R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
A. B ALLESTER
L. M. E ZQUERRO
A note on the Jordan-Hölder theorem
Rendiconti del Seminario Matematico della Università di Padova, tome 80 (1988), p. 25-32
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A. BALLESTER - L. M.
EZQUERRO (*)
1. Introduction.
All groups considered in this note will be finite. In recent years
a number of
generalizations
of the classic Jordan-H61der Theorem have been done.First, Carter,
Fischer and Hawkes in[1; 2, 6] proved
that in a soluble group G an one-to-one
correspondence
like in the Jordan-H61der theorem can be definedpreserving
notonly
G-iso-morphic
chief factors but even theirproperty
ofbeing
Frattini orcomplemented. Later,
Lafuente in[4]
extended this result to any(not necessarily soluble)
finite group.If P is a
subgroup
of G with the Cover and AvoidanceProperty,
i.e. a
subgroup
which either covers or avoids any chief factor ofG,
one can wonder if it is
possible
togive
a one-to-onecorrespondence
between the chief factors avoided
by
P with theproperties
of the onein the Jordan-H61der Theorem or in the Lafuente Theorem. Here
we prove
that,
ingeneral,
the answer ispartially
affirmative. Wegive
some sufficient conditions for a
subgroup
with the Cover and Avoid-ance
Property
to ensure an affirmative answer to ourproblem.
2. Notation and
preliminaries.
A
primitive
group is a group G suchthat
for some maximal sub- group TI ofG,
U .G, UG = r1 ~ rIg :
g EG}
= 1. Aprimitive
group is one of thefollowing types:
(*) Indirizzo
degli
AA.:Departamento
deAlgebra,
Facultad de C. C.Matemdticas, Universidad de Valencia,
C/Dr.
Moliners/n,
46100Burjassot
(Valencia), Spain.
26
(1) Soc (G)
is an abelian minimal normalsubgroup
of G com-plemented by
U.(2) Soc (G)
is a non-abelian minimal normalsubgroup
of G.(3) Soc (G)
is the directproduct
of the two minimal normalsubgroups
of G which are both non-abelian andcomplemented by
U.We will denote with
5’i, i
E2~ 3}y
the class of allprimitive
groups oftype
i. For basicproperties
of theprimitive
groups, the reader is referred to[2, 3].
DEFINITION 2.1. We say that two
isomorphic
chief factors i =1, 2,
of agroup G
areG-isomorphic
if =OG(H2IK2).
We denote then ·
DEFINITIONS 2.2.
(a)
IfB’/K
is a chief factor of G such thatg/K c
~
O(GfK)
then is said to be a Frattinichief factor
of G.If
.H’/K
is not a Frattini chief factor of G then it issupplemented by
a maximalsubgroup
U in G( i. e.
G = UH~ and U r1H).
More-over, this U can be chosen such that
G/ Ua
is aprimitive
group andSoc (G/ Ua) _
(b) [2, 3]
IfB’/g
is an abeliansupplemented
chief factor ofG,
then
G/ UG
isisomorphic
to the semidirectproduct
since =
HUG.
If is non-abelian thenU~
=CG(HIK)
and
GI U, = 6’/Cc(H/-E’)
DenoteThe
primitive
group is called the monolithicprimitive
group associated with the
chief factor of
the group G.The chief factor is called precrown
of
Gassociated with
H/.g
and U.(Notice
that ifHIK
is non-abelian is theunique
precrown of G associated with(c) [3]
IfHi/Xi, i
=1,
2 aresupplemented
chief factors ofG,
we say that
they
are G-related if there exist precrownsCilRi
associatedwith such that
Ci
=O2
and there exists a common com-plement
TI of the factorsRi/(R¡ n R2)
in G.Two
G-isomorphic
non-abeliansupplemented
chief factors have the same precrown and therefore are G-related. Ifthey
areabelian,
then
they
areG-isomorphic
if andonly
ifthey
are G-related.G-relatedness is an
equivalence
relation on the set of allsupple-
mented chief factors of G.
For more details the reader is referred to
[3].
3.
CAP-subgroups.
DEFINITION 3.1. Let G be a group, if and N two normal sub- groups of
G,
and P asubgroup
of G. We say that.(a)
P coversMIN
ifMPN.
(b)
P avoids i f P nM c N.
(c)
P isCAP-subgroup
of G if every chief factor of G is either covered or avoidedby
P.LEMMA 3.2
(Schaller [5] ) .
Let G be a group, P asubgroup
of Gand N a normal
subgroup
of G.(a)
If P is aCAP-subgroup
of G then NP and N n P are CAP-subgroups
of G and is aCAP-subgroup
ofG/N.
(b)
If and is aCAP-subgroup
ofG/N,
then P is aCAP-subgroup
of G.THEOREM 3.3. Given a
group G
and aCAP-subgroup P
ofG,
thereexists a one-to-one
correspondence
between the chief factors coveredby
P in any two chief series of G in whichcorresponding
factors have the same order(but they
are notnecessarily G-isomorphic).
PROOF. Denote
two chief series of G and suppose
28
are the chief factors of G covered
by
P in(1)
and(2) respectively.
We prove r = s
by
induction onIPI.
If P = 1 there isnothing
toprove. The normal series of
P, Hi : 1
=0,
... ,m~
isby, omitting repetitions, {.P~.B’~:~==0,...,~;~=0}
andsimilarly
with(1) : {JP~6~:~==0,l,...,~;~o=0}
is a normal series of P. ConsiderQ
= P r1Gi,.-,. Q
isstrictly
contained in P andby 3.2, Q
is a CAP-subgroup
of Gcovering
=1, ... ,
r - 1 andavoiding
allthe other chief factors in
(1). By induction Q
covers r - 1 chief factors of ~. If we haveIQI= /PI
andthen Q = P
which isnot
true. Hence r ~ s.
Similarly taking Q*
= P r1HZ.-1 we
obtain s c rand then s = r, as
required.
Finally, by induction,
there exists a one-to-onecorrespondence
between the chief factors covered
by Q
in 19 and in Je in which corre-sponding
factors have the same order. Theonly
chief factor in R avoidedby Q
is say; thenand the theorem is
proved.
EXAMPLE 1. If we consider G =
~a, b ;
c : a9 = b 2 = c9 = 1 ==
[a, c]
=[b, c],
ab =Dg
and P =(a3 cs>
then P is aCAP-subgroup
of G(G
issupersoluble)
and if we take the two chiefseries.
then P covers and The first is central and the latter eccentric and so
they
are notG-isomorphic.
COROLLARY 3.4
(Jordan).
All chief series of the group, G have thesame
length.
4.
SCAP-subgroups.
DEFINITION 4.1. Let P be a
CAP-subgroup
of a group G. We will say that P is aStrong CAP-subgroup
ofG, SCAP-subgroup
forshort,
if P satisfies(a)
Given asupplemented
chief factor of G avoidedby
Pthen P is contained in some maximal
supplement
U ofB’/..g
inG,
suchthat
GjUa Eff1
(b)
If Y and .M are normalsubgroups
ofG,
Y andthen
(P
is a normalsubgroup
ofIf t is a
trasposition, t>
is aSCAP-subgroup
ofSym (n),
for every n;if G is
soluble,
then Hallsubgroups
and maximalsubgroups
are SCAP-subgroups.
In theexample
of theorem3.3,
P is aCAP-subgroup satisfying (c~)
but not(b).
Notice that if P is a
SCAP-subgroup
of G and thenPN/N
is a
SCAP-subgroup
ofG/N.
Given a
supplemented
chief factorH/K
of G avoidedby
the SCAP-subgroup P,
then there existsalways
a precrown of G associated with avoidedby
Pby
condition(a). Conversely
if P avoids a precrown of G associated with.8’/.K
then P avoids.g/g.
Consider now, for each
SCAP-subgroup
P of G and for each sup-plemented
chief factorB’/K
ofG,
avoidedby P,
RP =
r’1~T : CIT
is a precrown of G avoidedby
P associated with achief factor G-related to If P =
1,
wesimply
denote .R =.Rl.
DEFINITION 4.2. With the above
notation,
theP-crown of G
as-sociated with
.g/g
is the factor groupO/Rp,
C =HOo(H/K).
Clearly
is avoidedby
P. For more details on crowns see[3].
LEMMA 4.3. Let P be a
SCAP-Subgroup
of G and.8’/.g
asupple-
mented chief factor of G avoided
by
P. Denote the P-crown of G associated with.g’/g.
If is a chief factor of G such that
KoRp
C thengo/go
is asupplemented
chief factor of G avoidedby
P and G-related to.H’/.g.
PROOF. Because of
[3; 2.7]
we haveonly
to prove that P avoidsSince then
equality
holds and is a chief factor of G avoided
by
P. If.g’o/go
were covered
by P,
thenH’o
=P)
and =RpKo(Ho (1 1 P) C lLplLp(lZ plLp r1 P)
and hence P would coverH0R0/K0RP,
acontradiction. Therefore P avoids
.go/.go.
LEMMA 4.4. Let
N,, i
==1, 2,
two distinctsupplemented
minimalnormal
subgroups
of G and P aSCAP-subgroup covering N/Ni, (N
=- Nl X N~),
andavoiding Ni
7i == 1, 2.
Denote the P-crownassociated to
Ni.
ThenNl
andN2
areG-isomorphic.
30
PROOF.
Suppose
that for somei E ~1, 2~,
9 IfNfNi
iscovered
by
then andthis
is a contradiction.So, NfNi
is avoidedby
andby 4.3,
is a chief factor of G avoidedby
P and r1 P = r1 P. Now N n n P andN =
Ni(P
r1N) ,Ni(P
n a contradiction.Therefore = 1 for
any i
E~1, 2}
and henceBy
4.3Ni
is G-related toSuppose Ni
andN2
are notG-isomorphic;
thenT2,
whereT~ = OG(Ni), i
=1,
2. P avoidsN~
and then avoids its precrown andP n Ti = P n Ni Ti, i
and
Tl
nN(T1
nT2)
=Ti
nN~ T2 = Tl
nTl
since=
N~ T~ ,
and Hence P avoidsTilT,
nT2, i
=1, 2
and then avoids its precrowns =1, 2.
Since P covers and
Consequently
n
T2
and then a contradiction. Therefore~2’
THEOREM 4.5. Let P be a
SCAP-subgroup
of G and consider two sectionsof two chief series of G. Denote
chief factors in
(1)
avoidedby P~ ,
chief factors in
(2)
avoidedby P} -
Then,
there exists a one-to-onecorrespondence a
between and~p
such that
(a)
is a Frattini chief factor if andonly
ifis a Frattini chief
factor;
in this case(b)
If issupplemented,
thenNilNi-,,
isG-isomorphic
to
PROOF. WLOG we can assume
17
N =M1
==M,
by [3; 3, 2]
we can assume that P coversY/M
andY/N
and avoids N and M. So we must see if thecorrespondence
satisfies the theorem. We have three cases:
(1)
Y nO(G)
=1. Then all chief factors below Y aresupple- mented, by [3, 2, 8].
Nowapply
4.4 toget
thatNl
isG-isomorphic
toN2.
(2)
1 Y nO(G)
and Y non-abelian. Then we can assumethat N is abelian and .M non-abelian.
By
order considerations P cannot coverY/N
andY/M
at the same time.(3)
1 Y nW(G)
and Y abelian.Suppose
first that ~P = P nn Y n
Ø(G)
= 1. Then Y =(P n Y) X ( Y n O(G))
and we can sup-pose that N n
O(G)
= 1. Then P is contained in some maximal com-plement
of N inG,
say U. Since Y nO(G)
Y nY,
Y nØ(G)==
= Yn TI. But
Y n JP Y n
and thenJP n Y = 1,
a contradiction. Therefore and
by
condition(b)
in the de-finition of
SCAP-subgroup, 1 #
W« G and then Y = W X N = W X .M.Hence
YIN
~aY/.ll
and N~a M. Finally
if andonly
if
O(G).
REMARK. If P = 1 this is Lafuente’s lemma in
[4].
If G is solu-ble
(and
P =1)
we obtain the Oarter-Fischer-Hawkes lemma[1; 2, 6].
EXAMPLE 2. Conditions
(a)
and(b)
in the definition of SCAP-subgroups
are necessary.Example
1 shows that we cannot remove(b).
To see the same for
(a),
take G =a,
b : a4 = b2 =[a, b]
=1~ ~
ro.J and P =
a 2b>.
Then P avoidsa2>
andb~.
Buta 2>
-
O(G)
andb~
iscomplemented by (~.
Here P is not contained in anycomplement
ofb>
in G.Notice that in this
example
P is a normalCAP-subgroup
whichis not a
SCAP-subgroup.
EXAMPLE 3.
SCAP-subgroups
are not theonly CA.P-subgroups satisfying
the thesis of theorem 4.5. Considerand Z =
z~
~Z3
such that ax =b,
bz = ab. Take twocopies Y1
and
V2
of Y’ and form W =Y1
XTr2
and then the semidirectproduct
G =
[W]Z.
Consider P =a2 b2, a2b2> (indexed
in the obviousway).
32
Any
chief series of (~ is of one of thefollowing
forms:P covers
Ø(G)/Ø(Vi)
andØ(G) Vt/Vt
andcertainly
Vt/Vt
for eachi,
t E{1, 2}.
So P satisfies the thesis of 4.5.However
P ~ ~(G)
and P is not normal in G and then P does not satisfies condition(b)
ofSCAP-subgroups.
Since P avoidsViIO(Vi)
but it is not contained in any
complement
ofVi/Ø(Vi)
inG,
P doesnot
satisfy
condition(a)
ofSCAP-subgroups
either.EXAMPLE 4. Take G = where N ~ Alt
(5)
~ M and con-sider P the
diagonal subgroup
P!2t-- Alt(5).
Then P is aCAP-subgroup
that avoids If and and N are G-related but not
G-isomorphic
since =
N ~
M = Here P is a maximalsubgroup
of Gand
REFERENCES
[1]
R. CARTER - B. FISCHER - T. HAWKES, Extreme classesof finite
solublegroups, J. of
Algebra,
9 (1968), pp. 285-313.[2]
P. FÖRSTER,Projektive
Klassen endlicherGruppen. -
I: Schunck-und Gast- chützklassen, Math. Z., 186(1984),
pp. 149-178.[3]
P. FÖRSTER,Chief factors,
Crowns and thegeneralised
Jordan-Hölder Theo-rem
(preprint).
[4]
J. LAFUENTE,Homomorphs
andformations of given
derived class, Math.Proc. Camb. Phil. Soc., 84 (1978), pp. 437-441.
[5]
K. U. SCHALLER,Über Deck-Meide- Untergruppen in
endlichenauflösbaren Gruppen,
Ph. D.University
of Kiel, 1971.Manoscritto