A Note on Posner's Theorem with Generalized Derivations on Lie Ideals
V. DEFILIPPIS(*) - M. S. TAMMAMEL-SAYIAD(**)
ABSTRACT- Let R be a prime ring of characteristic different from 2, Z(R) it s center, U its Utumi quotient ring, C its extended centroid, G a non-zero generalized derivation ofR,La non-central Lie ideal ofR. We prove that if [G(u);u];G(u)
2Z(R) for allu2Lthen one of the following holds:
1. there existsa2Csuch that G(x)ax, for allx2R;
2. R satisfies the standard identity s4(x1;. . .;x4) and there exista2U, a2Csuch thatG(x)axxaax, for allx2R.
1. Introduction.
The motivation for this paper lies in an attempt to extend in some way the well known first Posner's Theorem contained in [15]: there Posner proved that ifdis a derivation of a prime ringRsuch that [d(x);x] falls in the center ofR, for allx2R, then eitherd0 orRis a commutative ring.
Recently in [3] Cheng studied derivations of prime rings that satisfy cer- tain special Engel type conditions: he showed that ifRis a prime ring of characteristic different from 2 and d a non-zero derivation of R which satisfies the condition [[d(x);x];d(x)]0 for all x2R, then R mustbe commutative.
Our purpose here is to continue this line of investigation by studying the setS f[[G(x);x];G(x)];x2Lg, whereGis a generalized derivation
(*) Indirizzo dell'A.: DI.S.I.A., Faculty of Engineering University of Messina, Contrada di Dio, 98166, Messina, Italy.
E-mail: defilippis@unime.it
(**) Indirizzo dell'A.: Department of Mathematics, Faculty of Science Beni Suef University, Beni Suef, Egypt.
E-mail: m_s_tammam@yahoo.com
2000Mathematics Subject Classification. 16N60, 16W25.
defined on R andLis a non-central Lie ideal of R. More specifically an additive mapG:R !Ris said to be a generalized derivation if there is a derivation d of R such that, for all x;y2R, G(xy)G(x)yxd(y). A significative example is a map of the form G(x)axxb, for some a;b2R; such generalized derivations are called inner. Our goal is to confirm that there is a relationship between the structure of the prime ring Rand the behaviour of suitable additive mappings defined onRthat satisfy certain special identities. We will show that if any element ofSis central in R, then some informations about the form of the generalized derivationG and the structure ofRcan be obtained. More precisely we will prove the following:
THEOREM. Let R be a prime ring of characteristic different from 2, Z(R)its center, U its Utumi quotient ring, C its extended centroid, G a non-zero generalized derivation of R, L a non-central Lie ideal of R. We prove that if
[G(u);u];G(u)
2Z(R)for all u2L then one of the following holds:
1. there existsa2C such that G(x)ax, for all x2R;
2. R satisfies the standard identity s4(x1;. . .;x4)and there exist a2U, a2C such that G(x)axxaax, for all x2R.
For sake of clearness we premitthe following:
FACT1. Denote byTUCCfXgthe free product overCof theC- algebraUand the freeC-algebraCfXg, withXa coutable set consisting of non-commuting indeterminates fx1;. . .;xn;. . .g. The elements of T are called generalized polynomial with coefficients inU. Moreover ifIis a non- zero ideal ofR, thenI;RandUsatisfy the same generalized polynomial identities with coefficients inU. For more details about these objects we refer the reader to [1] and [4].
FACT2. Let a1;. . .;ak2U be linearly independentover C and
a1g1(x1;. . .;xn). . .akgk(x1;. . .;xn)02T, for some g1;. . .;gk2 2TUCCfXg. As a consequence of the result in [4], if for any i, gi(x1;. . .;xn)Pn
j1xjhj(x1;. . .;xn) and hj(x1;. . .;xn)2T, t hen g1(x1;. . .;xn);. . .;gk(x1;. . .;xn) are the zero element of T. The same conclusion holds if g1(x1;. . .;xn)a1. . .gk(x1;. . .;xn)ak02T, and gi(x1;. . .;xn)Pn
j1hj(x1;. . .;xn)xjfor somehj(x1;. . .;xn)2T.
2. The case of Inner Generalized Derivations.
In this section we study the case when the generalized derivationGis inner defined as follows:G(x)axxbfor allx2R, wherea;bare fixed elements ofU.
In all that follows we denote P(x1;x2;x3)h
a[x1;x2][x1;x2]b;[x1;x2]
;a[x1;x2][x1;x2]bi x3
x3h
a[x1;x2][x1;x2]b;[x1;x2]
;a[x1;x2][x1;x2]bi and assume thatRsatisfies the generalized identityP(x1;x2;x3).
LEMMA1. If R does not satisfy any non trivial generalized polynomial identity, then a;b2C and G(x)ax, for all x2R and foraab.
PROOF. Denote by TUCCfx1;x2;x3g the free product overC of theC-algebraUand the freeC-algebraCfx1;x2;x3g. Any elementofTis a generalized polynomial with coefficients inU.
Suppose thatRdoes not satisfy any non trivial generalized polynomial identity. Thus
P(x1;x2;x3)h
a[x1;x2]2[x1;x2](b a)[x1;x2] [x1;x2]2b;a[x1;x2][x1;x2]b
x3
x3
ha[x1;x2]2[x1;x2](b a)[x1;x2] [x1;x2]2b;a[x1;x2][x1;x2]bi
a
[x1;x2]2a[x1;x2][x1;x2]3b [x1;x2]a[x1;x2]2 [x1;x2]2(b a)[x1;x2][x1;x2]3b
x3
[x1;x2]
(b a)[x1;x2]a[x1;x2](b a)[x1;x2]2b [x1;x2]ba[x1;x2] [x1;x2]b[x1;x2]b ba[x1;x2]2 b[x1;x2](b a)[x1;x2]b[x1;x2]2b
x3
x3
ha[x1;x2]2[x1;x2](b a)[x1;x2] [x1;x2]2b;a[x1;x2][x1;x2]bi
02T:
Suppose thatf1;agare linearlyC-independent. SinceP(x1;x2;x3) is a tri- vial generalized polynomial identity forR, then
[x1;x2]2a[x1;x2][x1;x2]3b [x1;x2]a[x1;x2]2 [x1;x2]2(b a)[x1;x2]
[x1;x2]3b
x302T
that is
[x1;x2]2a[x1;x2][x1;x2]3b [x1;x2]a[x1;x2]2 [x1;x2]2(b a)[x1;x2][x1;x2]3b02T:
This implies thatf1;bgare linearlyC-dependent. In fact, if not it fol- lows that [x1;x2]3is an identity forR, a contradiction. Thusbb2Cand Rsatisfies
[x1;x2]2a[x1;x2]b[x1;x2]3 [x1;x2]a[x1;x2]2[x1;x2]2a[x1;x2] which is a non-trivial generalized identity, since we suppose thatf1;agare linearlyC-independent. This contradiction says thatf1;agare linearlyC- dependent, that isaa2C.
ThereforeRsatisfies the generalized identity
h[x1;x2](ba)[x1;x2] [x1;x2]2(ba);[x1;x2](ba)i x3
x3
h[x1;x2](ba)[x1;x2] [x1;x2]2(ba);[x1;x2](ba)i that is
0
[x1;x2]b0[x1;x2]2b0 [x1;x2]2b0[x1;x2]b0 [x1;x2]b0[x1;x2]b0[x1;x2]
[x1;x2]b0[x1;x2]2b0 x3
x3
[x1;x2]b0[x1;x2]2b0 [x1;x2]2b0[x1;x2]b0 [x1;x2]b0[x1;x2]b0[x1;x2]
[x1;x2]b0[x1;x2]2b0
[x1;x2]b0[x1;x2]2b0 [x1;x2]2b0[x1;x2]b0 [x1;x2]b0[x1;x2]b0[x1;x2]
[x1;x2]b0[x1;x2]2b0 x3
x3[x1;x2]b0[x1;x2]b0[x1;x2] x3
2[x1;x2]b0[x1;x2]2 [x1;x2]2b0[x1;x2] b0
whereb0ba. Iff1;b0gare linearlyC-independent, then x3
2[x1;x2]b0[x1;x2]2 [x1;x2]2b0[x1;x2]
is a non-trivial generalized identity forR, a contradiction. Thenf1;b0gare linearlyC-dependent, that isb02Cas well asb, and we are done. p LEMMA2. Let RMm(F)be the ring of mm matrices over the field F of characteristic different from2, with m>1, a;b elements of R such that
[auub;u];auub 2Z(R)
for all u2[R;R]. Then one of the following holds:
1) a;b2Z(R);
2) a b2Z(R)andm2.
PROOF. The first aim is to prove that a bis a diagonal matrix. Say aP
ij aijeij, bP
ij bijeij, where aij;bij2F, and eij are the usual matrix units. Letu[r1;r2][eii;eij]eij, for anyi6j. Thus
[aeijeijb;eij];aeijeijb
(bji aji)(aji bji)eij2Z(R) that is all the off-diagonal entries of the matrixa bare zeros.
Letnow x2AutF(R) with x(x)(1eji)x(1 eji). Of course [x(a)uux(b);u];x(a)uux(b)
2Z(R), for allu2[R;R]. By calculation we have that
x(a)aejia aeji ejiaeji x(b)bejib beji ejibeji
and by the previous argument we also have that x(a b) is a diagonal matrix. In particular the (j;i)-entry of x(a b) is zero, tha is aii biiajj bjj. By the arbitrariness ofi6j, we have thata bais a central matrix in R and
[auuaau;u];auuaau
2Z(R), for all u2[R;R], that isRsatisfies
ha[x1;x2]2 [x1;x2]2a;a[x1;x2][x1;x2]aa[x1;x2]
;x3i : In casem2 we are done. Thus assume thatm3.
Suppose thatais nota diagonal matrix, for example letaji60 fori6j.
Letnowv[eii;eijeji]eij eji. Thus X
av2 v2a;avvaav 2Z(R)
hence for anyk6i;j, the (k;i)-entry Xki of the matrixX is zero. By cal- culations we have that
Xkiaki(aij aji)akj(ajjaiia)0 (1)
On the other hand forw[eii;eij eji]eijeji we have Y
aw2 w2a;awwaaw
2Z(R)0:
Again the (k;i)-entryYkiof the matrixY is zero, that is Ykiaki(aijaji)akj(ajjaiia)0 (2)
By (1) and (2) itfollows that
2akiaji0 (3)
Therefore we have that ifaji60, thenaki0 for allk6i;j.
Let W2AutF(R) defined as W(x)(1ekj)x(1 ekj). Of course for all u2[R;R],
W(a)u2 u2W(a);W(a)uuW(a)au
2Z(R) Since the (k;i)- entry of the matrixW(a) is equal toaji60, then by the argument in (3) we have that the (j;i)-entrya0ji of the matrix W(a) is zero. By calculations it follows 0a0jiaji, a contradiction. Therefore a mustbe a diagonal matrix in R. As above, for all r6s, let x2AutF(R) with x(x)
(1esr)x(1 esr). Hence alsox(a)aesra aesr esraesr mustbe a diagonal matrix. In particular the (s;r)-entry ofx(a) is zero, tha isarrass. By the arbitrariness ofi6j, we have thatais a central matrix inR, and we
are done again. p
PROPOSITION1. LetRbe a prime ring of characteristic different from2.
Suppose thata; bare elements ofUsuch that
[auub; u]; aubu
2Z(R),
for allu2[R; R]. Then one of the following holds:
1) a;b2C;
2) a b2CandRsatisfies the standard identitys4(x1;. . .;x4).
PROOF. By Lemma 1 we may assume thatRsatisfies the non-trivial generalized polynomial identity
P(x1;x2;x3)h
a[x1;x2]2[x1;x2](b a)[x1;x2] [x1;x2]2b;a[x1;x2][x1;x2]bi x3
x3
ha[x1;x2]2[x1;x2](b a)[x1;x2] [x1;x2]2b;a[x1;x2][x1;x2]bi : By a theorem due to Beidar (Theorem 2 in [1]) this generalized polynomial identity is also satisfied byU. In caseCis infinite, we haveP(r1;r2;r3)2Cfor all r1;r2;r32UN
CC, whereC is the algebraic closure ofC. Since both U and UN
CCare centrally closed ([6], Theorems 2.5 and 3.5), we may replaceRbyUor UN
CCaccording asCis finite or infinite. Thus we may assume thatRis cen- trally closed overCwhich is either finite or algebraically closed. By Martindale's theorem [14],Ris a primitive ring having a non-zero socleHwithCas the as- sociated division ring. In light of Jacobson's theorem ([10], pag 75) R is iso- morphic to a dense ring of linear transformations on some vector spaceVoverC.
Assume firstthatVis finite-dimensional overC. Then the density ofR onVimplies thatRMk(C), the ring of allkkmatrices overC. SinceR is not commutative we assumek2. In this case the conclusion follows by Lemma 2.
Assume nextthatV is infinite-dimensional over C. As in lemma 2 in [16], the set [R;R] is dense on Rand so from P(r1;r2;r3)2Z(R), for all r1;r2;r32R, we have
[arrb;r];arrb
2Z(R), for all r2R. Due to the infinity-dimensionality,Rcannot satisfies any polynomial identity. In particular the non-zero idealHcannotsatisfiess4(x1;. . .;x4). Suppose that eithera2=Corb2=C, then at least one of them doesn't centralize the non zero idealHofR, and we will prove that this leads to a contradiction.
Hence we are supposing that there exist h1;h22H such that either [a;h1]60 or [b;h2]60 and there exist h3;h4;h5;h62H such that s4(h3;. . .;h6)60.
Lete2eany non-trivial idempotentelementofH. Forrexe, with anyx2R, we have that
[aexeexeb;exe];aexebexe
2Z(R). By com- muting with (1 e) and then right multiplying by (1 e) itfollows 2(1 e)a(exe)3b(1 e)0. Since char(R)62, we have that either (1 e)ae0 or eb(1 e)0. If (1 e)ae0 then aeeae and baebeae. On the other hand, in caseeb(1 e)0, we getebebe, and soebaabea. In any case we notice that the ringeResatisfies the gen- eralized identityh
[(eae)XX(ebe);X];(eae)XX(ebe)
;Yi .
By Litoff's theorem in [7] there exists e2e2H such that h1;h2, h3;h4;h5;h62eRe, moreover eRe is a central simple algebra finite di- mensional over its center. Sinces4(h3;. . .;h6)60, then eReMt(C), for t3. By the finite dimensional case, we have thateae;ebe2Z(eRe), but this contradicts with the choices ofh1;h2 ineRe. p
3. The proof of the Theorem.
In this final section we will make use of the result of Kharchenko [11]
about the differential identities on a prime ring R. We refer to Chapter 7 in [2] for a complete and detailed description of the theory of generalized polynomial identities involving derivations.
Itis well known thatany derivation of a prime ring R can be uniquely extended to a derivation of its Utumi quotients ring U, and so any deri- vation ofRcan be defined on the wholeU ([2], pg. 87).
Now, we denote by Der(Q) the set of all derivations on Q. By a deri- vation word we mean an additive mapDof the formDd1d2. . .dm, with each di2Der(Q). Then a differential polynomial is a generalized poly- nomial, with coefficients in Q, of the form F(Dj(xi)) involving non- commutative indeterminates xi on which the derivations wordsDj actas
unary operations. The differential polynomialF(Dj(xi)) is said a differential identity on a subsetTofQif itvanishes for any assignmentof values from Tto its indeterminatesxi.
LetDint be the C-subspace of Der(Q) consisting of all inner deriva- tions on Qand letd andd be two non-zero derivations on R. As a par- ticular case of Theorem 2 in [11] we have the following result (see also Theorem 1 in [13]):
FACT3. Ifdis a non-zero derivation onRandF(x1;. . .;xn;d(x1);. . .;d(xn)) is a differential identity onR, then one of the following holds:
1) eitherd2Dint;
2) orRsatisfies the generalized polynomial identity F(x1;. . .;xn;y1;. . .;yn;):
Now we are ready to prove our main result:
THEOREM. Let R be a prime ring of characteristic different from2, Z(R)its center, U its Utumi quotient ring, C its extended centroid, G a non-zero generalized derivation of R, L a non-central Lie ideal of R. We prove that if
[G(u);u];G(u)
2Z(R)for all u2L then one of the following holds:
1) there existsa2Csuch thatG(x)ax, for allx2R;
2) R satisfies the standard identity s4(x1;. . .;x4) and there exist a2U,a2Csuch thatG(x)axxaax, for allx2R.
PROOF. By Theorem 3 in [12] every generalized derivation g on a dense rightideal ofR can be uniquely extended to the Utumi quotient ringUofR, and thus we can think of any generalized derivation ofRto be defined on the whole U and t o be of t he form g(x)axd(x) for some a2U and d a derivation on U. Thus we will assume in all that follows that there exist a2U and d derivation on U such that G(x)axd(x). We note that we may assume that R is notcommu- tative, sinceLis notcentral. Moreover, since char(R)62, there exists a non-central two-sided idealIofRsuch that [I;I]L(see p. 4-5 in [8];
Lemma 2 and Proposition 1 in [5]). Therefore [[G(u);u];G(u)]2Z(R) for all u2[I;I]. Moreover by [13] R and I satisfy the same differ- ential polynomial identities, that is [[G(u);u];G(u)]2Z(R) for all u2[R;R].
By assumptionRsatisfies the differential identity (4) h
[a[x1;x2][d(x1);x2][x1;d(x2)];[x1;x2]];a[x1;x2][d(x1);x2][x1;d(x2)]i x3
x3
h[a[x1;x2][d(x1);x2][x1;d(x2)];[x1;x2]];a[x1;x2][d(x1);x2][x1;d(x2)]i
Firstsuppose thatdis notan inner derivation onU. By Kharchenko's theorem [11]Rsatisfies the polynomial identity
(5) h
a[x1;x2][y1;x2][x1;y2];[x1;x2]
;a[x1;x2][y1;x2][x1;y2]i x3
x3h
a[x1;x2][y1;x2][x1;y2];[x1;x2]
;a[x1;x2][y1;x2][x1;y2]i in particularRsatisfies any blended component
ha[x1;x2];[x1;x2]
;a[x1;x2]i
x3 x3h
a[x1;x2];[x1;x2]
;a[x1;x2]i
that is h
a[x1;x2];[x1;x2]
;a[x1;x2]i 2Z(R)
and by Proposition 1 we have thataa2C. Thus from (5), itfollows thatR satisfies the polynomial identity
h[y1;x2][x1;y2];[x1;x2]
;a[x1;x2][y1;x2][x1;y2]i x3 x3h
[y1;x2][x1;y2];[x1;x2]
;a[x1;x2][y1;x2][x1;y2]i : SinceRsatisfies a polynomial identity, there existsMk(F), the ring of all matrices over a suitable field F, such thatRandMk(F) satisfy the same polynomial identities (see [9], Theorem 2 p.54 and Lemma 1 p.89). For x1e22,x2e21,y1e21andy2e12we obtain
[y1;x2]0; [x1;y2] e12; [x1;x2]e21
and it follows the contradiction h e12;e21
;ae21 e12i
2e122ae212=Z(R):
Now consider the case whendis an inner derivation induced by the ele- ment b2U. Since G(x)ax[b;x]axbx xb(ab)xx( b) andbyProposition1,wehavethat eithera;b2Cora2b2CandRsatisfies
s4(x1;. . .;x4). In the first case we conclude thatG(x)ax, fora2C; in t he
second oneG(x)a0xxa0ax, wherea0 b. p
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Manoscritto pervenuto in redazione il 9 giugno 2008.