER CARLO CRAIGHERO
(*)
SUNTO - In questa nota si prova la rettificabilith della seconda delle linee di
Abhyankar, C6:
(t + tg, t5, t4) ; inoltre si costruisce unesempio
di lineadi
tipo
(6, 5, 4) che risulta elementarmente rettificabile.SUMMARY - In this paper the
rectifiability
of the second ofAbhyankar’s
lines,C6:
(t + t6, t5, t4), isproved;
moreover anexample
isgiven
of a (6, 5,4)-line
which istamely
rectifiable.0. Introduction.
The notations will be as in
[2]
and[3].
In[2]
therectifiability
of the first of
Abhyankar’s lines, C5: (t --~- t5, t4, t3),
wasproved;
theautomorphism 0 - A~ 2013~J~
such thatØ5(C5)
is astraight line,
wasexplicitly
found: it turns out to be theproduct
of anautomorphism
If of
« Nagata’s type »,
and of a tameautomorphism
V(an
auto-morphism
ofA3, (F, G, H),
is called of« Nagata’s type»
if theforms of maximum
degree
ofF, G, H,
are such that no one of themis a
polynomial
in the othertwo,
and moreover every two of themare not the power of a same
form;
anautomorphism
~1. ofA~
is calledtame if it is the
product
of linear andtriangular automorphisms,
and it is called
elementary
in[2]).
About at the same time when the author
got
the resultpublished
in
[2], C5
wasindipendently recognized
rectifiable alsoby
A.Sathaye,
(*) Indirizzo dell’A.: Istituto di Matematica
Applicata,
Universita, via Belzoni 7, 35100 Padova(Italy).
88
as himself communicated at Oberwohlfach: however up to now noth-
ing
was known about(t + t~, tn-2), n >
5. Since the intereston the
subject
seems tospread (see
forexample [5]),
Ithought
itopportune
topublish
these new results.In
§ 1
therectifiability
ofe6: (t + t6, t5, t4)
isproved;
the auto-morphism (/)6’
which rectifiesit,
is in the same condition as~5,
andshould not be
tame, by
the sameargument.
In
§ 2
anexample
isgiven
of a(6, 5, 4)-line
which isactually tamely
rectifiable: this shows that the fact offinding,
for rectifica-tion of the line
e6, only
anautomorphism
such as(/J6’
non-tameby Nagata’s conjecture (see [6],
Part2,
pp.41-52),
is not dueonly
tothe
particular
kind of thetriplet (n, n - 1, n - 2 )
of thedegrees
ofthe
polynomials defining e6 ~
In § 3
a definition of wild line isgiven,
in such a way thate6 (and
also
es)
iswild,
whereasCg
is not wild:perhaps
this could be the correctapproach, pointing
to thereasonably probable
factthat,
inorder to
rectify
a wildline,
ase6 (and
anautomorphism which, according
toNegata’s conjecture,
is « wild»(= non-tame)
is necessary.1. We want to show that
e6: (t + t6, tS, t4)
is a rectifiable line.Let us consider
We find
From all this it follows
Now we observe that it results
From
(*)
and(**)
weget
Now the surface of 5-th order
is a linear
plane,
that is a monoidal surface of the kindisomorphic
to aplane:
indeed it satisfies the conditions of Lemma 4 in[7] (of
course afterinterchanging
Y and Z in thatstatement,
thenmaking u
= Z and v =X). Moreover, always
from[7],
it follows that Y isequivalent
to aplane (see
theTheorem, § 1, [7]),
andby
consequence we have that
e6
is a rectifiableline, applying Prop. 3,
in
[2].
REMARK 1.
Proceeding
as above forC6,
wefind,
in the case ofthe line
C7 : (t + t7, t6, t5) ,
where we write in
place
of = t+ t7, y(t) = t6,
=
t5;
now,starting again
from(**),
which holds for every Abh-yankar’s
line C :(t + tn, tn-l, tn-2),
we can substitute twicey(t) 2
in(*’),
90
but we
get
a monoidal surface which is nolonger
a linearplane:
thisshows that
C7
is somewhat a crucial case in theproblem
ofrectify- ing Abhyankar’s
lines.Still in
degree 5,
there are also two otherlines,
ynamely
which are
particularly
difficult torectify.
If these twoquintics
wererectifiable,
then it would not be hazardous toconjecture
that everyquintic
line is rectifiable.2. The
automorphism ø6
that rectifiesC,
can be calculated fol-lowing Corollary
2 in[7],
which leads to the construction of an auto-morphism If’,
such that is aplane,
thenby multiplying
1Jf’by
an obvious tameautomorphism
~l’ : 1’’ turns out to be ofNagata’s type,
as If in the case ofBeing
== alsoø6,
as0,,
should not be
tame, according
toNagata’s conjecture (see
Introduction forreference).
In order to show that thedifficulty
offinding
a pos- sible tameautomorphism
that canrectify e6
is not dueonly
to theparticular triplet
of thedegrees
of thepolynomials defining Cgy
thatis a
triplet
of three consecutiveintegers,
y here wegive
anexample
of a
(6, 5, 4)-line
which isactually tamely
rectifiable.Let us consider the
following
curvewhere we have
together
with thefollowing triangular automorphisms
of AWe find
so that
e6
is atamely
rectifiable line.REMARK 2. It is very
unlikely
that there exists a(5, 4, 3)-line
which can be
tamely
rectified: such a line issurely
wild(see
Defini-tion
2,
in thefollowing paragraph),
andeverything
seems to indicatethat a wild line C cannot even be
tamely equivalent
to a line of lower totaldegree,
thisbeing naturally
defined as the sum of thedegrees
of those
polynomials defining C
which are not zero.Let us recall that a
proof
that a(5, 4, 3)-line
is nottamely
recti-fiable would be an indirect
proof
ofNagata’s conjecture
on the ex-istence of non-tame
automorphisms
ofA: (see [4], § 2).
3. After the
examples
consideredin ~ 1) and §2),
we think itnatural to
put
thefollowing
definitions.DEFINITION 1. Given any
pair
ofpolynomials (P(t), Q(t)),
we shalldenote
by
Sem(P(t), Q(t))
thesemigroup
of all thedegrees
ofF(P(t), Q(t)),
withY) varying
in the set of all thepolynomials
in twovariables such that
.F’(P(t),
0.DEFINITION 2. Given a line C:
(x(t), y(t), z(t)),
we call C a wildline if no one of the
polynomials x(t), y(t), z(t),
is aconstant,
andif, calling
m, n, p,respectively
thedegrees
ofx(t), y(t), z(t),
we haveWe recall that the
generators
ofSem(P(t), Q(t))
can be calculatedmaking
use of theprocedure given
in[1];
see also[4], §4.
92
We have then the
following
PROPOSITION.
e6
is a wildline; C’ 6
is not a wild line.PROOF. We
find,
forwhence the statement about
C6.
As for
Cl : (xl(t), y,(t), z.,(t)),
withx1(t), etc., given
abovein § 2),
let us consider the
polynomial
we find
REMARK 2. Of course the fact
that, according
to Definition2, e6
is a wildline,
could account for the other fact offinding only
anautomorphism
asø6
that canrectify
it.We also note that a line C:
(x(t), y(t), z(t))
which is notwild,
isclearly tamely equivalent
to a line of lower totaldegree.
Finally
we observe that what is remarkable aboute~
is the fol-lowing : generally speaking,
a(6, 5, 4)-line C,
which is notwild,
istamely equivalent only
to a(5, 4, 3)-line,
which in its turn isclearly wild,
sothat,
for the rectification ofC,
we are confronted with a newdifficulty ;
withCg instead,
weskip
thisimpasse, coming
to a tamerectification of it.
REFERENCES
[1] S. S.
ABHYANKAR,
Generalizationsof
ancient indian mathematics and ap-plications,
Bhakaracharia Pratishthana Souvenir, Poona, 1978.[2] P. C.
CRAIGHERO,
AboutAbhyankar’s conjectures
on space lines, Rend.Sem. Mat. Univ. Padova, 74
(1985),
pp. 115-122.[3] P. C. CRAIGHERO, A result on m-Flats in
Ank ,
Rend. Sem. Mat. Univ. Pa- dova, 75 (1986), pp. 39-46.[4] P. C. CRAIGHERO, Osservazioni sopra alcuni
esempi
di curve dellospazio A3k isomorfe
a rette, Boll. Un. Mat. Ital., (6), 1-B (1982), pp. 1199-1216.[5] Z. JELONEK, The extension
of regular
and rationalembeddings,
Mathema-tische Annalen, 277 (1987), pp. 113-120.
[6] M. NAGATA, On
automorphism
groupof k[X, Y], Kinokuniya
Book-Store Co.,Tokyo,
1972.[7] A. SATHAYE, On linear
planes, Proceedings
of the American MathematicalSociety,
56 (1976), pp. 1-7.Manoscritto