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Z

k1l

3 Z

2

-Graded Polynomial Identities for M

k,l

(E) 7 E.

ONOFRIO MARIO DI VINCENZO(*) - VINCENZO NARDOZZA(**)

ABSTRACT- LetKbe a field of characteristic zero, andEbe the Grassmann alge- bra over an infinite-dimensionalK-vector space. We endowMk,l(E)7Ewith aZk1l3Z2-grading, and determine a generating set for the ideal of its grad- ed polynomial identities. As a consequence, we prove that Mk,l(E)7Eand Mk1l(E) are PI-equivalent with respect to this grading. In particular, this leads to their ordinary PI-equivalence, a classical result obtained by Kemer.

1. Introduction.

LetKbe a field of characteristic zero, andEbe the Grassmann alge- bra over an infinite-dimensional K-vector space. For fixed integers k,l (kFl) we consider the K-algebra Mk,l(E), whose elements are the fol- lowing block matrices with entries in the even and odd part ofE, resp.

E0 and E1:

g

EE01 EE10

h

k l

N

k

N

l

l l l

As follows by the results of Kemer [K], these algebras generate non- trivial prime varieties, and their study is essential in the theory of PI-al- gebras. SinceMk,l(E) is a subalgebra ofMk1l(E), the following inclusion

(*) Indirizzo dell’A.: Dipartimento Interuniversitario di Matematica, via Orabona 4, 70125 Bari, Italia; e-mail: divincenzoHdm.uniba.it

(**) Indirizzo dell’A.: Dipartimento di Matematica, c.da Macchia Romana, 85100 Potenza, Italia; e-mail: vickkkHtiscalinet.it

Partially supported by MURST COFIN ’99.

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for the ideals of polynomial identities follows: T(Mk,l(E) )*T(Mk1l(E) ).

It is somehow surprising that to get a PI-equivalence with Mk1l(E) it suffices to consider the tensor product Mk,l(E)7E, regardless to k,l, i.e. theT-ideals of the polynomial identities of these algebras are equal.

Originally, this fact was proved by Kemer in [K1] as a consequence of his structure theory for varieties of algebras. Other proofs are in the papers of Regev [R] and Berele [B]. In this paper, we shall studyMk,l(E)7Eas a graded algebra. Recall briefly that, for a given groupG, aK-algebraR isG-graded if, for eachgG, there is a subspaceRgofR(theg-homoge- neous component of R) such that

R4

!

gG

Rg and RgRhRg1h for all g,hG.

We shall write¯G(r)4g(or simply¯(r)4gifGis clear from the con- text) to denote theG-homogeneous degree of the homogeneous element rRg.

The study of graded algebras is almost a standard approach in many problems of PI-theory, and many algebras have natural grading which enrich them with nice structure properties. The algebras Mn(K), Mk,l(E), Mn(E), for instance, are Z2-graded algebras in a natural way.

Before getting into details in the next section, we briefly recall some terminology:

LetGbe a group; for eachgGletXgbe a countable set of non-com- muting variables, and let XG be their disjoint union. Then the algebra KaXGb is a free object in the class of G-graded algebras. A polynomial f4f(x1g1,R,xrgr) with variablesxigiXgiis a graded polynomial identity for R if for all substitutions xigi

KaiRgi (i41 ,R,r) it results f(a1,R,ar)40 . The set of all graded polynomial identities for R is an ideal of KaXGbinvariant under all endomorphisms of KaXGbpreserving the homogeneous components; we call it theTG-ideal ofR, and denote it by TG(R). Now call:

VrG»4spanKaxs( 1 )g1 Rxs(r)gr NsSr,g1,R,grGb.

We callVrG the space of graded multilinear polynomials, and it is easily seen that the usual left action ofSr endowsVrGwith the structure of left Sr-module as in the ordinary case. Moreover, since the fieldKis of char- acteristic zero, standard arguments yield thatTG(R) is generated by its multilinear parts, i.e. by the Sr-submodules VrGOTG(R) for all rN. There are many more examples of these and other concepts related to

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graded algebras; for shortness, we introduce those who are related to this paper. The first is the natural Zn-grading for the algebra Mn(K):

(Mn(K) )t»4spanKaeijNj2i4tZnb.

Vasilovsky in [V] proved that itsTZn-ideal is generated by the following multilinear polynomials:

[x10,x20] x1tx2tx2t2x2tx2tx1t (tZn).

The second instance is about the algebra Mn(E)`Mn(K)7E, which has the natural Zn3Z2-grading

(Mn(E) )(t,l)»4Mn(K)t7El

where the first component is thet-homogeneous component ofMn(K) in the previous grading forMn(K). The authors in [DVN] found a system of generators for the TZn3Z2-ideal of its graded polynomial identities.

In this paper, for n4k1l, we define a Zn3Z2-grading for Mk,l(E)7E and describe a set of generators forTZn3Z2(Mk,l(E)7E).

In particular it turns out that this set generatesTZn3Z2(Mn(E) ) as well.

Hence Mk,l(E)7E and Mn(E) are equivalent as graded PI-algebras.

General arguments lead to their ordinary PI-equivalence, and we obtain a new proof for the mentioned result of Kemer, using only elementary tools.

2. Preliminaries.

Consider the K-algebra Mk,l(E), and let n»4k1l in the following.

We may start from the naturalZn-grading onMn(K) in order to endow Mk,l(E) with the following Zn3Z2-grading:

(Mk,l(E) )(t,l)»4spanKaEleijNj2i4tZnb OMk,l(E).

Of course some of the graded components may be trivial (for instance, (Mk,l(E) )( 0 , 1 )40). It is easy to verify, however, that this is actually a grading for Mk,l(E). Next, consider Mk,l(E)7E and define

(Mk,l(E)7E)(t,l)»4(Mk,l(E) )(t,l)7E05(Mk,l(E) )(t,l11 )7E1. ThenMk,l(E)7EisZn3Z2-graded, and we shall prove that it is PI-

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equivalent to the algebra Mn(E) with the Zn3Z2-grading (Mn(E) )(t,l)4spanKaeij7ElNj2i4tZnb.

In order to have a clearer view of the problem, the following consid- erations are useful:

DEFINITION 2.1. Let e:]1 ,R,n( 3 ]1 ,R,n( KZ2 be the map defined via

e(i,j)»4./

´ 0 1

if i,jGk or i,jDk otherwise .

Moreover, letE0be the naturalK-basis forE0, andE1be the correspond- ing basis for E1.

It is immediate to see that

A»4 ]aeijNi,jGn, aEe(i,j)( is a K-basis for Mk,l(E), and

B»4 ]aeij7bNi,jGn, aEe(i,j), bEl(

is a K-basis for Mk,l(E)7E. Moreover, writing al as a shorthand for aEl, it holds:

(Mk,l(E) )(t,l)4spanKaae(i,j)eijNj2i4tZn, e(i,j)4lb and

(Mk,l(E)7E)(t,l)4spanKaae(i,j)eij7bl1e(i,j)Nj2i4tZnb. By use of these definitions, the fact that Mk,l(E)7E is a Zn3Z2- graded algebra follows easily. By the way, we find useful to remark a couple of lemmas which will be of help in the following of this part.

LEMMA 2.2. Let

As»4ase(is,js)eisjs7bsls1e(is,js)B for s41 , 2 . If A1A2 is not zero, then there exists c]1 ,21( such that

cA1A2B.

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In particular it holds:

j14i2; e(i1,j1)1e(i2, j2)4e(i1,j2); ¯(A1A2)4(j22i1,l11l2) . PROOF. Suppose A1A2c0 and look ate(i1,j1)»4e1and e(i2,j2)»4 e2. Ife14e241 , we know thati1andj14i2are by opposite side with re- spect tokand this forces thatj2andi1are by the same side with respect tok, so e(i1, j2)404e11e2. Apply the same argument for the other cases to gete11e24e(i1, j2). Then, say Vthe infinite-dimensional vec- tor space which generates the Grassmann algebra E, and say

a14vl1Rvlr and a24vm1Rvmt

wherevl1,R,vlr,vm1,R,vmt are pairwise-distinct vectors in an ordered basis for V since A1A2c0 , with vl1Evl2EREvlh and vm1Evm2ERE Evmt. Then we may rearrange the entries in the worda1a2and obtain an element of Ee11e2 which is equal to a1a2up to its sign. The same argu- ments apply to theb’s, and using the first part of this Lemma we get the result. r

DEFINITION 2.3. Let m be a monomial in VrZn3Z2, and let S:(A1,A2,R,Ar) be the substitutionxiKAi(i41 ,R,r). We say that S is a standard substitution if

i) ¯(xi)4¯(Ai) for each xi occurring in m; ii) AiB for each i.

Since charK40 , the graded polynomial identities of TZn3Z2(Mk,l(E)7E) are determined by the multilinear ones, i.e. by the spaces

VrZn3Z2OTZn3Z2(Mk,l(E)7E) for all rN.

Actually, it suffices to prove that a multilinear polynomial is zero un- der all standard substitutions in order to prove that it is a graded poly- nomial identity. In the next considerations, the following Lemma is use- ful. Its proof can be found in ([V], Lemma 1), and we shall omit it here.

LEMMA 2.4. Let ei1j1,eij,ei2j2Mn(K) be elementary matrices with Zn-degrees

¯Zn(ei1j1)4¯Zn(ei2j2)4 2¯Zn(eij) .

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Then

ei1j1eijei2j2c0 if and only if i14j4i2 and j14i4j2. If this is the case, it holds: ei1j1eijei2j24ei2j2eijei1j1.

DEFINITION 2.5. LetI be the following set of multilinear polynomials:

[x1( 0 , 0 ),x2( 0 , 0 )] [x1( 0 , 1 ),x2( 0 , 0 )] x1( 0 , 1 ) ix2( 0 , 1 )

x1(t, 0 )x(2t, 0 )x2(t, 0 )2x2(t, 0 )x(2t, 0 )x1(t, 0 ) x1(t, 1 )x(2t, 0 )x2(t, 0 )2x2(t, 0 )x(2t, 0 )x1(t, 1 ) x1(t, 0 )x(2t, 1 )x2(t, 0 )2x2(t, 0 )x(2t, 1 )x1(t, 0 ) x1(t, 1 )x(2t, 0 )x2(t, 1 )1x2(t, 1 )x(2t, 0 )x1(t, 1 ) x1(t, 1 )

x(2t, 1 )x2(t, 0 )

1x2(t, 0 )

x(2t, 1 )x1(t, 1 )

x1(t, 1 )

x(2t, 1 )x2(t, 1 )

1x2(t, 1 )

x(2t, 1 )x1(t, 1 )

wheretvaries inZnandaibdenotes the Jordan productaib4ab1ba. We shall denote by I the TZn3Z2-ideal generated by I.

PROPOSITION 2.6.

I’TZn3Z2(Mk,l(E)7E) .

PROOF. It is enough to test polynomials listed in Definition 2 under standard substitutions, and verify they are zero for each such substitu- tions. The generic standard substitution for 3-degree polynomials will be

A14a1e(i1,j1)ei1j17b1l11e(i1,j1) A24a2e(i2,j2)ei2j27b2l21e(i2,j2)

A4ae(i,j)eij7bl1e(i, j)

for j12i14j22i24i2j4tZn. By Lemma 2.4, the products ei1j1eijei2j2 and ei2j2eijei1j1 are both zero unless

i14i24j and j14j24i

and in this case they are equal (to eji) and e(i1,j1)4e(i2,j2)4e(i,j) 4:e. So the substitutions we have to test are of kind

A14a1eeji7b1l11e A24a2eeji7b2l21e A4aeeij7bl1e ( for i2j4t) .

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Here we verify just one of them, the other ones can be treated in the same way. For instance, consider x1(t, 1 )x(2t, 1 )x2(t, 0 )1x2(t, 0 )x(2t, 1 )x1(t, 1 ): l14l41 , l240 . If e40 , then

A2AA14a20a0a10eji7b20b1b114 2A1AA2 and if e41 , then

A2AA14a21a1a11eji7b21b0b10

4 2A1AA2.

The same arguments and the use of Lemma 2.2 yield that the polynomi- als of second degree in the list are graded identities forMk,l(E)7E as well. r

In the rest of the section, let m»4x1Rxr be a multilinear graded monomial of length r. If sSr, we denote by ms the monomial xs( 1 )Rxs(r). IfSis any (graded) substitution, we denote bymNSthe value of m under the substitution S.

REMARK 2.7. For each sSrthere exists a graded standard substi- tution S such that

msNSc0 .

This is easy to prove, for instance using induction on the length r.

DEFINITION 2.8. For 1GpGqGr, call ms[p,q]»4xs(p)Rxs(q).

REMARK 2.9. Let S be a standard substitution, and fix from now on S:xsKAs»4ase(is,js)eisjs7bsls1e(is, js) (s41 ,R,r) ,

where ¯(xs)4(js2is,ls)4¯(As). If

msNS4As( 1 )RAs(r)c0

then there exists AB, c]1 ,21( such that msNS4cA. Moreover, msNSc0 if and only if (p,q 1GpGqGrit isms[p,q]NSc0 , and in this case it holds

¯(ms[p,q])4(js(q)2is(p),ls(p)1R1ls(q)) .

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In fact it is:

¯(ms[p,q])4¯(xs(p))1R1¯(xs(q))4

4(js(p)2is(p),ls(p))1R1(js(q)2is(q),ls(q))4 4(js(q)2is(p),ls(p)1R1ls(q))

by Lemma 2.2.

3. Technical results.

The considerations in this (and the next) section are similar to those in [V]. We start with rearranging a lemma. The symbols used are the same listed in the previous section. We recall thatIdenotes theTZn3Z2- ideal generated by the polynomials listed in Definition 2.5.

LEMMA 3.1. Suppose that for a graded standard substitution S it results

msNS4 6mNSc0 . Then there exists c]1 ,21( such that

msfcx1m8(x2,R,xr) modI.

PROOF. First of all, note thatmsNS4 6mNSc0 implies thati14is( 1 ). Of course, we may supposes( 1 )c1 , so 1Es21( 1 ). We may write the in- tegers in [ 1 ,s21( 1 ) ] in the form s21(j11 ) for j40 ,R,r21; then call

t»4min]jGr21N1Gs21(j11 )Es21( 1 )(.

By its definitions, t satisfies 1Gs21(t11 )Es21( 1 )Gs21(t); set p»4s21(t11 ) q»4s21( 1 ) u»4s21(t)

and consider the two possibilities: p41 or pD1 . For convenience, define

ls[a,b]»4ls(a)1R1ls(b).

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First, suppose p41 . By Lemma 2.9, it results

¯(ms[ 1 ,q21 ])4(js(q21 )2is( 1 ),l[ 1 ,s q21 ])

¯(ms[q,u])4(js(u)2is(q),l[q,s u])

and both the words are not zero under the substitutionS; by Lemma 2.9 this yields

js(q21 )2is( 1 ) js(u)2is(q)

4is(q)2i14i12i140

4jt2i14it112i14is(p)2i14is( 1 )2i14i12i140 . With respect to the parities of ls[ 1 ,q21 ] and l[q,s u] there is c]1 ,21( such that

x1( 0 ,ls[ 1 ,q21 ])

x2( 0 ,ls[q,u])fcx2( 0 ,l[q,s u])x1( 0 ,l[ 1 ,s q21 ])modI. Hence we get

msfcms[q,u]ms[ 1 ,q21 ]ms[u11 ,r]modI,

andms[q,u] starts with x1. Now consider the case pD0; with considera- tion similar to the previous case, it is

¯(ms[ 1 ,p21 ])4(js(p21 )2is( 1 ),ls( 1 )1R1ls(p21 ))

¯(ms[p,q21 ])4(js(q21 )2is(p),ls(p)1R1ls(q21 ))

¯(ms[q,u])4(js(u)2is(q),ls(q)1R1ls(u)) . Call

d»4 . /

´

it112i1 it112ii1n

if it112i1F1 if it112i1E1 . Then it holds that:

js(p21 )2is( 1 )4is(p)2i14it112i1fdmodn js(q21 )2is(p)4is(q)2is(p)4i12it11f2dmodn

js(u)2is(q)4jt2i14it112i1fdmodn. As before, there is c]1 ,21( such that

x1(d,l[ 1 ,s p21 ])

x(2d,l[p,s q21 ])x2(d,ls[q,u])fcx2(d,l[q,u]s )

x(2d,l[p,s q21 ])x1(d,l[ 1 ,s p21 ])

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modulo I; then

msfcms[q,u]ms[p,q21 ]ms[ 1 ,p21 ]ms[u11 ,r]modI and this monomial starts with x1. r

LEMMA 3.2. With the same notation as in the previous Lemma, if for a standard substitution S it holds

msNS4cmNSc0 , for a certain c]1 ,21(, then

msfcmmodI.

PROOF. Let s be the greatest positive integer such that msfc0x1Rxsm8(xs11,R,xr) modI

for a certainc0]1 ,21(. By Lemma 3.1, the numbersdoes exist and it is at least 1 . We want to show thats4r. Suppose on the contrary that 1GsEr, so that sGr22 . It holds

x1Rxsm8(xs11,R,xr)NS4 6msNS4 6mNSc0 .

Now comparem8 NSandxs11RxrNS. If we consider only the elementary matrices which occur in S, it has to be true that

ei1j1Reisjsm8(eis

11js11,R,eirjr)4ei1j1Reisjs(eis

11js11Reirjr)c0 so

ei1jsm8(eis11js11,R,eirjr)4ei1jseis11jrc0 . Thenm8(eis

11js11,R,eirjr) has to be an elementary matrix, sayepq, and this leads to p4js and q4jr, so we get

m8(eis11js11,R,eirjr)4eis11js11Reirjrc0 . Therefore the restriction S8 of S to t4s11 ,R,r is such that

m8(xs11,R,xr)NS84 6(xs11Rxr)NS8c0

and by Lemma 3.1 this yields that there exists c8]1 ,21( such that

m8fc8xs11m9(xs12,R,xr) modI.

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Then

msfc0c8x1Rxsxs11m9(xs12,R,xr) modI

which contradicts the definition of s. Now it follows easily that c04c. r

COROLLARY 3.3. Lets,tbe in Sr,and suppose that for a standard substitution S it results

msNS4cmtNSc0 for a certain c]1 ,21(. Then

msfcmtmodI.

4. The main results.

THEOREM 4.1. Let n4k1l.Then the set I described in Definition 2.5 generates TZn3Z2(Mk,l(E)7E), that is

I4TZn3Z2(Mk,l(E)7E) .

PROOF. By Proposition 2.6 we have to prove only that every multilin- ear graded identity forMk,l(E)7Eis inI. Suppose on the contrary that there exists a polynomial

f4f(x1,R,xr)VrZn3Z2OTZn3Z2(Mk,l(E)7E) which is not in I. Then we may write

ff

!

s41 t

dssmssmodI

for some monomials mssVrZn3Z2, ssSr, non-zero scalars 0cdsK ands41 ,R,t. Taketminimal with this property (of course,tshould be at least 2 by Remark 2.7): we want to prove that t40 .

By Remark 2.7 there exists a graded standard substitution S such that ms1NSc0 . Since f is an identity for Mk,l(E)7E it is fNS40 . Hence

ds1ms1NS4 2

!

s42 t

dssmssNS.

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As in Remark 2.9, there exists AB such that 0cms1NS4c1A for some c1]1 ,21(. Hence there must be p]2 ,R,t( such that

0cmspNS4c2A for some c2]1 ,21(. Then

0cms1NS4c1c2mspNS, and applying Corollary 3.3 we get

mspfcms1modI for c4c1c2. In the end, it is

ff(ds11cdsp)ms11

!

s42 ,scp t

dssmssmodI contradicting the minimality of t. r

Now we recall the main result in [DVN]:

THEOREM 4.2. TZn3Z2(Mn(E) ) is generated by the polynomials in I. As a corollary of Theorems 4.1 and 4.2 we get

COROLLARY 4.3. The algebras Mk,l(E)7E and Mn(E) are PI- equivalent as Zn3Z2-graded algebras.

Then it follows

COROLLARY 4.4. For n4k1l, the algebras Mk,l(E)7E and Mn(E) are PI-equivalent.

PROOF What we have to show is that the multilinear parts of the or- dinaryT-idealsT(Mk,l(E)7E) andT(Mn(E) ) are equal. Note that each of them is a subset of the corresponding TZn3Z2-ideal.

So take fVrOT(Mn(E) ). Then it suffices to prove that fNS40 for any ordinary standard substitution, i.e. for every substitution

S:xiKAi, (i41 ,R,r) such that A1,R,ArB.

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Let S be a ordinary standard substitution with elements in B, and define

fA»4f(x1¯(A1),R,xr¯(Ar))VrZn3Z2.

fA is a multilinear graded element in TZn3Z2(Mn(E) )4 TZn3Z2(Mk,l(E)7E), and the substitution Sis admissible for this poly- nomial. HencefNS4fA

NS40 and this means thatfT(Mk,l(E)7E). Re- versing the roles ofT(Mn(E) ) and T(Mk,l(E)7E) leads to the reverse inclusion. r

R E F E R E N C E S

[B] A. BERELE, Supertraces and matrices over Grassmann algebras, Ad- vances in Math.,108 (1) (1994), pp. 77-90.

[DVN] O. M. DIVINCENZO- V. NARDOZZA,Graded polynomial identities for ten- sor products by the Grassmann Algebra, Comm. Algebra (2002) (in press).

[K] A. R. KEMER, Varieties and Z2-graded algebras, Math. USSR Izv.,25 (1985), pp. 359-374.

[K1] A. R. KEMER,Ideals of identities of associative algebras, AMS Trans. of Math. Monographs, 87 (1991).

[R] A. REGEV,Tensor product of matrix algebras over the Grassmann alge- bra, J. Algebra, 133(1990), pp. 351-369.

[V] S. Y. VASILOVSKY,Zn-graded polynomial identities of the full matrix al- gebra of order n, Proc. Amer. Math. Soc., 127 (12) (1999), pp. 3517- 3524.

Manoscritto pervenuto in redazione il 14 dicembre 2001.

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