S ÉMINAIRE N. B OURBAKI
E NRICO B OMBIERI
Simultaneous approximations of algebraic numbers
Séminaire N. Bourbaki, 1973, exp. n
o400, p. 1-20
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400-01
SIMULTANEOUS APPROXIMATIONS OF ALGEBRAIC NUMBERS
[following
W. M.SCHMIDT]
by
Enrico BOMBIERI Seminaire BOURBAKI24e
annee, 1971/72,
n° 400 Novembre 1971I. Let
a~ , a2 ’
,...,~yn
be real numbers. Dirichlet’ s theorem inDiophantine Approximation
states thatTHEOREM
(Dirichlet).-
For every N z 1 there is q, 1 : q sN ,
such thatWhere )) ))
denotes the distance from the nearestinteger.
COROLLARY.- Let
1 , a~ , ,...,a n
be realnumbers, linearly independent over (p
. Then there areinfinitely
manyintegers
q such thatIn
1955,
afterprevious
workby Thue, Siegel, Dyson,
Gel’fond and Schneider it wasproved by
Roth thatROTH’S THEOREM.- Let a be irrational
algebraic
and let e > 0 . There areonly finitely
manyintegers
q such thatNow Rbth’s theorem has been
generalized by
W. M. Schmidt to the case of simul- taneousapproximations.
SCHMIDT’S THEOREM 1.- Let 1
, a1 ,..., an
bealgebraic
realnumbers, linearly
independent over Q ,
and let e > 0 . There areonly finitely
manyintegers
q such thatCOROLLARY.- There are
only finitely
manyintegers
q such thatSchmidt also proves a dual version of this result :
THEOREM 2.- Let
03B11 ,
...,03B1n
be as in Theorem1,
and let e > 0 . There areonly finitely
manyn-ples
of non-zerointegers
q ,...,q
such thatCOROLLARY.- Let (y be
algebraic,
k apositive integer
and e > 0 . There areonly finitely
manyalgebraic
numbers w ofdegree ~
k such thatwhere
H(w)
is theheight
of w(maximum
coefficient of an irreducibleintegral defining polynomial
ofw).
If k = 1 this reduces to Roth’s
theorem ;
a weakerresult,
with an exponent 2k + e instead of k + 1 + e has beenproved by Wirsing [3]
with a differentmethod.
Schmidt’s
proof
of these results uses Roth’smethod,
but the extension is notstraightforward
and manyoriginal
ideas are needed. In order to present Schmidt’sarguments,
it is therefore worthwhile to sketch Roth’sproof.
II. Roth’s Proof. For a neat
exposition
of Roth’sproof
we refer to Cassels[1].
Roth’s theorem is obtained
combining
thefollowing
two results :PROPOSITION 1.- Let (y be
algebraic,
let e > 0 and letr1,...,rm
bepositive
integers.
For m ~
e)
there is apolynomial
not
identically 0
ofdegree s rh
in such thatr i 1 r
Here
JP)
is the sum of the moduli of the coefficients of P andDJ
is the usual differentialo erator j1
" ,
x Jm
. The constant C.depends only
on 03B1 .The
proof
issimple. Considering
the(r, +1)
...(rm + 1)
coefficients of P as unknowns one has a system ofhomogeneous
linearequations
0 . Nowif 03B1
isalgebraic
ofdegree
s , theequation
splits
in a system of s linearequations
in the coefficients of thepolynomial P ,
withintegral
coefficients ~C~
whereC-
=C ((y) .
Since equa-tion
(2.1 )
has at most201420142014 (r.
+1)
...(r
+1) solutions,
we get a system ofm
s ~m (r1 + 1)
...(r
+1) equations
in(r.
+1)
...(r
+1)
unknowns with inte-gral
coefficients+ ... +rm .
This is easily
solved dusing
Dirichlet’s bprinciple, provided 2014~2014
;f ,
that is m ~ m 0e). , obtaining
a non-zerosolution
satisfying (i).
Now let
p =
be mapproximations
to oc such thatlet P be the
polynomial
ofProposition
1 and let v =(~ ,...,~ )
be suchthat,
if we write
Then
Q(03B2) = Q(03B21 ,...,03B2m)
is a rational number with denominator ~q1r1
...rm
therefore
r w
Now assume that
Then
Q
is notidentically
0 andQ(a)
=0 ,
thereforewhere the max is over the
n-ples
J such thatIf there are
infinitely
manyapproximations satisfying (2.2~
one can take" , N and more
precisely
If we choose
q~ , q
...rapidly increasing
thenr~ , r
... arerapidly
decreasing
and we may ensure thatr
+ ... +rm s 2r~ .
.Hence, letting q~ -~
oowe find
Since e is
arbitrary,
k ~ 2 and Roth’s theorem follows.The
difficulty
consists inshowing
that is small withoutputting
con- ditions of the sort "q
is not toolarge compared with q
". Nowusing
aningenious
inductivemethod,
Roth obtainsPROPOSITION 2.- Let 0 S
16 m ,
let P E~~x~,...,xm~
ofdegree s rh
inxh
and notidentically 0,
letand let
Sh
= be such thatIt is clear
that, taking
6sufficiently small, Proposition
2 is sufficient tocomplete
theproof
of Roth’s theoremalong
the lines mentioned before.The
proof
ofProposition
2 is ratherintricate,
and because of lack of space andtime,
we cannotgive
an indication of the ideas involved in it.III. Schmidt’s Proof. The index. In the
previous argument,
instead ofworking
withpolynomials
ofdegree ~ rh
inxh
we could work withpolynomials
inpairs
of variablesx , y ,
h =1,...,m
andhomogeneous
ofdegree rh
in thepair x ,
,y .
. Instead ofasking
that a derivativeDJP
should vanish at apoint
(p.,...,P )
we could introduce the linear formsand ask that P
belong
to the ideal inR[x, ,y. ,...,x , y 1 generated by poly-
nomialswith
ih > jh
for h =1,...,m .
This remark leads Schmidt to thefollowing
definitions.Let R =
"’’X1 ~ ’ ’
... ;Xm1’
be thering
ofpolynomials
in m~variables and let
L1,...,Lm
be linear forms(not 0 )
of thetype
For c > 0 let
I(c)
be the ideal in Rgenerated by
allLJ
where J =( j~ , ..., jm~
satisfieswhere
r~,...,rm
arepositive integers.
DEFINITION.- The index of P with respect to
(L1,...,L ; r,,...,r )
is thelargest
c with P EI (c)
and c = +~ if p isidentically
0 . We haveIf J is a
tm-uple
One
gets easily
" ~
The first
step
in Schmidt’sproof
is to obtain theanalogue
ofPropositions
1 and 2. We havePROPOSITION A.- Let
Lj
= I + ... +1 ,...,~ ,
beindependent
linearforms,
withalgebraic integers
as coefficients. Letand let E > 0 .
For m ~
e)
there is apolynomial
not
identically 0, homogeneous
ofdegree rh
inxh~,...,xh~
such thatwith respect to
~L~ ,...,tLm ;
’1 j ’ j r1,...,rm~
1 mfor j = 1,...,~ .
Moreover, if wefor all
J , j
andd (j)
= 0 unless for k =1,...,2
The
proof
ofProposition
A is rather similar to that ofProposition
1.Proposition
2 can also beextended,
and onegets
PROPOSITION B.- Let 0 b
C
, 0 03C4 ~ 1 , let P e notidentically 0, homogeneous
ofdegree r
inx .,...,x
, letbe non-zero linear forms whose coefficients are
integral
and have no common factor.Let also
and assume
Then the index of P with
respect
to(M. ,...,M ; r, ... ,r )
satisfiesThe ideas in the
proof
are the same asRoth’s,
but the technical difficultiesare of course much
greater.
The conclusion that may be drawn from
Propositions
A and Bis,
except in case t = 2substantially
weaker than Schmidt’s theorems. In Roth’s case, one takesand in Schmidt’s case one would take
However, in order to conclude the
proof,
oneeventually
has to consider many other sets of linear forms.IV. Schmidt’s Proof. The theorem of the next to last minimum.
Let K be a
symmetrical
convexbody
inRn
centered at theorigin
and letV(K)
be its volume. For 03BB > 0 let XK be thecorresponding
homothetic convexbody.
The successive minima~~,,.,,~n
are defined as follows :03BBi
=inf( À I
03BBK contains ilinearly independent points
A basic theorem of Minkowski statesSECOND THEOREM OF MINKOWSKI.- We have
We need another definition. Let
be
independent
linear forms withalgebraic
coefficients. Let S be a subset of~1 ,2, ...,~ .
DEFINITION.-
(M.,...,M ; S)
isregular
if(i) for j
E S the non-zero elements among03B2j1 ,...,03B2je
arelinearly
inde-pendent over
(ii)
for thereis j E S
with °Now let be
again
linear forms withalgebraic
coefficients and let S C{1,2,...,2~ .
DEFINITION.-
{L~,...,L~ ; S~
is proper if~M1,...,MQ ; S~
isregular,
wherethe M.
1
are the
adjoint
forms ofL..
Now Schmidt proves
THEOREM of the next to last minimum.- Let
S~
be proper and let bepositive
reals such thatis a
symmetric
convexbody
centered at0 ;
let~1,...,~~
denote its successive minima.such that
This is a consequence of
Propositions
A and B. Theproof
of the theorem is obtainedthrough
various reductionsteps.
c.
a)
It is sufficient to prove the result whenA. j
=Q J
andc. 1 ~...,c ~
arefixed constants such that
C1 + ... + cl = 0 , |cj| ~
1 for °This is easy, because b. one can show that if one modifies
slightly
theA.
~(say by
a factorQ J
withs~2 ~
then the minimum1 is modified
by
a factor of that order ofmagnitude.
Thus one may suppose that A. =J where the c.
belong
to a finite setdepending only
on 6 .J
b)
Ve may suppose that the coefficients ty.,, ’. arealgebraic integers.
In factij
if q is a common denominator for the u.. , the successive minima of ij
A . are
q-1
times the successive minima of A ..J J J
J
Now assume the theorem is false. There is b > O and an
increasing
sequence~l ’ ~2 ’
,...going
toinfinity
oflinearly
dent
points
ofZl
such thatWe let h =
1 , 2
,... be the(unique
up tosign)
linear form withinteger
coefficients without common
factor,
such thatLet us assume that
Q
islarge,
take(as
in Roth’sproof)
F n 1
where
r,
is verylarge
and let P be thepolynomial
ofProposition
A.Then using property (ii)
of P(the
lower bound for theindex)
Schmidt shows that P has indexwith
respect
to(M1 ,...,Mm; r. ,...~r ) ,
for some constantThe
proof
goes as follows.Let
be a linear combination of with
integral
coefficientsak ,
withc. - b
~~1 s
If we useProposition
A andQh~
we getand, by (ii)
and(iii)
the max is over thej’s
such that(iii)
holds.By
thechoice of r the
product
isNow
using (iii)
andc~
+ ... +c
=0,
1 we findif
(J/r) C14bm, Q~
islarge enough,
for esufficiently
small.Now the left hand side of this
inequality
is aninteger,
thereforeIt is not difficult to show that this
implies
that the restriction of1 , ... ,xm~~
to the linear spaceM~ .. .,x1 ~~ = 0 ,
~ ..,...,xm~~ - 0
vanishes
identically,
since it vanishes onsufficiently
many well-distributedintegral points
of this linear space ; therequired
statement about the index of P with respect toM~,..,,Mm
followseasily.
Now one would like to
apply Proposition
B and show that if therh
arerapidly
decreasing
then for every e > 0with
respect
to(M~,...,Mm ; r~,...,rm~
thusgetting
a contradiction. In order to be able to do this one needs first that therh
berapidly decreasing,
whichmeans the
Qh rapidly increasing
and this can be doneby taking
asubsequence
of theQh .
But one also needsinequalities
for therh
and theloglMhl
andone should show that
It turns out without much
difficulty
that this follows from the condition that(L. ,...,L ; S)
be a proper system, and this ends the argument.Let
Lj
= I + ... + be linear forms of determinent 1 and let E be thecorresponding automorphism
ofR .
For 1 ~p ~ l
the exterior powerP
A E defines an
automorphism
ofExpressing by
means of a standard basis of~~
one obtains a set of(~)
P linear forms indexed
by
orderedp-subsets a
of{1,...,l}
;explicitly
Let
A~,...,A~
bepositive
numbers withand consider the convex set :
This i s c alled the
p-compound
of the setKC~~ :
:Let be successive minima of and
~l ’°° °’ ~£
those ofP
K~~ ~ .
Put alsoMAHLER’S THEOREM.- There is an
ordering C.
,of the 03C3 such that
For Mahler’s
proof,
see Mahler[2].
Now Schmidt’s idea is to
apply
theprevious
theorem toget
a non-trivial lower bound for 03BD . and then use Mahler’s theorem to deduce a non-trivial lower bound(~)-l
~ 1for the first minimum
B..
One needs a lemma.
Lemma 1.- Let
L. X.
be as in the theorem of theprevious
section. Then ifA.... A -
1 andprovided
Q ~0.) .
(Note
that the condition A. 3: 1 1 for i e S is notneeded.)
The
proof
goes as follows. Puto 1 /0
By a
general
result ofDavenport
there is apermutation (p.)
of{1,...,l}
such that the successive minima xt of J
note that = p
for j = 1 ...~ -
1 , andJ J o
If 1 for some i E S then since
i
By
Minkowski’stheorem,
B. "’X. ~ 1 and we deduce’ ~
- /-
Now suppose
A!
> 1 for every i E S . Then we mayapply
the theorem of the next to last minimum and findBy Davenport’s
lemma one has03BB’l-1 « po
therefore sC and as before weget
hence the result
(taking
a smaller 6 ifnecessary).
It remains to show that if Q zmax(A~,...,A~ ; Q~~
then for some C we havemax(A’,...,A*, ; Q2) .
Thisis easy :
whence the result with C = 2~ .
The
proof
of Schmidt’s theorem now ends as follows.Firstly
one provesLemma 2.- Let
1 , ~~,...,a~_~
be realalgebraic linearly independent over Q .
Writeand for 1 ;
p ~ l -
1 let be the set of orderedp-uples 03C3
C(1 ,...,l}
with ~ ~ T .
Then the forms L(p)03C3
together
with S(p) form a propersystem.
Now let
A.... 1 At
= 1 ~At
> 1 , 0Ai
1 , i =1,...~ -
1 and letX~ ~..’~X.
be the successive minima ofL.(x)
:A..
One now proves that’ ~
..
J J
The theorem of the next to last minimum
gives
the result for and so our statement is true if t = 2 . Nowsuppose t
> 2 . We shall show thatfor p = 1
, 2,...,~ -
1 ,Q ~ Q4~
and the result will follow.Let 0-
= 1 , ... , p -
1, $~ .
We shall prove thatIn
fact,
let B. = i ~ 03C3 . Since A ...A _ 1 we have A z 1 andBy
definition ofÀ1
there is a non-zerointegral point x°
EZ
withand
by
Minkowski’s theorem~~ 5
1 . Hence 1 , i =1,...,2 -
1 , andthus the last coordinate
x~
ofx
is not 0 . Hence the vectory° _ (x~ , ...,xp-~ , x~~
is not 0 andregarding Li ,
i E~1 , ...,p-1 , ~~
asforms in p variables we
get
Hence the first minimum
~~
ofSince
B1 ...B P -1 Be
= 1 ,B
> 1 ,Bi
1 for i =1 , ... , p - 1 ,
and sincep S 2 -
1 we may use induction andapply ~5.1~.
Weget
~
provided Q ~
; since it suffices Q ~Clearly
theargument applies
to everys(p) ,
hencefor all ~‘ E
S~p~ . By
Mahler’s theorem the first minimumV~
of thep-compound
of the linear forms L. satisfies
C- J
Hence
taking
a smaller 6 if necessary, we mayapply
Lemma 1 and Lemma § andget
Since
A ,
it sufficesQ ~ max(A , Q6) . By
Mahler’s theoremagain,
we have
and
by (5.3)
we deduce(5.2). Clearly (5.2) implies B
I >B ~ Q 2014 ~
and since~1 ... ~~ ~
1by
Minkowski’stheorem,
we have alsoX
~1 1 and(5.1 ) follows,
by taking
a smaller 6 if necessary.Schmidt’s Theorem 1 is almost immediate from
(5.1).
Infact, by
definition of firstminimum, (5.1) implies
that theinequalities
are insoluble if
A,
1 ,...,At-1
1 ,At
> 1 andA1 ...A~
= 1 , forunless all the x. are 0 .
By
Liouville’stheorem,
there is C such that1
if
xe
islarge enough ;
now takewe deduce that we must have
(the inequalities (5.4)
areinsoluble)
Since the
only
restriction onQ
isfor some
C ,
we deduce that theinequalities
have
only
a finite number of solutions.Clearly
the conditionsq
are notrestrictive,
because if sayq E
it is sufficient to show thathas
only
a finite number ofsolutions,
and Schmidt’s theorem followsby
an obvious inductiveargument.
The
proof
of Schmidt’s second theorem isessentially
identical and therefore will be omitted.400-20
REFERENCES
[1]
J.W.S. CASSELS - An Introduction toDiophantine Approximation, Cambridge
Univ.Press, 1957.
[2]
K. MAHLER - OnCompound
Convex Bodies I., Proc. London Math.Soc., (3) 5 (1955),
358-379.[3]
E. WIRSING - OnApproximations
ofAlgebraic
Numbersby Algebraic
Numbersof Bounded
Degree,
Proc.Symposia
PureMath.,
XX(1969), 213-247.
Schmidt’s
proof
appears in three papersW.M. SCHMIDT - Zür simultanen
Approximation algebraischer
Zahlen durchrationale,
ActaMath.,
114(1965),
159-209.- On simultaneous
approximations
of twoalgebraic
numbersby rationals,
ActaMath., 119 (1967),
27-50.- Simultaneous
approximation
toalgebraic
numbersby rationals,
Acta