R ENDICONTI
del
S EMINARIO M ATEMATICO
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U NIVERSITÀ DI P ADOVA
G ABRIELLA D’E STE D IETER H APPEL
Representable equivalences are represented by tilting modules
Rendiconti del Seminario Matematico della Università di Padova, tome 83 (1990), p. 77-80
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Equivalences
are
Represented by Tilting Modules.
GABRIELLA D’ESTE - DIETER HAPPEL
(*)
Let .g be a
field,
let A be a finite-dimensionalK-algebra
and letAT
be a faithful and finite-dimensional left .A-module. Under these
hy- potheses,
we will showthat,
ifAT
induces anequivalence satisfying
the
requirements
of Menini-Orsatti’sRepresentation
Theorem[5],
thenAT
is atilting
module.The
proof
of this fact makes use, on the onehand,
of the resultson torsion theories induced
by tilting
modules obtainedby
Hoshino[4],
Assem
[1]
and Smalo[8], and,
on the otherhand,
of the new resultsobtained
by Colpi [2].
In this way, we solve an open
problem
of[3].
Before we do
this,
we recall some definitions.Let
AT
be a finite dimensional .A-module. ThenAT
is called a tilt-ing module,
if thefollowing
conditions are satisfied:(i)
Theprojective
dimension of,~T
is less than orequal
to 1.(iii)
There is an exact sequence of the formwith T’ and T n in add
T,
where add T denotes the additivecategory
whose
objects
are direct sums of direct summands ofAT.
(*) Indirizzo
degli
AA.: G. D’EsTE : Istituto di Matematica, Università di Salerno, 84100 SalernoItalia;
D. HAPPEL: Fakultät fur Mathematik, . Universitat Bielefeld, Postfach 8640, D 4800 Bielefeld 1, BR Deutschland.78
Finally,
let B and 8 be tworings,
let 9 be a fullsubcategory
ofleft R-modules closed under direct sums and factor
modules,
letbe a full
subcategory
of left S-modulescontaining ss
and closed undersubmodules,
and letbe an
equivalence
with F and G additive functors. Then Menini- Orsatti’s theorem([5]
Theorem3.1)
asserts that there is amodule RM,
with
endomorphism ring S,
such isthe
category
of all R-modulesgenerated by
whileand 0 is the
category
of all S-modulescogenerated by Homz (RM, RQ),
where
RQ
is aninjective cogenerator
of thecategory
of all R-modules.In the
following, according
to[2]
and[3],
such a module iscalled a *-module.
Using
thisterminology,
we deduce from([5]
Theorem
4.3)
that anytilting
module is a *-module.The next statement shows that the
relationship
between * -modules andtilting
modules is asstrong
asmight
beexpected.
In theproof
of the next theorem all modules will be finite-dimensional.
THEOREM 1. Let A be a finite-dimensional
.K-algebra,
letAT
bea finite-dimensional faithful *-module. Then
~T
is atilting
module.PROOF. Left 13 be the
category
of all modulesgenerated by AT.
We claim that
To see
this,
take anymodulo AX
and letAl
be aninjective
module such that SinceAT
isfaithful, 13
contains anyinjective module;
hence
AI E b. Moreover, applying HomA (AT, -)
to the short exact sequencewe get
the exact sequenceSuppose
first that 13.Then, by ([2] Corollary 4.2), Hom~ ~)
is
surjective. Hence, by ( ~ ),
we haveExt~ (~ T,
= 0.Assume now that
Ext’ (~T, d.X )
= 0. Then we deduce from( * )
that
Hom~ (~T, n)
issurjective. Consequently, by ([2] Proposition 4.3),
~X
G’6 and so b satisfies our claim. Itimmediately
follows that % is closed under extensions. Now letU
be the direct sum of a com-plete
set ofrepresentatives
of theisomorphism
classes of the inde-composable modules Ui
c- 73 which areExt-projective
in13, (see [1]
and
[8]),
that is with theproperty
thatExt’
= 0 for any.tX
e 13. Then we know from([8] Theorem) that
is atilting
module.Hence,
to prove thetheorem,
it suffices to check that addAT
== To this
end,
we first note that ourhypotheses
onAT
andthe above characterization of 13
imply
that add Nowlet
~V
be anindecomposable
summandThen, by ([2]
Theo-rem
4.1),
there is an exact sequence in 13 of the formSince
~Y
isExt-projective
in13,
it follows thatHence
using
the Krull-Schmidt theorem we infer thatadd U = - add ~T.
ThereforeAT
is atilting module,
and theproof
iscomplete.
As an immediate consequence of Theorem 1 and
([3]
Lemma1),
we obtain the
following corollary.
COROLLARY 2. Let .A be a finite-dimensional
K-algebra,
letA.l~
be a finite-dimensional module and let
~1 = A/annAM.
Then~.M
isa * -module if and
only
if1M
is atilting
module.The next remark
points
out anotherapplication
of Theorem 1.REMARK 3. Let .A be a finite-dimensional
K-algebra
and letAT
be an
co-tilting
module in the sense of[5].
Then,~T
is atilting
module.In
fact,
the definition of anm-tilting
moduleimplies
thatAT
is faithful andfinite-dimensional,
while([5]
Theorem4.3) guarantees
thatAT
is a ~ -module.
The
following
observationgives
apartial
answer to thequestion
whether or not ~ -modules over finite-dimensional
algebras
areactually finitely generated.
REMARK 4. Let A be a finite-dimensional
K-algebra,
and letbe a *-module. If A is
representation
finite[6],
then isfinitely
80
generated. Indeed,
ourhypothesis
on A and([7] Corollary 4.4)
guarantee
thatAM
is of the form where theNi’s
are inde-;
composable
modules of finite dimension over K. On the otherhand, by ([2]
Theorem4.1),
yAM
isself-small,
i.e. for anymorphism
I with for there exists a finite
?6j
subset such that C
Putting things together,
we~EF
conclude that
AM
=0 Nz
is the direct sum offinitely
manyNa’s.
Therefore is
finitely generated,
as claimed.REFERENCES
[1] I. ASSEM, Torsion theories induced
by tilting
modules, Can. J. Math., 36 (1984), pp. 899-913.[2]
R. COLPI, Some remarks onequivalences
betweencategories of
modules, toappear in Comm.
Algebra.
[3]
G. D’ESTE, Some remarks onrepresentable equivalences,
to appear in vol. 26 of the Banach Center Publications.[4]
M. HOSHINO,Tilting
modules and torsion theories, Bull. London Math.Soc., 14 (1982), pp. 334-336.
[5]
C. MENINI - A. ORSATTI,Representable equivalences
betweencategories of
modules and
applications,
Rend. Sem. Mat. Univ. Padova, 82(1989),
pp. 203-231.
[6] C. M. RINGEL, Tame
algebras
andintegral quadratic forms, Springer
LMN1099 (1984).
[7]
C. M. RINGEL - H. TACHIKAWA,QF-3 rings,
J. ReineAngew.
Math., 272(1974),
pp. 49-72.[8] S. O. SMALØ, Torsion theories and
tilting
modules, Bull. London Math.Soc., 16
(1984),
pp. 518-522.Manoscritto