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www.elsevier.com/locate/anihpc

Asymptotic behaviour and correctors for linear Dirichlet problems with simultaneously varying operators and domains

Comportement asymptotique et correcteurs pour des problèmes de Dirichlet linéaires avec des opérateurs et des domaines

qui varient simultanément

Gianni Dal Maso

a

, François Murat

b

aSISSA, via Beirut 4, 34014 Trieste, Italy

bLaboratoire Jacques-Louis Lions, boîte courrier 187, Université Pierre et Marie Curie, 75252 Paris cedex 05, France

Received 5 April 2003; accepted 2 May 2003 Available online 21 January 2004

Abstract

We consider a sequence of Dirichlet problems in varying domains (or, more generally, of relaxed Dirichlet problems involving measures inM+0(Ω)) for second order linear elliptic operators in divergence form with varying matrices of coefficients. When the matricesH-converge to a matrixA0, we prove that there exist a subsequence and a measureµ0inM+0(Ω)such that the limit problem is the relaxed Dirichlet problem corresponding toA0andµ0. We also prove a corrector result which provides an explicit approximation of the solutions in theH1-norm, and which is obtained by multiplying the corrector for theH-converging matrices by some special test function which depends both on the varying matrices and on the varying domains.

2003 Elsevier SAS. All rights reserved.

Résumé

Nous considérons une suite de problèmes de Dirichlet dans des ouverts variables (ou plus généralement une suite de problèmes de Dirichlet relaxés définis par des mesures deM+0(Ω)) pour des opérateurs elliptiques linéaires du deuxième ordre sous forme divergence avec des matrices de coefficients elles aussi variables. Quand les matricesH-convergent vers une matriceA0, nous démontrons qu’il existe une sous suite et une mesureµ0deM+0(Ω)telles qu’à la limite on obtienne le problème de Dirichlet relaxé correspondant àA0etµ0. Nous démontrons également un résultat de correcteur qui donne une approximation explicite des solutions en normeH1; ce correcteur est obtenu en multipliant le correcteur pour laH-convergence des matrices par une fonction test spéciale qui dépend à la fois des matrices variables et des ouverts variables.

2003 Elsevier SAS. All rights reserved.

E-mail addresses: dalmaso@sissa.it (G. Dal Maso), murat@ann.jussieu.fr (F. Murat).

0294-1449/$ – see front matter 2003 Elsevier SAS. All rights reserved.

doi:10.1016/j.anihpc.2003.05.001

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1. Introduction

In this paper we consider a sequence of linear Dirichlet problems uεH01

ε ,

−div

AεDuε

=f in D ε

, (1.1)

where the matricesAεand the domainsεboth depend on the parameterε. We assume that the open setsΩεare all contained in a fixed bounded open subset of Rn, and that the matricesAε, defined on with measurable coefficients, are coercive and bounded, uniformly with respect toε. Our goal is to study the behaviour of the solutionsuεasεtends to zero.

In the special caseε= it is known (see Section 3) that there exist a subsequence, still denoted by(Aε), and a matrixA0, called theH-limit of(Aε), such that for everyfH1(Ω)the solutionsvεof the problems

vεH01(Ω),

−div AεDvε

=f inD(Ω), converge weakly inH01(Ω)to the solutionv0of

v0H01(Ω),

−div

A0Dv0

=f inD(Ω), and satisfy also

AεDvε A0Dv0 weakly inL2 Ω,Rn

.

Without making any further hypothesis on the open setsε, we prove in the present paper that there exists a subsequence, still denoted by(Ωε), such that for everyfH1(Ω)the solutionsuε of (1.1) converge to the solutionu0of the problem







u0H01(Ω)L2 Ω, µ0 ,

A0Du0Dydx+

u0y0= f, yyH01(Ω)L2 Ω, µ0

, (1.2)

whereµ0belongs toM+0(Ω), a class of nonnegative Borel measures which vanish on all sets of capacity zero, but can take the value+∞on some subsets of(see Section 2).

Problems like (1.2) are called relaxed Dirichlet problems (see Section 4) and have been extensively studied to describe the limits of the solutions of (1.1) when the matricesAε do not depend on ε. On the other hand, problems (1.1) can be written as relaxed Dirichlet problems (see Remark 4.1) by considering the measuresµε defined by

µε(B)= 0, if cap B\ε

=0,

+∞, otherwise. (1.3)

Actually in the paper we consider not only the case of Dirichlet problems (1.1), which correspond to the measures µε defined by (1.3), but more in general we study the case of a sequence of relaxed Dirichlet problems with arbitraryµεM+0(Ω).

In the limit problem (1.2) the measureµ0does not depend onf, but, as shown in Section 6, it depends both on the sequence of sets(Ωε)and on the sequence of matrices(Aε)(and not only on itsH-limitA0). Nevertheless the sequence(Ωε)has a stronger influence than the sequence(Aε): indeed the limit measures corresponding to the same sequence(Ωε)but to different sequences(Aεi)are equivalent (see Theorem 8.1).

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In Section 5 we give a fairly general and flexible method to construct the limit measureµ0using suitable test functionsωε associated toε andAε. We then pass to the limit in the sequence of problems (1.1) by a duality argument and obtain (1.2).

In Section 7 we continue the study of the behaviour of the solutionsuε of (1.1) by giving a corrector result. By this we mean the following: when the solutionu0of the limit problem (1.2) can be written as

u0=ψω0, (1.4)

whereω0is the limit of the above test functionsωεandψis sufficiently smooth (actually inH2(Ω)W1,(Ω)), we prove that

uε=

ψ+ n j=1

Djψ zεj

ωε+rε withrε→0 strongly inH01(Ω), (1.5)

where the functionszεj depend only on the matrices Aε. This provides an approximation of uε in the norm of H01(Ω)by means of functions that are constructed explicitly.

When (1.4) is not satisfied with a smoothψ, a similar but more technical result holds (see Theorem 7.2). We also prove a local version of this corrector result.

Moreover, we prove (global and local) convergence and corrector results when also the right-hand side of (1.1) depends onεand converges strongly in a convenient sense (see Section 10).

Let us finally note that the case where the matricesAεand the domainsεare periodic, with periods converging to zero with different speeds, has been studied in detail by Ansini and Braides in [1]. Results similar to those proved in the present paper have been obtained by Kovalevsky in [18] for a class of nonlinear monotone elliptic equations under some geometric assumptions on the setsε, and more recently by Calvo Jurado and Casado Diaz in [6] in the general case.

2. Preliminaries on capacity and measures

In this section we first introduce a few notation. Then we recall some known results on measures, capacity, and fine properties of Sobolev functions.

2.1. Notation

Throughout the paper is a bounded open subset of Rn, n1. The space D(Ω)of distributions in is the dual of the spaceCc(Ω). The spaceW01,p(Ω), 1p <+∞, is the closure ofCc(Ω)in the Sobolev space W1,p(Ω), whileW1,q(Ω),1q <+∞, is the space of all distributions of the formf =f0+

jDjfj, with f0, f1, . . . , fnLq(Ω)(if 1/p+1/q=1, thenW1,q(Ω)is the dual ofW01,p(Ω)). In the Hilbert casep=q=2 these spaces are denoted byH01(Ω),H1(Ω), andH1(Ω), respectively. The norm inH01(Ω)is defined by

u H1 0(Ω)=

|Du|2dx 1/2

,

while the duality pairing between H1(Ω) andH01(Ω) is denoted by ·,·. We shall sometimes use also the Sobolev spaceH2(Ω)=W2,2(Ω).

The adjoint of a matrixAis denoted byA. Since complex numbers are not used in this paper, the bar never¯ denotes complex conjugation. Ifwis an object related to the matrixA, thenwdenotes the corresponding object related to the adjointA.¯

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Throughout the paperεvaries in a stricly decreasing sequence of positive real numbers which converges to 0.

When we writeε >0, we consider only the elements of this sequence, while when we writeε0 we also consider its limitε=0.

2.2. Capacity and measures

For every subsetEofΩthe capacity ofEinΩ, denoted by cap(E), is defined as the infimum of

|Du|2dx over the set of all functionsuH01(Ω)such thatu1 a.e. in a neighbourhood ofE. We say that a propertyP(x) holds quasi everywhere (abbreviated as q.e.) in a setEif it holds for allxEexcept for a subsetN ofE with cap(N )=0. The expression almost everywhere (abbreviated as a.e.) refers, as usual, to the analogous property for the Lebesgue measure.

A functionu:R is said to be quasi continuous if for everyε >0 there exists a setEΩ, with cap(E) < ε, such that the restriction ofuto\Eis continuous. A subsetU ofΩis said to be quasi open if for everyε >0 there exists an open setVΩ, with cap(VU ) < ε, wheredenotes the symmetric difference.

EveryuH1(Ω)has a quasi continuous representative, which is uniquely defined up to a set of capacity zero.

In the sequel we shall always identifyuwith its quasi continuous representative, so that the pointwise values of a functionuH1(Ω)are defined quasi everywhere in. IfuH1(Ω), then

u0 a.e. in ⇐⇒ u0 q.e. inΩ. (2.1)

If a sequence(uj)converges toustrongly inH01(Ω), then a subsequence of(uj)converges touq.e. inΩ. For all these properties concerning quasi continuous representatives of Sobolev functions we refer to [16], Section 4.8, [17], Section 4, [19], Section 7.2.4, or [27], Chapter 3.

The characteristic function 1E of a setE is defined by 1E(x)=1 ifxEand 1E(x)=0 ifx\E.

The following lemma (see [9], Lemma 1.5, or [11], Lemma 1.1) concerns the pointwise approximation of the characteristic function of a quasi open set.

Lemma 2.1. For every quasi open setU ofΩ there exists an increasing sequence(zk)of nonnegative functions ofH01(Ω)converging to 1Upointwise q.e. inΩ.

By a nonnegative Borel measure onΩ we mean a countably additive set function defined on the Borel subsets of with values in[0,+∞]. By a nonnegative Radon measure onΩ we mean a nonnegative Borel measure which is finite on every compact subset of. Every nonnegative Borel measureµon can be extended to a Borel regular outer measure on by setting for every subsetEof

µ(E)=inf

µ(B): BBorel,EB .

Ifµ is a nonnegative Borel measure on, we shall useLr(Ω, µ), 1r+∞, to denote the usual Lebesgue space with respect to the measureµ. We adopt the standard notationLr(Ω)whenµis the Lebesgue measure.

We will consider the coneM+0(Ω)of all nonnegative Borel measuresµonsuch that (a) µ(B)=0 for every Borel setBwith cap(B)=0,

(b) µ(B)=inf{µ(U ):Uquasi open, B⊆U}for every Borel setBΩ.

IfEand cap(E)=0, thenEis contained in a Borel setBwith cap(B)=0. ThereforeEisµ-measurable by (a). Property (b) is a weak regularity property of the measureµ. It is always satisfied if µis a nonnegative Radon measure. Since any quasi open set differs from a Borel set by a set of capacity zero, every quasi open set is µ-measurable for every nonnegative Borel measureµwhich satisfies (a).

Let us explicitly observe that the notation is not fixed in the literature and that in other works (see, e.g., [14]) M0(Ω)denotes the set of nonnegative Borel measures which only satisfy (a), while the set that we callM+0(Ω) in the present paper is sometimes denoted byM0(Ω)(see, e.g., [10]).

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For every quasi open setUwe define the Borel measureµU by µU(B)= 0, if cap(B\U )=0,

+∞, otherwise. (2.2)

Roughly speaking,µU is identically zero onUand identically+∞on\U. It is easy to see that this measure belongs to the classM+0(Ω). Indeed, property (a) follows immediately from the definition, and it is enough to verify (b) only for every Borel set withµU(B) <+∞; in this case cap(B\U )=0, and this implies thatV=UB is quasi open (sinceU is quasi open), containsB, andµU(V )=0 (since cap(V\U )=cap(B\U )=0), so that (b) is satisfied. The measuresµU will be used to transform a sequence of Dirichlet problems on varying domains into a sequence of relaxed Dirichlet problems on a fixed domain (see Remark 4.1 and the proof of Corollary 5.5).

IfµM+0(Ω), then the spaceH1(Ω)L2(Ω, µ)is well defined, since every functionuinH1(Ω)is defined µ-almost everywhere and isµ-measurable inΩ(recall thatuis quasi continuous, so that{u > t}is quasi open for everytR). It is easy to see thatH1(Ω)L2(Ω, µ)is a Hilbert space for the scalar product

(u, v)H1(Ω)L2(Ω,µ)=

DuDvdx+

uvdx+

uvdµ (2.3)

(see [5], Proposition 2.1).

The space of all (signed) Radon measures on will be denoted byM(Ω), whileMb(Ω)will be the space of allµM(Ω)with|µ|(Ω) <+∞, where|µ|denotes the total variation ofµ. A subsetAofM(Ω)is bounded if for every compact setKwe have

sup

µ∈A|µ|(K) <+∞.

Every Radon measure onwill be identified with an element ofD(Ω)in the usual way. Thereforeµbelongs toM(Ω)W1,q(Ω)if and only if there existf0, f1, . . . , fnLq(Ω)such that

ϕdµ=

f0ϕdx− n j=1

fjDjϕdx ∀ϕCc(Ω).

Note that, by Riesz’ theorem, every nonnegative element ofW1,p(Ω)is a nonnegative Radon measure on. The cone of all nonnegative elements ofH1(Ω)will be denoted byH1(Ω)+. It is well known that every element ofH1(Ω)+is a nonnegative Radon measure which belongs also toM+0(Ω). In other words we have the inclusionH1(Ω)+M(Ω)M+0(Ω).

3. H-convergence

In this section we recall the definition ofH-convergence and the corresponding corrector result. Moreover we prove a fairly general convergence theorem for right-hand sides which do not converge strongly inH−1(Ω).

Throughout the paper we fix two constantsαandβsuch that 0< αβ <+∞.

We defineMαβ(Ω)as the set of all matricesAinL(Ω,Rn×n)such that A(x)αI,

A(x)1

β1I, for a.e.xΩ. (3.1)

In (3.1) I is the identity matrix in Rn×n, and the inequalities are in the sense of the quadratic forms defined byA(x)ξ ξforξRn. Note that (3.1) implies that

A(x)β for a.e. xΩ, (3.2)

and that necessarilyαβ.

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3.1. Definition ofH-convergence

A sequence(Aε)of matrices inMαβ(Ω) H-converges to a matrixA0inMαβ(Ω)if for everyfH1(Ω)the sequence(uε)of the solutions to the problems

uεH01(Ω),

−div

AεDuε

=f inD(Ω), (3.3)

satisfies

uε u0 weakly inH01(Ω), AεDuε A0Du0 weakly inL2

Ω,Rn , whereu0is the solution to the problem

u0H01(Ω),

−div

A0Du0

=f inD(Ω). (3.4)

Every sequence of matrices in Mαβ(Ω) has a subsequence which H-converges to a matrix in Mαβ(Ω) (see [22,24,26]).

Denoting the adjoint of Aε by A¯ε, it is easy to prove that the sequence (A¯ε) H-converges to A¯0 when the sequence(Aε) H-converges toA0.

IfUis an open set contained in, we can consider also the notion ofH-convergence inU, replacingΩbyU in the definition. It is not difficult to prove that(Aε) H-converges toA0inU, for every open setUΩ, if(Aε) H-converges toA0in.

3.2. Corrector result

Besides the compactness result mentioned above, one of the main theorems is the corrector result (see [22,26], and [3,23] in the periodic case). Let(e1, e2, . . . , en)be the canonical basis of Rn. Forj=1,2, . . . , nthere exists a sequence(zεj)inH1(Ω)such that

zjε0 weakly inH1(Ω), (3.5)

Aε

Dzεj+ej

A0ej weakly inL2 Ω,Rn

, (3.6)

−div Aε

Dzεj+ej

→ −div A0ej

strongly inH1(Ω). (3.7)

Throughout the paper we will also assume that

zjε→0 strongly inL(Ω), (3.8)

zjε0 weakly inW1,p(Ω)for somep >2; (3.9)

using De Giorgi’s and Meyers’ regularity theorems, such a sequence can be constructed, for instance, by solving the problems

zεjH01

,

−div Aε

Dzεj+ej

= −div A0ej

inD

,

whereis a bounded open set withΩΩ, andAεis extended byαI on\. (The use ofis needed here only to obtain a globalW1,p(Ω)bound forzεj in the case where∂Ω is not smooth.)

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LetfH1(Ω), let(uε)be the sequence of the solutions to (3.3), and letu0be the solution to (3.4). Given δ >0, letψδbe a function inCc (Ω)which satisfies

β

Du0δ2dx < δ, (3.10)

and letvδεbe defined by vεδ=ψδ+

n j=1

Djψδzεj. (3.11)

Then (see [22,26]) lim sup

ε0

α

DuεDvεδ2dx < δ. (3.12)

Ifu0belongs toCc(Ω), we can takeψδ=u0in (3.10) for everyδ >0, so that vεδ=vε=u0+

n j=1

Dju0zεj, (3.13)

and (3.12) implies that

DuεDvε→0 strongly inL2 Ω,Rn

, (3.14)

which means thatDuεis equivalent toDvε(and also toDu0+

jDju0Dzjε, using (3.5)), as far as convergences inL2(Ω,Rn)are concerned.

In the general case whereu0only belongs toH01(Ω), we obtain from (3.12) that Duε=δ+

n j=1

DjψδDzεj+Rεδ, with lim sup

ε0

Rδε2

L2(Ω,Rn) α.

This is a corrector result: indeed it allows one to replaceDuεby an explicit expression, up to a remainderRεδwhich is small inL2(Ω,Rn)forδsmall, uniformly inε. Similar corrector results also hold in the case of local solutions.

Applications can be found, e.g., in [2,8].

3.3. A convergence result

We conclude this section with the following convergence result, which is implicitly used in various works (see, e.g., [4]). Observe that there is no boundary condition on the solutionsuε and that the right-hand sidesfεdo not converge strongly inH1(Ω).

Theorem 3.1. Let(Aε)be a sequence of matrices inMαβ(Ω)whichH-converges to a matrixA0inMαβ(Ω), and let(uε)be a sequence inH1(Ω)such that

uε u0 weakly inH1(Ω),

−div

AεDuε

=fε inD(Ω)for everyε0. (3.15)

Assume thatfε=gε+µε+νεfor everyε >0, where





(gε)is relatively compact inWloc1,p(Ω)for somep >1, ε)is bounded inM(Ω),

νε0 inD(Ω).

(3.16)

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Then

fε f0 weakly inH1(Ω)and strongly inWloc1,q(Ω)for everyq <2, AεDuε A0Du0 weakly inL2

Ω,Rn

. (3.17)

In the present paper, this theorem will be used withµε=0 and (gε)relatively compact (or even constant) inH1(Ω).

Proof. LetKbe any compact set of RnwithKΩ, and letϕCc(Ω)withϕ0 on andϕ=1 onK. We have

0

K

ε

ϕε=

AεDuεdx− gε, ϕ

ϕε. (3.18)

Because of (3.2), (3.15), and (3.16), the right-hand side of (3.18) is bounded independently ofε. This implies that

ε)is bounded inM(Ω). (3.19)

For every bounded open setU of Rn, the embeddingW01,r(U )C00(U ) is compact for every r > n. This implies that the embeddingMb(U )W1,s(U )is compact for everys < n/(n−1), and therefore the embedding M(Ω)Wloc−1,s(Ω)is compact for every s < n/(n−1).Therefore (3.16) and (3.19) imply that ε+νε)is relatively compact inWloc1,s(Ω), which implies by (3.16) that(fε)is relatively compact inWloc1,t(Ω)for some t >1. On the other hand, we deduce from (3.15) and (3.2) that(fε)is bounded inH1(Ω). By interpolation,(fε) is relatively compact inWloc1,q(Ω)for everyq <2.

Let nowv¯0be an arbitrary function inCc(Ω), and, for everyε >0, letv¯εbe the solution to the problem v¯εH01(Ω),

−divA¯εDv¯ε

= −divA¯0Dv¯0

inD(Ω). (3.20)

Recall that the sequence(A¯ε) H-converges toA¯0, so that





¯

vεv¯0 weakly inH01(Ω), A¯εDv¯εA¯0Dv¯0 weakly inL2

Ω,Rn ,

¯

vεv¯0 weakly in Wloc1,p(Ω)for somep >2,

(3.21)

where in the last assertion we have used Meyers’ regularity result (see [20]).

LetϕCc (Ω). Usingv¯εϕas test function in (3.15), anduεϕas test function in (3.20), we have











fε,v¯εϕ

=

AεDuεDv¯εϕdx+

AεDuεDϕv¯εdx

=

−divA¯0Dv¯0 , uεϕ

A¯εDv¯εDϕ uεdx+

AεDuεDϕv¯εdx.

(3.22)

Passing to a subsequence, we may assume that

AεDuε σ weakly inL2 Ω,Rn

,

fε f weakly inH1(Ω)and strongly inWloc1,q(Ω)for everyq <2, (3.23) for someσL2(Ω,Rn) andfH1(Ω). It is now easy to pass to the limit in the left and right-hand sides of (3.22) by using (3.15), (3.21), (3.23), and Rellich’s compactness theorem. One obtains

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





















f,v¯0ϕ

=

−divA¯0Dv¯0 , u0ϕ

A¯0Dv¯0Dϕ u0dx+

σ Dϕv¯0dx

=

A¯0Dv¯0Du0ϕdx+

σ Dϕv¯0dx

=

A0Du0Dv¯0ϕdx+

σ Dϕv¯0dx.

(3.24)

Since

−div(σ )=f inD(Ω), (3.25)

one deduces from (3.24) that

σ Dv¯0ϕdx=

A0Du0Dv¯0ϕdx, (3.26)

for everyϕCc(Ω)and everyv¯0Cc(Ω). Since, for every pointx, the vectorDv¯0(x)can be chosen to coincide with any prescribed vector of Rn, (3.26) implies that

σ=A0Du0 a.e. inΩ,

which, together with (3.25), givesf=f0. The uniqueness of the limits in (3.23) implies that the whole sequences converge, and this completes the proof of (3.17). 2

4. Relaxed Dirichlet problems

In this section we recall the definition, introduced in [13,14], of relaxed Dirichlet problems associated with measuresµM+0(Ω), and prove that, under some conditions on the data, the measureµcan be reconstructed from a solution of the corresponding relaxed Dirichlet problem.

4.1. Relaxed Dirichlet problems

GivenAMαβ(Ω), µM+0(Ω), andfH1(Ω), we call relaxed Dirichlet problem the problem of finding usuch that







uH01(Ω)L2(Ω, µ),

ADuDydx+

uydµ= f, yyH01(Ω)L2(Ω, µ). (4.1)

By a straightforward application of the Lax–Milgram lemma problem (4.1) has a unique solutionu(see [14], Theorem 2.4) andusatisfies the estimate

α

|Du|2dx+

|u|2dµ1 α f 2

H−1(Ω). (4.2)

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A connection between classical Dirichlet problems on open subsets of and relaxed Dirichlet problems of the form (4.1) is given by the following remark.

Remark 4.1. Using Theorem 4.5 of [17] it is easy to check that, ifUis open andµUis the measure introduced in (2.2), thenuH01(Ω)L2(Ω, µU)if and only if the restriction ofutoUbelongs toH01(U )andu=0 q.e. in \U. Therefore whenµ=µU problem (4.1) reduces to the following boundary value problem onU:

uH01(U ),

−div(ADu)=f inD(U ), (4.3)

in the sense thatuis the solution of (4.1) if and only if its restriction toUis the solution of (4.3) andu=0 q.e. in \U.

The name “relaxed Dirichlet problem” is motivated by the fact that the limit of the solutions to Dirichlet problems on varying domains ε always satisfies a relaxed Dirichlet problem (see, e.g., [11,14], and also Corollary 5.5 below). Moreover, the results proved in [12,14] ensure that every relaxed Dirichlet problem oncan be approximated in a convenient sense by classical Dirichlet problems on a suitable sequence of open sets(Ωε) included in.

4.2. Reconstructing the measureµ

We now want to reconstruct the measureµfrom one particular solution of the relaxed Dirichlet problem (4.1).

In view of the applications we consider also solutions of the equation in (4.1) which do not necessarily satisfy the homogeneous Dirichlet boundary condition on∂Ω, but we study only the case where the solution and the right-hand side are nonnegative. Let us fix

AMαβ(Ω), µM+0(Ω), λH1(Ω)+, (4.4)

and a solutionωto the problem







ωH1(Ω)L2(Ω, µ),

ADωDydx+

ωydµ=

ydλ ∀yH01(Ω)L2(Ω, µ), (4.5) which satisfies

ω0 q.e. inΩ. (4.6)

Remark 4.2. From the Lax–Milgram lemma, there exists a solution of (4.5) which belongs toH01(Ω); by the comparison principle (Theorem 2.10 of [13]) this solution satisfies (4.6), so that the set of such functionsωis not empty.

The following proposition (proved in [13], Proposition 2.6) will be frequently used throughout the paper.

Proposition 4.3. Assume (4.4), (4.5), and (4.6). Then there existsνH1(Ω)+such that

−div(ADω)+ν=λ inD(Ω). (4.7)

For technical reasons, the reconstruction of the measureµfromωrequires the following assumption: for every quasi open setUinwe have

cap

U∩ {ω=0}

>0 ⇒ λ(U ) >0. (4.8)

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Remark 4.4. Condition (4.8) is satisfied in the following (extreme) cases:

(a) ω >0 q.e. in;

(b) λ(U ) >0 for every quasi open setUwith cap(U ) >0.

Note that (b) is always satisfied ifλ(U )=

Ufdx withfL1loc(Ω)andf >0 a.e. in, since, by Lemma 2.1 and (2.1), every quasi open set with positive capacity has positive Lebesgue measure.

Proposition 4.5. Assume (4.4)–(4.6), and (4.8). Then

uH01(Ω)L2(Ω, µ)u=0 q.e. in{ω=0}. (4.9) Moreover for every Borel setB

cap

B∩ {ω=0}

>0 ⇒ µ(B)= +∞. (4.10)

Proof. The proof follows along the lines of Lemma 3.2 of [11], with some important variants, due to the fact that nowλis not the Lebesgue measure.

To prove (4.9) it is enough to consider a functionuH01(Ω)L2(Ω, µ)such that 0u1 q.e. inΩ. For everykN letukbe the solution of the relaxed Dirichlet problem













ukH01(Ω)L2(Ω, µ),

ADukDydx+

ukydµ+k

ukydλ=k

uy

yH01(Ω)L2(Ω, µ).

(4.11)

By the comparison principle (Theorem 2.10 of [13]) we have 0ukq.e. inΩ, henceuk=0 q.e. in{ω=0}. Takingy=ukuas test function in (4.11), from (3.1) we obtain, by using Cauchy’s inequality,

α

|Duk|2dx+

|uk|2dµ+2k

|uku|2dλ 1 α

|A Du|2dx+

|u|2dµ.

It follows that(uk)is bounded inH01(Ω)and converges toustrongly inL2(Ω, λ). Therefore a subsequence, still denoted by(uk), converges weakly inH01(Ω)to some functionv inH01(Ω)such thatv=u λ-a.e. inΩ. Since uk =0 q.e. in {ω=0}, and since suitable convex combinations of (uk)converge to v strongly in H01(Ω), we conclude thatv=0 q.e. in{ω=0}. LetV = {v=u}. ThenV is quasi open andλ(V )=0. It follows from (4.8) that cap(V∩ {ω=0})=0. Asu=vin\V andv=0 q.e. in{ω=0}, this implies thatu=0 q.e. in{ω=0}.

Let us prove (4.10). LetU be a quasi open subset of such thatµ(U ) <+∞. By Lemma 2.1 there exists an increasing sequence(zk)inH01(Ω)converging to 1U pointwise q.e. in and such that 0zk1U q.e. in for everykN. Asµ(U ) <+∞, each functionzkbelongs toL2(Ω, µ), hencezk=0 q.e. on{ω=0}by the previous step. This implies that 1U=0 q.e. on{ω=0}, hence cap(U∩ {ω=0})=0.

Let us consider a Borel setB with cap(B∩ {ω=0}) >0. For every quasi open set U containingB we have cap(U∩ {ω=0}) >0, henceµ(U )= +∞by the previous step of the proof. Then the regularity property (b) in the definition ofM+0(Ω)implies thatµ(B)= +∞. 2

Proposition 4.6. Assume (4.4)–(4.6), and (4.8), and letνbe the measure ofH1(Ω)+defined in (4.7). Then for every Borel setBΩwe have

µ(B)=







B

ω if cap

B∩ {ω=0}

=0, +∞ if cap

B∩ {ω=0}

>0,

(4.12)

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and ν

B∩ {ω >0}

=

B

ωdµ. (4.13)

In particular, this implies thatν=ωµon{ω >0}.

Proof. The proof follows along the lines of Lemma 3.3 and Proposition 3.4 of [11]. For everyη >0 letνηbe the Borel measure defined by

νη(B)=

B∩{ω>η}

ωdµ. (4.14)

AsωL2(Ω, µ), we haveνη(Ω)η1

ω2dµ <+∞. Let us prove that νη(B)=ν

B∩ {ω > η}

, (4.15)

for every Borel setB. Sinceνηis a Radon measure, it is enough to prove thatνη(U )=ν(U∩ {ω > η})for every open setUΩ. Let us fix an open setU, and letUη=U∩ {ω > η}. AsUηis quasi open, by Lemma 2.1 there exists an increasing sequence(zk)of nonnegative functions ofH01(Ω)converging to 1Uηpointwise q.e. inΩ.

Sinceµ(Uη) <+∞, the functionszk belong toL2(Ω, µ). Usingzk as test function in (4.5) and (4.7) we obtain

zkdν=

ωzkdµ.

Taking the limit asktends to∞we getν(U∩ {ω > η})=νη(Uη)=νη(U ), which proves (4.15). Whenηtends to 0, we obtain (4.13) from (4.14) and (4.15) (recall thatω0 q.e. inΩ).

From (4.13) we have µ

B∩ {ω > η}

=

B∩{ω>η}

ω,

for every Borel setBand everyη >0. Taking the limit asηtends to 0 we obtain µ(B)=

B

ω, (4.16)

for every Borel set B ⊆ {ω >0}. Since µ vanishes on all sets with capacity zero, (4.16) holds also when cap(B∩ {ω=0})=0. Finally, if cap(B∩ {ω=0}) >0, thenµ(B)= +∞by Proposition 4.5. 2

4.3. Density and uniqueness results

In the next proposition we assume, in addition, that

ωL(Ω). (4.17)

The following density result will be crucial in Sections 7 and 9. The proof follows along the lines of Proposition 5.5 of [15], with one important variant, due to the fact that it is now possible that the solutionsuk of the penalized problem (4.11) do not converge touweakly inH01(Ω)(see the proof of Proposition 4.5).

Proposition 4.7. Assume (4.4)–(4.6), (4.8), and (4.17). Then the set {ωϕ: ϕCc(Ω)}is dense in H01(Ω)L2(Ω, µ).

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Proof. For every uH01(Ω)L2(Ω, µ) we have to construct a sequence k) in Cc(Ω) such that (ω ϕk) converges touboth inH01(Ω)and inL2(Ω, µ). Clearly it is enough to consider the caseu0 q.e. in. For everyjN letvj =u(j ω). Sinceω0 q.e. in andu=0 q.e. in{ω=0}by Proposition 4.5, the sequence (vj)is nondecreasing and converges touq.e. in. By Lemma 1.6 of [9] there exists a sequence(uj)inH01(Ω), converging to u strongly in H01(Ω), such that 0uj vj u q.e. in for everyjN. By the dominated convergence theorem it turns out that(uj)converges touinL2(Ω, µ)too.

It is thus sufficient to consider the case where uH01(Ω) is such that 0ucω q.e. in for some constantc >0. Since{(uc ε)+>0} ⊆ {ω > ε}, and (uc ε)+ converges to u in H01(Ω)L2(Ω, µ) as ε tends to 0, we may also assume that there existsε >0 such that{u >0} ⊆ {ω > ε}. Thenu/ω=u/(ωε). Since ωH1(Ω)L(Ω), we haveuH01(Ω)L(Ω), and thusu/ωH01(Ω)L(Ω). Therefore there exists a sequencek)inCc(Ω), bounded inL(Ω), which converges toz=u/ωstrongly inH01(Ω)and q.e. inΩ, henceµ-a.e. in . SinceωH1(Ω)L(Ω), the sequence (ωϕk)converges to ωz=ustrongly in H01(Ω).

AsωL2(Ω, µ)andk)is bounded inL(Ω, µ)and converges toz=u/ω µ-a.e. inΩ, by the dominated convergence theorem the sequence(ωϕk)converges toωz=ustrongly inL2(Ω, µ). 2

The following uniqueness result will be crucial in Theorems 5.1 and 5.4. The proof follows along the lines of Lemma 3.5 of [11], with one important variant, due to the fact that now the condition

u2dλ=0 does not imply thatu=0 q.e. in.

Proposition 4.8. Assume (4.4)–(4.6), (4.8), and (4.17). Letube a solution of the problem







uH01(Ω)L(Ω),

ADϕDu ωdx−

ADωDϕ udx+

dλ=0 ∀ϕCc(Ω). (4.18)

Thenu=0 q.e. inΩ.

Proof. Sinceuandωbelong toH1(Ω)L(Ω), it is easy to see that the equation in (4.18) is satisfied also for ϕH01(Ω)L(Ω). Usingϕ=uas test function in this equation we obtain

ADuDu ωdx−1 2

ADωD u2

dx+

u2dλ=0. (4.19)

Usingy=u2as test function in (4.7), from (4.19) we get

ADuDu ωdx+1 2

u2dν+1 2

u2dλ=0.

This implies

Du=0 a.e. in{ω >0}, (4.20)

u=0 λ-a.e. inΩ. (4.21)

LetU= {u=0}. ThenU is quasi open and λ(U )=0 by (4.21). Therefore (4.8) implies thatu=0 q.e. in {ω=0}, and consequentlyDu=0 a.e. in{ω=0}. By (4.20) we conclude thatDu=0 a.e. in. SinceuH01(Ω), this yieldsu=0 q.e. in. 2

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5. A global convergence result

For everyε0 we consider a matrixAε in Mαβ(Ω) and a measureµε inM+0(Ω), that will remain fixed throughout the rest of the paper. We assume that

(Aε) H-converges toA0. (5.1)

In this section we use a duality argument to prove that, under suitable hypotheses onε)(which are always satisfied by a subsequence), the solutionsuε of the relaxed Dirichlet problems (4.1) for A=Aε andµ=µε converge to the solutionu0of the relaxed Dirichlet problem forA=A0andµ=µ0.

5.1. Definition of special test functions

For everyε0 we define the functionswεandwεas the unique solutions to the problems







wεH01(Ω)L2(Ω, µε),

AεDwεDydx+

wεyε=

ydx ∀yH01(Ω)L2(Ω, µε), (5.2)







wεH01(Ω)L2(Ω, µε),

A¯εDwεDydx+

wεyε=

ydx ∀yH01(Ω)L2(Ω, µε). (5.3) By the comparison principle (Theorem 2.10 of [13]) we have

wε0 and wε0 q.e. inΩ. (5.4)

Moreover, by the maximum principle, we have also sup

ε0

wε L(Ω)<+∞ and sup

ε0

wε L(Ω)<+∞ (5.5)

(see [11], Section 3). By Proposition 4.3 there exists two measuresνεandν¯εinH1(Ω)+such that

−div

AεDwε

+νε=1, −divA¯εDwε

+ ¯νε=1 inD(Ω). (5.6)

Finally, from (4.2) we obtain sup

ε0

|Dwε|2dx <+∞, sup

ε0

|Dwε|2dx <+∞, (5.7)

sup

ε0

|wε|2ε<+∞, sup

ε0

|wε|2ε<+∞. (5.8)

5.2. The main convergence result

Given, for everyε0,fεandf¯εinH1(Ω), we consider the solutionsuεandu¯εto the following problems







uεH01(Ω)L2(Ω, µε),

AεDuεDydx+

uεyε= fε, yyH01(Ω)L2(Ω, µε), (5.9)

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