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Abelian groups in which every Γ-isotype subgroup is a pure subgroup, resp. an isotype subgroup
Rendiconti del Seminario Matematico della Università di Padova, tome 62 (1980), p. 251-259
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Groups Every 0393- Isotype Subgroup
is
aPure Subgroup, Resp.
anIsotype Subgroup.
JINDRICH
BE010DVÁ0159
All groups considered in this paper are abelian.
Concerning
theterminology
andnotation,
we refer to[3].
Inaddition,
if G is a group then6~
t andGp
are the torsionpart
of G and thep-component
of6~
trespectively.
Let G be a group and p aprime. Following Ranga-
swamy
[10]
we say that asubgroup H
of G isp-absorbing,
resp. ab-sorbing
in G if(GIH), - 0,
resp. = 0. Asubgroup
H of G issaid to be
isotype
in G if for allprimes p
and allordinals «. Recall that if H is
p-absorbing
in G thenpag
= H r1paG
for every ordinal «
(see
lemma 103.1[3]).
Let N be the set of all
positive integers,
... be the sequence of allprimes
in the natural order and X the class of all sequences(«1 ,
«2 ,...),
where each «i is either an ordinal or thesymbol
oo whichis considered to be
larger
than any ordinal. Let G be a group and -V =(«1,
«2,...)eJ~.
Asubgroup
H of G is said to ber-isotype
in Gif for every i E N and for every
ordinal B ai.
If
r == (0, 0, ...),
1-’ _(1, 1, ... ), 1-’ _ (c~, c~, ... ), 1-’ _ ( oo, oo, ... )
thenT-isotype subgroups
of G areprecisely subgroups,
neatsubgroups
pure
subgroups, isotype subgroups respectively.
Note that if 1-’ _(al
«2,...),
7 .I" -(«i, (i.e.
for eachi E N)
then every
V’-isotype subgroup
of G isr-isotype
in G. Let G be ap-group, y be an ordinal or the
symbol
oo. Asubgroup H
of G is said to bey-isotype
in G if for everyordinal By.
A direct sum of
cyclic
groups of the same orderpe,
is denotedby Be .
(*)
Indirizzo dell’A.:Matematicko-Fyzikální
Fakulta, Universita Karlova - Sokolovska 83 - 18600 Praha 8(Ceskoslovensko).
252
The purpose of this paper is to describe the classes of all groups in which every
T-isotype subgroup
is aneat,
a pure, anisotype
sub-group, a direct
summand,
an absolute directsummand,
anabsorbing subgroup respectively.
Here are sogeneralized
the results of thistype
from[1], [2], [4], [6]-[9], [11], [13] (see [I]-introduction).
LEMMA 1. Let G be a torsion group and 1~’ =
(!Xl’
a2,...)
E Je.A
subgroup
H of G isT-isotype
in G iff isa2-isotype
in forevery
PROOF. Obvious.
LEMMA 2. Let G be a p-group, g E G an element of order
The
subgroup g~
isk-isotype
in G iff _~ k -1.Moreover,
the
subgroup g~
is pure(isotype)
in G iff ===PROOF.
Easy.
LEMMA 3. Let .g be a
subgroup
of agroup G
and p aprime.
IfGp
is divisible and
pH =
H then = H for every ordinal a.PROOF.
Obviously, Htp
is neat in6~
and henceHD
is divisible.Write and where Since H’ is
p-absorbing
inG’,
the result follows.LEMMA 4. Let G be a p-group If every
k-isotype
sub-group of G is a pure
subgroup
of G then either G= D @ B,
where Dis divisible and =
0,
orpk-1G
= for some e E liT.PROOF. Let
G = D ~ B,
where D is nonzero divisible and B is reduced.Suppose
B = whereo(a) = p~ and j ~ k;
let d E Dbe an element of order
pj+’-. By
lemma2, a -~- d~
isk-isotype
in Gbut is not pure in G-a contradiction. Hence = 0 .
Let G be reduced.
Suppose
G =~a~ ~ (b) @ G’,
whereo(a)
=pi,
~o(b) = p-
andm - 2 > j > k. By
lemma2,
thesubgroup ~a -~- pb~
isk-isotype
in G but is not pure in G-a contradiction. If B is a basicsubgroup
of G thenobviously
where and hence
(e
= m - k+ 1).
LEMMA 5. Let G be a group, p a
prime
anda #
ordinals. If is not essential inpaGp
and either is nonzero orp~G
is nottorsion then there is a
sugroup .g
of G withfollowing properties:
H is
q-absorbing
in G for every = H npvG
for everyordinal
a+1
andpØ+l H =1=
H npO+ 1
G.PROOF
(see
lemma 3[1]).
There is a nonzero elementsuch that Let such that either
0 =l=pgEGp
or
o(g)
= oo. Write X =+ g).
It is easy to see thatn>
= 0. Let H be ansubgroup
of Gcontaining
X.H m p v G
for every ordinal Sincenpp+IG. By
lemma 6[1],
H isq-absorbing
in G for everyprime q =1= p.
THEOREM 1. Let G be a group and 1~ _
(«1,
«2,... )
The fol-lowing
areequiv alent :
(i) Every T-isotype subgroup
of G is a puresubgroup
of G.(ii)
Forevery i
FN,
if then eitherD ~ B,
where Dis divisible and
0,
or G is torsion and iselementary
or Gis torsion and
= Be ~ Be+l
for some e E N.PROOF’. Assume
(i).
For each i EN,
everyai-isotype subgroup
of
G~;
isT’-isotype
in G and hence pure inBy
lemma 4 andby [4],
6~
is as claimed.Suppose
G is not torsion and «~ = 0 for some i E N.If
g E G is
an element of infinite order then and a sub- group H maximal withrespect
to theproperties
c His
T-isotype
in Gby
lemma 6[1].
Since H is pure inG,
there is anelement such that hence contra-
diction.
Finally,
if G is nottorsion,
«i C co for some i E N and then is not essential innot torsion and lemma 5
implies
a contradiction.Assume
(ii).
Let H be anhisotype subgroup
of G and«i and p = p,. If then H is p-pure in G. If
j8
= 0then
by assumption
G is torsion andGp
iselementary;
write G= G~ ~
G’For every
i.e. H is p-pure in G. Let 0
C ~8
co.Suppose
that =~+1
and G is torsion.
By
lemma1,
i.e. is neat in
pp-IG1J’ By [9], pP-l Htp
is pure in and henceHp
is pure inGp . Consequently,
H is p-pure in G.Suppose
thatD 0 B,
where D is divisible and = 0.Now,
254
Since is
divisible,
is p-pure inpfl-"G by
lemma 3.Therefore I~’ is p-pure in G.
THEOREM 2. Let G be a group and 7~==
(«l,
Ct2,...)
E Je.Every T-isotype subgroup
of G is a direct summand of G iff thefollowing
conditions hold:
(i)
G = where T is torsionreduced,
D is divisible and N is a direct sum of a finite numbermutually isomorphic
torsion-free rank one groups;
(ii)
if then either 0 or G is torsion andGp=
is
elementary
or G is torsion and0
for some e(iii)
if then is bounded.PROOF. If every
T-isotype subgroup
of G is a direct summand of G then everyisotype subgroup
of G is a direct summand of G and every.I’-isotype subgroup
of G is pure in G.Now,
theorem 2[1]
andtheorem 1
imply (ii). Conversely, by
theorem1,
everyT’-isotype
sub-group of G is pure in G and
by [2],
every puresubgroup
of G is adirect summand of G.
For the similar result see
[12].
THEOREM 3. Let G be a group and T =
(«1,
«2 ,...)
E Je.Every T-isotype subgroup
of G is an absolute direct summand of G ii~ G satisfies one of thefollowing
two conditions:(i)
G is torsion and for everyi E N,
if «i = 0 then is
elementary,
if 0 «i then either is divisible or =
Be
for some e e N.(ii)
«a ~ 0 forevery i
c N and either G is divisible or G = whereG
is divisible and Z~ is of rank one.PROOF.
Every T-isotype subgroup
of G is an absolute direct sum-mand of G iff every
T-isotype subgroup
of G is a direct summand of Gand every direct summand of G is an absolute direct summand of G.
Now,
theorem 2 and[11] imply
the desired result.THEOREM 4. Let G be a group and 1-’ _
(«1 ,
The fol-lowing
areequivalent:
(i) Every F-isotype subgroup
of G is a neatsubgroup
of G.(ii)
If «i = 0 for some i E N thenGpi
iselementary
and G istorsion.
PROOF. Assume
(i). Every ai-isotype subgroup
ofOPi
isobviously .T’-isotype
in G and hence neat inG,,. By [11],
if a2 = 0 thenOPi
iselementary. Suppose
that G is not torsion and ai = 0 for some i E N.If g
E G is an element of infinite order then asubgroup
H of G maxi-mal with
respect
to theproperties .hisotype
in G
by
lemma 6[1]
butobviously
it is not a neatsubgroup
of G.Assume
(ii).
If ai > 0 for each then everyT-isotype
sub-group of G is neat in G.
Suppose G
is torsion and if ai = 0 thenGpi
is
elementary.
If .~ is anh-isotype subgroup
of G thenHpi
isLxi-isotype
in
Gp~
for each i E N and hence neat inGpi by [11]. Consequently,
I~‘is neat in G.
LEMMA 6. Let G be a group, p a
prime and fl
an ordinal. Let H be apOG-high subgroup
of G andaEpPG.
If for each or-dinal a then there is a
subgroup X
of G such that = X r1paG
for each ordinal and
pOX = (~).
PROOF. If
(o(a), p ) =
1 then write X =a>
and all is well. Hence suppose that plo(a)
oro(a~)
= 00.If @
is not a limit ordinal then there is an element such thatpb = a.
Ifb f/= pP 0
then write aa = b for every ordinal a~8
andb>.
If and then b’ = b+
cpb’ = a;
in this case write for every ordinal and~b’~. Obviously X.
npPG
=a>.
Let P
be a limit ordinal. For each ordinal a~
there is an ele-ment such that a = px. We use the transfinite induc- tion to define the sets
obviously
- and
(G
nXo)[p]
c~. Further, Xo,
where a, Eand pal = ac;
obviously X, ~a~
and(pG
nXl)[p]
cc
~~. Suppose
that has been defined such that =a>
and
(pol-’G
r1Xa_1)[p] c a),
defineXa.
If there is an element such that px = a then let and Xa =Xa_1.
Otherwise let
Xa = aa>,
where and pa, - a. We show that Xa =~ac~. Let y +
where and z is aninteger. Obviously
py 6X«-i
r1paG
=~ac~ ;
write py = ma, where m is aninteger.
If(p, m) =
1 then there areintegers
suchthat upa
+
vmac = a andp(ua + vy),
ua+
vy Exa-I
r1paG
-a contradiction. Hence
m = pm’, p (y - m’ a) = 0
andy - m’ a E
E
(pa-l-G
r1 ca~.
Therefore y Ea),
y+
zaca E npPO
==
~a~.
Further we show that(paG
r1X«)[p]
ca>.
Let y+
zaa EE
(p«G
r1Xa)[p], where y
E and z is aninteger;
hence py = - za.256
If
(p, z)
= 1 then a =vy), where u, v
areintegers,
ua - vy Ee r1 contradiction. Hence
.and therefore
y E ~a~. Now, Finally,
if « is a limitordinal then let
U X,
’Y"
Let X be a
subgroup
of G maximal withrespect
to theproperties:
=
a~,
X~ c X. We prove thatpaX
= for every It is sufficient to show that if thisequality
holds for « -1 then it holds for (x. Let i.e. x = pg, where g Epa-1 G.
If g
E X then g E X r1poc-1 G
=pa-1
X and x E pa X. Ifg ~
X then thereis an element and an
integer z
such that zg+
y EObviously y
and(z, p)
= 1. Since pzg+
py E X r1pPG
=a>,
zx
+
py = ra = and zx =y). Now,
E X r’1=
zXEptXX
andx E paX.
LEMMA 7. Let G be a p-group and
~8
an ordinal. Thefollowing
.are
equivalent:
(i) Every B-isotype subgroup
of G isisotype
in G.(ii)
Either G = where D is divisible andpvB
= 0 forsome ordinal or
pfl G
iselementary
or forsome
PROOF. Assume
(i). If
= 0 then G iselementary by [4].
If@
is a limit ordinal then write
a = fl,
otherwise write oc =fJ -1.
Letp«G
=D QQ I-~,
where D is divisible and R is reduced. If both D and Rare nonzero, write R = where
o(a)
=pk,
kEN. The sub-group
ptX+kG
is not essential inpa G, pa+k+lG =1= 0
and lemma 5implies
a contradiction. If
paG
is reduced andpaG
=b~ ~+ I~’,
where.o(a)
=pk, o(b)
=p3 and j - k ~ 2,
thenpa+xG
is not essential inpaG,
and lemma 5
implies
a contradiction.Consequently,
either is nonzero divisible or for some
If
« _ ~8 -1
then we arethrough,
since if is divisible thenand
obviously pxB 0.
Hence suppose Let be nonzerodivisible;
write G If for everyordinal
y #
and then there is a~-isotype subgroup X
of G such that
pOX
=a> by
lemma 6.Now,
= 0 ~(a) =
= contradiction. Hence
pvB
= 0 for some ordinaly
fl.
LetpPG
=Be+1
and suppose thatpPG
is notelementary.
If H is
p,6G-high subgroup
of G then for every ordinal y~ since @
is a limit ordinal. Let a E be a nonzero element..By
lemma6,
there is aB-isotype subgroup X
of G such thatpOX
=a>.
0-Now,
contradiction. Hence iselementary.
Assume
(ii).
Let H be a~-isotype subgroup
of G. If === then
hence is neat in and therefore is pure in
pfl-’G by [9]. Consequently,
for every natural number and moreover, if n ~ e
-~--
l then=0. If G =
D ~ B,
where D is divisible andpvB
= 0for some
y #
thenIf
pPG
iselementary
thenIn all cases, .H is
isotype
in G.THEOREM 5. Let G be a group and T =
... )
c JC. The fol-lowing
statements areequivalent:
(i) Every T-isotype subgroup
of G isisotype
in G.(ii)
Forevery i
EN,
either =D @ B,
where D is divisible and 0 for some ordinaly
cxi, or is torsion and iselementary
or is torsion and= Be O B,+,
for some e E N.PROOF. Assume
(i). Every mi-isotype subgroup
ofGpi
isisotype
in and
hence Gpi
is as claimed in(ii) by
lemma 7. Let ie N;
write«i and p = pi .
Suppose
thatpPG
is not torsion. Ifthen is not essential in and
pO+,,G
isnot torsion. If is nonzero
elementary
thenpP+IG1J
is not essentialin and is not torsion. In these both cases, lemma 5
implies
a contradiction.
258
Suppose
thatpaG
is nottorsion,
0 and for eachordinal y fl.
Let ac- p,8G, o(a)
= oo and A be ap#G-high subgroup
of G
containing 6p.
Hence for each ordinal yfl. By
lem-ma
6,
there is asubgroup X
of G such thatPyX
= X for everyordinal and
pOX
=pa>.
Let H be asubgroup
of G maximal withrespect
to theproperties: X c H, By
lemma 6[1],
H isq-absorbing
in G for every We prove thatfor each ordinal It is sufficient to show that if this
equality
holds
~
then it holds also for y. H npvG;
thereis such that
h = pg. Obviously h E py-1.H.
If thenh c-pvh.
Ifg 0 H
then a Eg, H),
i.e. a = zg+ h’,
where h’ E H and z is aninteger. Now, (~ ?)===!
andFurther,
there is such thatzh+ph’-px’. Hence zh = p (x’ - h’ ),
where andtherefore
Now,
and( p, z ) = l imply
Hence H is
T-isotype
in G.Finally, For,
if pa = py, whereyc-pOH,
then-a contradiction.
Consequently,
H is notisotype
in G.Assume
(ii).
If H is aF-isotype subgroup
of G thenHt
isF-isotype
in
G,
andby
lemma1,
eachHpi
isai-isotype
inBy
lemma7,
each is
isotype
in6~
andby
lemmal, I~t
isisotype
inGi.
Let
write @
= ai and p = pi . IfpaG
is torsion thenfor every
y >fl. Suppose
thatG~ =
where D is divisible and= 0 for some ordinal y
~.
Hence andp v H~
are divisible.Write
pvH
=pYHptfj
Y. SincepvG,
n Y =0, pvG
=pYGptfJ X,
whereY c X. We show that
pE Y = pEX
for each ordinal E. It is suf- ficient to show that if thisequality
holds for 8 then it holds also for8
+
1. LetYnpe+lX;
there isx E pEX
suchthat y
= px.Now,
there is such that
y = ph.
Writeh = h’ -f- y’,
where and Sincey = ph’ -~- py’, ph’ E
Hence
and therefore
y E pE+1 Y. Finally,
for each ordinal 8.
THEOREM 6. Let G be a nonzero group and .1~ _
( «1, ... )
C-The
following
areequivalent:
(i) Every T-isotype subgroup
of G is anabsorbing subgroup
of G.(ii)
Either G is torsion-free and 0 for each i E N or G iscocyclic
and if « i = 0 for s ome i E N then eitherG,,
= 0 or G =PROOF.
Every T-isotype subgroup
of G isabsorbing
in G iff every-V-isotype subgroup
of G isisotype
in G and everyisotype subgroup
of G is
absorbing
in G.Now,
theorem 5 and theorem 6[1] imply
thedesired result.
’
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