A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
E LIZABETH F. D A C OSTA G OMES Solutions of the equation f
yu
x− f
xu
y= g
Annales de la faculté des sciences de Toulouse 6
esérie, tome 7, n
o3 (1998), p. 401-418
<http://www.numdam.org/item?id=AFST_1998_6_7_3_401_0>
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- 401 -
Solutions of the equation fyux 2014 fxuy
=g(*)
ELIZABETH F. DA COSTA
GOMES(1)
E-mail : beth@mat.ufrgs.br
Annales de la Faculte des Sciences de Toulouse
On etudie le probleme d’existence de solutions de 1’equation
aux dérivées partielles fyux - fyuy = g localement, au voisinage d’un point singulier isolé, dans le cadre analytique reel. On suppose que la fonction f a un minimum local a l’origine.
ABSTRACT. - We study locally, on a neighborhood of an isolated singular point, the existence of solutions of the partial differential equation fyux - fxuy = g, in the real analytic case. We suppose that the function
f has a minimum at the origin.
0. Introduction We consider the
equation
fyux - fxuy
= g ~(1)
where
f , g
are realanalytic
functions in aneighborhood
of(0, 0)
ER2.
We will suppose that:
i) f (0, 0)
= 0 andf
> 0 outside theorigin,
andii)
the idealJ f generated by fy
is of finite codimension as an R-vector space, in I~8~x, y~
.~*~ Recu le 13 mars 1997, accepte le 30 septembre 1997
(~) Departamento de Matematica Pura e Aplicada, Universidade Federal do Rio Grande do Sul, Av. Bento Gon~alves, 9500 Agronomia BR-91509-900 Porto
Alegre/RS (Brasil)
We say that a solution u of
(1)
is:a) regular
if u isanalytic
in aneighborhood
of theorigin.
b) singular
if u isanalytic
in aneighborhood
of theorigin,
but notnecessarily
at theorigin.
We consider
y}
anR{t}-module
with the definitionLet E be the R-vector space of germs at
(0, 0)
of thoseanalytic functions g
such that
(1)
has asingular
solution.Let r be the R-vector space of germs at
(0, 0)
of thoseanalytic
functionsg such that
(1)
has aregular
solution.Since
r c E are submodules of
y}.
The purpose of this article is to
study
thequotient
T =E/r.
We will show that its structure is related to the action of the
monodromy
of
f
at 0(extending f
to ananalytic
function in aneighborhood
of(0, 0)
EC2)
over thevanishing cycle y generated by
thecycle in R2
definedby f
= e(e
> 0sufficiently small).
Moreprecisely,
let E be the C-vector space of thesevanishing cycles
and letthe Milnor number of
f
at 0.Let k be the dimension of the
subspace
of Egenerated by
y,Ly, L203B3,
...where L : E -~ ~ is the
monodromy.
We have thefollowing
results.THEOREM 1. - T is a
free of
rank v = ~c - k.THEOREM 2. - lJ =
dimR E/(E
nJ f).
Observation. . - Since
we have
that 03B3 ~ 0. Then, 03BD ~ -
1.Examples
1) f
=x2
+y2.
In this case p = 1 and v = 0. The existence ofregular
solutions is
equivalent
to that ofsingular
solutions.2) f = x2
+y4.
In this case p = 3. Themonodromy
is inducedby
themap
It follows that
L2y
= -y. Since theeigenvalues
of L are1, i,
-i andy is an
integer cycle, if y
were aneigenvector
ofL,
we would haveLy = y,
which isimpossible. Then,
y andLy
areindependent
andk = 2. Then v = 1.
(Using
the theorem in Section1,
we see that theclass
of y
is a generator ofT . )
1. Solutions to the
equation
fy ux - fxuy
= 9(1)
THEOREM 1.1.- The
equation (1~
has asingular
solutionif
andonly if
First,
we aregoing
to define achange
of coordinates tosimplify
theresolution of the
equation (1).
Since the
problem
islocal,
we aregoing
to suppose,throughout
thiswork,
that the
neighborhoods
of theorigin
are allsufficiently
small.Let U be a
neighborhood
of theorigin
wheref
isanalytic
and where there is no criticalpoint
off
different from(0,0).
Let V C U be asimply
connected
neighborhood
of theorigin
such thatV
c U.LEMMA 1.1.
If E >
0 is smallenough,
= E is asimple
closed curveCE
around theorigin.
Consider the
composed
functionwhere
exp( x)
= and 03C3 is ananalytic diffeomorphism.
Theanalytic
curve 03B3 = o~ o exp is
periodic
withperiod
1 and is aparametrization
of thecurve
Ce.
Integrating
the vectorfield - grad f,
we obtain:such that
LEMMA 1.2.2014
~(t, x) _ ~0, 0) .
It is a direct
application
of theLiapunov
criterium.Consider
defined
by ~p(p, 8)
=8),
where t > 0 is such thatf( (t, 8))
= p,i.e.,
~))
= p.Since for each
(p, 9)
E(0, E)
xI18,
there exists aunique
t E{o, oo)
suchthat
8)
= p(Lemma 1.2),
~p is well defined.Moreover,
p islocally
one to one, since9)
=8‘)
if andonly
ifp=p‘and8-8‘E7L.
Using
theimplicit
function theorem we have the twofollowing
lemmas.LEMMA 1.3. - y~ is a real
analytic function, periodic
withperiod 1,
in the variable 9.LEMMA 1.4. - ~p is a local
diffeomorphism.
LEMMA 1.5.- The
diffeomorphism
ptransforms
theequation duAdf
=g dx A
dy
intowhere J is the Jacobian
of the change of coordinates,
u = andg
= gop.If we choose f > 0 small
enough,
we may suppose that h =-’9J
isanalytic
in(0, f)
x ?.Besides, h
isperiodic,
withperiod 1,
in the second variable.LEMMA 1.6. - The
function u(p, 8) given by:
is
analytic
in(0, e)
x II8 andverifies ~g
= h.Proof.
-Integration by parts.
0LEMMA 1.7. -
If
then the
function
u in Lemma 1.6 isperiodic
in9,
withperiod
1.Proof.
-Actually,
Proof of Theorem 1.1
Suppose (1)
has asingular
solution u.Choose f > 0 such that the curve
f
= f isentirely
contained inside theregion
where u isregular,
and satisfies Lemma 1.1.For 0 $ 6,
Hence,
On the other
hand,
if(2) holds,
And
then,
By
lemmas 1.6 and1.7,
there exists uanalytic
in(0,6)
x Rperiodic
withperiod
1 in8,
that verifies theequation ic~ _ -gJ.
The u passes toquotient
and defines u
by
ic = u o The function u is asingular
solution to(1), by
lemmas 1.4 and 1.5.D
Observe
that,
if(2) holds,
then theequation (1) always
has asingular
solution that can not be extended to a
regular
solution. Infact,
eventhough
the
equation
has aregular
solution u, the solution v = u +1/ f
can not beextended to a
regular
solution.2. Considerations on the Gauss-Manin connection
Let
f
be ananalytic
function in aneighborhood
of(0,0)
E~’ , n > 2,
with an isolated
singularity
at theorigin.
Let
be the Milnor number(cf. [5])
of the germ of the functionf
at 0.Denoting 52o
the sheaf of germs of thep-forms
that areholomorphic
in aneighborhood
of theorigin
inen ,
we defineThe
operation
o : x G --r G definedby
where
[ . indicates
the class inG, gives
G the structure of aTHEOREM 2.1.-
(Brieskorn, Sebastiani)
G is afree of rank .
Proof (cf. [3,
theorem5.1])
Consider
F,
the(C{t}-submodule
of Ggiven by
G/F
is a torsion module.Define the connection
It is clear that D is well
defined,
for ifd f
A a E~d f
A9~,
then there exists,Q
E such thatThus, by
the de Rham’slemma,
It goes without
saying
that D is C-linear and that it is a connection.We are
going
to show that D is abijective
connection.First,
note that ifthen
This is
equivalent
tod(~
+d f
A/?)
= 0.Thus,
thereexists,
e~"~
suchthat 9 +
d f
A/3
=d~,
thatis,
Hence,
D is a 1-1 connection.Moreover,
since every w E is exact, D issurjective.
If
t ~
0 isgiven,
letXt
n(t)
be the Milnor fiber of the functionf (cf. [5]),
whereBe
is the ball in (L~ with center in(0,0)
and radius { > 0.Also,
let 0b C E.
If w E
S2o
and p EXt,
there exists a(n - 1)-form
a,holomorphic
in aneighborhood of p,
such that w =d f
A a, inneighborhood of p,
and that03B1|Xt
is well defined. We definew / d f
this way.w / d f
is a( n - I)-form
overeach fiber.
Let yt
CXt,
0$,
be a(n - 1) vanishing cycle.
If N G G is the set
then N C G as a
(C{t}-submodule.
Observe
that 03B3~ 03C9/df depends only
on the class[03C9]
E G.Let M =
D-1 (N).
We want to show that if~d f
EM,
then B = 0.First we are
going
to prove thefollowing
lemma.’~
LEMMA 2.1
Proof.
-Suppose
d8 =d f
n ~r, where ~r EBy 3 § 4.3~
In the
general
case, if 9 E isgiven,
then there exists aninteger J1~
andr~ E such that =
d f
A r~.For 03C9 =
fN03B8,
we haveBy (3),
On the other
hand,
Since
0,
it follows from theequations
above thatThis proves the lemma. 0
PROPOSITION 2.1.- M = .
Proof.
- M CF, by
definition. If =0, then, by
thelemma,
In other
words, D~d f l18)
EN, i.e., ~d f l18)
E M.Suppose ~d,f
A8]
E M. There exists w EQg
such that[w]
E N andD-1 ~w) _
A~].
.Hence, by
the definition of N andby
thelemma,
It follows that
f,~t 8
is constant.Then, f,~t 8 -
0(cf. [3, § 4.5]).
0PROPOSITION 2.2.- M = N n F.
Proof.
- It follows fromProposition
2.1 that M is aC{t}-submodule
ofG and that M C N.
On the other
hand,
if[w]
E N nF,
there exists 9 E such that[(N]
=~d f
AB~.
Fromthis,
it follows that(W~ EM,
sincePROPOSITION 2.3.-
N/M is
a torsion module.Proof.
- SinceG/F
is a torsionmodule,
there exists aninteger
m suchthat tm o
~W~
EF,
whatever~w~
EN. . FromProposition
2.2 and from the fact that N is a it follows that t"° o~w~
e M. 0PROPOSITION 2.4. - rank M =
dimc N/(N
nF).
Proof.
- We havealready
seen thatand that
N/M
is a torsion module(Prop. 2.3). By
theMalgrange
indexformula
[4],
0 =
x(D; M, N)
= rank M -dime
.Hence, by Proposition 2.2,
v = rank M =
dime
f1F ) .
DObservation. - If it is
homologous
to0,
then ~V - G.Consequently,
M = F and
dime N/(N n F)
=dimC03A9n0/df^03A9n-10
= .In this
particular
case, we obtainagain
the formularank G = rank F =
.3. The rank of the module T
We may consider
f
arestriction,
toII8 2,
of ananalytic
function in aneighborhood of 0 ~ C2,
that will also be denotedby f.
With thehypothesis
on
J f,
0 is an isolated criticalpoint
of the extension.We define
C{t}-modules
G and F as in Section 2. The sub-index 0 will besuppressed
for we areonly
interested in functions and differential formsholomorphic
in aneighborhood
of theorigin.
We writewhere
S2~
is the space of germs ofanalytic
functions in 0 EC2 .
(x, y)
will denote the coordinatesin R2
and(z, w)
the coordinates inC2 .
Define A =
y}
and S =A/r.
It is clear that A and S
are R{t}-modules,
that r C E C A assubmodules,
and that T C S asR{t}-submodule.
Let
PROPOSITION. - a is and ker a = r .
Proof.
- r C ker utrivially.
If g e ker a,
g dz A dw =
-d f
Adu ,
which means that
g =
fwuz - fzuw
for a certain u EC~~z, w~ . Considering
the restriction of uto 2,
u(x, y)
=y)
+y)
where uR
and uI
are realfunctions,
9 = + .
Since g
is a realfunction,
= 0 andg{x, y)
= -that
is,
g ELet
S~
= C andT~
= C. It is clear thatS~
is aand that
Tc
CSc
as aC{t}-submodule.
THEOREM 3.1.- ~ passes to
quotient
anddefines
a iso-morphism
Proof.
-By
the definitions ofS~
andG,
T is asurjective homomorphism
Let g2, ..., gh E
A,
beR-independent modF,
and let[gj]
be the classof 9 j inS‘, j=1,2,..., h.
Suppose
Then,
for a certain u
analytic
on aneighborhood
of 0 EC2. Thus,
Let c3 = a j +
ibj,
aj,bj
E I18 andu I ~2
= uR +iuI
where uR and u I are,respectively,
the real andimaginary parts
of the functionu (~2. Hence,
In other
words,
,03A3bjgj
E r.Consequently, V j,
aj, ,bj
=0, i.e.,
c~ = 0.
Then,
T is anisomorphism.
DCOROLLARY 3.1.2014 S is a
free of
rank where ~c is the Milnor numberof
thefunction f
in 0(cf. j~3,
Sect.3~
andCOROLLARY 3.2. -
If, for
someE N, fyux
-fxuy
=fN 9
has a
regular
solution.Then,
fyux
-fxuy
= 9has a
regular
solution.COROLLARY 3.3. - T is a
free
andrankR{t}
T =rankC{t} Tc
~ .To
compute
the rank ofT,
we mustcompute
the rank r~ of the(C~t}-free
module
T~ .
Let If be the curve
f(x, y)
= E, thatis,
03B3~ =XE
n1I82,
whereXE
is theMilnor fiber of
f
over E. If isprolonged
to avanishing cycle (Sect. 2).
Let us recall the definition of the
C{t}-submodule
N ofG, given
inSection 2: , _ ,
where yt
CXt,
for 0I
smallenough,
is thevanishing cycle
definedabove.
THEOREM 3.2.-
T(Tc)
= N.Proof.
-Let g
E A whose class in Sbelongs
to T. Thereexists 17 E 01
such that
T(g) = [g
dz Adw] = [d?y].
by
the Theorem 1.1 and r~ is a multiformanalytic
function of t. Since theequality
above holds for all e > 0 smallenough, and 03B3~ = lYE
nI182,
itresults that = 0 for all 0
small enough.
By Proposition 2.1, ~d f
Ar~~
E M =Hence, D[df
nr~~
= EN,
andthen, [g dz
Adw~
EN.On the other
side,
if[~]
C~V,
there exists 0 such that ~ == 0
(Prop. 2.1). Besides, by
the definition ofD, [03C9]
=[d9]. Thus,
/ 03C9 = 03B3~ 03B8 = 0.
Let 03C9 = hdz A ~
03C9}. Considering
the restriction of h toR2,
let~2
=Then,
we haveTherefore,
Since the classes of
hR and h I belong
to T(Sect. 1),
the class of hbelongs
to
T~
andr~(h~~
=~W~.
~COROLLARY 3.4.-
rankTc
=dimc N/(N
nF).
Proof.
-Propositions
2.3 and 2.4.COROLLARY 3.5. - rank T =
dimR03A3/(03A3
nProof.
-By
theorems 3.1 and3.2,
it isenough
to show thatdimR E/(E
nJf)
=dimc N/(N
nF) .
.If 9 E
S, [g(z, w)
dz A E N(Theorem 3.2).
We define
A : E 2014
N/(N
nF)
A(g)
= class of[g(z, w)
dz A = class of .~ is a
homomorphism
between R-vector spaces whose kernel isJ f.
Infact,
. if
gEE
is such that g =a fx
+b fy,
for certain a, b E= +
b(z, w)fw(z, w))
dz Adw]
=
~d f
A(a(z, w)
dw -b(z, w) dz~~
E N nF ;
. on the other
side,
if g E ker~,
there exists a = al dz + a2 dw ES21
such that
g dz ^ dw = df na=(fzdz+fwdw)n(aldz+a2dw)
=
~.fza2
- dz Adw
;which means that
g(z, w)
=(fz03B12 - fw03B11)(z, w).
If we make the restriction to real
numbers,
y~
_(fxa2 - y~
=
y)
+y))
+-
y)
+y)~
~where = +
i03B1jI
and are realfunctions, j
=1,
2.Since
g(x, y), y)
andfy(x, y)
are realnumbers, (fx03B12I
-y)
= 0 .Consequently,
g = 03B12Rfx - 03B11Rfy
EJf.
.~ passes to
quotient
and defines a one to onehomomorphism
If
~W~
EN, by
Theorem3.2,
there existgl , g2 E ~
such thatThus,
It remains to show that n n n
Jf)
=~0~.
Suppose g, h
E ~ and[g(z, w)
dz Adw~ = i[h(z, w)
dz Adw]
inN/(N
nF).
Hence,
[(g(z, w) - ih{z, w))
dzAdz]
EF,
,i.e., g -
ih =a fz
+b fw
for some functions a, b Ew}.
Restricting to R2,
g - ih
=(ap
+iaI)fx
+(bR
+ibI)fy
=
(aRfx + bRfy) "~ i(aIfx+
> aR ~ aI ~bR
~bI
E~~x~ 2/} .
.Thus g, h E n J f
.Then,
rank T =dimc N/ ( N
nF)
= nNow,
let us prove theorems 1 and 2.Proof of
Theorem 1Part of it is a
corollary
of theorems 3.1 and 3.2.It
just
remains to show thatrank T =
!/ = ~ - ?.
.Since
G/N
is torsionfree,
we may write G = N®
P. . Let~w 1J ,
...,~w~,-1J
be a basis of G as a where~W1J,
... , is abasis of N and
~t,~v-1J,
...,~w~,-1J
is a basis of P asLet
b1t
, ... ,b(k-l~t ~, ~ I
f, e > 0sufhciently small,
be abasis of
E,
wherebs~
=0
s k - 1.If
belongs
toN,
= 0.Hence, t wi
=0,
for all s,Thus,
if,
the matrix
has a
vanishing k
x vminor,
with v+ k
> Which means thaton a
neighborhood
And this contradicts the fact that(cf. [1], 12):
Suppose
now v ~u - k. LetBy[2],
where
A(t)
ismeromorphic
and C is a constant(k
xk)-matrix.
Since
A(t)
is a((~ - v)
xk)-matrix
with> k,
then there existholomorphic
functionsg"(t), g"+1 (t),
...,, g~_1 (t),
not all of themidentically
zeroin |t|
e, such thatLet a = Then we have E P
and,
sincealso
belongs
to N. This means that[a]
= 0. Thus there exists a non trivial linear combination of[wo],
...,(w~_1J
that vanishes. That isimpossible,
since it is a basis of G.Therefore, v
=~c - ~ .
0Proof of
theorem ,~Theorem
3.2, Corollary
3.5.- 418 -
Acknowledgments
I am most
grateful
to myadvisor,
Prof. MarcosSebastiani,
for theconstant orientation. I also thank the
referee,
whose observation hasimproved
the result of Theorem 1.References
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VARCHENKO(A.)
and GOUSSEIN-ZADE(S.) .
2014 Singularités des applications différentiables, 2e partie, Monodromie et comportement asymptotiquesdes intégrales, Éditions Mir - Moscou, 1986.
[2]
BRIESKORN(E.) .
- Die Monodromie der isolierten Singularitäten von Hyperflächen, Manuscripta Math. 2(1970),
pp. 103-161.[3]
MALGRANGE(B.) .
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[4]
MALGRANGE(B.) .
2014 Sur les points singuliers des équations différentielles, L’Ensei- gnement Math. 20(1974),
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M ILNOR(J.) .
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