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Mathematical analysis/Complex analysis
Faber polynomial coefficient bounds for a subclass of bi-univalent functions
Bornes des coefficients des développements en polynômes de Faber d’une sous-classe de fonctions bi-univalentes
¸Sahsene Altınkaya, Sibel Yalçın
DepartmentofMathematics,FacultyofArtsandScience,UludagUniversity,Bursa,Turkey
a r t i c l e i n f o a b s t r a c t
Articlehistory:
Received12February2015 Acceptedafterrevision31July2015 Availableonline31October2015 PresentedbytheEditorialBoard
Inthiswork,consideringageneralsubclassofbi-univalentfunctionsandusingtheFaber polynomials,weobtaincoefficientexpansionsforfunctions inthisclass.Incertaincases, ourestimatesimprovesomeofthoseexistingcoefficientbounds.
©2015Académiedessciences.PublishedbyElsevierMassonSAS.All rights reserved.
r é s u m é
Danscetarticle,onconsidèreunesous-classedefonctionsbi-univalentes ;enutilisantles développementsenpolynômesdeFaber,onobtientlescoefficientsdecesdéveloppements pourlesfonctionsdelasous-classeconsidérée.Danscertainscas,lesestimationssurles bornesdescoefficientsaméliorentdesrésultatsdéjàconnus.
©2015Académiedessciences.PublishedbyElsevierMassonSAS.All rights reserved.
1. Introduction
Let A denote the class of functions f that are analytic in the open unit disk U = { z : | z | < 1 } of the form f ( z ) = z +
∞n=2
a
nz
n. (1)
Let S be the subclass of A consisting of functions f that are also univalent in U , and let P be the class of functions
ϕ ( z ) = 1 +
∞ n=1ϕ
nz
nthat are analytic in U and satisfy the condition Re ( ϕ ( z )) > 0 in U . By the Caratheodory’s lemma (see, e.g., [11]) we have
| ϕ
n| ≤ 2.
E-mailaddress:[email protected]( ¸S. Altınkaya).
http://dx.doi.org/10.1016/j.crma.2015.09.003
1631-073X/©2015Académiedessciences.PublishedbyElsevierMassonSAS.All rights reserved.
Let f ∈ A. We define the differential operator D
p, p ∈ N
0= N ∪ { 0 } , where N = { 1 , 2 , . . .} , by (see [24]) D
0f ( z ) = f ( z ) ;
D
1f ( z ) = D f ( z ) = zf
( z ) ; .. .
D
pf ( z ) = D
1D
p−1f ( z )
.
The Koebe one-quarter theorem [11] states that the image of U under every function f from S contains a disk of radius
14. Thus, every such univalent function has an inverse f
−1that satisfies
f
−1( f ( z )) = z ( z ∈ U )
and f
f
−1( w )
= w
| w | < r
0( f ) , r
0( f ) ≥ 1 4
,
where
f
−1( w ) = w − a
2w
2+ 2a
22− a
3w
3−
5a
32− 5a
2a
3+ a
4w
4+ · · · .
A function f ( z ) ∈ A is said to be bi-univalent in U if both f ( z ) and f
−1( z ) are univalent in U . For a brief history and interesting examples in the class , see [27].
Lewin [19] studied the class of bi-univalent functions, obtaining the bound 1.51 for the modulus of the second coef- ficient | a
2| . Netanyahu [22] showed that max | a
2| =
43if f ( z ) ∈ . Subsequently, Brannan and Clunie [7] conjectured that
| a
2| ≤ √
2 for f ∈ . Brannan and Taha [8] introduced certain subclasses of the bi-univalent function class similar to the familiar subclasses. Recently, many authors investigated bounds for various subclasses of bi-univalent functions [5,10,13,18, 20,21,23,27–29].
The Faber polynomials introduced by Faber [12] play an important role in various areas of mathematical sciences, espe- cially in geometric function theory. Grunsky [14] succeeded in establishing a set of conditions for a given function that are necessary and in their totality sufficient for the univalency of this function, and in these conditions the coefficients of the Faber polynomials play an important role. Schiffer [26] gave differential equations for univalent functions solving certain extremum problems with respect to coefficients of such functions; in this differential equation a polynomial appears again, which is just the derivative of a Faber polynomial (Schaeffer–Spencer [25]).
Not much is known about the bounds on the general coefficient | a
n| for n ≥ 4. In the literature, there are only a few works determining the general coefficient bounds | a
n| for the analytic bi-univalent functions [6,9,16,15,17]. The coefficient estimate problem for each of | a
n| ( n ∈ N\ { 1 , 2 } ; N = { 1 , 2 , 3 , . . .}) is still an open problem.
For f ( z ) and F ( z ) analytic in U , we say that f ( z ) is subordinate to F ( z ) , written f ≺ F , if there exists a Schwarz function
u ( z ) =
∞n=1
c
nz
nwith | u ( z ) | < 1 in U , such that f ( z ) = F ( u ( z )) . For the Schwarz function u ( z ) , we note that | c
n| < 1. (e.g., see Duren [11]).
A function f ∈ is said to be B
( p , λ, ϕ ) , p ∈ N
0, and λ ≥ 0, if the following subordination holes
( 1 − λ) D
pf ( z ) + λ D
p+1f ( z )
z ≺ ϕ ( z ) (2)
and
( 1 − λ) D
pg ( w ) + λ D
p+1g ( w )
w ≺ ϕ ( w ) (3)
where g ( w ) = f
−1( w ) .
In this paper, we use the Faber polynomial expansions to obtain bounds for the general coefficients | a
n| of bi-univalent
functions in B
( p , λ, ϕ ) as well as we provide estimates for the initial coefficients of these functions.
2. Mainresults
Using the Faber polynomial expansion of functions f ∈ A of the form (1), the coefficients of its inverse map g = f
−1may be expressed as, [3],
g ( w ) = f
−1( w ) = w +
∞ n=21
n K
n−−n1( a
2, a
3, . . .) w
n,
where
K
n−−n1= ( − n ) !
(− 2n + 1 )! ( n − 1 )! a
n2−1+ ( − n ) !
[2 (− n + 1 ) ] ! ( n − 3 )! a
n2−3a
3+ ( − n ) !
(− 2n + 3 )! ( n − 4 )! a
n2−4a
4+ (− n )!
[2 (− n + 2 ) ] ! ( n − 5 )! a
n2−5a
5+ (− n + 2 ) a
23+ (− n )!
(− 2n + 5 )! ( n − 6 )! a
n2−6[a
6+ (− 2n + 5 ) a
3a
4] +
j≥7
a
n2−jV
j, (4)
such that V
jwith 7 ≤ j ≤ n is a homogeneous polynomial in the variables | a
2| , | a
3| , . . . , | a
n| [4]. In particular, the first three terms of K
n−−n1are
1
2 K
1−2= − a
2, 1
3 K
2−3= 2a
22− a
3, 1
4 K
3−4= −
5a
32− 5a
2a
3+ a
4. (5)
In general, for any p ∈ N and n ≥ 2, an expansion of K
np−1is as, [3], K
np−1= pa
n+ p ( p − 1 )
2 E
n2−1+ p ! ( p − 3 ) ! 3 ! E
3
n−1
+ . . . + p !
( p − n + 1 ) ! ( n − 1 ) ! E
n−1
n−1
, (6)
where E
np−1= E
np−1( a
2, a
3, . . .) and by [1], E
mn−1( a
2, . . . , a
n) =
∞n=2
m ! ( a
2)
μ1... ( a
n)
μn−1μ
1!... μ
n−1! , for m ≤ n
while a
1= 1, and the sum is taken over all nonnegative integers μ
1, . . . , μ
nsatisfying
μ
1+ μ
2+ . . . + μ
n−1= m , μ
1+ 2 μ
2+ . . . + ( n − 1 ) μ
n−1= n − 1 .
Evidently, E
nn−−11( a
2, . . . , a
n) = a
n2−1, [2]; or equivalently, E
mn( a
1, a
2, . . . , a
n) =
∞n=1
m ! ( a
1)
μ1... ( a
n)
μnμ
1!... μ
n! , for m ≤ n
while a
1= 1, and the sum is taken over all nonnegative integers μ
1, . . . , μ
nsatisfying
μ
1+ μ
2+ . . . + μ
n= m , μ
1+ 2 μ
2+ . . . + n μ
n= n .
It is clear that E
nn( a
1, a
2, . . . , a
n) = a
n1. The first and the last polynomials are:
E
n1= a
n, E
nn= a
n1.
Theorem1.
For 0 ≤ β < 1, λ ≥ 1 and p ∈ N
0, let f ∈ B
( p , λ, ϕ ) . If a
m= 0; 2 ≤ m ≤ n − 1, then
| a
n| ≤ 2
n
p[1 + ( n − 1 ) λ ] ; n ≥ 4 . (7)
Proof.
Let f be given by (1). We have
( 1 − λ) D
pf ( z ) + λ D
p+1f ( z )
z = 1 +
∞n=2
n
p[1 + ( n − 1 ) λ ]a
nz
n−1, (8) and for its inverse map, g = f
−1, we have
( 1 − λ) D
pg ( w ) + λ D
p+1g ( w )
w = 1 +
∞n=2
n
p[1 + ( n − 1 ) λ ] 1
n K
n−−n1( a
2, a
3, . . . , a
n) w
n−1= 1 +
∞ n=2n
p[1 + ( n − 1 ) λ ] b
nw
n−1. (9) On the other hand, for f ∈ B
( p , λ, ϕ ) and ϕ ∈ P there are two Schwarz functions
u ( z ) =
∞ n=1c
nz
nand
v ( w ) =
∞ n=1d
nw
nsuch that
( 1 − λ) D
pf ( z ) + λ D
p+1f ( z )
z = ϕ ( u ( z )) (10)
and
( 1 − λ) D
pg ( w ) + λ D
p+1g ( w )
w = ϕ ( v ( w )) (11)
where
ϕ ( u ( z )) = 1 +
∞n=1
nk=1
ϕ
kE
kn( c
1, c
2, . . . , c
n) z
n(12)
and
ϕ ( v ( w )) = 1 +
∞n=1
nk=1
ϕ
kE
kn( d
1, d
2, . . . , d
n) w
n. (13)
Comparing the corresponding coefficients of (10) and (12) yields
n
p[1 + ( n − 1 ) λ ]a
n=
n−1
k=1
ϕ
kE
kn−1( c
1, c
2, . . . , c
n−1) , n ≥ 2 (14)
and similarly, from (11) and (13), we obtain n
p[1 + ( n − 1 ) λ ]b
n=
n−1
k=1
ϕ
kE
kn−1( d
1, d
2, . . . , d
n−1) , n ≥ 2 . (15)
Note that for a
m= 0 ; 2 ≤ m ≤ n − 1 we have b
n= − a
nand so n
p[1 + ( n − 1 ) λ ]a
n= ϕ
1c
n−1,
− n
p[1 + ( n − 1 ) λ ]a
n= ϕ
1d
n−1. (16) Now taking the absolute values of either of the above two equations in (16) and using the facts that | ϕ
1| ≤ 2, | c
n−1| ≤ 1 and | d
n−1| ≤ 1, we obtain
| a
n| ≤ | ϕ
1c
n−1|
| n
p[1 + ( n − 1 ) λ ] | = | ϕ
1d
n−1|
| n
p[1 + ( n − 1 ) λ ] | ≤ 2
n
p[1 + ( n − 1 ) λ ] . 2 (17)
Theorem2.
Let f ∈ B
( p , λ, ϕ ) , λ ≥ 1. Then
( i ) | a
2| ≤ min 1
2
p−1( 1 + λ) , √ 2 3
p( 1 + 2 λ)
= 1
2
p−1( 1 + λ) ,
( ii ) | a
3| ≤ min 1
2
2p−2( 1 + λ)
2+ 2
3
p( 1 + 2 λ) , 2 3
p−1( 1 + 2 λ)
= 1
2
2p−2( 1 + λ)
2+ 2 3
p( 1 + 2 λ) ,
( iii ) a
3− η a
22≤
3p(12+η2λ); η = 1 , 2 . (18)
Proof.
Replacing n by 2 and 3 in (14) and (15), respectively, we find that
2
p( 1 + λ) a
2= ϕ
1c
1, (19)
3
p( 1 + 2 λ) a
3= ϕ
1c
2+ ϕ
2c
12, (20)
− 2
p( 1 + λ) a
2= ϕ
1d
1, (21)
3
p( 1 + 2 λ) ( 2a
22− a
3) = ϕ
1d
2+ ϕ
2d
21(22)
From (19) or (21) we obtain
| a
2| ≤ | ϕ
1c
1|
2
p( 1 + λ) = | ϕ
1d
1|
2
p( 1 + λ) ≤ 1
2
p−1( 1 + λ) . (23)
Adding (20) to (22) implies
2 . 3
p( 1 + 2 λ) a
22= ϕ
1( c
2+ d
2) + ϕ
2c
12+ d
21or, equivalently,
| a
2| ≤ √ 2
3
p( 1 + 2 λ) . (24)
From (20)
| a
3| = ϕ
1c
2+ ϕ
2c
213
p( 1 + 2 λ) ≤ 4 3
p( 1 + 2 λ) .
Next, in order to find the bound on the coefficient | a
3| , we subtract (22) from (20). We thus get 2 . 3
p( 1 + 2 λ)
a
3− a
22= ϕ
1( c
2− d
2) + ϕ
2c
21− d
21(25) or
| a
3| = | a
2|
2+ | ϕ
1( c
2− d
2)|
3
p( 1 + 2 λ) ≤ | a
2|
2+ 2
3
p( 1 + 2 λ) . (26)
Upon substituting the value of a
22from (23) and (24) into (26), it follows that
| a
3| ≤ 1
2
2p−2( 1 + λ)
2+ 2 3
p( 1 + 2 λ)
and
| a
3| ≤ 2 3
p−1( 1 + 2 λ) .
Finally, we rewrite (22) as
3
p( 1 + 2 λ) ( a
3− 2a
22) = −
ϕ
1d
2+ ϕ
2d
21and therefore
a
3− 2a
22= ϕ
1d
2+ ϕ
2d
213
p( 1 + 2 λ) ≤ 4
3
p( 1 + 2 λ) .
Solving the equation (25) for a
3− a
22, we obtain
a
3− a
22= ϕ
1( c
2− d
2) + ϕ
2c
21− d
213
p( 1 + 2 λ) ≤ 2
3
p( 1 + 2 λ) . 2
Remark3.
If we put p = 0 in Theorem 2, we obtain that the bounds on | a
2| and | a
3| are improvement of the estimates given in Frasin and Aouf [13].
Remark4.
If we put p = 0 , λ = 1 in Theorem 2, we obtain that the bounds on | a
2| and | a
3| are improvement of the estimates given in Srivastava et al. [27].
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