R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
U. Z ANNIER
An effective solution of a certain diophantine problem
Rendiconti del Seminario Matematico della Università di Padova, tome 93 (1995), p. 177-183
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of
aCertain Diophantine Problem.
U.
ZANNIER (*)
Introduction.
Consider the
following diophantine question:
Let f(X, Y)
EK[X, Y],
where K is a numberfield
withring of
inte-gers D. Determine the set ,S =
Sf
=Sf,
K= I mE
D :f(m, Y) splits
intolinear
factors
overK ~.
’
A celebrated theorem of
Siegel immediately implies that,
if thesplitting
field £of f over K(X )
haspositive
genus, then S is finite. Actu-ally,
even if no effective version of thegeneral Siegel’s
theorem is known atpresent,
it follows from work of Belotserkovski[3]
that onecan
effectively
determine S(which
isessentially equivalent
to an effec-tive
Siegel’s
theorem on theintegral points
of a Galoiscovering
of theprojective
line. See also theAppendix
in[5]
for aproof).
The purpose ofthis brief note is to
complete
suchanalysis
with an effectivedescription
of ,S in the easier case when 2: has genus zero. We remark that
Siegel
himself gave a
good description
of theintegral points
for thegeneral equation
of genus zero, which moreover can now be made effective.Nevertheless some additional
information, compared
to thegeneral
case, is
gained by looking
at the abovequestion.
We may
clearly assume f to
be irreducible over K. Let d *= degyf Define K
as thealgebraic
closure of K in~,
G as the Galois group of 2:over
k(X)
and let d be the order of G. We shall prove the follow-ing
(*) Indirizzo dell’A.: D.S.T.R., S. Croce 191, 30135 Venezia
(Italy).
E-mail: [email protected].
178
THEOREM. Assume has genus zero. Then one may deter- mine whether S is
finite (in
which case its elements may befound),
ornot.
If not, then k = K
and G iscyclic
or dihedralaccording
as X hasone or two
poles in 1;.
In thefirst
case K contains aprimitive
d-th rootof unity.
Otherwise aprimitive (d/2)-th
rootof
1 is either in K orquadratic
over K. Moreover there arecomputable explicit parametric formulae for
the elementsof
,S(given by (5), (8), ( 11 ) below).
In the
proof
we shall use the factthat, given
a curve C defined overK,
of genus0,
it iseffectively possible
to establish whether there existsa K-rational
point (1)
on it(by
Hasseprinciple
forinstance) and,
in the affirmative case, toproduce
one suchpoint.
Even if this is wellknown,
for the sake of
completeness
we recall verybriefly
onepossible
method.For a a
divisor,
letV(a)
be the vector space of rational functionsf
suchthat div
( f ) ~
a. The divisor 8 of a nonzero K-rational differential on thecurve is of
degree - 2,
so,by Riemann-Roch, V(a)
has dimension 3. Letf,
g,h)
be a basis forV(e) (Coates algorithm-see [4]-guarantees
theeffectivity
of suchprocedure).
Then the functionsg 2 , gh, h 2
lie in
V(2~) which, by
Riemann-Rochagain,
has dimension 5. A non-trivial linear relation among such six functions
gives
a model for C as aconic in
p2 which,
after achange
ofvariables,
may be assumed to be of the formY’ - aX2
=cZ~
where a, c E K *(2).
Rationalpoints
thusgive
nontrivial solutions in D of such
equation
and exist iff c is a relativenorm from
K(yfa)
to K.(We
may exclude the trivial case a EK*2.)
Take any nontrivial solution
(X, Y, Z)
ED 3.
It is easy to see(using
the finiteness of the class
number)
that thegreatest
common ideal divi-sor of
X,
Y may be assumed to divide a fixed ideal.Consider then the ideal factorization of Y +
xyfa
in thering
of inte-gers of
By
the above remark( Y
+ =IJ2
where I is anideal in a finite set
depending
on c. Choose an ideal J * in the class of J andhaving
bounded absolute norm.Then,
set(Y* + X * ~) = IJ *2,
(t) = J -1 J *.
We have thatIJ *2
has bounded absolute norm, whenceY* ,
X* may be chosen to have boundedheight,
while t EAlso,
as fractional
ideals,
whence Y* ++ X*
( Y
+where g
is a unit from a finite set(in fact,
thegroup of units is
finitely generated,
and the squares of units may be ab- sorbed int *2). Taking
norms N from to K weget N((Y*
++ X * =
cU2,
whereU = ZN(t * ) E K.
SinceY*, X*, p.
have(1)
Here and in thesequel by point
on a curve we mean apoint
on the nonsin-gular
model of it.(2)
This result goes back to Hurwitz.bounded
height,
both(Y*
+ and U have boundedheight too,
whence ouroriginal equation
has solutions whoseheight
may beexplic- itly bounded, proving
the above contention.Having possibly
found such a K-rationalpoint
P we may take(after
Coates
algorithm)
a nonconstant function t inV( -- P).
Then the function fieldK( C) equals K( t )
and we mayeffectively
write anygiven
functionf E K(C)
in the forma(t),
a eK(t).
PROOF OF THEOREM. We first
show, by
means of a familiar trickthat,
ifK ~ K,
then S is fmite andcomputable.
Let z be a
primitive
element for 2: overK(X)
of the form z cl y, + + ... +(where
ci E K * andthe yi
are the rootsoff(X, Y) = 0)
andlet
H(X, Z)
= 0 be a minimalequation
overK(X),
irreducible overK[XI.
Since theconjugates
of z overK(X)
are linear forms in yl , ... , yd*with coefficients in
K,
we seethat,
if m e,Sf then H(m, Z) splits
intolinear factors over K. Now it is well known that K ~ K if and
only
ifH(X, Z)
is notabsolutely
irreducible. Assume this is the case, letL(X, Z)
be anabsolutely
irreducible factor withalgebraic coefficients,
and write
where
the ti
arealgebraic
numberslinearly independent
over K whileLi
EK[X, Z]
for all i.If the
Li
have a common factorQ,
this dividesL,
whence L =gQ
forsome
algebraic
number g.Also,
we mayclearly
assumeQ
EK[X, Z],
so,
since Q
dividesH,
which is irreducible overK,
we would have H == vL for some
algebraic
number v and H would beabsolutely
irre-ducible.
So the
polynomials Li
arecoprime,
whence anequation
where Bi
eK[X, Z]
for all i while C is a nonzeropolynomial
with coeffi- cients in K.Now,
if m E K and theequation L(m, Z)
= 0 has asolution ~
EK, then,
in view of(1)
and theindependence
ofthe ti
over K we haveLi (m, ~) = 0
forall i,
so, from(2), C(m)
= 0. Since C iscomputable
theproof
of the above contention iscompleted,
i.e. we may assume that K isalgebraically
closed in ~.According
to the remarks before theproof,
either 2: has no rationalnonsingular points,
whence S is finite andcomputable (as
a subset ofthe
singular
set of theplane
curve determinedby
the minimalpolyno-
180
mial for a
primitive
element z asabove),
or we maycompute
aparametrization
where 2: =
K(t).
Also,
there areparametrizations y2 = bi ( t ),
wherebi
EK( t ),
i ==
1,
... , d *. SinceK(X,
yl , ... ,yd* )
= 1: =K(t),
we have a relationwhere R is a rational function in its
arguments
with coefficients in K. Inparticular
this shows that if the values of X andthe yi
are defined atto,
then
they
all lie in K if andonly
ifto
E K.If the rational function a has at least three distinct
poles then,
as ex-plained
in[6],
Ch.8, § 5,
values of t in K such that X E D lead to a finite number of(computable)
Thueequations
to be solved inD,
so,by
Bak-er’s results
(see [1],
Ch.4,
Thm.4.1),
there arefinitely
many solutions which can be found.So,
assume that a has at most two distinctpoles.
The Galois group G has
clearly
a realization as a finite group of lin-’
ear fractional transformations on t.
(The
structure of such groups is well known: G may be eithercyclic,
dihedral or one of threesporadic
groups. See
[2]
fordetails.)
Moreover the action of G leaves the rational function a fixed andpermutes the bi
so we see from(4)
that the coeffi- cients of such tranformations may be assumed to lie in K.Now,
if a E G and 7r E C U 00 is apole
of a, we have is apole
of a, whence the orbit of 7r under the action of G contains one or two elements.
Suppose
first X hasonly
onepole, corresponding
to t = 7r. Then 7r iscertainly
in KU oo,
so,replacing eventually t
with n + we may as-sume that 7r = 00. In
particular a( t )
in(12)
is apolynomial. Also,
G sta-bilizes 00 and thus consists of tranformations of
type pt
+9.
This im-plies
that G iscyclic (the
mappt + ~
- p is anisomorphism
of G onto afinite
subgroup
ofK *). Finally
it iseasily
seenthat,
after a suitableK-translation on
t,
we may assume that G isgenerated by
a transfor-mation t -
Ct, where C
E K.Necessarily C
is aprimitive
d-th root of 1.The
degree
of thepolynomial a(t) is, by (3),
thedegree
of t overK(X),
whichequals
dby
definition. On the other hand a is invariant un- der the action of G so,by
theabove,
a EK[td ]
whencewhere a, b E K.
Now we see that m E S if and
only
if m =ar d+
b for a suitableT E K. It remains so to
classify
the -r E K such that + b E D. It is clear that the denominator of z must bebounded,
so we reduce to let zvary over
finitely
many sets of the where~
are fixed com-putable
elements of Kand IA
runs over D. Further + b E D if andonly if g
lies in certain congruence classes modulo a certain ideal J of Ddepending
ona, b,
~. In conclusion S is the union of a finite set withfinitely
many sets of the formfor
computable a i E K, Y i E D
and idealsJi
c D.Suppose
now that X hasprecisely
two distinctpoles corresponding
to t = 7r1 and t = ~c2. Observe that 7~1, ~2 either lie both in K U 00 or are
conjugate
numbers in aquadratic
extension. Put K’ = Consider the transformationWe may use = u, say, as a variable in
place
of t. In terms of thisvariable we have
and now the
poles
of Xcorrespond
to u =0, 00
while G isreplaced by
G * = as a group of linear fractional transformations on u.
Since the action of the Galois group is transitive on the
places
abovea
given
one, some element of G *(necessarily
of the form u --*b/u)
per- mutes theplaces u
= 0 and u = 00, so the stabilizer of 00 in G * has in- dex 2. It follows also that G is dihedral of order d = 2d’ and thatfor some b E K’. In
particular
K’ contains aprimitive
d’-th root of1,
say "1’).
(From
the above formula for r it follows alsothat,
ifK’ ~ K,
thenthe nontrivial
automorphism
of K’ over K acts ascomplex conjugation
on
"1’).)
-We have
for some
polynomial satisfying f(O)
= 0 and d =deg f >
m.Also,
since a * is invariant under the action of G * we obtain that182
, whence
where
the f
lie in K’.Actually,
since a EK(t)
and n1 and 7t2 either lie inK or are
conjugate quadratic,
one obtains from(6)
and(8)
that in factfo
EK, while f1
andf_ 1,
if not inK,
areconjugate
in K’.From
(8)
it followsthat,
if u e K’ is such that X = a *(u)
is analge-
braic
integer,
then the fractional idealgenerated by u
inD ’,
thering
ofintegers
ofK’,
hasfinitely
manycomputable possibilities,
sowhere a runs
through
a finitecomputable
set and v is a unit in D’.Starting
from(9),
the necessary and sufficient condition for(8)
to bean
algebraic integer
amounts to a congruence condition on vwhich,
inview of Dirichlet’s
Theorem,
is satisfied for all v in suitable cosets of the full unit group modulo asubgroup
V of finite index whose genera- tors may becomputed.
So X E D’ iffwhere B
runsthrough
a finitecomputable
set while w E V.We have still to
exploit
the conditionX E K,
in case K’ ~ K. This isequivalent
to t E Kwhich, by
the above formulas amounts to uic = 1 where the tilde denotesconjugation
in K’ over K. From(10)
we thusget
This is satisfied
precisely
when w lies in a certain set(possibly
emp-ty)
of cosets of V modulo itssubgroup
Wconsisting
of elements whoserelative norm to K is 1.
(We
remark that one may findgenerators
forW.)
Finally
we have that Z e D if andonly
ifwhere y
lies in a finitecomputable
set while z E W.REMARK. It follows from the
proof
that the setSf, x,
differsby
a fi-nite set from a set of the
form Sg,K’
where eitherg(X, Y) _ «Yd + p
+ Xand K’ = K or
g(X, Y) = aY2d
+ +y)Yd’
+ ~ and[K’ : K]
2.REFERENCES
[1] A. BAKER, Transcendental Number
Theory, Cambridge
Univ. Press, Cam-bridge
(1976).[2] F. BALDASSARRI - B. DWORK, On second order linear
differential equations
with
algebraic
solutions, Amer. J. Math., 101 (1979), pp. 42-75.[3] Yu. BELOTSERKOVSKI (BILU),
Effective analysis of
a new classof Diophan-
tine
equations
(Russian), Vestsi Akad. Navuk BSSR, Ser. Fiz.-Math.Navuk, (1988), no. 3, pp. 111-115 (Math. Rew. 89i:11038).
[4] J. COATES, Construction
of
rationalfunctions
on a curve, Proc. Camb. Phil.Soc., 68 (1970), pp. 105-123.
[5] R. DVORNICICH - U. ZANNIER, Fields
containing
valuesof algebraic func- tions (3),
Annali Sc. Norm.Sup.
Cl. Sci. Serie IV, Vol. XXI, Fasc. 3 (1994).[6] S. LANG, Fundamentals
of Diophantine Geometry, Springer-Verlag
(1983).(3)
Aprevious
version of this paperappeared,
without theAppendix, already
in 1982 under the same title as a
preprint
of theUniversity
of Pisa.Manoscritto pervenuto in redazione il 30
giugno
1993e, in forma revisionata, il 12 ottobre 1993.