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www.imstat.org/aihp 2013, Vol. 49, No. 2, 550–568

DOI:10.1214/11-AIHP468

© Association des Publications de l’Institut Henri Poincaré, 2013

Almost everywhere convergence of convolution powers on compact Abelian groups

Jean-Pierre Conze

a

and Michael Lin

b

aIRMAR, CNRS UMR 6625 Université de Rennes 1, 35042 Rennes Cedex, France. E-mail:[email protected] bDepartment of Mathematics, Ben-Gurion University, Beer-Sheva, Israel. E-mail:[email protected]

Received 24 August 2011; revised 22 November 2011; accepted 22 November 2011

Abstract. It is well-known that a probability measureμon the circleTsatisfiesμnf

fdmp→0 for everyfLp, every (some)p∈ [1,∞), if and only if| ˆμ(n)|<1 for every non-zeron∈Z(μis strictly aperiodic). In this paper we study the a.e.

convergence ofμnf for everyfLpwheneverp >1. We prove a necessary and sufficient condition, in terms of the Fourier–

Stieltjes coefficients ofμ, for the strong sweeping out property (existence of a Borel setB with lim supμn∗1B=1 a.e. and lim infμn∗1B=0 a.e.). The results are extended to general compact Abelian groupsGwith Haar measurem, and as a corollary we obtain the dichotomy: forμstrictly aperiodic, eitherμnf

fdma.e. for everyp >1 and everyfLp(G, m), orμhas the strong sweeping out property.

Résumé. Il est connu qu’une mesure de probabilitéμ sur le cercleTsatisfaitμnf

fdmp→0 pour toute fonction fLpet pour toutp∈ [1,∞)(ou pour unp∈ [1,∞)), si et seulement siμest strictement apériodique (i.e.| ˆμ(n)|<1 pour tout nnon nul dansZ). Nous étudions ici la convergence presque partout deμnf pourfLp,p >1. Nous montrons une condition nécessaire et suffisante portant sur les coefficients de Fourier–Stieltjes deμpour la propriété de “balayage fort” (existence d’un borélienBtel que lim supμn∗1B=1 p.p. et lim infμn∗1B=0 p.p.). Les résultats sont étendus aux groupes abéliens compacts générauxGde mesure de Haarm. Comme corollaire nous obtenons la dichotomie suivante : pourμstrictement apériodique, soit μnf

fdmp.p. pour toutp >1 et toute fonctionfLp(G, m), soitμvérifie la propriété de balayage fort.

MSC:Primary 37A30; 28D05; secondary 47A35; 60G50; 42A38

Keywords:Convolution powers; Almost everywhere convergence; Sweeping out; Strictly aperiodic probabilities

1. Introduction

Let (X,B)be a measurable space and P (x, A):X×B−→ [0,1] a transition probability, with Markov operator Pf (x)=

f (y)P (x,dy)defined for boundedf. Whenmis a probability onBwhich isP-invariant, the operatorP can be extended to a contraction ofL1(X, m). MoreoverP becomes a contraction in eachLp(X, m)space, 1≤p≤ ∞ [13].

Hopf’s pointwise ergodic theorem yields that forfL1(m)the Cesàro averages1nn

k=1Pkf converge a.e. and in Lp-norm whenfLp(m), 1p <∞. The limit is

fdmifP is ergodic inL1, i.e. whenPf =f a.e. forfL1 holds only forf constant a.e.

It is therefore a natural question to study the convergence of the unaveraged sequence{Pnf}, in norm or a.e. The following general results for a.e. convergence are known:

1. IfP=P and−1 is not an eigenvalue, thenPnf converges a.e. for everyfLp,p >1 (Stein–Rota theorem [23,25]; Rota’s proof yields the convergence also forfLlog+L[6], but in general convergence may fail forfL1 [17]).

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2. IfP is an aperiodic Harris recurrent operator, thenPnf

fdma.e. for everyfL1(X, m)(mis assumed finite), by S. Horowitz [11].

Often, a.e. convergence of {Pnf}n1 for every bounded measurable function fails in a very strong manner ex- pressed in the following definition, which seems to have been introduced for operator sequences{Pn}in the study of a.e. convergence of averages along subsequences.

Definition 1.1. We say that{Pn}(or simplyP) has the strong sweeping out property (SSO property)if there exists in Ba denseGδsubset of setsB of positive measure such thatlim supnμn∗1B=1a.e.andlim infnμn∗1B=0a.e.

In this paper we study the strong sweeping out property for the convolution operator Pμ defined by a strictly aperiodic probability measure μ on a compact Abelian group G, Pμf (x)=μf (x)=

Gf (x+y)dμ(y). We obtain a necessary and sufficient condition for the strong sweeping out property forPμ(we will say simply “forμ”), in terms of the Fourier–Stieltjes transform ofμ, and deduce the dichotomy:eitherμnf

fdma.e. for every fLp(G, m), everyp >1, orμhas the strong sweeping out property.

For the sake of clarity, we prove the results first for convolutions on the unit circle (Section 3), and after some examples for discrete probabilities on the circle (Section4), we add the necessary ingredients to prove the result in the general case (Section5).

2. Convolution powers on compact Abelian groups

In this section we look at the problem of almost everywhere convergence (to the integral) of convolution powers of a probability μ on a compact Abelian groupG, with Borel σ-algebraB and dual groupG. Characters onˆ Gwill be denoted by γ. The Markov transition is P (x, A)=μ(Ax), with invariant probability the normalized Haar measurem, and the corresponding Markov operator isPf:=Pμf =μf. The dual Markov operator isPμ=Pμˇ, whereμˇ is the reflected probability given byμ(A)ˇ =μ(A). By commutativity ofG, the operatorPμis normal in L2(G, m). We note that the Markov chain{Yn}onΩ=GN induced byPμis the random walk onGof lawμ, and μn∗1A(x)=Px{YnA}, wherePxis the probability onΩ for the chain started atx(initial distributionδx).

The Fourier–Stieltjes coefficientsμ(γ )ˆ are eigenvalues ofPμwith continuous eigenfunctions, so a necessary con- dition for a.e. convergence of{μnf}to the integral for all continuous functions is that| ˆμ(γ )|<1 for everyγ =0, i.e.μisstrictly aperiodic. We recall the well-known properties equivalent to strict aperiodicity of a probabilityμon a compact Abelian groupG:

Proposition 2.1. The following are equivalent:

(i) | ˆμ(γ )|<1for every character0 =γ∈ ˆG;

(ii) μnf

Gfdmuniformly for every continuous function onG;

(iii) the support ofμis not contained in a class of a proper closed subgroup;

(iv) μnf

Gfdm2→0for everyfL2(G, m).

It follows thatμnf

fdmpointwise forf in a dense subspace ofLp, 1≤p <∞, namelyC(G). However, a result of J. Rosenblatt [20] yields that forα=e2π withθ(0,1)irrational, the strictly aperiodicμ=121+δα) is strongly sweeping out onT.

Some of the general results of a.e. convergence cited in theIntroductioncan be improved for the powers of the convolution operatorPμin several particular cases:

1. Ifμis symmetric and strictly aperiodic, then for everyfLlogLwe haveμnf

fdma.e. [23] (see also [18]).

2. In any compact groupG(not necessarily Abelian), if some powerμk is non-singular with respect to the Haar measurem, thenμnm →0 in total variation norm with exponential rate (cf. [2], Theorem 3, forGconnected, [1], Theorem 4.1, forGnot necessarily connected and for the precise rate); see [22], Theorem 4.1, for a list of equivalent conditions. In this case, for everyf inL1(G, m)the series

n=1μn(f

fdm)converges a.e. It follows that any μwith the strong sweeping out property has all its convolution powers singular (cf. Proposition3.4).

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3. Another sufficient condition for a.e. convergence is supγ =0| ˆμ(γ )|<1. It implies supfp1μnffdmp→0 (exponentially fast) forp(1,)by [21], p. 202ff (see also [9], Proposition 4.1); so forp(1,), the series

n=1μn(f

fdm)converges a.e. for anyfLp(G, m).

In particular, on the circleT, the condition supγ =0| ˆμ(γ )|<1 holds whenμ(n)ˆ →0 as|n| → ∞[9]. Note that the above norm convergence needs not hold forp=1 orp= ∞[9].

4. There exists onTa continuous probabilityμwith all its convolution powers singular, such that supn =0| ˆμ(n)|<

1 (and then, by [21],μnf

fdma.e. for everyfLp(T, m),p >1). See [9], Proposition 4.7, for a construc- tion along classical lines. A result of Varopoulos [26] shows that we can findμcontinuous with all its convolution powers singular satisfyingμ(n)ˆ →0 as|n| → ∞(see also the first lines following [19], Theorem 4.2). (The result of Varopoulos is that in any non-discrete compact Abelian group there is a probabilityμwith all its convolution powers singular to the Haar measure such thatμ(γ )ˆ vanishes at infinity.)

Notations. The spectrum of the operatorPf =μf inL2(T, m)is denoted byσ (P ).It is the closure of{ ˆμ(γ ): γGˆ}.In the sequel we study the peripheral spectrum ofP,i.e.the unimodular complex numbers inσ (P ).It will be useful to distinguish notationallyT,the group on which the convolution operates(the state space of the Markov chain generated),fromS=S1,the boundary of the closed unit disk which contains the spectrum.

Since the spectral radius of an operator is bounded by its norm, and using the spectral theorem, one easily proves the equivalence between the following conditions:

(i)Pn(IP )

2→0, (ii) sup

λσ (P )

λn(1λ)→0, (1) (iii) sup

γ∈ ˆG

μˆn(γ )

1− ˆμ(γ )→0, (iv)σ (P )∩S= {1}. (2)

Remarks. 1.Ifμn+1μn1→0,then for1≤p <continuity of the representation ofGinLp(G, m)by trans- lations yieldsPn+1Pnp→0.

2.IfPn+1Pn2→0,then by the Riesz–Thorin theoremPn+1Pnp→0for every1< p <∞.However, forp=1we may still haveμn+1μn1=2for everyn(e.g., [12],Remark2.16(b)).

Proposition 2.2. Letμbe a strictly aperiodic probability on a compact Abelian groupG.Ifσ (P )∩S =S,then there exists an increasing subsequence{nk}such thatμnkf

fdma.e.for everyfL2(G, m).

Proof. SinceP is a positive contraction, the assumptionσ (P )∩S =Simplies that this intersection is finite, and for somej≥1 we haveσ (Pj)∩S= {1}[14], Proposition 1 (see Lemma3.5below for a direct proof). Therefore (iii) of (2) holds forμj and it follows from [12], Proposition 2.15, that there exists an increasing subsequence{ k}such that μj kf

fdma.e. for everyfL2(G, m).

Remark. The probabilityμ=121+δα)onThas the strong sweeping out property as mentioned above,although σ (Pμ)∩S= {1}(and alsoμn+1μn1→0by Foguel’s zero-two law).By Proposition2.2there is a subsequence {nk}withμnkf

fdmfor everyfL2(T, m).

Now we give a variant of a result of [5] (see also [12], Theorem 2.20) which gives a sufficient condition for the a.e. convergence forf inLp,p >1. It is based on Theorem 14 of [4], or the following extension of it which does not require normality.

We consider a positive contractionT onL2(X, m)where(X, m)is a probability space. For every integerr∈ [1, n], letΔrTn:=Tnr(TI )r, whereI is the identity onL2(X, m).

Theorem 2.3. Let T be a positive contraction of L2(X, m),withW be a closedT-invariant subspace.Let W =

jJVj be an orthogonal decomposition ofW into closedT-invariant subspaces such that the restrictionTj ofT toVj satisfiesTj<1.LetL(j ):=1IjTTj

j,whereIj is the identity onVj.

Putf0(x):=supn0|Tnf (x)|andfr(x)=supnr|nrΔrTnf (x)|,forr≥1.Then:

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(i) ForfW,iff =

jΠjf is its orthogonal decomposition,the maximal function satisfies f0

2≤2f2+

j

Πjf22L(j )2 1/2

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and

jΠjf2L(j )2<implies the convergencelimnTnf=0m-a.e.and inL2(m).

(ii) IfL:=supjL(j ) <∞,there are finite constantsCr such that for everyfW, fr

2Crf2,r≥0, (4)

and for everyr≥0,the convergencelimnnrΔrTnf =0holdsm-a.e.and inL2(m).

Proof. (i) The proof is based on the idea of comparingTnwith its Cesàro averages, like the proof of Stein’s theorem for self-adjoint positive contractions [25] or that of [4] for positive normal contractions, but does not require the spectral theorem.

Forn≥1 put Anf =1nn1

k=0Tkf. By Akcoglu’s ergodic theorem [13], p. 190, for everyfL2the sequence Anf (x)converges a.e. and the maximal functionAf (x)=supk0|Akf|(x)satisfies Af2≤2f2. Using the inequality

1 n

n

k=1

kak

2

n

k=1

k|ak|2, (5)

which holds for every complex numbersa1, . . . , an, we can write forfW: TnfAnf2=

1 n

n

k=1

k

TkfTk1f

2

n

k=1

kTkfTk1f2F1(f )2, withF1(f )2=

k=1k|Tk1(TI )f|2.

Observe that for 0≤λ <1, we have(1λ)2

1 2(k1)=1/(1+λ)2≤1. Therefore, F1(f )2

2=

k=1

k

X

j

Tjk1(TjIjjf

2dm=

k

k

j

Tjk1(TjIjjf2

2

j

k

kTj2(k1)

TjIj2Πjf22

j

TjIj2

(1Tj)2Πjf22=

j

Πjf22L(j )2.

This proves (3), since we have|Tnf| ≤Af +F1(f ),n≥1; hencef0Af +F1(f ). The convergence in L2-norm follows from the assumptionTj<1.

LetKbe a finite subset ofJ. Writef =ϕK+ρK, withϕK=

jKΠjf andρK=

j /KΠjf. Forε >0, take Ksuch thatρK2εand

j /KΠjf22L(j )2ε2.

Clearly lim supn|TnϕK| =0, since limnTnΠjf = 0,∀jJ. Hence lim supn|Tnf| ≤lim supn|TnϕK| + lim supn|TnρK| ≤K)0. Applying inequality (3) toρK, we obtain

lim sup

n

Tnf

2K)0

2AρK

2+F1K)≤2ρK2+

j /K

Πjf22L(j )2 1/2

≤3ε.

(ii) Forr≥1,x∈ [0,1[, we have

k=rk2r1xkr=ρr(x)/(1x)2r, whereρr is a polynomial. Therefore there exists a finite constantDr such that

(1λ)2r k=r

k2r1λ2(kr)=ρr

λ2

/(1+λ)2rD2r, 0≤λ <1. (6)

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The relationCrk1+Ckr=Ckr+1, satisfied by the binomial coefficientsCkr, yields Cnr++11ΔrTn=

n

k=r

CkrΔrTk+ n

k=r+1

Ckr+1Δr+1Tk, 0≤rn. (7)

ForfL2(X, m), it follows from (5):

1 n

n

k=r

CkrΔrTkf

2

n

k=r

k

Crk/k2Tkr(TI )rf2Fr2,

with Fr=

k=r

k1

Ckr2Tkr(TI )rf21/2

.

From the decomposition in the orthogonal subspacesVj, we get:

Fr22

j

k=r

k1 Ckr2

Tj2(kr)

TjIj2rΠjf2. (8)

According to (6) withλ= Tj, the series in[ ]in (8) is less thanDr2/(1Tj)2r, so Fr22Dr2

j

L(j )2rΠjf2Dr2

sup

j

L(j ) 2r

j

Πjf2=D2rL2rf2.

Fornr≥1 the identity (7) implies the inequality 1

n+1Crn++11ΔrTnf ≤ 1

n+1

n

k=r+1

Ckr+1Δr+1Tkf + 1

n+1

n

k=r

CkrΔrTkf

Fr+1+Fr;

sinceCnr++11=nr++11r1

j=0 nj

rjnr++11(nr)r fornr≥1, puttingBr =(r+1)rr we obtain fr

2=sup

nr

nrΔrTnf

2Br

sup

nr

1

n+1Cnr++11ΔrTnf

2

Br

Fr+12+ Fr2

Br

Dr+1Lr+1+DrLr f2.

The proof of the convergence statement in (ii) is similar to that of (i).

Suppose now thatT defines a positive contraction of eachLp(m), 1p≤ ∞, andW =L2(m)in Theorem2.3.

The inequalities (4) and the classical inequalitiessupnn+11(f+Tf + · · · +Tnf )ppp1fp, fLp(m), 1<

p <∞, are the needed properties for Stein’s complex interpolation theorem [25] (see also [7] for a detailed presenta- tion of the method applied to iterates of composed conditional expectations). It implies for 1< p <∞the maximal inequality and the a.e. convergence ofTnf forfLp(m). This applies to convolution powers, i.e.T =Pμ, even on non-Abelian (compact) groups. In the Abelian case, it yields:

Theorem 2.4 ([4]). Letμbe a strictly aperiodic probability on a compact Abelian groupG.If

sup

γ =0

|1− ˆμ(γ )|

1− | ˆμ(γ )|<, (9)

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then forp >1there is a constantCp such that for everyfLp(G, m),the maximal inequalityf0pCpfp

holds andμnf

fdma.e.

Proof. LetPf =μf be the normal operator induced onL2(G, m). Thenσ (P )is the closure of{ ˆμ(γ ): γ∈ ˆG}, and (9) implies thatσ (P )contains no unimodular points except 1 and is included in a Stolz region of the closed unit disk. Using part (ii) of Theorem2.3, whenVγ is the space of multiples of the characterγ∈ ˆG, the maximal inequality

and the a.e. convergence follow from Stein’s theorem as explained above.

As mentioned in theIntroduction, failure of a.e. convergence for a sequence of operators may be quite strong. In [8], del Junco and Rosenblatt gave a condition which implies the SSO property (cf. Definition1.1) and, for powers of convolution operators onG, reads:

Theorem 2.5. Letμbe a probability measure on the compact Abelian groupG.If for every integerN0>1and every ε >0,there exists a measurable setAsuch thatm(A) < εandm{supnN0μn∗1A(x)≥1−ε}>1−ε,thenμhas the strong sweeping out property.

The next lemma shows that it suffices to fulfill the conditions forN0=1.

Lemma 2.6. If for everyε >0there exists a setABsuch thatm(A) < εand m

xG: sup

n1

μn∗1A(x)≥1−ε

>1−ε, (10)

thenμhas the strong sweeping out property onG.

Proof. Let be given N0≥1 and ε >0. By applying (10) with ε= 2Nε0+ε instead ofε, we obtain a setA with μ(A) < εwhich satisfies the condition of Theorem2.5since

m

sup

nN0

μn∗1A(x)≥1−εm

sup

nN0

μn∗1A(x)≥1−ε

m

sup

n

μn∗1A(x)≥1−ε

N0m(A)/

1−ε

≥1−εN0m(A)/

1−ε

≥1−εN0ε/ 1−ε

≥1−ε.

3. Convergence and divergence of convolution powers on the circle

Our aim is to characterize the strong sweeping out property on the circleT by a property of the Fourier–Stieltjes coefficients of μ, and to study the a.e. convergence of the convolution powers of μ. In order to avoid repetition when dealing with general groups, we denote the characters byγ and the Fourier–Stieltjes coefficients byμ(γ ). Forˆ γ (x)=e2πinx, we write eitherμ(γ )ˆ orμ(n).ˆ

Theorem 3.1. Letμbe a strictly aperiodic probability on the unit circleT.If lim sup

ˆ

μ(n)1,n =0

|1− ˆμ(n)|

1− | ˆμ(n)|= ∞, (11)

thenμhas the strong sweeping out property onT.

Proof. We will use Lemma2.6to show the SSO property. For a characterγ =0 denote L(γ )=|1− ˆμ(γ )|

1− | ˆμ(γ )| and ρ(γ )=

1− μ(γ )ˆ

| ˆμ(γ )|

. (12)

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L(γ )is well-defined by strict aperiodicity,L(γ )≥1 and the triangle inequality yields ρ(γ )≥1− ˆμ(γ )

μ(γ )ˆ − μ(γ )ˆ

| ˆμ(γ )| =

1−μ(γ )ˆ L(γ )−1

. (13)

By (11), there exists an infinite sequence{γk},γk(x)=e2πinkxforx∈R/Z, such thatL(γk)→ ∞andρ(γk)→0.

Let 0< ε <1 be given and putM=1. We will constructABsatisfying (10), by adapting the ideas of Losert [16]. From the above sequence{γk}, we fixγksuch that

ρ(γk) < 1

M and L(γk) >32M2π

ε . (14)

Sinceγkis fixed, we denoteL=L(γk)andρ=ρ(γk); in all other quantities defined we will suppress the dependence onγk. Let ξ(0,1)satisfy e2π = ˆμ(γk)/| ˆμ(γk)|. Thenρ= |1−e2π| =2|sin(πξ )| ≤2πξ. Since L >2, (13) yields

ρ L

1−μ(γˆ k)L−1 L ≥1

2

1−μ(γˆ k). (15)

Putj:= [2ρπ] +1 andr:=1− | ˆμ(γk)|j. By (15) we have 1−r(1L)j>0. Then

r≥ln(1−r)jln

1−2ρ L

≥ −j

L, (16)

since ln(1−t )≥ −2t for t <1/4, while ρ <1/M and L >32π imply Lρ ≤1/32π. The estimate (16) and the definition ofj yield

r≤4ρj L ≤16π

L . (17)

We now defineδ:=max{ρ4, r

}. The estimates (14) and (17) yield r

2ε≤ 8π

Lε<

8π 32M2π= 1

2M, (18)

which showsδ <1/2Msinceρ <1/M.

Since 2|sin(πξ )| =ρ <1, we haveξ <1/6. We saw thatρ≤2πξ, so 1

j < ρ

< ξ <1

2sin(πξ )=ρ

4 < δ. (19)

Hence thej intervals[( −1)ξ, ξ )mod 1,1≤ ≤j, each of lengthξ >1/j, cover all the unit interval, so for each x∈ [0,1)there exists xwith|nkxmod 1− xξ|< ξ < δ(recall thatγk(x)=e2πinkx).

Fix 1≤ ≤j. Using the definition ofξwe obtain μˆ (nk)=μ(nˆ k) =e2πi ξ

ˆ μ(nk)

=e2πi ξ

I

e2πinks(s)

=

I

e2πi(nks+ ξ )(s)=

I

cos

(nks+ ξ )

(s)=1−2

I

sin

π(nks+ ξ )2

(s).

But for ≤j, we have| ˆμ(nk)| ≥ | ˆμ(nk)|j=1−r, so

I

sin

π(nks+ ξ )2

(s)=1 2

1−μ(nˆ k)

r 2.

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From Tchebyshev’s inequality we obtainμ {sI:|sin(π(nks+ ξ ))| ≥δ} ≤r2. GivenxI, we have xj with

|nkxmod 1− xξ|< δ. Hence|sin(π(nks+ xξ ))|< δimplies sin

π(nks+nkx)≤sin

π(nks+ xξ )+sin

π(nkxxξ )< (1)δ.

Sinceδ2r/2εby the definition ofδ, it follows that μ x

sI:sin

π(nks+nkx)< (1

≥1− r

2≥1−ε.

Defineϕ:I−→I byϕ(t )=nktmod 1. Thenϕpreserves Lebesgue’s measure onI. LetA=ϕ1(B), whereB= {sI: |sin(πnks)|< (1}. Since|sin(πy)| ≥ |2y|for|y| ≤12, we havem(A)=m(B)(1)δ <12M=ε and by the previous estimate

sup

1j

μ ∗1A(x)= sup

1j

μ (Ax)μ x(Ax)

=μ x

sI: sin

π(nks+nkx)< (1

≥1−ε.

This yieldsm{x∈ [0,1): supn0μn∗1A(x) >1−ε} =m([0,1))=1, so (10) is satisfied.

Corollary 3.2. Let μbe strictly aperiodic such thatS⊂ { ˆμ(n): n∈Z}.Then(11)holds,and thereforeμ has the strong sweeping out property on the circle.

Proof. LetPf =μf onL2(T, m)with spectrumσ (P ); it is easy to show thatσ (P )is the closure of{ ˆμ(n): n∈Z}.

Let 1 =λk∈Swithλk→1. By assumption there exists a sequenceμ(nˆ k,j)(with| ˆμ(nk,j)|<1 by strict aperiodicity) converging toλkasj→ ∞. Then limj|1− ˆμ(nk,j)|/(1− | ˆμ(nk,j)|)= ∞, since numerator converges to|1−λk| =0.

Callnk a value of nk,j withj large so|1− ˆμ(nk,j)|<2|1−λk|andL(nk,j) > k. Thus (11) holds, and the strong

sweeping out property follows from the theorem.

Lemma 3.3 ([15], Lemma 1). Condition(11)is equivalent to lim sup

ˆ

μ(n)1,n =0

|mμ(n)ˆ |

1− eμ(n)ˆ = ∞. (20)

Proof. For the sake of completeness, we give a proof and show the following equivalence: for every sequence{zn} with|zn|<1,

lim sup

|zn|<1,zn1

|1−zn|

1− |zn|= ∞ if and only if lim sup

|zn|<1,zn1

|mzn| 1− ezn = ∞.

Letz=ρebe a complex number with argumentα(12π,12π)and modulusρ <1. PutA(z)=A(α, ρ)=|11−|zz|| andB(z)=B(α, ρ)=1|mzez|. We have

A(α, ρ)=

1+4ρ

sin(α/2) 1−ρ

21/2

, B(α, ρ)=2ρ cosα

2

|sin(α/2)| 1−ρcosα. PuttingM(z)=Mα,ρ=2|sin(α/2)1ρ |, we get

A(α, ρ)=

1+ρMα,ρ2 1/2

, B(α, ρ)= ρ|cos(α/2)|

|sin(α/2)| +cosαMα,ρ1.

Hence the equivalence between limzn1A(zn)= ∞,limzn1M(zn)= ∞,limzn1B(zn)= ∞.

(9)

Remarks. 1.Even forμstrictly aperiodic,the conditionsupn =0|11−| ˆ− ˆμ(n)μ(n)|| = ∞is insufficient for the strong sweeping out(and(9)is not necessary for a.e.convergence).Letθ(0,1)be irrational,α=e2π ∈T,and putμ=12α1+ δα).The operatorPf =μf is self-adjoint on L2(m),so by the Stein–Rota theorem supnPn|f| ∈L2 for every fL2.We haveμ(n)ˆ =cos(2πnθ ),soμis strictly aperiodic,henceμnf

fa.e.for everyfL2,and thus μdoes not have the sweeping out property. (Note that the result of[5]does not apply toμ,because121+δ1)is not strictly aperiodic onZ,but it applies toμ2.)We havesupn =0|11−| ˆ− ˆμ(n)μ(n)||= ∞sinceL(nk)→ ∞whennkθ→1/2 mod 1, but(11)fails since whenμ(n)ˆ is close to1its values are positive reals andL(n)=1.

2.Letα=e2π be as above,and defineμ=121+δα).Thenμ(n)ˆ =12(1+αn),soμis strictly aperiodic.For z=12(1+e2πinθ),we have|z| = |cos(πnθ )|and|1−z| = |sin(πnθ )|,soL(n)→ ∞asnθ→0 mod 1.Hence(11) holds.

3.Letα=e2π be as above.Theorem3.1forμ=

k∈Zpkδαk (wherepk≥0with

k∈Zpk=1)follows from Theorem2of[16]:We put onZthe probabilityν:=

k∈Zpkδkand obtainμ(n)ˆ = ˆν({}).Henceμ(n)ˆ →1implies {} →0,so(11)implieslim supt0|11−|ˆ−ˆν(t )ν(t )||= ∞.

Example 1. Let{αk=e2πk}dk=1⊂Twithd >1,and assume that1, θ1, θ2, . . . , θdare linearly independent over the rationals.Letμ=d

k=1pkδαk (where0≤pk<1and

pk=1).Thenμhas the strong sweeping out property onT. Proof. We haveμ(n)ˆ =d

k=1pkαkn, andμis strictly aperiodic since its support has at least two “irrational” points.

The linear independence implies, by a result of Kronecker (e.g. [10], p. 382, [13], pp. 12–13), that the powers of 1, . . . , αd)are dense in the d-dimensional torusTd; hence for λ∈S there exists a subsequence{nj}such that αknjλ for k=1, . . . , d, which yields thatμ(nˆ j)λ. We conclude thatS⊂ { ˆμ(n): n∈Z}, and Corollary3.2

applies.

Remark. Since the flow defined on(T, m)byTtx=e2πitx is periodic,ford=3we cannot obtain Example1from Theorem2.18of[12] (which yields only non-convergence for somefL2(T, m),and not the strong sweeping out property).

Proposition 3.4. There exists a continuous probabilityμonTwhich has the strong sweeping out property onT. Proof. Recall that a closed set K⊂Tis called aKronecker set if every continuousf onK with|f| ≡1 can be uniformly approximated by continuous characters, i.e., there is a sequence{nj}such thatαnjf (α)uniformly for αK.

Hence forλ∈Sthere exists{nj}such thatαnjλforαK(uniformly). Ifμis a probability supported inK, we obtain thatμ(nˆ j)λ. Whenμis strictly aperiodic, Corollary3.2applies andμhas the strong sweeping out property onT.

By Theorem 5.2.2(a) in [24],Tcontains a Cantor setKwhich is a Kronecker set. HenceK supports a continu- ous probabilityμwith uncountable support (so strictly aperiodic), and by the aboveμhas the strong sweeping out

property.

By Theorem3.1, a.e. convergence ofμnf for everyfL2(T, m)implies lim sup

ˆ

μ(n)1,n =0

|1− ˆμ(n)|

1− | ˆμ(n)| <∞ (21)

for the Fourier–Stieltjes coefficients ofμ. We will prove the converse in Theorem3.6below.

First, let us observe that the proof of Corollary3.2shows that, if there is a sequence{λk} ⊂S∩σ (P )with 1 = λk→1, then (11) holds, contradicting (21). Hence, if (21) holds, thenσ (P )∩S =Sand therefore this intersection is finite, withσ (Pj)∩S= {1}for somej ≥1, sinceP is a positive contraction [14], Proposition 1. We give below a simple proof of this last fact for the convolution operators treated in this paper.

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