R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
V INCENZO D E F ILIPPIS
Right ideals and derivations on multilinear polynomials
Rendiconti del Seminario Matematico della Università di Padova, tome 105 (2001), p. 171-183
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VINCENZO DE FILIPPIS
(*)
ABSTRACT - Let R be an associative
prime
ring with center Z(R) and extended centroidC, f (xl ,
... , xn ) a non-zero multilinearpolynomial
over C in n non- commuting variables, d a non-zero derivation of R , m -> 1 a fixedinteger
and ea non-zero
right
ideal of R . We prove that: (i) if(d(f(x1,
... ,xn» -
... , is a differential
identity for Q
thenCQ
= eRC for someidempo-
tent element e in the socle of RC
and f (xl ,
...,xn )
is anidentity
for eRCe ; (ii) if... ,
rn ) ) - f ( rl ,
... ,rn»m
is central on R , for any r1, ... , rnEQ, thenCQ
= eRC, for someidempotent
element e in the socle of RC and either... , xn )
is central in eRCe or eRCe satisfies the standardidentity
... , X4)-
Let R be an associative
prime ring
with centerZ(R )
and extended centroid C . Recall that an additivemapping
d of R into itself is a deriva- tion ifd(xy) = d(x) y + xd(y),
for all x, In[5]
J.Bergen proved
that
if g
is anautomorphism
of R such that( g(x) - x)m
=0 ,
for all x eR ,
9where m ~ 1 is a fixed
integer, then g
= 1. Later Bell and Daif[3] proved
some results which have the same
flavour,
when theautomorphism
is re-placed by
a non-zero deivation d .They
showed that if R is asemiprime ring
with a non-zero ideal I such thatd( [ x , y ] ) - [ x , y] = 0,
ord([x, y])
+[x, y ]
=0,
for all x ,?/e/,
then I is central. Morerecently Hongan [13] proved
that if R is a 2-torsion freesemiprime ring
and I anon-zero ideal of
R ,
then I is central if andonly
ifd([x, y ] ) - [x, y ]
eeZ(R),
ord([x, y])
+[x, y] eZ(R),
for all x,yeI.
In this paper we prove two results
generalizing
some of theprevious
ones. More
precisely
we consider the case whenf(x1,
... , is a multili-(*) Indirizzo dell’A.:
Dipartimento
di Matematica, Universita di Messina, Sa-lita
Sperone
31, 89166 Messina, e-mail:[email protected]
near
polynomial
over C in nnon-commuting variables,
Q a non-zeroright
ideal of R and we show
THEOREM 1.
If (d( f (rl , ... , rn ) ) - f (rl ,
... , =o , for
any rl , ... , thenCQ
= eRCfor
someidempotent
element e E Soc(RC)
and
f(x1,
is apolynomial identity for
eRCe .THEOREM 2.
If (d(f(rI’
... ,rn)) - f(rl,
... ,for
any r1, ... , r nee, thenC~o
= eRCfor
someidempotent
element e E Soc(RC)
and either
f(x1"’"
is central in eRCe or eRCesatisfies S4 ( xl ,
... ,X4).
To prove these theorems we need some notations
concerning
quo- tientrings.
Denoteby Q
the two-sided Martindalequotient ring
of R andby
C the centerof Q ,
which is called the extended centroid of R . Note thatQ
is also aprime ring
with C a field. We will make afrequent
use ofthe
following
notation:for some and we denote ... ,
xn )
thepolynomial
obtained... ,
xn ) by replacing
each coefficient a ~ with Thus wewrite
... , rn ) ) = f d (rl , ... , rn ) + ~ f (rl ,
... ,d(ri ), ... , rn ),
for alli
rl, ..., rn E R . We recall that any derivation of R can be
uniquely
exten-ded to a derivation of
~,
moreoverby [19]
the two-sided ideal I andQ
sa-tisfy
the same differential identities. For this reason whenever R sati- sfies a differentialidentity, by replacing R by Q
we will assume, without loss ofgenerality, R = Q ,
C =Z(R )
and R will be aC-algebra centrally
closed.
To obtain the conclusions
required
we will also make use of the follo-wing
result:CLAIM 1
[14].
Let R be aprime ring,
d a non-zero derivation of R and I a non-zero two-sided ideal of R . Let ... , xn,d(xl ),
... ,a differential
identity
inI ,
that isThen one of the
following
holds:1)
either d is an inner derivationin Q,
in the sense that thereexists q E Q
such thatd = ad(q)
andd(x) = ad(q)(x) = [q, x],
for all x eE R ,
and I satisfies thegeneralized polynomial identity
2)
or I satisfies thegeneralized polynomial identity
We
premit
thefollowing:
LEMMA 1.
Let Q
be a non-zeroright
idealof R and
d a derivationof
R . Then the
following
conditions areequivalent: (i)
d is an inner deri- vation inducedby
some6 E Q
such thatbQ
=0; (ii)
= 0(For
itsproof
werefer
to[6, Lemma]).
LEMMA 2.
If (d(.f’(rl, ... , rn)) - f(rl, ... , rn))’~ E Z(R), for
any rl , ..., rn E o , then R is aGPI-ring.
PROOF. Assume R is not
commutative,
otherwise we conclude trivial-ly
that R is aGPI-ring. Suppose
that d is a innerderivation, d
=ad(b),
for some
6 e Q, d(x)
=[ b , x ],
for all x EQ .
Since d ~0,
letb f1.
C. Moreo-ver, since R is not
commutative,
there exists Thus... ,
6M?~)] 2013/(~.ri, .... xn + 1 ]
is a non-trivial GPI for R . Let now d an outer derivation of R . If for alld(r) E rC,
then[d(r), r] = 0,
that is R is commutative(see [4]).
Therefore there existssuch that Write
Thus
is a
generalized
differentialidentity
for R . Inparticular, by
Kharchen-ko’s theorem in
[14],
sinced( a) f/. aC,
we have thatis a non-trivial GPI for R .
Before
proceeding
to heproof
of mainresults,
we need to resolve thesimplest
case, when Q = R .LEMMA 3. Let R =
Mk(F)
be thering of
k x k matrices over thefield F,
with2 ,
d a non-zero inner derivation inducedby
a non-cen-tral eLerrzent A
of
R . Theorems 1 and 2 holdif
Q = R .PROOF.
Suppose
3 . Let eij the usual matrix unit with 1 in( i , j)- entry
and zero elsewhere.By
theassumption
If assume
f(ri ,
... ,xn )
not central inR , by [20,
Lemma2, proof
of Lem-ma
3]
there exist r1, ..., rn E R suchthat f (rl ,
...,rn )
= aeij, with 0 ~ a E Since the... , rn ) : rl , ... , rn E R ~
is invariant under anyF-automorphism,
then for any there existtl ,
... ,such that
f (t1,
... ,tn )
=Thus,
for any i~ j
moreover
( [A ,
has rank ~2,
that is( [A ,
= 0in R.-
Right multiplying by eij
It follows that the
(j,i)-entry
of the matrix A is zero, for all i~ j
and thismeans that the A is
diagonal,
that is A= E
a t ett , witha t E F .
Now deno-t
te d the inner derivation induced
by
A .If x
is aF-automorphism
of1~ ,
then the derivation
d. = x -1 dx
satisfies the same condition ofd ,
that isSince the derivation
dx
is the one inducedby
the elementx(A )
=x -1 Ax ,
then
x(A )
is adiagonal matrix, according
to the aboveargument.
Fix nowi ~ j
and for all Sincex(A) _ ( 1 +
must be
diagonal
thenis
diagonal
that is a i = a j and we
get
the contradiction that A is a central matrix.Therefore
f (xl ,
... ,xn )
must be central in R .Of course if
( [A , f ( r1, ... , rn ) ] - f ( rl , ... , rn ) )m = 0 ,
for allri, ..., rneR,
the aboveargument
can beadapted
to prove thatf (xl , ... , xn )
iscentral,
without any restriction on k .Moreover,
since inthis case
[A ,
... ,rn ) ]
... ,rn )
= 0 for all rl, ... , rn E E R and sof (xl ,
... ,xn )
is anidentity
in R[20,
Lemma3, proof
of Theo-rem
4].
LEMMA 4. Theorem 1 holds
if
Q = R . PROOF. LetIf d is not inner
then, by
Claim1,
R satisfies the differentialidentity g(X1,
..., Xn, Y1,...,yn)=
In
particular fm (Xl’ ..., xn )
is anidentity
for 1~ . In this case since R sati- sfies apolynomial identity,
there exists a suitable field F such that R andMk (F) satisfy
the samepolynomial
identities. It followsthat f (xl ,
... ,xn )
must be an
identity
inMk (F) (see [20])
and so in I~ .Now let d be an inner derivation induced
by
an element Ae Q . Then,
for any r1, r2 , ... ,( [A , f ( rl ,
... ,rn ) ] - f ( rl ,
... ,= 0. Since
by [1] (see
also[7])
R andQ satisfy
the samegeneralized
po-lynomial identities,
we have( [A , f ( rl , ... , rn ) ] - f ( rl ,
... ,rn ) )m = 0 ,
forany r2 , ... ,
r n E Q. Moreover, since Q
remainsprime by
theprimeness
of
R , replacing
Rby Q
we may assume that A E R and C =Z(Q) is just
the center of R . In the
present
situation R is acentrally
closedprime
C-algebra [10],
i.e.By
Martindale’s theorem in[21],
RC = R is aprimitive ring
which isisomorphic
to a densering
of linear transforma- tions of a vector space V over a divisionring
D . Since R isprimitive
thenthere exist a vector space V and the division
ring
D such that is dense of D-linear transformations over V.Assume first that
dimn V = 00.
Recall that one can write We want to showthat,
for any v E
V, v
and Av arelinearly D-dependent.
If Av = 0
then ~ v , Av)
isD-dependent.
Thus we may suppose that Av # 0. If v and Av areD-independent,
since then thereexist w3 , ... , wn E V such that v = wl , Av = w2 , w3 , ... , wn are also li-
nearly independent. By
thedensity
ofI ,
there exist r1, ... ,rn e l
suchthat
for all other
possible
choices ofi , j .
Therefore
and we obtain the contradiction
Hence
A ,
Av must beD-dependent,
for any v E V.Now we show that there exists b E D such that Av =
vb,
for any v E V.Choose v , w E V
linearly independent.
Since there exists U E V such that v, w, u arelinearly independent. By
aboveargument,
there exist av , a~,
au E D
such thatMoreover
A(v
+ w +u) _ (v
+ w +u)
for a suitablecause v , are
linearly independent,
au ~ aw = av = av + w + u ~ asrequi-
red.
Let now r E R and v E V. As we have
just
seen, there exists b E D such that Av =vb, r(Av)
=r(vb),
and alsoA(rv) _ (rv)
b. Thus 0 =[A, r]
v,for any v E
V,
that is[A , r] V =
0 . Since V is a left faithful irreducible R-module, [A , r]
=0,
for all r EI~ ,
i.e. A EZ(R )
and d =0,
which contradic- ts ourhypothesis.
Therefore
dimD
V must be a finitepositive integer.
In this case I~ is asimple
GPIring
with1,
and so it is a centralsimple algebra
finite dimen- sional over its center. From Lemma 2 in[16]
it follows that there exists asuitable field F such that R
c Mk (F),
thering
of all k x k matrices overF,
and moreover
Mk (F)
satisfies thegeneralized polynomial identity ([AW(xl ... , xn)] -J (xl ~ ... , xn))m.
As in Lemma 3 we conclude that
f(x1, ... , xn )
is anidentity
inR. D
LEMMA 5. Theorem 2 holds
if
Q = R .PROOF.
If,
for every rnE I ,
... ,rn ) ) -
... ,
=
0, by
Lemma... , rn )
is anidentity
in R . Other-wise, by
ourassumptions,
I nZ(l~) ~
0. Let now K be a non-zero two-si- ded ideal of thering
of the centralquotients
of R . Since K n R is anideal of R then K n R n
Z(R ) ~ 0,
that is K contains an invertible ele- ment in and soRZ
issimple
with 1.We know that for any
Thus R satisfies the differential
identity
If the derivation is not
inner, by
Claim1,
1~ satisfies thepolynomial identity
and in
particular
R satisfiesTherefore R is a
prime PI-ring.
For a eE R -
Z(R),
we have that R satisfiesand in this situation we
get
therequired
conclusionby
lemma 3.Now let d be an inner derivation induced
by
an element Ae Q.Also
inthis case we will prove that either
f(x1, ... , xn )
is central in R or R sati- sfies~4(~1, .... ~4).
By localizing
R atZ(R)
it follows that( [A , f ( r1, ... , rn ) ] - - f(r1, ...,
for all r1, r2, ... ,Since R and
Rz satisfy
the samepolynomial identities,
in order toprove that R satisfies ... ,
xn ), xn
+1 ],
we may assume that R is sim-ple
with 1.In this case,
( [A , f ( r1, ... , rn ) ] - f ( rl , ... , rn ) )m E Z(R ),
for all rl ,r2 ,
... , rn E R .
Therefore R satisfies ageneralized polynomial identity
and it is
simple
with1,
whichimplies
thatQ
= RC = R and R has a mini- malright
ideal. Thus A e R= Q
and R issimple
artinian that is R =Dk ,
where D is a division
ring
finite dimensional overZ(R) [21].
From Lem-ma 2 in
[16]
it follows that there exists a suitable field F such that thering
of all k x k matrices overF,
and moreoverMk (F)
satisfies the
generalized polynomial identity
- f(x1, ..., xn))m, xn + 1].
We end upagain by
lemma 3.REMARK. In all that
follows
weprefer
to write thepolynomial f(x1,
... ,by using
thefollowing
notation:where any gi is a multilinear
polynomial of degree
n - 1 and xi neverappears in any monomial
of
gi . Note thatif
there exists anidempotent
e E H = Soc
( ~ )
such that any gi is apolynomial identity for eHe ,
thenwe
get
the conclusion thatf (x1, ... ,
is apolynomial identity for
eHe . Thus we suppose that there exists an index i and r1, 1 E-=
E eHe such that
gi ( rl , ... , rn -1 ) ~
0. Now letf(x1’"’’
=gi(X1, ...,
Xi-I’ xi + 1, ... ,Xn)
xi +h(xl ,
... ,Xn) where gi
and h are mul-tilinear
polynomials,
xi never appears in any monomialsof
gi and xinever appears as last variable in any monomials
of
h . Without lossof
generality
we assume i = n, say gn(Xl’
... ,Xn - 1) = t(xl ,
... ,xn -1 )
andwhere t
PROOF OF THEOREM 1.
Suppose
first ... , 1 is notan
identity
for e. Weproceed
to derive a contradiction. Sinceby
lemma 2R is a GPI
ring,
so is alsoQ (see [1]
and[7]). By [21] Q
is aprimitive ring
with H = Soc
(Q) # 0,
moreover we may assumethat f ( xl , ... , xn ) xn + 1 is
not an
identity
forQH,
otherwiseby [1]
and[7]
it should be anidentity
also for
eQ,
which is a contradiction. Let aI, ... , an + 1 EQH
such that... ,
an )
an + 1 ~ o . Since H is aregular ring,
then for all a E H there existse 2 =
e E H such that eH =a1 H + a2 H + .. + an + 1 H, e E eH,
a = eaand ai
= eai for all i =1,
... , n + 1. Therefore we havef ( eHe ) _
= f(eH) e ~ 0. By
ourassumption
andby [19]
we also assume that(d( f (x1, ... , xn ) ) - f(x1, ... , xn ) )m
is anidentity
for Inparticular ( d( f ( xl , ... , xn ) ) - f ( x1, ... , xn ) )m
is anidentity
for eH . It followsthat,
for all rl , ... ,
rn E H,
As we said
above, xn ) = t(x1,
... ,xn -1 ) xn + h(xl ,
... ,where xn
never appears as last variable in any monomials of h . Let r E H andpick rn
=r ( 1 - e).
Hence we have:Left
multiplying by ( 1 - e)
we obtainand so that is
and, by
eH = 0 whichimplies
Since eHe is a
simple
artinianring
andt( eHe ) ~
0 is invariant under the action of all innerautomorphisms
ofeHe , by [8,
lemma2], ( 1 - e ) d( e )
== 0 and so
d(e)
=ed(e)
E eH. Thusd(eH)
cd(e)
H +ed(H)
c eH coH
andd(a)
This means thatd(QH)
gQH.
Therefore the derivation d induced another oned ,
which is defined in theprime ring
, where is the left annihilator in H of
QH,
and6(Y) = d(x),
for all Moreover weobviously
have that(d(, f (xl , ... , xn ) ) - f (xl , ... ,
is a differentialidentity
forQH. So, by
lemma
4,
one of thefollowing
holds: either 6 =0,
... , is anidentity
for(2H.
If 6 =
0
thend(gH)
c that isd(gH) gH
= 0 .By
lemma1,
d isan inner derivation induced
by
an element b EQ
such thatbe
= 0.Thus,
for all rl , ... , r
E oH,
Right multiplying by f (rl , ... , rn )
we have ... ,rn )m +
= 0and,
as aconsequence of main theorem in
[8]
weget
the contradiction... ,
rn ) ~oH
= 0 . Also in the casef(x1,
... ,xn )
is anidentity
foroH
we obtain the contradiction
that f (xl , ... , xn ) xn +
1 is anidentity
foroH.
Finally
we are in the case whenf (rl , ... , rn ) rn + 1 = 0
for allrl, ... , rn + In this case, the
proof
of theorem 6 of[18,
page17,
rows3-8]
shows that there exists anidempotent
element e ESoc(RC)
such thatCQ
= eRC andf ( xl ,
... , is anidentity
for eRCe . 0PROOF OF THEOREM 2. Consider first the case when
[ f (x1, ... , xn),
is an
identity
for o .By [18, proposition] CQ = eRC
forsome
idempotent
element e E Soc(RC). Moreover, by [7],
theorem2, [f( Xl’
... , is also anidentity
inQR
and so inOQ .
Inparticular
it is anidentity
for~OC
=eRC,
that is[ f ( erl , ... , ern ), 6~+2=0,
for all r1, ... , so, for all rl , ... , 7ern e ), ern + 1 e ]
= 0 . This means thatf(x1, ..., Xn)
is central-valued in eRCe and we are done.Suppose
now that[f( Xl’
... , is not anidentity
for e.As in
proof
of theorem1,
sinceby
lemma 2 R is a GPIring
and so isalso
Q ([1], [6]), Q
is aprimitive ring
with socle H = Soc(Q) #
0[21]
and[/(~i, .... xn + 1 ]
xn + 2 is not anidentity
forQH,
otherwise we havethe contradiction that 9 ... ,
xn ), xn + 1 ] xn + 2
should be anidentity
for Let ..., such that
[ f ( al , ... , an ), an + 1 ] an + 2 ~ ~ .
By
theregularity
ofH,
for all there exists anidempotent
ele-ment g E
()H
such that a = ga , ai for all i =1,
... , n + 2.Moreover, by [19], [(d( f(xl, ... , xn)) - f(x1, ..., xn))m,
xn +1 ]
is anidentity
inQQ,
inQH
and also ingH.
As above we writef(x1,
... ,xn )
=t(xl ,
... ,Xn-1)
Xn ++
h(x1,
... ,xn ),
where t and h are multilinearpolynomials,
xn never ap- pears in any monomialsof t ,
xn never appears as last variable in any mo-nomials of h and let
rl , ... , rn E H,
ThusTherefore, by commuting (1)
with we havethat is
and
by [12] ( 1 - g) d( g) t(gr1,
... ,grn -1) gH .
SincegHg
is asimple
arti-nian
ring
andt( gHg) ~
0 is invariant under the action of all the inner au-tomorphisms
ofgHg , by [8,
lemma2], ( 1 - g ) d( g )
=0,
that isd( g )
==
gd(g)
EgH.
Therefored(gH)
cd(g)
H +gd(H)
cgH
coH
and sod( oH)
Therefore the derivation d induced another one6,
which isdefined in the
prime ring e
where is the left an-nihilator in H of
QH,
and =d(x),
for all x EQH.
Moreover we obviou-sly
have that[ ( d( f ( xl ,
... ,xn)) - f ( x1,
... , xn +1 ]
is a differentialidentity
forQH. By
lemma5,
one of thefollowing
holds: = 0or
f(x1,
... ,xn)
is central-valued inW
orQH
satisfies the standard iden-1_’1__ m , I -- u B
If f ( x1, ... , xn )
is central-valued inC7
weget
the contradiction thatis an
identity
for o . On the otherhand, if 3(gH)
=0,
as in theproof
oftheorem
1,
we have that d is an inner derivation inducedby
an elementb such that
bo
= 0 and for all r1, ... , rn EgH
By commuting (2)
with ... ,rn )
weget
In this case, the main theorem in
[8]
says thatf (r1,
... ,eHb
=0 ,
for all ri,
...,~E~77.
Since H isprime
andb ~ 0 ,
it follows that... ,
rn ) oH = 0 ,
and a fortiori ... ,rn ), rn + 1 ] rn + 2 = o ,
for allr1, ... , rn E
eH,
a contradiction.Finally
we consider the last case whenS4 (XI X4)
is anidentity
for
gH.
In this condition 9 ... ,x4 ) x5
is anidentity
foroH
and so alsofor
QC. By [18, proposition],
there exists anidempotent
element e EE Soc
(RC)
such thatQC
= eRC and soS4 (eRC)
eRC =0,
which meansS4(eRCe)
=0,
asrequired. 0
Acknowledgement.
The author whishes to thank the referee for hishelpfull suggestions.
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