Correction :
Exercice1:
f (x) 2x
x 1
D
f 1 ; 1 1;
f (2) 4
3 f ( 2) 4 f ( 2) f(2) f ( 2) f(2)
(C )
f( 1; 2)
d
c 1
a c 2
x 1 y 2
(P) y x
2A(1;1) B(2; 4)
(C )
fO(0;0) C(1;1) 4
D(2; ) 3
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prof: atmani najib
2x
2x 0
x 1
2x
2x 1 x
(C )
f(P)
S 2; 1 0;1
g 2 x
g(x) x 1
x 0 x 1 1 D
g
2 x 2 x
g( x) g(x)
x 1 x 1
x x f (x) g(x)
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Exercice2:
2 2
f (x) x 4
x
D
f x \ x 0
;0 0;
D
ff ( x) f (x) ( x)
2 x
2
4 2 2 2 4 2
2 2
2 2 2 2 2
2 2 2 2
2
4 4 a b 4b a b 4a
a b
f (a) f (b) a b a b (ab) (a b ) 4(a b )
T a b a b a b (ab) (a b)
2 2 2 2
2 2
((ab) 4)(a b ) ((ab) 4)(a b)
(ab) (a b) (ab)
2;
a 2 b 2 a b 2 2 a b
ab 2 (ab)
4 4 T 0 2;
0; 2
0 a 2 0 b 2 0 ab 2 a b 4 (ab)
24 0
0 a b 2 2 T 0
0; 2
2;
; 2
0; 2
2; 0
f (x) 4
2 2