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Discrete Applied Mathematics
journal homepage:www.elsevier.com/locate/dam
A permutation code preserving a double Eulerian bistatistic
Jean-Luc Baril, Vincent Vajnovszki
∗LE2I, Université de Bourgogne Franche-Comté, BP 47870, 21078 Dijon Cedex, France
a r t i c l e i n f o
Article history:
Received 19 October 2016
Received in revised form 10 February 2017 Accepted 16 February 2017
Available online 22 March 2017
Keywords:
Set-valued/Eulerian statistic on permutation
Permutation/Lehmer code Subexcedant sequence Constructive bijection
a b s t r a c t
In 1977 Foata proved bijectively, among other things, that the joint distribution of ascent and distinct nonzero value numbers on the set of subexcedant sequences is the same as that of descent and inverse descent numbers on the set of permutations, and the generating function of the corresponding bistatistics is the double Eulerian polynomial. In 2013 Foata’s result was rediscovered by Visontai as a conjecture, and then reproved by Aas in 2014.
In this paper, we define a permutation code (that is, a bijection between permutations and subexcedant sequences) and show the more general result that two 5-tuples of set- valued statistics on the set of permutations and on the set of subexcedant sequences, respectively, are equidistributed. In particular, these results give another bijective proof of Foata’s result.
©2017 Published by Elsevier B.V.
1. Introduction
In enumerative combinatorics, it is a classical result that the descent numberdesand the inverse descent numberides (defined asides
π =
desπ
−1) on permutations are Eulerian statistics, and their distributions on the setSnof length-n permutations are given by thenth Eulerian polynomialAn, that isAn
(
u) =
π∈Sn
udesπ+1
=
π∈Sn
uidesπ+1
,
and the joint distribution ofdesandidesis given by thenth double Eulerian polynomial, An
(
u, v) =
π∈Sn
udesπ+1
v
idesπ+1,
see for instance [2,8].
An alternative way to represent a permutation is its Lehmer code [5], which is a subexcedant sequence. The ascent numberascon the setSnof subexcedant sequences is still an Eulerian statistic (see for example [9]), and in [7] the statistic that counts the number of distinct nonzero symbols in a subexcedant sequence (that following [1] we denote byrow) is proved to be still Eulerian; this result is credited to Dumont by the authors of [7]. In terms of generating functions, we have
An
(
u) =
s∈Sn
uascs+1
=
s∈Sn
urows+1
.
∗Corresponding author.
E-mail addresses:[email protected](J.-L. Baril),[email protected](V. Vajnovszki).
http://dx.doi.org/10.1016/j.dam.2017.02.014 0166-218X/©2017 Published by Elsevier B.V.
In 1977 Foata [4] proved, among other things, that the joint distribution ofdesandideson the set of permutations is the same as that ofascandrowon the set of subexcedant sequences, that is
An
(
u, v) =
π∈Sn
udesπ+1
v
idesπ+1=
s∈Sn
uascs+1
v
rows+1.
In the present paper, we define a bijection between permutations and subexcedant sequences (i.e., a permutation code) and show that the tuple of set-valued statistics
(
Des,
Ides,
Lrmax,
Lrmin,
Rlmax)
on the set of permutations, and(
Asc,
Row,
Posz,
Max,
Rlmax)
on the set of subexcedant sequenceshave the same distribution (each of the occurring statistics is defined below). In particular, our bijection provides set-valued partners forAsc(answering to a question in [1]) and gives a alternative proof of Foata’s result.
2. Notation and definitions
A length-n word
w
over the alphabetAis a sequencew
1w
2. . . w
nof symbols inA, and we will consider only finite alphabetsA⊂
N.Statistics
Astatisticon a setXof words is simply a function fromXtoN; aset-valued statistic is a function fromX to 2N; and a multistatisticis a tuple of statistics.
Let
w = w
1w
2. . . w
nbe a length-nword. Adescentinw
is a positioniinw
, 1≤
i<
n, withw
i> w
i+1, and thedescent setofw
isDes
w = {
i:
1≤
i<
nwithw
i> w
i+1} .
Aleft-to-right maximumin
w
is a positioniinw
, 1≤
i≤
n, withw
j< w
ifor allj<
i, and theset of left-to-right maximais Lrmaxw = {
i:
1≤
i≤
nwithw
j< w
ifor allj<
i} .
Clearly, 1
∈
Lrmaxw
, andDesandLrmaxare classical examples of set-valued statistics on words. We define similarly the setsAscw
ofascents,Lrminw
ofleft-to-right minima,Rlmaxw
ofright-to-left maximaandRlminw
ofright-to-left minimainw
.To each set-valued statisticStcorresponds an (integer-valued) statisticstdefined asst
w =
cardStw
, for exampledesw
andlrmaxw
count, respectively, the number of descents and the number of left-to-right maxima inw
.LetXandX′be two sets of words, andstandst′be two statistics defined onXandX′, respectively. We say thatstonX has thesame distributionasst′onX′(or equivalently,standst′areequidistributed) if, for any integeru,
card
{ w ∈
X:
stw =
u} =
card{ w ∈
X′:
st′w =
u} ,
and the multistatistic
(
st1,
st2, . . . ,
stp)
defined onXhas the same distribution as the multistatistic(
st′1,
st′2, . . . ,
st′p)
defined onX′(or the two multistatistics are equidistributed) if, for any integerp-tupleu= (
u1,
u2, . . . ,
up)
,card
{ w ∈
X: (
st1,
st2, . . . ,
stp) w =
u} =
card{ w ∈
X′: (
st′1,
st′2, . . . ,
st′p) w =
u} .
The notion of equidistribution of (multi)statistics can naturally be extended to set-valued (multi)statistics.
Permutations, subexcedant sequences and codes
This paper deals with two particular classes of words: permutations and subexcedant sequences. A permutation is a length- nword over
{
1,
2, . . . ,
n}
with distinct symbols. Alternatively, a permutation is an element of the symmetric group on{
1,
2, . . . ,
n}
written in one line notation, andSndenotes the set of length-npermutations. If two permutationsπ = π
1π
2. . . π
nandσ = σ
1σ
2. . . σ
nare such thatσ
π1σ
π2· · · σ
πn=
12· · ·
n(i.e., the identity inSn), thenσ
is theinverseofπ
, which is denoted byπ
−1.A length-n subexcedant sequence1is a words
=
s1s2. . .
snover{
0,
1, . . . ,
n−
1}
with 0≤
si≤
i−
1 for 1≤
i≤
n, and Sndenotes the set of length-nsubexcedant sequences; and we haveSn= {
0} × {
0,
1} × · · · × {
0,
1, . . . ,
n−
1}
.Some statistics are consistently defined only on particular classes of words,e.g.permutations or subexcedant sequences.
For a permutation
π ∈
Sn, aninverse descent(idesfor short) inπ
is a positionifor whichπ
i+
1 appears to the left ofπ
iin
π
. Equivalently,iis an ides inπ
ifπ
iis a descent inπ
−1. Theides setis defined as Idesπ = {
i:
1<
i≤
nwithπ
i+
1 appears inπ
to the left ofπ
i} ,
andides
π =
desπ
−1, but in generalIdesπ
is not equal toDesπ
−1.Lets
=
s1s2. . .
snbe a subexcedant sequence inSn. ThePoszstatistic gives the positions of 0s ins, Poszs= {
i:
1≤
i≤
n,
si=
0} ,
1 Known in the literature also asinversion sequence,inversion tableorsubexceedant function.
and obviously 1
∈
Poszs. TheMaxstatistic is defined as Maxs= {
i:
1≤
i≤
n,
si=
i−
1} ,
and as above, 1
∈
Maxs.Alast-value positioninsis a positioniinssuch thatsi
̸=
0 andsidoes not occur in the suffixsi+1si+2. . .
snofs. The last-value position set, denoted byRow, is defined asRows
= {
i:
si̸=
0 andsidoes not occur in the suffixsi+1si+2. . .
sn} .
Clearly, 1
̸∈
Rows, androws=
cardRowscounts the number of distinct nonzero symbols ins.Example 1. If
π =
6 2 5 8 7 3 1 4∈
S8ands=
0 1 1 0 2 3 6 3∈
S8, then Desπ =
Ascs= {
1,
4,
5,
6}
,Ides
π =
Rows= {
3,
5,
7,
8}
, Lrmaxπ =
Poszs= {
1,
4}
, Lrminπ =
Maxs= {
1,
2,
7}
, Rlmaxπ =
Rlmins= {
4,
5,
8}
.Aninversionin a permutation
π = π
1π
2. . . π
n∈
Snis a pair(
i,
j)
withi<
jandπ
i> π
j. The setSnis in bijection with Sn, and any such bijection is calledpermutation code. TheLehmer code Ldefined in [5] is a classical example of permutation code; it maps each permutationπ = π
1π
2. . . π
nto a subexcedant sequences1s2. . .
snwhere, for allj, 1≤
j≤
n,sjis the number of inversions(
i,
j)
inπ
(or equivalently, the number of entries inπ
larger thanπ
jand on its left). For example L(
6 2 5 8 7 3 1 4) =
0 1 1 0 1 4 6 4. See also [11] for a family of permutation codes in the context of Mahonian statistics on permutations.In [3] is showed thatdmcstatistic which counts the number of distinct nonzero symbols in the Lehmer code of a permu- tation
π
(the statisticπ →
rowL(π)
with the above notations) is Eulerian, and so has the same distribution asdes,ascor idesonSn. See also [10] where Dumont’s statisticdmcis extended to words.Although the following properties are folklore, they are easy to check.
Property 1. If
π ∈
Snand L(π) ∈
Snis its Lehmer code, thenDesπ =
AscL(π)
,Lrmaxπ =
PoszL(π)
,Lrminπ =
MaxL(π)
, andRlmaxπ =
RlminL(π)
.3. The permutation codeb
We define a mappingb:Sn
→
SnandTheorem 1shows thatbis a bijection, that is, a permutation code, and it is the main tool in proving that(
Des,
Ides,
Lrmax,
Lrmin,
Rlmax)
onSnhas the same distribution as(
Asc,
Row,
Posz,
Max,
Rlmax)
on Sn(seeTheorem 2).A positioniin
π = π
1π
2. . . π
n∈
Sn, 1≤
i≤
n, can satisfy the following properties:P1:
π
i+
1 occurs inπ
at the right ofπ
i, P2:π
i−
1 occurs inπ
0 at the right ofπ
i,where
π
0 is the permutation of{
0,
1, . . . ,
n}
obtained by adding a 0 at the end ofπ
. And, to each positioniinπ
, we associate an integerλ
i(π) ∈ {
0,
1,
2,
3}
according toisatisfies both, one, or none of these properties:λ
i(π) =
0
,
ifisatisfies both P1 and P2,
1,
ifisatisfies P2 but not P1,
2,
ifisatisfies P1 but not P2,
3,
ifisatisfies neither P1 nor P2,
and we denote it simply byλ
iwhen there is no ambiguity.Alternatively, using the Iverson bracket notation (
[
P] =
1 iff the statementP is true), we have the more concise expression:λ
i= [ π
i=
norπ
i+
1 occurs at the left ofπ
i] +
2· [ π
i−
1 occurs at the left ofπ
i]
.For example, for any
π ∈
Snwe haveλ
1=
0 exceptλ
1=
1 ifπ
1=
n; and whenn>
1, thenλ
n=
3 exceptλ
n=
2 ifπ
n=
1. Eachλ
iis uniquely determined byπ
, for instance ifπ =
6 2 5 8 7 3 1 4, thenλ
1, λ
2, . . . , λ
8=
0,
0,
1,
1,
3,
2,
1,
3, seeFig. 2.Aninterval I
= [
a,
b]
,a≤
b, is the set of integers{
x:
a≤
x≤
b}
; and alabeled intervalis a pair(
I, ℓ)
whereIis an interval andℓ
is an integer. In order to give the construction of the mappingb, we define below the slices of a permutation, and some of their properties are given inRemark 1.Definition 1. For a permutation
π = π
1π
2. . . π
n∈
Snand ani, 0≤
i<
n, theithsliceofπ
is the sequence of labeled intervalsUi(π) = (
I1, ℓ
1), (
I2, ℓ
2), . . . , (
Ik, ℓ
k)
, defined by the following process (seeFig. 1).Fig. 1. The four cases inDefinition 1.
•
U0(π) = ( [
0,
n] ,
0)
.•
Fori≥
1, letUi−1(π) = (
I1, ℓ
1), (
I2, ℓ
2), . . . , (
Ik, ℓ
k)
be the(
i−
1)
th slice ofπ
andv
, 1≤ v ≤
k, be the integer such thatπ
i∈
Iv. Theith sliceUi(π)
ofπ
is defined according toλ
i:– If
λ
i=
0 (or equivalently, minIv< π
i<
maxIv), thenUi
(π) = (
I1, ℓ
1), . . . , (
Iv−1, ℓ
v−1), (
H, ℓ
v), (
J, ℓ
v+1), (
Iv+1, ℓ
v+2), . . . , (
Ik−1, ℓ
k), (
Ik, ℓ
k+
1),
whereH= [ π
i+
1,
maxIv]
andJ= [
minIv, π
i−
1]
;– If
λ
i=
1 (or equivalently, minIv<
maxIv= π
i), thenUi
(π) = (
I1, ℓ
1), . . . , (
Iv−1, ℓ
v−1), (
J, ℓ
v+1), (
Iv+1, ℓ
v+2), . . . , (
Ik−1, ℓ
k), (
Ik, ℓ
k+
1),
whereJ= [
minIv, π
i−
1]
;– If
λ
i=
2 (or equivalently, minIv= π
i<
maxIv), thenUi
(π) = (
I1, ℓ
1), . . . , (
Iv−1, ℓ
v−1), (
J, ℓ
v), (
Iv+1, ℓ
v+1), . . . , (
Ik−1, ℓ
k−1), (
Ik, ℓ
k+
1),
whereJ= [ π
i+
1,
maxIv]
;– If
λ
i=
3 (or equivalently, minIv=
maxIv= π
i), thenUi
(π) = (
I1, ℓ
1), . . . , (
Iv−1, ℓ
v−1), (
Iv+1, ℓ
v+1), . . . , (
Ik−1, ℓ
k−1), (
Ik, ℓ
k+
1).
Example 2. For the permutation
π =
6 2 5 8 7 3 1 4 in Fig. 2,λ
1(π), λ
2(π), . . . , λ
8(π) =
0,
0,
1,
1,
3,
2,
1,
3, and the process described inDefinition 1gives the slices below.Remark 1. LetUi
(π) = (
I1, ℓ
1), (
I2, ℓ
2), . . . , (
Ik, ℓ
k)
be theith slice ofπ
, 0≤
i<
n. Then, the following properties can be easily checked:Fig. 2. The permutationπ=6 2 5 8 7 3 1 4 withb(π)=0 1 1 0 2 3 6 3 andλ1(π), λ2(π), . . . , λ8(π)=0,0,1,1,3,2,1,3.
– the intervalsI1
,
I2, . . . ,
Ikare in decreasing order, that is maxIj+1<
minIjfor anyj, 1≤
j<
k;– the sequence
ℓ
1, ℓ
2, . . . , ℓ
kis increasing, that isℓ
j< ℓ
j+1for anyj, 1≤
j<
k;–
{ ℓ
1, ℓ
2, . . . , ℓ
k} ⊆ [
0,
i]
, andℓ
k=
i;– 0
∈
Ik;–
∪
kj=1Ij= { π
i+1, π
i+2, . . . , π
n} ∪ {
0}
;– the
(
i+
1)
th entry of the Lehmer code ofπ
is given by the number of entriesπ
j> π
i+1, withj<
i+
1, that is the cardinality of[ π
i+1,
n] \ ∪
kj=1Ij.A byproduct ofDefinition 1is the construction ofb:Sn
→
Sndefined below.Definition 2. Let
π = π
1π
2. . . π
n∈
Sn. For eachi, 1≤
i≤
n, we definebi= ℓ
v, wherev
is such that(
Iv, ℓ
v)
is a labeled interval in the(
i−
1)
th slice ofπ
withπ
i∈
Iv, and we denote byb(π)
the sequenceb1b2. . .
bn.FromRemark 1it follows thatb
(π)
is a subexcedant sequence, see for instanceExample 2andFig. 2.Proposition 1. Let
π = π
1π
2. . . π
n∈
Sn, b(π) =
b1b2. . .
bn, and let an i,1≤
i≤
n.1. i is a descent in
π
iff i is an ascent in b(π)
;2. i is an ides in
π
iff bidoes not occur in bi+1bi+2. . .
bn; 3. i is a left-to-right maximum inπ
iff bi=
0;4. i is a left-to-right minimum in
π
iff bi=
i−
1;5. i is a right-to-left maximum in
π
iff i is right-to-left minimum in b.Proof. Points 1 and 2 obviously follow from the definition ofb.
Point 3. Letjbe such that
π
j=
n;bi=
0 iffi≤
jandπ
ilies in the first interval of the(
i−
1)
th slice ofπ
, which in turn is equivalent toiis a left-to-right maximum inπ
.Point 4. Similarly, letjbe such that
π
j=
1;bi=
i−
1 iffi≤
jandπ
ilies in the last interval of the(
i−
1)
th slice ofπ
, which in turn is equivalent toiis a left-to-right minimum inπ
.Point 5. By the construction ofb,iis a right-to-left maximum in
π
iffπ
iis the largest element of the first interval of the(
i−
1)
th slice ofπ
, which in turn is equivalent tobiis smaller than any ofbi+1,
bi+2, . . . ,
bn.See for instanceExample 1, wheres
=
b(π)
.For a length-nsubexcedant sequenceb
=
b1b2. . .
bn, let us consider the following properties that a positioni, 1≤
i≤
n, can satisfy:R1: bioccurs in the suffixbi+1bi+2
. . .
bnofb, R2: i−
1 occurs inb.The next proposition shows that each
λ
i(π)
can be obtained solely fromb(π)
. Proposition 2. Letπ ∈
Snand b(π) =
b1b2. . .
bn. Then, for any i,1≤
i≤
n, we haveλ
i(π) =
0
,
if i satisfies both R1 and R2,
1,
if i satisfies R2 but not R1,
2,
if i satisfies R1 but not R2,
3,
if i satisfies neither R1 nor R2.
Proof. By the construction given inDefinition 2forb
(π)
from the slices ofπ
, it follows that the positioniinπ
satisfies property P1 (resp. P2) if and only if the positioniinb(π)
satisfies property R1 (resp. R2), and the statement holds.Proposition 3. Let
π, σ ∈
Snwith b(π) =
b(σ )
. Then 1.λ
i(π) = λ
i(σ )
for any i,1≤
i≤
n.2. If
(
I1, ℓ
1), (
I2, ℓ
2), . . . , (
Ik, ℓ
k)
is the ith slice ofπ
, and(
J1,
m1), (
J2,
m2), . . . , (
Jp,
mp)
that ofσ
, for some i,1≤
i<
n, then k=
p andℓ
j=
mj, for1≤
j≤
k.Proof. The first point is a consequence ofProposition 2.
The second point follows by the next considerations. Theith slice of
π
,i≤
1<
n, has the same number of intervals as its(
i−
1)
th slice, except in two cases:λ
i(π) =
0 (when an interval is split into two intervals); and whenλ
i(π) =
3 (when a one-element interval is removed). The result follows by considering the first point and by induction oni.The sequenceb
(π) =
b1b2. . .
bn∈
Snwas defined by means of the slices ofπ
, but in proving the bijectivity ofbwe need rather the complement of these slices. Letπ ∈
SnandUi(π) = (
I1, ℓ
1), (
I2, ℓ
2), . . . , (
Ik, ℓ
k)
be theith slice ofπ
for ani, 1≤
i<
n. Theithprofileofπ
is the sequenceX1,
X2, . . . ,
Xpof decreasing nonempty maximal intervals (that is, maxXj+1<
minXj, and none of them has the formXj∪
Xj+1) with∪
pj=1Xj= {
1,
2, . . . ,
n} \ ∪
kj=1Ij. And, clearly,∪
pj=1Xjis the set of entries inπ
to the left ofπ
i+1, andpj=1cardXj
=
i.Example 3. The vertical gray regions on the right side ofExample 2correspond to the profiles of
π =
6 2 5 8 7 3 1 4 inFig. 2.These profiles are
[
6,
6]
;[
6,
6] , [
2,
2]
;[
5,
6] , [
2,
2]
;[
8,
8] , [
5,
6] , [
2,
2]
;[
5,
8] , [
2,
2]
;[
5,
8] , [
2,
3]
; and[
5,
8] , [
1,
3]
. In the proof ofTheorem 1, we need the next result.Proposition 4. Let
π, σ ∈
Snwith b(π) =
b(σ)
, and let an i,1≤
i<
n. If X1,
X2, . . . ,
Xpand Y1,
Y2, . . . ,
Ymare the ith profiles ofπ
and ofσ
, then– n
∈
X1if and only if n∈
Y1, – p=
m, and– cardXj
=
cardYjfor any j,1≤
j≤
p.Proof. It is easy to see thatn
∈
X1iff 0 does not appear inbi+1(π) . . .
bn(π) =
bi+1(σ) . . .
bn(σ)
, that is, iffn∈
Y1. And, if i=
1, then the first profile ofπ
and ofσ
are one-element intervals, and the statement holds.From the first point ofProposition 3, we have
λ
i(π) = λ
i(σ )
. Suppose that the statement is true fori−
1, and we will prove it fori.In passing from the
(
i−
1)
th profiles ofπ
and ofσ
to theirith profiles, the following cases can occur (we refer the reader toDefinition 1andFig. 1).– If
λ
i(π) = λ
i(σ ) =
0, orλ
i(π) = λ
i(σ ) =
1 andbi(π) =
bi(σ ) =
0, then a new one-element interval is added to theith profile ofπ
and ofσ
. Moreover, sinceb(π) =
b(σ)
, by the second point ofProposition 3, it follows that these intervals are both, for somek, thekth intervals in theith profile ofπ
andσ
.– If
λ
i(π) = λ
i(σ ) =
1 andbi(π) =
bi(σ ) ̸=
0, then for somek, a new element is added to thekth interval of bothith profiles ofπ
andσ
; this element is the smallest one in the obtained intervals.– If
λ
i(π) = λ
i(σ ) =
2, orλ
i(π) = λ
i(σ) =
3 andbi(π) =
bi(σ ) =
0, then for somek, a new element is added to thekth interval of bothith profiles ofπ
andσ
; this element is the largest one in the obtained intervals.– If
λ
i(π) = λ
i(σ ) =
3 andbi(π) =
bi(σ ) ̸=
0, then two consecutive intervals are merged in theith profiles ofπ
and ofσ
: thekth and(
k+
1)
th ones, for somek.Now, we explain how the Lehmer codec1c2
. . .
cnis linked to the profiles of a permutation. By definition,c1=
0 and ci,i>
1, is the number of entries inπ
at the left ofπ
iand larger thanπ
i. IfX1,
X2, . . . ,
Xpis the(
i−
1)
th profile ofπ
, it follows thatci=
uj=1cardXj, whereuis such that
∪
uj=1Xjis the set of entries inπ
at the left ofπ
iand larger thanπ
i, and soci=
card∪
uj=1Xj.Theorem 1. The mapping b:Sn
→
Snis a bijection.Proof. Let
π, σ ∈
Snwithb(π) =
b(σ)
, andc1c2. . .
cnandd1d2. . .
dnbe the Lehmer codes ofπ
andσ
. Let alsoibe an integer, 1<
i≤
n, and(
I1, ℓ
1), (
I2, ℓ
2), . . . , (
Ik, ℓ
k)
be the(
i−
1)
th slice ofπ
, andv
such thatπ
i∈
Iv(seeDefinition 2). If X1,
X2, . . . ,
Xpis the(
i−
1)
th profile ofπ
, thenifn
∈
X1, it follows thatci=
vj=1cardXj, and ifn
̸∈
X1, it follows thatci=
v−1j=1 cardXj.
Sinceb
(π) =
b(σ )
, combiningProposition 4and the second point ofProposition 3, we have thatci=
di. It follows that the Lehmer code ofπ
and ofσ
are equal, and so areπ
andσ
, and thusbis injective. And, by cardinality reasons, it follows that bis bijective.It is straightforward to see that the 4-tuple of statistics
(
Des,
Lrmax,
Lrmin,
Rlmax)
onSnhas the same distribution as(
Asc,
Posz,
Max,
Rlmin)
onSn. Indeed, for the Lehmer codeL(π)
of a permutationπ
, we have(
Des,
Lrmax,
Lrmin,
Rlmax) π = (
Asc,
Posz,
Max,
Rlmin)
L(π)
, see Property 1. But, generally,Idesπ
is different from RowL(π)
. For example, ifπ =
6 2 5 8 7 3 1 4, thenL(π) =
0 1 1 0 1 4 6 4,Idesπ = {
3,
5,
7,
8}
andRowL(π) = {
5,
7,
8}
.CombiningTheorem 1andProposition 1, it follows thatbbehaves not only as the Lehmer code for the above 4-tuples of statistics, but also it transformsIdes
π
intoRowb(π)
. Formally, we have the next theorem, which subsequently givesRow as a set-valued partner forAsc, thereby answering to an open question stated in [1].Theorem 2.For any
π ∈
Sn,(
Des,
Ides,
Lrmax,
Lrmin,
Rlmax) π = (
Asc,
Row,
Posz,
Max,
Rlmin)
b(π),
and so the multistatistic
(
Des,
Ides,
Lrmax,
Lrmin,
Rlmax)
onSnhas the same distribution as(
Asc,
Row,
Posz,
Max,
Rlmin)
on Sn.The next corollaries are consequences ofTheorem 2. The first of them is Foata’s result in [4] saying that
(
asc,
row)
on subexcedant sequences is a double Eulerian bistatistic.Corollary 1. The bistatistics
(
asc,
row)
on the set of subexcedant sequences has the same distribution as(
des,
ides)
on the set of permutations.Corollary 2. The bistatistics
(
asc,
row)
and(
row,
asc)
are equidistributed on the set of subexcedant sequences.Proof. Lets
∈
Snand let us definet=
b(σ )
whereσ = π
−1withπ =
b−1(
s)
. It is clear that(
asc,
row)
s= (
des,
ides) π = (
ides,
des) σ = (
row,
asc)
t.Final remarks: Recently, Lin and Kim [6] defined a bijectionΨ between two combinatorial classes counted by the large Schröder numbers, namely the setSn
(
021)
of subexcedant sequences avoiding the pattern 021, and the setSn(
2413,
4213)
of permutations avoiding the patterns 2413 and 4213. In [6], it is shown thatΨ proves the equidistribution of two 6-tuples of set-valued statistics, that is(
Asc,
Row,
Posz,
Max,
Rlmin,
Expo)
s= (
Des,
Ides,
Lrmax,
Lrmin,
Rlmax,
Rlmin)
Ψ(
s),
for anys
∈
Sn(
021)
. Here,Expois theexposed positions statisticdefine in [6], and if the last statistic of both 6-tuples is dropped out, then the 5-tuples in ourTheorem 2are obtained. Also in [6] is pointed out that the restriction of our mapping byields a bijection betweenSn(
2413,
4213)
andSn(
021)
, but unlikeΨ−1, this restriction ofbdoes not transformRlmin toExpo.References
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