R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
C ARLO C ASOLO
Groups with subnormal subgroups of bounded defect
Rendiconti del Seminario Matematico della Università di Padova, tome 77 (1987), p. 177-187
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Groups Subgroups
CARLO CASOLO
(*)
1. The
principal object
of this note are soluble p-groups with a bound on the defects of their subnormalsubgroups.
We denoteby ll3n
the class of groups in which every subnormal
subgroup
has defect00
at
most n,
andput 113
=U ll3n.
n=l
It is well known that soluble groups in
B1 (more
often calledT-groups)
are metabelian[3], [9];
while there is no bound on the derivedlength
of soluble groups in~2’
as shownby
Robinson in[11].
However in
[2]
weproved
thatperiodic
soluble groups in8)2
havebounded derived
length
and that a soluble p-group in~2
has derivedlength
at most 4. Here we prove:THEOREM every
prime
p and everypositive integer d,
thereexists a soluble
p-group in ~4
with derivedlength exactly
d.We leave open the
question
whether soluble p-groups in~3
havebounded derived
length.
Soluble p-groups in the class 58 are the
object
of a paperby McDougall[8].
He denotes withQ
the class ofperiodic
abelian di-visible groups, and with
PQ and PQ
the classes of groupsadmitting respectively
a finite or anascending
series whose factors areQ-groups.
As a consequence of Theorem
1,
wegive
an answer to aquestion posed by McDougall
in his paper.(*)
Indirizzo dell’A. : Istituto di Matematica, Informatica e Sistemistica, Via Zanoni 6, 33100 Udine.The author
aknowledges
the very kindhospitality
of the Mathematics Institute of theUniversity
of Warwick while this work was done.THEOREM 2. For every
prime
p, there exists a non soluble p-group which is aPQ-group (hence hyperabelian)
and has a bound on thedefects of
its subnormalsubgroups,.
We will show that the groups constructed in order to prove The-
orem 2
actually
are in the class~5.
Theorem 1
yields
also a similar result forSD-groups,
that is groupsadmitting
adescending
series with abelian factors.THEOREM 3. For every
prime
p, there exists alocally finite
p-group in~4’
which is aSD-group
and whose Baer radical is trivial.We wish to observe here that Leinen has
recently
shown in his doctoral dissertation[6],
y thatlocally
finite p-groups in~1
need notto be
soluble,
thusanswering
aquestion
which had been open fora certain time
(see
Robinson[13],
Vol.I,
pag.174).
Finite soluble groups in
~2
have derivedlength
at most 5([1], [7]).
By
contrast Hawkes[5]
proves that every finite soluble group is iso-morphic
to asubgroup
of a finite soluble group in The groups in obtainedby
Hawkes’sprocedure have,
at least for oneprime p, Sylow p-subgroups
ofhigh >>
derivedlength;
therefore T. Hawkesasked whether there are
A-groups
in~n
ofarbitrary
derivedlength,
where an
A-group
is a finite group all of whoseSylow subgroups
areabelian.
Using
the sametechnique
used to prove Theorem1,
wegive
an answer to thisquestion
for n = 4.THEOREM 4. For every
positive integer d,
there exists a solubleA-group
in~4’
with derivedlength exactly
d.Throughout
the paper, g wr K willalways
denote the restricted standard wreathproduct
of the group gby
the group.g,
andyn(G)
will denote the n-th term of the lower central series of the group G.
2. The
proofs
of Theorems 1 and 4 are similar and based upona construction for which is basic the
following
extension of a lemma of P. Hall’s.LEMMA 1. Let H and K be groups, and B denote the base group
of
H wr K.
If
subnormalof defect
n in BS and the expo- nent(1) of BSjB
isgreater
than n, then(1) By « exponent »
of group G, we mean the supremum among the orders of the elements of G.PROOF. We consider H wr .g as the semidirect
product [B].K,
andproceed by
induction on n.Let rSaBS
(P.
Hall[4],
Lemma4);
there exists suchthat xB
E SB,
and let b E B such that bx E S. LetHz
be the coor- dinatesubgroup
of B related to z EK,
andlet h, g
EHz.
We haveand therefore:
since as Hence
~S > Hz .
Thesame is true for any therefore
~S ~ B’ = y2 (B) .
Assume now n >
1,
and letYES
such that(yB)i
=yi B =1= B
fori =
1,
..., n, andwrite y
= bx with b eB, x
E K and Xi =1= 1 fori =
1,
... , n. Let withSi
of defect n -1 inBS1
= BS.Since we
have, by
inductivehypothesis,
Let
Hz
be the coordinatesubgroup
of Bcorresponding
to z eK,
andlet f
eHz
and g e Since 1 for i =1,
... , n, the groups andpermute
if1 c ?,
Therefore we have:and, by
induction on n, it is easy to check that:Since g E
8]81
and S has defect n inBS,
we now have:as
Hx
commutes with.blxx · · · gxxn
·Therefore · The same is true for any
hence 0
REMARK. The
hypothesis
exp(SBIB)
> n in Lemma 1 cannot be relaxed to > n.Let,
infact,
.H be thesymmetric
group on threeobjects
and K be anelementary
abelian group of order 4. It is easy to check that has a subnormalsubgroup S
ofdefect
3,
such that SB = W but S does not containB’,
where B isa,gain
the base group of W.3. In his paper on soluble p-groups in the +ass b
[8], McDougall
proves that every soluble p-group in 93 is the extention of a
PQ-group (that
is a groupadmitting
a finite series whose factors areperiodic
abelian divisible
groups) by
anilpotent
group.Since, by
a Theoremof Roseblade’s
[14], nilpotent
groups in~n
have class boundedby
a function of n, in order to prove Theorem 1 we need to construct
PQ-groups
in~4
witharbitrary
derivedlength.
For the
properties
ofPQ-groups
that we willneed,
we refer tothe
quoted
paperby McDougall.
LEMMA 2. Let H be a p-group in
PQ,
K aperiodic
group, B the base groupof
H wr.g,
and let S be a subnormalsubgroup of
BS. Theneither
~S’ ~ B’ .
PROOF. Assume
S ~ B.
We prove thatby
induction onthe defect n of 8 in BS.
In n =
1,
then the result is aparticular
case of Lemma 1. Assumen > 1 and let with
Sl
of defect n -1 in SB.Clearly hence, by
inductivehypothesis,
It is clear that B is aPQ-group and, therefore,
is a normalperiodic
abelian di- visiblesubgroup
of8BIB’;
since .Kand,
inparticular,
is aperiodic
group, we have that normalizes(see
Robinson
[10],
Lemma2.2).
HenceSi
is normal in SB and so n = 2.If has
exponent greater
than2,
thenby
Lemma1,
and,
since B is aPQ-group,
we have = B’(McDougall [8],
Th.
4.8), yielding ~S’~B’.
Assume now exp(BBIB)
= 2. Let y E~B,
then with x E .g and ~==1. Let
Hx
be acoordinate
subgroup
inB,
and t EHz;
since S has defect 2 inSB,
we have
[t, 2bx] E S and, by expanding
the commutarorusing
thefacts that = 1 and x2 =
1,
weget:
Let now
f, g, hE Hz
andw = [h, g],
then Since isdivisible,
there exist such that Sincewe have:
as commutes with
Hzz.
Hence:Since we have also:
and, by comparing
with(+),
weget: [w,
ES, yielding
Hence =
H’,
and soS>B’.
l7Let G be a group; we denote
by D(G) = D1(G)
the maximal normal divisibleperiodic
abeliansubgroup
of G(see
e.g. Robinson[10],
Lemma
2.2)
and weput:
=D(G/Dn_1(G))
for any n > 1.If G E
PQ
then there is a minimalinteger n
such thatDn(G)
= G.Such n is called the
Q-length
ofG,
and it isequal
to the derivedlength
ofG, according
to a result ofMcDougall ([8], Th. 4.5).
PROOF OF THEOREM 1.
By
induction on n, we construct a p-group inPQ
r1~4
with derivedlength
2n(to get
a group of therequired type
and odd derivedlength
we can take the derivedsubgroup
ofone of the groups we will
construct).
Moreprecisely,
we obtainp-groups
satisfying
thefollowing
conditions:(i)
G is aPQ-group ; (ii) CG(D(G)) = D(G);
i(iii)
if 8 is subnormal inG,
then either or(iv)
G is in~4.
Let
Q
be a divisible abelian p-group and 0 I"-’ Let V be the base group ofQ
wrC, considering
the latter as the semidirectproduct [ Y] C,
let H =[V, C] C.
Then H satisfies(i)-(iv)
and it has derivedlength
2. Moreover ~’ _[V, C]
==Dl (H ) = (this
followseasily
from Lemma 2.2 in[10]).
Assume now that we have
already
constructed a groupGo
whichsatisfies
(i)-(iv)
and has derivedlength 2(n -1 ).
Let B be the basegroup of W = H wr
Go,
y whereagain
we consider yY as the semi-direct
product [B] Go .
LetDi =
The action ofGo
on Binduces an action of
Go
on B = withrespect
to thisaction,
let Since we have We
put
G = and
verify
that G satisfies(i)-(iv)
and has derivedlength (== Q-length )
2n.(i)
Since is a metabelianPQ-group,
such isB;
therefore.B’
is divisible and so
.R
is divisible. Hence .R is aPQ-group
of derivedlength
2. Since the classPQ
is closed underextensions,
weget GEPQ.
(ii)
Let .g’ =D1(G) ;
then .g r1 .1~ =D1(R) and, by
the structure of.H,
we have B’ =D1(B),
inparticular
B’ =D1(R)
= .g r1 .R. It,is
Ce(B’)
= G r1and,
since .g isabelian, .g c Oo(B’).
LetC =
Cw(B)7
then and soBut
(HIH’)
wrGo and,
since C centralizesBIB’,
we haveCB,
that is C = B’. Inparticular CG(B’ )
=B’, yielding
K = B’and
Go(K)
-K,
thusproving (ii).
We observe now that
D2(G)
= 1~.Clearly,
infact,
Assume
D2(G) =F
R. Then(D2(G)
r1Go)B’/B’
isinfinite,
and there-fore,
its centralizer in the base groupB/B’
of the restricted wreathproduct W/B’
is trivial(see
Robinson[13],
Lemma6.28),
contra-dicting
the fact thatD2(G)
centralizes HenceD2(G) ===
R.This proves that the
Q-length,
and so the derivedlength,
of G isis
equal
to theQ-length
ofGo plus two,
that is2(n - 1)
+ 2 = 2n.(iii)
Let S be a subnormalsubgroup
of G and assume that,~ ~D2(G) _ .R.
We use 4 - ~) to denotesubgroups
modulo I~. Wehave
1 andhence 9
is normalizedby Dh..
r1 =
1,
then ~S’ centralizesDl(Go) and,
sinceGo
satisfies(ii),.
we
get S
=1, contradicting S|R.
HenceL/B = 8
n=F 1;
letT = L r1
S,
then and(L
r1~S) .R =
L r1 SR =L,
andso
T4;R.
It is therefore sufficient to prove that = B’.Looking
atW,
we have:yielding
and since
T ~ I~. Now, by applying
Lemma2,
weget T ~B’= D1(G),
as we wanted.(iv)
Let S be a subnormalsubgroup
of G.N’ow, .R
is in~2’
since it is aPQ-group
oflength
2(McDougall
[8],
Th.4.7);
hence ifS~D2(G) _ .R,
then S has defect at most 2 in Rand,
since .R is normal inG,
it has defect at most 3 in G. Other-wise = B’. Since is a normal abelian divisible sub- group of it normalizes every subnormal
subgroup,
inparticular:
and so Since G satisfies
(iii)
we have twocases:
a)
in this case,working
moduloB’, get:
and,
since X is subnormal inG, yielding
Itfollows from the
property (iv)
ofGo,
that S has defect at most 4 in G.b)
then we have with SRof defect at most 2 in
D2(Go)R;
hence S has defect at most 4 in G.This
completes
theproof
of Theorem 1. DREMARK. In the notation used in the
previous proof,
and 7T is an
arbitrary
divisible abelian p-group; it is therefore easy toverify
that Theorem 1 can be restated in the fol-lowing
way: every finite p-group isisomorphic
to asubgroup
of ap-group in
584,
which is aPQ-group (in particular
it issoluble).
4. Before
giving
theproofs
of Theorems 2 and3,
we state in alemma a well known fact
concerning
the classesll3n (see
e.g. Robin-son
[12],
Ex.1,
pag.127).
LEMMA 3. For each
positive integer
n,58n
is a local class.That
is,
G E58n
if every finite subset of G is contained in a sub- .group ofG,
which is aThroughout
this sectionGn
will denote the group constructed as in theproof
of Theorem1,
of derivedlength 2n,
for any fixedprime
p.PROOF OF THEOREM 2. For every
prime p,
we may take the group ,G = DirGn,
andapply
thefollowing
result:neN
PROPOSITION.
If, for a
n, H~,for every ~.
thenfunction depending only
on n.kEA
PROOF. Let 8 be a subnormal
subgroup
of H = Dir kEAH,
of defectsay
d,
and letIh,
be theprojection
on Hi for each Then:-
ds] ~ S,
hence r1S)
isnilpotent,
for
every A
Now is subnormal inHI,
which is a0,,-group;
therefore all the
subgroups
of r1S)
have defect at most n.By
Roseblade’s Theorem[14],
there exists a function such that the class of r1S)
is at mostr~(n),
for every A LetThen and .K is subnormal in H of defect at most n. But is
nilpotent
of class at mostq(n),
hence 8 has defect at most71(n)
inK,
and defect at mostq(n) +
n in .H. Thereforewhere
a(n)
=q(%)
+ n. D(For
thisproperty,
see also Smith[15], Th. 4.16. )
We now show that G = Dir
Gn actually
is in We first observeneN
that the groups
Gn,
besides of(i)-(iv)
in theproof
of Theorem1, satisfy
the
following property:
in
fact, (by repeating
anargomentation
used in theproof
of Theo-rem
1)
if thenby (iii),
sincegg Hence
by (iii). Then,
~S subnormalyields
Since
~5
is a localproperty,
in order to show that G is in~5’
weneed
only
to showthat,
for a finite number ofintegers
nl, ... , nr, the group DirGnt
is in~5 .
We make induction on The casei=l ’
Eni = 1
is trivial,
hence letIni
> 1 and H = DirGni,
and let Ti=1,...,r ’
be a subnormal
subgroup
of H. Ifthen, by McDougall ([8],
Th.4.7),
T has defect at most 4 inD4(H)
and so it has defect at most 5 in H.Otherwise,
for some index i E11,
... ,rl
which wemay assume to be
1,
theprojection Till
of T inGnl
is not containedin
D4(Gnl)’
henceby (+), Now,
for someinteger
d:(observe that,
sinceTill
is not contained inD4(GnJ,
it isand so
[GnI’
HenceT ~.I~ =
NowGnI/E
X ... XGnr
XGn,
X ...X Gnr,
andby
inductivehy- pothesis,
we have that T = has defect at most 5 in.g, concluding
the
proof
that .H(and
thereforeG)
is in~85.
PROOF OF THEOREM 3. Let .H be the group of
PQ-length 2,
asdefined in the first
part
of theproof
of Theorem 1. ThenGn+1
canbe viewed as a
subgroup
ofH wr G n, containing
asubgroup
iso-morphic
toGn .
We have therefore the sequence of inclusions:Let G be the direct limit of it. Then where
_ _
nEN
and for every n E N.
Clearly G
is alocally
finite p-groupand,
since~4
is a localclass,
G is in~4.
It is also easy to check that G is aSD-group .
We have
only
to show now that the Baer radical of G is trivial.Let
x_~
be acyclic
subnormalsubgroup
ofG;
thenxEGk
for someNow
(where
is the same as in theproof
of Theorem1),
with .R r1
Gk
=1,
and the subnormalsubgroups
ofGk+,,
which arenot contained in 1~ contain
D1(Gk+l).
Inparticular (z)
cannot containtherefore x
Gk
=1, proving
that the Baer radical of is trivial. 05. Since the
proof
of Theorem 4 is similar to theproof
of The-orem
1,
wegive only
a sketch ofit, leaving
the details to the reader.We first need an
analogous
of Lemma 2 for finite groups.LEMMA 4. Let
finite
groups, withy3(.H) _
H’ and=1,
and let B be the base groupof
H wr K.If
is subnormal in
SB,
then either PROOF. Omitted. 0PROOF OF THEOREM 4. For a
given
finite group G letFi (G)
bethe i-th term of the
Fitting
series of G.By
induction on n, one constructs a finite soluble group, with derivedlength 2n, satisfying
thefollowing
conditions :(i*)
is anelementary
abelian pi-groupg where thepi’s
aregiven primes
with for i =1, 2, ...,
2n.In
particular
if thepi’s
are alldistinct,
G is anA-group;
(ii*)
if 8 is a subnormalsubgroup
ofG,
then eitheror
(iii*)
G is in~4.
Let be
given primes
with for i =2,
... , 2n.,Suppose
we havealready
constructed a groupGo
of derivedlength 2(n -1 ), satisfying (i*)-(iii*)
with involvedprimes
P3, ... , P2fl. Let H be a group such that = H’=y3(H)
is anelementary
abelianpi-group and is an
elementary
abelian p2-group. Let B be the base group ofH wr Go:
we take G =B’[B, .F’1(Go)] Go
whereGo
isviewed in a natural way as a
subgroup
of 8 wrGo .
Then G satisfies,(i*)-(iii*)
and has derivedlength
2n. C1REMARK. With a similar construction it is
possible
to embed any -finite soluble group of derivedlength n
in a finite soluble group in~4’
y.of derived
length
2n.REFERENCES
[1] C.
CASOLO, Gruppi finiti
risolubiti in cui tutti isottogruppi
subnormalihanno
difetto
alpiù
2, Rend. Sem. Mat. Univ. Padova, 74(1984),
pp. 257- 271.[2] C. CASOLO, Periodic soluble groups in which every subnormal
subgroup
hasdefect at
most two, Arch. Math., 46 (1986), pp. 1-7.[3] W. GASCHÜTZ :
Gruppen in
denen das Normalteilersein transitiv ist, J.Reine
Angew.
Math., 198 (1957), pp. 87-92.[4] P. HALL, Wreath powers and
characteristically simple
groups, Proc. Cam-bridge
Phil. Soc., 58(1962),
pp. 170-184.[5] T. O. HAWKES,
Groups
whose subnormalsubgroups
have boundeddefect,
Arch. Math., 43 (1984), pp. 289-294.
[6] F.
LEINEN,
Existenziellabgeschlossene L~-Gruppen,
Dissertation, Albert-Ludwigs
Univ.,Friburg
i.Br., 1984.[7] D. J. McCAUGHAN - S. E. STONEHEWER, Finite soluble groups whose subnormal
subgroups
havedefect
at most two, Arch. Math., 35 (1980),pp. 56-60.
[8] D. McDOUGALL, The subnormal structure
of
some classesof
soluble groups, J. Austral. Math. Soc., 13(1972),
pp. 365-377.[9] D. J. S. ROBINSON, On groups in which
normality
is a transitive relation, Proc.Cambridge
Phil. Soc., 60(1964),
pp. 21-38.[10] D. J. S. ROBINSON, On the
theory of
subnormalsubgroups,
Math. Zeit., 89 (1965), pp. 30-51.[11] D. J. S. ROBINSON, Wreath
products
and indicesof subnormality,
Proc.London Math. Soc.,
(3)
17 (1967), pp. 257-270.[12]
D. J. S. ROBINSON,Infinite
soluble andnilpotent
groups, London, Q.M.C.Math. Notes (1968).
[13] D. J. S. ROBINSON, Finiteness conditions and
generalised
soluble groups,Springer, Berlin-Heidelberg-New
York, 1972.[14] J. E. ROSEBLADE, On groups in which every
subgroup
is subnormal, J.Algebra,
2 (1965), pp. 402-412.[15] H. SMITH,
Groups
with the subnormaljoin
property, Can. J. Math., 37 (1985), pp. 1-16.Manoscritto