C OMPOSITIO M ATHEMATICA
J OHN M YRON M ASLEY
Class numbers of real cyclic number fields with small conductor
Compositio Mathematica, tome 37, n
o3 (1978), p. 297-319
<http://www.numdam.org/item?id=CM_1978__37_3_297_0>
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297
CLASS NUMBERS OF REAL CYCLIC NUMBER FIELDS WITH SMALL CONDUCTOR
JOHN MYRON MASLEY
Sijthoff & Noordhoff International Publishers-Alphen aan den Rijn Printed in the Netherlands
By
analgebraic
number field F we shall mean a finite extension ofQ,
the field of rational numbers. The class number h
(F)
of F is the order ofC(F),
the group of ideal classes(non-zero
fractional ideals moduloprincipal ideals)
of F. The discriminant of F will be denotedd(F).
The Kronecker-Weber Theorem says that the abelian extensions ofQ
arethe subfields of all the full
cyclotomic
fieldsC(m)
=Q(exp 21Ti/m)
wherem is a
positive integer.
If K is an abelian extension ofQ,
the leastpositive integer f
withC(f) D
K is called the conductor of K and is denotedf (K).
SinceC(2f )
=C(f )
for oddf, f (K)
is either odd ordivisible
by
4.Hasse
compiled
many results about class numbers of abelian ex-tensions of
Q
in hismonograph [9].
Inparticular,
for K an abelianextension of
Q, h (K)
=h *(K)h (K’)
where K’ is the maximal realsubfield of K and the
quotient h(K)lh(K’)
=h*(K),
the relative classnumber of
K,
is aninteger.
WhenK = C(m)
we shall abbreviateh(C(m))
toh(m) = h*(m)h’(m)
withh’(m)
=h(Q(cos 21Tlm».
Hasseshows that
h *(K)
is very easy tocompute
and he lists the relative class numbers of allimaginary
abelian extensions ofQ
whose conductor does not exceed 100. In[8]
Hasse calculatedh(K)
for realcyclic KI Q
ofdegree
3 and 4 wheref (K):5
100.Hasse’s student
Leopoldt
took up the attack on the class number of real abelian extensions ofQ
in a series of papers[13-17].
Inparti- cular,
he showedthat, essentially,
one need consideronly
the classnumbers of the real
cyclic
extensions and some information on units.Bauer
[1]
used acomputer
to calculate the class numbers of most of the realcyclic
extensions ofQ
of conductor 5 100 via methods derived fromLeopoldt’s
results.In
previous
work[18-21],
we have determinedexplicitly
allpositive
integers m
withh(m):5
10. Oneingredient
needed in that workwas various
knowledge
about the class numbers of realcyclic
number fields with small conductor. Reference was made to
[1]
which covered most of the needed facts.Unfortunately
Bauer’spaper is
merely
areport
and does notgive
any details of how heapplied Leopoldt’s
results. A latercomputational
paper of Bauer[2]
does contain errors, so we wish to show that the results of
[1]
whichwe used are correct. We are able to
verify
the results of Bauer’scomputations
for all but 5 fields. We are also able tocompute
the class numbers of 13 fields for which Bauer’scomputations
wereincomplete.
Inparticular,
we show that the class number of any real abelian field ofprime
power conductor less than 71 has class numberone.
1. Root-discriminants and
Odlyzko
boundsIn this section we
develop
thetheory
of the root-discriminant and illustrate itsapplication
to class numberproblems.
DEFINITION: Let F be an extension of
Q
of finitedegree n
and discriminantd(F).
Then the root-discriminant ofF,
denotedrd(F),
isld(F) 1/n 1.
PROPOSITION 1.1: Let E D F both be
algebraic
numberfields.
Thenrd(E) > rd(F). Furthermore, equality
holdsif
andonly if
noprime
ideal
of
Framifies
in E.PROOF: Let
d(EI F)
be the absolute norm from F of the relative discriminant ideal forE/F. By
the relative discriminant formula for the towerEDFDQ,
we haveId(E)1 = d(EIF)ld(F)IIE:FI.
NowD(EIF) k
1 withequality
if andonly
if noprime ideal,
i.e. no finiteprime divisor,
of F ramifies in E. The result follows upontaking
JE:QL = JE:FL - IF:Ql-th roots
COROLLARY 1.2: Let F be an
algebraic
numberfield
and let E be any intermediatefield
between Fand the narrow Hilbertclass field of
F. Thenrd(E)
=rd(F).
Inparticular,
the Hilbert classfield of Fhas
the same rootdiscriminant as F.
PROOF: The narrow Hilbert class field of
F, N(F),
is the maximal abelian extension of F unramified at all finiteprime
divisors of F.By
(1.1)
we haverd (N(F)) > rd (E) > rd(F)
=rd(N(F)).
Inparticular,
N(F)
contains the Hilbert class field ofF.//
EXAMPLE 1.3: All the fields in the infinite Hilbert class field tower
of
Q(9699690l/2)
have root discriminant 6228.9-.EXAMPLE 1.4. We put
rd(m) = rd(C(m))
andrd’(m) = rd(C’(m)).
Ifat least two distinct
primes,
p and q say, are ramified inC(m),
thenrd(m)
=rd’(m).
This follows from(1.1)
sinceC(m)
=C’(m)C(p) = C’(m)C(q)
showsthat,
on the onehand,
at mostprime
ideals above pare ramified in
C(m)/C’(m) and,
on the otherhand,
at mostprime
ideals above q can be ramified.
(If
p =2,
useC(4)
instead ofC(2).)
PROPOSITION 1.5: Let F and K be
algebraic
numberfields
withrelatively prime
discriminants and let E be thecompositum of
F andK. Then
rd(E)
=rd(F) rd(K).
PROOF: This follows from the relation
PROPOSITION 1.6: The root-discriminants
rd(m)
ofC(m )
andrd’(m )
of
Q(cos 21rim)
aregiven by
for the
prime
powerpa #
2 where[x]
is thegreatest integer
in x, andrd(m)
=rd’(m) = npDllmrd(pa)
whenever at least twoprimes ramify
inC(m).
PROOF: It is well-known that
d(C(pa» = :tpalp(pD)-lp(pD)/(P-l).
Also(use
the conductor-discriminant
formula)
we have that[p/p - 1] .
p.d (C’(p a ))2 = ±d(C(p"))
so the root-discriminant values in theprime
power case followeasily.
Form = p ;1 p 22 ... p 1
t note thatC(m)
=C(prl)C(p22) ... C(p at)
andapply (1.5)
and(1.4)
To connect root-discriminants and class number bounds we need a new
concept.
DEFINITION: An
increasing
arithmetical arithmetical functiong :N -->
{x
ER l x
>01
is called a class number bound function(for totally
realfields)
if for allpositive integers
n we haveg(n) -«5
infrd (F)
where the infimum is taken over alltotally
real number fields ofdegree
n.Since all the fields in the Hilbert class field tower of
Q(96996901/2)
have the same root-discriminant
(1.3),
a class number bound function isnecessarily
bounded. The best bound is not known.Optimal
valuesof a class number bound function are known
only
for n =1,2,... ,7 [27].
The best known class number bound functions for class numberproblems
have been constructedby
AndrewOdlyzko
in a recentseries of articles
[23-26]
andpreprints dealing
with lower bounds forthe absolute values of discriminants of number fields. We have indicated in
[22]
how the results ofOdlyzko apply
to number fieldswhich are not
totally
real. For most of our purposes thefollowing special
case of
Odlyzko’s
work will be sufficient.THEOREM 1.7: There are
explicit
orderedpairs of positive
realnumbers
(A,E) for
whichg(A,E)(X)
=Ae-Elx
is a class number boundfunction.
Thefunction G(x)
= SUP(A,E)g(A,E)(X)
is also a class number boundfunction.
PROOF: The reader is referred to
[23-26]
and also to the survey article[27].//
We
give
a small table of values ofG(x)
which we used in our work in theappendix.
We can nowgive
the main result of this section.THEOREM 1.8:
(Class
NumberBound)
Let F be atotally
real numberfield
and letg(x)
be a class number boundfunction.
Theng(x)
>rd(F) implies h(F) xIIF:QI.
PROOF: Let
H(F)
be the Hilbert class field of F. We haveg(x)
>rd(F) = rd(H(F» 2: g(IH(F):Qf) = g(h(F) .IF:Qf)
and g is in-creasing.//
Since
g(x)
isnecessarily
bounded(Example 1.3),
Theorem 1.8 is usefulonly
for fields with small root discriminants. The best known upper bound forg(x)
is 1058.5+ and is due to Martinet[31].
2. Some
general
theorems.In this section we
give
somegeneral
results about the class numbers and ideal class groups of extensionsE/F
of number fields.We shall illustrate the results with abelian number
fields, especially
those which are
(totally)
real. Ofspecial
interest will beQ(cos 21rim)
which we shall denoteby C’(m),
the maximal real subfield ofC(m).
The discriminant and class number of
C’(m )
will be denotedby d’(m )
and
h’(m) respectively.
We shall also use the notationF(n,f)
todenote an n -th
degree cyclic
extension ofQ
with conductorf.
When nand
f
do not determine aunique field,
we shall beconsidering
all thefields with a
given n
andf
at the same time. We will mention other ways todistinguish
them when necessary.For a number field
F,
the Hilbert class fieldH(F)
is the maximal unramified abelian extension of F. Since the Galois group ofH(F)/F
iscanonically isomorphic
toC(F), IH(F):FI
=h(F).
The letter p shallalways
denote aprime
number.The
following
theorem enables one to characterize the relative class numberh *(m ).
THEOREM 2.1: Let
E/Fbe
an extensionof number fields. The following
are
equivalent :
(i)
For anyunramified
abelian extension Hof F,
E n H = F.(ii)
The norm mapN: C(E) - C(F)
issuilective.
If (i)
and(ii)
aresatisfied for EIF,
thenC(F)
isisomorphic
to asubgroup of C(E).
Inparticular, h(F)
dividesh(E)
and the orderof
thekemel
of
N ish (E)/ h (F).
PROOF:
By
class fieldtheory,
the unramified abelian extensions of F which are contained in Ecorrespond
in aninclusion-reversing
manner to the
subgroups
ofC(F)
which contain theimage
of thenorm map
N : C(E) - C(F).
When
(i)
and(ii)
aresatisfied, C(E)/ ker
N isisomorphic
toC(F).
Since a finite abelian group A is
isomorphic
to itsdual,
any factor group of A isisomorphic
to somesubgroup
ofA.//
If the
equivalent
conditions of Theorem 2.1 are satisfied for the extensionE/F,
then one seesdirectly
thath (F) =
JH(F):Fl = JEH(F):El
dividesIH(E):EI = h(E)
sinceEH(F)
CH(E).
Weincorporate
this weaker result inCOROLLARY 2.2
(Pushing up):
LetEIF
be an extensionof
numberfields.
ThenIH(F):H(F) nEI
dividesh(E)
andh(F)
dividesIE:Flh(E).
Inparticular, if for
anyunramified
abelian extension Hof
F we have E nH =
F,
thenh (F)
dividesh (E).
PROOF: We have
JH(F):H(F) nEl = JEH(F):El I dividing JH(E):EI.4e
We call an extension
EI F totally
ramified if no subextension ofEIF
except F itself is unramified over F.COROLLARY 2.3:
Suppose EIF
istotally ramified.
Thenh(F)
dividesh(E).
PROOF: For any unramified abelian extension
H of F, E fl H = F
since any extension of F contained in E istotally ramified.//
EXAMPLE 2.4: Let F C E C
C(p a )
Thenh (F)
dividesh (E).
COROLLARY 2.5: For the
cyclotomic fields
we haveh’(m)
dividesh(m), h’(m)
dividesh’(km),
andh(m)
dividesh(km) for
anypositive integer
k.PROOF: The extensions
C(m )/C’(m ), C’(km)/C’(m),
andC(km)/C(m)
aretotally ramified.//
The
preceding
resultsgive
information on the class group of anumber field which is
"pushed up"
from the class groups of certain subfields. We can also"push
down" information. Thefollowing
lemma is fundamental.
LEMMA 2.6: Let
EIF be
a non-trivialp-extension
which is un-ramified
outside the(possibly empt) finite
set Sof prime
divisorsof
F.
If S is empty, F has an unramified
cyclic
extension ofdegree
p.If v E
S, put
S’ =S - ivl. If p
dividesh (E),
then F has acyclic
extension of
degree
p which is unramified outside S’.PROOF:
Any
propersubgroup
of a p -group is contained in a normalsubgroup
of index p.Let S be
empty.
ThenGal(E/F)
contains a normalsubgroup
A ofindex p
and the subfield of E fixedby
A satisfies ourrequirements.
Suppose
v E S. Sincep ) h(E), P(E),
the maximal unramified abel- ianp -extension
ofE,
is a proper extension of E. If s is anyembedding
ofP(E)
into analgebraic
closure of F which restricts to theidentity
onF,
thens(E) = E
sinceEIF
is normal ands(P(E»Is(E)
is an unramified abelianp-extension. B y maximality, s (P (E))
=P(E)
soP (E)/F
is Galois. Let G =Gal(P (E)/F).
Now let T be an inertia group for a
prime w
ofP(E) lying
abovev. Since
P (E) #
E andP (E)/E
isunramified,
T is a propersubgroup
of G. Let N be a normal
subgroup
of Gcontaining
T withIG:NI
= pand let K be the subfield of
P(E)
fixedby
N. The inertia group T’ C G of anyprime
ofP(E) lying
above v isconjugate
in G toT,
hence is contained in N. It follows thatKIF
is unramified at v.Since
P(E)IF
is unramified outsideS, KIF
is then unramifiidoutside
S’./
We now have the
following
THEOREM 2.7
(Pushing down): Suppose EIF
is ap-extension
with atmost one
ramified prime
divisorof
Framified
in E. Then p dividesh(E) only if p
dividesh(F). If EI Fis totally ramified,
then p dividesh(E) if
andonly if p
dividesh(F).
PROOF:
By
Lemma2.6, H(F),
the Hilbert class field ofF,
containsa
cyclic
extension ofdegree
p over F. Hence p dividesh (F) _
JH(F):Fl.
If
E/F
istotally ramified, Corollary
2.3 shows thath(F)
dividesh(E)
so p inh (F)
wouldpush
up toh(E).Il
EXAMPLE 2.8:
If p
dividesh(pa), then
p dividesh(p).
EXAMPLE 2.9. Let p, q be
primes
with p = 1 mod2q.
Thenh(F(q,p))
isprime
to q. Inparticular,
for p = 1 mod4, Q(p 1/2)
has oddclass number.
THEOREM 2.10:
Suppose f
=4p,
pq, or2aq
with a *3,
p and q oddprimes,
and q = 3 mod 4. Then the maximal real abelian 2-extension Kof Q
with conductorf
has odd class number.PROOF:
By
ourassumptions,
there is a finiteprime
v ofQ
which isfully
ramified inK/Q.
Ifh (K)
is even, Lemma 2.6gives
us aquadratic
extension
LI Q,
unramified at v, with L contained inP(K),
the Hilbert2-class field of K.
By looking
at v we see thatKnL = Q
so thatK C LK C
P(K). However,
then LK is a real abelian 2-extension of conductorf properly containing K.//
EXAMPLE 2.11: The field
C’(68)
has odd class number.EXAMPLE 2.12: The
totally
real fieldsF(4, 87), F(4, 91),
andF(4, 95)
have odd class number since 7 = 19 = 3 mod 4.
EXAMPLE 2.13: The maximal real abelian 2-extension K of conductor 65 has odd class number. Theorem 2.10 and this result are
special
cases of results of Frohlich[4].
We prove that K has odd class numberdirectly.
SinceQ(51/2)
has aunique prime
above13,
Lemma 2.6 can be used toproduce
aquadratic
extensionL/Q(51/2)
ramifiedonly
at theprime
above 5 ifh(K)
is even. Since theonly
non-abelian2-group
which is asubgroup
of thesymmetric
group on 4 elements isD,
the dihedral group of order8,
N = the Galois closure of LoverQ
has Galois group D.However,
then an inertia group for the rationalprime
5 cannot becyclic
of order 4 or 8.The
following
theoremgives
information on the structure of ideal class groups.By
thep-rank
of a finite abelian group C we mean the dimension of the vector spaceZ/pZ0zC = C/{cp 1 c EE CI
over thefield
Z/p Z.
Thep-rank
of C is thus the number ofcyclic
factors in anelementary
divisordecomposition
of thep -Sylow subgroup
of C.Analogously, for q
=p a,
a anypositive integer,
we define theq-rank
of C to be the number of
cyclic
factors in anelementary
divisordecomposition
of thep-Sylow subgroup
of C whose order is divisibleby
q. Then we haveTHEOREM 2.14
(Structure):
LetEIF
be acyclic
extensionof degree
nand let
p be
aprime
which divides neither n norh(É) for
F CÉ C
E.Let q = p a for
somepositive integet
a. Then theq-rank of C(E)
is divisibleby f,
the orderof
p modulo n.PROOF: Assume the
q-rank
ofC(E)
is not zero. Weidentify C(E)
withGal(H(E)/E)
via the Artinreciprocity
law and put L = the subfield ofH(E)
fixedby Cq
={cal c E C(E)}.
The group G =Gal(E/F)
actsnaturally
onC(E) and,
fromproperties
of the Artinsymbol,
this actioncorresponds
to group theoreticconjugation
ofGal(H(E)/E) by
G. NowCq
is G-invariant so it is a normalsubgroup
ofGal(H(E)/F), L/F
isGalois,
and G acts on B =Gal(LI E) = C(E)/Cq.
To prove our
theorem,
it suffices to show that the action of G onB -
{1}
is faithful. For then the orbits of agenerator
of G will each have n elements so card B = 1 mod nand, consequently,
the order ofB =
B(q)
is a power ofpf.
Thep-rank
ofC(E)
isjust
theexponent
r = r1
with p’
= cardB(p).
For a > 1 and q =pa,
theq-rank
ofC(E)
isthe
exponent
r = ra withpr =card B(p’)/card B(pa-’). By
inductionon a we will have
f ) ra
f or anypositive integer
a. Inparticular,
thep-Sylow subgroup
ofC(E)
is then thef -fold
direct sum of an abelianp -group with itself.
To show G acts
faithfully, take g
E G and let S be thesubgroup generated by
g. For b E Bletgb
denote the result of the action of g on b andextending
this actionby additivity
consider B as aZ[G]-
module. Assume now that
g 0
1. We will be done if we show that(g - 1)B
= B for then g - 1 actssurjectively
on a finite set and thusinjectively.
Theinjectivity
shows that G acts as desired.Let
É
be the subfield of E fixedby
S. Now(g - 1)B
is asubgroup
of B on which S acts and hence is a normal
subgroup
ofGal(L/E).
Then
L,
the subfield of L fixedby (g - 1)B
is a normal extension ofÉ.
We
put
A =Gal(LIE)
and we haveB
=BI(g - 1)B
=Gal(LIE).
NowA/B = S and S
actstrivially
B.Since the order of S is
prime
to the order ofB,
the group extensionA/B splits
and we have the directproduct A
=B
x D where D = S.Let K be the fixed field of D so that
Gal(L/K)
= D andGal(K/E) =
A/D
= B.Suppose B
is non-trivial. Let P be anyprime
divisor ofL
with inertia group T for
L/É.
SinceL/E
is unramified at allprime divisors,
TnB
= 1. The groupsB
and D haverelatively prime
ordersso it follows that T is contained in D. This shows that
K/E
isunramified at all
prime
divisors. HenceK C H(É)
and sop h (É)
contradicting
ourhypothesis.
ThusB
= 0 and we aredone.//
COROLLARY 2.15
(Rank): Suppose E/Fis
acyclic
extensionof degree
n.Let p be a prime which does not divide h (2) forany field É with F
CÉ
CEand which does not divide n.
If
pl h (E)
then thep-rank of C(E)
is amultiple of f,
the orderof
p modulo n, andpf ) l h(E).
EXAMPLE 2.16: If a
prime p ~
29 dividesh’(59),
thenp f
wheref
isthe smallest
positive integer
withpf
= 1 mod 29 also dividesh’(59).
Since
h’(59)
isprime
to 29by
thePushing
Down Theorem(2.7),
wesee that
h’(59)
= 1 orh’(59) ?
59.However, d’(59)
51.27 so(1.8)
andthe class number bound function value
(Table
1 in theAppendix) G(340)
= 51.328 shows thath’(59) 340/29.
Henceh’(59)
= 1.EXAMPLE 2.17: From the
Odlyzko
class number boundfunction,
it is easy to see thath (F(3, 67))
4 andh(F(11, 67 ))
13. ThePushing
Down Theorem eliminates 3 and 11
respectively
from these class numbers. The RankCorollary (2.15)
shows thath(F(3, 67))
= 1 or 4 and also shows that if 11 ~ p 13 dividesh (F( 11, 67))
then so does apower
p f >
13. Henceh (F(11, 67))
= 1.Applying
the RankCorollary
now to
C’(67)
shows that ifp ~ 2, 3,
11 andp ;h’(67)
we must havepf >
199 andpf
a factor ofh’(67). (We
have used here the fact that67 X h’(67), [30].)
Since thePushing
Down Theorem eliminates 3 and 11 fromh’(67),
we see thath’(67)
is a power of 2(possibly 20)
or apower of 2 times a number greater than 198.
We have seen in
(2.5)
thath(m)
=h *(m )h’(m )
for a natural numberh*(m)
called the relative class number. When m = p there is aclassical closed formula for
h *(p ),
where the
product
runs over allprimitive,
odd(i.e. X(-I) = -1) Dirichlet characters X
of conductorf (X) dividing
p. This formula wasknown to Kummer and he called this the f ormula for the first factor
hl(p)
of thecyclotomic
class number ofp-th
roots ofunity. By replacing
pby
m in ourdefinition,
one obtains Kummer’sgeneral
formula for the first factorh,(m)
of thecyclotomic
class number ofm -th roots of
unity,
m ~ 2 mod4,
m odd. For m divisibleby 4,
the 2 outside theproduct
should bedropped
also.Correspondingly
thesecond factor
h2(m )
was for Kummer thequotient h(m)/h1(m),
Whenm is a
prime
powerpa,
thenhl(p’)
=h*(pa)
and soh2(P’)
is the classnumber of
C’(pa). However,
when more than one rationalprime
ramifies in
C(m), h*(m) = 2h1(m ) and, thus, h2(m )
is twice the classnumber of
C’(m). Kummer, however,
considered the second factor to be the class number ofC’(m )
because his class group was ideals modulo idealsgenerated by
an element ofpositive
norm. For Kum-mer and some others then the first factor of the
cyclotomic
classnumber is not
necessarily
aninteger
butonly
ahalf-integer.
In thispaper we use
exclusively
the relative class number which is aninteger.
The first factor
hl (p)
=h *(p )
enabled Kummer to tell whether aprime
was
regular (i.e. p§ h(p))
orirregular (p 1 h(p)),
because heproved
that p divided
h2(p )
=h’(p ) only
if p dividedh*(p).
Thisgeneralizes
as
follows;
THEOREM 2.19
(Kummer Criterion):
Let F be atotally
realalgebraic
number
field
and let p be an oddprime. Suppose
thatadjoining
ap-th
root
of
a rootof unity in FC(p)
toFC(p)
nevergives
anunramified
extension
of FC(p) of degree
p. Then p dividesh(F) implies
that p divides thequotient h (FC(p ))/ h (FC’(p )).
PROOF: Let K =
FC(p)
and K’ =FC’(p).
Ifp l l h(F),
then the Push-ing Up Corollary (2.2)
shows thatp lh(K’)
sincept IK’:FI
and so K’has a
cyclic,
unramified(totally real)
extension L ofdegree
p. Since L and K are both abelian extensions of L fl K =K’,
we see thatLKIK’
is a
cyclic
extension ofdegree 2p.
If s generatesGal(LKI K)
and J isthe
automorphism
of LK inducedby complex conjugation,
thensJ = Js is a
generator
ofGal(LK/K’).
As a Kummer extension of
K,
LK =K(a1/p)
for some non-zero a E K which is not thep -th
power of an element in K. Let a =a 1/P
bea fixed
p -th
root of a and let(Ja)"P
= Ja. Now sa =(la
ands(Ja) =
(2Ja
whereCi, C2
areprimitive p -th
roots ofunity.
ButC2Ja
=s(Ja) = J(sa) = C-11 Ja
sos (aJa ) = (sa)(sJa)
= aJa. It f ollows thata (Ja )
is ap -th
power in K. Since b =alJa = a 2I aJa
we get LK =K(a) =
K(a2)
=K(b"P).
Furthermore the ideal(b) generated by
b in K mustbe bP for some fractional ideal b of K
(since LKI K
isunramified)
withJb = b-1
because bJb = 1. The ideal class of b then is in the kernel of N :C(K) --> C(K’)
soby (2.1 )
we will be done if we prove that b is not aprincipal
ideal.If we had b =
(d)
with d EK,
thenb2p
=bP/(Jb)P
=(dlJd)P
=(u)P
where
u = dlJd.
Then(b 2) = (up)
so v =uPlb2
=(dP/a2)IJ(dP/a2)
is aunit of
K,
all of whoseconjugates
have absolute value one. But then the unramified extensionLKI K
isjust K(v 1/P)/ K
with v a root ofunity
in K contrary tohypothesis.//
COROLLARY 2.20 : Let Mbe the least common
multiple of
m and the oddprime
p. Then p dividesh’(m) only if
p dividesh*(M).
PROOF: When M = m, the result follows
immediately
sinceh(m) = h (M) = h *(M)h’(M) and (2.19) shows that p l h *(M).
When m = p this isthe case of Kummer’s
original criterion.
When
p X m, p h’(M)
wheneverp l h’(m) by (2.5).
We may arguethen as
above.//
We remark that
h *(p ) l h *(M) (see [21])
so anirregular prime
cannever be eliminated from
h’(m )
via(2.20).
There is a result
analogous
to(2.20)
for the case p = 2.THEOREM 2.21
(Parity check):
LetEIF
be aramified quadratic
extension
of
numberfields
with nocapitulation,
that is no non-principal
idealof
F becomesprincipal
in E. Thenh(F)
is evenonly if h(E)lh(F) is
even. Inparticular, h’(m)
is evenonly if h*(m)
is even.PROOF:
Suppose c E C(F), c2 = 1,
c ~ 1.By hypothesis C(F)
in-jects
intoC(E)
so we may consider c EC(E),
c ~ 1. Nowby (2.1)
thenorm map
N : C(E) --> C(F)
issurjective
and since Ne =c2 =
1 thekernel of N has even order
equal
toh (E)I h (F).
Inparticular, C(m )IC’(m )
is ramified at the infiniteprimes
andby
a theorem of Kronecker[12]
nonon-principal
ideal ofC’(m )
becomesprincipal
inC(m )./
THEOREM 2.22
(Cyclotomic spiegelungsatz):
Let p be anyprime
number and let M be the least common
multiple of
m and p. Then p dividesh’(m) only if
p dividesh *(M).
PROOF: Since
C(M)
=C(m)
when p =2,
this isjust
a restatement of(2.20)
and(2.21).//
EXAMPLE 2.23: For conductors
f - 100, h*(f )
is even([9], [29]) only
forf
=29, 39, 55, 56, 65, 68, 77, 87, 91,
and 95.Consequently h’(f )
isodd for all other conductors
f S 100.
Inparticular h’(pa)
is odd forp a
100 since(1.8)
can be used to showh’(29)
= 1.EXAMPLE 2.24: The relative class number
h *(3p )
isprime
to 3 forp =
71, 79, 89,
and 97(see [29]).
Henceh’(p)
isprime
to 3 for p =71, 79, 89, 97,
andby (2.4)
the class number of any real abelian number field with conductor71, 79, 89,
or 97 is alsoprime
to 3.Besides
eliminating possible
class number divisors one can some-times also find class number divisors. For abelian number fields there is a
generalization
of thetheory
of genera forquadratic
fields. For Kan abelian extension of
Q,
the genus field ofK, G(K),
is the maximal subfield of C( f (K))
such thatG(K)/K
is unramified at all finiteprimes.
For K ofprime
power conductor thenG(K)
= K. In that case or for K of odddegree
or for Knon-real, G (K)
is the maximalsubfield of
H(K)
which is still abelian overQ.
In these cases then non-trivial factorsof l G(K):Kl
are also factors ofh(K) = l1 H (K): KI.
In the
remaining
cases we may have Ktotally
real andG(K) totally imaginary
soG(K)I K
is ramified at infiniteprimes. However,
themaximal
real subfieldG’(K)
ofG(K)
is contained inH(K)
solG(K):Kl = lG(K):G’(K) l 1 G’(K):KI divides 2h(K).
Unlike the
quadratic
fieldtheory, however, only
a lower bound onthe
p-rank
ofC(K)
for K acyclic
extension ofdegree p
ispossible
viagenus
theory.
Forexample,
the genus field of anF(3, 79.97)
hasdegree
3 over that cubic field but the 3-rank ofC(F(3, 7663))
is 2 forboth of those cubic fields
([6]).
Bauer[1]
mentions that in each field K for which hesuccessfully
determined the class number there isonly
one class per genus. What is meant
by
this is thatG’(K)
is the same asH(K)
for those K.The genus field of an abelian extension K is
easily
determined via the Dirichlet characters attached to K. Since K CC(f (K», Gal(KIQ)
may be viewed as a factor group of
(Zif(K)Z)’,
themultiplicative
group of units mod
f(K).
The dual ofGal(K/ Q)
is then asubgroup
Hof the group of characters of
(Zlf(K)Z)X.
The characters in H may then be identified with asubgroup
of the Dirichlet characters modulof (K).
A Dirichletcharacter Xf
modf
is aproduct
of(not necessarily
primitive)
Dirichlet charactersXpa
modulopa, p a ll f,
where we callXpa
the
p-primary
component of Xf. One alsogets
aproduct
decom-position of Xf by replacing
eachp -primary component by
the Dirich-let character modulo
f
which it induces. Now we can characterizeG(K).
THEOREM 2.25: Let K be the abelian number
field of
conductorf corresponding
to thesubgroup
Hof
the group Dof
Dirichlet characters modulof.
Let G be thesubgroup of
D which isgenerated by
all thecharacters
of
D which are inducedfrom
ap-primary component of
any character in H. Then theabelian field G(K) of conductor f corresponding
to G is
thegenus field of K,
the maximal abelian extensionof K unramified
at all
finite primes
which is still abelian overQ.
PROOF: The reader is referred to
[131.,e
EXAMPLE 2.26: Let
p; - 1 mod q,
i =1, 2
where p1, p2,and q
are distinctprimes. Any
of theq - 1
fieldsF(q, P IP2) corresponds
to acyclic
group Hgenerated by
a Dirichlet character Xp1 Xp2 oforder q
where each
component
is non-trivial. The group Ggenerated by
the q-power characters mod pi,
1,
2 is a(q, q)
groupcorresponding
tothe field
G(F(q,PIP2)
=F(q, p l)F(q, P2).
Inparticular q l h(F(q, PlP2»
if
G(F(q, P1P2))
is real.REMARKS: The
Pushing
Down Theorem(2.7)
and the RankTheorem
(2.15)
aregeneralizations
of results of Iwasawa[10], [11].
Frôhlich derived 2.7 in
[5].
Ourproof
is more direct. Frôhlich also proves atype
of Structure Theorem in[3].
Theproof
of Kummer’sCriterion
(2.19)
isGreenberg’s [7] though
he states the result in a lessgeneral
f orm.3. The
prime-power
conductor case.In this section we
apply
the results of thepreceding
sections tocalculate the class numbers of most of the real
cyclic
number fields ofprime
power conductor less than 100. Our results arecompiled
in Table 2which we
explain
below. The class number was one for all the fields for which we were able to make acomplete computation.
This is not thegeneral
case as, forexample, h’(257)
is divisible(2.4) by
the classnumber of
Q(2571/2)
which is 3.Given any
prime
powerpa, C’(pa)/Q
iscyclic
so thedegree
of a real abelian field of conductorp a
determines aunique
field. In Table 2 welist for each field its
conductor,
itsdegree,
and its root-discriminant rounded up. If b is the value listed in the rd column forF(n, f )
thenb - .01
rd(F(n,f))
b. Weignore quadratic
fields since methods ofdetermining
their class numbers are well-known. The values of the class number bound functionG(x)
in Table 1 aretruncated,
so toreproduce
our work one should find the minimal x withG(x) > b
inorder to
apply
the Class Number Bound Theorem(1.8).
The bound we obtainedusing
that theorem is listed in the column headed "h :5". We used a morecomplete
table of values ofG(x)
so for a few fields the value in the "h " column will be less than that obtainedby using
Table 1. A blank in the "h -.5 " column indicates that
(1.8)
does notapply
since the root-discriminant exceeds all values ofG(x).
In the column marked "elimination" we indicate how
possible prime
divisors ofh(K)
are eliminated for the field K. We saw(2.23),
forexample,
thath’(pa)
is odd. We have indicated thisby
2PC sincethe
Parity
Check Theorem(2.21)
was used. From(2.4)
we see that allproper subfields of
C’(p a ), p a 100,
also have odd class number sincea 2
"pushes up"
toC’(pa).
We use PU to denote that thePushing Up Corollary (2.2)
was used. BecauseF C E C C’(pa) implies
thatEIF
has aunique
ramifiedprime,
thePushing
Down Theorem(2.7)
can often be used. This is indicatedby
PD. The use of the RankCorollary (2.15)
is indicatedby
R. We do not,however,
indicate whichauxiliary
fields are used when a
prime
is eliminated viaPU, PD,
or R. We also remark that there may be more than one way to eliminate aprime.
One other method used in this section is the
generalized
KummerCriterion
(2.19)
or its corollaries for which we use the notation K(see (2.24)).
Fordiagrams
of the fields involved in our considerations the reader is referred to the tables at the end of[9].
EXAMPLE 3.1: In
example
2.17 we saw thatF(11, 67)
had class number one and thatF(3, 67)
had class number 1 or 4.However,
2 inh (F(3, 67)) pushes
up toh’(67)
which violates theParity
CheckTheorem. We also saw that 3 and 11 in
h’(67)
can be eliminated via thePushing
Down Theorem. From theOdlyzko
Bound Theoremh’(67) 136
and 67 is theonly prime
power less than 137 which iscongruent
to 1 mod 33. Since67 X h’(67),
the RankCorollary
now shows thath’(67)
= 1.Our results
give
thefollowing:
THEOREM 3.2:
Any
real abelian numberfield of prime
power conductor less than 70 has class number one.We
conjecture
that 70 may bereplaced by
100. If thisconjecture
isfalse,
then we would have a zero of the Dedekind zeta function of anumber field whose real part would be
greater
than2.
This wouldoccur because
Odlyzko
hasproduced
a class number bound functiong(x)
with limg(x)
= 185+as x goes toinfinity by assuming
thatDedekind zeta functions of
totally
real fields have nozeroes ß
+iy
ina bounded
region
containedin 1/2 ß
1.Using
ourtechniques
we canuse this
improved
but conditional class number bound function toreplace
70by
100 in theorem 3.2.A blank in the "h = " column of Table 2 indicates that Bauer
[1]
computed h,
but we know of noindependent
verification. Aquestion
mark indicates that we are unaware of any
computation
of h. Weneed to refer to
[8]
to eliminate 5 for the fieldsF(4, 89)
andF(4, 97).
4. The
non-prime-power
conductor case.In this section we show how to calculate the class numbers of most of the real
cyclic
number fields whose conductor is not aprime
power and does not exceed 100. Our results arecompiled
in Table 3. Table 3 is very similar to Table 2. In this case,however,
there may be morethan one field with a
given degree
and conductor. In some cases, the root-discriminants candistinguish
the fields. When this is not the case, there is a doubleentry
to indicate that there are two fields with the sameconductor, degree,
and root-discriminant.Although
suchfields can have different class numbers
(for example,
the twoF(3,
79 -
97)’s,
see[6]),
this does not occur for conductors less than 100except possibly
forF(12, 91).
Another difference is the presence of genus factors. As we remar-
ked in section
2,
we must haveG(K)
= K forf (K)
=p a.
This is nolonger
the case whenf (K)
is not aprime
power. Hence the columnbetween "h " and "h = " is headed "divisors". A G indicates that the divisor is
present
fromIG’(K):KI (see 2.21).
In all other cases a reason is indicatedwhy
apossible prime
divisor of the class number h is eliminated. The notation is the same as in Table 2 with the addition of F to denote thatFr~hlich’s
results were used(see 2.10-2.13).
The genus factors are
always
taken into account first. Forexample, knowing
thath(F(3,91))
6 does not allow us to eliminate 2by
the Rank Theorem.However,
since3 / h(F(3, 91 )) by (2.26),4.X h (F(3, 91)).
Thefollowing
result was also used.PROPOSITION 4.1: Let