A NNALES DE L ’I. H. P., SECTION B
L OUIS H. Y. C HEN
Characterization of probability distributions by Poincaré-type inequalities
Annales de l’I. H. P., section B, tome 23, n
o1 (1987), p. 91-110
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Characterization of probability distributions
by Poincaré-type inequalities
Louis H. Y. CHEN
Department of Mathematics, National University of Singapore,
Lower Kent Ridge Road, Singapore 0511, Republic of Singapore
Ann. Inst. Henri Poincaré,
Vol. 23, n° 1, 1987, p. 91-110. Probabilités et Statistiques
ABSTRACT. - We define a functional related to a
Poincaré-type inequality
and use it to characterize the
infinitely
divisible distribution on the Eucli- dean space. Some related resultsincluding
a limit theorem areproved.
This leads us to the
problem
ofuniquely determining
the distribution ofa random vector X in terms of the constant c and the class of
functions g
for which the
inequality E [g(X) ]2 cE ~
withEg(X)
= 0 becomesan
equality.
Wegive
a solution to thisproblem
in somespecial
cases andconsider a discrete
analog
of it. Our resultsgeneralize substantially
knownresults in the literature.
List of key-words : Poincaré-type inequality, infinitely divisible distribution, weak limit theorem, characterization of probability distributions.
RESUME. - Nous definissons une fonctionnelle reliée a une
inégalité
de type Poincaré et nous l’utilisons pour caractériser les lois infiniment divisibles sur
l’espace
euclidien. Nous démontrons des résultats relies comprenant un théorème limite. Cela nous conduit auproblème
de deter-miner
uniquement
la loi d’un vecteur aléatoire X en donnant la constante cet la classe des
fonctions g
pourlesquelles l’inégalité
E[g(X) ] 2 cE ~ 2
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques - 0246-0203
Vol. 23/87/01/91/20 /~ 4,00/~C Gauthier-Villars 91
92 L. H. Y. CHEN AND J. H. LOU
avec
Eg(X)
= 0 devient uneégalité.
Nous donnons une solution a ce pro- bleme dansquelques
casspéciaux
et nous considérons unanalogue
discret.Nos résultats
généralisent
substantiellement les résultats connus dans la littérature.1. INTRODUCTION
In
[4 Chernoff proved
that if X has a normal distribution with variance~2 > 0
and g
is anabsolutely
continuous function such that E[g(X) ]2
oo,then Var
[g(X) ]
x 62E[g’(X) JZ
andequality
holds if andonly
ifg(x)
= ax + bfor some real numbers a and b. Borovkov and Utev
[1 ] defined
the func-tional
Ux
=sup var [g(X)] 03C32E[g’(X)]2
for any random variable X with variance03C32 >
0,
where the supremum is taken over a suitable class ofabsolutely
continuous functions g, and
proved
that ifUx
= 1 then X has a normal distribution.Combining
the result of Chernoff and of Borovkov andUtev,
one obtains an
interesting
characterization of the normal distribution:X is
normally
distributed if andonly
ifUx
= 1.The Chernoff
inequality
has beengeneralized
tohigher
dimensions and then to the multivariateinfinitely
divisible distribution(see
Chen[2 ], [3 ]).
It is therefore natural to ask whether the above characterization of the normal distribution can be extended to the multivariate
infinitely
divisibledistribution. In Section 2 we
give
apositive
answer to thisquestion using
a much
simpler
method than that of Borovkov and Utev.In connection with the characterization
theorem,
Borovkov and Utevobtained a list of
properties
of the functionalRx (which
is related toUx by Ux
=Rx/Var (X)),
andproved
a limit theoreminvolving Ux.
Wegeneralize
these results in Section 3.The
proof
of the characterization theorem leads us to thefollowing question
which isanalogous
to the well known « Can one hear theshape
of a drum ? »
(see
Kac[5 ] and
Remark(1)
in Section4) :
If c isgiven
andthe
inequality E [g(X) ] 2 Vg(X) 2
whereEg(X)
= 0 becomes anequality for g belonging
to agiven
class offunctions,
does thisuniquely
determine the distribution of the random vector X ? In Section
4,
we showthat the answer is
positive
in somespecial
cases.In the last
section,
we consider a discreteanalog
of thisproblem.
TheAnnales de l’lnstitut Henri Poincaré - Probabilités et Statistiques
CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS 93
m
inequality
in this case becomes Var[g(X)] c E[0394ig(x)]2
where0394ig(x) = g(x1,...,xi + 1,...,xm) - g(x1,...,xi, ... , xm).
Throughout
the paper all functions are real-valued unless otherwise stated. We denoteby
orrespectively
the class ofCk
functionson an open set Q which are bounded or have compact support. The trans- pose of a matrix C is denoted
by
C*. All vectors are taken to be columnvectors and we write x =
(xi,
...,xm)*
for a column vector. The usualinner
product
of two vectors x and y is denotedby (x, y)
and the normof x
by ) x ~ .
2 CHARACTERIZATION
OF THE INFINITELY DIVISIBLE DISTRIBUTION
In their
proof
of the characterization theorem[l,
Theorem 3],
Borovkovand Utev used the
properties
of the functionalRx
and aningenious
construc-tion to characterize the normal distribution
by
the method of moments.In this
section,
we show that theproof
of Borovkov and Utev can be substan-tially simplified
and the theoremgeneralized
to the multivariateinfinitely
divisible distribution. This is done
by reducing
theproblem
to a system of first orderpartial
differentialequations
whoseunique
solution is the characteristic function of aninfinitely
divisible distribution. In ourproof,
the use of
Rx
is avoided.Let X =
(Xi, ... , Xm)*
be a random vector with distribution y andmean vector b such that Var
(X~)
oo for i =1,
..., m. Denoteby L2(X)
the class of Borel measurable functions g defined on ~m such that
E [g(X) ]2
oo andQ(X)
the class of such functions such that Var[g(X) ] >
0.Define = n
L2(X)
nQ(X).
Let E == ...,
T~) == (ii~)
be an m x mpositive
semidefinite matrixand J1
a measure on such that it has no atom at 0 and|x|2 (dx)
~. Definewhere
Vol. 23, n" 1-1987.
94 L. H. Y. CHEN AND J. H. LOU
THEOREM 2 .1.
Suppose
> 0for j =1,
..., m.Then
U(X, 03A3, )
> 1 andU(X, 03A3, )
= 1if
andonly f
the distribution y isinfinitely
divisible with characteristicfunction given by
for
t EProof
- The factU(X, ~, ,u) >
1 followstrivially
from the definition(2 .1)
and the substitution
g(x)
forany j
=1,
..., m. Thenecessity
ofU(X, ~, ~c)
= 1 isimplied by
Theorem 4 .1 of Chen[3 ].
For thesufficiency,
let where
and j =1,
..., m. ThenU(X, E, ,u) =1 implies
that for ~. ER,
This
yields
Since this
inequality
holds for all i~ it follows thatSubstituting f ~(x) =
and then Im in (2 . 3), we obtainfor t E [Rill
and j
=1,
..., m, wherey
is the characteristic function of y.Since
y(0)
= 1 and the characteristic function of theinfinitely
divisibledistribution never
vanishes, (2.4)
has aunique
solution which isgiven by (2.2).
This proves thesufficiency
ofU(X, ~, ,u)
= 1 and hence the theo-rem.
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
95 CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS
Two
special
cases of Theorem 2.1 are of interest. We state them withoutproof.
COROLLARY 2 .1. - Let X =
(Xi, ..., Xm)* be a
random vector suchthat
Var (X~)
= > 0for j
=1,
..., m.Define
where ~ is an m x m
positive semidefinite
matrix with ...,6~
as itsdiagonal
elements. ThenU(X, ~) >
1 andU{X, ~)
= 1if
andonly if
X hasa multivariate normal distribution with covariance matrix ~.
For the next
corollary
we defined~PX
to be the class of functions g : ~m ~ (~ such that E[g{X) ]2
oo and Var[g(X)] >
0 where X is arandom vector
taking
values in ~m.COROLLARY 2. 2. - Let X =
(X 1,
..., be a random vectortaking
values in ~m such that Var
(X~) _ ~,~
> 0for 1,
..., m.Define
...,
l,
..., ..., x;, ...,xm).
ThenUX = 1 if
andonly if
eachXj
has a translated Poisson distribution andX1,
...,Xm
are
independent.
3. SOME RELATED RESULTS
Although
we have avoided the use ofRx
in theproof
of Theorem2.1,
itsproperties proved
and usedby
Borovkov and Utev[1 ] are
nevertheless of interest in themselves. Borovkov and Utev alsoproved
a limit theoreminvolving Ux.
Theobjective
of this section is togeneralize
these results.As in section 2, let = n n
Q(X).
Let 03A3 = (03C4ij) be an m x mpositive
semidefinite matrixand J1
a measure on suchthat
hasno atom at 0 and
f |x|2 (dx)
~. Assume that 03C4ij +,u(dx)
> 096 L. H. Y. CHEN AND J. H. LOU
for j
= 1, ..., m. For each random vector X =(Xi,
...,Xm)*,
defineU(X, ~, ,u) by (2.1).
Also defineNote that
U(X, E, ,u)
andUo(X, E, ,u) correspond
toRx
and rx in[1 ] res- pectively. Although C1(1R)
is smaller than the class ofabsolutely
conti-nuous
functions,
there is no loss ofgenerality
in our definitionof U(X, E, ,u),
when
specialized
to onedimension,
in view ofi)
of Theorem 2 in[1 ].
We abbreviate and to and
Uo(X,E)
respectively if j1
is the zero measure. Also writeThe
following
lemma is ageneralization
of Lemma 1 in[1 ].
We omitits
proof
here as theproof
of the latter carries overeasily
to thisgeneral
case
LEMMA 3.1. - Let and
C1(lRm) n L2(X). Suppose
THEOREM 3 .1.
i) U(X, ~, ,u)
=Uo(X, it, ~c).
ii)
Let g EIf U(X, 03A3, )
oo and ~, thenand Var
[g(X) ] U(X, ~,
iii) If U(X, ~)
ao, then the distributionof
X has a continuous(but
not
necessarily absolutely continuous)
component.iv) If U(X, ~, ,u)
oo and there exists a(0
a1)
such that-
1)|03B6| (d03BE)
oo, then E[exp {t1X
1 + ... +]
cofor
| ti I
i =1,
..., m, where97 CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS
and
v)
Let C be an m x mnonsingular
matrix and b E Thenis the covariance matrix
of
X.vii) If
X and Y areindependent,
thenviii) X"
ijT distribution to X, thenProof
- We note that Lemma 4 . 2 of Chen[3 ] is
true for anyproba- bility distribution y
if D =~. By
anapplication
of thislemma, i)
follows.For
ii),
let gn = +g2)1/2.
Then gn gpointwise,
n,and ~.
So gn satisfies the condi- tions in Lemma 3.1 andii)
follows.By letting g depend
on onevariable,
partiii)
of Theorem(2)
in[1 ] implies
that eachXi
has anabsolutely
conti-nuous component and this proves
iii).
To see that the distribution of X may besingularly continuous,
let m =2, Xi
have the standard normal distribution andX2
=Xi.
Thenby
the Chernoffinequality,
for g E
C1(~2)
such that E[g(X) ]2
oo. Theproofs
ofv)-viii)
are easy extensions of those of thecorresponding
parts of Theorem 2 in[1 ],
andare therefore omitted here. But we remark that for
vii)
andviii)
Lemma 4. 2of
[3] ]
is used.It remains to prove
iv).
Since98 L. H. Y. CHEN AND J. H. LOU
it suffices to consider each
Xi separately.
AbbreviateU(X, E, ,u~
to U.By taking g
todepend
on onevariable,
we havefor
L2(Xi)
and i =1,
..., m. LetXi
be anindependent
copy ofXi
and letWi
=Xi - Xi.
Thenfor g
E we haveThis
yields
By
Lemma 4.2 of[3], (3.1)
holds for g E nBy
Jensen’sinequality
and Fubini’s theorem as in theproof
of Theorem 4 . 3 in[3 ],
and then
by
achange
ofvariable, (3.1) yields
where
1 - °°
Let
ei
= ~ii +~m
~ii + - 2 w~‘f’i~t~
+~i~ t}
and defineYi
to be a random variable
independent
ofWi
and distributed asi
whereAnnales de l’Institut Henri Poincaré - Probabilités et Statistiques
99 CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS
Then
(3.2)
may be written asBy ii)
andinduction,
U oo and the condition(eat~~ -1) ~ ~
~m(
o0imply
that all moments ofXi
exist for i =1,
..., m, which in turnimplies
the same for
Wi
for i =1,
..., m. We now proveby
induction that for1,
By
asimple calculation,
EeaYi =8i 1 ~ iii + a 1 Rm 03BEi
(~ m sinh which
is finite
by
virtue of the condition(ea ~ ~~
-1) ~ ~ ~
oo, and sob~
= max( 1, ~m
For the rest of the
proof,
wedrop
thesubscript
i forbrevity,
but willpick
it up whenever it is necessary to avoidambiguity.
Since EW2 = 2Ue c,(3.4~ holds for n = 1. For n >
2, (3.3) yields
where we have used the fact that all odd moments of W vanish.
By
theinduction
hypothesis
’
100 L. H. Y. CHEN AND J. H. LOU
If n is
odd,
then EWn - 0. On the otherhand,
if n is even, then EWn 2 n ! bc a2 n/2] 2 n!) 2 bc a2 n4n1/2(2n!) 22n(bc a2)
nc 2 -1 2n!)( bc a2 n.
In either case the
right
hand side of the lastinequality
in(3. 5)
is less than(2n
and(3 . 4)
isproved. By
Jensen’sinequality,
So for
This
implies
that E exp E exp oo . Asiv)
isproved.
Hence the theorem.For the next
theorem,
letXn
= ..., be a random vectorwith mean vector
bn
and 0 Var oo for i =l,
..., m. Let~n
bean m x m
positive
semidefinite matrix and ,un a measure on~( f~’~)
suchthat it has no atom at 0 and
Rm |x|2 n(dx)
oo .THEOREM 3.2. - Assume the
diagonal
elementsof 03A3n
+are
respectively
i =1,
..., m.Suppose
as n ~ oo,b,
~
and x
convergesweakly to x
where without lossof generality
,u may be assumed to have no atom at o.~n,
-~ 1as n -~ oo, then
~(Xn)
convergesweakly
to theinfinitely
divisible distribu- tion y whose characteristicfunction
isgiven by (2.2~
as n - oo.Proof
- Sincebn
--~ band~n --~
~, the distributions ofXn,
n > 1are
tight.
Hence it suffices to prove that everyweakly
convergent subse-Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS 101
quences
of { ~(Xn) ~
converges to y.Suppose Xn. =~
X. Then for g EBy
Theorem3 .1 i), U(X, ~,
1.By
Theorem 3.1iv), {
isuniformly
integrable
for i =1,
..., m and so thediagonal
elementsare
Var (Xi),
i =1,
..., m, where X =(Xi,
...,Xm)*.
It follows from Theorem 2.1 thatU(X, ~, f-l)
= 1 and so the distribution of X is y. This proves the theorem.4. MORE ON CHARACTERIZATION.
THE CONTINUOUS CASE
In
Theorem 2.1, although
theinfinitely
divisible distribution is charac- terizedby using
the functionalU(X, E, ,u),
theproof depends crucially
onthe
knowledge
of the functions for which theinequality
becomes an equa-lity.
One may therefore restate aspecial
case of Theorem 2 .1 as follows : If theinequality E [g(X)]2 :(
whereEg(X)
= 0 becomes anequality
forg(x)
= xi, i =1,
..., m, then X has the multivariate normal distribution with zero mean vector and covariance matrix cI. This leads us to thefollowing question :
If c isgiven
and theinequality
E[g(X) ] 2 cE ~ pg(X) ~ 2
where
Eg(X) = 0
becomes anequality for g belonging
to agiven
class offunctions
(not necessarily linear),
does thisuniquely
determine the distri-bution of X ? The
objective
of this section is togive
an answer to this ques- tion. We show that the answer ispositive
in somespecial
cases butnegative
in
general.
As in Section 2, we reduce the
problem
to a system of first orderpartial
differential
equations.
But unlike that in Section2,
the method here ismore akin to a method of normal
approximation
due to Stein[~ ].
LEMMA 4 .1. - Let I =
(a, b) be an
open(possibly infinite)
interval. LetX be a random variable
taking
values inI,
and y the distributionof
X.Suppose
for
allabsolutely
continuousfunctions
g on I such that E[g{X) ]2
oo andEg(X)
=0,
there is a constant c such thatE [g(X) ]2 cE [g’(X)]2
and102 L. H. Y. CHEN AND J. H. LOU
equality
holdsif g(x) =
wheret/r
EC1(I). If 0)
= 0, then X is absolutely continuous.Proof. Decompose
y into y = a,u +(1
-a)v,
where ,u and v are pro-bability
measures on I suchthat Il
isabsolutely
continuous with respectto the
Lebesgue
measure and v issingular,
and 0 ~ x ~ 1. Let A be the set ofpoints
of increase of v. Thenwhere the last
inequality
follows from the observation that is a Borel measurable derivative of~.
Hence we have(1 - a)
= 0. Thisimplies
that either a = 1 or~r’(x)v(d~x) _
~. If =0,
then~r’
- 0 v-a. e., that isv(~’ - 4)
= 1. Theassumption y{~r’
-0)
= 0 thenforces a to be
equal
to l. In this case, y = ,u and is thereforeabsolutely
continuous with respect to the
Lebesgue
measure.LEMMA 4 . 2. - Under the condition
o, f ’
Lemma 4 .l,
supposefurther
that
03C8’
never vanishes on I. Then thedensity function o.f
X isgiven by fX
=/ I
a. e., where= 1 03C8’ exp - - C 03C8 03C8’) and , 4’ ,
is an indefinite
integral of 03C8 .
~~r’
.Proof :
- Let h be anabsolutely
continuous function on I such that E[h{X) ] 2
~ . Put g =~,(h - Eh(X))
-~-i/r,
~, E IF~ in theinequality. By
thesame argument as in the
proof
of Theorem 2.1, we obtainAnnales de l’Institut Henri Poincaré - Probabilités
103 CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS
whenh(x)
===(x -
where xo EI,
the aboveidentity
can be rewrittenas
Taking
bothintegrals
as functionsof xo
and thentaking
Borel measurable derivatives with respect to xo on bothsides,
we have thefollowing identity
*’ ^’ U
r~
for almost all xo w. r. t. the
Lebesgue measure.
LetH(,~) _ ~~ y)~X( y)dy._
Wex
observe that H is
absolutely
continuous and is a version on I. NowThis
implies
H is differentiableeverywhere
on I andSolving
forH
we obtain a solutiongiven by
u to a multi-plicative
constant. It is now clearthat f ’x = 03C6 / I a. e., where I
is
the
normalizing
constant to makefX
adensity
function.For the
following theorem,
let ~ --.I1
x .. , xIm
where eachIi
=b~)
is an open
(possibly infinite)
interval. Let X =(X 1,
... ,Xm)*
be a randomvector
taking
values in ~. For~ri
E and c >o,
definewhere
~~
is an indefiniteintegral
of~~ .
~,
ie eg a
i
THEOREM 4.1. -
Suppose
that there is a constant c such thatfor
atlg E
C1(S2)
with E[g{X) ]~
oo andEg(X)
=0,
and that
equality
holdsif g(x) _ for
i =1,
..., m, where E Vol. 23, n° 1-1987.104 L. H. Y. CHEN AND J. H. LOU
i =
1,
..., m. Assume that does not vanish onIi for
i =l,
..., m. Thenm
X is
absolutely
continuous withdensity function given by fx(x)=
where
03C6i(xi) = (xi) / Iii.
Proof By letting g depend
on onevariable, (4 . 2)
and[l,
Theorem 2f)] ] imply
E[g(X i) ]2
cE[g’(Xi) ]2
for allabsolutely
continuous g defined onIi
such that E[g(Xi) ]2
oo andEg(Xi)
=0,
i =1,
..., m.By
Lemmas 4 .1and
4.2, Xi
isabsolutely
continuous withdensity
function It remainsto prove that
Xi, ... , Xm
areindependent.
Letf
ECB(SZ)
and substituteg =
~.( f - E f (X))
+ in(4 . 2)
where ÀE (~.By
the same argument as in theproof
of Theorem2.1,
we obtainN
for i =
1,
..., m. Foreach i, let vi
ECo(Q)
such that = 0. The diffe-rential
equation
Iiwhere
f
is defined on Q has a solutiongiven by
where the second
equality
follows from the condition Iivii = 0. Sincevi e
Co(Q),
we havef
eC0(03A9)
and hencef
eC§(Q) by
virtue of theequation
Substituting (4. 4)
in(4 . 3),
we obtainEvi(X)
= 0. Now let u,hi
ECo(Q),
and let
Kl
c=K2
c= Q be two compact sets such that onKi, hi= 0
onK2,
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
105 CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS
hi
and 0
hi
1 onK2 -
K 1and Ii hi 03C6i~0. By letting
vi = u - I= , we
obtain Ii
Now let
Ki
1 increase to Q. Then(4 . 5) yields
By approximating
functions ofby
those of(4.6)
also holdsfor u e Now take u to be a function of ...,
xi)
for f =l,
..., m.Then it follows that
Xi,
...,Xm
areindependent with joint density
functionrn
given by fx(x) =
This proves the theorem.i= 1
By applying
Theorem 4.1 to a number ofinequalities,
we obtain thefollowing
corollaries.COROLLARY 4.1. 2014 Let y be a
probability
measure on~((!~m).
Then. = (2703C003C32)-m/2 exp (-|x|2 B ~~ / )dx if
andonly if
thefollowing inequality
holds : For such that and
62
Vg
andequality holds if
andonly if g(x)
= a*xProo~ f
- Combine Theorem 4 .1 withj3, Corollary 5.1].
COROLLARY 4.2. - Let y be a
probability
measure on~(!RT)
such thatm
= 0. Then
exP ( - 4 .~C e 2 dx, Where
i= 1
0,
ocl, ..,, andonly if the following inequality
holds : Forsuch that oo and
Rm+gd03B3
=0, Rm+|~g|2d03B3
andVol. 23, n° 1-1987.
106 L. H. Y. CHEN AND J. H. LOU
m
equality
holdsf
andonly if g(x)
=403B1i03B8) for
al, ..., am E R.Proof
- Combine Theorem 4 .1 with[3, Corollary 5 . 5 ].
COROLLARY 4. 3. Let y be a
probability
measure on[o, ~ ]m)
suchthat
y(~ [o, ~ ]m)
= 0. Thenwhere ai >
0, 03B2i
> 0 and 03BB = ai +03B2i for
i =1,
..., m;if
andonly if
thefollowing inequality
holds: For g EC1( [0,
suchthat g2dy
o0and =
0,
J[o,n]m
and
equality
holdsf
andonly if
Proof
- We firstgive
a sketch of theproof
of theinequality (4. 8)
underthe
assumption (4. 7).
LetXi
andX~
beindependent
random variableshaving
the gamma distributionsh(a, 8)
andr(/3, 8) respectively.
WriteX =
(Xl, X2)*. By [3, Corollary 5.3],
we have for g EC1(~+)
such thatE
[g(X) ] 2
oo andEg (X)
=0,
Equality
holds if andonly
ax - a
+ a(x2 - 03B2 03B8)
for a e [R.Let
Yi = Xi/(Xi
+X2)
andY~
=Xi
+X~.
ThenYi
andY~
are inde-pendent, Yi
has the beta distributionB(a, ~8)
andYi
+Y2
the gamma distributionI-’(~,, 0)
where~, = a + /~. Let f ’ E ~ 1 ( [o, 1 ])
such thatE, f ’(Yl ) = 0.
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
107 CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS
Substituting g(X)
=Y2 f (Y1)
in(4 . 9),
weobtain,
after somecalculations,
which reduces to an
equality
if andonly
iff( y) = ~ y 2014 - j for a E (~.
By
suitable transformations in thespirit
of[3, Corollary 5 . 5 ], (4.10) yields
the one dimensional
special
case of(4.8)
under theassumption
thaty(dx)
=x dx.
Amartingale
argument as in22
Chen
[2 then
extends it to thehigher
dimensions.Combining
this withTheorem
4.1,
we prove thecorollary.
We now
give
anexample
to show that Theorem 4.1 is false if the dimen- sion of the class of functions g for which(4.2)
becomes anequality
is lessthan the dimension of the domain Q even
though
other conditions of the theorem are satisfied.Example.
LetX1
andX2
beindependent
random variables withX1
distributed as
N(0, 1)
andX2
asN(0, ~2)
where 0 62 1. Thenby [3, Corollary
5.1], for g
ECl([R2)
such that E[g(X) ] 2
oo andEg(X)
=0, E [g(X} ] 2 E Og(X) ( 2
andequality
holds if andonly
ifg(x)
= ax1 fora E f~.
Clearly
the distribution of X =(X 1, X2)*
is notuniquely
determined.Remarks.
1)
Incharacterizing
the distribution of Xby
theinequality
E [g(X) ]2 cE [~,
suppose, inaddition,
the distribution of X isgiven
to be uniform on a bounded domain Q. Then theinequality
becomes2
cf ! Vg 2 where 1
is the firsteigenvalue
of theLaplacian A
on Qin the Neumann
problem,
and the class of functions for which theinequality
becomes an
equality
is the firsteigenspace. Furthermore, finding
the distri-bution of X is
equivalent
tofinding
theshape
of Q. Hence theproblem
of
characterizing
the distribution of X becomes that ofdetermining
theshape
of Qgiven
the firsteigenvalue
and the « form » of the functions inthe first
eigenspace
of A on Q. This isanalogous
to theproblem
« Can onehear the
shape
of a drum? »(see
Kac[5 ])
where theshape
of Q is to bedetermined
given
all theeigenvalues
of A on Q. The answer to thisquestion
has been shown to be
negative
for dimension of Q greater than orequal
to 4 in both the Dirichlet and the Neumann
problem (see
Urakawa[7]).
2)
In the case Q is anarbitrary
open set and the class of functions forVol. 23, n° 1-1987.
108 L. H. Y. CHEN AND J. H. LOU
which the
inequality
becomes anequality
is alsoarbitrary,
thefollowing question
remains unanswered : Under what conditions is the distribution of Xuniquely
determined ?5. MORE ON CHARACTERIZATION.
THE DISCRETE CASE
In this section we consider a discrete
analog
of theproblem
in Section 4.Let X =
(Xi, ... , Xm)*
be a random vectortaking
values in ~’~ and let=
P(XI
=z). Define ei
=(0,
...,1,
...,0).
where the number 1 occu-pies
theposition. Suppose
for g : ~m -~ I~ such thatE [g(X) ]2
00and
Eg(X)
=0,
we havetM
and
equality
holds if andonly
ifg(x) _
for i =l,
... , r~i, whereeach f~. We show that if +
1)
- 0 forthen the distribution of X is
uniquely
determinedand X1, ... , Xm
are
independent.
By
the same argument asbefore,
we have the identitiesfor i = 1, ..., m, where
f ’ :
~m -~ If~ and is bounded.By choosing f
tobe the indicator function ...,
xm)
e ~m : xi =z ~, (5 . 2) yields
Let a.
be the supremum of the set of zeros of0 + - c It
is easy to see from(5.3)
that - ~ ai oo.If ai
> - ao, then > 0 andAnnales de l’Institut Henri Poincaré - Probabilités et Statistiques
CHARACTERIZATION OF PROBABILITY DISTRIBUTIONS 109
If aj = - co, then
pi(0)
> 0 andNote that
(5 . 3) implies
that1)
and+ -
have thec
same
sign
for xi > ai. Without loss ofgenerality
we assume that ai > - o0 for i =l,
..., m’ and that ai = - oo for i = m’ +1,
..., m.Now let
f
be the indicator functionof ~ (x i, ... ,
E...,
xi) _ (xl, -
..,xi) ~.
Substitution of this in(5.2) yields
a diffe-rence
equation
whose solutionimplies
thatXi
isindependent
of(Xl, ... , Xi- I O By
induction on i,X 1,
..., arcindependent.
Hence we have thefollowing
theorem.
THEOREM 5 . l. -
Suppose
theinequality (5 .1 ~
holds andequality
isachieved when
g(x)
=for
i =1,
..., m, where each ~ ~ (~.If
never
vanishes for
i =1,
..., m, thenX1,
...,X m
areindependent
andtheir individual
density functions
aregiven by (.~ . 4~
and~S . 5) .
Combining
this theorem with[3, Corollary 5 . 2 ],
we have thefollowing corollary.
COROLLARY 5 .1. - The random variables
X 1,
...,Xm
areindependent
each
having
the Poisson distribution with mean ~.if
andonly if
thefollowing inequality
holds : For g : 7~m --~ ~ such that E[g(X) ]2
oo andEg(X)
=0,
Added in
Proof
A. A. Borovkov and S. A. Utevpointed
out an error inthe
proof
of Theorem 3 . 2 and gave a correction of it as follows : The uniformintegrability of { ~ni ~
beproved by substituting g(x)
= +x2)1~2
in the
Poincaré-type inequality
forXn
instead ofusing
Theorem 3.1iv).
Vol. 1-1987.
110 L. H. Y. CHEN AND J. H. LOU
REFERENCES
[1] A. A. BOROVKOV and S. A. UTEV, On an inequality and a related characterization of the normal distribution, Theory Prob. Appl., t. 28, 1984, p. 219-228.
[2] L. H. Y. CHEN, An inequality for the multivariate normal distribution, J. Multivariate Anal., t. 12, 1982, p. 306-315.
[3] L. H. Y. CHEN, Poincaré-type inequalities via stochastic integrals, Z. Wahrscheinlich- keitstheorie verw. Gebiete, t. 69, 1985, p. 251-277.
[4] H. CHERNOFF, A note on an inequality involving the normal distribution, Ann. Probab.,
t. 9, 1981, p. 533-535.
[5] M. KAC, Can one hear the shape of a drum? Amer. Math. Monthly, t. 73, 1966, p. 1-23.
[6] C. STEIN, A bound for the error in the normal approximation to the distribution of
a sum of dependent random variables, Proc. Sixth Berkeley Sympos. Math. Statist.
Probab., t. 2, 1972, p. 583-602.
[7] H. URAKAWA, Reflection groups and the eigenvalue problems of vibrating membranes
with mixed boundary conditions, Tôhoku Math. Journ., t. 36, 1984, p. 175-183.
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques