C OMPOSITIO M ATHEMATICA
H EIKKI A PIOLA
Characterization of subspaces and quotients of nuclear L
f(α, ∞)-spaces
Compositio Mathematica, tome 50, n
o1 (1983), p. 65-81
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65
CHARACTERIZATION OF SUBSPACES AND
QUOTIENTS
OFNUCLEAR Lf (03B1, ~)-SPACES
Heikki Apiola
@ 1983 Martinus Nijhoff Publishers, The Hague. Printed in the Netherlands
Introduction
In a series of
important
papers([15-20])
D.Vogt
and M.J.Wagner study
the structure of
subspaces
andquotients
of some classes of nuclear Kôthe spaces.They
are able togive
acomplete
basis free characterization in thecase of stable power series spaces thus
completing
andgeneralizing
to thebasis free
setting
thestudy
carried outby Alpseymen, Dubinsky,
Robin-son and
Wagner
in[2], [4], [5]-[9], [21] and [22].
The method of
Vogt
andWagner
can bebriefly
described as acombination of the
following steps: (1) Proving
that under suitabletopological
conditionsconcerning
the Fréchetspaces E
andF,
a shortexact sequence of the form 0 - E - G - F - 0
splits. (2) Constructing
exact sequences of power series spaces of the form
0 ~ ^r(03B1) ~ ^r(03B1) ~
0.
(3) Using
a suitablegeneralization
of the Komura embed-ding
theorem.The purpose of the
present
paper is tostudy
to which extent thismethod can be further
generalized
to cover a wider class of nuclear Kôthe spaces. We first introduce a relation called Sconcerning pairs
ofFréchet spaces and prove two forms of
splitting
theoremsusing
thisrelation. These
splitting
criteriaalong
with suitablegeneralizations
of thetwo other
steps
described above allow us to characterizesubspaces
andquotients
of nuclearLf ( a, 00 )-spaces.
As aspecial
case,assuming
thesubspace
to have abasis,
weget
the result ofAlpseymen [2]
111.1. Thequotient
space case is new even in the case of aquotient
with basis.We
hope
that the ideasdeveloped
in this paper will find furtherapplications
in the structuretheory
of nuclear Fréchet spaces. Reference[3]
can beregarded
as anexample
of such anapplication,
which is also the reason for outstating
some of thepresent
results in a moregeneral
form than would be necessary for the needs of this paper.
At this
point
1 would like to express mygratitude
to EdDubinsky
forinviting
me to ClarksonCollege
and for his kindhospitality during
my visit. 1 amespecially happy
about his active interest in my work as well asthe work of the whole functional
analysis
group in Finland. 1 would alsolike to thank D.
Vogt
and M.J.Wagner
forproviding
me with several of theirpreprints.
Needless to say, this paper isstrongly
influencedby
theirwork.
0. Preliminaries and notation
This paper will deal
exclusively
with Fréchet spaces, i.e.locally
convexmetrizable linear spaces. The main interest will be on nuclear and Schwartz spaces, i.e. reduced
projective
limits of Banach spaces withnuclear,
resp.compact linking
maps. We shall use the abbreviations(F)-, (NF)-, (FS)-space respectively.
By
asubspace
we shall mean a closed linearsubspace
which isusually
understood to be infinite dimensional. If M is a set in an
(F)-space E,
we denoteby sp(M)
its closed linear span.By
afundamental
systemof
seminorms, or
equivalently
a seminormbasis,
we shallalways
mean asequence ...
such that thecorresponding
unit balls form aneighborhood
basis of theorigin. If
is a continuous seminorm on thespace E
and ifU
is thecorresponding
unitball,
we shall use thenotations:
Ej = U =
thecompletion
of the normed spaceE/ker E’j
= the dual ofEj
= the linear span ofUJ0
in E’. For1 E
E’ we let=
supx~Uj|f(x)|~ [0, oo ].
The restrictionof on E’j
defines the usual dual norm.By
the absolute basistheorem,
every(NF)-space E
with a basis( xn )
can be identified with a Kôthe sequence space
K(a),
where a =(ank) =
(II x n Il k)’
The matrix a is called arepresentation
of(E, (xn)).
If E isnuclear
(resp. Schwartz),
therepresentation a
can be so chosen that(ank/ak+1n)n ~ ~1, (resp. c0).
The natural system of seminorms inK(a)
isunderstood to
be .
In the nuclear case thesystem 03BE ~
supn|03BEn|akn
isequivalent
to this. We shall make theslightly
unconven-tional
agreement
that ourrepresentations always correspond
to a semi-norm
basis,
which means that the unit balls(rather
than the--balls)
ofthe
corresponding
seminorms form aneighborhood
basis.The dual of Kôthe space
K(a)
can be identified with the set of sequences(~n)
such thatl11n 03BCakn
for some IL > 0 and some k. Iff = (~n) ~ K(a)’, then ’k
= the infimum of the aboveit’s
=supn(|~n|/akn),
where the conventions0/0
= 0 anda/0
= 00 for a > 0 areused.
Especially, if f = em = the
mth coordinate vector inK(a)’,
thenIlf Ilk = em’k = 1/akm.
The Kôthe spaces of
special
interest to us are theLf(03B1, oo )-spaces
introduced
by Dragilev [ 10]. Here f is
astrictly increasing
odd function in thereal line, logarithmically
convex on thepositive
axis(i.e. log 0 10
exp isconvex)
and a =( an )
is anincreasing
unbounded sequence, called anexponent sequence. We shall refer to a function
f
with the above proper- ties as aDragilev function.
The spaceLf(03B1, (0)
is then defined to be the Kôthe space withrespect
to the matrix(ef(k03B1n)).
Thespecial
casef
= idgives
us the infinitetype
power series spaces. Our main interest will be in the case wheref
is arapidly increasing Dragilev function,
i.e.limt~~(f(at)/f(t))
=00 for all a > 1 and( «n )
is a stableexponent
sequence, i.e.
supn(03B12n/03B1n)
00. The latter condition isequivalent
toLf(03B1, ~) being isomorphic
to its Cartesian square.For details of the above discussion and for
unexplained
standardconcepts
and notation the reader is referred to[8], [11 ] and [12].
1.
Splitting
of exact séquences of Fréchet spaces1.1. DEFINITION: Let E and F be
(F)-spaces
with fundamentalsystems (·k)
and(·p)
of seminormsrespectively.
We say that(E, F) ~ S
ifThe definition is
clearly independent
of theparticular
fundamentalsystems.
Thefollowing
fact is an immediate consequence of the defini- tion :1.2. PROPOSITION: Let
(E, F) ~
S.If E1 is isomorphic
to aquotient of
Eand
if F1 is isomorphic
to asubspace of F,
then(E1, FI)
E S.Let us next consider the relation S in the case where either one of the spaces E or F is a Kôthe space. If
( K( a ), F) ~ S,
thenchoosing
forf
in(1)
then t h coordinate
functional withrespect
to the canonical basis ofK(a),
weget
thefollowing:
If
( E, K(b)) ~ S,
thenchoosing
for x in(1)
thenth
basis vector ofK(b),
we get
In fact
SI (resp. S2)
isequivalent
to S in case E(resp. F)
is a Kôthespace as will be shown in the next two
propositions.
1.3. PROPOSITION: Let E and F be
(F)-spaces
and assume E to have anabsolute basis. The
following
conditions areequivalent:
(i) ( E, F) ~
S.(ii)
There exists an absolute basis(xn)
such that((E, (xn))’ F) E SI’
(iii)
For all absolute bases( xn ) of quotients of E, ((sp(xn), (xn)), F) E SI’
PROOF:
(i)
~(iii)
follows from 1.2 and the discussionfollowing
it.(iii)
-(ii)
is trivial.(ii)
-(i) :
Let(akn)
be arepresentation
of(x n)’ By
theS1-assumption,
Let
f = (~n)
EK( a )’. Multiplying
both sides of the aboveinequality by
|~n|, taking
sup over n andremembering that ’k = supn(|~n|/akn),
weare led to condition S. 0
The
proof
of thecorresponding
fact aboutS2
isanalogous
and will be omitted.1.4. PROPOSITION: Let E and F be
(F)-spaces
and assume F to have anabsolute basis. The
following
conditions areequivalent:
(i) (E, F)
E S.(ii)
There exists an absolute basis(yn)
in F such that( E, ( F, (yn))) ~ S2 . (iii)
For all absolute basic sequences(yn)
inF, ( E, (sp(yn), (yn))) E S2.
The next lemma will serve as a
preparation
for the firstsplitting theorem,
which is one of the two main results of this section.1.5. LEMMA: Let
K(c)
be a Kôthe space with a continuous norm and let(Vp)
be aneighborhood
basis in an(F)-space
F.If (K(c), F)
ESI’
thereexists a
representation (akn) of
the canonical basisof K(c)
such that~p~q~k~r
=r(k, q):3
PROOF:
Choose p according
to the definition ofproperty SI
andproceed
by
induction as follows:For j
= 0 choose k =k
1 such that~~~q~r(0,~, q) ~
Having
chosenk 1, ... , km _ 1, take j
=km _ and
denote thecorresponding
k in the definition of
S1 by k
=km .
Thisgives
us a sequence( k, )
and afunction
r(i, ~, q )
such thatNow, given i, choose ~ = ki+1.
Then the matrix(a1n) = (c k, )gives
us thedesired
representation.
~T
1.6. THEOREM: Let 0 ~
K(a) ~
G - F - 0 be an exact sequenceof (NF)-spaces
and assumeK(a)
to have a continuous norm.If (K(a), F)
ESI’
the sequencesplits.
PROOF :
Identify K(a)
with Ker T and assume that therepresentation
a ischosen
according
to 1.5. Thenuclearity
allows us to use the sup-norms, thus Ker T =K(a)
is the reducedprojective
limit of the Banach spacesLet Pk:
K(a) ~ Kk
and pm,k:Km ~ Kk
for m > k be the inclusion maps.Then we have the canonical commutative
diagrams:
Pk = Pm,k 0 Pm form > k. Our aim is to extend the
mappings
Pk to the whole of G in such a manner that the extendeddiagram
also commutes for m > k.By
thenuclearity
ofK( a ),
themapping
Pk is nuclear for eachk,
henceadmits an extension to G. Let’s denote such an extension
by Fk
and letAs
G, IKer
T =0,
there existsGk
EL ( F, Kk )
such thatGk
=Gk -
T.Let fn(03BE) = 03BEn for 03BE ~ Kk -
It follows from thenuclearity
of F thatGk
isnuclear,
hence admits arepresentation
where
( a n ) n
isequicontinuous
inF’, (yn)n
boundedin Kk
and(03BEn) ~ ~1.
From this and the fact that
= 1 la n k
it followseasily
that the set{aknfn ° Gk}n
isequicontinuous
in F’ for each k. DenoteGn = fn ° Gk .
Weshall next construct a
neighborhood
basis(Vk),
in F such that{aknGkn}n
cV k 0 and
(where
means the same asV0).
The construction goes as follows: We shallpick
a suitablesubsequence
of ourgiven neighborhood
basis(Vp)
(and
relabel theindices).
Startby taking V = lg according
to 1.5.By
theequicontinuity
of the sequence{a1nG1n}n
we canpick
aneighborhood VI
such that
{a1nG1n}n
cVlo. Having
chosen theneighborhoods V1, ... , Vk
weapply
1.5 withVq = 2-k-1Vk .
Theneighborhood Vr(k,q)
will be denotedby Vk+1
and it will be chosen smallenough
to ensure the inclusionV0k+1.
Thiscompletes
the construction.Formula
(1) implies
The rest of the
proof
ispractically
the same asVogt’s proof
of[15] 1.5,
c.f. also[16]
2.2. So we shallonly give
a brief outline.The fact that
Gn
E(1/akn)V0k together
with(2)
enables us todefine,
forfixed n,
inductively
a sequence(Akn)k
in F’ such thatNow define the
operator Ak :
F -Kk by Akx
=(Aknx)n.
LetÃk = Ak ° T
and 7Tk =
Fk - Ak . Using (3)
we infer that for all m and all x G G there existslimk~~03C1k,m° 03C0k(x)
which will be denotedby m(x).
It is noweasy to check that the
mapping
x -(’"mx)m
defines a continuousprojec-
tion of G onto Ker T. Thus Ker T is
complemented
and so our exactsequence
splits.
0To prove our second
splitting
theorem we shallagain begin
with alemma,
which is in a sense dual to Lemma 1.5. Theproof
isanalogous
and will hence be omitted.
1.7. LEMMA: Let E be an
( F )-space
and letK(b)
be a Kôthe space with acontinuous norm.
If (E, K(b))
ES2,
there exists aneighborhood
basis(Uk)k in E
such that~k~j~~(k, j) ~
((Uk)
can be chosen as asubsequence of
anygiven neighborhood
basis inE.)
We shall
give
the secondsplitting
theorem in agenerality
thatslightly
exceeds the needs of this paper but will be needed in
[3].
q
1.8. THEOREM: Let 0 ~ E ~ G ~ F ~ 0 be an exact sequence
of (NF)-
spaces. Let
K(b)
be a(not necessarily nuclear)
Kôthe space with acontinuous norm and let H be a
subspace of K(b).
Assume that(E, K(b)) ~ S2.
Thenfor ail cpEL(H,F)
there exists alifting 03C8,
that is03C8 ~ L(H, G’) and ~ = q ° 03C8.
PROOF:
By nuclearity,
we can start out with a Hilbertianneighborhood
basis
(W’k)
in G. LetUk
= E nWk . By
1.7 we can choose aneighborhood
basis
( Uk )
inE,
which is asubsequence
of( Uk )
andLet
(Wk)
be theCorresponding subsequence
of the(W’k)-basis. Taking Vk = q(Wk)
anddenoting Ek
=EVk’ Gk
=G Wk, Fk
=Êvk,
we have theexact sequence
Let now
H ~ K(b) and ~ ~ L(H, F).
We have for each k thefollowing
canonicaldiagram:
Define
~k
= l1k o ~.By
thenuclearity
ofF,
themapping ~k
is nuclear for eachk,
henceadmits
a nuclearlifting 03C8k : H ~ Gk.
Let X k =03C1k+1,k° 03C8k+1 - 03C8k.
Then qk °~k = 0,
henceIm(~k) ~ Ek. Now,
X k is nuclear considered as amapping
intoGk
andEk
iscomplemented
inGk (because Gk
is a Hilbertspace),
thus X k :H ~ Ek
is also nuclear.Therefore there exists an extension
k : K(b) ~ Ek .
Setxn, k = k(en) ~ Ek,
where( en )
denotes the coordinate basis inK( b ). By
thecontinuity
ofk
there exists a function k Hm(k)
such thatWe want to choose a
representation (call
it(bkn) again)
such thathold for all n and k. So fix n and
apply (1) for j = m(l),
k = 1. Letv (2)
=max{~(k,j), m(2)}.
Nextapply (1) for j
=v (2),
k = 2 and choose03BD(3)
=max{~(k,j), m(3)}. Continuing
this way anddenoting b03BDn(k) by bn
we
get
the desiredrepresentation.
The rest of theproof
goesexactly along
the lines of the
proof
of[19]
1.4 and will therefore be omitted. D 2.Properties D3( f )
andD4( f )
In what follows we shall denote
by f
arapidly increasing Dragilev
function
satisfying
thefollowing
condition:This will cause no loss of
generality
because of[8] Proposition
1.5.4.2.1 DEFINITION: Let E be an
(F)-space
with a continuous norm and let... be a fundamental
system
of norms in E. E is said to have propertyD3(f)
if2.2. DEFINITION: Let E be an
(F)-space
with a fundamental system ofseminorms
... E is said to have propertyD4(f)
ifVj3k
>It is easy to see that the above definitions are
independent
of theparticular
fundamental systems of seminorms. It is alsostraightforward
to
verify
thefollowing:
2.3. PROPOSITION:
If E
hasD3(f)
and F is asubspace of E,
then F hasD3(f). If E
hasD4(f)
and F is aquotient
spaceof E,
then F hasD4(f).
If in the above definitions we take E to be a Kôthe space
K(a)
andrequire
theinequalities
to be valid for all basis vectors or all coordinate functionalsrespectively,
we are led to thefollowing
conditions:The conditions
d3(f)
andd4(f)
were introducedby
H. Ahonen[1], d3(f)
is the" representation
invariant" form of thecondition d f
in[2]
p.42.
2.4. PROPOSITION: Let E be a nuclear
(F)-space
with a basis and continu-ous norm. The
following
conditions areequivalent:
(1) EhasD3(f).
(2)
There exists ad3(f)-basis
in E.(3)
All basic sequences in E ared3(f).
PROOF:
(1) ~ (3)
is obtainedimmediately
fromproposition
2.3 and(3) ~ (2)
is trivial.(2) ~ (1):
Let(akn)
be arepresentation
of ourd3(f)-
basis
(xn)’ By nuclearity
we can choose the system of seminorms:(The
indexqk
exists because(03BEnakn)n ~ c0.) By
the definition ofd3(f),
wecan choose an
index j
such that for all M > 1 and k there exists an 1 such that thed3(f) inequality
holds. Denote g= f-1 ° log. Now,
2.5. PROPOSITION: Let E be an
(FS)-space
with an absolute basis. Thefollowing
conditions areequivalent:
(1) E has D4(f).
(2)
There exists an absoluted4(f)-basis in
E.(3)
All absolute bases01 quotients 01 E
ared4(f)
PROOF:
Again,
there isonly
one non-trivialimplication: (2) ~ (1) :
Let( a n )
be arepresentation
of the absoluted4(f)-basis (xn)
in E.Given j,
choose k
> j
such that forall ~ >
k there exists M such that thed4(f)-in- equality
holds. In order to prove theD4(f)-inequality,
weonly
need toconsider
those y ~ El
forwhich
00.Let y E
E’ and n EN. Ifan
= 0 andy( xn )
=1=0,
it followsthat
= 00. Henceassuming,
as wedo, that
00, wehave ajn
~ 0 for all n forwhich y(xn)
=1= 0 and hencethe
d4(f)-inequality
is valid for all such n.Now,
hence
for all k
> j (because
of theSchwartz-assumption).
Thus for each k> j
there is an index
qk
suchthat = |~qk|/akqk.
Letg = f-1 ° log.
Thenfor j
k~
and M as above we haveand the
proof
iscomplete.
0The next
proposition
tells us how theproperties D3(f)
andD4(f)
areaffected
by changing
therapidity
ofgrowth
of the functionf.
RecallDragilev’s
definition[10]:
Iff
and h areDragilev
functions such that cp =f - ou
is arapidly increasing Dragilev function,
we say that h increases morerapidly
thanf
and denote h >f.
2.6. PROPOSITION:
If E
hasD3(f)
and hf,
then E hasD3 ( h ). If E
hasD4(f) and h>f,
then E hasD4(h).
PROOF: The
proofs
are verysimilar,
so let usonly
consider theD4(f)-case.
Let
gf, N(t) = expf (Nf- log t)
for N > 1. It suffices to find for agiven
N 1 an M > 1 such that
gh, M (t) gf, N(t)
for tsufficiently large.
This isdone
simply by taking
M suchthat ~(M) N~(1), where ç = f-1 0
h islogarithmically
convexby assumption.
Thisimplies
that~(Ms) N~(s)
for all s 1. The rest of the
proof
is now obvious. 0Note that the conditions
D3(id)
andD4(id)
are the same as the( DN )
- and
(03A9) -
conditionsrespectively,
introducedby Vogt
andWagner
in[15]
and[20].
The aboveproposition
tells usespecially
thatD3 ( f ) implies ( DN )
and(03A9) implies D4 ( f ),
for anyDragilev function f.
We now turn to the
study
of the connection of the conditionsD3 ( f )
and
D4 ( f )
to thesplitting
condition S. We shallbegin
with thefollowing
two
propositions,
whoseproofs
are very muchalike,
so we choose togive only
theproof
of the latter one.2.7. PROPOSITION. An
(F)-space
E hasD3(f) if
andonly if
(equivalently :
wheregM(t) =
exp f(Mf-1 log t).
2.8. PROPOSITION: An
(F) - space E
hasD4(f) if and only if Vj3kVP3M
:3
PROOF: Assume that E has
D4(f). Given j,
choose k such that forall £
there exists an M such thatFrom this it follows in a
straightforward
manner thatTaking polars
weget
Thus we
only
need to choose k’ such thatUk -
c-t Uk,
tocomplete
thefirst half of the
proof. (To
see that the statement inparentheses
isequivalent
is a standard dualizationargument.)
Conversely
assume that~j~k~~~g
= gM 3Fix j, k, ~,
Mand y E E’j
and substitute r =2
in the aboveinequality.
Thisyields
theD4(f)-condition
where instead of k we take k’such that
2
f or aily.
2.9. PROPOSITION : Let E and F be
(F)-spaces
such that E hasD4(f)
and Fhas D3(f). Then ( E, F ) ~ S.
PROOF : Let
(’k) [resp. (p)]
be a fundamental system in E’[resp. F].
As F has
D3(f),
we canchoose p
such that ~M1~q~s
such thatNow,
E hasD4 ( f ),
sogiven j
we can choose k such that forall £
there existsM(~, j)
such thatwhere
g’,j
=gM(~,j)
=exp f (M(~, j)f-1 log).Now,
for anarbitrary q
andfor M =
M(~, j), pick s
such that(1)
holds.Fix y ~ E’j
and substituter = . Hence we get:
and the
proof
iscomplete.
0This combined with
propositions
2.4 and 2.5yields:
2.10. COROLLARY:
If K(a)
hasd4(f)
and E hasD3(f),
then(K(a), E) ~ S1. If E has D4(f) and K(b) has d3(f), then (E, K(b))
ES2.
NOTE: It looks as if there were an omission in the latter statement because of the
nuclearity assumption
in 2.4. The statement of 2.10 is however correct as itstands,
as can beproved directly.
In abbreviated notation we can write the statements of 2.9 and 2.10 as
follows:
To end this
section,
we shall prove the easy halves of our characteri- zation theorems.2 .1 1 . PROPOSITION:
Lf(03B1, ~)-spaces
haveproperties d3(f)
andd4(/).
PROOF: The
d3(f)-condition
can be derived from[2]
111.1.(c.f.
also[8]
6.2.1) although
a directproof is just
as easy andanalogous
to thed 4 ( f )-case,
which we shallgive.
Given j,
choose k such thatThen,
for anarbitrary £
> k we haveHence we have
d4(f)
withM(j, ~)
=2~.
2.12. COROLLARY:
Subspaces of
nuclearLf(03B1, oo)-spaces
haveD3(f).
Quotients of Lf(03B1, ~)-spaces
haveD4(f).
PROOF.
2.3, 2.4, 2.5,
2.11.COROLLARY:
If E
hasD3(f),
then(Lf(03B1, ~), E) ~ S1. If E
hasD4(f),
then
( E, Lf(03B1, ~)) ~ S2.
3. Characterization of
subspaces
andquotients
ofLf ( a, oo )-spaces
In this section we shall deal
exclusively
withnuclear,
stableLf(03B1,
~)-spaces.
We shall say that a space E isA(f ,
a,N)-nuclear
if it isA(a, N)-nuclear
in the sense of[13],
withrespect
to the matrix a =(akn),
whereakn = exp f(k03B1n).
This isequivalent
to the condition0394(E) ~ 0394(Lf(03B1,
oo)),
where0394(E)
is the diametral dimension of E(c.f. [14]).
We shallneed the
following Komura-type
theorem due toRamanujan
and Rosen-berger [13]:
If E is aA(a, N)-Nuclear
Fréchet space, then E is isomor-phic
to asubspace
of(K(a)1B1
under certain conditions aboutK(a),
which are
certainly
satisfiedby
anuclear,
stableLf(03B1, oo )-space.
One ofthe basic facts we shall also need is the existence of an exact sequence
for any
stable,
nuclearLf(03B1, oo).
This follows from[20]
2.3.(For
aproof
of a
slightly
moregeneral
result we refer to[3].)
Let’s make the
following
conventionconcerning
the rest of the paper.All
Lf(03B1, oo )-spaces
encountered are nuclear and stable.3.1. PROPOSITION: Let E be a
A(f,
a,N)-nuclear (F)-space.
Then thereexists an exact sequence
where G is a
subspace of Lf(03B1, ~).
PROOF: Start out with the exact sequence
(1).
Embed E as asubspace
of(Lf(03B1, ~))N using
theRamanuj an-Rosenberger
theorem discussed above.Define G to be the
pre-image
of E under thequotient
map:Lf(03B1,
~) ~ (Lf(03B1, ~))N. Restricting
thequotient
map to Ggives
us thedesired exact sequence. 0
We are now
ready
to prove our first main result.3.2. THEOREM: An
(F)-space
E isisomorphic
to asubspace of Lf(03B1, ~) if
and
only if
it isA (f,
a,N)-nuclear
and hasproperty D3(f).
PROOF: The
necessity
of the conditions follows from 2.12together
with[13] 3.8 and 3.3.
To prove the
sufficiency,
assume E isA(f, 03B1, N)-nuclear
and hasD3 ( f ).
Set up the exact sequence of 3.1.proposition. By 2.13, (Lf(03B1, ~),
E ) E S1,
hence the sequencesplits by
1.6. This means that there exists anoperator
S: E ~ G suchthat q -
S =id E, where q
is thequotient
map:G ~ E. It follows that S is an
isomorphism
intoG,
which in turn is asubspace
ofLf(03B1, ~).
Thiscompletes
theproof.
0The
proof
of thequotient
space case usesagain
the samesteps
withappropriate modifications,
as thecorresponding proof
forquotients
of(s )
due toVogt
andWagner [19].
In addition to theprevious
results weshall need the
following
fact whoseproof
is standard and can be found in[19].
3.3. LEMMA: Assume that both the row and the column of the
following
commutative
diagram
of(F)-spaces
is exact:Then there exists the
following
exact sequence:3.4. THEOREM: An
(F)-space
E isisomorphic
to aquotient Of Lf(03B1, ~) if
and
only if
it isA (f,
a,N)-nuclear
and has propertyD4(f).
PROOF. The
necessity
followsagain
from 2.12 and[13] 3.8
and 3.3.To prove the
sufficiency,
assume that E isA(f,
a,N)-nuclear
and hasproperty
D4(f). Using
theRamanujan-Rosenberger embedding
theoremwe can
identify
E with asubspace
of(Lf(03B1, ~))N.
LetQ = (Lf(03B1,
~))N/E. Now, Q
isagain A(f,
a,N)-nuclear,
hence we can set up the exact sequence of 3.1with Q
in the role of E. Thus weget
thefollowing
exact row and column:
where
G ~ Lf(03B1, ~). By 2.13, (E, Lf(03B1, ~))
ES2,
hence 1.8 Theoremgives
us alifting
~. Then 3.3applies
and weget
the exact sequence:Set up the exact sequence
(1)
as a column and useagain
2.13(together
with
2.12)
and 1.8 toget
thefollowing
commutativediagram:
Finally,
3.3gives
us the exact sequence:By
ourstability assumption, Lf(03B1, oo )
~Lf(03B1, oo )
isisomorphic
toLf(03B1,
~),
so E ~ G and hence E is aquotient
ofLf (a, ~).
0We shall conclude the paper
by characterizing complemented
sub-spaces of
Lf(03B1, ~).
3.5. THEOREM: An
(F)-space E is isomorphic
to acomplemented subspace
of Lf(03B1, ~0) if
andonly if
E isA (f,
a,N)-nuclear
and hasproperties D3(f) and D4(f).
PROOF: The
necessity
is clear. To prove thesufficiency,
assume E hasD3 ( f ), D4 ( f )
and isA(f,
a,N)-nuclear.
Theproof
of 3.4gives
us anexact sequence:
where G is a
subspace
ofLf(03B1, ~). Now,
E and G haveD3 ( f ),
hencealso E ~ G
(as
can be seenimmediately).
So the sequencesplits by
2.13and 1.6.
Thus, E
fl3 G isisomorphic
to acomplemented subspace
ofLf(03B1,
(0)
and so is E. D3.6. COROLLARY: E is
isomorphic
to acomplemented subspace of Lf(03B1, 00) if and only if E is isomorphic
to asubspace
and aquotient
spaceof Lf ( a,
00 ).
Having
3.4theorem,
thequestion
arises of what spaces weget by taking quotients
of stableLf(03B1a, oo )-spaces.
It turns out that if weconsider the wider class of Schwartz
Lf ( a, oo )-spaces,
thisgives
us allnuclear Fréchet spaces. This is the
topic
of[3].
References
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Manuscripta Math. 31 (1980) 97-109.
(Oblatum 21-IV-1980)
Department of Scientific Computing
State Computer Centre
PL 40
SF-02101 ESPOO 10 Finland