C OMPOSITIO M ATHEMATICA
J. DE R UITER
On derivations of Lie algebras
Compositio Mathematica, tome 28, n
o3 (1974), p. 299-303
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299
ON DERIVATIONS OF LIE ALGEBRAS
J. de Ruiter
Noordhoff International Publishing
Printed in the Netherlands
Let L be a Lie
algebra
of finite or infinite dimension over a field k ofarbitrary
characteristic and letDER(L)
denote the Liealgebra
of all deri- vations of L. Then we may raise thefollowing question:
how far doesDER(L)
determine L?In the case of finite-dimensional Lie
algebras
we have the well-known results obtainedby
G. F.Leger,
N.Jacobson,
S.Tôgô,
T. Satô and others.But in the case of infinite-dimensional Lie
algebras
almostnothing
isknown ! Since this type of Lie
algebras
appears more and more in miscel- laneous fieldsof research,
as for instance grouptheory,
differential geom-etry
and operatortheory,
it becomesimportant
to have thedisposal
ofsome
general
relations betweenarbitrary
Liealgebras
and their deriva- tionalgebras.
In this paper we will prove some initial results.Section 1 deals with notation and basic definitions. In section 2 we
shall
give
sufficient conditions for a Liealgebra
to have outer derivations.The main result of this section is a
generalization
of a well-known theorem of N.Jacobson,
which states that every non-zeronilpotent
Liealgebra
has outer derivations
([1],
Theorem4).
We shall prove: every Liealgebra
L with nonzero centre, where L 1
L2
contains somenilpotent element,
has outer derivations. As acorollary
we have : Liealgebras
of type(T)
have outer derivations d such that d2 = 0.
In section 3 we are concerned with
nilpotency
andsimplicity
of deriva-tion
algebras.
First we shall prove : if the centre of L is not contained inL?
andDER(L)
isnilpotent,
then L is one-dimensional. This theorem in- cludes a lemma of S.Tôgô. By
means of this theorem we can prove that a non-zero Liealgebra
with Abelian derivationalgebra
is also one-dimen-sional,
a resultalready proved by
S.Tôgô
in.the case of finite-dimensional Liealgebras ([5],
Lemma6).
Next we will show thatnon-semisimple
Liealgebras
may havesimple
derivationalgebras,
as distinct from the finite- dimensional case, whereonly simple
Liealgebras
havesimple
derivationalgebras.
Someproperties
of such Liealgebras
will be derived.Finally
weshow that Jacobson’s theorem
concerning
finite-dimensional Liealgebras
with
non-singular (= injective)
derivations([1],
Theorem3)
does notremain valid for infinite-dimensional Lie
algebras.
We shallgive
an exam-ple
of anon-nilpotent
Liealgebra
withnon-singular
derivations.300
1. Notation and
terminology
For notation we refer to I. N. Stewart
[4].
L willalways designate
a Liealgebra (possibly
of infinitedimension)
over anarbitrary
field k. L isperfect
if L = L2 andsimple
if 0 and L are theonly
ideals of L. We shallcall L
semisimple
if L does not contain solvable ideals :0 0. The centre of Lwill be denoted
by 03B6(L).
The ideal ofDER(L)
of all inner derivations of L will be referred to asad(L).
If L is asplit
extension of an ideal Iby
a sub-algebra S,
we will write L = I 83 S. In the case of a direct sum thesign
83will be
replaced by
thesign
~. The radicals of a Liealgebra
will be de- notedby 03B2(L)
= the Baerradical, v(L)
= theFitting radical, p(L)
= theHirsch-Plotkin radical
(for
their definitions see[4])
andRL
= theVasilescu radical
(introduced
in[7]).
2. Outer dérivations of Lie
algebras
We first
give
some information about the derivationalgebra
of certain types ofsplit
extensions.LEMMA 1 :
Suppose
L = IS, I2 =
0 and I ~[I, 03B6(S)].
Then L has outerderivations.
PROOF :
Every
x ~ L has aunique representation
x = x, + xs, x, E I and xs E S. Define dx = XI, thend[x, y] = [xj, ys]
+[xs, y,] = [dx, y]
+[x, dy],
since I is Abelian. Therefored E DER(L);
d cannot be an innerderivation,
forsuppose d
=ad(z)
for some z EL,
then x, = dx =[z, x]
forall x E L.
Now zI
=[z, z]
=0,
soz~03B6(S). Consequently
I =[I, (8)],
acontradiction to our
hypothesis.
COROLLARY : A Lie
algebra
L,splitting
over a non-zero Abelian ideal Iby
some subideal
S,
has outer derivations.PROOF : Since S si L,
[I, nS]
c S for some n, so[I, nS]
= 0. Hence I ~[1, 03B6(S)],
for otherwise I =[I, nS]
= 0.LEMMA 2: Let L = H 0 K and suppose H has outer
derivations.
ThenL has outer derivations.
PROOF : Let u be some outer derivation of H.
Every
x E L can beuniquely
written as x = xH+xK,
xH E H
andxK E K.
We define dx = ux, for all x E L. Then it iseasily
verified thatd E DER(L).
If d would be an innerderivation,
then d =ad(z)
for some z E L andconsequently
UXH = dx =[z, x] = [zH, xH]
+[zK, xK],
so uxH -[zH, xH]
E H n K = 0. Hence u =ad(zH)’
contrary to its choice.REMARK: Lemma 2 makes
clear,
that in T. Satô’s result([2], Corollary
1 of
Proposition 10)
the conditionsof imite-dimensionality, semisimplici-
ty and
solvability
are redundant.LEMMA 3:
Ç(L) qb
L2implies
that L has outer derivations.PROOF:
03B6(L)
contains some element e such thate ~ L2. Consequently
L = M E9
ke,
whereL3 ~
M for some ideal M of L. We nowapply
Lemma2 or the
Corollary
of Lemma 1.THEOREM
1:If03B6(L) ~
0 and L 1 L2 contains somenilpotent element,
thenL has outer derivations.
PROOF:
By
thepreceding
Lemma weonly
have to consider the case03B6(L)
c L2.Suppose
all derivations of L are inner.By
thehypothesis
Lcontains some
nilpotent
element e such thate~L2.
Now L can be writtenas L = M
88 ke,
whereL2 ~
M for some M. We have 0 ~03B6(L)
c03B6(M).
Let 0 ~
z~03B6(M). Every
x E L can beuniquely
written as x =xM + a(x)e, xM E M
anda(x) E k.
Define d:L~Lby
dx =a(x)z
for allx E L,
thend[x, y]
=0,
since[x, y]
EL2 ~
M and[dx, y]
+[x, dy]
=03B1(x)03B1(y)[z, e]
+a(y)a(x)[e, z]
=0,
sod E DER(L). Consequently
d =ad(m + Âe)
for somem~M and some 03BB~k. But z = de =
[m, e]
and 0 = dm =À[e, m],
so03BB =
0,
since z ~ 0.Moreover,
0 = dM =[m, M],
so 0 ~m~03B6(M).
Wecan
proceed
in the same way with m. Hence((M)
contains a sequencem = ml, m2,m3,··· such that z =
[mi, ie].
But e isnilpotent,
so z = 0.This is a contradiction ! Therefore
ad(L) ~ DER(L).
COROLLARY : Lie
algebras of type (T)
have outer derivations d such thatd2 =
0.PROOF : A Lie
algebra
L is calledof type (T),
if there exists some sub-space U ~ 0 of L with the
following properties :
where 0 ~
c~03B6(L),
and themapping
i : U xU - k,
definedby [u, v] = i(u, v)c,
isnon-singular.
This notion was first introducedby
S.Tôgô
forfinite-dimensional Lie
algebras
in[6].
It is clear that every 0 ~ U E U is not contained in L2 and has the property[L, 2u]
= 0. Moreover we have(L)
cL2,
since x ~03B6(L) implies
xu =0,
for i isnon-singular.
From theproof
of Theorem 1 it follows nowimmediately,
that L has outer deriva-tions d such that
d2 =
0. In the case of finite-dimensional Liealgebras
thisresult was
already
obtainedby Tôgô.
3.
Nilpotency
andsimplicity
of dérivationalgebras
The
following
result is due to S.Tôgô ([5],
Lemma5): Suppose
L to302
be non-Abelian
nilpotent
and(L) 1-
L2. ThenDER(L)
is notnilpotent.
We will
give
thefollowing sharpening.
THEOREM 2:
If dim L ~
1 and(L) 1- L2,
thenDER(L)
is notnilpotent.
PROOF:
(L) 1- L2,
so03B6(L)
contains some element e such thate ~ L2.
Consequently
L = M @ke,
whereL2 ~
M. It is easy toverify
that03B6(L) = 03B6(M)
C ke. If03B6(M)
=0,
then03B6(L)
=ke,
so L is notnilpotent by
aLemma of Schenkman
([3],
Lemma4).
If(M) =1= 0,
then we may choose 0 ~ z E((M). Every
x ~ L can berepresented
in the form x = xM +a(x)e, xM E M
andcx(x)Ek.
We now defined1:L ~ L by putting dix
=a(x)z
and
d2 :
L - Lby putting d2 x
=a(x)e
for all x E L. Thendi~DER(L)
fori =
1,
2 and we have[dl, d2]X
=03B1(x)d1
e -03B1(x)d2
Z =03B1(x)z
=dl
x. Thetheorem now follows.
COROLLARY :
If L ~
0 andDER(L)
isAbelian,
then L is one-dimensional.PROOF :
ad(L)
isAbelian,
so il = 0. Let U be somesubspace
of L com-plementary
to L2. Then every x E L can beuniquely
written as x = x2 + xU, x2 E L2 and xu E U. Define d : L ~ Lby setting
dx =2x2
+ XU for allfx
E L, then d ~DER(L),
as an easycomputation
shows. Butad(dx) = [d, ad(x)]
=
0,
sinceDER(L)
is Abelian. Thus[dx, y]
= 0 for all x and for all y;choose x,
y E U,
then[x, y]
= 0. Hence U is Abelian andconsequently
L2 =U2 =
0. Now L =(L) 1-
L2 =0,
so dim L = 1by
Theorem 2.THEOREM 3 :
Suppose DER(L)
issimple.
Then either L is one-dimensionalor L
satisfies
eachof the following
conditions : 1. All derivativesof
L are inner.2.
DER(L) is
centreless.3. L is
perfect.
4. L ~ 03B6(L) = 03A3
H.5. All radicals
of
Lequal
the centreof
L.PROOF :
ad(L) DER(L),
so we have to consider two cases.Case I :
ad(L)
= 0.L2 =
0,
soDER(L)
consists of all linearmappings
of L into itself. There- fore scalarmultiplications
form an idealof DER(L)
and since theidentity mapping
of L is nottrivial,
we must have that all linearmappings
arescalar
multiplications.
Thisimplies
that L is one-dimensional.Case II :
ad(L)
=DER(L).
Then
L/03B6(L)
issimple.
IfAbelian,
it must beone-dimensional,
so thatL is Abelian and Case 1
applies.
So we may assumeL/03B6(L) simple
non-Abelian. In
particular
its centre is 0. Now L =03B6(L)
+L2,
so L =L2,
sinceby
Lemma 3(L)
c L2. If H L, then either~ 03B6(L)
or L = H +C(L).
But L is
perfect,
so the latter caseimplies
H = L. We can nowimmediately
conclude that the centre of L is the sum of all proper subideals of L. Since L is not
solvable, 03B6(L) = 03B2(L)
=v(L).
L is not
locally nilpotent,
for otherwiseL/03B6(L)
would belocally
nil- potent and alsosatisfy the minimum
condition forideals,
sinceDER(L)
is
simple; consequently L/03B6(L)
would be solvableby
a result of I. N.Stewart
([4],
Lemma14.3),
contrary to the fact that L is not solvable. Itnow follows that
(L)
=p(L).
The center of L is
evidently
aprimitive
ideal of L and therefore containsRL.
But03B6(L) ~
RL, so03B6(L)
=RL.
This finishes theproof.
REMARK : The centre of L does not
necessarily vanish,
if L is infinite- dimensional in Case II. M. Favre has drawn my attention to thefollowing counterexample,
due to P. de laHarpe:
Let H be an
arbitrary
infinite-dimensionalcomplex
Hilbert space,B(H)
thealgebra
of all its bounded linear operators andC(H)
the ideal ofcompact operators. Then
B(H)/C(H)
is aC*-algebra. By considering
thisassociative
algebra
as a Liealgebra L,
it turns out thatad(L)
=DER(L)
is
simple
and(L) =1=
0. Theproof
is rather technical and will be omitted.A finite-dimensional Lie
algebra
over char. 0 withsimple
derivationalgebra
is itselfsimple.
This well-known result also followsimmediately
from Theorem 3
by using
the Levidecomposition.
We will finish
by showing
that infinite-dimensional Liealgebras
withnon-singular
derivations need not to benilpotent.
Forexample,
takeL =
C(R),
the vector space of all continuous realfunctions,
where the Lieproduct
isgiven by [ f, g]
=f(0)g-g(0)f.
This Liealgebra
L is infinite-dimensional,
but notnilpotent,
since[x,nx+1] = (-1)nx
for all n.However,
d : L ~L,
definedby df
=xf,
is anon-singular
derivation of L.Finally,
1 wish to thank my referee for his useful comments.REFERENCES
[1] N. JACOBSON: A note on automorphisms and derivations of Lie algebras. Proc. Amer.
Math. Soc. 6 (1955) 281-283.
[2] T. SATO: The derivations of the Lie algebras. Tôhoku Math. J. 23-1 (1971) 21-36.
[3] E. SCHENKMAN : Infinite Lie algebras. Duke Math. J. 19 (1952) 529-535.
[4] I. N. STEWART: Lie algebras. Lecture Notes in Mathematics, Vol. 127 (1970).
[5] S. TOGO: On the derivation algebras of Lie algebras. Can. J. Math. 13 (1961) 201-216.
[6] S. TOGO: Outer derivations of Lie algebras. Trans. Amer. Math. Soc. 128 (1967) 264-276.
[7] F. H. VASILESCU : Radical d’une algèbre de Lie de dimension infinie. C.R. Acad. Sc.
Paris, Série A 274 (1972) 536-538.
(Oblatum 23-X-1973 & 12-11-1974) The UBBO EMMIUS Foundation of Training of Teachers
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