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S0294-1449(00)00121-9/FLA

LONG-TIME VANISHING PROPERTIES OF SOLUTIONS OF SOME SEMILINEAR PARABOLIC EQUATIONS

Yves BELAUDa,Bernard HELFFERb,Laurent VÉRONa

aLaboratoire de Mathématiques et Physique Théorique, CNRS ESA 6083, Faculté des Sciences et Techniques, Université François Rabelais, 37200 Tours, France

bDépartement de Mathématiques, CNRS UMR 8628, Bât. 425, Université Paris-Sud, 91405 Orsay, France Manuscript received 4 February 2000

ABSTRACT. – We study the long-time behavior of solutions of semilinear parabolic equations of the following type (PE)tu− ∇. A(x, t, u,u)+f (x, u)=0 wheref (x, u)b(x)|u|q1u, bbeing a nonnegative bounded and measurable function andqa real number such that 06q <1.

We give criteria which imply that any solution of the above equations vanishes in finite time and these criteria are associated to semi-classical limits of some Schrödinger operators. We also give a series of sufficient conditions onb(x)which imply that any supersolution with positive initial data does not to vanish identically for any positivet.2001 Éditions scientifiques et médicales Elsevier SAS

RÉSUMÉ. – Nous étudions le comportement en temps grand de solutions d’équations paraboliques du type (PE) tu− ∇. A(x, t, u,u)+f (x, u)=0, oùf (x, u)b(x)|u|q1u, b étant une fonction positive, bornée et mesurable, et q un nombre réel tel que 06q <1.

Nous donnons des critères qui impliquent que toute solution des équations ci-dessus devient identiquement nulle en temps fini et ces critères sont associés à des problèmes de limite semi- classique d’opérateurs de Schrödinger. Nous donnons aussi une série de conditions suffisantes sur b(x)qui impliquent que toute sur-solution avec des données initiales positives ne devient jamais identiquement égale à zéro.2001 Éditions scientifiques et médicales Elsevier SAS

1. Introduction

Letbe a bounded domain in RN,b(x)a nonnegative function inΩ, non-identically zero and 06q <1. Consider the following equation semilinear equation

tu1u+b(x)|u|q1u=0 in×(0,∞),

νu=0 on∂Ω,

u(x,0)=u0(x) inΩ.

(1.1)

E-mail addresses: belaud@univ-tours.fr (Y. Belaud), Bernard.Helffer@math.u-psud.fr (B. Helffer), veronl@univ-tours.fr (L. Véron).

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This type of equation is a simple model to understand some phenomenological properties of nonlinear heat conduction with a non-constant strong absorption term b(x)uq, depending both on the media and the temperature u. It is well-known that if b(x)>β >0 the comparison principle with the solutions of the ordinary differential equation

tϕ+γ|ϕ|q1ϕ=0 in(0,), ϕ(0)= ku0kL,

(1.2)

implies thatuvanishes fort>T = ku0k1Lq/γ (1q). The property that any solution of Eq. (1.1) becomes eventually zero fortlarge enough is called the Time-Compact Support property (shortly the TCS-property). On the opposite, if we assume thatb(x)≡0 for any x belonging to some connected open subsetωofΩ, the restriction toωof any solution uof (1.1) satisfies the linear equation

tu1u=0 inω×(0,). (1.3)

Let λω denote the first eigenvalue of −1 in W01,2(ω) and ϕω the corresponding eigenfunction normalised by maxωϕω=1. If we assume thatuis a nonnegative solution of (1.1) with ess infωu0=σ >0, then u(x, t)is bounded from below by σet λωϕω(x) onω×(0,).

Between those two extreme situations there exists a wide class of situations which were first explored by Kondratiev and Véron [10]. Ifnis an integer, they introduce the fundamental state of an associated Schrödinger operator

µn=inf Z

|∇ψ|2+2nb(x)ψ2dx: ψW1,2(Ω), Z

ψ2dx=1

, (1.4) and they proved that if

X n=0

µn1ln(µn) <∞ (1.5)

holds, then (1.1) possesses the TCS-property. For example, if b(x)>β >0, then µn >β2n and the above series is convergent. On the contrary, if b(x)≡0 for any xωfor some open subdomainω, thenµn6λ1,ω and the series is divergent.

In this article we study the TCS-property for a much more general class of quasilinear equations which need not satisfy any comparison principle between solutions, namely we consider weak solutions of equations of the following type

tu− ∇.A(x, t, u,u)+f (x, u)=0 in×(0,),

νu=0 on∂Ω×(0,∞),

u(x,0)=u0(x) inΩ.

(1.6)

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Besides the standard Caratheodory assumptions on A and f, it is assumed only a minimal linear growth estimate in the gradient forA,

|A(x, t, r, p)|6C|p|, A(x, t, r, p).p>|p|2,

(1.7)

for some positive constantC. As for the functionf, we shall assume that there exists a nonnegative, bounded and measurable functionband a real numberq∈ [0,1)such that, f (x, r)r >b(x)|r|q+1, (1.8) in×R. Defining the functionµon(0,)by

µ(α)=inf Z

|∇ψ|2+αq1b(x)ψ2dx: ψW1,2(Ω), Z

ψ2dx=1

, (1.9) we first prove the following result.

THEOREM 2.2. – Suppose that 06q <1, that b is a nonnegative, bounded and measurable function defined inΩ and that there exists a decreasing sequence {αn}of positive numbers such that

X n=1

1 µ(αn)

ln µ(αn)+ln αn

αn+1

+1

<, (1.10)

then Eq. (1.7) satisfies the TCS-property.

Under this form, this result is not easy to apply, but a simpler form of the above criterion is derived from the fact that the existence of a decreasing sequence {αn} satisfying (1.10) is a consequence of the following relation

Z1

0

ln(µ(t)) µ(t)

dt

t <∞. (1.11)

Since the function µin (1.9) is monotone and{αn}decreases, condition (1.10) implies that limn→∞µ(αn)= ∞and limn→∞αn=0. It is derived from (1.9) that the analysis of the functionµnear 0 is linked to the analysis of the fundamental state of the Neumann realization of the Schrödinger operatorHh2binL2(Ω)defined by

ϕ7→Hh2bϕ= −1ϕ+h2b(x)ϕ, (1.12) in whichhis a positive parameter tending to 0. Because we will need only a rather weak information, this analysis of the behaviour ofµcan be performed by using techniques of the so-called semi-classical analysis. Using a formula due to Lieb and Thirring, we obtain an estimate on meas.{x: h2b(x)6ρ} from which we derive a simple integral criterion which implies the TCS-property in a bounded domain.

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THEOREM 3.1. – Suppose that N >1, and that b is a bounded, measurable and almost everywhere nonnegative function which is essentially positive near ∂Ω. If ln(1/b)∈Lp(Ω)for somep > N/2, then estimate (1.11) holds.

A similar result holds if the Neumann boundary conditions in (1.6) are replaced by homogeneous Dirichlet condition, without the assumption thatb is essentially positive near∂Ω. For example ifb>0 is continuous and nonnegative inΩ, analytic in¯ and positive on∂Ω the above integrability condition is satisfied. We give other examples in which the setb1(0)has a much less regular structure.

On the opposite, the global non-vanishing property asserts that a solution of some inequation with positive initial data will not vanish for any positive t. Our method is a local one, settled upon the study of some mean value types inequalities, therefore we consider semilinear differential inequalities in divergence form in some domainRN (not necessarily bounded)

tuxi(ai,j(x)∂xju)+b(x)uq>0 in×(0,),

u>0 in×(0,),

u(x,0)=u0(x) inΩ.

(1.14)

The matrix A(x) = (aij(x)) is symmetric, locally bounded and defines a locally uniformly elliptic operator in Ω, q is some real number with 06q <1, and bL1/(1loc q)(Ω)a nonnegative function. Ifωis any smooth subdomain andρL(ω) is nonnegative, we denote by

νρ,ωA =inf Z

ω

aij(x)∂xjψ∂xiψ+ρ(x)ψ2dx: ψW01,2(ω), Z

ω

ψ2dx=1

.

(1.15) Ifψρ,ω is a corresponding positive eigenfunction and ifu0L1loc(Ω), u0>0, we define

Tρ,ω(u0)= 1

νρ,ωA ln 1+ νρ,ωA Rωψρ,ωu0dx1q R

ωb1/(1q)ψρ,ωdx1q

!

. (1.16)

Our general criterion for a global nonnegative weak solution not to vanish is as follows.

THEOREM 4.1. – Let

uC [0,∞);L1loc(Ω)L1loc [0,∞);Wloc1,1(Ω) be a weak solution of (1.14). If

sup

ρ,ω

Tρ,ω(u0)= ∞, (1.17)

then, for anyt∈ [0,∞),x7→u(x, t)is never identically zero.

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Clearly the above criterion is uneasy to check since the initial value u0 and the potentialbappear only in a very intricate way in (1.16). Therefore we shall give a series of expressions where inf essu0>0, which emphasizes the local behavior ofbnear its minimal value 0, and will imply that (1.17) holds forTρ,ω(u0). For example

THEOREM 4.3. – Let us assume that the matrix A(x) is uniformly elliptic and bounded. ForyΩlet us introduceRy=sup{r >0:Br(y)}. Then, if inf essu0>

0,

sup

y

sup

0<r<Ry

r2ln

1

R

|xy|<rb1/(1q)dx

= ∞ ⇒sup

ρ,ω

Tρ,ω(u0)= ∞. (1.18) Condition (1.18) is strongly linked to the behaviour ofb(x)near the setb1(0). As another application, we prove that, ifb>0 satisfies

sup

0<r<Rx0

r2ln 1

R

|xx0|<rb1/(1q)dx

!

= ∞, (1.19)

for somex0anduis a solution of (1.1) with a continuous initial datau0nonnegative in¯ and positive atx0, thenu(x0, t) >0 for anyt >0.

In the model case of Eq. (1.1) with b(x)=e−|xx0|β, for some x0Ω, the border case between TCS-property and its negation occurs forβ=2.

Our paper is organized as follows:

(1) Introduction.

(2) The time compact support property.

(3) The semi-classical analysis.

(4) The non-vanishing property.

(5) References.

2. The time compact support property

In this section is a bounded domain of RN (N >1) with a Lipschitz-continuous boundary, A:(x, t, r, p)7→A(x, t, r, p) andf:(x, t, r, p)7→f (x, t, r)are measurable functions from×R+×R×RNwith value respectively in RNand R. We assume that Aandf are continuous in the variables(r, p)R×RNand satisfies

(i) |A(x, t, r, p)|6C|p|

(ii) A(x, t, r, p).p>α|p|2(x, t, r, p)×R+×R×RN,

(2.1) f (x, t, r)r>b(x)|r|q+1(x, t, r)×R+×R, (2.2) for some positive constants C and α. In the sequel b is a bounded, nonnegative and measurable function,qis a parameter in[0,1)andCdenotes a generic positive constant, whose value usually only depending onΩ, and sometimes onA,bandq.

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DEFINITION 2.1. – A function u belonging to C([0,∞);L2(Ω))L2loc([0,∞);

W1,2(Ω))and such thatf (. , . , u)L2loc((Ω×(0,))is a weak solution of the problem

tu− ∇.A(x, t, u,u)+f (x, t, u)=0 in×(0,),

νu=0 on∂Ω×(0,),

u(x,0)=u0(x) inΩ,

(2.3)

where u0L2(Ω), if for any ζL2loc([0,∞);W1,2(Ω))Wloc1,2([0,∞);L2(Ω)) and t >0, there holds

Zt

0

Z

t+A(x, t, u,u).ζ +f (x, t, u)ζdxdτ

=Z

ζ (x,0)u0(x)dx−Z

ζ (x, t)u(x, t)dx. (2.4) Remark 2.1. – Assumptions 2.1 and 2.2 are the natural ones for giving meaning to the notion of weak solutions and to use energy estimates in the spaceW1,2(Ω). The use of energy estimates is fundamental for deriving uniform bounds of the solutions via the Nash–Moser iterative scheme and L2-time exponential decay. Moreover, by changing the functionsAandbit is always possible to assume thatα=1, which will be done in the sequel.

The scheme for proving that weak solutions of (2.3) may vanish identically whent becomes large enough is first to start by an exponential L2-decay estimate at time τ0, and this is done by using the energy estimate. Then, thanks to the regularizing effects associated to this type of equation, to transform this L2 estimate into an exponential L-decay estimate at time τ0+τ1. Finally using the fact that the exponent q is less than 1, to derive an improved exponential L2 decay at time τ0+τ1+τ2. The TCS- property will follow by iterating this procedure and optimizing over the different time shift τi (i=0,1, . . . ,∞). The following a priori estimates are classical in the theory of monotone second order parabolic equations, but for the sake of completeness and to point out the role of our assumptions, we shall give a sketch of their proofs.

THEOREMA. – Suppose thatb>0 a.e. inΩand thatuis a weak solution of (2.3).

(i) Ifu0Lp(Ω) (26p6∞), thenuL([0,∞);Lp(Ω))andt→ ku(. , t)kLp

is decreasing on[0,∞).

(ii) Ifu0L2(Ω), thenu(. , t)L(Ω)for anyt >0 and there holds

u(. , t)L6C 1+t1N/4ku0kL2, (2.5) whereC=C(Ω).

Proof. – The proof of (i) is straightforward, by taking as test functions the trun- cated functionTm,p(u)=min(mp1,|u|p1)sign(u)form >0 (at this point the assump- tions (2.1)–(2.2) are needed), and then by letting m go to infinity. The proof of (ii) is

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an adaptation from Evans [4] of the celebrated Nash–Moser iterative scheme [17,16].

It relies on taking Tm,pn(u) as test functions, for some sequence {pn}nN= {2kn}nN. Herek >1 depends only onN via the Gagliardo–Nirenberg inequality (this is for this point that we need the Lipschitz regularity of ∂Ω). Using the definition of a solution betweentn1andtnwheretn=(1−2n)t, instead of 0 andtand applying the previous imbedding inequalities yields an estimate of the type

Cpn11(tntn1)min(|u(. , tn)|, m)pLnpn1

6 1+(tntn1)min u(. , tn), mpLn−1pn−1, (2.6) valid for anym >0 andnN. This series of inequalities implies (2.5).

2

We define a decreasing functionµon(0,)by µ(α)=inf

Z

|∇ψ|2+αq1b(x)ψ2dx: ψW1,2(Ω), Z

ψ2dx=1

. (2.7) The followingLexponential decay estimate is fundamental in the sequel.

LEMMA 2.1. – Supposeb>0 a.e. inΩ, 06q <1 anduis a bounded weak solution of (2.3) such thatku0kL6αfor someα >0. Then

u(. , t)L6min 1, C µ(α)N/4et µ(α)ku0kL (t>0), (2.8) whereC=C(Ω) >0.

Proof. – We takeζ =uin (2.4) and use (2.2), then Zt

s

Z

uut+ |∇u|2+b(x)|u|q+1dxdτ 6Z

u2(x, s)dx−Z

u2(x, t)dx for 06s < t. Since|u|q1>αq1by Theorem A(i), we get

1 2

d dt

Z

u2dx+ Z

|∇u|2+q1u2dx60. (2.9) Combining this with Hölder’s inequality yields

u(. , s)L2 6esµ(α)ku0kL26||1/2esµ(α)ku0kL (2.10) fors>0. From (2.5)

u(. , t)L6C

1+ 1 ts

N/4

||1/2esµ(α)ku0kL. (2.11) If we takets=1/µ(α)(this is actually almost the optimal choice forswhenµ(α) is large), we derive the following inequality from which (2.8) follows immediately

C

1+ 1 ts

N/4

||1/2esµ(α)=C 1+µ(α)N/4e||1/2et µ(α). 2

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THEOREM 2.2. – Let us assume that (2.1)–(2.2) holds and thatn}is a decreasing sequence of positive numbers such that

X n=1

1 µ(αn)

ln µ(αn)+ln αn

αn+1

+1

<. (2.12)

Then any weak solution of (2.3) satisfies the TCS-property.

Proof. – Since any weak solution of (2.3) is bounded for positivet, we shall assume that u0 is bounded. By changing u into λu and b into λ1−qb, which does not affect the property (2.12), we can also assume ku(. ,0)kL=1. Settingα0=1 and applying Lemma 2.1 yields

u(. , t)kL6min 1, C µ(1)N/4et µ(1). (2.13) Clearly ift>t0=ln(C(µ(1))N/4)/µ(1), thenku(. , t)kL 6C(µ(1))N/4×eµ(1)t. We definet1> t0by

α1=C µ(1)N/4et1µ(1)⇔ 1 µ(1)ln

C(µ(1))N/4 α1

=t1 (2.14)

(it is always possible to assumeα1<1). Sinceku(. , t1)kL6α1, we apply Lemma 2.1 with 0 replaced byt1, and obtain

u(. , t)L6min 1, C µ(α1)N/4e(tt1)µ(α1)α1 (2.15) in×(t1,). We definet2by

α2=min 1, C µ(α1)N/4e(t2t1)µ(α1)α1

=C µ(α1)N/4e(t2t1)µ(α1)α1

⇔ (2.16)

t2t1= 1 µ(α1)ln

C µ(α1)N/4α1

α2

.

Iterating this process, we construct an increasing sequence{tn}such thatku(. , t)kL6 αn1fort>tn1and

αn =min 1, C µ(αn1)N/4e(tntn−1)µ(αn−1)αn1

=C µ(αn1)N/4e(tntn1)µ(αn1)αn1

⇔ (2.17)

tntn1 = 1 µ(αn1)ln

C µ(αn1)N/4αn1

αn

. Consequentlyku(. , t)kL6αnfort>tn and accordingly

u(. , t)L6min 1, C µ(αn)N/4e(ttn)µ(αn)u(. , tn)L. (2.18)

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From (2.17) tnt0=

n−1

X

k=0

1 µ(αk)ln

Cµ(αk) αk

αk+1

=lnC

n1

X

k=0

1 µ(αk)+

n1

X

k=0

1 µ(αk)

ln µ(αk)+ln αk

αk+1

. (2.19)

By assumption the right-hand side is bounded. Therefore limn→∞tn =T and (2.18) yields

u(. , t)L6min 1, C µ(αn)N/4e(tT )µ(αn)αn, (2.20) fort>T. Because of (2.12), limn→∞µ(αn)= ∞and limn→∞(µ(αn))N/4×eδµ(αn)=0 for anyδ >0. Lettingngo to infinity in (2.20) impliesku(. , t)kL=0(t>T ). 2

Actually the following result gives a simpler form for the assumption (2.12).

THEOREM 2.3. – The existence of a decreasing sequence satisfying condition (2.12) in Theorem 2.3 is implied by

Z1

0

ln(µ(t)) µ(t)

dt

t <. (2.21)

Moreover it implies

Z1

0

dt

tµ(t)<. (2.22)

Proof. – Suppose that (2.12) holds for some decreasing sequence{αn}converging to zero and such that 0< αn61. Then{µ(αn)}increases,{1/µ(αn)}decreases fornlarge enough (n>1 without any loss of generality) and limn→∞µ(αn)= ∞. Therefore

1

µ(αn+1)ln αn

αn+1

6

αn

Z

αn+1

dt

tµ(t) 6 1

µ(αn)ln αn

αn+1

, (2.23)

and

α1

Z

0

dt

tµ(t) 6X

n=1

1

µ(αn)ln αn

αn+1

<. (2.24)

Conversely suppose that (2.21) holds and consider {αn} = {2n}. Then ln(αnn+1)= ln 2,

lnµ(αn+1)

µ(αn+1) lnαn+1

αn+2

=lnµ(αn+1) µ(αn+1) ln αn

αn+1

6

αn

Z

αn+1

lnµ(t) µ(t)

dt

t , (2.25)

and

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1

µ(αn+1)lnαn+1

αn+2 = 1

µ(αn+1)ln αn

αn+16 1 lnµ(αn+1)

αn

Z

αn+1

lnµ(t) µ(t)

dt t ,

6 1

lnµ(2)

αn

Z

αn+1

lnµ(t) µ(t)

dt

t . (2.26)

Consequently X n=1

1 µ(αn)

ln µ(αn)+ln αn

αn+1

+1

< C Z1

0

lnµ(t) µ(t)

dt

t <∞ (2.27) for someC >0. 2

Remark 2.2. – In problem (2.3), we can replace the Neumann boundary condition on

∂Ω by a Dirichlet boundary condition. In that case µ(α)has to be replaced by µ0(α), which is defined in the same way, except that the test functionsψ in the definition (2.7) are taken inW01,2(Ω). Lemma 2.1 still holds without any regularity requirement on∂Ω. Consequently, if there exists a decreasing subsequence {βn}such that

X n=1

1 µ0n)

ln µ0n)+ln βn

βn+1

+1

<, (2.28)

then any solution of (2.3) with Dirichlet boundary conditions satisfies the TCS-property.

Remark 2.3. – If b(x)>β >0, then µ(α)>βαq1 and the convergence of the integral in (2.13) follows. More generally as soon as there exists an estimate of one of the following types

µ(α)>δα(0,) (2.29) for someδ >0, or

µ(α)>K ln(α1)ρα(0,1) (2.30) for some ρ >1, then the condition (2.12) is fulfilled. Therefore the key problem is to look for a condition on the function b which implies estimates as above. Clearly, if b≡0 in some subdomainωΩ, (2.12) does not hold.

Remark 2.4. – Estimate (2.8) in Lemma 2.1 has the disadvantage that it contains the termCµ(α)N/4et µ(α) which might be very large whent is close to 0, (or equivalently the exponential decay will not be effective unless t is large enough, depending on µ(α)). If we suppose that A(x, t, r, p)=p, and f (x, u)=b(x)|u|q1u (2.3) reduces to a semilinear heat equation. The Riesz–Thorin interpolation theorem applied to the linear problem

tu1u+αq1b(x)u=0 in×(0,),

νu=0 on∂Ω×(0,),

u(x,0)=u0(x) inΩ,

(2.31)

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whose solutions are natural supersolutions for (2.3), implies the following decay estimate u(. , t)Lp6e2t µ(α)/pku0kLp (2.32) fort>0 and 26p6∞, while Lemma 2.2 means an exponential decay estimate inL of orderC(µ(α))N/4et µ(α). It would be interesting to know for what type of nonnegative and bounded functions b(x)the following estimate holds:

u(. , t)L6Cet µ(α)δku0kL (2.33) fort>0, with constantsC, δ >0 independent ofµ(α). This estimate withδ=1/2 was supposed to be always true in [10], which we do not know; therefore in Theorem 4.3 (respectively 4.7) of this paper, inequalityP0 µn1<∞(respectivelyP0 µn1/2<∞) has to be replaced byP0 lnµnn<∞(respectively P0 lnµn/µn<∞). However if any solution of (2.31) satisfies an estimate of the type

u(. , t)L6Cet αq1δku0kL, (2.34) for anyt>0, with constants C, δ >0 independent ofα, then inf essxb(x)>δ. This follows by takingu0=Φ whereΦ is a first eigenfunction of the Neumann realization of−1+αq1b(.)inL2(Ω)and by applying Lemma 3.2 in Section 3.

The TCS-property admits a local version if we assume that the operator Areduces to a N ×N bounded and measurable matrix A(x)= (aij(x)) and r 7→f (x, r) is nondecreasing. Ifωis some subdomain, we denote

µ0,ω(α)=inf Z

ω

|∇ψ|2+αq1b(x)ψ2dx: ψW01.2(ω), Z

ω

ψ2dx=1

, (2.35) and we consider the following problem

tu− ∇.(A(x)u)+f (x, u)=0 in×(0,),

νu=0 on∂Ω×(0,),

u(x,0)=u0(x) inΩ.

(2.36)

THEOREM 2.4. – LetωΩbe some smooth subdomain. Assume thatr7→f (x, r)is nondecreasing for anyxΩ, satisfies (2.2) with 06q <1 andbL(Ω),b>0 a.e.

inΩ. We assume also thatbis essentially bounded from below by a positive constant in a neighbourhood of∂ωand that there exists a decreasing sequence of positive numbers {γn}such that

X n=1

1 µ0,ωn)

ln µ0,ωn)+ln γn

γn+1

+1

<. (2.37) If u is a solution of (2.36), then for any compact subset Kω there exists T >0 depending onK,u0andn}such thatu(x, t)0 for any(x, t)K× [T ,∞).

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Proof. – From (2.2) and the Caratheodory assumptionf (x,0)=0 andf (x, r)has the sign ofr for anyxΩ. Consequently, ifu0is nonnegative, the same holds foru. From Theorem A(ii) we can assume thatu0is bounded and therefore continuous inω¯×(0,∞), from the standard regularity theory for parabolic equations. Finally, for anyτ >0 there holds

u6uτ,1+uτ,2 (2.38)

onω¯ × [τ,)where theuτ,iare solutions of

tuτ,i− ∇. A(x)uτ,i

+b(x)uqτ,i=0 inω×(0,), (2.39) fori=1,2, with the boundary and initial conditions (remember thatuis continuous),

(uτ,1=0 on∂ω×(τ,), uτ,2=u on∂ω×(τ,), and

(uτ,1(. ,0)=u(. , τ ) inω,

uτ,2(. ,0)=0 inω. (2.40) Moreoveruτ,2(x, t)6ϕτ(x)inω× [τ,)for anyτ >0, where

−∇.(A(x)ϕτ)+b(x)ϕτq=0 inω, ϕτ(x)=sup

t>τ

u(x, t) on∂ω. (2.41)

By the assumption onb, there exist ω0⊂ ¯ω0ωand δ >0 such that inf essω\ ¯ω0b=δ.

Consequently forε >0 small enough the solutionψεof

−∇.(A(x)ψε)+δψε|ψε|q1=0 inω\ ¯ω0,

ψε(x)=ε on∂ω,

ψε(x)=0 on∂ω0,

(2.42)

is nonnegative and has compact support inω¯\ ¯ω0[5]. Defining ψeε=

ψε inω\ω0, 0 inω0,

and be=

δ inω\ω0, b inω0,

(2.43)

we see thatψeεis the unique solution of

−∇.(A(x)ψeε)+beψeεq=0 inω,

ψeε(x)=ε on∂ω.

(2.44) Since u(. , t)has exponential uniform decay whent→ ∞, there existsτ >0 such that kukL×(τ,))6ε. From the maximum principle ψeε>ϕτ, and consequently ϕτ has compact support inω\ ¯¯ ω0. From Remark 2.2, there existsT > τ such thatuτ,1(x, t)≡0

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inω¯× [T ,∞). Thereforeu≡0 inω¯0× [T ,∞). Because we can replaceω0by any larger strict subdomain ofω, it follows that ifKωis any compact subset andua solution of (2.36), there existsT =T (a, K,ku(. ,0)kL) >0 such thatu≡0 inK×[T ,∞). 2

3. The semi-classical analysis

The semi-classical analysis deals with the description of the behaviour of the spectrum of Hh2bϕ = −+h2b(.)ϕ when h >0 goes to zero. Writing Hh2bϕ = −+ αq1b(.)ϕ, then the first non-zero eigenvalueλ1=λ1(h)of this operator can be written as

λ1(h)=λ1(1q)/2)=µ(α). (3.1) We denote byσ (Hh2b, Ω)the spectrum of the Neumann realization ofHh2binL2(Ω).

Sinceis bounded, this spectrum is discreteσ (Hh2b, Ω)= {λj: j =1,2, . . .}. This is usually not the case if=RN. We also introduce the counting number ofHh2bdefined forθ >0 by

NHh−2b,Ω(θ )=cardλσ (Hh−2b, Ω): λ6θ . (3.2) The following theorem is the main result of this section.

THEOREM 3.1. – Suppose that N >1 and that b is a bounded, measurable and almost everywhere nonnegative function which is essentially positive near ∂Ω. If ln(1/b)∈Lp(Ω)for somep > N/2, then equation (2.3) satisfies the TCS-property.

Since we are dealing with Neumann boundary conditions, the assumption on the boundary lower bound of b is essential in our proof in order to extend some known estimates concerning spectrum of Schrödinger operators defined in the whole space to a bounded domain situation. The next lemma gives a very rough estimate on the behaviour ofλ1(h)whenhgoes to zero.

LEMMA 3.2. – Assume thatN >1 and thatb is a locally bounded and measurable function inΩ.

(i) If ess infb=η>0, then limh0h2λ1(h)=η.

(ii) Ifb(x) >0 for almost allx inΩ, then limh0λ1(h)= ∞.

Proof. – (i) It is always true thath2λ1(h)>ess minxb(x)=η. Letε(0,1), and ε = {x ∈Ω: η6b(x)6η+ε}. The set ε is measurable with positive measure, therefore almost all its points have density 1 with respect to Lebesgue measure [4] that is

rlim0

meas.(Br(x)ε)

meas.(Br(x)) =1 (for a.e.xε) (3.3) (Br(x) denoting the ball of center x and radius r >0). Let y be a point in ε such that (3.3) holds, then for any δ(0,1/2), there exists ρ0 >0 such that, for any 0< ρ6ρ0,

meas. Bρ(y)ε

>(1δ)meas. Bρ(y). (3.4)

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Let us define θ (ε, ρ) by θ (ε, ρ) =meas.(Bρ(y)\Ωε)/meas.(Bρ(y)); from (3.4) we deduce the inequality

06θ (ε, ρ)6δ. (3.5)

We denote by λ1,Bρ(y) the first eigenvalue of −1 in W01,2(Bρ(y)) and by ϕBρ(y) the corresponding eigenfunction with the normalizationRBρ(y)ϕB2ρ(y)dx=1. Let α(ε, ρ)= θ (ε, ρ)1/N. Since ϕBρ(y) is radially decreasing and since Bρ(y)ε and Bα(ε,ρ)ρ(y) have same measure, we obtain

Z

Bρ(y)\ε

ϕB2ρ(y)dx6 Z

Bαρ(y)

ϕB2ρ(y)dx, (3.6)

and, using (3.5) and the definition ofα, Z

Bρ(y)\ε

ϕB2ρ(y)dx6 Z

Bρδ1/N(y)

ϕB2ρ(y)dx.

ButϕBρ(y)(xy)=ρN/2ϕB1(y)((xy)/ρ), so we get Z

Bρδ1/N(y)

ϕB2ρ(y)dx= Z

Bδ1/N(y)

ϕB21(0)dx=γ (δ). (3.7)

It is clear thatγ (δ)→0 asδ→0, and we have Z

Bρ(y)\ε

ϕB2

ρ(y)dx6γ (δ). (3.8)

Finally

λ1(h)6 Z

Bρ(y)

|∇ϕBρ(y)|2+h2b(x)ϕB2ρ(y)dx 6λ1,Bρ(y)+h2

Z

Bρ(y)ε

b(x)ϕB2ρ(y)dx+h2kbkL

Z

Bαρ(y)

ϕB2ρ(y)dx

6λ1,Bρ(y)+h2+η)+h2kbkLγ (δ), (3.9) which implies that lim suph0h2λ1(h) 6+η)+ kbkLγ (δ). Since ε and δ are arbitrary, the claim follows.

(ii) Let us assume that (ii) does not hold and that there exists a positive constantCsuch that λ1(h)6C, for anyh >0. Letϕ1,h be the corresponding eigenfunction normalized by Rϕ1,h2 dx =1. Our assumption implies that ϕ1,h remains bounded inW1,2(Ω)and subsequently we can, by compactness, extract a subsequence {ϕ1,hn}such thatϕ1,hnϕ1,0 strongly in L2(Ω)as hn→0. But R(h2|∇ϕ1,h2 | +b(x)ϕ1,h2 )dx =h2λ1,h6h2C, thereforeRb(x)ϕ1,02 dx=0, which leads to a contradiction. 2

Références

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