C OMPOSITIO M ATHEMATICA
G IORGIO B OLONDI J AN O. K LEPPE
R OSA M ARIA M IRO -R OIG
Maximal rank curves and singular points of the Hilbert scheme
Compositio Mathematica, tome 77, n
o3 (1991), p. 269-291
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Maximal rank
curvesand singular points of the Hilbert scheme
GIORGIO
BOLONDI1,
JAN O.KLEPPE2
and ROSA MARIA
MIRÒ-ROIG3
(C 1991 Kluwer Academic Publishers. Printed
1 Dipartimento
di Matematica, Università di Trento, I-38050 Povo (Trento), Italy’Oslo College of Engineering, Cort Adelergate, Oslo 2, Norway
3Dept.
D’Algebra i Geometria, Facultat Matematicas, Universitat de Barcelona, Gran Via 585, 08007 Barcelona, SpainReceived 24 October 1989
0. Introduction and
preliminaries
Let X be a curve in
P3,
i.e. a closed one-dimensional andequidimensional, locally Cohen-Macaulay
subscheme ofP’.
We say that X is non-obstructed if thecorresponding point
of the Hilbert scheme issmooth,
otherwise we say that X is obstructed. Ageometrical
characterization of non-obstructedness is not known even for smooth space curves, and severalexamples
of obstructed smooth space curves are known(also
ingenerically
non-reducedcomponents
of the Hilbertscheme),
see for instance[Ml], [S], [EF], [Kl], [K3], [K4], [E].
We want to
point
out that all theseexamples
are curves which have not maximalrank,
with theexception
of a non-reduced curve in[K4],
3.22.On the other
side,
in 1975Ellinsgrud proved
thatarithmetically
Cohen-Macaulay
curves are non-obstructed[El].
Recall that a curve C inp3
isarithmetically Cohen-Macaulay
if andonly
if itsdeficiency
module is zero(hence
it has maximalrank). Trying
togeneralize
this result we will prove that ageneral (in
a sense that will be made moreprecise)
maximal rank curve whosedeficiency
module is concentrated in onedegree
is non-obstructed. This is the best that one canhope,
since we willgive
a criterion forconstructing
obstructedcurves in these liaison classes
(from
which oneclearly
seeswhy
these curves are’particular’).
This criterion willgive
asmooth,
obstructed maximal rank curve.We will
give
a minimal setof generators
for thehomogeneous
ideal of this curve(by using Macaulay, [BS])
and then we will check smoothness.This work was
prepared during
astage (May 1989)
of the first and the second author inBarcelona, supported by
theDepartament d’Algebra
i Geometria of theUniversity
ofBarcelona,
which these authors thank for itshospitality.
Thethird author was
partially supported by
DGICYT No. PB88-0224.During
the Trieste Conference onProjective
Varieties(Trieste,
June1989)
wemet Charles
Walter,
who had constructed anexample
of smooth obstructedmaximal rank curve, and in fact it turned out that his
example
has the samecohomological properties
of ourexample.
Hiselegant technique
forproving
smoothness is different
([W]).
We need some
preliminaries.
The field k is analgebraically
closed field of characteristic zero. We set R =k[x, y,
z,t],
m =(x,
y, z,t)
andP’ = Proj(R).
Given a curve X in
P’,
we denoteby J x (resp. 1(X))
the ideal sheaf(resp.
thehomogeneous ideal)
of X. If X sits in some closed subscheme Y ofp3,
thenFX/Y
denotes the ideal sheaf of X in Y We set d
= degree
ofX,
pa = arithmetic genus of
X,
s
= min(t |H0(P3, fx(t» * 01,
o-
= min{t|H0(H, FX~H(t)) ~ 01
where H is ageneral plane,
e =
max{t|1 Hl(P3, OX(t)) ~ 0},
c
= max{t|1 Hl(p3, J x(t» ::j:. 01,
b
= min{t|H1(P3, FX(t)) ~ 01,
andM(X) = ~t H1(P3, FX(t)), deficiency
module of X.If M(X)
=0,
then let c =- oo and b = +00.
Recall that a curve X in
P3
is said to bearithmetically
Buchsbaum(or,
morebriefly, Buchsbaum)
if andonly
if m ·M(X)
=0,
and X is said to have maximal rank if andonly
if the natural restriction mapshave maximal rank for
every t e
Z.We consider liaison classes of curves in
p3
whosedeficiency
module isconcentrated in at most one
degree.
If n is anon-negative integer,
we denoteby
concentrated in at most one
degree
the liaison class of curves with at most one
deficiency
group different from zeroand of dimension n. These classes are studied in
[BM].
If Y is a curve, we denote
by FY
itscohomology function,
that is to sayand if F:
{0, 1, 2}
x Z ~ N is anyfunction,
we will denoteHF
={C
curve inP3|FC = F}.
If two curves X and Y have
only
onedeficiency
group different from zero andFX
=FY,
thenthey
aretrivially
in the same liaisonclass;
moreover, if F =FX,
then from
[B], 2.2,
we have thatHF
is alocally
closed irreducible subset of the Hilbert scheme. In this sense we will be able tospeak
about a’general’
elementHF .
So we will use the sentence ’ageneric
Buchsbaum curve C of diameter l’with the
meaning
’ageneral
element ofHpc’,
for everyC ~ Ln,
Vn.For results about obstructedness and deformation
theory
in the Hilbertscheme we will refer
mainly
to[K4]; indeed,
manyproofs
here are gen- eralizations of results therecontained,
hence we recall some results about obstructedness and deformationstheory
in the Hilbert schemeH(d, pa)
of curvesof
degree d
and arithmetic genus pa used in thesequel.
We denoteby D(d, pa; fi, f2),
resp.D(d, pa;f),
the Hilbert scheme of nests(or fiags) parametrizing
curves Xfrom
H(d, pa)
andcomplete
intersections Y oftype
orbidegree ( fl, f2),
resp.surfaces Y of
degree f,
such that Y ;2 X.Forgetting
Y =V(f1,f2),
weget
a naturalprojection
inducing
atangent
mapbetween the
tangent
spaces of D =D(d,
pa;f i, f2)
andH(d, pa)
at the closedpoints (X c
Y zP3)
and(X ~ Pl) respectively.
By [K4], (1.11)
there is an exact sequencewhere 03B2
=03B2X/Y
is definedby sending
aglobal section 0
of the normal sheafNX = HomOP3(FX, (9x)
to(t~1(F1), t~2(F2)),
whereis the natural map and
is induced
by ~: FX ~ (9x.
Then(i2)
the fibersof prl are
smooth and irreducible. Moreover pr1 is smooth at(X ~ V(F1, F2) g P3) provided H1(P3, FX(fi))
= 0 for i =1, 2,
cf.[K4],
th. 1.16.(i3)
Moregenerally,
let S be a local artiniank-algebra
with residue field k andlet
Xs G P3 x
S(with
idealsheaf FXS)
be any deformation of(X g P3)
to S. If thenatural map
is
surjective
for i =1, 2,
then pr, is smooth at any t Epri 1((X ~ P3)),
cf.[K4],
lemma 1.17.
(i4)
If03B2X/Y
issurjective
andH(d, pa)
is smooth at(X ~ p3),
then D is smooth at(X z
Y zP3),
cf.[K4],
prop. 3.12.(i5)
Furthermoreby [K4],
th. 2.6 there exists anisomorphism
of schemes which on the
underlying
sets of closedpoints
is definedby sending (X g
y,-P3)
to(X’ ~
Y zP3)
where X’ is linked to Xby
Y Of course i inducesan
isomorphism
between thecorresponding tangent
spaces and in fact we havean
isomorphism
between the ’obstructionspaces’ A 2(X £ Y)
andA 2(X’ £ Y)
aswell, provided
thelinkage
isgeometric,
cf.[K4],
cor. 2.14.(i6)
Let X and X’ be linked via somecomplete
intersection Y oftype ( f, g).
Then one knows that
Xxjy( f + g - 4) ~
03C9X’ is thedualizing
sheaf of X’ fromwhich one
easily
proves theduality
So if n =
s(X/Y)
is the leastinteger satisfying H0(Y, FX/Y(n)) ~ 0,
weget
and two
corresponding
formulasinterchanging X
and X’.Of course if D =
D(d,
Pa;f),
then(il), (i2), (i3)
and(i4)
are still true,slightly
reformulated.
1. General non-obstructedness
A maximal rank curve of diameter 1
(i.e.
whosedeficiency
module has diameter1)
is known to be non-obstructed under some conditions on its numerical character([MR]).
In this section we shall provethat,
without thisassumption
on the numerical
character,
any such curve admits a non-obstructedgeneriza-
tion with the same
cohomology. By
theirreducibility of HF,
this is theequival-
ent to the
following
PROPOSITION 1.1. A
generic
Buchsbaum curve Xof
maximal rank andof
diameter 1 is non-obstructed.
Proof.
We link X via somecomplete
intersection Y oftype ( f, g) satisfying Hl(p3, FX(v))
= 0 for v =f, g, f - 4,
g -4,
and weget
a curve C withe(C) c(C)
and
H1(P3, FC(v))
= 0 for v= f, g by (i6).
Since(i2) implies
that pr1 andpr’1: D(d’, p’a;f1,f2)
-H(d’, p’)
are smooth at(X ~
Y zp3)
and(C g
y _p3) respectively,
X is non-obstructed
provided
C is non-obstructed. So theproposition
willfollow from
PROPOSITION 1.2. A
generic
Buchsbaum curve C of diameter 1satisfying e(C) c(C) is
non-obstructed.In the
proof
of(1.2)
and in several otherplaces
in this paper we need to determinehl(X, NX)
and relatedobjects
in terms of some of the invariants of aminimal resolution
of
I(X).
Note that
pdRI(X) 2, since I(X) ~ ~v 0393(P3, 7(Y)(v)),
i.e.depthm I(X)
2.Moreover
by non-obstructedness,
lemma 1.3 alsogives
us the dimension of the Hilbert schemes involved inproposition
1.1 and 1.2. We sketch aproof
sincethe version in
[K4],
section4,
is somewhat more restrictive.In the
sequel, vHomR(M, -)
denoteshomomorphisms of graded
R-modules ofdegree
v.If rm (M)
is the group of sectionsof M with support
inV(m) G Spec(R),
i.e.
we
denote by v Extim(M, -),
resp.Him(-),
theright
derived functor of0393m(HomR(M, -))v,
resp.of 0393m(-).
LEMMA 1.3. Let X be a Buchsbaum curve in
p3
and letH(X)
=~vH1(X, (9x(v».
Then there is an exact sequencewhere
fi
iscorrespondingly defined
as in(il)
and where E is determinedby
the exactsequence
In
particular, if
diam X 2 ande(X) b(X),
thenfi
issurjective. If
in additione(X) s(X)
andc(X)
n2jfor any i,
thenH1(2, % x)
= 0.COROLLARY 1.4.
If
X is a Buchsbaum curve with 1diam X
2 ande(X) c(X) s(X),
orif
X is anarithmetically Cohen-Macaulay
curve withe(X) s(X),
thenH1(X, % x)
= 0.Proof of
1.3.Let M be a
graded
R-module andput
7 =I(X). By [SGA2],
exp.VI,
there isan exact sequence
and a
spectral
sequenceEp,q2
=oExtP(I, H" (M» converging
tooExtf:.+q (I, M).
First let M = I and observe that
ExtiOP3(, ) ~ Hi-1(X, NX)
for i =1, 2, by
[K1],
remark 2.2.6.Since
depthmI 2,
i.e.Him(I)
= 0 for i1,
thespectral
sequence for p + q = 2 and thetriviality
of the R-module structure ofM(X)
=H2m(/) imply
The same
arguments imply
the second exact sequenceof (1.3) provided
we letE =
0Ext3m(I, 1».
In fact thespectral
sequence for p + q = 3gives
us the exactsequence
and
H3 m(I)
=H(X). Moreover,
thesurjectivity
ofd2, -l
follows from thespectral
sequence for p + q = 4 because0Ext4m(I, I)
= 0by continuing
thelong
exact
sequence(*).
The
proof
of the existence of the two exact sequences is nowcomplete
if weshow that
To prove
it,
we observe that0Ext2R(I, -)
isright-exact,
and thisimplies
theexactness of
Since the module structure of
M(X)
istrivial,
it isenough
to prove thatHowever
by
Serreduality
anddepthmR( - v)
=4,
Indeed the
isomorphism
on theright
side followsdirectly
from the exactsequence
(*)
withM = R( - v),
since thespectral
sequenceimplies 0Extim(I, R(-v))
= 0 fori 3
becausedepthm R( - v)
= 4.Finally
supposee(X) b(X).
Since it is well known thatn1i max{c(X)
+2, e(X)
+3}
and since the diameter ofM(X)
is at most2,
weget nli -4 b(X).
Sofi
issurjective
andH1(X, NX) ~ E.
Howevere(X) s(X) implies immediately oHom(I, H(X))
= 0 and soc(X) n2i implies
E = 0by
the second exact sequence of(1.3)
and theproof
of(1.3)
iscomplete.
REMARK 1.5. In
general
one may prove that the dimension of the k-vectorspace
oHomR(I(X), H(X))
of lemma 1.3 isIn
fact, using
thespectral
sequenceEp,q2 (with
M =I )
in theproof
above and0Extim(I, 1)
= 0 for i =4,
5 weget EP 3
= 0 for p =1,
2 and we concludeeasily by applying oHomR( -, H3 m(I»
to the minimal resolution of I.COROLLARY 1.6. Let X be a maximal rank Buchsbaum curve, with
e(X) s(X).
ThenH1(X, NX) ~ EB i H1(P3, FX(ni - 4»V,
where theni’s
are thedegrees of
a minimal setof
generatorsof
thehomogeneous
idealI(X).
Proof.
Since X is of maximalrank, H1(P3, FX(Xji)
= 0for j = 1, 2,
3 and any i.Moreover
e(X) s(X) implies oHom(I(X), H(X)) = 0,
and the conclusion followsimmediately
from the two exact sequences of lemma 1.3.LEMMA 1.7. Let C be a curve
of
diameter 1 with s =s(C),
e =e(C),
c =c(C),
and suppose e c. Then there exists a
complete
intersection Y 1? Cof
type(s,
c +2) linking
C to C’ such that1 t
follows
that either(i) c(C’)
c -1,
so there exists acomplete
intersection Y’ ;2 C’of
type(s,
c +1) linking
C’ to C" such thate(C")
= e -1, c(C")
= c -1, s(C")
s - 1or
(ii)
c s - 2(in fact
we haveequality).
Proof.
The existence of Y follows from thegeneral
fact thatJ c(v)
isglobally generated
for vmax{e(C)
+3, c(C)
+2},
and now theinequalities
fors(C’), c(C’)
ande(C’)
follows from(i6). By
the samearguments
andby e(C’)
+3
c +1, (i)
is trueprovided c(C’)
+2
c + 1. So if(i)
is not true, thenc(C’)
c, and we concludeby c(C’)
= s - 2.The
key
lemma in theproof
ofproposition
1.2 is thefollowing:
LEMMA 1.8. Let C be a
generic
Buchsbaum curve inp3 of
diameter 1 andsuppose e c and s + 1 c. Then link C to a curve C’
using
asufficiently general complete
intersection Y=V(F, G) of
type(s,
c +2) containing C,
and link C’ to acurve X
using
ageneral
Y’ =Y(F’, G’) of
type(s,
c +1) containing
C’. Then X is ageneric
Buchsbaum curve, and Y’ is ageneral complete
intersectioncontaining
X.Moreover
if
X isnon-obstructed,
then C is non-obstructed.Proof.
C’ must be ageneric
Buchsbaum curve and Y isgeneral
withrespect
to C’ because for anygenerization C’
of C’ with the samecohomology,
there existsa
complete
intersectionY ;2 C’
oftype (s,
c +2)
such that the curve linked toC’
by Y
is agenerization
ofC,
cf.[K4],
prop. 3.7. The sameargument
forgenericness
works for X and Y’ as well.Now observe that C is non-obstructed if and
only
if C’ is non-obstructedthanks to
(i2)
and theisomorphism
i of(i5)
of the introduction andIn the same way
is seen to be smooth at
(C’ z
Y’ ~P3).
However theprojection
is not
necessarily
smooth at t =(X c
Y’ ~p3),
sinceh1(P3, Jx(s»
=h1(P3, FC’(c - 3))
=h1(P3, FC(s
+1))
is not zero in the case c = s + 1. If c > s +1,
then pri 1 is smooth at t, and so C’ and C are non-obstructed since X is non-
obstructed.
Now suppose c = s + 1 and X is non-obstructed. To
complete
theproof
it isenough
to prove thatD(d,
pa; s, c +1)
is smooth at t. First suppose that F’ is a minimalgenerator of I(X).
In this case the mapfi of (1.3)
issurjective,
and so isthe map
of
(i4),
and hence we concludeby (i4).
Finally
suppose that F’ is not a minimalgenerator
ofI(X).
Since we canassume that Y’ =
V(F’, G’)
is ageneral complete
intersection oftype (s,
c +1) containing X by
the firstpart
of theproof, I(X)
contains no minimalgenerators
ofdegree s
=c(X).
(In
fact if F’ is not minimal andI(X)
contains a minimalgenerator of degree s,
then one may also use the
following proposition
2.1 to see that C’ - and so C is not ageneric
Buchsbaumcurve).
It follows that
H1(P3, fx(ni»
= 0 for anyi,
where theni’s
are thedegrees
of aminimal set of
generators
ofI(X). By [K2],
remark 3.7 orby [PiS],
thegraded
deformations of R - A =
RII(X) (in
thecategory
of local artiniank-algebras S
with residue field
k)
and the deformations of X zp3 correspond uniquely.
Wewill use this
correspondence
and the criterion(i3)
to prove that pr1 is smooth att. So let
Xs ç; P3S, p3
=p3
xSpec(S),
be a deformation of X zp3
to a local artiniank-algebra
S. Then there exists agraded
deformationRs - As
ofR - A =
R/I(X)
to S suchthat, applying
theProj-functor,
weget
backXs g p3
Put
Is
=ker(RS - AS)
andI(XS) = ~v H0(P3S, J’xs(v»
and observe that there exists amorphism Is
~I(Xs)
sinceI(XS)
is thelargest homogeneous
ideal inRs
which defines
XS ~ P3S.
SinceAS
is S-flat andAS ~S k ~ A,
it follows thatIS ~S k ~ 7(X),
i.e. thecomposition
is an
isomorphism.
Inparticular
the mapI(XS) Os
k -I(X)
issurjective,
and sois
surjective
for every v, and we concludeby (i3).
Proof of proposition
1.2.By
lemma 1.7 there exists a finite sequence of doublelinkages
where each double
linkage Ci - Ci+1
isperformed using complete
intersections oftype (s, c
+2)
and(s, c
+1),
where s =s(Ci)
and c =c(Ci),
and at theend we have
c(Ck) s(Ck) -
2. Moreoverby
1.7 we havee(Ci) c(Ci)
andc(Ci) - s(Ci) c(Ci-1) - s(Ci-1).
In
particular
there exists aninteger n
such thatc(Ci) s(Ci)
+ 1 for i n andc(Ci) s(Ci) for n
i k.By corollary 1.4, H’(C,,, % cn)
= 0 andby
lemma 1.8Ci,
for i n, is non-obstructedprovided Ci+1
is non-obstructed. Thiscompletes
the
proof.
2.
Techniques
forconstructing
obstructed curvesIn this section we consider différent
techniques
forconstructing
obstructedcurves
(of
maximalrank). Inspired by
Sernesi’sexample [S],
Ellia and Fiorentini(cf [EF])
succeeded ingiving
a criterion for obstructednessusing
the Liaison- invariance ofA2(X ~ Y).
Their result wasgeneralized
in[K4], leading
to asimple criterion,
cf.[K4]
th.3.18,
for the obstructedness of a bilinked curve. Wewere not able to find obstructed curves of maximal rank
using
theseprevious
results. The
following proposition provides, however,
a tool forconstructing
smooth obstructed maximal rank curves, and can be used to
complete
theproof
of
proposition
1.2.PROPOSITION 2.1. Let X be a Buchsbaum curve with 1
diam X
2 ande(X) b(X), let f be an integer satisfying HI(P3, fx (f»
~ 0 and supposes(X) f
and that
I(X)
contains a minimal generator Fof degree f. Let F 0
be a non-minimal generator(i.e. F 0 = 03A3ri = 1 HiFi, Fi
EI(X)
anddeg Fi deg F 0,
1 ir) of degree
f,
and link X to a curveC,
resp. to a curveCo, using
acomplete
intersectionof
theform
Y =V(F, G),
resp.Yo
=V(F 0’ G),
where G EI(X)
isof degree g c(X)
+ 1.If
HI(p3, FX(g - 4)) = 0,
then(i) Co
is an obstructed curve, andif
F issufficiently general,
then C is agenerization of Co
in the Hilbertscheme;
(ii)
C is non-obstructedprovided
X is non-obstructed.Furthermore
if g b(X)
+ 3 ande(X) b(X),
then C andCo
areof maximal
rank.Proof.
To prove thatCo
isobstructed,
we first claim that dimA1(X ~ Yo)
> dimA1(X ~ Y).
For this we consider the exact sequence of
(il)
of the introduction and thecorresponding
sequenceinvolving Ai(X ~ Yo).
We observe that03B2X/Y
is sur-jective by
lemma 1.3 since F is a minimalgenerator
ofI(X)
andHI(p3, fx(g»
= 0. The
corresponding
map03B2X/Yo
of X ~Yo
is however zerosince, by
definition of
03B2X/Yo,
we havewhere
is the map induced
by ’multiplication’
withHi
E R. So03B2X/Yo
sincet/lHi
= 0 forBuchsbaum curves.
Now recall the exact sequence
and the similar one for
FX/Yo.
Since Y andYo
arecomplete
intersection of thesame
type,
for every v. The exact sequence
of (i1)
thereforeimplies
and the claim follows from the
assumption H’(P’, FX(f)) ~
0.Next we claim
that to
=(X ~ Y0 ~ P3)
isobstructed,
i.e. that theHilbert-flag
scheme D =
D(d, pa; f, g)
issingular
at the closedpoint
to.Suppose
D is non-singular
at to, and let W z D be theunique
irreduciblecomponent containing
to.Since t =
(X g
Y zP3) and to
are in the same fiber of pr,: D ~H(d, pa)
andsince the fibers of pr are irreducible
by (i2),
then t ~ W. Hencedim A1(X ~ Yo)
= dim(!J D,to
= dimW
dim(9D,
dimA1(X Y)
and we have a contradiction.
We now conclude
quickly.
Indeedby
the liaisonisomorphism
of
(i5),
D’ issingular at t’ = (C0 ~ Yo z P3).
Moreoverpr’1: D’ ~ H(d’, p’a)
issmooth
at t’ 0
sinceIt follows that
H(d’, p’a)
issingular
at(Co ç P3),
i.e.Co
is obstructed.Finally
theirreducibility
of the fibersof pr1 implies
that t is agenerization of to provided
Yis
general enough,
and so C is agenerization
ofCo
inH(d’, p’a).
Now
(ii)
follows from(i4)
since we havealready proved
that03B2X/Y
issurjective.
Furthermore
by (i6) Co
and C are of maximal rank and we are done.REMARK 2.2. The
proof of proposition
2.1 admits thefollowing generaliza-
tion : Let X be a curve in
P3
and suppose that there are twocomplete
intersections Y and
Yo
of the sametype (1, g)
such thatdim coker
03B2X/Y
dim cokerf3 XIY o.
If H1(P3, FX(f - 4))
=H1(P3, FX(g - 4))
=0,
then the curveCo
linked to Xby Yo
is obstructed.At least under some more extra
assumption
on the curve X of(2.1)
we canprove that the obstructed curve
Co
is in the intersection of two irreduciblecomponents
of the Hilbert scheme.PROPOSITION 2.3. Let X be a
generic
Buchsbaum curve inLn
withe(X) c(X), s(X) c(X),
and suppose that the number mof minimal generators of
I(X) of degree f
=c(X) satisfies
1 m n.If Fo, F, G,
C andCo
are as inproposition 2.1,
thenCo
sits in the intersectionof two
irreduciblecomponents Vi
and Y2 of
the Hilbert scheme. Moreover(C ~ P3)
eVI - V2,
and thegeneric
curveof V2 belongs to the
liaison classLn-m.
Proof. By
prop.1.2,
X isnon-obstructed,
and so itbelongs
to aunique
irreducible
component
V ofH(d, pa),
say withgeneric point (Î 9 p3).
We claimthat the number
m()
of minimalgenerators of I() of degree f
is zero. Indeedsuppose
m(f)
>0,
i.e. thatI(f)
has a minimalgenerator F
ofdegree f.
Sinceby semicontinuity e()
=e(X)
andc()
=c(X) (or c() = - ~)
it follows fromlemma 1.3 that
is
surjective.
In
general, however, 03B2/V()
= 0 for non-obstructedgeneric
curves. Infact,
since the fibers of pr 1:D(d,
pa;f) ~ H(d, pa)
aresmooth,
we haveby generic
flatness
([M2],
page57)
the existence of an open subscheme U ofH(d, p,,,),
( ~ P3)~U,
such that the restriction of pr 1 topr-11(U), pr-11(U) ~ U,
issmooth. Hence its
tangent
map at(Î 9 v(F) ç p3),
is
surjective,
and so03B2/V()
= 0by (il)
of the introduction.Now
combining
this with thesurjectivity
of03B2/V(),
weget H1(P3,f(f))
= 0.Hence
by
Riemann-Roch we haveSince
h°(P3, J(v))
=h°(P3, FX(v))
for vf by semicontinuity,
we deducem(X)
= m - n, and nowm(X)
= 0by
theassumption m
n. So we have acontradiction and the claim is
proved.
Now observe that the
arguments
above also lead to n - m =hl(P3, J(f)),
i.e. that
X belongs
toLn-m.
Moreoverby
the proven claim above it is clear that there is nocomplete
intersectionV(F1, G1) containing
X such that( ~ V(F1, G1) ~ P3)
is agenerization
of t= (X ~ V(F, G) z P3)
inD(d, Pa; 1, g)
because if such a
complete
intersectionexists,
thenFI
must be a non-minimal elementby
the provenclaim,
i.e.F1
EmI(),
and so thespecialization
F must sitin
mI(X),
i.e. we have a contradiction.Next we claim that there is a
complete
intersectionV(Fo, G)
oftype ( f g) containing
thegeneric
curveX
above such that= ( ~ V(Fo, ) ~ P3)
is agenerization
of to =(X ~ V(F°, G) g P3)
in D =D(d, p,,; f, g).
Indeed
F 0 = 03A3ri=1 HiFi
wheredeg Fi =fi f,
1 i r, and prl:D(d,
pa;fi) ~ H(d, pj
is smooth at(X c V(Fi) ~ P3) because H1(P3,JX(fi))
= 0. So forany i we have a
generization ( ~ V(Fi) g P3) of (X ~ V(Fi) g P3)
inD(d,
pa;fi),
and one may take
Fo
tobe 03A3ri=1 Hii.
In the same way,H1(P3, JX(g))
= 0implies
the existence of agenerization (X c V() ~ P3) of(X c V(G) z P3),
andthe claim follows
easily
from this. Observe thatchoosing Fo
andG general enough,
one may suppose thatFis
ageneric point
of D sinceX
is ageneric
curveof
H(d, p.).
In
conclusion,
we haveproved
that in D =D(d, Pa;f, g), to
admits twogenerizations t and 1 that t is
ageneric point
of D and thatt is
not agenerization
of t. This shows
that to
sits in the intersection of two different irreduciblecomponents
ofD,
andusing
the liaisonisomorphism
and the smoothness of
in some open subset U’ c D’
containing to, t
and7 (for instance,
define U’ to con- sist ofpoints (X’g V(F’, G’)ç;P3)
for whichHI(p3, fx,(f»=Hl(P3, fx,(g»
=0),
we haveexactly
a similar situation inH(d’, p’a).
Thiscompletes
theproof
since the smoothness of
pri
in U’ also shows that the curve linkedto X by V(Fo, G)
is ageneric
curve ofH(d’, p’)
and so itbelongs
toLn-m
since X does.REMARK 2.4.
(a) By
thearguments
in the firstpart
of theproof we
can see thata curve X in
Ln
withe(X) c(X), s(X) c(X)
must have agenerization f
in theHilbert scheme which
belongs
to the liaison classLr
where r =max(o, n - m).
(b)
If in addition to theassumption of (2.3)
we suppose m =1,
then one may prove that C is ageneric
curve of thecomponent V1
of the Hilbert scheme.Now we use corollaries 1.4 and 1.6 for
giving
anothertechnique
of con-struction of obstructed curves:
they provide
an easy way forcomputing H1(C, % c), if e(C) s(C),
when C isarithmetically Cohen-Macaulay (and
inthat case
H1(C, NC) = 0),
or whenC E Ln, n
> 0. Then the idea is to construct aflat
family {Yt}
of curves,satisfying e
s, suchthat Y
isarithmetically
Cohen-Macaulay
if t ~0,
andYo
ELn,
and then to forceYo
to have minimalgenerators
ofdegree c(Y0)
+ 4. In this situation one hasand therefore
Yo
must be obstructed.In order to
produce examples
ofapplications
of those statements and of the aboveargument
we need atechnique
fordeforming arithmetically
Cohen-Macaulay
curves to Buchsbaum curves(or,
moregenerally,
to curves which arenot
arithmetically Cohen-Macaulay).
This is
essentially
done in[BB];
but now we want to construct curves with maximalrank,
and since there is described the case of families of curves with fixedspeciality (and postulation jumping),
we now sketch theproof
for the caseof a
family
of curves with fixedpostulation.
PROPOSITION 2.5. Let Y be an even liaison class. Then there exists an
irreducibleflatfamily of curves {Yt}t~T
such that(i) Yo E y
(ii) Yt
isarithmetically Cohen-Macaulay if
t ~ 0.Moreover,
thisfamily
is withfixed postulation,
i.e.t ~
hO(P3, f Yt(n)
is constant onT for
every n.Proof.
Let F be alocally
free sheafsatisfying HI(P3, F(t))
= 0 for every t,corresponding
to the liaison class Y. This means that~ H2(P3, F(1)) ~
M up toshift,
where M is the Hartshorne-Rao module of a curve of Y. Let now G be a direct
sum
(of enough large rank)
of line bundles(of enough large degrees)
such thatthere exists an
injective morphism
of vector bundlesNow consider the
morphisms
Thanks to
[BB], 2.2,
there exist a direct sum of line bundlesP,
with rank P = p = rank G - rank F -1,
andmorphisms
such that
drop
rank in codimension two(in fact,
one lifts p = rank G - rank F - 1general
sections of[(F ~ G)/03A6i(F)](t),
where t is aninteger
such that[(F ~ G)/03A6i(F)](t)
isglobally generated;
P is thenpOP3(-t)).
Then there exists an open non void subset T of k for which the
morphism
drops
rank in codimension two, hencealong
a curveY, t E
T.Hence we have a flat
family
ofcurves {Yt}t~T
and exact sequences(and
r does notdepend
ont).
Since
HI(p3, F(n))
= 0 for every n, weget
from the associatedlong
exactsequences that
is constant on T for every n.
Moreover,
the exact sequencesshow that
since
H2(039Bt(n))
is anisomorphism
if t *0,
and thatsince
H2(Ao(n))
is zero.Hence Y
isarithmetically Cohen-Macaulay
if t ~0,
andYo E fil.
Example
2.6.Let us
apply
thisproposition, performing explicitly
itssteps,
in order toproduce
examples
of Buchsbaum curves which arespecializations
ofarithmetically
Cohen-Macaulay
curves. We concentrate on the liaison classLn.
In this case,needed vector bundle is the
tangent
bundle toP’,
let us denote itby
T.There exists an
injective morphism
(in fact,
there is asurjection 6OP3 ( - 2)
~Qp3);
let a be an
integer > 0,
and let us consider theinjective morphism
(this
will force the existence of minimalgenerators
in the neededdegree).
Now
consider,
as inproposition 2.5,
themorphisms
Thus we have two exact sequences
Note that
HI(P3, T(t))
=0 Vt,
thatT(t)
isglobally generated if t -1 (thanks
tothe Castelnuovo-Mumford
lemma)
and that[6OP3(2)
0aOP3](t) (and
hisquot-
ienttoo)
isglobally generated
if t 0.Hence we can choose P =
(5
+a)OP3(-1),
and find twomorphisms
whichdrop
rankalong
a curveAs in
proposition 2.5,
we have afamily
ofcurves {Yt}t~T
definedby
exactsequences of the form
where
Y0~L1 and Y
isarithmetically Cohen-Macaulay
if t ~ 0.One can
compute
thecohomology
functions of these curves and findThis forces
Yo
to havegenerators
indegree b
=c(Yo)
+4,
and thereforeH’(YO, Xy.) *
0. Sincee(Yt) s(Yt) b’t,
we haveH1(Yt, NYt) = 0
if t ~ 0.Hence Yo
cannot
correspond
to a smoothpoint
of the Hilbert scheme.REMARK 2.7.
Starting
with T (BH,
where H is a direct sum of linebundles,
orchanging
the twists of the line bundles in thisconstruction,
onegets
differentexamples, always
inL1.
REMARK 2.8. Note that
Yo
has maximal rank. Note moreover that in this waywe are not able to check that there is a smooth obstructed maximal rank curve in
LI,
even if there are smooth curves inLI with
the samecohomology
function ofYo.
3. An
example
of obstructed smooth space curve of maximal rankIn this
section, using Prop. 2.5,
we willproduce
concreteexamples
of obstructed smooth connected maximal rank curves.Let Y be a smooth connected maximal rank curve of
degree d( Y)
= 24 andarithmetic genus
pa(Y)
= 66 with an Q-resolution of thefollowing
kind(see [C],
th. 2.3 for the existence of such
curves):
Note that Y is an
arithmetically
Buchsbaum curve with thefollowing
invariants:
03C3(Y)
=e( Y)
=5, s(Y)
=6, c(Y)
= 4 andM(Y) ~
k(i.e., Y~L1).
Itsnumerical character
([BM])
is(8, 7, 7, 6, 6),
and hence the existence of such asmooth curve follows also from
[BM],
th. 5.3.We link Y to an
arithmetically
Buchsbaum curve Xby
means of twogeneral
surfaces
S6
andSq
ofdegrees
6 and 9respectively containing
Y(this
ispossible
since
Yy(8)
isglobally generated).
Thanks to[PS],
prop.2.5,
the ideal sheafJX
of X has a
locally
free resolution of thefollowing
kind:In
particular, e(X)
= 5s(X)
= 6c(X)
=7,
and thehomogeneous
idealI(X)
of X has two minimalgenerators
indegree
6 and at least one minimalgenerator
indegree 7,
let us call themF6, G6
andF 7.
Let now
Co
be a curve linked to Xby
means of H ·F6
+ H’ ·G6
andF9,
whereF9
is ageneral
surface ofdegree
9containing Co
andH,
H’ aregeneral planes.
Invoking [PS],
prop. 2.5again
weget
alocally
free resolution ofJ Co
Furthermore, deg(Co)
=33, Pa(CO)
=117, s(Co)
=7, c(Co)
=5, 03C3(C0) = e(Co)
= 6.So, Co
has maximal rankand, by
prop.2.3,
it is obstructed(more, precisely,
it is in the intersection of two irreduciblecomponents
of the Hilbertscheme).
It remains to prove that between the
Co’s
constructed in such a way there is asmooth connected curve; that is to say,
choosing suitably
Y and the surfaces wecan construct a smooth curve with the
required properties.
To this
end,
we useMacaulay ([BS]).
We constructexplicitly Y,
K andCo, performing
a sequence of directlinkages starting
from thehomogeneous
ideal oftwo skew lines
(xz,
xt, yz,yt). Macaulay gives
us a minimalsystem
ofgenerators of I(Y), I(X)
and thenof I(Co),
and then we checkthat Y,
X andCo
are smoothconnected space curves.
The
computations
are ratherlengthy,
so we omit them. Weonly
write here theminimal
system
ofgenerators
ofI(Co);
note that it isgenerated by
7 elements(5 of degree 7, 1 of degree
8 and 1of degree 9); unfortunately
thesepolynomials
arehuge.
We list the 7polynomials
from thecomputer printing,
where the curve iscalled bkm.
REMARK 3.2. Note that the obstructed smooth maximal rank curve
Co
constructed