R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
I RVING R EINER Hereditary orders
Rendiconti del Seminario Matematico della Università di Padova, tome 52 (1974), p. 219-225
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Hereditary
IRVING REINER
(*)
1. Class groups.
Throughout
this article let R denote a Dedekind domain with quo- tient field.K,
and let ll be an R-order in aseparable K-algebra
A. Weshall
give
anotherapproach
to some results of Jacobinski[2]
on here-ditary
orders. Asgeneral
references for thebackground
material needed for thisarticle,
the reader is referred to[3]-[5].
A
(left)
A-lattice is a left A-module M which isfinitely generated
and torsionfree as R-module. For each maximal ideal P of
.R,
letI~p, (and
soon)
denote P-adiccompletions.
Two A-latticesM, N
arein the same genus
(notation:
if foreach P, Mp - Np
asllp-
lattices. If we call M
locally free (of
rank1).
Two A-latticesX,
Y are
stably isomorphic
if X+
A(k) I’"’V Y+
A(k) for some k. Let[X]
denote the stable
isomorphism
class of X.The R-order is
hereditary
if every left ideal of l1. isA-projective.
We state without
proof (see references):
(1)
THEOREM. Thefollowing
areequivalent:
i)
!1 ishereditary.
ii) Every
left 11-lattice isprojective.
iii) Every right
A-lattice isprojective.
(*)
Indirizzo dell’A.:University
of Illinois, Urbana, Illinois 61801 U.S.A.This work was
partially supported by
a researchgrant
from the National Science Foundation.220
The
locally free
class group CIA is defined to be the abelian groupgenerated by {[M]:
with additiongiven by
Thus
[M]
= 0 in Cl1J.
if andonly
if If isstably isomorphic
to A.If ~l.’ is a maximal .R-order in
A,
then the class group can becomputed explicitly, especially
when g is analgebraic
numberfield,
or when g is a function field and A satisfies the Eichler condition rela- tive to In these cases, Clll.’ turns out to be a ray class group of the center of A’. Given any order we may find a maximal order A’
in A with It is
obviously
desirable to relate the two class groups Cl A and C1 1.’ .Whether or not .K is a
global field,
each inclusion of orders A c A’gives
rise to a well definedhomomorphism
We now prove
(2)
THEOREM. Let 11. be ahereditary order,
and let ~l’ be any .R- order in Acontaining
11.. Thenfl :
is anisomorphism.
PROOF.
(We
do not assume that ll’ is a maximalorder,
nor that Kis a
global field.)
Given any[X’]
E Cl11.’,
we may assume without loss ofgenerality
that X’ is a A’-lattice in A. Letu(A )
denote the group of units of A. Since for each P we may writefor some
Furthermore, X) = A)
a.e.(«
almosteverywhere »),
so we may choose xp = 1 a. e. Now setThen X is a A-lattice in A such that for all
P,
whenceWe have
ll.’ X = X’,
since this holdslocally
at each P.Then
[X’],
since X ~ This proves thatP
is anepimorphism.
Now let be the set of all .P at which
If then
by
Roiter’s Lemma there is a A-exact sequencewhere T is a left A-module such that
Tp =
0 for all Now A’is a
right A-lattice,
hence isA-projective by
Theorem1,
since 1l. ishereditary.
Therefore the functorA’OA -
is exact.Applying
it to thesequence
(3),
we obtain a A’-exact sequencewhere we have identified
A’(DA X
with1J.’ X.
We claim next that T - T as left A-modules.
Indeed,
bothare R-torsion
modules,
so we needonly
show thatThis is clear when while
for P 0 S
it follows from the fact that This shows thatT,
so(4)
may be rewritten asComparing (3)
and(5)
andusing
SchanueFsLemma,
we obtainNow let
[X]
E kerfl,
so[AX]
= 0 in Thus isstably isomorphic
to1l.’,
so there exists a free A’-lattice F’ such thatIt follows from
(6)
thatSince
!1’ -I- .F’’
is aA-lattice,
and hence isA-projective,
there existsa A-lattice L such that
ll.’ -I- T’’ -E-
L is a free A-lattice.Adding
Lto both sides of
(7),
it follows that X isstably isomorphic
to ll as222
A-lattices. Therefore
[X]
= 0 in ClA.
Thiscompletes
theproof that
is an
isomorphism.
For later use, we
quote
withoutproof
(8)
THEOREM(Jacobinski [1]).
Let K be aglobal field,
and let Abe an
arbitrary
order. If A satisfies the Eichler condition relative to1~,
then[X] = [Y]
in CIA if andonly
if X ~ Y.2.
Endomorphism rings.
For any A-lattice let
EndA M
denote itsA-endomorphism ring.
It is well known that if 11.’ is a maximal R-order in
.A,
and M’ is anyA’-lattice,
then EndA’ is also a maximal order. We now establisha
corresponding
result forhereditary
orders.(9)
THEOREM. Let ll. be ahereditary order,
and let M be any non-zero A-lattice. Then EndA M is a
hereditary
R-order inEndd
K.M~.PROOF. It is clear that EndA M is an R-order in EndA
.glVl,
anywe must show that it is
hereditary.
Since M isA-projective,
we madchoose a
A-lattice
M’ such thatM + M’ ~
for some n. Set .1~ =EndA ~L~n~;
theprojection
map e: A (n) - M is then anidempotent
in the
ring
1~. We haveNow A(n) is a
progenerator
for thecategory
of leftA-modules,
andhence T is Morita
equivalent
to ~1.. But Moritaequivalence
preserves theproperty
ofbeing hereditary,
y sinceby
Theorem1,
an order !1 ishereditary
if andonly
if every submodule of afinitely generated
pro-jective
A-module isA-projective.
It follows that 7" ishereditary,
andit remains to prove that also eFe is
hereditary.
Let L be any left ideal in
ere;
then L c ehec r,
and we can formthe left ideal TL in 7~. Now L is
finitely generated
asere-module,
so there exists a left
ehe-epi.morphism (for
somer)
We may
extend 4p
to a left-P-epimorphism
But is
I’-projective
since .1~ ishereditary,
y and hence there existsa
-V-homomorphisni y’ :
such that 1 on FL. We may writeThen
Also we have
so in
particular
Now define 1p: L
--~ (ehe)~r~ by setting
Each
by (11), and 1p
is a lefteT’e-homomorphism by (10).
We have
This shows
that y splits
theepimorphism cp,
and proves that L is ere-projective.
Hence eFe ishereditary,
y and the theorem is established.3. Restricted genus.
Two A-lattices are in the same restricted genus if M
V N and
for some maximal order A’
containing
A. We shallapply
our
preceding
results to prove thefollowing
result of Jacobinski[2]:
224
(12)
THEOREM. Let 1l. be ahereditary
R-order in theseparable
K-algebra A,
where .g is aglobal
field and whereEnd,
KM sati-fies the Eichler condition relative to R. If
M,
N are A-latticesin the same restricted genus,
then M gz
N.PROOF. Let
!1’
be a maximal ordercontaining ~1.,
such thatLet us set
Then T c
B,
and r’ is a maximal order in theseparable K-algebra
B.The order is
hereditary, by
Theorem 9.Replacing N by
aN for some nonzero ce E.R,
we may assume here- after that N c M. We shall view M as a left~l.-, right
F-bimodule. SetThen J is a left ideal in 1-’. We claim that and that N = MJ.
For each
P,
there is anisomorphism
and hence we may writewhich shows that This also proves that N =
MJ,
since theequality
holdslocally
at all P.Now we observe that
since this holds
locally
at each P. But for somey E u(B),
since Therefore which shows thatthe element
[J]
E Cl 1~ maps onto the zero element of Cl Hence[J] =
0by
Theorem2,
and so J isstably isomorphic
to 1’. ThereforeJ = Tz for s ome z E
u(B) by
Theorem8,
whenceas desired. This
completes
theproof
of the theorem.REFERENCES
[1]
H. JACOBINSKI, Genera anddecomposition of
lattices over orders, Acta Math., 121 (1968), 1-29.[2] H. JACOBINSKI, Two remarks about
hereditary
orders, Proc. Amer. Math.Soc., 28
(1971),
1-8.[3] I. REINER, Maximal orders, London Math. Soc.
Monographs,
Academic Press, London 1975.[4] K. W. ROGGENKAMP, Lattices over orders, II, Lecture notes 142,
Springer- Verlag,
Berlin 1970.[5]
R. G. SWAN - E. G. EVANS,K-theory of finite
groups and orders, Lecture notes 149,Springer-Verlag,
Berlin 1970.Manoscritto