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S EMINARIO M ATEMATICO
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T ELEMACHOS H ATZIAFRATIS On the multiplicity of holomorphic maps and a residue formula
Rendiconti del Seminario Matematico della Università di Padova, tome 89 (1993), p. 37-45
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TELEMACHOS
HATZIAFRATIS (*)
ABSTRACT - We obtain
integral
formulas for themultiplicity
of aholomorphic
map at an isolated zero of it. The
proof
is based on Stokes’ theorem and a pro-cess of
passing
to a residue.1. Introduction.
Let U c
C~n
be an openset,
0 E Uand f = ( fl ,
... ,fn ):
U ~C~n
a holo-morphic
map with 0 an isolated zeroof f.
Then it isdefined, by
variousequivalent
ways, themultiplicity mult ( f, 0) of f
at0;
see[3,
p.667].
This
multiplicity
turnsput
to be thefollowing integral
where
(*) Indirizzo dell’A.:
Department
of Mathematics,University
of Athens, Pa-nepistimiopolis
157 84, Athens, Greece.38
see [ 1,
p.20].
(In
the abovedeterminants j
runsfrom j
= 1to j
= nforming
the nrows; the
integer
above a column means that this column is to be re-peated
so many times as theinteger indicates.)
If n = 1 then the above
integral
is reduced to( f ’/f )
dzwhich
by
the residue theorem isequal
toRes (f’lf, 0).
SeIn this paper we
generalize,
in a sense, this situation(to
the case n >1) by writing integral (1)
which is anintegral
of a(2n - 1)-form
asan
integral
of a differential form of lowerdegree,
moreprecisely
of(2n - 2p - 1) degree
for 1 ~p ~ n -1.
Inparticular (by applying
ourformula for p
= n -1 )
we express themultiplicity of f at
0 as a line inte-gral.
Let us alsopoint
out that there are certain choices that can be made inconstructing
these differential forms whichgive
variousformulas.
The
(2n - 2p - l)-dimensional cycles
on which theintegrals
aretaken lie on
appropriately
chosenanalytic
varieties which pass from 0 and which could besingular
at 0.As for the process of
obtaining
these formulas it is the classical pro-cess of
passing
to a residue after the use of Stokes’ theorem(see [3, chap. 3]).
The
arrangement
of the paper is as follows: in Section 2 we state theformula,
in Section 3 wegive
theproof
of it and in Sections 4 and 5 weobtain some consequences of it in some
special
cases.2. Statement of the result.
With notation as above let us consider a
holomorphic
map h ==?1,
...,hp):
U -CP
so thatfor
some
E0( U), 1 ~ i ~ p, 1 j ~ n.
Let us also assume that M
=: IZ E
U:h(z)
=01
is smooth near thepoints
ofSe
and that Mmeets S., transversally
so that is asmooth
(2n - 2p - l)-dimensional
manifold. Of course 0 E M and 0 could be asingular point
of M.Let us define
where
With this notation we will prove the
following
THEOREM 1. The
multiplicity of f at
0 isgiven by
the formula3. Proof of Theorem 1. °
The idea of this
proof
is similar to the one in theproof
of Theorem2.1 of
[4];
so we willgive only
the modifications which are needed to carry out theproof
in this case and we will refer to[4]
where more de- tails can be found about some calculations.We devide the
proof
into severalsteps.
STEP 1. Let
and
Then s~
(z)
is defined for z e U - M andLet us set
40
We claim that
a1)
=c~~ (g~) _
on U - M.To prove this it suffices to work close to a
point where f1 =
0 and towrite
(in
the lastdeterminant j
runsfrom j
= 2to j
= nforming
the 2nd ton-th row of
it).
Then,
in view of( 1 ), ~
can be writtenwhich
implies
that whereTherefore
8Y) = ( 1 ~fl ) (Xn _ 1 - Xo).
But it is easy to calculate and find that and
Xo
=0,
which proves the claim.
STEP 2. Let us start with the
integral
and write it as
where
Se,a
=I
>~}.
But for z
ESe, a
we have(by Step 1)
rem)
aswhere
TE,8
={2:
EI
=d} (here
E and d are smallenough
and sothat the various sets over which we
integrate
aresmooth).
p-2
STEP 3. We can
write q = q + I r.
wherem=0
and
provided
that differential forms are restricted toT,,
t.This follows from the fact that on we have rm = 0 if m > p;
see
[4,
p.791].
STEP 4. With differential forms restricted to
Te, t, if
can be written(up
to asign)
as follows:The
proof
of this is similar to theproof
of Lemma 3 of[4].
This follows from an
analogous
estimate to the one in Lemma 4of [4].
STEP 6.
By Steps 2,
3 and 5 we obtain42
But
(up
to asign);
this follows from Lemma 1 of[4].
Therefore
(also by Step 4)
which
completes
theproof.
4.
Parametrizing T,,.
With the notation of Theorem 1 let us consider the case p = n -1 in which case the
integrand
0 in theintegral
of Theorem 1 is a differential form oftype (1, 0).
Now suppose
that ~
is aholomorphic
map from aneighborhood VcC
of 0 to U so that themap ~ H ~(~) _ ( ~1 (~), ..., ~n (~))
isa
parametrization
of M ={2:
E U:h, (z) = ... = hn _ 1 (z)
=01
with, Then ~: Te -
T.,
and letdeg ~
de-note. the
degree of ~.
’
With this notation we have the
following.
THEOREM 2. The
multiplicity of f at
0 isgiven by
the formulawhere
t*(0)
in thepull-back
of 0 via ~.whence
5(~* (0)) 0;
from this it follows that there is aholomorphic
function in V -
101,
denotedby ~* (0)/dA
which has apole
at 0 so that~* (0) = (~* (e)/d~,)
da.Now, by
Theorem1, mult ( f, 0) =j 0.
Butby [2, p. 253]
we have:Also, by
the residuetheorem,
and the formula of the theorem follows.
REMARK. Of course an
analogue
of Theorem 2 can beproved
in thecase 1 ~
p £ n -
2 too.5. A
special
case.We will prove the
following.
THEOREM 3. Let U c
Cn
be an openneighborhood
of 0 andf = ( fi ,
...,fn):
U -cn
aholomorphic
map with 0 isolated zero off.
Suppose
that 0 is an isolatedsingular point
of M ={2:
E U:f1
= ... == fp = 0}.
Then for E > 0
sufficiently
small we havewhere 7% = n - p
and ~
=(h+1,
PROOF. We will
apply
Theorem 1 withhi = 11’ ...,~p = fp.
Then wemay choose
~
= 1 if i= j
and~
= 0 if44
Then
On the other hand
provided
that differential forms are restricted to M. This follows from[5,
p.483]
and therepresentation
ofB(z)
in terms of local coordi- nates as isgiven by [4,
Lemma2].
Now(1)
and(2)
and Theorem 1 com-plete
theproof.
EXAMPLES.
1)
Letf: (;3 ~ ~3
be the mapConsider the map ~:
C - (~3
definedby r(A) = (À21, ~14, À 10).
IfTF
= then ~: T£ ~T,
anddeg f
= 1.Thus
combining
Theorems 1 and 2 we obtain thatwhich defines the
hypersurfaces
S= f(Zl, Z2)
e~2 : g (zl , Z2)
=0}
whose0 is an isolated
singular point.
Then the Milnor number of C at 0 is the
multiplicity
of the mapf
== (Bg/Bz1,
at 0(see [6]).
Now f (zl, z2) _ (z1 - z2
+5zi).
Hence in thesetting
of The-orem
2,
if we set z1 =À3,
z2 =~2
wecompute (using
also Theorem3)
that the Milnor number of S at 0 is 7.REFERENCES
[1] I. AIZENBERG - A. YUZHAKOV,
Integral representations
and residues in mul- tidimensionalcomplex analysis,
Transl.Math.
Monos., 58, Amer. Math.Soc., Providence, R.I. (1983).
[2] M. BERGER - B. GOSTIAUX,
Differential Geometry Manifolds,
Curves andSurfaces, Springer-Verlag,
New York (1988).[3] P. GRIFFITHS - J. HARRIS,
Principles of Algebraic Geometry, Wiley,
NewYork (1978).
[4] T. HATZIAFRATIS, On certain
integrals
associated toCR-functions,
Trans.Amer. Math. Soc., 314 (2) (1989), pp. 781-802.
[5] T. HATZIAFRATIS, A
global
residue theorem onanalytic
varieties, J. Math.Anal.
Appl.,
149 (2) (1990), pp. 475-488.[6] J. MILNOR,
Singular points of complex hypersurfaces,
Ann. Math. Studies, 61, Princeton Univ. Press, NewJersey
(1968).Manoscritto pervenuto in redazione il 19 Novembre 1991.