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Davenport series and almost-sure convergence

Julien Brémont

To cite this version:

Julien Brémont. Davenport series and almost-sure convergence. Quarterly Journal of Mathematics,

Oxford University Press (OUP), 2011, 62 (1), pp.825-843. �hal-00794135�

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Davenport series and almost-sure convergence

Julien Br´ emont

Universit´ e Paris-Est, janvier 2010

Abstract

We consider Davenport-like series with coefficients inl2 and discussL2-convergence as well as almost-everywhere convergence. We give an example where both fail to hold. We next improve former sufficient conditions under which these convergences are true.

1 Introduction

LetR\Zbe the Circle andL2 be the restriction of the spaceL2(R\Z→R) to odd functions.

For a real parameterλ >1/2, we introduce the map : gλ(x) = X

m≥1

sin(2πmx) mλ .

This function is defined everywhere onR\Z. It is continuous, except at 0 when 1/2< λ≤1, and belongs toL2. For real sequences (an)∈l2, we consider expansions based on the dilated functions system{gλ(nx)}n≥1 of the following form :

Xangλ(nx), (1)

where we writePfor the summationP+∞

n=1. We are interested in the questions ofL2-convergence and Lebesgue almost-everywhere (a.e) convergence of such series.

This is a natural problem which can be formulated withgλ replaced by a generalg∈L2(R\Z).

A reason for focusing on odd functions is that sin series in general better converge than cos series.

Wheng(x) = sin(2πx), theL2-convergence ofPang(nx) follows from the fact that the{g(nx)}n≥1

are orthonormal. A.e-convergence in this case is the difficult theorem of Carleson [4]. For a different g such that the {g(nx)}n≥1 are complete inL2, the{g(nx)}n≥1 are not orthogonal, see Bourgin and Mendel [2], and the question of L2-convergence is already not clear. The case of g = gλ was introduced by Wintner in [17]. A special motivation comes Arithmetics and the caseλ= 1, corresponding to the first Bernoulli polynomial or “sawtooth function”{x}:=x−[x]−1/2, where [x] is the integer part ofx∈R. Indeed :

{x} = −1 π

X

m≥1

sin(2πmx)

m .

Series of the formPan{nx} appear since long ago in the litterature, at the interface of Number Theory and Analysis. We recommend the very detailed presentation of such series by Jaffard in [12], where they are called Davenport series, due to Davenport’s initial systematic study [5, 6]. In

AMS2000subject classifications : 11A25, 26A30, 42A16, 42A61, 60F05

Key words and phrases : Davenport series, Carlitz’s lemma,L2-convergence, almost-everywhere convergence.

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this article and for simplicity we callDλ-series a series of the form (1), the case of Davenport series corresponding toλ= 1.

Beginning with a discussion in L2, Wintner [17] established that the family {gλ(nx)}n≥1 is complete inL2for anyλ >1/2. We now consider theL2-convergence ofDλ-series with (an)∈l2. According to work by Wintner [17] and next Hedenmalm, Lindqvist and Seip [11], the{gλ(nx)}n≥1

form a Riesz basis whenλ >1. By a “Riesz basis” we mean a complete sequence (ξn) in L2 such that for some constantC >0 :

C−1X

a2n≤ kX

anξnk2≤CX

a2n, ∀(an)∈l2.

Here and in the whole article we denote byk kthe usualL2-norm, with scalar producth,i. Lindqvist and Seip [15] provide the inequalities :

ζ(2λ) ζ(λ)2

Xa2n≤ kX

angλ(nx)k2≤ ζ(λ)2 ζ(2λ)

Xa2n,

where ζ(s) = P

n≥1n−s, for s > 1, is the Riemann Zeta function. Constants are optimal. This settles the question of L2-convergence when λ >1. In this case, the a.e-convergence ofDλ-series for (an)∈l2 follows from Carleson’s theorem [4] on the a.e-convergence of Fourier series. Indeed :

N

X

n=1

angλ(nx) = X

m≥1

m−λ

N

X

n=1

ansin(2πmnx). (2)

For eachm≥1,PN

n=1ansin(2πmnx) converges a.e, asN →+∞, by Carleson’s theorem. Next :

|

N

X

n=1

ansin(2πmnx)| ≤ sup

K≥1

|

K

X

n=1

ansin(2πmnx)|=:M(mx).

By classical work on the maximal operator,kMkL1(R\Z)≤CP

a2n (cf for instance Fefferman [7]).

Thus P

m≥1m−λM(mx) is integrable and in particular a.e finite. One can now a.e apply the Lebesgue dominated convergence theorem in (2) to conclude. Of course this argument does not work when 1/2< λ≤1. Mention also that Carleson’s theorem uses properties of the Fourier basis.

There exists orthonormal bases of L2 for whichL2-convergence does not imply a.e-convergence, see Rademacher [16].

For the rest of the article we suppose that 1/2 < λ≤1. As a consequence of an analysis by Wintner [17] of some Dirichlet series associated to Dλ-series, for any 1/2 < λ ≤ 1 there exists (an)∈l2such thatPangλ(nx) isL2-divergent. In particular for 1/2< λ≤1, the{gλ(nx)}n≥1do not form a Riesz basis ofL2. We now detail known sufficient conditions forL2and a.e-convergence.

We are essentially aware of results concerning Davenport series. Wintner [17] proved thatP an{nx}

converges inL2 wheneveran =O(n−κ), withκ >1/2. Extending this result, Jaffard [12] showed that for (an) ∈l2 the sum P

an{nx} converges in a Sobolev space very close to L2. About a.e- convergence, Davenport in his fundamental papers [5, 6] gave non-trivial arithmetical examples where a.e-convergence is true, such as :

+∞

X

n=1

λ(n) n {nx},

+∞

X

n=1

Λ(n) n {nx},

+∞

X

n=1

µ(n)

n2 {n2x}, (3)

whereλ(n), Λ(n) and µ(n) are respectively Liouville’s function, Von Mangolt’s function and Mo- bius’ function. When the an are slowly varying, the a.e-convergence of Pan{nx} follows, via an Abel transform, from estimates on P

n<N{nx}, cf Lang [14]. Jaffard [12] deduced the a.e- convergence ofPan{nx}, whenever an =O(logn)−α and an+1−an = O(n−1(logn)−(1+α)) for someα >2. In particular, Hecke series :

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Hs(x) =

+∞

X

n=1

{nx}

ns (4)

converge a.e for Re(s) > 0, a result already shown by Hardy and Littlewood [8]. For general sequences, Hartman proved in [9] the a.e-convergence of Pan{nx} when an = O(n−κ), with κ > 2/3. Mention finally some results going further than a.e-convergence. Using P-summation techniques, de la Bretˆeche and Tenenbaum [3] proved that (4) is convergent whens = 1 outside a set of Hausdorff dimension zero that they describe. Also the second series in (3) is everywhere convergent.

We now detail the content of the article. We discuss theL2and a.e-convergence ofDλ-series of the form (1) for general (an)∈l2. We first complete the L2-divergence result of Wintner [17] by an a.e-divergence result. We next improve former sufficient conditions forL2 and a.e-convergence.

Theorem 1.1

Assume that1/2< λ≤1.

i) There exists(an)∈l2 such that Pangλ(nx)is simultaneouslyL2-divergent and a.e-divergent.

ii) Suppose that for someε >0 :





Pa2nn

(1+ε)(logn)−(2λ−1)

2(1−λ) log logn <∞, when 1/2< λ <1, Pa2n(logn)3(log logn)2+ε<∞, whenλ= 1.

ThenP

angλ(nx) converges inL2 and a.e.

In particular, the latter conditions are verified if P

a2nnε<∞, for some ε >0. For example, the following series converge inL2and a.e when s >1/2 :

+∞

X

n=1

λ(n) ns {nx},

+∞

X

n=1

Λ(n)

ns {nx}and

+∞

X

n=1

µ(n) n2s {n2x}.

We note that whereas Wintner’s approach is abstract we build here an explicit example. The fact that (an) ∈ l2 does not imply the a.e-convergence ofDλ-series is not that surprising, since this condition is not the correct one forL2-convergence. One can make the second moment explode and develop a probabilistic argument based on the Central Limit Theorem. The true question, more difficult, is whetherL2-convergence implies a.e-convergence. A weak formulation is as follows : Question. If 1/2< λ≤1 andP

k≥1

P

n≥1n−λ|akn|2

<+∞, doesP

angλ(nx) converge a.e ? The above condition is strictly stronger than (an)∈l2, when 1/2< λ≤1. As detailed below, it ensures theL2-convergence ofPangλ(nx) and is necessary when thean have constant sign.

We next consider three classical situations, for instance Hadamard lacunarity, where we can proveL2-convergence, but a.e-convergence only under stronger conditions. We define the support supp(n) of an integernas its set of prime divisors and write|supp(n)|for the cardinal of this set.

Theorem 1.2

Suppose that1/2< λ≤1.

i) Let(nk)checknk+1/nk ≥c, wherec >1. ThenP

akgλ(nkx)converges inL2whenever(ak)∈l2 and more precisely :

C1 X

a2k ≤ kX

akgλ(nkx)k2≤C2 X a2k,

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where :

C1= (1−1/e)ζ(4λ) 2

2λ−1 2λ

ln(c2λ−1) 1 + ln(c2λ−1)

2

andC2= ζ(2λ) 2

cλ+ 1 cλ−1

.

If the stronger conditionP

a2k(logk)2<∞ is verified, thenP

akgλ(nkx)is also a.e-convergent.

ii) If(an)∈ l2 and {|supp(n)|, an 6= 0} is finite, then Pangλ(nx) converges in L2. In fact, for N ≥1 there existsC(λ, N)>0such that for (an)∈l2 withan= 0 if|supp(n)|> N, then :

C−1(λ, N) X

a2n≤ kX

angλ(nx)k2≤C(λ, N) X a2n. If moreoverPa2n(logn)2<∞, thenPangλ(nx)is also a.e-convergent.

iii) Let an = O(bn), where (bn)n≥1 ∈ l2∩(R+)N satisfies bnm = bnbm whenever n and m are relatively prime. ThenPangλ(nx)converges inL2.

A word on the method. The study of the convergence of Davenport series often starts with trying to writeP

an{nx}as a Fourier seriesP

cmsin 2πmx. It was indeed remarked by Davenport [5] that formally the (cm) are explicitly given in terms of the (an) and vice-versa. An alternative approach, developed here, when consideringL2-convergence is to orthonormalize the{gλ(nx)}n≥1. The Gram-Schmidt orthonormalisation procedure is explicit and a consequence of Carlitz’s lemma on the reduction of quadratic forms. We provide details for simplicity. This furnishes a rather simple characterization ofL2-convergence. Theorem 1.2 follows via more or less standard compu- tations. Concerning a.e-convergence, the orthonormalisation approach allows to adapt a technique of Rademacher [16] initially developed for the pointwise convergence of series built with general orthonormal systems.

A few notations. We writei∧j andi∨j respectively for the greatest common divisor and the smallest common multiple of integersiandj. The set of primes isP ={pn, n≥1}.

2 Orthonormalization

Recall that 1/2 < λ ≤1. We first study correlations. The following computation is already contained in Lindqvist and Seip [15].

Lemma 2.1

Let i, j≥1. Thenhgλ(i.), gλ(j.)i= ζ(2λ) 2

i∧j i∨j

λ . Proof of the lemma :

Leti0 = i/i∧j, j0 = j/i∧j. Since Lebesgue measure on R\Z is invariant by x7−→ px for any integerp, we havehgλ(i.), gλ(j.)i=hgλ(i0.), gλ(j0.)i. Using the Fourier expansion ofgλ :

hgλ(i0.), gλ(j0.)i = X

k,l≥1

Z 1 0

sin(2πki0x) kλ

sin(2πlj0x)

lλ dx= 1 2

X

m≥1

1

(m2i0j0)λ =ζ(2λ)

2 (i0j0)−λ, since a relationki0 =lj0 reduces tok=j0mand l=i0m for some integerm. This concludes the

proof of the lemma.

Remark. — The correlations being positive, ifP

bngλ(nx) isL2-convergent with (bn)∈(R+)Nand ifan =O(bn), thenP

angλ(nx) also converges inL2.

We turn to the orthonormalization of the {gλ(nx)}n≥1. The following proposition is an appli- cation of Carlitz’s lemma, cf for instance Haukkanen, Wang and Sillanp [10].

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Recall that the M¨obius functionµon the integers is defined byµ(1) = 1,µ(pi1· · ·pik) = (−1)k andµ(n) = 0 if n is not square-free. Iff and g are real maps defined on the integers related by f(n) =P

k|ng(k), then (M¨obius inversion formula) we haveg(n) =P

k|nµ(n/k)f(k).

Proposition 2.2 i) Let fn,λ(x) =n−λX

k|n

kλµ(n/k)gλ(kx),n≥1. Then{fn,λ}n≥1 is an orthogonal family with : kfn,λk2= ζ(2λ)

2 Y

p|n,p∈P

1−p−2λ

∈ 1

2,ζ(2λ) 2

.

The{fn,λ}n≥1 form an orthogonal Riesz basis of L2, with : 2ζ(2λ)−1X

n≥1

hfn,λ, hi2≤ khk2≤2X

n≥1

hfn,λ, hi2,∀h∈L2.

ii) An equality Pn

i=1aigλ(i.) = Pn

i=1bifi,λ holds if and only if bi = P[n/i]

k=1 k−λaki, 1 ≤ i ≤n.

These equalities are reversed intoai=P[n/i]

k=1 k−λµ(k)bki, 1≤i≤n.

Proof of the proposition :

Letn≥1. We introducen-square matricesDandT, whereDis diagonal andTis upper-triangular.

SetT = (tij) withtij =j−λ1i|j and write D= diag(di), where the (di) are defined below. First : (tT DT)ij = X

1≤k≤n

tkidktkj= (ij)−λ X

k|i∧j

dk.

We chooseDso thatP

k|mdk= (ζ(2λ)/2)m, which by the M¨obius inversion formula corresponds to settingdk= (ζ(2λ)/2)P

l|kµ(k/l)l. Lemma 2.1 gives (tT DT)ij =hgλ(i.), gλ(j.)i.

Next, the inverse ofT is given byTij−1= 1i|jiλµ(j/i), since for anyi≤j :

n

X

k=1

1i|kiλµ(k/i)j−λ1k|j= 1i|jiλj−λX

l|j/i

µ(l) = 1i=j,

using thatP

k|mµ(k) = 0, ifm≥2. Observe thatfi,λ=i−λP

1≤k≤n(tT−1)ikgλ(k.), for 1≤i≤n.

The{fi,λ}i≥1 are therefore orthogonal in L2, with kfi,λk2 =dii−2λ. They also form a complete family, since it is the case for the{gλ(nx)}, cf Wintner [17]. Decomposingi=pαl1

1 · · ·pαlk

k in prime factors, we have :

kfi,λk2=ζ(2λ) 2

X

d|i

d−2λµ(d) =ζ(2λ) 2

k

Y

j=1

X

d|pαjlj

d−2λµ(d) = ζ(2λ) 2

Y

p|i, p∈P

(1−p−2λ).

Finally :

n

X

i=1

aigλ(i.) =

n

X

i=1

ai n

X

k=1

(tT)ikkλfk,λ=

n

X

i=1

ai n

X

k=1

i−λ1k|ikλfk,λ=

n

X

k=1

fk,λ [n/k]

X

i=1

i−λaki.

The reversed formula is proved in a similar way.

We deduce the following characterization ofL2-convergence.

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Corollary 2.3

i) The seriesPangλ(nx)converges inL2if and only if the numerical seriesP

k≥1k−λakiconverge for alli≥1, together with the uniformity condition :

X

i≥1

 X

k>[n/i]

k−λaki

2

→0, asn→ ∞.

ii) A sufficient condition forPangλ(nx)to beL2-convergent is :

X

i≥1

 X

k≥1

k−λ|aki|

2

<+∞.

This condition is necessary when(an)∈(R+)N. Proof of the corollary :

If Pangλ(nx) converges in L2, by proposition 2.2 the component P[n/i]

k=1 k−λaki with respect to each fi,λ converges as n → +∞. The L2-limit then has to be P

i≥1fi,λ(P

k≥1k−λaki). The uniformity condition is a consequence from the fact that the norm offi,λbelongs to (1/2, ζ(2λ)/2).

The first assertion of the second item is an application of the Lebesgue Dominated Convergence Theorem, whereas the second one follows from the first item.

Remark. — Corollary 2.3 can also be obtained when considering directly the Fourier expansion ofP

angλ(nx) given bygλ. In the sequel, the orthonormalization point of view has the practical advantage to keep finite all partial sums.

3 A l

2

-example of a L

2

-divergent and a.e-divergent series

We prove theorem 1.1i), using that for 1/2< λ≤1 the seriesP

p∈Pp−λ is divergent. For each integerK≥1, we choose a finite setPK ={pj,K}1≤j≤lK of consecutive primes satisfying :

lK

X

j=1

(pj,K)−λ≥K. (5)

We fixmK ≥2 so that

mK−1 mK

lK

≥1/2. Introduce sets :





F1,K=n

pu1,K1 · · ·pullK

K,K ,1≤u1,· · ·, ulK ≤mKo F1,K0 =n

pu1,K1 · · ·pullK

K,K ,1≤u1,· · ·, ulK ≤mK−1o .

We have|F1,K|= (mK)lK and|F1,K0 |= (mK−1)lK. Letq1,K= 1 and take next infinitely many primesq2,K<· · ·< qn,K<· · ·, larger thanplK,K and subject to the condition :

(p1,K· · ·plK,K)mK

1 + (mK)lK/2 K

+∞

X

r=2

(qr−1,K)r−1 qr,K

≤ 1

K. (6)

Define the random variable :

X1,K= 1 K|F1,K|1/2

X

n∈F1,K

gλ(nx).

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It has zero mean and belongs toL2. We write σK2 =R1

0(X1,K)2(x)dxfor its variance and choose an integerTK≥K so that :

Z 1 0

(X1,K)2(x)1{|X1,K|>(TK)1/12σK} dx≤ 1

K. (7)

We define another collection of sets :

F2,K=q2,KF1,K F2,K0 =q2,KF1,K0

· · ·

FTK,K=qTK,KF1,K FT0K,K=qTK,KF1,K0 . Grouping sets, we define :

EK =

TK

[

r=1

Fr,K andEK0 =

TK

[

r=1

Fr,K0 .

We have|EK|=TK|F1,K|and|EK0 |=TK|F1,K0 |. In particular :

|EK0 |

|EK| =|F1,K0 |

|F1,K| =

mK−1 mK

lK

≥ 1

2. (8)

When considering the next integer (ieK+ 1) we start withp1,K+1> qTK,K(p1,K· · ·plK,K)mK. Observe that all the (Fr,K)K≥1,1≤r≤TK, are pairwise disjoint and in particular the (EK)K≥1, which furthermore are consecutive. We finally set :

an=





1

K|EK|1/2 , whenn∈EK, for some K≥1,

0 , otherwise.

This completes the definition of the sequence (an). FormallyPangλ(nx) =P

K≥1ZK, with : ZK= 1

√TK

TK

X

r=1

Xr,K(x) andXr,K(x) = 1 K|F1,K|1/2

X

n∈Fr,K

gλ(nx). (9)

From the previous construction, observe that a partial sumPN

K=1ZK(x) corresponds to a partial sum ofPangλ(nx). We now proceed to verifications.

i) The sequence (an) belongs tol2. Indeed : X

n≥1

a2n= X

K≥1

X

n∈EK

1

K2|EK| = X

K≥1

1 K2 <∞.

ii) The seriesP

angλ(nx) isL2-divergent. Indeed, using (5) and (8) :

X

n≥1

 X

k≥1

k−λakn

2

≥ X

K≥1

X

n∈EK0

 X

k≥1

k−λakn

2

≥ X

K≥1

X

n∈EK0

X

k∈PK

k−λakn

!2

≥ X

K≥1

X

n∈EK0

1 K2|EK|

X

k∈PK

k−λ

!2

≥ X

K≥1

|EK0 | K2

K2|EK| ≥ X

K≥1

1

2 = +∞.

Since thean are positive, the conclusion comes from corollary 2.3.

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iii) The seriesPangλ(nx) is a.e-divergent. This requires longer computations. For a fixedK≥1, all (Xr,K)1≤r≤TK have the same law, due to the invariance of Lebesgue measure on R\Z under multiplication by an integer. They do not form a stationary process, but are nearly independent.

Under our hypotheses, it is routine to check that the law of (σ2KTK)−1/2PTK

r=1Xr,K is asymptoti- cally normal.

In a first step, we compute the variance σK2 and verify that it grows rapidly to infinity, as suggested byii). Via lemma 2.1, we have :

σ2K= Var(X1,K) = ζ(2λ) 2

1 K2(mK)lK

X

n,m∈F1,K

n∧m n∨m

λ

= ζ(2λ) 2

1 K2(mK)lK

X

1≤aj,bj≤mK,1≤j≤lK lK

Y

j=1

(pj,K)−λ|aj−bj|

= ζ(2λ) 2

1 K2(mK)lK

lK

Y

j=1

mK

X

a,b=1

(pj,K)−λ|a−b|

= ζ(2λ) 2

1 K2(mK)lK

lK

Y

j=1

mK+ 2(pj,K)−λ(mK−1)

mK−1

X

k=1

k(pj,K)λ(k−1)

! .

Forx >1, we havePn−1

k=1kxk−1 = ((n−1)xn−nxn−1+ 1)/(x−1)2 =nxn−2(1 +o(1)), whenx andnare large. Inserting this in the previous calculations, we obtain, with a uniformo(1) :

σ2K = ζ(2λ) 2

1 K2(mK)lK

lK

Y

j=1

mK+ 2mK(pj,K)−λ(1 +o(1))

= ζ(2λ) 2

1

K2ePlKj=1log(1+2(pj,K)−λ(1+o(1)))

= ζ(2λ) 2

1 K2e2

PlK

j=1(pj,K)−λ (1+o(1))

≥eK, (10)

for largeK, using (5).

We now establish the convergence : (σK2TK)−1/2

TK

X

r=1

Xr,K→ N(0,1), in law. (11)

We write E for the expectation under Lebesgue measure on R\Z. Set Yr,K = (σK2TK)−1/2Xr,K

andSN =PN

r=1Yr,K. For 1≤r≤TK, introduce the finite partitions : Fr={[k/qr,K,(k+ 1)/qr,K), 0≤k < qr,K}.

EachYr,K being (1/qr,K)-periodic, for a bounded measurablef :

E(f(Yr,K)) =E(f(Yr,K)|Fr). (12) Fort∈Rand 2≤N≤TK, we have :

E(eitSN) = E(eitSN−1eitYN,K)

= E(E(eitSN−1|FN)eitYN,K) +E((eitSN−1−E(eitSN−1|FN))eitYN,K)

= A + B.

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First of all, taking conditional expectation and using (12) :

A=E(E(eitSN−1|FN)E(eitYN,K|FN)) = E(E(eitSN−1|FN)E(eitYN,K))

= E(eitSN−1)E(eitYN,K). (13) Next :

|B| ≤E(|eitSN−1−E(eitSN−1|FN)|). (14) The mapx7−→eitxis|t|-Lipschitz. On each piece ofFN which contains no discontinuity ofSN−1, when counting the oscillation we have :

|eitSN−1−E(eitSN−1|FN)| ≤ |t|

qN,K

2KTK)−1/2 (K(mK)lK))1/2

N−1

X

r=1

(mK)lK(p1,K· · ·plK,K)mKqr,K

≤ |t|

(mK)lK/2

K (p1,K· · ·plK,K)mK

(N−1)qN−1,K

qN,K , (15)

sinceTK ≥K and σK ≥1 for large K, by (10). Next, SN−1 is continuous on the interior of each segment of the partition whose step−1 is q1,K· · ·qN−1,K(p1,K· · ·plK,K)mK. The total measure of the pieces ofFN which may contain a discontinuity ofSN−1 is bounded from above by :

q1,K· · ·qN−1,K(p1,K· · ·plK,K)mK 1

qN,K ≤(p1,K· · ·plK,K)mK(qN−1,K)N−1

qN,K . (16)

From (14), (15) and (16), we deduce that :

|B| ≤ 2(1 +|t|)(p1,K· · ·plK,K)mK

1 +(mK)lK/2 K

(qN−1,K)N−1

qN,K . (17)

Using that for all 1≤N ≤TK, we have |E(eitYN,K)| ≤1, when iterating the procedure with (13) and (14), we obtain via (6) :

|E(eitSTK)−

TK

Y

r=1

E(eitYr,K)| ≤ 2(1 +|t|)(p1,K· · ·plK,K)mK

1 +(mK)lK/2 K

TK

X

r=2

(qr−1,K)r−1 qr,K

≤ 2(1 +|t|)1

K. (18)

As a consequence of (18), in order to show (11) we only need to focus on :

TK

Y

r=1

E(eitYr,K) =E(eitY1,K)TK. (19) We now use the fact that for allt∈R:

|eit−(1 +it−t2/2)| ≤min{|t|3/6,|t|2}, (20) which comes fromeit−(1 +it−t2/2) = i3/2Rt

0(t−s)2eis ds=i2Rt

0(t−s)(eis−1) ds. Via (20) and the property thatX1,K has zero mean, we now deduce the following inequalities :

(11)

E eitY1,K

1− t2 2TK

≤ E

eitY1,K

1 +itY1,K−t2 2Y1,K2

≤ E

eitY1,K

1 +itY1,K−t2 2Y1,K2

≤ E min{|tY1,K|3/6,|tY1,K|2} .

Withε= (TK)−5/12and using (7), as well as TK ≥K andσK ≥1 for largeK:

E eitY1,K

1− t2 2TK

≤ |t|3

6 E |Y1,K|31|Y1,K|≤ε

+|t|2E |Y1,K|21|Y1,K|>ε

≤ |t|3

6(TK)5/4 + |t|2 σ2KTK

E

|X1,K|21|X1,K|>(TK)1/12σK

≤ 1 TK

|t|3

6(TK)1/4 + |t|22K

≤ 1 TK

|t|3

6K1/4 +|t|2 K

. (21)

SinceTK →+∞, as K →+∞, we deduce from (18), (19) and (21) that E(eitSTK)→e−t2/2, as K→+∞, for allt∈R. This proves (11).

To conclude, for allL≥1 we chooseKL≥Lso that : P(|STKL| ≤1/L2)≤2

Z

|t|≤1/L2

dN(0,1)(t) =:δL. Clearly P

L≥1δL <∞, so by Borel-Cantelli’s lemma, for a.e x when L is large enough we have

|STKL| ≥1/L2. For such ax, using (10) and whenLis large enough :

|ZKL|=

1 pTKL

TKL

X

r=1

Xr,KL(x)

KL|STKL| ≥ eKL/2

L2 ≥ eL/2 L2 .

Since partial sumsPN

K=1ZK(x) are partial sums ofPangλ(nx), this preventsPangλ(nx) from converging atx. This completes the proof of itemi) of theorem 1.1.

4 Sufficient conditions for L

2

and a.e-convergence

We take a finite sequence (an) and writePangλ(nx) =Pbnfn,λ(x), where (bn) is also finite.

By proposition 2.2 :

kX

angλ(nx)k2=kX

bnfn,λk2≤ ζ(2λ) 2

Xb2n ≤ζ(2λ) 2

X

n≥1

 X

k≥1

k−λ|akn|

2

.

Set ψλ(k) = k1−λ(logk)2 if 1/2 < λ < 1 and ψ1(k) = logk(log logk)1+ε, for some ε > 0. For simplicity we write log(x) for max{1,log(x)}. Using Cauchy-Schwarz’s inequality :

(12)

X

n≥1

 X

k≥1

k−λ|akn|

2

= X

k,k0≥1

(kk0)−λX

n≥1

|ankank0| ≤ X

k,k0≥1

(kk0)−λ

 X

n≥1

a2nk

1/2

 X

n≥1

a2nk0

1/2

 X

k≥1

k−λ

 X

n≥1

a2nk

1/2

2

 X

k≥1

k−λ 1 ψλ(k)

 X

k≥1

k−λψλ(k)X

n≥1

a2nk

≤ CεX

n≥1

a2nX

k|n

k−λψλ(k). (22)

We first consider the case 1/2< λ <1. Remark that 0<2λ−1<1. Using a classical upper-bound forP

k|nk2λ−1, cf Kr¨atzel [13], we have for anyδ >0 : X

k|n

k−λψλ(k) = X

k|n

k1−2λ(logk)2≤(logn)2X

k|n

k1−2λ≤(logn)2n1−2λX

k|n

k2λ−1

≤ (logn)2n1−2λCδn2λ−1e(1+δ)(logn)1

−(2λ−1)

(1−(2λ−1)) log logn ≤Cδ0n(1+2δ)(logn)1

−2λ 2(1−λ) log logn .

In the situation whenλ= 1, we have : X

k|n

k−1ψ1(k)≤ψ1(n)X

k|n

k−11(n)n−1X

k|n

k.

We use this time the inequalityP

k|nk≤Cnlog logn, see again [13]. As a result, for any ε >0 there is a constantCε>0 such that for any sequence (an) :





kPangλ(nx)k2≤CεPa2nn(1+ε)(logn)

−(2λ−1)

2(1−λ) log logn , when 1/2< λ <1, kP

an{nx}k2≤CεP

a2nlogn(log logn)2+ε, whenλ= 1.

(23)

These properties imply theL2-convergence ofDλ-series under the assumptions of theorem 1.1.

We turn to the question of the a.e-convergence ofDλ-series. The second item of theorem 1.1 is a consequence of inequalities (23) and of the following proposition. The latter is an adaptation of a method due to Rademacher [16] for the study of series based on a general orthonormal family.

Proposition 4.1

Let (an)n≥1 and(ϕ(n))n≥1 be such thatPa2nϕ(n)(logn)2<∞ and for anyM ≤N :

N

X

n=M

angλ(nx)

2

N

X

n=M

a2nϕ(n).

ThenP

angλ(nx) converges a.e.

Proof of the proposition :

We can suppose that log is the logarithm in base 2. LetS(n)(x) =P

1≤k≤nakgλ(kx). Form < n, introduce the notations :

S(m, n)(x) = X

m≤k<n

akgλ(nx) andσl(m, n) = X

m≤k<n

a2kϕ(k)(logk)l, forl∈ {0,1,2}.

(13)

Step 1. We show that (S(2n)(x)) converges for a.ex. Let 0< N < n. We have :

Z 1 0

X

N≤r<n

S(2r,2n)2(x)dx ≤ X

N≤r<n

σ0(2r,2n) = X

N≤r<n n−1

X

s=r

σ0(2s,2s+1)

n−1

X

s=N

(s−N+ 1)σ0(2s,2s+1)

n−1

X

s=N

0(2s,2s+1)≤σ1(2N,2n).

By Markov’s inequality,P

N≤r<nS(2r,2n)2(x)≤σ1(2N,2n)2/3for allxin a Borel setEN,nwith : λ(EN,n)≥1−σ1(2N,2n)1/3≥1−σ1(2N,∞)1/3.

In particular, forx∈EN,nand allN ≤r < n, we haveS(2r,2n)(x)≤σ1(2N,2n)1/3. Define a set EN,n0 by the condition that for all N≤r≤r0 < n:

S(2r,2r0)(x)≤2σ1(2N,∞)1/3.

SinceEN,n⊂EN,n0 , we haveλ(EN,n0 )≥1−σ1(2N,∞)1/3.FixingN, theEN,n0 are monotonic inn.

The setDN defined by the condition that for allN ≤r ≤r0, S(2r,2r0)(x)≤2σ1(2N,∞)1/3 has therefore a measure λ(DN) ≥ 1−σ1(2N,∞)1/3. Since λ(DN) → 1, as N → +∞, we deduce that λ(lim supDN) = 1. If x∈lim supDN, the sequence (S(2n)(x)) clearly satisfies the Cauchy criterion, so converges. This concludesstep 1.

Step 2. To complete the proof, we show that a.e sup2r<n<2r+1|S(2r, n)(x)| →0, as r→+∞. Let 2r< n <2r+1 and decomposenin base 2 :

n= 2r+

r

X

l=1

θl2r−l, with θl∈ {0,1}.

Then :

S(2r, n) =

r

X

l=1

S 2r+

l−1

X

m=1

θm2r−m,2r+

l

X

m=1

θm2r−m

! .

By convexity :

S(2r, n)2 ≤ r

r

X

l=1

S 2r+

l−1

X

m=1

θm2r−m,2r+

l

X

m=1

θm2r−m

!2

≤ r

r

X

l=1 2r−l−1

X

h=0

S 2r+h2l,2r+h2l+ 2l−12

=:T(r).

The quantityT(r) is independent on 2r< n <2r+1. Next :

(14)

Z 1 0

T(r)(x)dx = r

r

X

l=1 2r−l−1

X

h=0

Z 1 0

S 2r+h2l,2r+h2l+ 2l−12 (x)dx

≤ r

r

X

l=1 2r−l−1

X

h=0

σ0(2r+h2l,2r+h2l+ 2l−1)

≤ r

r

X

l=1

σ0(2r,2r+1) =r2σ0(2r,2r+1)≤σ2(2r,2r+1).

FixN and letr ≥ N. By Markov’s inequality, for xin a Borel setFr(N) of Lebesgue measure λ(Fr(N))≥1−σ2(2r,2r+1)/σ2(2N,∞)2/3, we have :

sup

2r<n<2r+1

S(2r, n)2(x)≤T(r)≤σ2(2N,∞)2/3. LetGN =∩r≥NFr(N). Thenλ(GN)≥1−P

r≥Nσ2(2r,2r+1)/σ2(2N,∞)2/3= 1−σ2(2N,∞)1/3. Forx∈GN :

∀r≥N, sup

2r<n<2r+1

|S(2r, n)(x)| ≤σ2(2N,∞)1/3.

Asλ(GN)→1, we getλ(lim supGN) = 1. Ifx∈lim supGN, then sup2r<n<2r+1|S(2r, n)(x)|tends to 0, asr→ ∞. This concludes step 2 and the proof of the proposition.

5 Particular classes where L

2

-convergence is true

We consider the proof of theorem 1.2.

5.1 Proof of i)

Let (nk) be lacunary in the sense that nk+1/nk ≥ c > 1 and (ak) ∈ l2. We first consider the upper bound. We can assume the sequence (ak) finite. By lemma 2.1, the L2-norm of (2/ζ(2λ))1/2P

akgλ(nkx) is given by : X

k,l≥1

akal

nk∧nl nk∨nl

λ

=X

a2k+ 2X

k<l

akal(nk∧nl) (nknl)λ . Using Cauchy-Schwarz’s inequality, the second term is bounded by :

X

k<l

|akal|(nk∧nl) (nknl)λ ≤X

k<l

|akal| nk

(nknl)λ ≤ X

k<l

|akal|c−λ(l−k)≤X

k≥1

|ak|X

l≥1

c−λl|ak+l|

 X

n≥1

a2k

1/2

 X

k≥1

 X

l≥1

c−λl|ak+l|

2

1/2

.

Next, still via Cauchy-Schwarz’s inequality :

(15)

X

k≥1

 X

l≥1

c−λl|ak+l|

2

= X

l,l0≥1

c−λ(l+l0)X

k≥1

|ak+lak+l0|

≤ X

l,l0≥1

c−λ(l+l0)

 X

k≥1

a2k+l

1/2

 X

k≥1

a2k+l0

1/2

 X

l≥1

c−λl

 X

k≥1

a2k+l

1/2

2

≤ 1

(cλ−1)2 X

k≥1

a2k.

As a consequence :

X

k<l

|akal|(nk∧nl)

(nknl)λ ≤ 1 (cλ−1)

X

k≥1

a2k.

Since 1 + 2/(cλ−1) = (cλ+ 1)/(cλ−1), this completes the proof of the upper-bound.

For the lower bound, one can also suppose that (ak) is finite. We haveP

akgλ(nkx) =P bkfk,λ, where (bk) is also finite. By proposition 2.2 :

kX

akgλ(nkx)k2=kX

bkfk,λk2≥1 2

Xb2k.

Fixing 0< ε <1−(2λ)−1, giving 2λ(1−ε)>1 :

Xa2k=X

k≥1

 X

l≥1

l−λµ(l)blnk

2

≤ X

k≥1

 X

l≥1

l−2λ(1−ε)µ(l)2

 X

l≥1

l−2λεb2lnk

≤ Y

i≥1

1 +p−2λ(1−ε)i

 X

l≥1

b2l X

k,nk|l

nk l

2λε

≤ Y

i≥1

1−p−4λ(1−ε)i 1−p−2λ(1−ε)i

!

 X

m≥0

c−2λεm

 X

l≥1

b2l

≤ ζ(2λ(1−ε))

ζ(4λ(1−ε))(1−c−2λε)−1X

l≥1

b2l.

To complete the proof, we first use thatζ(4λ(1−ε))≥ζ(4λ) andζ(2λ(1−ε))≤1+1/(2λ(1−ε)−1).

Setε=ρ(1−1/(2λ)), with 0< ρ <1. We have :

1 + 1

2λ(1−ε)−1

1

1−c−2λε ≤ 2λ 2λ−1

1

(1−ρ)(1−c−(2λ−1)ρ).

Minimizing inρ, we takeρ= 1/(1 + lnc2λ−1). We finally use the inequality 1−e−x≥(1−1/e)x, for 0≤x≤1, giving (1−c−(2λ−1)ρ)≥(1−1/e)(1−ρ).

Concerning a.e-convergence, we can now apply proposition 4.1 with ϕ= 1.

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