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On the family relation for artinian rings

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C OMPOSITIO M ATHEMATICA

K. R. P EARSON

On the family relation for artinian rings

Compositio Mathematica, tome 24, n

o

3 (1972), p. 273-275

<http://www.numdam.org/item?id=CM_1972__24_3_273_0>

© Foundation Compositio Mathematica, 1972, tous droits réservés.

L’accès aux archives de la revue « Compositio Mathematica » (http:

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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques

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273

ON THE FAMILY RELATION FOR ARTINIAN RINGS by

K. R. Pearson

COMPOSITIO MATHEMATICA, Vol. 24, Fasc. 3, 1972, pag. 273-275 Wolters-Noordhoff Publishing

Printed in the Netherlands

In

[4] (see

also

[5], Chapter III),

Kruse and Price introduced the notion of two

rings being

in the same

family.

This was motivated

by

the relation

of group

isoclinism introduced

by

P. Hall in

[3].

Rings R1

and

R2

are said to be in the same

family,

denoted

by R1 4 R2,

if there exist

isomorphisms 0 : R1/(R1) ~ R2/U(R2)

and

03C8: R21 ~ R2

such that

Here

2!(R)

denotes the annihilator of a

ring

R and is defined

by

is an

equivalence

relation which is identical with

isomorphism

if

either

Ri - Ri

for i =

1,

2 or

&#x26;(R1) = &#x26;(R2)

= 0.

Also,

if

R1 R2,

then

R1

is

nilpotent

if and

only

if

R2

is

nilpotent.

We show below how the

family

relation for commutative Artinian

rings

reduces to

isomorphism

between certain

subrings equal

to their own

square and the

family

relation for certain

nilpotent

factor

rings.

We

first need the

following proposition.

PROPOSITION.

If R1 R2 then, for

all

integers m ~ 2, Rm1 ~ Rm2

and

R1/Rm1 R2/Rm2.

PROOF.

Let 4J : R1/&#x26;(R1) ~ R2/&#x26;(R2) and t/1 : R21 ~ R22

be isomor-

phisms

such that

(1)

holds. Because of

(1)

it is clear

that,

for all

m ~ 2,

the restriction

of 03C8

to

Rm1

is an

isomorphism

onto

Rm2.

Suppose m ~

2. For i =

1,

2 let

Vi

=

Ri/Rmi,

ai :

Ri ~ Vi

be the

canonical map and

Then

(Ri) ~ Li

and

(Vi)

=

Li/Rmi.

Because

03C803B12

maps

Rf

onto

R 2IR’ = V22

and has kernel

Rm203C8-1

=

Rm1, 03C8

induces an

isomorphism

03A8:

V,2 , V22 given by

(3)

274

For i =

1,

2

let 03B2i be

the map from

Ri/&#x26;(Ri)

onto

Ri/Li given by

and let yi be the

isomorphism

from

RilLi

onto

VJSl1(VJ given by

Then

OP272

maps

R1/&#x26;(R1)

onto

V2/&#x26;(V2)

and has kernel

(L2/&#x26;(R2))~-1.

But because of

(1)

this

equals L1/&#x26;(R1)

which is also the kernel of

03B2103B31. Hence 0

induces an

isomorphism 0

from

V1/&#x26;(V1)

onto

V2/ÇJ1(V2)

given by

Finally

it is easy to check that e and IF

satisfy

the

compatability

condition

corresponding

to

(1)

and

hence V1 h V2.

If R is a

ring

with D.C.C. on two-sided ideals

(in particular,

if R is

Artinian),

there is a least

positive integer n

such that Rm - Rn for all

m ~ n.

We denote Rn

by K(R). Then,

of course,

K(R)2 = K(R)

and

R/K(R)

is

nilpotent.

Suppose R1

and

R2

are two

rings

with D.C.C. on twosided ideals.

If

R1 1 R2

it follows from the

proposition

that

K(R1) ~ K(R2)

and

R1/K(R1) h R21K(R2).

That the converse is not true may be seen

by considering

the

(non-commutative)

4 dimensional

algebra

R over the

field with two elements and with

basis e,

a,

b,

c where

multiplication

is

such that all

products

of the basis elements are zero

except

that ee = e,

ea = a, eb = b and ac = b. Then it is easy to check that R is

associative, R2

is the

subspace

with basis e, a,

b, K(R)

=

R2, (R)

= 0 =

(R2).

Hence

K(R)

=

K(R2), R/K(R) h R2/K(R2)

but R and

R2

are not in the

same

family.

However,

suppose in addition that

R1

and

R2

are commutative.

Then, if Ji

is the Jacobson radical of

Ri,

there exists an

idempotent ei ~ R

i

such that

ei+Ji

is the

identity

of

Ri/Ji and,

if

Ti = {x - xei|x ~ Ri},

R i = Riei + Ti and Ti ~ Ji

is

nilpotent ([1],

Theorem 9.3

C).

Since

Riei is

a

ring

with

identity

ei,

(Riei)m = Riei for

all

m ~

1 and so, since

Ti

is

nilpotent, K(Ri) = Riei.

Hence

Ri

=

K(Ri)

e

Ti

and

Ri/K(Ri) ~

Ti.

Thus if

K(R1) ~ K(R2)

and

R1/K(R1) R2/K(R2)

then also

Tl dl T2

and so

clearly R1 1 R2.

This proves the

following.

THEOREM. Let R and S be

rings

with D.C.C. on two-sided ideals.

If F

then

K(R) ~ K(S)

and

R/K(R) S/K(S). If,

in

addition, Rand

S are

commutative,

the converse is also true.

(4)

275

Finally

if

R1 R2

then it is clear that

R1/J1 ~ R2/J2. (Indeed,

if ye

is any radical

property (see [2], Chapter 1)

such that every

ring

whose

square is zero is an

e-ring

and if

3Q(R)

denotes the H-radical of a

ring

R then from

R1/&#x26;(R1) ~ R2/&#x26;(R2)

it follows that

R1/H(R1) ~ R2/£(R2)

since

&#x26;(Ri) ~ A(Ri).)

But if

Ri

is a commutative Artinian

ring then Ji

is the direct sum of the radical of

K(Ri)

and

Ti.

Hence if

R1 R2

and each

R is

commutative and

Artinian,

then

R1/J1 ~ RZ/J2 and Jl 1 J2.

That the converse is however false can be seen

by

consider-

ing R1

as the

ring

of

integers

modulo 4 and

R2

the

algebra

over the

field with two elements with basis 1 and x and with

x2 =

0.

REFERENCES E. ARTIN, C. NESBITT AND R. M. THRALL

[1] Rings with minimum condition. University of Michigan, Ann Arbor, 1944.

N. J. DIVINSKY

[2] Rings and radicals. University of Toronto, 1965.

P. HALL

[3] The classification of prime-power groups. J. Reine Angew. Math. 182, 130-141 (1940).

R. L. KRUSE AND D. T. PRICE

[4] On the classification of nilpotent rings. Math. Zeit. 113, 215-223 (1970).

R. L. KRUSE AND D. T. PRICE

[5] Nilpotent rings. Gordon and Breach, New York, 1969.

(Oblatum 14-IV-71) Dr. K. R. Pearson

Department of Mathematics La Trobe University BUNDOORA Victoria 3083 Australia

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