A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
M ARIUS V AN DER P UT
Galois properties of linear differential equations
Annales de la faculté des sciences de Toulouse 6
esérie, tome 13, n
o3 (2004), p. 459-475
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459
Galois properties of linear differential equations (*)
MARIUS VAN DER
PUT (1)
Dedicated to Jean
Écalle for
theanniversary of
his transseries.ABSTRACT. - The theme of this paper is rationality, field of definition and descent for linear differential equations over some differential field.
The results extend and supplement
[H-P,Ho-P,P].
The questions and re-sults are mainly of an algebraic nature, with the exception of differential equations over fields of convergent Laurent series.
RÉSUMÉ. - Le thème de ce papier est rationnalité, corps de définition et descent pour des équations différentielles linéaires sur un corps différentiel.
Les résultats étendent et complètent
[H-P,Ho-P,P].
Les questions et lesrésultats sont pour la plupart de nature algébrique à l’exception des équations différentielles sur des corps de séries de Laurent convergentes.
Annales de la Faculté des Sciences de Toulouse Vol. XIII, n° 3, 2004 ]
1. Introduction
Let k be a differential field of characteristic 0. Its field of constants will b(
denoted
by Ck.
LetCk
denote thealgebraic
closure ofCk
andput k
=Ckk
The skew
ring
of differentialoperators
over k is denotedby k[~].
A moni(differential
operator
L Ek[~]
may factor in[~]
as aproduct L 1 L2
of moni(operators
such thatLi, L2 belong
tok’[~]
for some finite extension k’ of k contained ink.
The theme of this paper is to determine the fields k’ whiclare involved in these factorizations. The translation of this
question
in term:of differential modules can be
phrased
as follows:Let M denote the differential module over k
corresponding
toL,
i.e.M =
k[~]/k[~]L.
Put M= k
0k M. A submodule N C M will be callec(*) Reçu le 29 août 2003, accepté le 14 janvier 2004
(1) Department of Mathematics, University of Groningen, P.O.Box 800, 9700 AB Groningen, The Netherlands.
E-mail: mvdput@math.rug.ni
- 460 -
rational over a
field
k’ with k C k’C k
if there exists a submodule N’ ofk’ 0k
M such that N= k
~k’ N’.A related notion is the
following.
A differential module A over(say) k
descends to a
field
k’(with
say, k C k’ Ck)
if there exists a differential module B over k’ and anisomorphism
A ~ k ~k’ B.Let M be a differential module over k and consider a proper submodule N
(if any)
of M. Over which field k’ is N rational and for which fields k’does N descend to k’?
We make some observations. The module M is
equal
tok[~]/k[~]L.
Thesubmodules N of
M are
in 1-1correspondence
with the monicright
handfactors
L2
Ek[a]
of L. Thiscorrespondence
isgiven by L2 k[~]L2/k[~]L.
Let N C M
correspond
toL2.
The groupGal(k/k) = Gal(Ck/Ck)
acts inan obvious way on M and on
k[~].
For 03C3 EGal(k/k)
one has that03C3(N) corresponds
tocr(L2).
Inparticular, 03C3(N)
= N if andonly
if03C3(L2) = L2. Furthermore,
N is rational over k’ if andonly if 03C3(N) =
N for all03C3 E
Gal(k/k’).
Inparticular,
let H denote the opensubgroup
ofGal(k/k)
consisting
of the a with03C3(N) =
N. The fixed fieldk H
is the smallest field ofrationality
for N. We will call this field thefield of definition of
N.The above shows that the
given
translation from differentialoperators
to differential modules is correct.An
important notion,
introduced in[Ho-P],
is that of a skewdifferential field
F over k. This will mean here thefollowing:
F is a skew fieldcontaining k, k
lies in the center ofF,
the dimension of F over k isfinite,
and F has adifferentiation which extends the differentiation of k. A
diff erential
moduleM over F is a finite dimensional left vector space over
F, provided
with anadditive
map ~ :
M -4 Msatisfying ~(fm) = f a(m)
+f’m
for allf
E Fand m E M.
By
restriction ofscalars,
M is also a differential module over k.Using
skew differential fields over k one canproduce
in this way differential modules over k with ratherspecial properties.
The above
questions
are studied in[H-P]
and in recentpreprints [Ho-P]
and
[P].
Here we review some of the material(from
a somewhat differentpoint
ofview)
andprovide
some newcomplementary results,
inparticular
for differential fields of
convergent
Laurent series.2.
Rationality
for submodulesThe results of this section extend and correct
[H-P], Corollary
4.2part
2. We note that a mistake in this
corollary (namely 2d
should bewas
discovered
by
Mark vanHoeij.
THEOREM 2.1. - Let M be a
differential
module over kof
dimension n.Let N c M be an irreducible submodule and
N ~ 0, M. Suppose
that thereis no submodule
A ~
N with A ~ N.(a)
Thefield of definition
k’of
Nsatisfies [k’ : k] n dim N.
(b) Suppose
moreover that M is irreducible. Then C:= Endk[~] (M)
is afinite field
extensionof Ck.
For a suitableCk-linear embedding
C CCk
Ck
one has k’ = Ck. Let Z denote
M, regarded
asdifferential
module over k’.Then
k
~k’ Z ~ N.~
Proof.
-(a)
The sum of all03C3(N),
with 03C3 CGal(k/k),
is a submoduleN
that is rational over k. Let H be the opensubgroup
of finite indexr of
Gal(k/k) consisting
of the elements a with03C3(N) =
N. Then N is rational over the fixed field k’ of H and[k’ : k]
- r. Let al,... , ar denoterepresentatives
ofGal(k/k)/H
with ul = 1. Then7V
is the sum of the03C3i(N)
for i =
1, ... ,
r. This sum is direct since03C3i(N) ~ aj (N)
for ij.
Hence[k’ : k] dim
N ’(b)
M = ol(N)
~ ···~ 03C3r(N)
since M is irreducible. E:= Endk[~](M)
isthe
product
of rcopies
ofCk,
since the03C3i(N)
are irreducible andpairwise non-isomorphic.
Put C :=Endk[8] (M).
ThenCk 0Ck
C ~ E(by [Ho-P],
lemma
2.3).
Since M is irreducible one has that C is a commutative field and[C : Ck] ==
r. Let Z denoteM,
considered as differential module overCk. Then
Furthermore, k~kkC
isisomorphic
to theproduct
of rcopies
of k. Therefore M is the direct sumof k~kC
Z taken over all k-linearembeddings
of kC intok. For the
embedding
of kC intok,
which is induced from theembedding
of C into the first factor of the
product Ck
x ... xCk,
onehas 15. ~kC Z ~ 03C31(N) =
N.Finally,
oneeasily
sees that C =kH
and thus Ck =k H
isthe field of definition of N. D
Examples
2.2. -Example for
Theorem 2.1part (b).
For À Eone
de-fines the 1-dimensional differential module
E(03BB)
:=Q(x)ex
overQ(x) by
8e,B == 03BB xe03BB.
Let03BB1,..., Àr
be all solutions inQ
of some irreduciblepoly-
nomial over
Q. Suppose
thatÀi - 03BBj ~
Z for ij.
On the differential module A:= E(03BB1) ~ ··· EBE(Àr)
overQ(x)
one defines an action of Gai :=Gal(/Q) = Gal((x)/WQ(x)) by
03C3e03BB2 =e03C3(03BB2)
and03C3(fa) = 03C3(f)03C3(a)
forf
EQ.(x)
and a e A. This action commutes with a. Then M =A Gal
is a differential module over
Q(x)
andQ(x) ~Q(x)
M = A. Thus M andN :==
E(03BB1)
is anexample
for(b). Clearly Q(03BB1)
is the field of definition-462-
of N. Put Z :=
Q(03BB1)(x)e03BB1.
ThenQ(x) ~Q(03BB1)(x)
Z ~ N(for
the inclu-sion
Q(03BB1)(x)
C((x)). Furthermore, Z, considered
as differential mod- ule overQ(x),
isisomorphic
to M.Indeed, Q(x) ~Q(x)
Z isisomorphic
to(Q(x) ~Q(x) Q(03BB1)(x)) ~Q(03BB1)(x) Z. Furthermore, Q(x) ~Q(x) Q(03BB1)(x)
isisomorphic
aproduct
rcopies
of(x).
It follows thatQ(x) ~Q(x)
Z isisomorphic
to A. AlsoQ(x) ~Q(x)
M ~ A.By [Ho-P],
lemma2.3,
onehas Z ~ M.
The above theorem can be
supplemented
with analgorithm
in case k =Ck(x).
Let L Ek[~]
bemonic,
irreducible ofdegree
n. Put M :=k[~]/k[~]L.
Write e E M for the
image
of 1. There are several efficient ways to calculatea basis of C :=
Endk[~] (M)
overCk (see [P-S]).
Amultiplication
table for Ccan be calculated. e is also a
cyclic
vector forZ,
which is M seen as a Ck-differential module of dimension d =
n
The monicoperator
P ECk[~]
of
degree
d with Pe = 0 can be calculatedby
some linearalgebra.
Then Pis a
right
hand factor of L. The irreducible monicright
hand factors ink[~]
of L are the
images
of P ink[~]
obtainedby
theCk-linear embeddings
of Cinto Ck C k.
THEOREM 2.3. - Let M be a
differential
module over kof
dimension n.Let N C M be an irreducible submodule and
N ~ 0,
M.Suppose
that thereis a submodule
A ~
N with A r--" N.(a)
There exists a submodule A ~ Nhaving
afield of definition
k’ with[k’ : k] n dim N.
(b) Suppose
moreover that M is irreducible. Then F°:= Endk[~] (M)
isa skew
field of
dimensions2
> 1 over its center C. Put r:= [C : Ck].
Assume that F := F°
~Ck
k isagain
a skew field.Then F is a skew
differential field.
Let Z denoteM,
considered as adiffer-
ential module over F. For a suitable maximal commutative
subfield
G° ~ Cof
F° and a suitableembedding of
G =G°~Ck
k into k one hask~G Z ~
N.In
particular,
dim N is amultiple of
s.The
finite field
extensionsof
minimaldegree
k’ ~k,
contained ink,
suchthat there exists a submodule A C
M,
with A N andfield of definition k,
have the
form
Sk where S ~ C is a maximal commutativesubfield of
FO.(c) Suppose
that thedifferential field
k has theform Ck (x)
Then:(cl)
Theassumption
in(b)
issatisfied.
(c2)
For the case dim N = 1 in(a),
the estimate[k’ : k] n 2
holds.Proof.
-(a)
Let N+ denote the sum of all submodules of M that areisomorphic
to N. Let H cGal(k/k)
be the opensubgroup consisting
ofthé cr
with 03C3(N+) = N+.
Let 1 - 03C31,..., 03C3r denoterepresentatives
ofGal(k/k)/H.
Then03C31(N+) ~ ··· ~ 03C3r(N+)
is rational over k. HenceN+
isrational over a field
k+
with[k+ : k] n dim N+.
We have to show thatN+
contains an irreducible A ~ N which is rational over an extension
A/ D k+
with
[k’ : k+] dim N
For notational convenience we suppose that
k+
= k and thatN+
= M.Since M is a sum of irreducible modules it is also a direct sum
Ni
~ ··· 0Ns
of irreducible
modules, isomorphic
to N.. ThenEndk[a] (M)
isisomorphic
tothe
algebra Matr(s, Ck)
of all s-x s-matrices with entries inCk.
Thealgebra
B :=
Endk[~](M)
has theproperty
that the canonical mapCk ~Ck
B ~Endk[~](M)
is anisomorphism (see [Ho-P],
lemma2.3).
Hence B is asimple algebra
of dimensions2
over its centerCk.
LetC,
withCk
C C cB,
be a maximal commutative subfield. It is known that
[C : Ck]
= s andthat C is a
splitting
field forB, i.e.,
C~Ck B ~ Matr(s, C).
Put k’ = Ckand M’ - k’ 0k M. Then
Endk’[~](M’) =
C~Ck B ~ Matr(s, C).
LetP E C
~Ck B satisfy P2 =
P and the rank ofP,
considered as element ofMatr(s, C),
is 1. Then theimage
A’ =P(M’)
is a submodule such thatk
0k’ A’ is irreducible andisomorphic
to N. This proves(a).
(b)
LetN+
denote the sum of all submodules A c M that areisomorphic
to N. Let H c
Gal(k/k)
denote the stabilizer ofN+.
Then H is an opensubgroup
of finite index r. One choosesrepresentatives
1 = 03C31,..., 1 U, ofGal(k/k)/H.
Since M is irreducible one has M -~03C3i(N+). Furthermore, N+
is the direct sum of s > 1copies
of N. One concludes that E :=Endk[~](M) = 03A0ri=1 Endk[~] (03C3i(N+)).
Thus E is theproduct
of rcopies
ofthe matrix
algebra Matr(s, Ck).
Put FO ==Endk[~] (M).
From M irreducible andCk 0Ck
F° ~ E one concludes that FO is a skew field of dimensionrs2
over
Ck.
The center C of FO has theproperty
thatCk 0Ck
C is the centerof E and hence
isomorphic
toC/c .
It follows that[C : Ck]
= r. Thealgebra
F := FO
~Ck k
isgiven
a differentiationby (f
(g)a)’ f
(g) a’ for allf
E FOand a ~ k.
By assumption
F is a skew field ofdimension s2
over its center Ck. The left action of F onM,
makes M into a differential module Z over F.By
restricting
the scalars from F tok,
one obtains Magain.
The dimension of M isequal
to rs - dim N. Let z be the dimension of M as vector space over F. Then the dimension of M over k isequal
tozs2r.
It follows that dim N is divisibleby
s.- 464 -
Let GO ::) C be a maximal commutative subfield of FO and write G == G°k. Then G is a maximal commutative subfield of F and Z can be considered as a differential module over G. Now M =
k~kZ
=(k~kG)~GZ.
Furthermore, k
~k G is aproduct
of rscopies
of k. Thisyields
adecompo-
sition of M as a direct sum of rs submodules. One of them is
isomorphic
to N.
A finite extension S D
Ck, contained
inCk,
has theproperty
that Sk ~kM contains a submodule D with Ii ~Sk D ~ N if and
only
if Sk ~k M isa direct sum of
rs2
irreducible submodules. This condition isequivalent
toS~Ck
F° isisomorphic
to03A0ri=1 Matr(s, S).
The latter isequivalent
to S D Cand S is a
splitting
field for Fo. The extensions S of minimaldegree, having
that
property,
are the maximal commutative subfields of pocontaining
C.See
[Ho-P]
for more details.(c1)
followseasily
from the observation thatF°~Ck Ck(x) ~ FOQ9CC(x).
(c2)
Let N be a submodule of M of dimension 1. With the above nota-tion,
one has that03C31(N+)
~ ··· 003C3r(N+)
has field of definition k. We may suppose that this module isequal
to M.By (b),
we find that M isreducible,
since dim N = 1. Now M and M are
semi-simple
and M has adecomposi-
tion
Ml
~ ··· EBMt
into irreducible submodules of the same dimension. Forsome i E
{1,..., t}
theprojection
of N toMi
isinjective.
Wereplace
nowN
by
itsisomorphic image
inMi. By (2) (b)
we have thatMi
contains nosubmodule
A ~
N with A ~ N. Thus we canapply Theorem 2.1, part (a)
and therefore
[k’ : k] n t 2
~Examples 2.4.
-Example for
Theorem 2.3part (a) k
==Q(s,t)
withs2
+t2
= -1 and differentiationgiven by s’
= 1 and t’ =-st-1.
The 2-dimensional vector space M :=
k2
over k is made into a differential moduleby ~(a1, a2)
=(a’1 - a2/2t, a’2+a1/2t).
A calculation shows(compare
section2.5 of
[Ho-P])
thatEndk[~](M)
isisomorphic
to H =Q1
+Qi + Qj
+Qk,
the standard
quaternion
field overQ.
Then thealgebra
of theQ(s, t)[~]-
linear
endomorphisms
of M isisomorphic
to the matrixalgebra Matr(2, Q).
Thus M has a 1-dimensional submodule.
Moreover,
all the 1-dimensional submodules of M areisomorphic.
For everysplitting
field C ofdegree
twoover
Q, i.e.,
the fieldsQ(-m)
where m is the sumof
3 rational squares, there is a 1-dimensional submodule N of M with field of definition C.One observes that the
assumption
of Theorem 2.3(b)
is not satisfied.Indeed, k
is asplitting
field for H and thus H Q9 k ~Matr(2, k). Moreover,
the conclusions of Theorem 2.3
(b)
and(c2)
are not valid for thisexample.
Example for
Theorem 2.3part (b)
In[Ho-P]
manyexamples
aregiven. They
are constructed as follows. Consider a differential field k =
Ck (x)
and a skewfield po of dimension
s2
> 1 over its centerCk.
One makes the skew field F = po~Ck k
into a skew differential fieldby defining ( f
0a)’ = f
tg) a’for
f
E FO and a E k. One considers a suitable differential module M overF of dimension z. Then M considered as differential module over k has the
properties:
M isirreducible, Endk[a](M)
=F°, Endk[~](M) ~ Matr(s,Ck),
and M has an irreducible submodule N of dimension sz.
The
simplest example
isgiven by k = Q(x),
F° = H the standardquaternion
field overQ,
M = Fe and B on M isgiven by
~e =(i + jx) e.
The differential
operator corresponding
to M and thecyclic
vector e isL4
is irreducible as element ofQ(x)[~].
For everysplitting
field C cQ
of Hthere is a
decomposition L4
asproduct
of two monic irreducibleoperatoi
ofdegree
2 inC(x)[~].
For the case C =Q(i)
thisdecomposition
readsSuppose
that k =Ck(x)
and let L Ek[~]
denote a monic irreducible op- erator. We suppose that M :==k[~]/k[~]L
satisfies the condition of Theorem 2.3. Let e E M denote theimage
of 1. Analgorithm
forfinding
factorizations of L is thefollowing.
One calculates a basis overCk
of FO ==Endk[~] (M)
and a
multiplication
table w.r.t. this basis. From these data it is easy to cal- culate C DCk,
the center of FO. Letf
E FO be a"generic"
element. Then GO =C( f )
hasdegree s
over C and thus GO is a maximal commutative subfield ofFO, containing
C. NowM,
as differential module over G =G°k,
has
again
e ascyclic
vector.Using
linearalgebra,
one determines the monic differentialoperator
of smallestdegree
P EG [9]
with Pe = 0. Aftertaking
a
Ck-linear embedding
of GO intoCk
Ck,
one obtains aright
hand factorof L of minimal
degree
ink[~].
3. Descent for differential modules
Consider a Galois extension K D k of differential fields such that K =
CKk.
Let G denoteGal(K/k)
=Gal(CK/Ck).
For a differential module Mover K and any a E G one defines the twisted differential module 03C3M
by:
a M == M as additive
group, ’M
has a new scalarmultiplication given by
f *
m =03C3-1(f)m (for f
E K and m eM)
and the derivation a of aM coincides with the 9 of M. A necessary condition for M to descend to k is the existence of anisomorphism ~(03C3) :
03C3M ~ M for every a E G. The- 466 -
descent
problem
asks whether this condition issufficient,
or moregenerally
for which intermediate fields l
(i.e.,
k c l cK)
M descends to l.The results of
[Ho-P]
and[P] concerning
thisquestion
can be formulatedas:
Suppose
that K =CKk, CK/Ck
is afinite
Galois extension with groupG,
A is adifferential
module over K withEndK[~] (A) = CK
and 03C3A ~ Afor
all 03C3 ~ G. Then:(1) If
k is afield of formal
Laurentseries,
say, k =Ck((x)),
then Adescends to k.
(2) If
k is afield of convergent
Laurentseries,
say k =R({x}),
K -
C({x}),
then A will ingeneral
not descend to k. The obstruction to descent is determinedby
the Stokes matricesbelonging
to M.(3) If
k is afunction field
in onevariable,
say, k =Ck(x),
then there isa
(skew) field
F° overCk
such that M descends to lif
andonly if
thefield of
constantsof
l is asplitting field for
F°.The descent
problem
is related to therationality
results for irreducible submodules formulated in Theorem 2.3. This can be formulated as follows.PROPOSITION 3.1. - Let N be an irreducible module over
k. Suppose
that 03C3N ~ N
for
all 03C3 CGal(k/k).
(1)
There exists an irreducible module M over k and anembedding N ~ M.
(2)
The moduleM,
withproperty (1),
isunique
up toisomorphism.
(3)
N descends to afinite
extension k’of
k with k’ c kif
andonly if
there exists a submodule A C M with A N and A has
field of definition
k’.
Proof.
- There is a finite Galois extension K ~ k contained ink
suchthat N descends to K. Thus N =
k
~K B for some differential module Bover K. One
regards
B as a differential module over k.By [Ho-P],
B is asemi-simple
k-differential module andmoreover, k.
~k B is the direct sum of[K : k] copies
of N.Indeed,
Then
Ck~Ck Endk[~](B) ~ Endk[~] (N ~ ··· ~N) ~ Matr([K : k], Ck).
There-fore
Endk[~](B) ~ Matr(d, F°)
for some d and some(skew)
field F° with- 467 -
center
Ck.
Hence B is a direct sumBi
~ ··· EBBd
ofisomorphic
irreducible differential modules over k andEndk[~] (Bi)
= F°.Clearly
N can be seenas a submodule of k 0k
Bl.
Thus M =BI
has therequired property (1).
Suppose
thatM(l)
has alsoproperty (1).
Then N =k 0K
B CM(l)
=k~kM(1)
and B :==k~kB ~ N[K:k]
CM(1)[K:k].
The last module is semi-simple
and there is aprojection
P :M(1)[K:k]
---+M(1)[K:k], commuting
with 9 and with
image
B. For any cr EGal(k/k)
one can form theconjugate upu-1.
This isagain
aprojection commuting
with 9 and withimage
B.Let
03C3iP03C3i-1,
i =1,..., s
denote the distinctconjugates
of P. ThenQ
:=1 s 03A303C3iP03C3i-1
isagain
aprojection, commuting
with 9 and withimage
P.Since
Q
also commutes with the action ofGal(k/k)
onM(1)[K:k],
one hasthat
Q
mapsM(1)[K:k]
onto B. Now B is a direct sum ofcopies
of M andtherefore M ~
M(l).
This proves(2).
The "if"
part
of(3)
is obvious.Suppose
that N descends to k’. We may suppose that k’ CK,
where K is the finite Galois extension of(1).
Then N
= k
~k’ C and B = K ~k’ C satisfies N= k
0K B. As in(1),
B
= B1
0... OE)Bd
as k-differential module. The inclusion C C B induces aninclusion
k 0k
C C~di=1k
~kBi. Moreover,
A := k ~k’ C can be consideredas a submodule of k 0k C. Hence A is a submodule
of k 0k Bi
for some i.Now
Bi ~
M :=B1
for all i and thus A can be considered as a submodule of M. 0Proposition
3.1 has a translation in terms of differentialoperators.
Let L Ek[~]
be a monic irreducible differentialoperator
and suppose that for any a EGal(k/k),
theoperator cr(L)
isequivalent
to L(in
the sense that thetwo
operators
defineisomorphic
differentialmodules).
Let N :==k[~]/k[~]L
be the
corresponding
differential module. LetL1,...,Ls,
denote the con-jugates
of L for the groupGal(k/k).
ThenL+
denotes the least commonright multiple
ofLi,...,Lg
in the skewring k[~] (i.e., L+
is the monicgenerator
of theright
ideal~si=1 Lik[~]).
ThenL+
Ek[~], L+ =
LA forsome A E
k[8]
and thusk[~]/k[~]L+
contains the submodulek[~]A/k[~]LA
which is
isomorphic
to N. Theoperator L+
can be reducible ink[~].
ButL+
issemi-simple by
construction and for any irreducibleright
hand factorR E
k[~]
ofL+
one has M ~k[~]/k[~]R.
Part(3)
of 3.1 reads now: L descends to k’ if andonly
if R has a monic irreducibleright
hand factor ink[8]
with coefficients in k’.- 468 -
4. Galois structure on the solution space
Closely
related torationality
and descent is Galois structure on the solu- tion space of a differential module. Let A be a differential module over k. LetK ~ k
denote a Picard-Vessiot extension for A. The solution space of A is then V :=ker( 8, K ~ A).
Let G andG+
denote the groups of the differentialautomorphisms
ofK/k.
andK/k.
There is an obvious exact sequencewhere for any g E
G+,
the elementpr(g)
is the restrictionof g
toCk.
Interesting questions
are: what is theimage of pr
and does pr have aquasi-
section ?
Example. 2013 k
=Q(x), k
=Q(x),
A = ke with 9e =03BBxe
and À EQ B Q.
The
image
H of pr consists of thé cr eGal(Q/Q)
such that03C3(03BB)
= or03C3(03BB) =
-A + a for auniquely
determined a e Z.Moreover,
there is a sectionH ~ G+.
In
particular, G+ ~ Gal(Q/Q)
issurjective
if andonly
if the minimalpolynomial
of 03BB overQ
has the formT2
+ aT + b with a E Z.Proof.
- The Picard-Vessiot field K isQ(x,t)
with t transcendentalover
Q(x)
and t’= 03BB xt. Any 03C3
such that either03C3(03BB) = 03BB
or03C3(03BB) =
-03BB + ahas an obvious extension to an element
a+
EG+, given by
the formulaa+t
= t in the first case andby a+t
=xat-1
in the second case. Moreover(03C303C4)+ = 03C3+03C4+.
Suppose
that a extends to an T EG+.
A calculation shows that theequation y’ == ?y
with J1 EQ
has a non-zero solution in K if andonly
if03BC ~ Z03BB + Z. Now
7(t)’ == 03C3(03BB) x03C4(t).
Therefore03C3(03BB)
EZ03BB + Z.
Also03C3-1(03BB)
EZÀ + Z. Hence
03C3(03BB) =
±03BB + a with a e Z.Suppose
that03C3(03BB) = 03BB
+ a, thenan (À)
= a + na for any n 1. Hence a = 0.The last assertion is an immediate consequence. D
LEMMA 4.1. - Let M be a
differential
module over k =Ck (x)
and letK be the Picard- Vessiot
field for k
~k M. Then pr :G+ ~ Gal(Ck/Ck)
issurjective
and there exists a section s :Gal(Ck/Ck) ~ G+.
Proof.
- It suffices to prove the existence of a section s. Consider apoint
x = a ECk
at which M has nosingularity.
ThenCk((x - a))
0 Mis a trivial differential module and so is
Ck((x - a))
0 M. PutV =
ker(Ck((x - a))
0M).
Then V is a full solution space ofM, i.e.,
- 469 -
the dimension of V over
Ck
isequal
to the dimension of M over k. Thefield, generated
over k CCk((x - a)) by
the coordinates of all elements of V withrespect
to a fixed basis of M overk,
is a Picard-Vessiot field for M and can be identified with K.Moreover,
V can be identified with the above solution space inside K 0 M. NowGal(Ck/Ck)
acts in an obviousway on
Ck((x - a)).
The induced action ofGal(Ck/Ck)
onCk((x - a))
0 Mcommutes with 9. Hence the space V C
Ck((x - a))
0 M is stable under this action. Therefore K is also stable under this action and we obtain therequired
section s :Gal(Ck/Ck) ~ G+.
0COROLLARY 4.2. -
Suppose
that k =Ck(x).
Let B be adifferential
module
over k
such that 03C3B has the same Picard- Vessiotfield
asB, for
everya e
Gal(Ck/Ck).
ThenG+ ~ Gal(Ck/Ck)
issurjective
and has asection.
Proof.
- B descends to some finite Galois extension k’ ofk,
containedin k. Thus B
= k
~k’ C for some C. Let M denoteC,
considered as differ- ential module over k. Thenk 0k
M isisomorphic
to the direct sum 003C3C,
taken over all 03C3 e
Gal(k’/k). By assumption, k
0k M and B have thesame Picard-Vessiot field. Now the above statement follows from Lemma 4.1. 0
OBSERVATION 4.3. - Galois structure on the solution space V
of
adif- ferential
module M = k 0k M.Rationality properties for
submodulesof
M.As in lemma 4.1 we assume that k =
Ck (x).
We will use the abovenotations. The natural action of
G+
on K 0k M induces an action ofG+
on the solution space V
= ker(9,
K 0kM). Moreover,
this action ofG+
onK 0k M induces the
natural
action ofGal(Ck/Ck) on k 0k M
= M.The choice of a section s :
Gal(Ck/Ck) ~ G+ provides
V with aCk-
linear action of
Gal(Ck/Ck). By [S], Proposition 3, p.159,
theCk-vector
space
has the
property
that the natural mapCk ~Ck V0 ~
V is abijection.
Wewill formulate this
property by
"V has aCk-structure".
For the section s, considered in theproof
of Lemma4.1,
one hasVo
=ker(~, Ck((x - a)) 0M).
The
Ck-structure
of Vdepends
of course on the choice of s.There is a 1-1
correspondence
between the submodules N of M and the G-invariantsubspaces
W of V. Thiscorrespondence
isgiven by
N ~ W :=ker(~,
K tg)N)
c V =ker(a,
K tg)M).
Let Ncorrespond
to W. Let H be-470-
the open
subgroup
of finite index ofGal(Ck/Ck)
that stabilizes N. Thenpr-1 H C G+
is the stabilizer of W and moreover, H is the stabilizer of W for the chosenCk-structure
on V. Let C’ CCk
denote the fixed field of H.Then W is defined over C’ and the field of definition of N is
k’
-C’ (x) .
Oneconcludes that
rationality properties
of G-invariantsubspaces
W of V(and
the
corresponding
N CM)
do notdepend
on the choice of the section s.5. Fields of
convergent
Laurent seriesThe field of
convergent
Laurent series over R will be denotedby
k =
R({x}).
Then k =C({x})
is the field ofconvergent
Laurent seriesover the
complex
numbers. The main observation is that there are exam-ples
forpart (b)
of Theorem 2.3 in this situation. This is in contrast with the formal case,i.e.,
differentialequations
over the fieldsR((x))
andC((x)).
We are
looking
for anexample
of an irreducible differential module Mover
R({x})
and an irreducible submodule N of M =C({x}) ~R({x})
Mwith
N ~ 0, M
such that M contains a submodule A withA ~
N andA ~ N. For the construction of an
example
we need a skew differential field F of finite dimension over its center k =R({x}).
The most obviousexample
is F = H Q9RR({x}),
where H is thequaternion
field over R.The differentiation on F is
given by (h
0r)’ - h
0 r’ for any h E Hand r E
R({x}). According
topart (b)
of Theorem2.3,
M must have thestructure of a differential module over the skew differential field F. The
cheapest
choice that one can make is M = Fe and o9e = de for a suitable element d E F. This choice works. Theexplicit example
d = i +x-1 j
istreated in detail in
[P] (in
the contextof descent).
One obtains a differentialoperator
ofdegree
4 inR({x})[03B4] (where 03B4
=x dx namely
which has the
properties:
L4
ER({x})[03B4]
is irreducible.L4
factors inC({x})[03B4] (in
manyways)
as aproduct
of irreducible oper- ators ofdegree
2. Oneright
hand factor is for instanceL2:= 03B42 + 03B4 + (1 +
x-2 - i).
Thecomplex conjugate L2 := 62 + 6
+(1
+x-2
+i)
isobviously
also a
right
hand factor ofL4
and is moreoverequivalent
toL2.
L4
factors inR((x))[03B4]
as aproduct
of irreducibleoperators
ofdegree
2.One can construct
large
classes of differentialoperators
inR({x})[03B4]
with these somewhat bizarre
properties.
One way of
explaining
theseexamples
is that a differential module over,-
say,
C({x})
can be seen as a differential module overC((x)), provided
withthe additional data of a
family
of Stokes matrices. Thepossibilities
forthese additional data form a finite dimensional affine space over C
(see [P-S]).
These Stokes matrices areresponsible
for the abovephenomena.
Itseems that similar
examples
can be constructed for non-linear differentialequations
overR({x})
and their solutions written in terms of transseries.There are
only
a few skew fields of finite dimension over their centerR({x}).
Infact,
the Brauer group of this field is(Z/2Z)2.
More room forexamples
seems to be available for the field ofconvergent
Laurent seriesover the
p-adic numbers, i.e.,
for the differential fieldQp({x}).
There aremany skew differential fields F of finite dimension over their center
Qp({x}).
Indeed,
the Brauer group of the fieldQp
is known to beQ/Z.
Let FO bea skew field of finite dimension over its center
Qp.
The skew field F =F°~Qp Qp({x})
has the same dimension over its centerQp({x}). Moreover,
F becomes a skew differential field
by
the formula(f 0 a)’ - f
0 a’ for anyf ~ F° and a ~ Qp({x}).
The calculation of the full Brauer group
Br(k)
goes as follows. The fieldk = Qp 0Qp k
is aCi-field
and has trivial Brauer group. As a consequenceBr(k) = H2(Gal(k/k),k*).
There is a Galoisequivariant isomorphism
Hence
Br(k) ~ Br(Qp)
xH2(Gal(k/k), Z). Furthermore,
The last group is
isomorphic
to the group of the continuoushomomorphisms Z ~ Q/Z.
In the final
part
of this paper we consider a differential field K :=k({x}),
where k is a
complete
valued fieldcontaining Qp.
We want to compare the classification of differential modules over K and overk
:=k((x)),
in orderto see whether there is indeed room for
examples
with"strange"
descentproperties
due to skew differential fields with center K. As we willshow,
there is no multisummation
theory
for differentialequations
over K andthere are no Stokes matrices. The difference between differential
equations
over K and the formal
theory, i.e.,
differentialequations over R
=k((x)),
lies in the appearence of
p-adic
Liouville numbers. An element A EZp
iscalled
a p-adic
Liouville number if liminfn~~|03BB-n|1/n
= 0. In otherwords,
À is a
p-adic
Liouville number if À is too wellapproximated by positive
-472-
integers.
Thisterminology
and some of thefollowing
results were discoveredin
[C],
and rediscovered in[P80].
The basicexample
whichexplains
the roleof
p-adic
Liouville numbers is the differentialequation
This
equation
has theunique
formal power series solution03A3n- 1 n-03BBxn.
This solution is
divergent precisely
when À is ap-adic
Liouville number.First we recall the
classification of differential
modules overK
=k((x)),
where k is any
algebraically
closed field. Let 03B4 denote the differentiationxd dx.
A differential module M =(M, 03B4) over K
is calledregular singular
ifthere exists a
k[[x]]-lattice Mo
C M(i.e., Mo = k[[x]]b1
+ +k[[x]]bm
forsome basis
b1,..., bm
of M overK)
which is invariant under 03B4. One canshow that for any
regular singular
differential module M there exists a ba- sisbl, ... , bm
such that the matrix of 03B4 w.r.t. this basis has coefficients in k and moreover the difference of(distinct) eigenvalues
of this matrix is not aninteger. For q
Ex-1k(x-1] one
defines the differential moduleE(q)
=Ke
of dimension 1by 6(e)
= qe. For distinct elements q1, ... , qs Ex-1k[x-1]
andregular singular
differential modulesMi,..., Ms
one considers the differen- tial module~si=1E(qi)
0Mi.
The differential modules obtained in this wayare called "unramified differential modules" over
K.
Let us call the abovedecomposition
theeigenvalue decomposition
of the unramified module. The q1, ... , qs will be called theeigenvalues
of the unramified module. For anyinteger
n 1 weput Kn := k((x1/n)).
The classification of differential modules overK
can be formulated as follows:For any
differential
module M overK
there exists a smallestinteger
n 1 such that
Kn ~
M is anunramified differential
module overKn.
Moreover,
theeigenvalue decomposition of Kn ~
M isunique.
The
following
result seems to be new. Itgives
the firststep
towards a classification of differential modules over K= k({x}),
where k is analge- braically
closed andcomplete
fieldcontaining Qp.
For convenience weonly
formulate the result for the unramified case.
PROPOSITION 5.1. - The
eigenvalue decomposition.
Let M be a
differential
module over K.Suppose
that :=K
~K M isunramified.
Let thedecomposition of
be~si=1E(qi)
~Ni (with
the abovenotations).
Then there exists aunique decomposition
M =~si=1E(qi)
0Mi,
with all