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On the computation of the order of Janko’s first simple group <span class="mathjax-formula">$\mathfrak {F}_1$</span>

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R ENDICONTI

del

S EMINARIO M ATEMATICO

della

U NIVERSITÀ DI P ADOVA

H ERBERT D IETZSCH

On the computation of the order of Janko’s first simple group F

1

Rendiconti del Seminario Matematico della Università di Padova, tome 46 (1971), p. 371-374

<http://www.numdam.org/item?id=RSMUP_1971__46__371_0>

© Rendiconti del Seminario Matematico della Università di Padova, 1971, tous droits réservés.

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is to correct this mistake.

We use

terminology

and notation of

[ 1 ] .

Case

( i )

of Lemma 3.1.

Here

N(U)CC(t). Thus, T=t, t1&#x3E;

is a

S2-subgroup

of

N(U),

where

ti is an involution of F which acts

invertingly

on U.

We have

U(ti) X ~ t ) =N(U).

The group

N(U)/ (t)

has two linear characters:

ç’o (the principal character), 0’,

and two irreducible characters

~’1 , ~’2

of

degree

2.

Let %’

be the nontrivial linear character of

N(U)/(N(U)

n

F).

Put

U = ( (.t ) .

We get the

following

character-table of

N{ U).

Let the set of «

special

classes » of

N( U)

in the sense of Suzuki

[2]

consist of the

conjugate

classes of p, in

N(U)..

The module

(over

the

ring

of

integers)

of the

generalized

characters

of

N( U) vanishing

on non

special

classes of

N(U)

has the

following

basis:

*) Indirizzo dell’A.: Mathematisches Institut der Universitdt, 65 Mainz, Ger-

mania Occ.

(3)

372

We have the

following decomposition

of the induced charac-

ters

P ~* :

(4)

Hence we get:

v~ }.

Since

0==(p~(~

we

y4 1

and

v~ }.

Therefore,

in both cases we

get: A’i(~)==±5

and

Z2(~)=±4.

We shall

apply

the Suzuki order formula of

[2]

for the

generalized

char-

acters

(p~3=~o+P~2013~i,

and the

subgroup N( U~

of G.

Put thus

/+1=-~22(1)

as

0 = ~cp3*( 1 )~.

Denoting [ G I by

g we obtain

Hence, g.~-3)’=2~3~./.(/+l).

We know that

botch 1

and

f -I-1

divide g and that

f

and

f+1

are

coprime.

This

implies

that

f - 3

is a divisor of 23.3.5.

On the other hand a

S2-subgroup

of G has order 8 and U is a

S5-subgroup

of G. This

implies

22.5 divides

f - 3.

(5)

374

Therefore we have the

following possibilities:

It is easy to see that all

eight possibilities

lead to a contradiction.

For

example

which is

impossible

as 7 divides g.

Similarly f - 3

= - 60

implies g=2~’3’5’7’19

which is

against

the

order of a

S2-subgroup

of G.

Thus,

we have ruled out Case

(i)

of Lemma 3.1.

REFERENCES

[1] JANKO, Z.: A new finite simple group with abelian Sylow-2-subgroups and

its characterization, Journal of Algebra 3 (2) (1966), 147-186.

[2] SUZUKI, M.: Applications of group characters, Proc. Symp. Pure Math. 1 (1959), 88-89.

I am very grateful to Dr. DIETER HELD for suggesting this problem to me.

Manoscritto pervenuto in redazione il 10 Luglio 1971.

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