Generalized Derivations with Power Central Values on Multilinear Polynomials on Right Ideals.
N. ARGACË(*) - V. DEFILIPPIS(**) - H.G. INCEBOZ(*)
ABSTRACT- LetK be a commutative ring with unity,Ra prime K-algebra, with extended centroidCand right Utumi quotient ringU,ga non-zero generalized derivation ofR. Suppose thatf(x1;. . .:;xn) is a multilinear polynomial overK,I is a non-zero right ideal ofRandm1, a fixed integer. We prove the following results:
If g(f(r1;. . .:;rn))m0, for all r1;. . .:;rn2I, then one of the following holds:
(1) [f(x1;. . .:;xn);xn1]xn2is an identity forI;
(2) g(x)axfor allx2R, wherea2Usuch thataI0;
(3) g(x)ax[q;x] for allx2R, wherea;q2Usuch thataI0 and [q;I]I0.
If there exist a1;. . .;an2I such that g(f(a1;. . .:;an))m 60 and g(f(r1;. . .;rn))m2Z(R), for allr1;. . .:;rn2I, then one of the following holds:
(1) f(x1;. . .;xn)xn1is an identity forI;
(2) f(x1;. . .;xn) is central valued onR;
(3) g(x)axfora2Candf(x1;. . .;xn) is power central valued onR;
(4) Rsatisfiess4, the standard identity in four variables.
1. Introduction.
Throughout this paper,Ris always a prime ring with centerZ(R), ex- tended centroidC, and right Utumi quotient ringU. An additive mapping d:R!Ris called derivation ifd(xy)d(x)yxd(y) holds for allx;y2R.
The study of derivations of prime rings was initiated by Posner [20]. By a
(*) Indirizzo degli AA.: Department of Mathematics, Ege University, Science Faculty, 35100, Bornova, Izmir, Turkey.
E-mail: [email protected]
(**) Indirizzo dell'A.: Faculty of Engineering, University of Messina, Contrada Di Dio, 98166, Messina, Italy
E-mail: [email protected]
generalized derivation onRone usually means an additive mapg:R!R such that, for anyx;y2R,g(xy)g(x)yxd(y), for some derivationdin R. Obviously any derivation is a generalized derivation. Moreover, other basic examples of generalized derivations are the following: (i) g(x)
axxb, fora;b2R; (ii)g(x)ax, for somea2R:Many authors have studied generalized derivations in the context of prime and semiprime rings (see [13], [10], [17]).
In [7], Giambruno and Herstein proved that ifdis a derivation ofRsuch thatd(x)n0 for allx2R, thend0. Following this line of investigation in [8] Herstein showed that ifd(x)n2Z(R), for allx2R, then eitherd0 orR satisfies the standard identitys4. Later in [23], Wong considered a similar condition in case the derivation acts on a multilinear polynomial f(x1;. . .;xn). The conclusion was that eitherf(x1;. . .;xn) is central inRor Rsatisfiess4. Recently in [2], Chang extended Wong's result to the case when thead(f(x1;. . .;xn))m0, for allx1;. . .;xnin a non-zero right idealI ofR,a2Randmis a fixed integer. He concluded that either aI0 or d(I)I0 or [f(x1;. . .;xn);xn1]xn2is an identity forI. At this point the natural question is what happens in case the derivation is replaced by a generalized derivation. More recently in [[22], Theorem 5], Wei proved that ifRis a prime ring,Ia non-zero ideal ofR,ma fixed positive integer and gis a generalized derivation such that g(x)m0, for allx2I, then g0. Finally in a very recent paper [21] Wang generalized above theorem to the case when the generalized derivation acts on all evaluations of a multilinear polynomial in a prime ring. More precisely he proved that ifgis a generalized derivation of a prime K-algebra R and f(x1;. . .;xn) is a multilinear polynomial over K, such that g(f(r1;. . .;rn))m0 for all
r1;. . .;rn2R, then either there exists an element l2C such that
g(x)lxfor allx2R, orf(x1;. . .;xn) is central valued onR, except when Rsatisfiess4 the standard identity in four variables.
In this paper we will continue this line of investigation. Our aim is to extend the Wang's result to the case when the multilinear polynomial is evalued on one-sided ideals of the primeK-algebraR. We will prove that:
THEOREM1. Let K be a commutative ring with unity, R a prime K- algebra, with extended centroid C, g a non-zero generalized derivation of R,
f(x1;. . .:;xn)a multilinear polynomial over K, I a non-zero right ideal of R
and m1, a fixed integer. If g(f(r1;. . .:;rn))m0, for all r1;. . .:;rn2I, then one of the following holds:
(i) [f(x1;. . .:;xn);xn1]xn2 is an identity for I;
(ii) g(x)ax for all x2R, where a2U such that aI0;
(iii) g(x)ax[q;x]for all x2R, where a;q2U such that aI0 and[q;I]I0.
THEOREM2. Let K be a commutative ring with unity, R a prime K- algebra, with extended centroid C, g a non-zero generalized derivation of R. Suppose that f(x1;. . .:;xn)is a multilinear polynomial over K, I is a non-zero right idealof R and m1, a fixed integer such that g(f(r1;. . .:;rn))m2Z(R), for al l r1;. . .;rn2I. If there exist a1;. . .;an2I such that g(f(a1;. . .:;an))m60, then one of the following holds:
(i) f(x1;. . .;xn)xn1 is an identity for I;
(ii) f(x1;. . .;xn)is centralvalued on R;
(iii) g(x)ax for a2C and f(x1;. . .;xn)is power centralvalued on R;
(iv) R satisfies s4, the standard identity in four variables.
2. Preliminaries.
In all that follows, unless stated otherwise,Kwill be a commutative ring with unity andRwill be a primeK-algebra. The related object we need to mention is the right Utumi quotientUof a ringR(sometimes, as in [1],U is called the maximal right ring of quotients).
The definitions, the axiomatic formulations and the properties of this quotient ringUcan be found in [1].
In any case, whenRis a prime ring, all that we need aboutUis that 1) RU;
2) U is a prime ring;
3) The center of U, denoted by C, is a field which is called the extended centroid ofR.
We make also a frequent use of the theory of generalized polynomial identities and differential identities (see [1], [12], [16], [19]). In particular we need to recall that whenRis prime andIa non-zero right ideal ofR, thenI;IRandIUsatisfy the same generalized polynomial identities [4].
In [13] T.K. Lee extended the definition of a generalized derivation as follows; by a generalized derivation we mean an additive mappingg:I!U such thatg(xy)g(x)yxd(y) for allx;y2I, whereIis a dense right ideal of Randd is a derivation fromIintoU. Moreover Lee also proved that every generalized derivation can be uniquely extended to a generalized derivation ofUand thus all generalized derivations ofRwill be implicitly assumed to be defined on the wholeUand obtained the following results:
THEOREM. (Theorem 4, [13]). Every generalized derivation g on a dense right idealof a semiprime ring R can be uniquely extended to U and assumes the form g(x)axd(x);for some a2U and a derivation d on U.
More detail about generalized derivations can be found in [13], [10], [17].
REMARK3. It is well known that every derivation ofRcan be uniquely extended to a derivation ofU[16]. Moreover sinceRis prime ring , we may assumeKCand so for anya2K one hasd(a1)2C.
We will use the following notation:
f(x1;. . .;xn)ax1x2. . .xnX
s61
asxs(1)xs(2). . .xs(n)
for somea;as2Cand moreover we denote byfd(x1;. . .;xn) the polynomial obtained fromf(x1;. . .;xn) by replacing each coefficientaswithd(as). Thus we writed(f(r1;. . .;rn))fd(r1;. . .;rn)P
i f(r1;. . .;d(ri);. . .;rn), for all r1;r2;. . .;rn2R:
REMARK4. We will also write a multilinear polynomialf(x1;. . .;xn) as follows:
f(x1;. . .;xn)X
i
ti(x1;. . .;xi 1;xi1;. . .;xn)xi
whereti are multilinear polynomials inn 1 variables, andxi never ap- pears in any monomials ofti.
Before the beginning of our proofs, we would like to recall Wang's re- sults, more precisely we refer to Theorem 2 and Theorem 4 in [21]. All that we need here is to remind the conclusions contained in [21] in the casegis an inner generalized derivation ofR. We summarize these reduced results in the following Facts 1,2 and 3:
FACT1. Let a;b2R such that(af(x1;. . .;xn)f(x1;. . .;xn)b)m0, for all x1;. . .;xn 2R. Then either a b2Z(R)or f(x1;. . .;xn)is central valued on R.
FACT 2. As a specialsimple case of Fact 1 we have that if
f(x1;. . .;xn) is a non-central multilinear polynomial over K such
that (af(x1;. . .;xn))m0, for al l x1;. . .;xn2R, then a0.
FACT3. Let R be a prime ring and a;b2R, and m1be a fixed in- teger. Suppose that f(x1;. . .;xn)is a multilinear polynomial over K which is not vanishing on R, such that(af(x1;. . .;xn)f(x1;. . .;xn)b)m2Z(R) for all x1;. . .;xn 2R. Then one of the following holds:
(i) f(x1;. . .;xn)is central-valued on R;
(ii) a b2Z(R);
(ii) R satisfies s4;
(iv) a;b2Z(R)and f(x1;. . .;xn)is power centralvalued on R.
3. The nilpotent case.
We begin with the following:
LEMMA 1. Let R be a prime K-algebra, I a non-zero right ideal of R, a2R, m1, a fixed integer, f(x1;. . .;xn)a multilinear polynomial over K such that (af(r1;. . .;rn))m0, for all r1;. . .;rn2I. Then one of the following holds:
(i) [f(x1;. . .;xn);xn1]xn2 is an identity for I;
(ii) aI0.
PROOF. Suppose that conclusions (i) and (ii) do not occur. We prove that, in this case, we get a contradiction. Letb1;. . .;bn2;w2Isuch that
[f(b1;. . .;bn);bn1]bn260 and aw60 (1)
SinceaI60, there exists a non-central elementuofIsuch thatau60.
Hence (af(ux1;. . .;uxn))mis a non-trivial generalized polynomial identity forR. ThusRis a GPI-ring, so thatRChas a non-zero socleHwith non- zero right ideal JIH. Moreover His a simple ring with minimal right ideals (see [19]). Note thatJJHandJsatisfies the same basic conditions asI. ReplacingRbyH;IbyJwe have thatRis a simple ring with minimal right ideals, moreoverRis equals to its own socle andIRI. Recall that, by Remark 2, we have
f(x1;. . .;xn)X
i
ti(x1;. . .;xi 1;xi1;. . .;xn)xi:
Since R is a simple ring with minimal right ideals, it is a right-semi- simple ring. Of course it is also a left-semisimple ring, so that R is a semisimple noetherian ring. Therefore any right (left) ideal ofRis finitely generated. Moreover, sinceRis regular there existse2e2IRsuch that
eRwRn2P
i1biR such that, eww;ebibi;i1;. . .;n2. In parti- cular for allr1; ::;rn2Rand for alli1; ::;nwe have
(af(er1;. . .;eri(1 e);. . .;ern))m(ati(er1;. . .;ern)eri(1 e))m0:
Hence for alli1; ::;n
((1 e)ati(er1;. . .;ern)eri)m10
that is (1 e)ati(er1;. . .;ern)eR is a nil right ideal of bounded in- dex. Thus, by a well known result which is attribuited to Levitzki (for a proof see [6] and pp. 1-2 in [9]), (1 e)aeti(er1;. . .;ern)eri0 for any r1;. . .;rn2R. By the primeness of R it follows that (1 e)aeti(er1;. . .;ern)e0 for all i1; ::;n. Thus the left ideal Re satisfies the generalized identity (1 e)aeti(x1;. . .;xn). By main theorem in [5] we have that (1 e)ae(Re)ti(Re;. . .;Re)(0).
Therefore, again by the primeness of R, we get that either
(1 e)ae0 or ti(x1;. . .;xn)xi is an identity for eR for all
i1; ::;n.
Firstly we assume that (1 e)ae0. Then (eaef(ex1e;. . .;exne)m is an identity for R. In view of Fact 2, we have that either eae0 or
f(x1;. . .;xn) is central for eRe. Second possibility gives that
[f(er1;. . .;ern);ern1]ern20. In particular
0[f(eb1;. . .;ebn);ebn1]ebn2[f(b1;. . .;bn);bn1]bn260;
a contradiction. If eae0, then 0aeaewaw, a contradiction again.
Finally we assume thatti(er1;. . .;ern)eri0 for anyr1;. . .;rn2Rand for alli1; ::;n. Then, in particular, we get the contradiction
06[f(eb1;. . .;ebn);ebn1]ebn2h X
i
ti(eb1;. . .;ebn)ebi;bn1i
bn20:
p LEMMA 2. Let R be a prime ring, a;b2R, m1 a fixed integer, I a non-zero right idealof R, f(x1;. . .;xn)a multilinear polynomial over K such that(af(r1;. . .;rn)f(r1;. . .;rn)b)m0, for all r1;. . .;rn 2I.
Then either[f(x1;. . .;xn);xn1]xn2is an identity for I, or(ab)I0 and[b;I]I0.
PROOF. If b2C then the proof is finished by Lemma 1. So we may assume thatb2=C. First aim is to show thatRis a GPI-ring. Letu2Isuch
thatfau;ugare linearly C-independent. Then
(af(ux1;. . .;uxn)f(ux1;. . .;uxn)b)m (2)
is a nontrivial generalized polynomial identity forR, as (af(ux1;. . .;uxn))m occurs nontrivially in (2). So Ris a GPI-ring. Let nowauau for some a2C. ThenRsatisfies
(af(ux1;. . .;uxn)f(ux1;. . .;uxn)b)m (3)
Iffbu;ugare C-independent, then (f(ux1;. . .;uxn)b)moccurs nontrivially in (3). ThenRis a GPI-ring. If bubu, for some b2C, then the coeffi- cients which occur in (3) are only fu;bg. If umb for somem2C, then, sinceb2=C,Ris GPI-ring. On the other hand, if fu;bgare linearly C-in- dependent, then (3) is again a non-trivial generalized polynomial identity forR. Therefore, again by [19],RChas a non-zero socleHwith non-zero right idealJIH. As aboveHis a simple ring with minimal right ideals, moreover we have thatJJHandJsatisfies the same basic conditions as Iin view of [16]. ReplacingRby H;IbyJwe have thatRis simple and equals to its own socle andIRI. Notice that if (ab)I0 then, from the assumption (af(r1;. . .;rn)f(r1;. . .;rn)b)m0 for allr1;. . .;rn 2I, it follows that [b;f(r1;. . .;rn)]m 0 for all r1;. . .;rn2Iand by [2] we have that either [b;I]I0 or there exists an idempotent elemente2Hsuch thatICeRC andf(x1; ::;xn) is central valued oneRCe. In this last case we have [f(er1e;. . .;erne);ern1e]e0, for all r1; ::;rn12R, that is
[f(er1;. . .;ern);ern1]e0. In other words I satisfies the polynomial
identity [f(x1;. . .;xn);xn1]xn2and we are done.
Now we assume that the conclusion of the lemma doesn't hold. Then there existw;b1;. . .bn22Isuch that
(ab)w60 and [f(b1;. . .;bn);bn1]bn260:
As in Lemma 1, since R is a simple regular ring, we write P
n2
i1biRwReRfor some idempotent elemente2R. Moreovere2IR
and ebibi fori1;. . .;n2 and eww. By the hypothesis we have
that, for alli1; ::;n,Rsatisfies
(af(ex1;. . .;exi(1 e);. . .exn)f(ex1;. . .;exi(1 e);. . .exn)b)m and by calculations it follows thatRsatisfies
(ati(ex1;. . .;exn)exi(1 e)ti(ex1;. . .;exn)exi(1 e)b)m (4)
for alli1; ::;n. Left multiplying (4) by (1 e), we get
0(1 e)(ati(er1;. . .;ern)eri(1 e))m 8r1; ::;rn2R:
It means that, for allr1; ::;rn2Rand for alli1; ::;n, ((1 e)(ati(er1;. . .;ern)eR)m1(0):
By the above cited result of Levitzki (see again [6] and pp.1-2 in [9]) we have thatRsatisfies (1 e)aeti(ex1;. . .;exn)exifor alli1; ::;n.
Here we repeat the same argument in Lemma 1: by the primeness ofR it follows thatRsatisfies (1 e)aeti(ex1;. . .;exn)efor alli1; ::;n. Thus the left idealResatisfies the generalized identity (1 e)aeti(x1;. . .;xn). By main theorem in [5] we have that (1 e)ae(Re)ti(Re;. . .;Re)(0). It fol- lows that either (1 e)ae0 orti(x1;. . .;xn)xiis an identity foreRfor all i1; ::;n.
If second case holds, then in particular we get the contradiction 06[f(eb1;. . .;ebn);ebn1]ebn2
h X
i
ti(eb1;. . .;ebi 1;ebi1;. . .;ebn)ebi;bn1i
bn20:
So we haveaeeae. Now right multiplying (4) byewe get (ti(er1;. . .;ern)eri(1 e)b)me0
for allr1; ::;rn2Randi1; ::;n, that is
((1 e)beti(er1;. . .;ern)eR)m1(0):
Once again by Levitzki's theorem we have thatRsatisfies the generalized identity (1 e)beti(ex1;. . .;exn)exifor alli1; ::;n.
Thus the left ideal Re satisfies the generalized identity (1 e)beti(x1;. . .;xn). By main theorem in [5] we have that (1 e)be(Re)ti(Re;. . .;Re)(0). It follows that either (1 e)be0 or ti(x1;. . .;xn)xi is an identity foreRfor alli1; ::;n.
As above, in this last case we get the contradiction 06[f(eb1;. . .;ebn);ebn1]ebn2
h X
i
ti(eb1;. . .;ebi 1;ebi1;. . .;ebn)ebi;bn1
ibn20:
Hence it follows that (1 e)be0. Therefore the finite dimensional simple central algebraeRCesatisfies (af(x1;. . .;xn)f(x1;. . .;xn)b)m. Then by Fact 1, eithereae ebe2Corf(ex1e;. . .;exne) is central. In the last case we have [f(er1;. . .;ern);ern1]ern2[f(r1;. . .;rn);rn1]rn260, a contradiction. Finally if aeeae ebe be, then 0(ab)e
(ab)ew(ab)w60, which is again a contradiction. p
THEOREM1. Let K be a commutative ring with unity, R a prime K- algebra with extended centroid C and g a non-zero generalized derivation of R. Suppose that f(x1;. . .;xn)is a multilinear polynomial over K and I is a non-zero right idealof R and m1, a fixed integer.
If(g(f(r1;. . .;rn)))m0, for all r1;. . .;rn2I, then one of the following holds:
(i) [f(x1;. . .;xn);xn1]xn2 is an identity for I;
(ii) g(a)ax for all x2R, where a2U such that aI0;
(iii) g(x)ax [q;x]for all x2R, where a;q2U such that aI0 and[q;I]I0.
PROOF. As remarked above, every generalized derivationgon a dense right ideal of R can be uniquely extended to U and assumes the form g(x)axd(x), for some a2U and derivation d onU. Therefore, for u2I;Usatisfies the following differential identity
(af(ux1;. . .;uxn)d(f(ux1;. . .;uxn)))m0 Suppose that [f(x1;. . .;xn);xn1]xn2is not identity forI.
Ifd0, then (af(x1;. . .;xn))m0 for allx1;. . .;xn2I:Hence by the initial hypothesis and Lemma 1 we getg(x)axfor allx2RandaI0.
So the conclusion (ii) holds.
We may assume thatd60. Thus we have thatIsatisfies af(x1;. . .;xn)fd(x1;. . .;xn)X
i
f(x1;. . .;d(xi);. . .;xn)m :
In light of Kharchenko's theory [12], we divide the proof into two case:
CASE1. Ifdis inner derivation induced by the elementq2U, that is d(x)qx xqfor allx2U. Thusg(x)axd(x)(aq)x xqandU satisfies
(aq)f(ux1;. . .;uxn) f(ux1;. . .;uxn)qm :
Since [f(x1;. . .;xn);xn1]xn2 is not identity forI, then by Lemma 2 we have that 0(aq q)IaIand [q;I]I0.
CASE2. Let nowdan outer derivation ofU. SinceIandIUsatisfies the same differential identities,
af(x1;. . .;xn)d(f(x1;. . .;xn))m is an identity forIU, that is, for anyu2I,
af(ux1;. . .;uxn)d(f(ux1;. . .;uxn))m
is an identity forU. ThusUsatisfies the following af(ux1;. . .;uxn)fd(ux1;. . .;uxn)X
i
f(ux1;. . .;d(u)xiud(xi);. . .;uxn)m : Sincedis an outer derivation, by Kharchenko's results in [12],Usatisfies the identity
af(ux1;. . .;uxn)fd(ux1;. . .;uxn)X
i
f(ux1;. . .;d(u)xiuyi;. . .;uxn)m : In particular taking xi0 it is easy to see that U satisfies the blended componentf(ux1;. . .uyi;. . .;uxn)m, that isI satisfies f(x1;. . .;yi;. . .;xn)m. SinceIsatisfies a non-trivial polynomial identity, then there exists an idem- potente2socle(RC) such thatIeRC (see Proposition in [15]). HenceR satisfiesf(ex1;. . .;exn)mthat isRsatisfies the identityef(ex1;. . .;exn)m.
Then by main theorem in [5] we have that R satisfies ef(ex1;. . .;exn)exn1 that is f(x1;. . .;yi;. . .;xn)xn1 is satisfied by
IeRC, a contradiction. p
4. The power central case.
At first we need to fix the following:
LEMMA3. Let R be a prime ring, I a non-zero right idealof R and m1 a fixed integer. If f(x1;. . .;xn) is a multilinear polynomial over K such that f(r1;. . .;rn)m2Z(R) for all r1;. . .;rn2I, then either
f(x1;. . .;xn)xn1 is an identity for I or f(x1;. . .;xn) is power central
valued on R.
PROOF. Suppose thatf(r1;. . .;rn)m2Z(R) for anyr1;. . .;rn2I. Since Isatisfies a non-trivial polynomial identity, then there exists an idempotent e2socle(RC) such that IeRC (see Proposition in [15]). Thus, since [f(r1;. . .;rn)m;r]0 for allr1;. . .;rn2Iandr2R, we have that for any r1;. . .;rn12R
0[f(er1;. . .;ern)m;rn1(1 e)]f(er1;. . .;ern)mrn1(1 e):
SinceRis prime, either (1 e)0 orf(er1;. . .;ern)m0. In the first casee1 and IRC. Thusf(x1;. . .;xn) is power central valued onRC and so also on R. On the other hand, if f(er1;. . .;ern)m0, then ef(er1;. . .;ern)m0 and by main theorem in [5]ef(er1;. . .;ern)eR0, for
allr1;. . .;rn 2R. Hencef(x1;. . .;xn)xn1is an identity forIeRCand we
are done. p
THEOREM2. Let K be a commutative ring with unity, R a prime K- algebra, with extended centroid C, g a non-zero generalized derivation of R.
Suppose that f(x1;. . .;xn)is a multilinear polynomial over K, I is a non- zero right idealof R and m1, a fixed integer such that g(f(r1;. . .;rn))m2Z(R) for all r1;. . .;rn2I. If there exist a1;. . .;an2I such that g(f(a1;. . .;an))m60, then one of the following holds:
(i) f(x1;. . .;xn)xn1 is an identity for I;
(ii) f(x1;. . .;xn)is centralvalued on R;
(iii) g(x)ax for a2C and f(x1;. . .;xn)is power centralvalued on R;
(iv) R satisfies s4.
PROOF. Write again g(x)axd(x), for suitable a2U andda de- rivation ofR. Since (af(x1;. . .;xn)d(f(x1;. . .;xn)))m is a central differ- ential identity forI, by Theorem 1 in [3]Ris a PI-ring and soRCis a finite dimensional central simple C-algebra. By Wedderburn-Artin theorem RCMk(D) for somek1 andDa finite-dimensional central division C- algebra. By Theorem 2 in [16] (af(x1;. . .;xn)d(f(x1;. . .;xn)))m2Cfor
allx1;. . .;xn2IC. Without loss of generality we may replaceRwithRC
and assume that RMk(D). Let s1;. . .;sn be arbitrary elements of I.
ThenRsatisfies the following central differential identity in the variables XandY:
"
af(s1X;s2;. . .;sn)fd(s1X;s2;. . .;sn)f(d(s1)Xs1d(X);s2;. . .;sn)
X
i2
f(s1X;. . .;d(si);. . .;sn)m
;Y
# : If d is an outer derivation, fix d(X)y, X0 and obtain f(s1r;s2;. . .;sn)m2C, for alls1;. . .;sn 2Iandr2R. By Lemma 3 either f(x1;. . .;xn)xn1is an identity forIorf(x1;. . .;xn) is power central valued onR. In the first case we are done.
Hence we assume thatf(x1;. . .;xn)m is central valued on R. In parti- cular, iff(r1;. . .;rn)m0 for allr1;. . .;rn 2Ithen we obtain as a reduc- tion of Lemma 3 that f(x1;. . .;xn)xn1 is an identity for I. In the either case there exists b1;. . .;bn2Isuch that 06f(b1;. . .;bn)m2C, that isI contains an invertible element ofR, and soIR. Hence we conclude by Wang's theorem in [21].
Suppose now thatdis an inner derivation, sayd(x)[q;x]qx xq.
Let F be a maximal subfield of D, so that Mk(D)CFMt(F) where tk[F:C]. Hence the derivationdcan be extended toMk(D)CFand (af(x1;. . .;xn)d(f(x1;. . .;xn)))m2Z(Mt(F)), for any x1;. . .;xn2IF (Lemma 2 in [14] and Proposition in [18]). Therefore we may assume that RMt(F). Notice that if t1;2 then we have respectively that either RForRM2(F). In any caseRsatisfies the standard identitys4and we are done.
Here we assume thatt3. Denoteeijthe usual matrix unit with 1 in the (i;j)-entry and zero elsewhere. Since there exists a set of matrix units that contains the idempotent generator of a given minimal right ideal, we ob- serve that any minimal right ideal is part of a direct sum of minimal right ideals adding toR. In light of this and applying Proposition 5 on page 52 in [11], we may assume that any minimal right ideal ofRis a direct sum of minimal right ideals, each of the formeiiR.
Moreover we know that the right ideal I has a number of uniquely determinated simple components: they are minimal right ideals ofRandI is their direct sum. In light of this argument, we may writeIeRfor some ePl
i1eii and l2 f1;2; :::;tg, that is IeR(e11R. . .ellR), where t3 andlt.
DenoteqP
r;sqrsers,aP
r;sarsers, forqrs;ars2F.
Iff(x1;. . .;xn) is not an identity forI, then by Lemma 3 in [2], for any
il,j>l;the elementeijfalls in the additive subgroup ofRCgenerated by all valuations off(x1;. . .;xn) inI. Since the matrix (aeijqeij eijq)m has rank2, then it is not central. Therefore (aeijqeij eijq)m0 and right multiplying by eii we have ( eijq)meii0. This means that qji0 for any il and for any j>l, that is qII. Moreover from ejj(aeijqeij eijq)m0 we also get ejj((aq)eij)m0, that is aji0, and aII. All this implies that g(I)I. Since 06g(f(a1;. . .;an))m2 2I\F, it is invertible andIR. Also in this case we conclude thanks to Theorem 4 in [21].
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Manoscritto pervenuto in redazione il 19 marzo 2007.