C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
M ICHAEL B ARR
Closed categories and topological vector spaces
Cahiers de topologie et géométrie différentielle catégoriques, tome 17, n
o3 (1976), p. 223-234
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Article numérisé dans le cadre du programme
CLOSED CATEGORIES AND TOPOLOGICAL VECTOR SPACES
by Michael BARR
CAHIERS DE TOPOLOGIE ET GEOMETRIE DIFFERENTIELLE
Vol. XVII-,3
(1976)
INTRODUCTION I
In the
paper [1],
henceforth referred to asDVS,
we consideredtwo
duality
theories on thecategory 2
oftopological
vector spaces overa discrete field
K . They
were each describedby
a certaintopology
on theset of linear functionals. The
first,
the weakdual,
led to a category of re- flexive spaces( i. e. isomorphic
to their seconddual)
which gave a closed monoidal category when thehom
sets aretopologized by pointwise
con-vergence.
The
second,
strongduality,
was based on uniform convergence onlinearly
compact(LC) subspaces.
This led to a nicerduality theory (now
the discrete spaces are
reflexive)
but we did not describe there any closed monoidal category based on that stronghom .
In this paper we fill that gap.It is clear that one cannot expect an internal
hom-functor
which be- haves well on all spaces or even all reflexive ones. It is a consequence of the closed monoidal structure that the tensorproduct
of two LC spacesmust be LC
(
see Section1).
Such aproduct
istotally
bounded(in
a sui-table
generalized
sense whichis, together
withcompleteness, equivalent
to linear
compactness).
This fact suggestslooking
at asubcategory
of spa-ces which
satisfy
samecompleteness
condition. If the category is to havea
self-duality theory,
a dual condition isimposed
as well. When this is done the result is indeed a closed monoidal category in which everyobject
isreflexive. The set of
morphisms
between two spaces istopologized by
atopology
finer(possibly)
than LC convergence toprovide
the internalhom .
* I would like to thank the Canada Council and the National Research Council of Canada for
supporting
this resarch, and the I.F.M.,E.T.H., Zurich,
forproviding
a
congenial
environment.The
dual,
moreover, has the strongtopology.
One
word about notation. For the most part we adhere to that of DVS.However there is one
significant change. Owing
to a lack ofenough
kindsof brackets and
hieroglyphs,
we takeadvantage
of the fact that this paperconcerns
exclusively
itself with the stronghom
to use(-, -)
and(- )*
torefer to the strong
hom
and strongdual, respectively. Similarly,
a spaceV
is called reflexive if it isisomorphic
with the strong seconddual,
heredenoted
V**.
1.
Preliminaries.
The
subject
of this paper is thecategory 2
as described inDVS, equipped
with thestrong
internalhom
functor defined there.Specifically,
if
U and V
are spaces, we let( U, V )
denote the set of continuous linear mapsU -
vtopologized by
uniform convergence on LC Slspaces.
A basicopen
subspace
iswhere
Uo
is an LCsubspace
inU
andV0
is an opensubspace
ofV.
We l et
V*=(V,K).
P R O P O S IT ION 1.1. Let
U
be afixed
space.The functor ( U,- )
commuteswith projective
limitsand has
anadjoint - 0 U.
PROOF. It
certainly
does at theunderlying
set level soonly
thetopology
is in
question.
Letbe the
projection.
A basic open set in(U , V )
is{f) l f (U0) C V0}
whereUo
is an LCsubspace
ofU
andVo
an opensubspace of V .
We can sup- poseVo
=TT Ww
whereWw
is open inVw
andis, Vw
for all but a finiteset
00
of i ndices. ThenThere is no restriction on the other coordinates of
f .
ThenI f l f (U0)
CV0}
corresponds
to the setThe argument for
equalizers
is easy and is omitted. Infact,
when V is asubspace of W , ( U, V)
has thesubspace topology
in( U, W).
Now the existence of the
adjoint
follows from thespecial adjoint
theorem
( cf. DVS, 1.2 -1.4 ).
This
hom
is notsymmetric
and is not closed monoidal. A map fromU
h toW
can beeasily
seen to be a bilinear mapU X V - W
whichis,
foreach u f
U ,
continuouson V ,
and for each LCsubspace C v ,
anequi-
continuous
family
onU .
From this it is easy to see the assymmetry. Tosee that we don’t even get a closed monoidal category, we observe that that would
imply
that theequivalences
between mapsarise from a natural
isomorphism (UXV, W) = (U, (V, W)) (see [2],11.3).
Suppose X
andY
are infinite sets,U
=K X and V
=Ky .
Thenassuming
that the above
isomorphism held,
we would have( U X V ) *= ( U , V*),
whichcan be
directly
calculated to beKXXY Let W
be thesubspace
ofKXxY
Iproper
when X
andY are infinite,
whose elements are those of thealge-
braic tensor
product K X XKY .
Then onpurely algebraic grounds
there isa map
KX-> (KY, W)
which is continuouswhen W
isgiven
thesubspace topology.
Thisclearly
has no continuous extensionKXxY ->
W.There
is, however,
an alternative. Toexplain
it werequire
a defini-tion. A
space V
is called(linearly) totally bounded
if for every open sub- spaceU ,
there is a finite number of vectorsvl , ... , vn which, together
with
U , span V . Equivalently,
every discretequotient
is finite dimensio- nal. The obviousanalogy
of this definition with the usual one is streng- thenedby
thefollowing proposition
whoseproof
isquite
easy and is omitted.P RO P O SITION 1.2.
The
space V isLC iff
it iscomplete and totally
boun-ded.
PROPOSITION 1.3.
Let U be totally bounded and V be LC. Then UXV
istotally bounded.
P ROO F.
Let W
be discrete andf : U X V ,-> W.
Then therecorresponds
ag:
U , ( V, W)
and the latter space is discrete. Hence theimage
is genera- tedby
theimages
of a finite number ofelements,
sayg(u1 ), ... , g(un) .
Each of these in turn defines a
map V - W
whoseimage
is a finite dimen- sionalsubspace of W,
and thus the wholeimage f (U X V)
is a finite di-mensional
subspace of W
2. S- and C*-spaces.
We say that a space U is a
(-space
if every closedtotally
boundedsubspace
is LC(or, equivalently, complete).
The fullsubcategory of I -
spaces is
denoted CZ .
P R O P O S I T I O N 2.1.
The
spaceU
i s a(-space iff
every map toU from
adense subspace of
aLC
space toU
can beextended
tothe whole
space.PROOF.
Let V0 ->
U begiven where Vo
is a densesubspace
of the LCspace V. The
image Uo
C U istotally
bounded and hence has an LC clo-sure which we may as well suppose is
U . Now U
isLC,
hence is a power ofK ,
which means it is acomplete
uniform space and thus the map ex-tends,
since a continuous linear function isuniformly
continuous.The converse is trivial and so the
proposition
follows.We say that
U
is a(*-space provided U*
is a(-space.
Since bothdiscrete and LC spaces are
C-spaces, they
are each(*-spaces.
PROPOSITION 2.2.
Let U
be a(-space. Then U*
is a(*-space;
i. e.,U ** is
aispace.
P RO O F .
Let V0 -> V
be a dense inclusionwith V
an LC space. Ifho -> U **
is
given,
wehave, using
the fact thatU -
isa (-space,
the commutative dia- gramDouble dualization
gives
us therequired V = V** - U** .
If
U
is a space, it has a uniformcompletion U" ,
and welet CU
denote the intersection of all the
C-subspaces
ofU"
which containU .
Evi-dently, U
is a densesubspace of CU.
For any
subspace
V CU",
let(I V
be the union of the closuresof the
totally
boundedsubspaces
ofV.
For anordinal 11,
letand,
for a limitordinal ft ,
letLet C V
be the union of all thev
PROPOSITION 2.3.
SU = CooU.
PROO F. It is clear that
SooU
is closed under theoperation
ofC,
and henceis a
C-space containing U . Thus (V
CSoo U ,
while the reverse inclusionis obvious.
PROPOSITION 2.4.
The
constructionU l-> SU
is afunctor which, together
with the inclusion U C U,
determines aleft adjoint
to theinclusion of .
P ROO F. Let
f : U - V
be a map. Since it isuniformly continuous,
there is induced a mapf -: U- -> V-.
It isclearly
sufficient to show thatf- ((U )CSv.
But since the continuous
image
of atotally
bounded space istotally
bound-ed,
we see that whenever W is asubspace
ofU"’
withf (W) C S V ,
andW0 C W
istotally bounded, f ( cl ( W0 )) C (Vas
well. From this it follows thatf(S1W)CSV,
and so we seeby
inductionf((W)C’V. Applying
this to
U ,
we see thatf (SU) C C V.
PROPOSITION 2.5. Let
U
bereflexive. Then
sois CU.
so that
can be extended to The
diagram
commutes, the first square
by construction,
the secondby naturality.
SinceU
is densein (U
and the top map is theidentity,
so is the bottom one.Thus’ U
is reflexive.PROPOSITION 2.6.
Let U be
areflexive ’*-space. Then
so isCU.
P RO O F .
Let Vo - V
be a dense inclusionwith V
an LC space. Given a mapthis
extends,
sinceU *
is aC-space,
to amap V-> U * .
Thisgives
usand since V * is
discrete,
hencecomplete,
this extendsto £ U -
V* whosedual is a map
The outer square and lower
triangle
ofcommute, and since the lower map is 1-1 and onto, so does the upper
triangle.
If X
is atopological
space andX1
andX2
are subsetsof X ,
saythat
X1
isclosed
inX2
ifXi
nX2
is a closed subset ofX 2 . Equivalently
there is a closed subset
X’1
CX
such thatWe use without
proof
the obvious assertion thatXI
closed inX2
andX 3
closed in
X4 implies
thatX1 n X2
is closed inX3 n X4.
PROPOSITION 2.7.
Let {U w }
be afamily of discrete
spacesand U be
asubspace of TT U. Then U
is aS-space iff for
everychoice of
acollection
of finite dimensional subspaces V w C Uw , U
isclosed in TT Vw .
PROOF.
Suppose
the latter condition is satisfied andU 0
is a closed total-ly
boundedsubspace
ofU .
Then theimage
ofis a
totally bounded,
hence finite dimensionalsubspace Vw
CUw .
Evident-ly Uo
CTTVw,
and sinceUo
is closed inU ,
it is closed inU n TT Vw,
which is closed in
TT Vc.
ThusUo
is LC.Conversely,
ifU
is aC-space,
then for any collection
( V (L) }
of finite dimensionalsubspaces, U n TT Vw
isa closed
totally
boundedsubspace
ofU
and hence isLC,
hence closed inII V (L).
3. The internal hom .
If U and V
are spaces, we recall that( U, V)
denotes the set of continuous linearmappings U - V topologized by taking
as a base of opensubspaces {f I {(U0) C V0 I
whereUo
is an LCsubspace
ofU and Vo
an open
subspace
ofV .
Anequivalent description
is that( U , V)
is topo-logized
as asubspace
ofTT(UY, V/ Vw) where U Y
ranges over the LC sub-spaces of
U and Vw
over the opensubspaces
ofV .
We may consider thatV / V(L)
range over the discretequotients
ofV.
Each factor isgiven
the dis-crete
topology.
From thatdescription
and theduality
between discrete and LC spaces, thefollowing
becomes a formal exercise.PROPOSITION 3.1. L et U
and V
bereflexive
spaces.Then the equival-
ence
between
maps U , Vand V* , U* underlies
anisomorphism
LEMMA 3.2.
Suppose
Uis a reflexive S*-space and V
areflexive’ -space.
Then ( U, h)
is a£.space.
P RO O F .
Let {UY}
and{Vw}
range over the LC and opensubspaces,
resp-ectively,
ofU
andV.
A finite dimensionalsubspace
of(UY, V/ Vw)
isspanned by
a finite number of maps, each of which has a finite dimensional range. Thusaltogether
it is contained in asubspace
of the formwhere
U,,,
is a cofinite dimensionalsubspace
ofU ,
andVYw /Vw
is a fi-nite dimensional
subspace
ofh/ Vw .
Toapply
2.7 it is sufficient to consider families of finite dimensionalsubspaces
of the factors. So let us suppose that for allpairs w ifI
of indices a cofinitedimensional quotient UY /UYw
and a finite dimensional
subspace VYw/w,
have been chosen. Then for eachglr , V
is closedin fl
cvVYw/ Vw
and so(U ) Y V)
is closed inIt follows that is closed in q
1 . Using 3.1,
wehave
similarly that,
foreach ;& , (U, V/ V.) is
closed in Jand so is closed in
is closed in
A collection of maps
U4 -+
V is the same as amap :
, andsimilarly
a collection of maps
U - V/V (L)
isequivalent
to oneU - II V / V úJ.
Now amap in both
TT (UY, V)
andTT (U , V/ V(L)) corresponds
to a commutative squareThe top map is onto and the lower a
subspace
inclusion and hence there is a fill-in on thediagonal.
Thus the intersection isexactly ( U, V).
Clear-ly
any mapUy/UY w -> V 41 w /Vw belongs
to bothand hence to their intersection. Thus
(U, V)
is closed inand is a
C-space.
4. The category R.
Ye
let 31
denote the fullsubcategory of b
whoseobjects
are thereflexive
S-S*-spaces.
PROPOSITION 4. 1.
The functor UF l-> 6 U
=(((U*))*
isright adjoint
to theinclusion R -> SB. For
anyU,
8U ->
U is 1-1and
onto.P ROO F. The map
U* -> S U*
is a dense inclusion so thatare each 1-1 and onto and so their
composite
is.If h
isin N
and V->U isa map, we get
Now
U*
is a reflexive( DVS 4.4 ) (-(*-space (2.2),
and soI s SU* (2.6),
and hence its dual is reflexive as well. If h is
in fl and V -> U ,
we get and thenThe other direction comes from
We now
define,
forU,
hin R, [U, V] = 6 (U, V) (cf. 3.2).
Itconsists of the continuous maps
U -
V with atopology (possibly)
finerthan that of uniform convergence on LC
subspaces. Note,
of course, thatU* [U, K]
isunchanged.
If
U, V
arein 91
andW0
is atotally
bounded subset of( ll , V) ,
its
closure W
is LC.Then 8 W = W
is an LCsubspace
of[U, V]
and con-tains the
same W0 . Thus Wo
istotally
bounded in[U, V] .
The conversebeing clear,
we see that( U , V)
and[U, h ]
have the sametotally
boundedsubspaces.
LEMMA 4.2.
,Suppose U, V in 91. Any totally bounded subspace of [U, V]
is
equicontinuous.
PROO F. Let
W C (U, V )
betotally
bounded.Corresponding
toW -> (U, V )
we
have Jl’ - (V*, U*) (3.1), and thus WX V* -> U * .
IfVo
is an open sub- space ofV , its
annihilatorann Vo
inV *
is LC . This follows from the re-flexivity of V
and the definition of thetopology V** . Then WX(ann V0 )
istotally
bounded(1.2 )
and hence so is itsimage
inU * .
The closure of thatimage
is an LCsubspace
ofU *
which we can callann Uo ,
withUo
openin
U ( same
reason asabove).
From this it is clear that theimage
ofW X U0
is in
Vo ,
which meansthat W
isequicontinuous.
COROLLARY 4.3. L et
U, V, W be in R. There
is a 1-1correspondence
between
mapsU , [ V, W] and V - [ U, W] .
PROOF. A map
U->[V,W] gives U -> (V, W)
andUXV -> W.
To any LCsubspace
ofU corresponds
anequicontinuous family V , W . Certainly
anyvc V gives
a continuousmap U , W and thus, by
the discussion in Section1,
we getV -+ (U, W)
and thenV -> [U,W] .
PROPOSITION 4.4.
Let U and V be in R. Then [U, V]= [V*, U*] by
the
natural
map.PROOF.
Apply 6
to both side s in 3.1.Now we
define,
forU , h in R,
P R O P O S IT IO N 4.5.
Let U, V, W
bein 31. Then there is
a 1-1 correspon-dence
between mapsU X
V -+W and
mapsU -> I V , W].
PROOF. Each of the transformations below is a 1-1
correspondence
COROLLARY 4.6.
For
any iPROPOSITION 4.7.
Let U, V be LC
spaces.Then U0V
=S(U XV) and
is an
L C
space.PROOF, We know it is
totally
bounded(1.2)
so thatS( U X V)
is LC. WhenW
isin 31 ,
each of the transformations below is a 1-1correspondence:
PROPOSITION 4.8. Let
U, V and
W’belong
tom. The natural composi- tion of maps (V, W) x (U, V) -> (U, W)
arisesfrom
a mapPROOF. If G is an LC
subspace
of(U,. V ), U0
an LCsubspace
ofU ,
and
Wo
an opensubspace
ofW,
the closure of theimage
of the evalua- tion map -is an LC
subspace
inV.
Then the basic open set in(V, W),
is transformed
by G
intoThus G determines an
equicontinuous family
of maps( V, W) -> (U, W)
andso we have the indicated map.
PROPOSITION 4.9. Let
U,
Vand W belong to 91. Then natural composi-
tion arises
from
a mapP RO O F . Let
FC[V, W] and GC[U, V]
be LCsubspaces.
Fromand the fact that
(U, W)
isa (-space,
we haveand
then, by adjointness,
This
gives
usG -> [F, [U, W]]] .
Now G is an LC space and hence de- fines anequicontinuous family.
Eachfc
Fgives, by composition,
a con-tinuous function
to -: ( U, V ) -> ( U, W)
which extendsby functoriality
toa continuous
function [ U, V] -> [U, W].
Hence we have a bilinear map:F x [ U, V] -> [U, W]
whichis,
for allff F,
continuous on[U, V],
and forall LC
subspaces
G C[U, V] , equicontinuous
onF .
There results a mapF X[U, V] - [U, W]
whichgives F -> ([ U, V), [ U, W] ) and, by adjoint-
ness,
F -> [[ U, V], [ U, W]] .
ThenF
determines anequicontinuous family,
so that we have a bilinear map
[ V, W]
X[U , V]-> , [ U, W]
with the property that every LCsubspace
of[ V, W]
determines anequicontinuous family
on[U, V] . Repeating
the argument usedabove,
we see that every element of[ U , V]
determines a continuous map on[V, W] .
Hence we haveTHEOREM 4-io.
The category N, equipped with - @ - and [ - , - ] , isaclosed
monoidal category
inwhich
everyobject
isreflexive.
REFERENCES.
1. M. BARR, Duality of vector spaces, Cahiers
Topo.
et Géo.Diff.
XVII- 1 (1976),3- 14.
2. S. EILENBERG and G. M. KELLY, Closed categories, Proc.
Conf. Categorical Algebra
( L a Jolla, 1965), pp. 421 - 562. Springer, 1966.Mathem atics Department Me Gill University
P . O. Bo x 6070, Station A MONTREAL, P. Q. H3C - 3GI CANADA